On the class-breadth conjecture for \(p>2\) -groups

Alexander A. Skutin
Faculty of Mechanics and Mathematics of Lomonosov Moscow State University
Moscow Center for Fundamental and Applied Mathematics
a.skutin@mail.ru


Abstract

The class-breadth conjecture of Leedham-Green, Neumann and Wiegold states that the nilpotency class of any \(p\)-group is at most \(b(G) + 1\), where \(\displaystyle{b(G) = \max_{g\in G}\log_p[G:Z_G(g)]}\) denotes the breadth of \(G\). While several counter-examples to this conjecture have been found for \(p = 2\), it is still open in general for \(p>2\). This article is dedicated to the general case \(p>2\) of the conjecture. We propose a generalization for the case \(p>2\), which we prove under some additional conditions.

1 Introduction↩︎

Let \(G\) be a finite \(p\)-group. The breadth \(b(x)\) of an element \(x\) of a group \(G\) is defined as \(b(x) := \log_p|G:Z_G(x)|\), where \(Z_G(x)\) denotes the centralizer of \(x\) in \(G\). The breadth \(b(G)\) of \(G\) is defined as \(\displaystyle{b(G) := \max_{g\in G}b(g)}\).

C. Leedham-Green, P. Neumann, and J. Wiegold in [1] stated the following conjecture: \(\operatorname{cl}(G)\leq b(G) + 1\) for all \(p\)-groups \(G\) (\(\operatorname{cl}(G)\) denotes the nilpotency class of \(G\)).

W. Felsch, J. Neubüser, and W. Plesken in [2] provided a series of counterexamples to the conjecture for \(p = 2\). Further counterexamples were found by B. Eick, M. Newman, and E. O’Brien in [3]. In [3], they also proved that the analogue of the conjecture for finite-dimensional nilpotent Lie algebras is false for all finite fields; i.e., for every finite field \(\mathbb{F}\), there exists a finite-dimensional nilpotent Lie algebra \(\mathfrak{g}\) over \(\mathbb{F}\) such that \(\operatorname{cl}(\mathfrak{g}) > b(\mathfrak{g}) + 1\), where \(b(\mathfrak{g}) := \max_{a\in\mathfrak{g}}(\dim \mathfrak{g} - \dim Z_{\mathfrak{g}}(a))\) and \(Z_{\mathfrak{g}}(a) := \{x\in\mathfrak{g} \mid [a, x] = 0\}\).

The conjecture has been proved in some special cases; see, for example: if \(b(G)\leq 4\) in [4], [5], if \(b(G)\leq p + 1\) in [6], if \(G\) is a \(p\)-group of maximal class in [7], if \(G\) is metabelian in [1], and if \(G\) is not covered by its two-step centralizers in [1]. See also [3] for more classes of \(p\)-groups satisfying the conjecture. A more detailed description of the results related to the class-breadth conjecture can be found in the introduction of [2].

In this paper, we study the general case \(p>2\) of the conjecture.

Notation and conventions. For any \(p\)-group \(G\), any of its subgroups \(H, H_1, H_2,\ldots, H_n\), any subset \(S\subseteq G\), and any elements \(a, b\in G\), we denote:

  • \([a, b] := aba^{-1}b^{-1}\),

  • \(a^b := bab^{-1}\),

  • \(H^a := aHa^{-1}\)

  • \(H_1H_2\ldots H_n := \langle \cup_{i=1}^nH_i\rangle\) (it should be noted that this notation differs from the standard one, in particular, \(H_1H_2\ldots H_n = H_{\sigma(1)}H_{\sigma(2)}\ldots H_{\sigma(n)}\) for each permutation \(\sigma\in S_n\)),

  • \([H_1, H_2,\ldots, H_n] := \left\langle\left\{ [[\ldots [[h_1, h_2], h_3],\ldots ], h_n] \mid h_i\in H_i, 1\leq i\leq n\right\}\right\rangle\),

  • \(\langle S\rangle\) – the subgroup of \(G\) generated by \(S\),

  • \(\langle\!\langle S\rangle\!\rangle^H := \langle\{s^h\;\vert\;h\in H, s\in S\}\rangle\) – the normal closure of \(S\) in \(\langle S\rangle H\),

  • \([a, S] := \{[a, s] \mid s\in S\}\),

  • \([S, a] := \{[s, a] \mid s\in S\}\),

  • \(\llbracket H_1, H_2,\ldots, H_n\rrbracket^H := \langle\!\langle\left\{ [[\ldots [[h_1, h_2], h_3],\ldots ], h_n] \mid h_i\in H_i, 1\leq i\leq n\right\}\rangle\!\rangle^H\),

  • \(N_G(H)\) – the normalizer of \(H\) in \(G\),

  • \(Z_G(H) := \cap_{h\in H}Z_G(h)\),

  • \(Z_i(G)\) – the \(i\)-th term of the upper central series of \(G\) (\(Z_0(G) = \{e\}, Z_1(G) = Z(G)\)),

  • \(\gamma_i(G)\) – the \(n\)-th term of the lower central series of \(G\) (\(\gamma_1(G) = G, \gamma_2(G) = G'\)),

  • \(G^{(i)}\) – the \(i\)-th derived subgroup of \(G\) (\(G^{(0)} = G\), \(G^{(1)} = G'\)),

  • \(d(G)\) – the derived length of \(G\),

  • for each element \(h\in H\), denote \(b_H(h) := \log_p[H : H\cap Z_G(h)]\),

  • by a maximal subgroup \(M\) of \(G\), we mean a proper subgroup not contained in any other proper subgroup of \(G\); such a subgroup is always normal in \(G\) and has index \(p\) in \(G\).

In Section 2, we introduce the necessary notions regarding \(G\)-groups.

In Section 3, we introduce a strengthened class-breadth conjecture for \(G\)-groups (see Conjecture 1). For this conjecture, we make some additional assumptions and state Theorem 1.

In Section 4, we prove Theorem 1.

Acknowledgments↩︎

I am grateful to Y. V. Novikova and Huawei Moscow Research Center, and to the Theoretical Physics and Mathematics Advancement Foundation “BASIS”.

2 \(G\)-Groups and Relative Structures↩︎

Let \(p\geq 2\) be any prime number and \(G\) be any \(p\)-group. By a \(G\)-group, we will denote any \(p\)-group \(P\) such that \(G\subseteq Aut(P)\), endowed with the natural action of \(G\) via automorphisms (unless specified otherwise, when \(G\) is a \(p\)-group, any \(G\)-group is assumed to be a \(p\)-group for the same prime \(p\)).

