Quantitative Stability of First Laplacian Eigenstates for the Incompressible Euler Equation on a Flat 2-Torus


Abstract

In this paper, we establish quantitative estimates for the orbital stability of the first Laplacian eigenstates of the incompressible Euler equation on a two-dimensional flat torus. We focus mainly on the hexagonal torus, where the first Laplacian eigenspace has a more intricate structure and the Casimir functionals may exhibit strong degeneracy at special amplitude and phase configurations. The main novelty of the proof is to reduce the estimates for the amplitude parameters of the perturbed solution to a root-stability problem for a cubic polynomial under coefficient perturbations, thereby overcoming the strong degeneracy in an effective way. These estimates appear to indicate that stronger degeneracy in the amplitude-phase configuration leads to weaker stability.

1 Introduction↩︎

1.1 Motivation↩︎

Let \(\Lambda\) be a two-dimensional lattice; that is, there exist two linearly independent vectors \(\boldsymbol{\xi}, \boldsymbol{\eta}\in\mathbb{R}^2\) such that \[\Lambda = \left\{ m \boldsymbol{\xi} + n \boldsymbol{\eta} \mid m, n \in \mathbb{Z} \right\}.\] The pair \((\boldsymbol{\xi}, \boldsymbol{\eta})\) is called a basis of \(\Lambda\). Consider the flat 2-torus \(\mathbb{T}_\Lambda:=\mathbb{R}^2/\Lambda\) and the incompressible Euler equation on \(\mathbb{T}_\Lambda\) in vorticity form: \[\label{euler} \left\{ \begin{align} &\partial_t \omega + \nabla^\perp\psi \cdot \nabla \omega = 0, \qquad t \in \mathbb{R},\;\mathbf{x} = (x_1,x_2) \in \mathbb{T}_\Lambda,\\ &\psi= (-\Delta)^{-1}\omega, \end{align} \right.\tag{1}\] where \(\omega\) is the scalar vorticity, \(\psi\) is the stream function, and \(\nabla^\perp:= (\partial_{x_2}, -\partial_{x_1})\). Note that \(\omega\) is assumed to have mean zero to ensure that \(\psi\) is well defined. The global well-posedness theory for 1 has been well developed in various function spaces [1][4]. In particular, global well-posedness holds in the class of mean-zero \(C^1\) functions. However, a comprehensive theory describing the evolution of solutions remains far from complete [5]. Among the many problems concerning evolution, a fundamental one is to study the long-time behavior of solutions near various steady states.

In this paper, we study the Lyapunov stability of a class of steady states, referred to as Laplacian eigenstates, whose stream functions are given by eigenfunctions of the following Laplacian eigenvalue problem: \[\require{physics} \label{lep} \begin{cases} -\Delta u = \lambda u, & \mathbf{x} \in \mathbb{T}_\Lambda,\\ \displaystyle \int_{\mathbb{T}_\Lambda} u \, \dd{\mathbf{x}} = 0. \end{cases}\tag{2}\] Note that all eigenfunctions of 2 are sinusoidal and can be obtained by computing the dual lattice of \(\Lambda\). For the first eigenspace, denoted by \(\mathbf{E}_1\), the following properties hold (see [6]):

  • The dimension of \(\mathbf{E}_1\) is either \(2\), \(4\), or \(6\).

  • \(\dim(\mathbf{E}_1) = 6\) if and only if \(\mathbb{T}_\Lambda\) is a hexagonal torus; that is, \(\Lambda\) admits a basis \((\boldsymbol{\xi}, \boldsymbol{\eta})\) such that \[|\boldsymbol{\xi}| = |\boldsymbol{\eta}|, \quad \angle(\boldsymbol{\xi}, \boldsymbol{\eta}) = \pi/3.\]

  • If \(\mathbb{T}_\Lambda\) is a hexagonal torus, then there exist three nonzero vectors \(\mathbf{k}_1, \mathbf{k}_2, \mathbf{k}_3\) satisfying \[|\mathbf{k}_1| = |\mathbf{k}_2| = |\mathbf{k}_3|, \quad \mathbf{k}_3 = \mathbf{k}_1 + \mathbf{k}_2,\] such that \[\label{e1df} \mathbf{E}_1 = \operatorname{span}\left\{ \cos(\mathbf{k}_1 \cdot \mathbf{x}),\, \sin(\mathbf{k}_1 \cdot \mathbf{x}),\, \cos(\mathbf{k}_2 \cdot \mathbf{x}),\, \sin(\mathbf{k}_2 \cdot \mathbf{x}),\, \cos(\mathbf{k}_3 \cdot \mathbf{x}),\, \sin(\mathbf{k}_3 \cdot \mathbf{x}) \right\}.\tag{3}\]

For the square torus, orbital stability (up to translations) of the first Laplacian eigenstates has been established in [7][9], and has recently been extended to flat \(2\)-tori of arbitrary shape in [6].

Theorem A 1 ([6]). Fix \(1<p<\infty\) and \(\bar\omega \in \mathbf{E}_1\). Then, for any \(\varepsilon>0\), there exists \(\delta>0\), depending on \(\bar\omega\) and \(\varepsilon\), such that for any mean-zero \(C^1\) solution \(\omega\) to 1 , \[\|\omega(0,\cdot)-\bar\omega\|_{L^p(\mathbb{T}_\Lambda)}<\delta \quad\Longrightarrow\quad {\rm dist}_p(\omega(t,\cdot),\mathbf{O}_{\bar\omega}) <\varepsilon \quad \forall\,t\in\mathbb{R},\] where \(\mathbf{O}_{\bar\omega}\) denotes the translational orbit of \(\bar\omega\), \[\label{defoforbit} \mathbf{O}_{\bar\omega}:=\left\{\bar\omega(\cdot-\mathbf{p})\mid \mathbf{p}\in\mathbb{T}_{\Lambda}\right\},\qquad{(1)}\] and \({\rm dist}_p\) denotes the \(L^p\) distance.

However, the dependence of \(\delta\) on \(\varepsilon\) remains unknown, except in the special case of the square torus [7]. Our goal in this paper is to provide explicit estimates for this dependence on tori of arbitrary shape.

1.2 Main theorem↩︎

We present only the quantitative estimates for the most delicate hexagonal case as the main theorem below, and postpone the simpler non-hexagonal cases to the final section.

Theorem 1. Let \(\mathbb{T}_\Lambda\) be a hexagonal torus, and let \(\mathbf{E}_1\) be given by 3 . Fix \(\bar{\omega} \in \mathbf{E}_1\) of the form \[\bar \omega(\mathbf{x})=\sum_{i=1}^3A_i\cos(\mathbf{k}_i\cdot \mathbf{x}+\alpha_i),\quad A_i\geq 0,\,\, \alpha_i\in\mathbb{R},\,\, (A_1,A_2,A_3)\neq (0,0,0).\] Then there exist \(\varepsilon_0>0\) and \(C>0\), depending only on \(\Lambda\) and \(\bar\omega\), such that for any \(\varepsilon\in(0,\varepsilon_0)\) and any mean-zero \(C^1\) solution \(\omega(t,\mathbf{x})\) to 1 , it holds that \[{\rm dist}_{2}(\omega(0,\cdot), \mathbf{O}_{\bar\omega}) < \varepsilon \quad\Longrightarrow\quad {\rm dist}_{2}(\omega(t,\cdot), \mathbf{O}_{\bar\omega}) < C \varepsilon^\gamma \quad\text{for all } t \in \mathbb{R},\] where \(\mathbf{O}_{\bar\omega}\) is given by ?? , and \(\gamma\) is determined by \(A_i\) and \(\alpha:=\alpha_1+\alpha_2-\alpha_3\) as follows:

  • \(A_1A_2A_3=0\):

    • If exactly one of \(A_1,A_2,A_3\) is zero, then \(\gamma=\frac{1}{2}\).

    • If exactly two of \(A_1,A_2,A_3\) are zero, then \(\gamma=\frac{1}{4}\).

  • \(A_1A_2A_3\neq 0\):

    • If \(A_1,A_2,A_3\) are pairwise distinct and \(\sin\alpha\neq 0\), then \(\gamma=1\).

    • If \(A_1,A_2,A_3\) are pairwise distinct and \(\sin\alpha=0\), then \(\gamma=\frac{1}{2}\).

    • If exactly two of \(A_1,A_2,A_3\) are equal and \(\sin\alpha\neq 0\), then \(\gamma=\frac{1}{2}\).

    • If exactly two of \(A_1,A_2,A_3\) are equal and \(\sin\alpha=0\), then \(\gamma=\frac{1}{4}\).

    • If \(A_1=A_2=A_3\) and \(\sin\alpha\neq 0\), then \(\gamma=\frac{1}{3}\).

    • If \(A_1=A_2=A_3\) and \(\sin\alpha=0\), then \(\gamma=\frac{1}{6}\).

We give some remarks on Theorem 1 below.

Remark 2. Theorem 1 holds for more general perturbations, not only for \(C^1\) solutions. Indeed, our proof only requires that \(\omega \in C(\mathbb{R}; \mathring L^2(\mathbb{T}_\Lambda))\) (see 7 for the definition of \(\mathring L^2(\mathbb{T}_\Lambda)\)) and that both the kinetic energy \(\mathsf E\) and various Casimir functionals \(\mathsf C_F\) (see 4 and 5 for the definitions) are conserved.

Remark 3. It remains unclear whether the stability exponent \(\gamma\) is optimal, except in case (2-1). This is an interesting but difficult problem for future investigation. Similar issues also arise in [7], [10], [11].

Remark 4. In Remark 8, we will discuss in detail the dependence of the constant \(C\) on the amplitude and phase configuration \((A_1, A_2, A_3,\alpha)\), from which one can see how the exponent \(\gamma\) exhibits a change in order as the amplitude and phase configuration varies.

Remark 5. The table below shows more clearly how the value of \(\gamma\) depends on \((A_1,A_2,A_3,\alpha)\). It follows from the table that stability becomes weaker as the amplitudes become more degenerate, either through vanishing components or through coincidences among \(A_1,A_2,A_3\). When all amplitudes are nonzero, the additional phase degeneracy \(\sin\alpha=0\) further reduces the stability exponent \(\gamma\) by a factor of two. However, this interpretation is only heuristic, since the sharpness of the exponent \(\gamma\) remains unclear. A similar weakening of stability for certain special flow patterns also appears in [7], [10], [11].

Figure 1: image.

Figure 2: image.