Consider any \(G\)-group \(P\), let \(P_1 := G\ltimes P\) denotes the respective semidirect product.

Definition 1. For each subgroup \(H\) of \(P\), we say that \(H\) is a \(G\)-invariant subgroup of \(P\) if \(g\cdot h\in H\) for all \(g\in G\) and all \(h\in H\), which is equivalent to \([G, H]\subseteq H\) (\(G, H\subseteq P_1\)). Therefore, each \(G\)-invariant subgroup \(H\) of \(P\) is a \(G\)-group, equipped with the restricted action of \(G\) on \(H\).

Definition 2. For each \(G\)-group \(P\), define \(\gamma_2^G(P) := P'[G, P]\).

Definition 3. For each \(G\)-group \(P\), denote \(\gamma_1^G(P) := P\) and \(\gamma_i^G(P) := \gamma_2^G(\gamma_{i-1}^G(P))\) for each \(i\geq 2\). We will call \(\gamma_i^G(P)\) the \(G\)-lower central series of \(P\). Define \[\operatorname{cl}^G(P) := \min \{k \mid \gamma_{k + 1}^G(P) = \{e\}\}.\]

We will call \(\operatorname{cl}^G(P)\) the \(G\)-nilpotency class of \(P\).

Definition 4. Let \(P\) be a \(G\)-group. A finite sequence of subgroups \(C_i\), \(0\leq i\leq N\) of \(P\) such that \(C_0 = P\) and \(C_N = \{e\}\) is called a \(G\)-central series of \(P\) if, for each \(0 \le i \le N-1\), the following hold:

  1. \(C_{i+1} \subseteq C_i\),

  2. \([G, C_i] \subseteq C_{i+1}\).

The following two propositions are straightforward, and we omit their proofs.

Proposition 1. For each \(G\)-group \(P\) and each its \(G\)-central series \(C_i\), \(0\leq i\leq N\):

  1. \(C_i\) are \(G\)-invariant subgroups of \(P\),

  2. \(\gamma_i^G(P)\subseteq C_{i-1}\), \(\forall 1\leq i\leq N + 1\).

Proposition 2. In the case \(G = \{e\}\), we have that for each \(G\)-invariant subgroup \(H\) of \(P\), \(\gamma_2^G(H) = H'\), \(\gamma_i^G(H) = H^{(i-1)}\), and \(\operatorname{cl}^G(H) = d(H)\). In the case \(G = \operatorname{Int}(P)\trianglelefteq Aut(P)\), we have that for each \(G\)-invariant subgroup \(H\) of \(P\), \(\gamma_2^G(H) = [G, H]\), \(\gamma_i^G(P) = \gamma_i(P)\), and \(\operatorname{cl}^G(P) = \operatorname{cl}(P)\).

Definition 5. For each element \(x\in P\), define \(b^G(x) := b_{P_1}(x)\). We will call \(b^G(x)\) the \(G\)-breadth of \(x\in P\).

Definition 6. Define \(\displaystyle{b^G(P) := \max_{x\in P}b^G(x)}\). We will call \(b^G(P)\) the \(G\)-breadth of \(P\).

The following lemma is well-known, and we omit its proof.

Lemma 1. Consider any group \(A\) and any its subgroups \(B, C\) such that \(C\) is a normal subgroup of \(A\). Then \(BC = CB = \{bc \mid b\in B, c\in C\} = \{cb \mid b\in B, c\in C\}\).

The following lemma is straightforward to verify, and its proof is omitted:

Lemma 2. For each \(G\)-invariant subgroup \(H\) of \(P\), the group action of \(G\) on \(P\) induces an action of \(G\) on \(H\), and \(GH = G \ltimes H = \{gh \mid g\in G, h\in H\} \subseteq P_1\) is the respective inner semidirect product of \(G\) and \(H\).

Definition 7. For each \(G\)-invariant subgroup \(H\) of \(P\) and each element \(h\in H\), define \(b_H^G(h) := b_{GH}(h) \overset{\text{Lem. }\ref{lemma2}}{=} b_{G\ltimes H}(h)\).

Definition 8. Define \[\mathcal{M}^G(P) := \min \biggl\{ k \biggm| \begin{align} &\text{the set } \{x \in P \mid b^G(x) > k\} \text{ can be covered} \\ &\text{by two proper subgroups of } P \text{ containing } \gamma_2^G(P) \end{align} \biggr\}.\]

Remark. These two proper subgroups of \(P\) are \(G\)-invariant from the fact that they contain \([G, P]\subseteq \gamma_2^G(P)\).

3 Strengthened Class-Breadth Conjecture for \(G\)-groups↩︎

The class-breadth conjecture for \(p > 2\) -groups can be generalized via the following statement that also generalizes [8]:

Conjecture 1. Consider any prime number \(p > 2\) and any \(p\)-group \(G\). Then for each \(G\)-group \(P\) there exists a \(G\)-central series \(C_i\), \(0\leq i\leq N\) of \(P\) such that:

  1. \(C_0 = P\), \(C_1 = \gamma_2^G(P)\), \(C_N = \{e\}\),

  2. \(\log_p[C_i : C_{i+1}]\leq \mathcal{M}^G(P) - i + 1\), \(\forall 1\leq i\leq N - 1\).

Proposition 3. Conjecture 1 implies both the class-breadth conjecture and [8] for \(p>2\) -groups.

Proof. Without loss of generality, we may assume that \(C_{N-1}\not=\{e\}\). From Properties 1, 2, it follows that \(1\leq\log_p|C_{N-1}| = \log_p|C_{N-1}/C_N| \leq \mathcal{M}^G(P) - N + 2\), therefore, \(N\leq \mathcal{M}^G(P) + 1\) and, from Proposition 1, \(\gamma_{\mathcal{M}^G(P) + 2}^G(P)\subseteq\gamma_{N+1}^G(P)\subseteq C_N = \{e\}\), i.e. \(\operatorname{cl}^G(P)\leq \mathcal{M}^G(P) + 1\). In the case \(G = Int(P)\), from Proposition 2 we obtain the class-breadth conjecture for \(p>2\) -groups. To prove [8], notice that Properties 1, 2 imply \(\log_p|\gamma_2^G(P)| = \log_p|C_1| = \sum_{i=1}^{N-1}\log_p[C_i : C_{i+1}]\leq \sum_{i=1}^{N-1}\max (0, \mathcal{M}^G(P) - i + 1) \leq \mathcal{M}^G(P)(\mathcal{M}^G(P)+1)/2\). In the case \(G = Int(P)\), from Proposition 2 we obtain [8] for \(p>2\) -groups. ◻

In this paper, we prove the following special case of Conjecture 1:

Theorem 1. Consider any \(p>2\) -group \(G\) and any \(G\)-group \(P\), let \(P_1 := G\ltimes P\) denotes the respective semidirect product. Assume that there exists a normal and \(G\)-invariant subgroup \(M\) of \(P\) satisfying:

  1. \(\log_p[P : M] \leq 1\),

  2. \([G, M] = \{e\}\).

Then \(G\)-group \(P\) has a \(G\)-central series \(C_i\), \(0\leq i\leq N\) as in Conjecture 1.

Remark 1. When \(M = P\) and \(P\not= \{e\}\) (the statement is trivially true when \(P = \{e\}\)) in Theorem 1, we can replace \(M\) with any maximal subgroup of \(P\) that contains \(\gamma_2^G(P)\) (for example, \(M = M_0\cap P\), where \(M_0\) is any maximal subgroup of \(G\ltimes P\)), preserving Conditions 1 and 2 of Theorem 1 (\(M\) will be still \(G\)-invariant since \([G, M]\subseteq [G, P]\subseteq \gamma_2^G(P)\subseteq M\)). Therefore, without loss of generality, we will assume that \(\log_p[P : M] = 1\) in Theorem 1.

Remark 2. Theorem 1 in the case when \(M = P\) implies [8] by a similar argument to that in Proposition 3.

4 Proof of Theorem 1↩︎

Lemma 3. Consider any group \(X\) and any its subgroups \(A, B, C, D\) such that either \(B\subseteq N_X(C)\) or \(C\subseteq N_X(B)\) holds, and \(D\trianglelefteq X\). Consider also any subset \(S\) of \(X\). Then

  1. \([A, BC]\subseteq [A, B]\llbracket A, C\rrbracket^B\),

  2. \([A, \langle\!\langle S\rangle\!\rangle^X]\subseteq \langle\!\langle \{[\langle\!\langle A\rangle\!\rangle^X, s]\;\vert\;s\in S\}\rangle\!\rangle^X\).

Proof. Part (a) follows from Lemma 1, the fact that either \(B\subseteq N_X(C)\) or \(C\subseteq N_X(B)\), and the fact that \([a, bc] = [a, b][a, c]^b\), \(\forall a, b, c\in A\).

Part (b) follows from \([a, bc] = [a, b][a, c]^b\), \(\forall a, b, c\in A\) and the induction on the length \(k\) of a word \(s = s_1^{x_1}\ldots s_k^{x_k}\in \langle\!\langle S\rangle\!\rangle^X\) (the base case \(k=1\) follows from \([a, s^x] = [a^{x^{-1}}, s]^x\in RHS\), \(\forall a\in A, \forall s\in S, \forall x\in X\)). ◻

Lemma 4. Consider any group \(X\) and any its subgroups \(A, B\), such that \(B\trianglelefteq X\). Then \([\langle\!\langle A\rangle\!\rangle^X, B] = \llbracket A, B\rrbracket^X\).

Proof. From \(B, \langle\!\langle A\rangle\!\rangle^X\trianglelefteq X\), we obtain \([\langle\!\langle A\rangle\!\rangle^X, B]\trianglelefteq X\) and, therefore, from \([A, B]\subseteq [\langle\!\langle A\rangle\!\rangle^X, B]\), that \(\llbracket A, B\rrbracket^X\subseteq [\langle\!\langle A\rangle\!\rangle^X, B]\). Inclusion \([\langle\!\langle A\rangle\!\rangle^X, B] \subseteq \llbracket A, B\rrbracket^X\) follows from Lemma 3(b). ◻

Lemma 5. For each \(p\)-group \(G\) and any its maximal subgroup \(H\) such that \(H' \subsetneq G'\), the set \(X := \{x\in H \mid [x, G]\subseteq H'\}\) is a proper subgroup of \(H\).

Proof. Note that from the maximality of \(H\) in \(G\), it follows that \(H\trianglelefteq G\) and \([G : H] = p\), which implies \(H' \trianglelefteq G\). Consider the natural homomorphism of factorization \(\pi : G \to G/H'\). It is straightforward to check that \(X = \pi^{-1}(Z(\pi(G))) \cap H\), which is clearly a subgroup of \(H\). If \(X = H\), then \(\pi(X) = \pi(H)\) is a central subgroup of index \(p\) in \(\pi(G)\). This implies that \(\pi(G)\) is abelian, and, consequently, \(G' = H'\), which is a contradiction. ◻

Lemma 6. If the conditions of Theorem 1 are satisfied, then the following hold:

  1. \(M\trianglelefteq P_1\),

  2. \(\llbracket G, M\rrbracket^{P_1} = \{e\}\),

  3. \([\langle\!\langle G\rangle\!\rangle^{P_1}, M] = \{e\}\),

  4. \([P_1, P]\subseteq M\),

  5. \([G, P_1]\subseteq G'[G, P]\).

Proof. Proof of (a). It follows from:

  1. the fact that \(P_1 = GP\),

  2. the fact that the normalizer \(N_{P_1}(M)\) of \(M\) in \(P_1\) contains \(P\), because \(M\trianglelefteq P\), and

  3. the fact that the normalizer \(N_{P_1}(M)\) of \(M\) in \(P_1\) contain \(G\), because \(M\) is \(G\)-invariant.

Proof of (b). It follows from the fact that \([G, M] = \{e\}\).

Proof of (c). It follows from Part (b) and Lemma 4.