1.3 Comments, proof strategy, and novelties↩︎

The Euler equation possesses a rich family of conservation laws, which provides a natural framework for stability analysis. In the case of a flat 2-torus, the following quantities are conserved:

  • The kinetic energy \(\mathsf E\), which in terms of vorticity can be expressed as \[\require{physics} \label{defofe}\mathsf E(\omega)=\frac{1}{2}\int_{\mathbb{T}_\Lambda}\omega\,(-\Delta)^{-1}\omega\dd{\mathbf{x}}\footnote{Although (-\Delta)^{-1}\omega may differ by an arbitrary constant, this integral is well-defined since \omega has mean zero.};\tag{4}\]

  • The Casimir functionals of the form \[\require{physics} \label{defofc} \mathsf C_F(\omega)=\int_{\mathbb{T}_\Lambda}F(\omega)\dd{\mathbf{x}},\tag{5}\] where \(F\in C(\mathbb{R})\). In particular, the \(k\)-th order Casimir \[\require{physics} \label{kcm} \mathsf C_k(\omega):=\int_{\mathbb{T}_\Lambda} \omega^k\dd{\mathbf{x}}\tag{6}\] is conserved, where \(k\) is a positive integer.

In the 1960s, inspired by the Lyapunov function method in ODE theory, Arnold [12], [13] introduced the energy-Casimir (EC) functional and established two types of stability theorems, now known as Arnold’s first and second stability theorems. For Laplacian eigenstates, the associated Casimir is the enstrophy, i.e., the \(L^2\) norm of the vorticity. Using the EC functional method, it can be proved that for any \(\bar\omega \in \mathbf{E}_1\), the first energy shell \[\mathbf{S}_{\bar\omega} := \left\{ v \in \mathbf{E}_1 \;\middle|\; \|v\|_{L^2(\mathbb{T}_{\Lambda})} = \|\bar\omega\|_{L^2(\mathbb{T}_{\Lambda})} \right\}\] is stable with respect to the enstrophy norm. However, this result cannot be improved using only the kinetic energy and the enstrophy, since these quantities do not distinguish between different states in \(\mathbf{S}_{\bar\omega}\). The first refinement was obtained by Wirosoetisno and Shepherd [9] for the square torus. They introduced higher-order Casimirs \(\mathsf C_k,\) \(k=2,4,6\), to distinguish elements of \(\mathbf{S}_{\bar\omega}\), and studied the stability of the translational orbit \(\mathbf{O}_{\bar\omega}\). Nevertheless, their formulation of stability relies on higher-order Casimirs, and complete orbital stability remains unresolved. A complete proof of the stability of \(\mathbf{O}_{\bar\omega}\) for both rectangular and square tori was given in [8], where they used a compactness argument originating from Burton’s work [14], [15], reducing the problem to the equimeasurable partition of the first eigenspace. The stability result in [8] is qualitative, and is measured by the \(L^p\) norm of the vorticity for any \(p\in(1,\infty)\). Later, Elgindi [7] established a quantitative estimate on the stability of \(\mathbf{O}_{\bar\omega}\) for the square torus in the \(L^2\) setting, building on and refining the approach of Wirosoetisno and Shepherd. Similar ideas have since been applied to the orbital stability of Laplacian eigenstates on the sphere [10] or in a disk [11]. Very recently, the result of [8] was extended to tori of arbitrary shape in [6], with the main contribution being the treatment of the hexagonal case.

The proof of Theorem 1 follows the framework introduced in [7], [9] (see also [10], [11] for further developments) and is divided into two main steps:

  • We first establish the quantitative stability of the first eigenspace \(\mathbf{E}_1\). This step mainly relies on the conservation of the kinetic energy and the enstrophy, in combination with proper use of a Poincaré-type inequality.

  • We then estimate the distance between the projection of the perturbed solution onto \(\mathbf{E}_1\) and the translational orbit \(\mathbf{O}_{\bar\omega}\). More specifically, we introduce modified integer-order Casimirs that are globally Lipschitz continuous in \(L^2\) and use them to control the variation of the amplitude and phase parameters. The problem is then reduced to the analysis of a possibly degenerate nonlinear map in finite dimensions.

The first step is standard and follows from an argument similar to that in [11]. The main challenges and differences lie in the second step. First, the structure of the first eigenspace and the characterization of translational orbits within the first eigenspace are more complicated, which makes the analysis of energy and vorticity transfer within it more difficult. Second, the nonlinear map arising in the second step may be highly degenerate at certain special configurations, leading to weaker stability. For example, the stability exponent \(\gamma\) may be as small as \(1/6\) when \(A_1=A_2=A_3\) and \(\sin\alpha=0\), whereas the smallest value of stability exponent appearing in [7], [10], [11] was \(1/2\). This strong degeneracy prevents us from directly applying the previous methods, such as the degenerate inverse function lemma established in [10] and the direct computations carried out in [11]. To overcome these difficulties, we make a key observation: the complicated nonlinear map in the second step can be suitably combined into a polynomial map given by the three elementary symmetric polynomials in three variables. This reduces the estimates for the amplitude parameters to a root-stability problem for a cubic polynomial under perturbations of its coefficients, which can be handled in a straightforward manner; see Lemma 2. Once the estimates for the amplitude parameters have been established, the estimates for the phase parameters can be obtained through careful and intricate computations.

1.4 Organization of the paper↩︎

The remainder of the paper is organized as follows. In Section 2, we establish a quantitative stability estimate for the first eigenspace \(\mathbf{E}_1\). In Section 3, we prove a technical lemma on the quantitative stability of the roots of a polynomial under perturbations of its coefficients. This lemma plays a crucial role in the proof of the main theorem. Section 4 is devoted to the proof of Theorem 1. Finally, in Section 5, we treat the remaining non-hexagonal cases and provide the corresponding quantitative stability results with brief proofs.

2 Quantitative stability of \(\mathbf{E}_1\)↩︎

Denote by \(\mathring L^2(\mathbb{T}_\Lambda)\) the closed subspace of mean-zero functions in \(L^2(\mathbb{T}_\Lambda)\), i.e., \[\require{physics} \label{defoflo} \mathring L^2(\mathbb{T}_\Lambda):=\left\{v\in L^2(\mathbb{T}_\Lambda) \;\middle|\; \int_{\mathbb{T}_\Lambda} v \dd{\mathbf{x}}=0\right\},\tag{7}\] and denote by \(\mathbf{E}_1^\perp\) the orthogonal complement of \(\mathbf{E}_1\) in \(\mathring L^2(\mathbb{T}_\Lambda)\).

Proposition 6. Let \(\omega_t := \omega(t,\cdot)\) be a mean-zero \(C^1\) solution of the Euler equation 1 . Consider the orthogonal decomposition \[\omega_t=v_t+w_t,\quad v_t \in \mathbf{E}_1,\quad w_t \in \mathbf{E}_1^{\perp}.\] Then, for all \(t\in\mathbb{R}\), we have \[\|w_t\|_{L^2(\mathbb{T}_\Lambda)} \leq \sqrt{\frac{\lambda_2}{\lambda_2-\lambda_1}}\, \|w_0\|_{L^2(\mathbb{T}_\Lambda)},\] where \(\lambda_i\) is the \(i\)-th eigenvalue (counted without multiplicity) of 2 .

Remark 7. It is clear that \[{\rm dist}_2\bigl(\omega_t,\mathbf{E}_1\bigr) =\|w_t\|_{L^2(\mathbb{T}_\Lambda)}.\] Therefore, Proposition 6 establishes a quantitative stability estimate for \(\mathbf{E}_1\).

To prove Proposition 6, we need the following Poincaré-type inequality associated with \(\mathbf{E}_1\).

Lemma 1. For any \(v\in \mathbf{E}_1^\perp\), it holds that \[\require{physics} \label{l2} \displaystyle \int_{\mathbb{T}_\Lambda} v\,(-\Delta)^{-1}v \dd{\mathbf{x}} \leq \frac{1}{\lambda_2}\displaystyle \int_{\mathbb{T}_\Lambda} v^2 \dd{\mathbf{x}}.\tag{8}\]

The proof of the above lemma is standard and follows by repeating the argument in [11].

Proof of Proposition 6. Define the energy-Casimir functional \(EC: \mathring L^2(\mathbb{T}_{\Lambda})\to \mathbb{R}\) by \[\require{physics} EC(v):=\int_{\mathbb{T}_\Lambda}v\,(-\Delta)^{-1}v \dd{\mathbf{x}}-\frac{1}{\lambda_1}\int_{\mathbb{T}_\Lambda} v^2\dd {\mathbf{x}},\] which is conserved for any mean-zero \(C^1\) solution of 1 . A straightforward computation yields \[\require{physics} \label{461} EC(\omega_t) =\displaystyle \int_{\mathbb{T}_\Lambda} w_t\,(-\Delta)^{-1}w_t \dd{\mathbf{x}}-\frac{1}{\lambda_1} \displaystyle \int_{\mathbb{T}_\Lambda} w_t^2 \dd{\mathbf{x}}.\tag{9}\] On the other hand, by Lemma 1, we have \[\require{physics} \label{462} \int_{\mathbb{T}_\Lambda} w_t\,(-\Delta)^{-1}w_t \, \dd{\mathbf{x}} \leq \frac{1}{\lambda_2} \displaystyle \int_{\mathbb{T}_\Lambda} w_t^2 \, \dd{\mathbf{x}}.\tag{10}\] From 9 and 10 , we have \[\require{physics} -\frac{1}{\lambda_1} \displaystyle \int_{\mathbb{T}_\Lambda} w_t^2 \dd{\mathbf{x}}\leq EC(\omega_t) \leq \left(\frac{1}{\lambda_2}-\frac{1}{\lambda_1}\right)\int_{\mathbb{T}_\Lambda} {w_t}^2 \dd{\mathbf{x}}.\] Since \(EC\) is conserved, it follows that \[\require{physics} -\frac{1}{\lambda_1}\displaystyle \int_{\mathbb{T}_\Lambda} {w_0}^2 \dd{\mathbf{x}}\leq EC(\omega_0)=EC(\omega_t) \leq \left(\frac{1}{\lambda_2}-\frac{1}{\lambda_1}\right)\displaystyle \int_{\mathbb{T}_\Lambda} {w_t}^2 \dd{\mathbf{x}},\] which implies that \[\require{physics} \displaystyle \int_{\mathbb{T}_\Lambda} {w_t}^2 \dd{\mathbf{x}} \leq \frac{\lambda_2}{\lambda_2-\lambda_1} \displaystyle \int_{\mathbb{T}_\Lambda} {w_0}^2 \dd{\mathbf{x}}.\] The proof is complete. ◻

3 A technical lemma↩︎

Let \(n \ge 2\) be an integer. Denote by \(f_1, \dots, f_n\) the \(n\) elementary symmetric polynomials in \(n\) variables, i.e., \[f_1(\mathbf{a})=\sum_{i=1}^n a_i,\quad f_2(\mathbf{a})=\sum_{1\le i<j\le n} a_i a_j,\quad \dots,\quad f_n(\mathbf{a})=\prod_{i=1}^n a_i,\] where \(\mathbf{a} = (a_1,a_2, \dots, a_n) \in \mathbb{R}^n.\)

The following lemma gives quantitative bounds on \(|b_k-a_k|\) in terms of \(\sum_{i=1}^n |f_i(\mathbf{a}) - f_i(\mathbf{b})|\), and plays a key role in proving the main theorem.