Proof of (d). From the facts that \(M\) is a \(G\)-invariant subgroup of \(P\), \([P : M]\leq p\), and Lemma 2, we obtain \(GM = G\ltimes M\) and \([P_1 : GM] = [P : M]\leq p\), which implies \(P_1'\subseteq GM = G\ltimes M\). Therefore, from \(P_1'\subseteq G\ltimes M\) and \(P\trianglelefteq P_1\), it follows that \([P_1, P]\subseteq P\) and \[[P_1, P] = \underbrace{[P_1, P]}_{\subseteq P_1'\subseteq G\ltimes M}\cap P\subseteq (G\ltimes M)\cap P = M.\]

Proof of (e). It follows from Lemma 3(a), the fact that \(P_1 = GP\), and the fact that \([G, P]\) is a \(G\)-invariant subgroup of \(P\). ◻

Lemma 7. Consider any \(p\)-group \(G\) and any \(G\)-group \(P\), let \(P_1 := G \ltimes P\) denotes the respective semidirect product. Consider any \(G\)-invariant subgroup \(H\) of \(P\). Denote \(H_1 := GH \overset{\text{Lem. }\ref{lemma2}}{=}G\ltimes H\). Then:

  1. \([G, H]\trianglelefteq H_1\),

  2. \(\gamma_2^G(H)\) is a \(G\)-invariant subgroup of \(P\),

  3. \(H_1' = G'\gamma_2^G(H) = G'\ltimes\gamma_2^G(H)\),

  4. \(H_1' \cap P = \gamma_2^G(H) \subseteq H\).

Proof. Proof of (a). It follows from [9] (see also [10], [11]).

Proof of (b). From \(H\trianglelefteq H_1\), we obtain \(H'\trianglelefteq H_1\) and \(G\subseteq N_{H_1}(H')\cap N_{H_1}(H)\). Therefore, for any element \(g\in G\), we have that \[(\gamma_2^G(H))^g = ([G, H]H')^g = [G^g, H^g](H')^g = [G, H]H' = \gamma_2^G(H).\]

Proof of (c). This follows by applying [12] to the semidirect product \(H_1 = G \ltimes P\).

Proof of (d). Applying Part (c), we get \(H_1'\cap P = \gamma_2^G(H)\). To prove the final inclusion, note that \(\gamma_2^G(H) \subseteq H\) holds from the fact that \(H\) is \(G\)-invariant. ◻

Lemma 8. In the situation of Theorem 1, consider any \(G\)-invariant subgroup \(H\) of \(P\) such that \([P : H] = p\). Denote \(H_1 := GH \overset{\text{Lem. }\ref{lemma2}}{=}G\ltimes H\) and \(X := \{x \in H_1 \mid [x, P_1] \subseteq H_1'\}\). Then:

  1. The set \(X\) is a subgroup of \(H_1\) that is normal in \(P_1\).

  2. In the case when \(H\not= M\), at least one of the following holds:

    1. \(H_1' = P_1'\),

    2. the set \(X\) is a proper subgroup of \(H_1\) that contains \(G \gamma_2^G(H) \overset{\text{Lems. }\ref{lemma2}\text{ and }\ref{lem9}\text{(b)}}{=} G\ltimes \gamma_2^G(H)\).

  3. In the case when \(H_1'\subsetneq P_1'\) and \(X\cap H\subsetneq H\), we have that \(b_{H_1}(h) \leq b_{P_1}(h) - 1\) for all \(h \in H \setminus X\).

  4. \(\gamma_2^G(P) = \gamma_2^G(H)\circ [x, P_1]\), \(\forall x\in P\setminus H\) (here \(A\circ B := \{ab\;\vert\;a\in A, b\in B\}\) for each subsets \(A, B\) of \(P_1\)).

Proof. Proof of (a). From \([P : H] = p\), we get \([P_1 : H_1] = [P : H] = p\). Therefore, \(H_1 \trianglelefteq P_1\), which implies \(H_1' \trianglelefteq P_1\). Consider the natural homomorphism of factorization \(\pi : P_1 \to P_1/H_1'\). Then we can express \(X\) as \[X = \pi^{-1}(Z(\pi(P_1))) \cap H_1,\] which is clearly a subgroup of \(H_1\). From \(H_1, \pi^{-1}(Z(\pi(P_1)))\trianglelefteq P_1\), we have that \(X\trianglelefteq P_1\).

Proof of (b). Assume that \(H_1' \subsetneq P_1'\), then Property (ii) holds due to the following arguments:

  1. From (a), it follows that \(X\) is a subgroup of \(H_1\).

  2. From Lemma 3(a), Lemma 6(b), and the facts that \(H\not= M\), \([P : H] = [P : M] = p\), it follows that \(P = HM\) and: \[[G, H] \subseteq [G, P] = [G, HM] \subseteq [G, H]\llbracket G, M\rrbracket^{P_1} = [G, H]\]

    and, therefore, \[[G, P] = [G, H].\label{equationPH}\tag{1}\]

  3. \(X\) is a proper subgroup of \(H_1\): this follows directly from Lemma 5.

  4. \(X\) contains \(G\): from Lemma 6(e) and (4.1), we obtain \[\begin{align} [G, P_1] &\subseteq G'[G, P] \subseteq H_1'[G, P] =\\ &= [G, P]H_1' = [G, H]H_1' = H_1'. \end{align}\]

  5. It contains \(\gamma_2^G(H)\): Since \([P_1 : H_1] = [P : H] = p\), we have \(H_1 \trianglelefteq P_1\), which implies \(H_1' \trianglelefteq P_1\). So \([H_1', P_1]\subseteq H_1'\), \(\gamma_2^G(H) = [G, H]H'\subseteq H_1'H' \subseteq H_1'\), and \[[\gamma_2^G(H), P_1] \subseteq [H_1', P_1] \subseteq H_1'.\]

  6. Therefore, it contains the product \(G \gamma_2^G(H)\).

Proof of (c). Consider any element \(h\in H\) such that \(b_{H_1}(h) > b_{P_1}(h) - 1\). Since \(H_1 \subseteq P_1\), it is easy to see that then \(b_{H_1}(h) = b_{P_1}(h)\), which implies \([h, P_1] = [h, H_1]\subseteq [H, H_1]\subseteq H_1'\), i.e. that \(h\in X\).

Proof of (d). Consider any element \(x\in P\setminus H\). From the proof of [8] and the facts that \([P_1 : H_1] = [P : H] = p\) and \(x\in P\setminus H\subseteq P_1\setminus H_1\), it follows that \[P_1' = H_1'\circ [x, P_1],\text{ where }A\circ B := \{ab\;\vert\;a\in A, b\in B\}\text{ for each subsets }A, B\text{ of }P_1.\label{eqphx}\tag{2}\]

Therefore, from 2 , Lemma 7(c) (applied to \(P, H\subseteq P\)), Lemma 7(b) (applied to \(H\subseteq P\)), and Lemma 2, it follows that \[\begin{align}&\gamma_2^G(P) = P_1'\cap P = (H_1'\circ [x, P_1])\cap P = \\ &= ((P'\gamma_2^G(H))\circ [x, P_1])\cap P = ((P'\ltimes\gamma_2^G(H))\circ [x, P_1])\cap P = \gamma_2^G(H)\circ [x, P_1].\end{align}\] ◻

Lemma 9. Consider any \(p\)-group \(\widetilde{G}\) and any its normal subgroups \(G_1, G_2\) such that \(G_1G_2 = \widetilde{G}\). Let \(C\) be a maximal subgroup of \(G_2\). Assume that \([G_1, C] = \{e\}\) and \(C\) is a normal subgroup of \(\widetilde{G}\). Then \([G_1, x] = [G_1, G_2]\) for each element \(x\in G_2\setminus C\).

Proof. Consider any element \(x\in G_2\setminus C\). Consider the natural homomorphism of factorization \(\pi : \widetilde{G}\to\widetilde{G}/C\) (\(C\trianglelefteq \widetilde{G}\) by the assumptions of the lemma). From \(G_2\trianglelefteq\widetilde{G}\) and \([G_2 : C] = p\), we obtain \(\pi(G_2)\trianglelefteq\pi(\widetilde{G})\) and \(|\pi(G_2)| = p\), therefore, \(\pi(G_2)\subseteq Z(\pi(\widetilde{G}))\) and \([\pi(G_2), \pi(\widetilde{G})] = \{e\}\). So, combining \([G_1, C] = \{e\}\) and \([\pi(G_2), \pi(\widetilde{G})] = \{e\}\), we obtain \[[\widetilde{G}, G_2]\subseteq\ker\pi = C\subseteq Z_{\widetilde{G}}(G_1).\label{eqgg2}\tag{3}\]

We have that \([G_1, x]\) is a normal subgroup of \(\widetilde{G}\), because:

  1. \([G_1, x]\) is a subgroup of \(\widetilde{G}\), because: \[\forall a, b\in G_1,\quad [a, x][b, x] = (\underbrace{[a, x]}_{\mathclap{\in [\widetilde{G}, G_2]\underset{\eqref{eqgg2}}{\subseteq} Z_{\widetilde{G}}(G_1)}})^b[b, x] = [ba, x].\]

  2. \([G_1, x]\trianglelefteq \widetilde{G}\), because:\[\begin{align} g\in G_1,\;\forall y\in \widetilde{G},\quad [g, x]^y &= [g^y, x^y] = [g^y, x[x^{-1}, y]] =\\ &= [g^y, x]\underbrace{[\overbrace{g^y}^{\in G_1}, \underbrace{[x^{-1}, y]}_{\mathclap{\in [G_2, \widetilde{G}]\underset{\eqref{eqgg2}}{\subseteq} Z_{\widetilde{G}}(G_1)}}]^x}_{\mathclap{\subseteq [G_1, Z_{\widetilde{G}}(G_1)]^x = \{e\}}} = [\underbrace{g^y}_{\in G_1}, x]\in [G_1, x]. \end{align}\]

Obviously, \([G_1, G_2]\supseteq [G_1, x]\), so after the factorization \(\widetilde{G}\to \widetilde{G}/[G_1, x]\), we may reduce this lemma to the case \([G_1, x] = \{e\}\). From \([G_1, x] = [G_1, C] = \{e\}\), the facts that \(C\trianglelefteq \widetilde{G}\), \(G_2 = \langle x\rangle C\), and Lemma 3(a), we obtain \(\langle x\rangle\subseteq Z_{\widetilde{G}}(G_1)\) and \[[G_1, G_2] = [G_1, \langle x\rangle C] \subseteq [G_1, \langle x\rangle]\llbracket G_1, C\rrbracket^{\langle x\rangle} = \{e\}\subseteq [G_1, x]\subseteq [G_1, G_2].\] ◻

Lemma 10. Consider any \(p\)-group \(A\) and any its normal subgroup \(N\). Then there exists a sequence of normal subgroups \(N_i\), \(0\leq i\leq \log_p|N|\) of \(A\) such that:

  1. \(N_i\subseteq N\), \(\forall 0\leq i\leq \log_p|N|\),

  2. \(N_i\subseteq N_{i+1}\), \(\forall 0\leq i\leq \log_p|N| - 1\),

  3. \(N_0 = \{e\}\),

  4. \(N_{\log_p|N|} = N\),

  5. \([N_{i+1} : N_i] = p\), \(\forall 0\leq i\leq\log_p|N| - 1\),

  6. \([A, N_{i+1}]\subseteq N_i\), \(\forall 0\leq i\leq\log_p|N| - 1\).

Proof. The proof is by induction on \(|N|\). The base case \(|N| = 1\) is trivial. Induction step: Assume that \(|N|>1\). From \(N\trianglelefteq A\) it follows that \(N\cap Z(A)\not=\{e\}\) and there exists an element \(e\not= x\in N\cap Z(G)\) such that \(x^p = e\). After the application of the induction hypothesis to \(A/\langle x\rangle\), we get that there exists a sequence \(K_i\), \(0\leq i\leq \log_p|N| - 1\) of normal subgroups of \(A/\langle x\rangle\) that satisfies Properties 1 – 6 for \(A/\langle x\rangle\) and \(N/\langle x\rangle\trianglelefteq A/\langle x\rangle\). Easy to check that \(N_0 := \{e\}\), \(N_i := \langle x\rangle K_{i-1}\), \(\forall 1\leq i\leq\log_p|N|\) satisfies Properties 1 – 6 of the lemma. ◻

4.1 Proof of Theorem 1↩︎

We proceed by induction on the order \(|P|\) of the \(G\)-group \(P\). The base case \(|P| = 1\) is trivial. Consider any \(G\)-group \(P\) of order \(\geq p\) and assume that the statement is proved for all smaller \(G\)-groups \(P\).

Assume that \(P/\gamma_2^G(P)\) is cyclic (\(P'\subseteq \gamma_2^G(P)\subseteq P\), so \(\gamma_2^G(P)\trianglelefteq P\)).