Lemma 2. Let \(\mathbf{a} = (a_1, a_2, \dots, a_n) \in \mathbb{R}^n\), and fix \(k \in \{1,2,\dots,n\}\). Suppose that \(a_k\) appears \(m\) times in the multiset \(\{a_1, a_2, \dots, a_n\}\), i.e., \[\# \left\{ i \in \{1,\dots,n\} \;\middle|\; a_i = a_k \right\}=m.\] Then there exist \(\delta=\delta(\mathbf{a})>0\), and \(C=C(|\mathbf{a}|)>0\), such that for any \(\mathbf{b}\in\mathbb{R}^n\) satisfying \(|b_k- a_k|<\delta,\) \[\left|b_k-a_k\right|^m \le \frac{C}{\rho}\sum_{i=1}^n \left|f_i(\mathbf{a})-f_i(\mathbf{b})\right|, \qquad \rho:=\begin{cases} \prod_{\substack{1\le i\le n\\ a_i\ne a_k}} \left|a_i-a_k\right|,&if 1\leq m<n,\\ 1,&ifm=n. \end{cases}\]

Proof. Define \[P_{\mathbf{a}}(s) := s^n - f_1(\mathbf{a})s^{n-1} + f_2(\mathbf{a})s^{n-2} - f_3(\mathbf{a})s^{n-3} +\cdots+(-1)^{n-1}f_{n-1}(\mathbf{a})s + (-1)^n f_n(\mathbf{a}).\] Then, by Vieta’s formula, \[P_{\mathbf{a}}(s)=\prod_{i=1}^n (s-a_i).\] Since \(a_k\) appears \(m\) times in the multiset \(\{a_1, a_2, \dots, a_n\}\), \(a_k\) is a root of multiplicity \(m\) of \(P_{\mathbf{a}}\). So we can write \[\label{decom1} P_{\mathbf{a}}(s)=(s-a_k)^m Q_{\mathbf{a}}(s),\tag{11}\] where \[Q_{\mathbf{a}}(s):= \begin{cases} \prod_{\substack{1\le i\le n\\ a_i\ne a_k}}(s-a_i),&if 1\leq m<n,\\ 1,&ifm=n. \end{cases}\] It is clear that \(|Q_{\mathbf{a}}(a_k)| =\rho\) according to the definition of \(\rho\). Moreover, since \(Q_{\mathbf{a}}\) is continuous, there exists some \(\delta>0,\) depending only on \(\mathbf{a}\), such that \[\label{qb01} \left|Q_{\mathbf{a}}(b_k)\right|\geq \frac{\rho}{2}\tag{12}\] as long as \(|a_k-b_k|<\delta.\) Without loss of generality, we assume that \(\delta<1.\) Define \(P_{\mathbf{b}}\) analogously to \(P_{\mathbf{a}}\), \[P_{\mathbf{b}}(s) := s^n - f_1(\mathbf{b})s^{n-1} + f_2(\mathbf{b})s^{n-2} - f_3(\mathbf{b})s^{n-3} +\cdots+(-1)^{n-1}f_{n-1}(\mathbf{b})s + (-1)^n f_n(\mathbf{b}).\] Then \[P_{\mathbf{a}}(s)-P_{\mathbf{b}}(s) = \sum_{i=1}^n (-1)^i\bigl(f_i(\mathbf{a})-f_i(\mathbf{b})\bigr)s^{n-i}.\] Taking \(s=b_k\), we get \[\left|P_{\mathbf{a}}(b_k)\right|\leq \left( |\mathbf{a}|+1\right)^n \sum_{i=1}^n \left|f_i(\mathbf{a})-f_i(\mathbf{b})\right|,\] where we used the fact that \(P_{\mathbf{b}}(b_k)=0\), together with \(|b_k|\leq |a_k|+\delta\leq |\mathbf{a}|+1.\) On the other hand, in view of 11 , \[P_{\mathbf{a}}(b_k)=(b_k-a_k)^m Q_{\mathbf{a}}(b_k).\] So we further get \[\label{qb02} \left|b_k-a_k\right|^m |Q_{\mathbf{a}}(b_k)|\le \left( |\mathbf{a}|+1\right)^n \sum_{i=1}^n \left|f_i(\mathbf{a})-f_i(\mathbf{b})\right|.\tag{13}\] The desired estimate then follows from 12 and 13 . ◻

In the rest of this paper, we only need Lemma 2 in the cases \(n=2\) and \(n=3\), which we state as the following two corollaries.

Corollary 1. Let \(f_1,f_2\) be the elementary symmetric polynomials in two variables. Let \(\mathbf{a} = (a_1,a_2) \in \mathbb{R}^2\), and fix \(k \in \{1,2\}\). Then there exist \(\delta=\delta(\mathbf{a})>0\), and \(C=C(|\mathbf{a}|)>0\), such that for any \(\mathbf{b} \in \mathbb{R}^2\) satisfying \(|b_k - a_k| < \delta\), the following hold:

  • If \(a_1 \ne a_2\), then \[\left|b_k - a_k\right| \le \frac{C}{|a_1 - a_2|} \sum_{i=1}^2 \left|f_i(\mathbf{a}) - f_i(\mathbf{b})\right|.\]

  • If \(a_1 = a_2\), then \[\left|b_k - a_k\right|^2 \le C\sum_{i=1}^2 \left|f_i(\mathbf{a}) - f_i(\mathbf{b})\right|.\]

Corollary 2.

Let \(f_1,f_2,f_3\) be the elementary symmetric polynomials in three variables. Let \(\mathbf{a} = (a_1,a_2,a_3) \in \mathbb{R}^3\), and fix \(k \in \{1,2,3\}\). Then there exist \(\delta=\delta(\mathbf{a})>0\), and \(C=C(|\mathbf{a}|)>0\), such that for any \(\mathbf{b} \in \mathbb{R}^3\) satisfying \(|b_k - a_k| < \delta\), the following hold:

  • If \(a_k\) appears exactly once in the multiset \(\{a_1,a_2,a_3\}\), then \[\left|b_k - a_k\right| \le \frac{C}{\left|a_i - a_k\right|\,\left|a_j - a_k\right|} \sum_{l=1}^3 \left|f_l(\mathbf{a}) - f_l(\mathbf{b})\right|,\] where \(\{i,j\}=\{1,2,3\}\setminus \{k\}\).

  • If \(a_k\) appears exactly twice in the multiset \(\{a_1,a_2,a_3\}\), then \[\left|b_k - a_k\right|^2 \le \frac{C}{\left| a_i - a_k\right| } \sum_{l=1}^3 \left| f_l(\mathbf{a}) - f_l(\mathbf{b}) \right|,\] where \(i\in\{1,2,3\}\) is the unique index such that \(a_i \neq a_k\).

  • If \(a_1=a_2=a_3\), then \[\left|b_k - a_k\right|^3 \le C \sum_{i=1}^3 \left|f_i(\mathbf{a}) - f_i(\mathbf{b})\right|.\]

4 Proof of main theorem↩︎

For simplicity, write \(\mathbf{O} = \mathbf{O}_{\bar\omega}\), where \(\bar\omega\) is as in Theorem 1. Let \(\omega_t := \omega(t,\cdot)\) be a mean-zero \(C^1\) solution of the Euler equation 1 . Our goal is to estimate \({\rm dist}_2(\omega_t,\mathbf{O})\). Denote by \(v_t\) the orthogonal projection of \(\omega_t\) onto \(\mathbf{E}_1\). Then \[{\rm dist}_2(\omega_t,\mathbf{O})^2 = {\rm dist}_2(\omega_t,\mathbf{E}_1)^2 + {\rm dist}_2(v_t,\mathbf{O})^2.\] In view of Proposition 6, it suffices to estimate \({\rm dist}_2(v_t,\mathbf{O})\). To this end, we proceed in several steps.

4.1 Reduction to estimates of amplitudes and phases↩︎

Assume that \(v_t\) has the form \[v_t(\mathbf{x})=\sum_{i=1}^{3} B_i(t) \cos\left(\mathbf{k}_i \cdot \mathbf{x} + \beta_i(t)\right),\qquad B_i(t)\geq 0, \quad \beta_i(t)\in\mathbb{R}.\] Recall that \(\mathbf{O}\) is determined by \(A_1, A_2, A_3\) and \(\alpha_1, \alpha_2, \alpha_3\), as stated in Theorem 1. The following lemma shows that \({\rm dist}_2(v_t,\mathbf{O})\) can be expressed explicitly in terms of the amplitudes \(A_i, B_i(t)\) and the phases \(\alpha_i, \beta_i(t)\), where \(i=1,2,3\).

Throughout this section, for notational simplicity, we use \(C\) to denote various positive constants depending only on \(\Lambda\) and \(\|\bar\omega\|_{L^2(\mathbb{T}_\Lambda)}\), whose values may vary from line to line. We also sometimes write \(B_i = B_i(t)\) and \(\beta_i = \beta_i(t)\) when convenient.

Lemma 3. It holds that \[\label{min} \mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr)^2 =C \min_{\theta_1, \theta_2 \in \mathbb{R}} \left( \left|B_1- A_1 e^{i\theta_1}\right|^2 + \left|B_2- A_2 e^{i\theta_2}\right|^2 + \left|B_3- A_3 e^{i(\theta_1 + \theta_2 +\beta-\alpha)}\right|^2\right),\tag{14}\] where \[\label{deofab} \alpha:=\alpha_1 + \alpha_2 - \alpha_3,\quad \beta:=\beta_1 + \beta_2 - \beta_3.\tag{15}\]