From Lemmas 2 and [lemy](b), it follows that \(\gamma_2^G(P)\) is a \(G\)-invariant subgroup of \(P\) and \(G\gamma_2^G(P) = G\ltimes \gamma_2^G(P)\). From Definitions 7 and 8, it follows that there exist two proper subgroups \(Q_1, Q_2\) of \(P\) such that \(\gamma_2^G(P) \subseteq Q_1 \cap Q_2\) and \[b_{P_1}(x) \leq \mathcal{M}^G(P), \quad \forall x \in P\setminus (Q_1 \cup Q_2).\]

Since \(\gamma_2^G(P) \subseteq Q_1 \cap Q_2\) and the quotient group \(P/\gamma_2^G(P)\) is cyclic, we have \(Q_1 \cup Q_2 \subseteq Q\), where \(Q\) is the unique maximal subgroup of \(P\) containing \(\gamma_2^G(P)\). Therefore, \[b_{P_1}(x) \leq \mathcal{M}^G(P), \quad \forall x\in P\setminus Q. \label{eq1}\tag{4}\]

Consider any element \[a\in P\setminus (Q\cup M)\label{eqelx}\tag{5}\] (such an element exists since a group \(P\) cannot be covered by its two proper subgroups \(Q\) and \(M\)). Combining the facts that \(a\in P\setminus Q\) and 4 , we obtain \[b_{P_1}(a)\leq\mathcal{M}^G(P).\label{eqclm}\tag{6}\]

From Lemma 7(a) applied to \(P\subseteq P\), we obtain \([G, P]\trianglelefteq P_1\). Consider the natural homomorphism of factorization \(\pi : P_1\to P_1/[G, P]\). From \(\pi(P)/\pi(P)' = \pi(P/P') = P/([G, P]P') = P/\gamma_2^G(P)\) – is a cyclic group, it follows that \(\pi(P)\) – is a cyclic group and, therefore, \(\pi(P') = \pi(P)' = \{e\}\), which implies \(P'\subseteq\ker\pi = [G, P]\) and \[\gamma_2^G(P) = [G, P]P' = [G, P].\label{eqpker}\tag{7}\]

From Lemma 6(c), we get \([\langle\!\langle G\rangle\!\rangle^{P_1}, M] = \{e\}\). Therefore, after the application of Lemma 9 to \(\widetilde{G} := P_1\), \(G_1 := \langle\!\langle G\rangle\!\rangle^{P_1}\), \(G_2 := P\), \(C := M\), \(x := a\), we get that \([\langle\!\langle G\rangle\!\rangle^{P_1}, a] = [\langle\!\langle G\rangle\!\rangle^{P_1}, P]\) and, therefore, \[\log_p|[\langle\!\langle G\rangle\!\rangle^{P_1}, P]| = \log_p|[\langle\!\langle G\rangle\!\rangle^{P_1}, a]|\leq \log_p|[P_1, a]| = b_{P_1}(a).\label{equationsublemma2}\tag{8}\]

Combining 6 , 7 , and 8 , we obtain \[\log_p|\gamma_2^G(P)| = \log_p|[G, P]|\leq \log_p|[\langle\!\langle G\rangle\!\rangle^{P_1}, P]| \leq b_{P_1}(a) \leq \mathcal{M}^G(P).\label{equationlemma}\tag{9}\]

From \(P'\subseteq \gamma_2^G(P)\subseteq P\) and Lemma 7(b) it follows that \(\gamma_2^G(P)\) is a normal and \(G\)-invariant subgroup of \(P\). So \(P, G\subseteq N_{P_1}(\gamma_2^G(P))\) and \(\gamma_2^G(P)\trianglelefteq GP = P_1\). Therefore, from Lemma 10 applied to \(\gamma_2^G(P)\trianglelefteq P_1\), it follows that there exists a sequence \(K_j\), \(0\leq j\leq \log_p|\gamma_2^G(P)|\) of normal subgroups of \(P_1\) such that:

  1. \(K_j\subseteq \gamma_2^G(P)\), \(\forall 0\leq j\leq \log_p|\gamma_2^G(P)|\),

  2. \(K_j\subseteq K_{j+1}\), \(\forall 0\leq j\leq \log_p|\gamma_2^G(P)| - 1\),

  3. \(K_0 = \{e\}\),

  4. \(K_{\log_p|\gamma_2^G(P)|} = \gamma_2^G(P)\),

  5. \([K_{j+1} : K_j] = p\), \(\forall 0\leq j\leq \log_p|\gamma_2^G(P)| - 1\),

  6. \([P_1, K_{j+1}]\subseteq K_j\), \(\forall 0\leq j\leq \log_p|\gamma_2^G(P)| - 1\).

We will prove that the sequence \(C_i\), \(0\leq i\leq \log_p|\gamma_2^G(P)| + 1\) of subgroups of \(P\), defined as \[\begin{align} C_0 &:= P\\ C_i &:= K_{\log_p|\gamma_2^G(P)|- i + 1},\quad \forall 1\leq i\leq \log_p|\gamma_2^G(P)| + 1 \end{align}\label{eqCK}\tag{10}\] is a \(G\)-central series of \(P\) that satisfies Properties 1 and 2 of Conjecture 1, which would complete the proof for the case of cyclic \(P/\gamma_2^G(P)\). This follows from:

  1. \(C_i\), \(0\leq i\leq \log_p|\gamma_2^G(P)| + 1\) is a \(G\)-central series of \(P\) that satisfies Property 1 of Conjecture 1, because from 10 and Properties (2), (3), (4), (6) of \(K_j\) we obtain:

    1. \(C_0 = P\),

    2. \(C_{\log_p|\gamma_2^G(P)| + 1} = K_0 = \{e\}\),

    3. \(C_1 \subseteq P = C_0\)

    4. \(C_{i+1} = K_{\log_p|\gamma_2^G(P)| - i}\subseteq K_{\log_p|\gamma_2^G(P)| - i + 1} = C_i\), \(\forall 1\leq i\leq \log_p|\gamma_2^G(P)|\),

    5. \([G, C_0] = [G, P]\subseteq \gamma_2^G(P) = K_{\log_p|\gamma_2^G(P)|} = C_1\),

    6. \([G, C_i] = [G, K_{\log_p|\gamma_2^G(P)| - i + 1}]\subseteq [P_1, K_{\log_p|\gamma_2^G(P)| - i + 1}]\subseteq\)

      \(\subseteq [P_1, K_{\log_p|\gamma_2^G(P)| - i}] = C_{i+1}\), \(\forall 1\leq i\leq \log_p|\gamma_2^G(P)|\),

    7. \(C_0 = P\),

    8. \(C_1 = K_{\log_p|\gamma_2^G(P)|} = \gamma_2^G(P)\),

    9. \(C_{\log_p|\gamma_2^G(P)| + 1} = K_0 = \{e\}\).

  2. \(C_i\), \(0\leq i\leq \log_p|\gamma_2^G(P)| + 1\) satisfies Property 2 of Conjecture 1, because:

    1. in the case when \(\log_p|\gamma_2^G(P)| = 0\), there is no such \(1\leq i\leq \log_p|\gamma_2^G(P)|\) and Property 2 of Conjecture 1 is trivially satisfied,

    2. in the case when \(\log_p|\gamma_2^G(P)| > 0\), from Property (5), 9 , and 10 it follows that \(\forall 1\leq i\leq \log_p|\gamma_2^G(P)|\),\[\begin{align} \log_p[C_i : C_{i+1}] &= \log_p[K_{\log_p|\gamma_2^G(P)|- i + 1} : K_{\log_p|\gamma_2^G(P)|- i}] = 1\leq\\ &\leq \log_p|\gamma_2^G(P)|- i + 1\leq \mathcal{M}^G(P) - i + 1.\end{align}\]

This concludes the case where \(P/\gamma_2^G(P)\) is cyclic.

Assume that \(P/\gamma_2^G(P)\) is non-cyclic (\(P'\subseteq \gamma_2^G(P)\subseteq P\), so \(\gamma_2^G(P)\trianglelefteq P\)).

Consider any two maximal subgroups \(C_1, C_2\) of \(P\) such that:

  1. The following hold:

    1. \(C_1, C_2\) are \(G\)-invariant,

    2. \(\gamma_2^G(P)\subseteq C_1\cap C_2\),

    3. \(\{x\in P \mid b_{P_1}(x) > \mathcal{M}^G(P)\}\subseteq C_1\cup C_2\).

    Such subgroups exist by the definition of \(\mathcal{M}^G(P)\) and from the fact that each proper subgroup of \(P\) containing \(\gamma_2^G(P)\) is contained in a maximal subgroup of \(P\) which also contains \(\gamma_2^G(P)\) (which is therefore \(G\)-invariant).

  2. \(C_1 \neq C_2\). These exist, because, if \(C_1 = C_2\) in Property i), then, from the fact that \(P\gamma_2^G(P)\) is non-cyclic, we can replace \(C_2\) with \(C_2^*\), where \(C_2^*\) is any maximal subgroup of \(P\) containing \(\gamma_2^G(P)\) (which is therefore \(G\)-invariant) and is different from \(C_1\).

Consider any maximal subgroup \(H\) of \(P\) such that:

  1. \(C_1 \cap C_2 = H \cap C_1 = H \cap C_2 = H\cap (C_1\cup C_2)\),

  2. \(H\not= M\).

Such a group exists since \(p>2\), \(P/(C_1\cap C_2)\cong \mathbb{Z}_p^2\), and \(M\subsetneq P\). From \(\gamma_2^G(P)\subseteq C_1\cap C_2 = H\cap C_1 \subseteq H\subseteq P\), it follows that \(H\) is a \(G\)-invariant subgroup of \(P\) and contains \(\gamma_2^G(P)\). Therefore, from Lemma 2, we get \(H_1 := GH \overset{\text{Lem. }\ref{lemma2}}{=} G\ltimes H\). From \([P : H] = p\), \([P : C_1\cap C_2] = p^2\), it follows that \([H : C_1\cap C_2] = p\) and \(C_1\cap C_2\) is a proper subgroup of \(H\).

We now prove the following two properties of \(H\):

  1. \(\mathcal{M}^G(H) \leq \begin{cases} \mathcal{M}^G(P) & \text{if } H_1' = P_1', \\ \mathcal{M}^G(P) - 1 & \text{if } H_1' \subsetneq P_1', \end{cases}\)

  2. \(\log_p|\gamma_2^G(P)|\leq\begin{cases} \log_p|\gamma_2^G(H)| & \text{if } H_1' = P_1', \\ \log_p|\gamma_2^G(H)| + \mathcal{M}^G(P) & \text{if } H_1' \subsetneq P_1'. \end{cases}\)

Proof of A1 and A2 in the case when \(H_1' = P_1'\).

  • Proof of A1. From the definition of \(C_1, C_2\) and the fact that \(H\setminus (C_1\cap C_2) = H\setminus (H\cap (C_1\cup C_2)) = H\setminus (C_1\cup C_2) \subseteq P\setminus (C_1\cup C_2)\) we obtain \[\begin{align} &\gamma_2^G(H)\subseteq \gamma_2^G(P)\subseteq C_1\cap C_2\text{ and} \\ &b_{H_1}(h) \leq b_{P_1}(h) \leq \mathcal{M}^G(P),\quad\forall h \in H \setminus (C_1 \cap C_2). \end{align}\]

    Therefore, the set \(\{h \in H \mid b_{H_1}(h) > \mathcal{M}^G(P)\}\) can be covered by two coinciding proper subgroups \(A = B = C_1 \cap C_2\) of \(H\), which contain \(\gamma_2^G(H)\).

  • Item A2 follows from \(H_1' = P_1'\) and Lemma [lem10](d) applied to \(P\subseteq P\) and to \(H\subseteq P\): \[\log_p|\gamma_2^G(P)| = \log_p|P_1'\cap P| = \log_p|H_1'\cap P| = \log_p|\gamma_2^G(H)|.\]

Proof of A1 and A2 in the case when \(H_1' \subsetneq P_1'\). Denote \(X := \{x \in H_1 \mid [x, P_1] \subseteq H_1'\}\). By Lemma [lem4](a, b) \[G\gamma_2^G(H)\subseteq X\subsetneq H_1\text{ and }X\trianglelefteq P_1.\label{eqXH}\tag{11}\]

We have that \(H\nsubseteq X\), since otherwise, \(X\) would be a proper subgroup of \(H_1\) containing both \(G\) and \(H\), which contradicts to \(H_1 = GH\). From Lemma [lem5](c), we obtain \(b_{H_1}(h) \leq b_{P_1}(h) - 1\) for all \(h \in H\setminus X\). Thus, from the fact that \(H\setminus (X\cup (C_1\cap C_2))\subseteq H\setminus (\underbrace{C_1\cap C_2}_{\mathclap{ = H\cap (C_1\cup C_2)}}) = H\setminus (C_1\cup C_2)\subseteq P\setminus (C_1\cup C_2)\) and the definition of \(C_1, C_2\), it follows that \[b_{H_1}(h) \leq b_{P_1}(h) - 1 \leq \mathcal{M}^G(P) - 1, \quad \forall h \in H \setminus (X \cup (C_1 \cap C_2)).\]

Therefore, the set \(\{h \in H \mid b_{H_1}(h) > \mathcal{M}^G(G) - 1\}\) is covered by two subgroups \(X\cap H\) and \(C_1 \cap C_2\) of \(H\). From the definition of \(C_1, C_2\), we have \(\gamma_2^G(H)\subseteq \gamma_2^G(P)\subseteq C_1\cap C_2\), therefore, from \(H\nsubseteq X\), \([H : C_1\cap C_2] = p\), and 11 , it follows that \(X\cap H\) and \(C_1\cap C_2\) are proper subgroups of \(H\) that contain \(\gamma_2^G(H)\). Hence, \(\mathcal{M}^G(H) \leq \mathcal{M}^G(P) - 1\), and A1 is proved.