Proof. Using the fact that \(\cos(\mathbf{k}_i\cdot \mathbf{x})\) and \(\sin(\mathbf{k}_i\cdot \mathbf{x})\), \(i=1,2,3\) are mutually orthogonal in \(\mathring L^2(\mathbb{T}_\Lambda)\), we can calculate as follows: \[\require{physics} \notag \begin{align} &\mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr)^2\\ =&\min_{\mathbf{p}\in\mathbb{T}_{\Lambda}}\|v_t(\mathbf{x})-\bar\omega(\mathbf{x}-\mathbf{p}) \|^2_{L^2(\mathbb{T}_\Lambda)}\\ =&\min_{\mathbf{p}\in\mathbb{T}_{\Lambda}}\int_{\mathbb{T}_{\Lambda}}\left(\sum_{i=1}^{3} B_i\cos\left(\mathbf{k}_i \cdot \mathbf{x} + \beta_i\right)-\sum_{i=1}^{3} A_i \cos\left(\mathbf{k}_i \cdot (\mathbf{x}-\mathbf{p}) + \alpha_i\right)\right)^2 \dd\mathbf{x}\\ =&\min_{\theta_1, \theta_2 \in \mathbb{R}}\int_{\mathbb{T}_{\Lambda}}\left(B_1 \cos\left(\mathbf{k}_1 \cdot \mathbf{x} + \beta_1\right)- A_1 \cos\left(\mathbf{k}_1 \cdot \mathbf{x}+\theta_1+ \alpha_1\right)\right)^2\\ &\quad\quad+\left(B_2 \cos\left(\mathbf{k}_2 \cdot \mathbf{x} + \beta_2\right)-A_2 \cos\left(\mathbf{k}_2 \cdot \mathbf{x}+\theta_2 + \alpha_2\right)\right)^2 \\ &\quad\quad+\left(B_3 \cos\left(\mathbf{k}_3 \cdot \mathbf{x} + \beta_3\right)-A_3 \cos\left(\mathbf{k}_3 \cdot \mathbf{x}+\theta_1+\theta_2 + \alpha_3\right)\right)^2 \dd\mathbf{x}\\ =&C \min_{\theta_1, \theta_2 \in \mathbb{R}}\left(B_1 \cos\beta_1-A_1 \cos\left(\theta_1 + \alpha_1\right)\right)^2+\left(B_1 \sin\beta_1- A_1 \sin\left(\theta_1 + \alpha_1\right)\right)^2\\ &\quad\quad+\left(B_2 \cos\beta_2- A_2 \cos\left(\theta_2 + \alpha_2\right)\right)^2+\left(B_2 \sin\beta_2- A_2 \sin\left(\theta_2 + \alpha_2\right)\right)^2\\ &\quad\quad+\left(B_3\cos\beta_3- A_3 \cos\left(\theta_1+\theta_2 + \alpha_3\right)\right)^2+\left(B_3 \sin\beta_3-A_3 \sin\left(\theta_1+\theta_2 + \alpha_3\right)\right)^2\\ =&C \min_{\theta_1, \theta_2 \in \mathbb{R}}\left( \left|B_1 e^{i\beta_1}-A_1e^{i(\theta_1+\alpha_1)}\right|^2+ \left|B_2 e^{i\beta_2}-A_2e^{i(\theta_2+\alpha_2)}\right|^2+ \left|B_3 e^{i\beta_3}-A_3e^{i(\theta_1+\theta_2+\alpha_3)}\right|^2\right)\\ =&C \min_{\theta_1, \theta_2 \in \mathbb{R}} \left( \left|B_1-A_1 e^{i\theta_1}\right|^2 + \left|B_2-A_2 e^{i\theta_2}\right|^2 + \left|B_3-A_3 e^{i(\theta_1 + \theta_2 +\beta-\alpha)}\right|^2\right). \end{align}\] ◻

4.2 Casimirs and estimates involving elementary symmetric polynomials↩︎

Given that \({\rm dist}_2(\omega_0,\mathbf{O})<\varepsilon\), by replacing \(\bar\omega\) with another element of \(\mathbf{O}\) if necessary, we may assume that \[{\rm dist}_2(\omega_0,\mathbf{O})= \|\omega_0-\bar\omega\|_{L^2(\mathbb{T}_\Lambda)}<\varepsilon.\] Without loss of generality, we also assume that \(0<\varepsilon<1.\)

Lemma 4. Let \(k\) be a positive integer. Then \[\left|\mathsf C_k(v_t)-\mathsf C_k(\bar\omega)\right|<C_k\varepsilon,\quad \forall\,t\in\mathbb{R},\] where \(\mathsf C_k\) is the \(k\)-th order Casimir given by 6 , and \(C_k>0\) depends on \(k,\Lambda\) and \(\|\bar\omega\|_{L^2(\mathbb{T}_\Lambda)}.\)

Proof. Let \(\chi\in C^\infty(\mathbb{R})\) be an even cut-off satisfying \[\chi(s)= \begin{cases} 1, & if|s|\leq 1, \\ 0, & if|s|\geq 2, \end{cases}\quadand\quad \|\chi'\|_{L^\infty(\mathbb{R})}\leq 2.\] Set \[M:= C \left(\|\bar\omega\|_{L^2(\mathbb{T}_\Lambda)}+1\right),\] where \(C\) is chosen such that \[\label{fdneq} \|v\|_{L^\infty(\mathbb{T}_\Lambda)} \le C\|v\|_{L^2(\mathbb{T}_\Lambda)}, \qquad \forall\, v\in\mathbf{E}_1.\tag{16}\] Note that such \(C\) exists since \(\mathbf{E}_1\) is finite-dimensional. Define the modified \(k\)-th Casimir by \[\require{physics} \label{MCK} \tilde{\mathsf C}_k(\omega) := \int_{\mathbb{T}_\Lambda} \omega^k\, \chi \left(\frac{\omega}{M}\right)\dd{\mathbf{x}},\tag{17}\] which is conserved under the Euler dynamics. Then, by a straightforward computation, for any \(v_1,v_2\in L^2(\mathbb{T}_\Lambda)\), \[\require{physics} \label{CK} \begin{align} |\tilde{\mathsf C}_k(v_1)-\tilde{\mathsf C}_k(v_2)|&=\left|\int_{\mathbb{T}_\Lambda} h(v_1)-h(v_2)\dd{\mathbf{x}} \right|\quad\quad\left(h(s):=s^k \chi \left(\frac{s}{M}\right)\right)\\ &\leq \|h'\|_{L^\infty(\mathbb{R})}\|v_1-v_2\|_{L^1(\mathbb{T}_\Lambda)}\\ &\le(2M)^{k-1}(k+4) \left|\mathbb{T}_{\Lambda}\right|^{1/2} \|v_1-v_2\|_{L^2(\mathbb{T}_\Lambda)}. \end{align}\tag{18}\] Using 18 , Proposition 6, and the fact that \(\tilde{\mathsf C}_k\) is conserved, \[\begin{align} |\tilde{\mathsf C}_k(v_t)-\tilde{\mathsf C}_k(\bar\omega)| &\le \left|\tilde{\mathsf C}_k(v_t)-\tilde{\mathsf C}_k(\omega_t)\right| + \left|\tilde{\mathsf C}_k(\omega_t)-\tilde{\mathsf C}_k(\bar\omega)\right| \\ &= \left|\tilde{\mathsf C}_k(v_t)-\tilde{\mathsf C}_k(\omega_t)\right| + \left|\tilde{\mathsf C}_k(\omega_0)-\tilde{\mathsf C}_k(\bar\omega)\right| \\ &\le (2M)^{k-1}(k+4) \left|\mathbb{T}_{\Lambda}\right|^{1/2} \left(\|v_t-\omega_t\|_{L^2(\mathbb{T}_\Lambda)} + \|\omega_0-\bar\omega\|_{L^2(\mathbb{T}_\Lambda)}\right) \\ &\leq (2M)^{k-1}(k+4) \left|\mathbb{T}_{\Lambda}\right|^{1/2} \left(\sqrt{\frac{\lambda_2}{\lambda_2-\lambda_1}}\|v_0-\omega_0\|_{L^2(\mathbb{T}_\Lambda)} + \|\omega_0-\bar\omega\|_{L^2(\mathbb{T}_\Lambda)}\right) \\ &\le (2M)^{k-1}(k+4) \left|\mathbb{T}_{\Lambda}\right|^{1/2} \left(1+\sqrt{\frac{\lambda_2}{\lambda_2-\lambda_1}}\right) \|\omega_0-\bar\omega\|_{L^2(\mathbb{T}_\Lambda)}. \end{align}\] Thus \[\left|\tilde{\mathsf C}_k(v_t)-\tilde{\mathsf C}_k(\bar\omega)\right| < C_k\varepsilon, \quad C_k:=(2M)^{k-1}(k+4) \left|\mathbb{T}_{\Lambda}\right|^{1/2}\left(1+\sqrt{\frac{\lambda_2}{\lambda_2-\lambda_1}}\right).\] To conclude the proof, it remains to show that \[\tilde{\mathsf C}_k(\bar\omega)= {\mathsf C}_k(\bar\omega),\qquad \tilde{\mathsf C}_k(v_t)= {\mathsf C}_k(v_t).\] In view of the definition of \(\tilde{\mathsf C}_k\) and the fact that \(\chi\equiv 1\) in \([-M,M]\), it suffices to prove that \[\label{tdeq}\|\bar\omega\|_{L^\infty(\mathbb{T}_\Lambda)}\leq M,\qquad \|v_t\|_{L^\infty(\mathbb{T}_\Lambda)}\leq M.\tag{19}\] For \(\bar\omega\), by the definition of \(M\), \[\|\bar\omega\|_{L^\infty(\mathbb{T}_\Lambda)}\leq C\|\bar\omega\|_{L^2(\mathbb{T}_\Lambda)}\leq M.\] As to \(v_t\), recalling that \(v_t\) is the orthogonal projection of \(\omega_t\) onto \(\mathbf{E}_1\), we have \[\label{vtbdd} \begin{align} \|v_t\|_{L^2(\mathbb{T}_\Lambda)} \le \|\omega_t\|_{L^2(\mathbb{T}_\Lambda)} = \|\omega_0\|_{L^2(\mathbb{T}_\Lambda)} &\le \|\bar\omega\|_{L^2(\mathbb{T}_\Lambda)} +\|\omega_0-\bar\omega\|_{L^2(\mathbb{T}_\Lambda)}\\ &< \|\bar\omega\|_{L^2(\mathbb{T}_\Lambda)} +\varepsilon\\ & < \|\bar\omega\|_{L^2(\mathbb{T}_\Lambda)} +1. \end{align}\tag{20}\] Therefore, \[\|v_t\|_{L^\infty(\mathbb{T}_\Lambda)} \le C \|v_t\|_{L^2(\mathbb{T}_\Lambda)} < C \bigl(\|\bar\omega\|_{L^2(\mathbb{T}_\Lambda)}+1\bigr) = M.\] Hence 19 has been verified, and the proof is complete. ◻

Let \(f_1,f_2,f_3\) be the elementary symmetric polynomials in three variables. Denote \[\mathbf{a}=(A_1^2,A_2^2,A_3^2),\qquad \mathbf{b}=(B_1^2,B_2^2,B_3^2).\] From Lemma 4, we can prove the following lemma.

Lemma 5. For any \(t\in\mathbb{R},\) it holds that \[\label{C3lip} \bigl|B_1B_2B_3\cos\beta-A_1A_2A_3\cos\alpha \bigr|< C\varepsilon\tag{21}\] and \[\label{f-control} \left|f_i(\mathbf{a})-f_i(\mathbf{b})\right|< C\varepsilon, \qquad i=1,2,3.\tag{22}\]

Proof. We compute the Casimirs \({\mathsf C}_k(\bar \omega)\) for \(k=2,3,4,6\) with the help of Maple: \[\label{C2346} \begin{align} & {\mathsf C}_2(\bar \omega)= \frac{|\mathbb{T}_\Lambda|}{2}\left(A_1^2+A_2^2+A_3^2\right),\\ & {\mathsf C}_3(\bar \omega) =\frac{3\left|\mathbb{T}_\Lambda\right|}{2} A_1 A_2 A_3\cos\alpha,\\ & {\mathsf C}_4(\bar \omega) =\frac{3\left|\mathbb{T}_\Lambda\right|}{8} \left({A_1^4}+{A_2^4}+{A_3^4}+{4A_1^2A_2^2}+{4A_1^2A_3^2} +{4A_2^2A_3^2} \right),\\ & {\mathsf C}_6(\bar \omega) =\frac{5\left|\mathbb{T}_\Lambda\right|}{16}\Bigl({A_1^6}+{A_2^6}+{A_3^6}+{9A_2^2A_3^4}+{9A_2^4A_3^2} +{9A_1^4A_2^2}+{9A_1^4A_3^2} +{9A_1^2A_2^4}+{9A_1^2A_3^4}\\ &\qquad\qquad +{9A_1^2A_2^2A_3^2\cos(2\alpha)} +{36A_1^2A_2^2A_3^2} \Bigr). \end{align}\tag{23}\] Note that taking \(k=5\) does not give an independent constraint. A similar computation holds for \(\mathsf C_k(v_t)\) with \(A_1,A_2,A_3,\alpha\) replaced by \(B_1,B_2,B_3,\beta\). Then 21 follows by applying Lemma 4 with \(k=3\). To prove 22 , we observe that from 23 , \[\label{f123b} \begin{cases} f_1(\mathbf{a})= \frac{2}{\left|\mathbb{T}_\Lambda\right|} {\mathsf C}_2(\bar \omega), \\[1ex] f_1^2(\mathbf{a})+2f_2(\mathbf{a})= \frac{8}{3\left|\mathbb{T}_\Lambda\right|} {\mathsf C}_4(\bar \omega), \\[1ex] f_1^3(\mathbf{a})+6f_1(\mathbf{a})f_2(\mathbf{a})+3f_3(\mathbf{a}) = \frac{16}{5\left|\mathbb{T}_\Lambda\right|} {\mathsf C}_6(\bar \omega)-\frac{8}{\left|\mathbb{T}_\Lambda\right|^2} {\mathsf C}_3(\bar \omega)^2, \end{cases}\tag{24}\] and \[\label{f123t} \begin{cases} f_1(\mathbf{b})= \frac{2}{\left|\mathbb{T}_\Lambda\right|} {\mathsf C}_2(v_t), \\[1ex] f_1^2(\mathbf{b})+2f_2(\mathbf{b})= \frac{8}{3\left|\mathbb{T}_\Lambda\right|} {\mathsf C}_4(v_t), \\[1ex] f_1^3(\mathbf{b})+6f_1(\mathbf{b})f_2(\mathbf{b})+3f_3(\mathbf{b}) = \frac{16}{5\left|\mathbb{T}_\Lambda\right|} {\mathsf C}_6(v_t)-\frac{8}{\left|\mathbb{T}_\Lambda\right|^2} {\mathsf C}_3(v_t)^2. \end{cases}\tag{25}\] Based on 24 , 25 and Lemma 4, we analyze as follows:

  • From 24 \(_1\) and 25 \(_1\), we get 22 with \(i=1\).

  • From 24 \(_2\) and 25 \(_2\), we get \[\begin{align} \left|f_2(\mathbf{a})-f_2(\mathbf{b})\right|&< C \varepsilon+C\left|f_1^2 (\mathbf{a})-f_1^2 (\mathbf{b})\right| \\ &< C\varepsilon+C\varepsilon(\left|\mathbf{a}\right|+\left|\mathbf{b}\right|)\\ &< C\varepsilon, \end{align}\] where we used the estimate for \(i=1\), and \[\label{ababsv} |\mathbf{a}|\leq C\|\bar\omega\|^2_{L^2(\mathbb{T}_\Lambda)},\quad |\mathbf{b}|\leq C\|v_t\|^2_{L^2(\mathbb{T}_\Lambda)}\leq C\left(\|\bar\omega\|^2_{L^2(\mathbb{T}_\Lambda)}+1\right) \quad(by \eqref{vtbdd}).\tag{26}\]

  • From 24 \(_3\) and 25 \(_3\), we get \[\begin{align} \left|f_3(\mathbf{a})-f_3(\mathbf{b})\right| &< C \varepsilon+ C\varepsilon\left|\mathsf C_3(\bar\omega)+\mathsf C_3(v_t)\right|+C|f_1 (\mathbf{a})f_2(\mathbf{a})-f_1 (\mathbf{b})f_2(\mathbf{b})|+C|f^3_1 (\mathbf{a}) -f^3_1 (\mathbf{b})|\\ &< C \varepsilon+ C\varepsilon\left(\|\bar\omega\|^3_{L^\infty(\mathbb{T}_\Lambda)}+\|v_t\|^3_{L^\infty(\mathbb{T}_\Lambda)}+|\mathbf{a}|+|\mathbf{b}|^2+|\mathbf{a}|^2+|\mathbf{b}|^4\right)\\ &< C\varepsilon, \end{align}\] where we used 16 , 26 and the estimates for \(i=1,2\).

The proof is complete. ◻

4.3 Estimate of \(|b_k(t)-a_k|\)↩︎

Let \(k\in\{1,2,3\}\) be fixed. Combining Lemma 5 with Corollary 2, we obtain the following estimate of \(|b_k(t)- a_k|\) for all \(t\in\mathbb{R}\).

Lemma 6. There exists \(\varepsilon_0=\varepsilon_0(\Lambda,\bar\omega)>0,\) such that if \(\varepsilon<\varepsilon_0\), then the following hold:

  • If \(a_k\) appears exactly once in the multiset \(\{a_1, a_2, a_3\}\), then \[\label{ak1} \left|b_k(t) - a_k\right| < \frac{C \varepsilon}{\left|a_i - a_k\right| \, \left|a_j - a_k\right|},\quad\forall\,t\in\mathbb{R},\tag{27}\] where \(\{i,j\} = \{1,2,3\} \setminus \{k\}\).

  • If \(a_k\) appears exactly twice in the multiset \(\{a_1, a_2, a_3\}\), then \[\label{ak2} \left|b_k(t) - a_k\right| < \frac{C\varepsilon^{1/2}}{\left|a_i - a_k\right|^{1/2}},\quad\forall\,t\in\mathbb{R},\tag{28}\] where \(i\in\{1,2,3\}\) is the unique index such that \(a_i \neq a_k\).

  • If \(a_1=a_2=a_3\), then \[\label{ak3} \left|b_k(t) - a_k\right| < C \varepsilon^{1/3},\quad\forall\,t\in\mathbb{R}.\tag{29}\]

Proof. We prove only (iii), as the other two cases follow by a similar argument. By Corollary 2 and 22 in Lemma 5, there exists \(\delta=\delta(\mathbf{a})>0\) such that \[\label{c1o3} \left|b_k(t)-a_k\right|<\delta\quad\Longrightarrow\quad |b_k(t) - a_k| < C \varepsilon^{1/3}\tag{30}\] for any \(t\in\mathbb{R}.\) To finish the proof, it remains to show \[\label{lesdelta} |b_k(t)-a_k|<\delta,\quad \forall\,t\in\mathbb{R},\tag{31}\] if \(\varepsilon\) is sufficiently small. To this end, recall that \[\|v_0-\bar\omega\|_{L^2(\mathbb{T}_\Lambda)} \leq \|\omega_0-\bar\omega\|_{L^2(\mathbb{T}_\Lambda)}<\varepsilon,\] which implies that \[\label{a0-close-b} \left|b_k(0)-a_k\right|< C \varepsilon<C\varepsilon^{1/3}.\tag{32}\] Take \(\varepsilon_0=\varepsilon_0(\Lambda,\bar\omega)>0\) such that \(C\varepsilon^{1/3}<\delta/3\) for any \(\varepsilon\in(0,\varepsilon_0)\). We now verify 31 by contradiction. Suppose that \(\left|b_k(t^*)-a_k\right|\geq \delta\) at some \(t^*\in\mathbb{R}\). Then, by continuity, there exists \(t^{**}\in\mathbb{R}\) such that \(\left|b_k(t^{**})-a_k\right|=\delta/2,\) which in combination with 30 gives \(\left|b_{k}(t^{**})-a_k\right|<C\varepsilon^{1/3}<\delta/3,\) a contradiction. The proof is complete. ◻

4.4 Concluding the proof: \(A_1A_2A_3=0\)↩︎

Without loss of generality, we may assume that \(A_3=0\). Then 14 becomes \[\mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr)^2 =C\left(\left|B_1-A_1\right|^2 + \left|B_2-A_2\right|^2 + \left| B_3\right|^2\right).\] So \[\mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr) <C\left(\left|B_1-A_1\right| + \left|B_2-A_2\right| + B_3 \right).\] Now we estimate \(\left|B_1-A_1\right|\), \(\left|B_2-A_2\right|\) and \(B_3\) based on Lemma 6 (recall that \(\mathbf{a}=\left(A_1^2,A_2^2,A_3^2\right), \mathbf{b}=\left(B_1^2,B_2^2,B_3^2\right)\)). We distinguish three cases.

In this case, \[\left|B_1^2 - A_1^2\right| < \frac{C\varepsilon}{\left|\left(A_2^2 - A_1^2\right)\left(A_3^2 - A_1^2\right)\right|},\quad \left|B_2^2 - A_2^2\right| < \frac{C\varepsilon}{\left|\left(A_1^2 - A_2^2\right)\left(A_3^2 - A_2^2\right)\right|},\quad B_3^2 < \frac{C\varepsilon}{A_1^2 A_2^2},\] which yields \[\left|B_1 - A_1\right| < \frac{C\varepsilon}{\left|\left(A_2^2 - A_1^2\right)\left(A_3^2 - A_1^2\right)\left(B_1 + A_1\right)\right|}<\frac{C\varepsilon}{\left|\left(A_2^2 - A_1^2\right)\left(A_3^2 - A_1^2\right)\right| A_1 },\] \[\left|B_2 - A_2\right| < \frac{C\varepsilon}{\left|\left(A_1^2 - A_2^2\right)\left(A_3^2 - A_2^2\right)\left(B_2 + A_2\right)\right|}<\frac{C\varepsilon}{\left|\left(A_1^2 - A_2^2\right)\left(A_3^2 - A_2^2\right)\right| A_2 },\] and \[B_3 < \frac{C\varepsilon^{1/2}}{A_1 A_2 }.\] Thus \[\begin{align} \mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr) &<\frac{C \varepsilon }{\left|\left(A_2^2-A_1^2\right) \left(A_3^2-A_1^2\right)\right| A_1 }+\frac{C \varepsilon }{\left|\left(A_1^2-A_2^2\right) \left(A_3^2-A_2^2\right)\right| A_2 }+\frac{C \varepsilon^{1/2}}{ A_1A_2}\\ &\leq \frac{C \varepsilon^{1/2}}{ A_1A_2}. \end{align}\] Note that we may need to choose a smaller \(\varepsilon_0\) so that the last inequality holds.