To prove A2, consider any element \(a\in P\setminus (H\cup C_1\cup C_2)\) (such an element exists from the fact that each non-trivial \(p>2\) -group cannot be covered by any its three proper subgroups). From \(a\in P\setminus (H\cup C_1\cup C_2)\subseteq P\setminus (C_1\cup C_2)\) and the definition of \(C_1, C_2\), we obtain \[b_{P_1}(a)\leq \mathcal{M}^G(P).\label{equationx2}\tag{12}\]

From Lemma [lemmaX](d) applied to \(H\subseteq P\), \(a\in P\setminus H\), and 12 , it follows that \[\begin{align} \log_p|\gamma_2^G(P)| &= \log_p|\gamma_2^G(H)\circ [a, P_1]|\leq\\&\leq \log_p|\gamma_2^G(H)| + \log_p|[a, P_1]| =\\&= \log_p|\gamma_2^G(H)| + b_{P_1}(a)\leq \log_p|\gamma_2^G(H)| + \mathcal{M}^G(P). \end{align}\label{equationx1}\tag{13}\]

Therefore, A1 and A2 are proved.

We are now ready to complete the proof in the case when \(P/\gamma_2^G(P)\) is non-cyclic.

From the induction hypothesis applied to the \(G\)-group \(H\) and its normal and \(G\)-invariant subgroup \(M\cap H\), it follows that there exists a \(G\)-central series \(K_i\), \(0\leq i\leq N\) of \(H\) such that: \(K_0 = H\), \(K_1 = \gamma_2^G(H)\), \(K_N = \{e\}\), and \[\log_p[K_i : K_{i+1}]\leq \mathcal{M}^G(H) - i + 1,\;\forall 1\leq i\leq N - 1.\label{eqK}\tag{14}\]

Let us analyze the two possible cases:

Case 1. Consider the case when \(H_1' = P_1'\). From Lemma 7(d) and \(P_1' = H_1'\), we obtain \[\gamma_2^G(P) = P_1'\cap P = H_1'\cap P = \gamma_2^G(H).\label{equationcpk}\tag{15}\]

We will prove that the sequence \(C_i\), \(0\leq i\leq N\) of subgroups of \(P\), defined as \[\begin{align} C_0 &:= P\\ C_i &:= K_i,\quad \forall 1\leq i\leq N \end{align}\label{equationcpn}\tag{16}\] is a \(G\)-central series of \(P\) that satisfies Properties 1 and 2 of Conjecture 1, which would complete the proof for the case of non-cyclic \(P/\gamma_2^G(P)\). This is because from 14 , 15 , 16 , and A1, we obtain:

  1. \(P = C_0\supseteq \gamma_2^G(P) = \gamma_2^G(H) = K_1 \supseteq K_2 = C_2\supseteq\ldots\supseteq K_N = C_N = \{e\}\),

  2. \([G, C_0] = [G, P]\subseteq \gamma_2^G(P) = \gamma_2^G(H) = K_1 = C_1\),

  3. \([G, C_i] = [G, K_i]\subseteq K_{i+1} = C_{i+1}\), \(\forall 1\leq i\leq N - 1\),

  4. \(C_0 = P\),

  5. \(C_1 = K_1 = \gamma_2^G(H) = \gamma_2^G(P)\),

  6. \(C_N = K_N = \{e\}\).

  7. \(\log_p[C_i : C_{i+1}] = \log_p[K_i : K_{i+1}]\leq \mathcal{M}^G(H) - i + 1 \leq \mathcal{M}^G(P) - i + 1\), \(\forall 1\leq i\leq N\).

Case 2. Consider the case when \(H_1' \subsetneq P_1'\). We will prove that the sequence \(C_i\), \(0\leq i\leq N + 1\) of subgroups of \(P\), defined as \[\begin{align} C_0 &:= P\\ C_1 &:= \gamma_2^G(P)\\ C_i &:= K_{i-1},\quad \forall 2\leq i\leq N + 1 \end{align}\label{equationcpm}\tag{17}\] is a \(G\)-central series of \(P\) that satisfies Properties 1 and 2 of Conjecture 1, which would complete the proof for the case of cyclic \(P/\gamma_2^G(P)\). This is because from 14 , 17 , A1, and A2, we obtain:

  1. \(P = C_0\supseteq \gamma_2^G(P) = C_1\supseteq\gamma_2^G(H) = K_1 = C_2\supseteq K_2 = C_3\supseteq\ldots\supseteq K_N = C_{N+1} = \{e\}\),

  2. \([G, C_0] = [G, P]\subseteq \gamma_2^G(P) = C_1\),

  3. \([G, C_1] = [G, \underbrace{\gamma_2^G(P)}_{\subseteq H}] \subseteq [G, H]\subseteq \gamma_2^G(H) = K_1 = C_2\),

  4. \([G, C_i] = [G, K_{i-1}]\subseteq K_i = C_{i+1}\), \(\forall 2\leq i\leq N\),

  5. \(C_0 = P\),

  6. \(C_1 = \gamma_2^G(P)\),

  7. \(C_{N + 1} = K_N = \{e\}\),

  8. \(\log_p[C_1 : C_2] = \log_p[\gamma_2^G(P) : K_1] = \log_p[\gamma_2^G(P) : \gamma_2^G(H)]\leq \mathcal{M}^G(P)\),

  9. \(\log_p[C_i : C_{i+1}] = \log_p[K_{i-1} : K_i]\leq \mathcal{M}^G(H) - (i-1) + 1\leq \mathcal{M}^G(P) - i + 1\), \(\forall 2\leq i\leq N\).

This finishes the proof of Theorem 1. \(\square\)

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