In this case, \[\left|B_1^2-A_1^2\right|+\left|B_2^2-A_2^2\right|< \frac{C\varepsilon^{1/2}}{A_1}, \qquad B_3^2< \frac{C \varepsilon}{A_1^4},\] which yields \[\left|B_1 -A_1\right| < \frac{C\varepsilon^{1/2}}{A_1^2},\quad \left|B_2 -A_2\right| < \frac{C\varepsilon^{1/2}}{A_1^2},\quad B_3<\frac{C\varepsilon^{1/2}}{A_1^2}.\] Thus \[\mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr) <\frac{C\varepsilon^{1/2}}{A_1^2}.\]

Without loss of generality, we may assume that \(A_2=0\). Then \[\left|B_1^2-A_1^2\right|<\frac{C \varepsilon}{A_1^4}, \quad B_2^2+B_3^2< \frac{C \varepsilon^{1/2}}{A_1},\] which gives \[\left|B_1 -A_1 \right|<\frac{C \varepsilon}{A_1^5}, \quad B_2 < \frac{C \varepsilon^{1/4}}{A^{1/2}_1},\quad B_3 < \frac{C \varepsilon^{1/4}}{A^{1/2}_1}.\] Thus, by choosing a smaller \(\varepsilon_0\) if necessary, we get \[\mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr) <\frac{C\varepsilon^{1/4}}{A_1^{1/2}}.\] This completes the proof of Theorem 1 in the case \(A_1A_2A_3=0\).

4.5 Concluding the proof: \(A_1A_2A_3\neq 0\)↩︎

In this case, we further estimate \(\mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr)\) according to 14 as follows: \[\label{min95control} \begin{align} &\mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr)^2\\ =&C\min_{\theta_1, \theta_2 \in \mathbb{R}} \left( \left|B_1-A_1 e^{i\theta_1}\right|^2 + \left|B_2-A_2 e^{i\theta_2}\right|^2 + \left|B_3-A_3 e^{i(\theta_1 + \theta_2 +\beta-\alpha)}\right|^2\right)\\ =&C\min_{\theta_1, \theta_2 \in \mathbb{R}} \left( \left|B_1-A_1 e^{i\theta_1}\right|^2 + \left|B_2-A_2 e^{i\theta_2}\right|^2 + \left|B_3e^{-i(\beta-\alpha)}-A_3 e^{i(\theta_1 + \theta_2)}\right|^2\right)\\ \leq&C\min_{\theta_1, \theta_2 \in \mathbb{R}} \left( \left|B_1-A_1 e^{i\theta_1}\right|^2 + \left|B_2-A_2 e^{i\theta_2}\right|^2 + \left( \left|B_3e^{-i(\beta-\alpha)}-A_3\right|+ \left|A_3-A_3 e^{i(\theta_1 + \theta_2)}\right|\right)^2\right)\\ =&C \left( \left|B_1 -A_1\right|^2 + \left|B_2 -A_2\right|^2 + \left|B_3e^{-i\beta}-A_3e^{-i\alpha}\right|^2\right). \end{align}\tag{33}\] So \[\mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr) \leq C \left( \left|B_1 -A_1\right| + \left|B_2 -A_2\right| + \left|B_3e^{-i\beta}-A_3e^{-i\alpha}\right|\right).\] To estimate \(\left|B_1-A_1\right|\), \(\left|B_2 -A_2\right|\) and \(\left|B_3e^{-i\beta}-A_3e^{-i\alpha}\right|\), we distinguish three cases.

Case 1: \(A_1, A_2, A_3\) are pairwise distinct. In this case, based on Lemma 6, we have the following estimates on \(|B_k-A_k|\), \(k=1,2,3\): \[\label{bkak1} \begin{align} &\left|B_1^2-A_1^2\right| <\frac{C\varepsilon}{\left|A_2^2-A_1^2\right| \,\left|A_3^2-A_1^2\right|} \quad\Longrightarrow\quad \left|B_1 -A_1 \right| <\frac{C\varepsilon}{\left|A_2^2-A_1^2\right| \,\left|A_3^2-A_1^2\right|A_1},\\ &\left|B_2^2-A_2^2\right|<\frac{C\varepsilon}{\left|A_1^2-A_2^2\right| \,\left|A_3^2-A_2^2\right|}\quad\Longrightarrow\quad \left|B_2 -A_2 \right|<\frac{C\varepsilon}{\left|A_1^2-A_2^2\right| \,\left|A_3^2-A_2^2\right|A_2},\\ &\left|B_3^2-A_3^2\right|<\frac{C\varepsilon}{\left|A_1^2-A_3^2\right|\,\left|A_2^2-A_3^2\right|}\quad\Longrightarrow\quad \left|B_3 -A_3 \right|<\frac{C\varepsilon}{\left|A_1^2-A_3^2\right|\,\left|A_2^2-A_3^2\right|A_3}. \end{align}\tag{34}\] To estimate \(|B_3 e^{-i\beta}-A_3e^{-i\alpha}|\), notice that \[|B_3 e^{-i\beta}-A_3e^{-i\alpha}| \leq |B_3\cos\beta-A_3\cos\alpha|+|B_3\sin\beta-A_3\sin\alpha|.\] So it suffices to estimate \(|B_3\cos\beta-A_3\cos\alpha|\) and \(|B_3\sin\beta-A_3\sin\alpha|\). To estimate \(|B_3\cos\beta-A_3\cos\alpha|\), notice that \[\begin{align} \left|B_3\cos\beta-A_3\cos\alpha\right| &=\frac{ \left|B_1B_2B_3\cos\beta-A_1A_2A_3\cos\alpha +A_1A_2A_3\cos\alpha -B_1B_2A_3\cos\alpha\right| }{ B_1B_2 }\\ &\leq \frac{ \left|B_1B_2B_3\cos\beta-A_1A_2A_3\cos\alpha\right| + A_3\left|B_1B_2-A_1A_2\right| }{ B_1B_2 }\\ &\leq \frac{ \left|B_1B_2B_3\cos\beta-A_1A_2A_3\cos\alpha\right| + A_3\left(\left|B_1B_2-A_1B_2\right|+\left|A_1B_2-A_1A_2\right|\right) }{ B_1B_2 }. \end{align}\] By choosing a smaller \(\varepsilon_0\) if necessary, we may assume that \(A_i/2<B_i< 3A_i/2\), \(i=1,2,3\). Then, in view of 21 and 34 , \[\label{BACOS1} \left|B_3\cos\beta-A_3\cos\alpha\right| \leq \frac{C\varepsilon}{A_1A_2}+\frac{CA_3\varepsilon}{A_1^2\left|A_2^2-A_1^2\right| \,\left|A_3^2-A_1^2\right|} +\frac{CA_3\varepsilon}{A_2^2\left|A_1^2-A_2^2\right| \,\left|A_3^2-A_2^2\right|}.\tag{35}\] We now turn to the estimate of \(|B_3\sin\beta-A_3\sin\alpha|\). Notice that \[\begin{align} \left| \left(B_3\sin\beta\right)^2-\left(A_3\sin\alpha\right)^2\right| =&\left| B_3^2-A_3^2+ \left(A_3\cos\alpha\right)^2-\left(B_3\cos\beta\right)^2 \right|\\ \leq & \left(B_3+A_3\right) \left(\left|B_3-A_3 \right| +\left|B_3\cos\beta-A_3\cos\alpha \right|\right). \end{align}\] Taking into account 34 \(_3\) and 35 , \[\label{b2a2} \begin{align} &\left| B_3\sin\beta-A_3\sin\alpha\right|\,\left| B_3\sin\beta+A_3\sin\alpha\right|\\ \leq& C\left( \frac{1}{\left|A_1^2-A_3^2\right| \,\left|A_2^2-A_3^2\right|} +\frac{A_3^2}{\left|A_2^2-A_1^2\right| \,\left|A_3^2-A_1^2\right|A_1^2} +\frac{A_3^2}{\left|A_1^2-A_2^2\right| \,\left|A_3^2-A_2^2\right|A_2^2}+ \frac{A_3}{A_1A_2}\right)\varepsilon. \end{align}\tag{36}\] We further distinguish two cases.

In this case, \(|B_3\sin\beta \pm A_3\sin\alpha| =|B_3\sin\beta|\). Thus, in view of 36 , \[\begin{align} &|B_3\sin\beta-A_3\sin\alpha|\\ \leq& C\left( \frac{1}{|A_1^2-A_3^2||A_2^2-A_3^2|}+ \frac{A_3^2}{|A_2^2-A_1^2||A_3^2-A_1^2|A_1^2} +\frac{A_3^2}{|A_1^2-A_2^2||A_3^2-A_2^2|A_2^2} +\frac{A_3}{A_1A_2} \right)^{1/2}\varepsilon^{1/2}. \end{align}\] Combining this estimate with 34 and 35 , and choosing \(\varepsilon_0>0\) smaller if necessary, we obtain \[\begin{align} &\mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr)\\ \leq&C\left( \frac{1}{|A_1^2-A_3^2||A_2^2-A_3^2|}+ \frac{A_3^2}{|A_2^2-A_1^2||A_3^2-A_1^2|A_1^2} +\frac{A_3^2}{|A_1^2-A_2^2||A_3^2-A_2^2|A_2^2} +\frac{A_3}{A_1A_2} \right)^{1/2}\varepsilon^{1/2}. \end{align}\]

In this case, we have \[\label{positive95lower95bound} 0<2A_3|\sin\alpha| \leq \left|B_3\sin\beta-A_3\sin\alpha\right| + \left|B_3\sin\beta+A_3\sin\alpha\right|.\tag{37}\] Combining 36 with 37 , we obtain the following pointwise-in-time dichotomy. For every \(t\in\mathbb{R}\), at least one of the following two alternatives holds: \[\label{alternative-new-1} \begin{align} &\left|B_3\sin\beta-A_3\sin\alpha\right|\\ \leq& \frac{C\varepsilon}{|\sin\alpha|} \Bigg( \frac{1}{A_3|A_1^2-A_3^2||A_2^2-A_3^2|} + \frac{A_3}{|A_2^2-A_1^2||A_3^2-A_1^2|A_1^2} + \frac{A_3}{|A_1^2-A_2^2||A_3^2-A_2^2|A_2^2} + \frac{1}{A_1A_2} \Bigg), \end{align}\tag{38}\] or \[\label{alternative-new-2} \begin{align} &\left|B_3\sin\beta+A_3\sin\alpha\right|\\ \leq& \frac{C\varepsilon}{|\sin\alpha|} \Bigg( \frac{1}{A_3|A_1^2-A_3^2||A_2^2-A_3^2|} + \frac{A_3}{|A_2^2-A_1^2||A_3^2-A_1^2|A_1^2} + \frac{A_3}{|A_1^2-A_2^2||A_3^2-A_2^2|A_2^2} + \frac{1}{A_1A_2} \Bigg). \end{align}\tag{39}\] Indeed, by 37 , at least one of \(\left|B_3\sin\beta-A_3\sin\alpha\right|\), \(\left|B_3\sin\beta+A_3\sin\alpha\right|\) is not smaller than \(A_3|\sin\alpha|\). Dividing the product estimate 36 by this lower bound gives either 38 or 39 . The constants in this dichotomy are independent of \(t\), but the dichotomy is, at this stage, only pointwise in time.

We next show that, for sufficiently small \(\varepsilon\), the second alternative cannot occur. If 38 holds at a time \(t\), then combining 34 , 35 , and 38 , we obtain \[\label{dist-O-case12} \begin{align} &\mathrm{dist}_2(v_t,\mathbf{O})\\ \leq\;& \frac{C\varepsilon}{|A_2^2-A_1^2||A_3^2-A_1^2|} \left( \frac{1}{A_1} + \frac{A_3}{A_1^2} + \frac{A_3}{A_1^2|\sin\alpha|} \right) + \frac{C\varepsilon}{|A_1^2-A_2^2||A_3^2-A_2^2|} \left( \frac{1}{A_2} + \frac{A_3}{A_2^2} + \frac{A_3}{A_2^2|\sin\alpha|} \right)\\ &+ \frac{C\varepsilon}{|A_1^2-A_3^2||A_2^2-A_3^2|A_3|\sin\alpha|} + \frac{C\varepsilon}{A_1A_2} + \frac{C\varepsilon}{A_1A_2|\sin\alpha|}. \end{align}\tag{40}\] On the other hand, if 39 holds at a time \(t\), then the same argument, applied to the conjugate phase configuration, gives \[\label{dist-conj-case12} \begin{align} &\mathrm{dist}_2(v_t,\widetilde{\mathbf{O}})\\ \leq\;& \frac{C\varepsilon}{|A_2^2-A_1^2||A_3^2-A_1^2|} \left( \frac{1}{A_1} + \frac{A_3}{A_1^2} + \frac{A_3}{A_1^2|\sin\alpha|} \right) + \frac{C\varepsilon}{|A_1^2-A_2^2||A_3^2-A_2^2|} \left( \frac{1}{A_2} + \frac{A_3}{A_2^2} + \frac{A_3}{A_2^2|\sin\alpha|} \right) \\ &+ \frac{C\varepsilon}{|A_1^2-A_3^2||A_2^2-A_3^2|A_3|\sin\alpha|} + \frac{C\varepsilon}{A_1A_2} + \frac{C\varepsilon}{A_1A_2|\sin\alpha|}, \end{align}\tag{41}\] where \[\widetilde{\mathbf{O}} := \left\{ \widetilde{\omega}(\cdot-\mathbf{p}) \mid \mathbf{p}\in\mathbb{T}_{\Lambda} \right\}, \qquad \widetilde{\omega}(\mathbf{x}) = \sum_{i=1}^3 A_i\cos(\mathbf{k}_i\cdot\mathbf{x}-\alpha_i).\] Since \(\sin\alpha\neq0\), \(\mathbf{O}\neq \widetilde{\mathbf{O}}.\) By Lemma B.1(3) in [6], the two compact orbits are separated in \(L^2\). Thus \[d_0:=\mathrm{dist}_2(\mathbf{O},\widetilde{\mathbf{O}})>0.\] Choose \(\varepsilon_0>0\) sufficiently small such that, whenever \(0<\varepsilon<\varepsilon_0\), the right-hand sides of both 40 and 41 are smaller than \(d_0/3\). We also choose \(\varepsilon_0\) so that \[\mathrm{dist}_2(v_0,\mathbf{O})<\frac{d_0}{3}.\]

Define \[I_1:= \left\{ t\in\mathbb{R}: \mathrm{dist}_2(v_t,\mathbf{O})<\frac{d_0}{3} \right\}, \qquad I_2:= \left\{ t\in\mathbb{R}: \mathrm{dist}_2(v_t,\widetilde{\mathbf{O}})<\frac{d_0}{3} \right\}.\] The pointwise dichotomy above implies that \(I_1\cup I_2=\mathbb{R}.\) Moreover, \[I_1\cap I_2=\varnothing.\] Indeed, if \(t\in I_1\cap I_2\), then \[d_0 = \mathrm{dist}_2(\mathbf{O},\widetilde{\mathbf{O}}) \leq \mathrm{dist}_2(v_t,\mathbf{O}) + \mathrm{dist}_2(v_t,\widetilde{\mathbf{O}}) < \frac{2d_0}{3},\] which is impossible. Since \(t\mapsto v_t\) is continuous in \(L^2\), both \(I_1\) and \(I_2\) are open subsets of \(\mathbb{R}\). Furthermore, \(0\in I_1\). Since \(\mathbb{R}\) is connected, we must have \[I_2=\varnothing.\] Therefore the second alternative 39 never occurs, and 38 holds for all \(t\in\mathbb{R}\). Combining this with 34 and 35 , we conclude that 40 holds for all \(t\in\mathbb{R}\).

Case 2: Exactly two of \(A_1, A_2, A_3\) are equal. Without loss of generality, we may assume that \(A_1=A_2\), and then, based on Lemma 6, we have the following estimates on \(|B_k-A_k|\), \(k=1,2,3\). \[\label{bkak952} \begin{align} &\left|B_1^2-A_1^2\right| <\frac{C\varepsilon^{1/2}}{\left|A_3^2-A_1^2\right|^{1/2}} \quad\Longrightarrow\quad \left|B_1 -A_1 \right| <\frac{C\varepsilon^{1/2}}{\left|A_3^2-A_1^2\right|^{1/2}A_1},\\ &\left|B_2^2-A_2^2\right|<\frac{C\varepsilon^{1/2}}{\left|A_3^2-A_1^2\right|^{1/2}}\quad\Longrightarrow\quad \left|B_2 -A_2 \right|<\frac{C\varepsilon^{1/2}}{\left|A_3^2-A_1^2\right|^{1/2}A_1},\\ &\left|B_3^2-A_3^2\right|<\frac{C\varepsilon}{\left|A_1^2-A_3^2\right|^2}\quad\Longrightarrow\quad \left|B_3 -A_3 \right|<\frac{C\varepsilon}{\left|A_1^2-A_3^2\right|^2A_3}. \end{align}\tag{42}\] The same estimate as in the previous case, with the bounds in 21 and 42 substituted, gives

\[\label{BACOS952} \begin{align} |B_3\cos\beta-A_3\cos\alpha| \leq \frac{C\varepsilon}{A_1^2} +\frac{CA_3\varepsilon^{1/2}}{A_1^2\left|A_3^2-A_1^2\right|^{1/2}}. \end{align}\tag{43}\] The same argument as above gives \[\label{b2a2952} \left|B_3\sin\beta-A_3\sin\alpha\right|\,\left|B_3\sin\beta+A_3\sin\alpha\right| \leq \frac{C A_3^2\varepsilon^{1/2}}{A_1^2\left|A_3^2-A_1^2\right|^{1/2}} +\frac{C\varepsilon}{\left|A_1^2-A_3^2\right|^2}+ \frac{CA_3\varepsilon}{A_1^2}.\tag{44}\]

By 44 , \[\begin{align} |B_3\sin\beta-A_3\sin\alpha| \leq \frac{C A_3\varepsilon^{1/4}}{A_1\left|A_3^2-A_1^2\right|^{1/4}} +\frac{C\varepsilon^{1/2}}{\left|A_1^2-A_3^2\right|}+ \frac{CA_3^{1/2}\varepsilon^{1/2}}{A_1}. \end{align}\] Choosing \(\varepsilon_0>0\) smaller if necessary, we have \[\begin{align} \mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr) \leq & \frac{CA_3\varepsilon^{1/4}}{\left|A_3^2-A_1^2\right|^{1/4} A_1}. \end{align}\]

As in Case 1.2, the pointwise dichotomy obtained from 44 and 37 has two branches. The branch corresponding to the conjugate orbit is excluded by the continuity of \(t\mapsto v_t\) in \(L^2\), the positive distance between \(\mathbf{O}\) and the conjugate orbit, and the initial closeness to \(\mathbf{O}\). From 44 , we have that \[\left|B_3\sin\beta-A_3\sin\alpha\right| \leq \frac{C A_3\varepsilon^{1/2}}{A_1^2\left|A_3^2-A_1^2\right|^{1/2}\left|\sin\alpha\right|} +\frac{C\varepsilon}{\left|A_1^2-A_3^2\right|^2A_3\left|\sin\alpha\right|}+ \frac{C\varepsilon}{A_1^2\left|\sin\alpha\right|}.\] Then, choosing \(\varepsilon_0>0\) smaller if necessary, we obtain \[\begin{align} \mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr) \leq \frac{C\varepsilon^{1/2}}{\left|A_3^2-A_1^2\right|^{1/2}}\left(\frac{A_3}{A_1^2\left|\sin\alpha\right|}+\frac{A_3}{A_1^2}+\frac{1}{A_1}\right). \end{align}\]

Case 3: \(A_1=A_2=A_3\). Based on Lemma 6, we have \[\label{bkak953} \begin{align} &\left|B_k^2-A_k^2\right| <{C\varepsilon^{1/3}} \quad\Longrightarrow\quad \left|B_k -A_k \right| <\frac{C\varepsilon^{1/3}}{A_1},\quad k=1,2,3. \end{align}\tag{45}\] Repeating the argument leading to 35 , we obtain \[\label{BACOS953} \begin{align} |B_3\cos\beta-A_3\cos\alpha| \leq \frac{C\varepsilon}{A_1^2} +\frac{C\varepsilon^{1/3}}{A_1}. \end{align}\tag{46}\] Repeating the argument leading to 36 , we obtain \[\label{b2a2953} \begin{align} \left|B_3\sin\beta-A_3\sin\alpha\right|\,\left|B_3\sin\beta+A_3\sin\alpha\right| \leq C \varepsilon^{1/3}+\frac{C\varepsilon}{A_1}. \end{align}\tag{47}\]

By 47 , \[\begin{align} |B_3\sin\beta-A_3\sin\alpha|\leq C \varepsilon^{1/6}+\frac{C\varepsilon^{1/2}}{A_1^{1/2}}. \end{align}\] Therefore, \[\begin{align} \mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr) \leq C\varepsilon^{1/6}, \end{align}\] after choosing \(\varepsilon_0\) smaller if necessary.

As in Case 1.2, the branch corresponding to the conjugate orbit is excluded by the continuity of \(t\mapsto v_t\) in \(L^2\), the positive distance between \(\mathbf{O}\) and the conjugate orbit, and the initial closeness to \(\mathbf{O}\). From 47 , we have that \[\begin{align} \left|B_3\sin\beta-A_3\sin\alpha\right| \leq \frac{C \varepsilon^{1/3}}{\left|\sin\alpha\right|A_1}+\frac{C \varepsilon}{\left|\sin\alpha\right|A_1^2}. \end{align}\] Therefore, \[\begin{align} \mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr) \leq &\frac{C \varepsilon^{1/3}}{\left|\sin\alpha\right|\,A_1}+\frac{C \varepsilon^{1/3}}{A_1}, \end{align}\] after choosing \(\varepsilon_0\) smaller if necessary.

Remark 8. We briefly explain how the estimates in Theorem 1 deteriorate as the amplitude configuration becomes more symmetric, with a further loss in the degenerate phase case \(\sin\alpha=0\). Assume that \({\rm dist}_{2}(\omega_0,\mathbf{O})<\varepsilon\), \(A_1,A_2,A_3\) are pairwise distinct and \(\sin\alpha\neq 0\). Then the proof yields \[\label{ABDa} \begin{align} &\mathrm{dist}_2\bigl(\omega_t,\mathbf{O}\bigr)\\ \leq & \frac{C\varepsilon}{\left|A_2^2-A_1^2\right|\,\left|A_3^2-A_1^2\right|} \left(\frac{A_3}{A_1^2}+\frac{1}{A_1}+\frac{A_3}{A_1^2\left|\sin\alpha\right|}\right) + \frac{C\varepsilon}{\left|A_2^2-A_1^2\right|\,\left|A_3^2-A_2^2\right|} \left(\frac{A_3}{A_2^2}+\frac{1}{A_2}+\frac{A_3}{A_2^2\left|\sin\alpha\right|}\right)\\ &+ \frac{C\varepsilon}{\left|A_1^2-A_3^2\right|\,\left|A_2^2-A_3^2\right|\,\left|\sin\alpha\right|A_3} +\frac{C\varepsilon}{A_1A_2}+\frac{C\varepsilon}{A_1A_2\left|\sin\alpha\right|}. \end{align}\tag{48}\] This estimate shows explicitly how the stability deteriorates as the amplitude configuration becomes more symmetric. Suppose that \(A_2\to A_1\) while \(A_3\) remains fixed in 48 . Since the factor \(|A_2^2-A_1^2|^{-1}\) blows up, the preceding estimate degenerates into \[\label{AABa} \begin{align} \mathrm{dist}_2\bigl(\omega_t,\mathbf{O}\bigr) \leq \frac{C\varepsilon^{1/2}}{\left|A_3^2-A_1^2\right|^{1/2}} \left(\frac{A_3}{A_1^2\left|\sin\alpha\right|} +\frac{A_3}{A_1^2} +\frac{1}{A_1}\right). \end{align}\tag{49}\] Thus the stability weakens from order \(O(\varepsilon)\) to order \(O(\varepsilon^{1/2})\). If \(A_1\), \(A_2\), and \(A_3\) all become close to one another, then 49 degenerates further into \[\label{AAAa} \begin{align} \mathrm{dist}_2\bigl(\omega_t,\mathbf{O}\bigr) \leq \frac{C\varepsilon^{1/3}}{\left|\sin\alpha\right|A_1} +\frac{C\varepsilon^{1/3}}{A_1}. \end{align}\tag{50}\] Hence the stability order drops from \(O(\varepsilon^{1/2})\) to \(O(\varepsilon^{1/3})\).

We next explain how the phase factor \(\sin\alpha\) affects the stability estimate. Examining the three cases above separately, we observe the same phenomenon: as \(\sin\alpha\) tends to zero, the stability estimate deteriorates. When \(\left|\sin\alpha\right|\) approaches \(0\), the bound 48 degenerates to \[\label{ABD0} \begin{align} &\mathrm{dist}_2\bigl(\omega_t,\mathbf{O}\bigr)\\ \leq & C\left( \frac{A_3^2}{|A_2^2-A_1^2||A_3^2-A_1^2|A_1^2} +\frac{A_3^2}{|A_1^2-A_2^2||A_3^2-A_2^2|A_2^2} +\frac{1}{|A_1^2-A_3^2||A_2^2-A_3^2|} +\frac{A_3}{A_1A_2} \right)^{1/2}\varepsilon^{1/2}. \end{align}\tag{51}\] Hence the stability order drops from \(O(\varepsilon)\) to \(O(\varepsilon^{1/2})\). And, 49 further degenerates to \[\label{AAB0} \begin{align} \mathrm{dist}_2\bigl(\omega_t,\mathbf{O}\bigr) \leq \frac{CA_3\varepsilon^{1/4}}{\left|A_3^2-A_1^2\right|^{1/4}A_1}. \end{align}\tag{52}\] Accordingly, the stability order drops from \(O(\varepsilon^{1/2})\) to \(O(\varepsilon^{1/4})\). Moreover, 50 reduces to \[\label{AAA0} \begin{align} \mathrm{dist}_2\bigl(\omega_t,\mathbf{O}\bigr) \leq C\varepsilon^{1/6}. \end{align}\tag{53}\] In this most symmetric regime, the stability deteriorates further from \(O(\varepsilon^{1/3})\) to \(O(\varepsilon^{1/6})\).

A similar phenomenon appears when exactly one of \(A_1,A_2,A_3\) is zero. Without loss of generality, we may assume that \(A_3=0\). In this case, the proof gives \[\label{CI4} {\rm dist}_2\bigl(\omega_t,\mathbf{O}\bigr) < \frac{C \varepsilon^{1/2}}{ A_1A_2}.\tag{54}\] If \(A_2\to 0\), then 54 degenerates to \[{\rm dist}_2\bigl(\omega_t,\mathbf{O}\bigr) < \frac{C\varepsilon^{1/4}}{A_1^{1/2}}.\] This corresponds to a further deterioration of the stability estimate from order \(O(\varepsilon^{1/2})\) to \(O(\varepsilon^{1/4})\).

5 Non-hexagonal tori↩︎

In this section, we consider the remaining cases of flat two-dimensional tori for which \(\dim(\mathbf{E}_1)=2\) or \(4\). For these two cases, by [6], we have the following:

  • If \(\dim(\mathbf{E}_1) = 2\), then there exists some nonzero vector \(\mathbf{k}\) such that \[\mathbf{E}_1={\rm span}\left\{\cos(\mathbf{k} \cdot \mathbf{x}), \sin(\mathbf{k} \cdot\mathbf{x})\right\}.\]

  • If \(\dim(\mathbf{E}_1) = 4\), then there exist two linearly independent vectors \(\mathbf{k}_1, \mathbf{k}_2\) satisfying \(|\mathbf{k}_1| = |\mathbf{k}_2|\) such that \[\mathbf{E}_1={\rm span}\left\{ \cos(\mathbf{k}_1 \cdot\mathbf{x}), \sin(\mathbf{k}_1 \cdot\mathbf{x}), \cos(\mathbf{k}_2 \cdot\mathbf{x}), \sin(\mathbf{k}_2 \cdot\mathbf{x})\right\}.\]

5.1 2D case↩︎

Theorem 9. Assume that \(\dim(\mathbf{E}_1)=2\). Fix \(\bar{\omega} \in \mathbf{E}_1\) of the form \[\notag \bar \omega(\mathbf{x})=A \cos(\mathbf{k}\cdot \mathbf{x}+\alpha ),\quad A> 0,\,\,\alpha\in\mathbb{R}.\] Then there exist positive constants \(\varepsilon_0=\varepsilon_0(\Lambda,\bar\omega)\) and \(C=C(\Lambda,A)\), such that for any \(\varepsilon\in(0,\varepsilon_0)\) and any mean-zero \(C^1\) solution \(\omega(t,\mathbf{x})\) to 1 , \[{\rm dist}_{2}(\omega(0,\cdot),\mathbf{O}_{\bar\omega})<\varepsilon \quad\Longrightarrow\quad {\rm dist}_{2}(\omega(t,\cdot),\mathbf{O}_{\bar\omega})<C\varepsilon \quad\text{for all } t\in\mathbb{R}.\]

Proof. As in Section 4, denote by \(v_t\) the orthogonal projection of \(\omega_t:=\omega(t,\cdot)\) onto \(\mathbf{E}_1\). Then \(v_t\) can be expressed as \[v_t(\mathbf{x})= B(t)\cos\bigl(\mathbf{k}\cdot \mathbf{x} + \beta(t)\bigr),\quad B(t)\ge 0,\;\beta(t)\in\mathbb{R}.\] For simplicity, write \(B = B(t)\), \(\beta = \beta(t)\) and \(\mathbf{O} = \mathbf{O}_{\bar\omega}\), where \(\bar\omega\) is as in Theorem 9. Then \({\rm dist}_2(v_t,\mathbf{O})\) can be expressed explicitly in terms of the amplitudes \(A, B\): \[\label{501} \begin{align} \mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr)^2 =&\min_{ \mathbf{p}\in\mathbb{T}_\Lambda}\|v_t(\mathbf{x})-\bar\omega(\mathbf{x}-\mathbf{p}) \|^2_{L^2(\mathbb{T}_\Lambda)} =C\min_{\theta \in \mathbb{R}} \left|B-Ae^{i( \theta+\alpha-\beta)}\right|^2 =C|B-A|^2, \end{align}\tag{55}\] where \(C\) denotes various positive constants depending only on \(\Lambda\) and \(A\). By replacing \(\bar\omega\) with another element of its orbit if necessary, we may assume that \[\mathrm{dist}_2(\omega_0,\mathbf{O}) = \|\omega_0-\bar\omega\|_{L^2(\mathbb{T}_\Lambda)} <\varepsilon.\] Then, Lemma 4 with \(k=2\) (note that Lemma 4 actually holds for flat 2-tori of arbitrary shape) yields \[\label{502} \left| \mathsf C_2(v_t) - \mathsf C_2(\bar \omega) \right| =\frac{|\mathbb{T}_\Lambda|}{2}\left|B^2- A^2\right|< C \varepsilon,\tag{56}\] where we have used \[\mathsf C_2(\bar \omega)= \frac{|\mathbb{T}_\Lambda|A^2}{2}\] by a straightforward computation. From 55 and 56 , we get \[\mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr) <C|B-A|<\frac{C\varepsilon}{B+A}< \frac{C\varepsilon}{A},\] and the desired conclusion follows. ◻

5.2 4D case↩︎

Theorem 10. Assume that \(\dim(\mathbf{E}_1)=4\). Fix \(\bar{\omega} \in \mathbf{E}_1\) of the form \[\notag \bar \omega(\mathbf{x})=\sum_{i=1}^2A_i\cos(\mathbf{k}_i\cdot \mathbf{x}+\alpha_i),\quad A_i\geq 0,\,\,\alpha_i\in\mathbb{R},\,\, (A_1,A_2)\neq (0,0).\] Then there exist positive constants \(\varepsilon_0=\varepsilon_0(\Lambda,\bar\omega)\) and \(C=C(\Lambda,A_1,A_2)\), such that for any \(\varepsilon\in(0,\varepsilon_0)\) and any mean-zero \(C^1\) solution \(\omega(t,\mathbf{x})\) to 1 , \[{\rm dist}_{2}(\omega(0,\cdot),\mathbf{O}_{\bar\omega})<\varepsilon \quad\Longrightarrow\quad {\rm dist}_{2}(\omega(t,\cdot),\mathbf{O}_{\bar\omega})<C\varepsilon^\gamma \quad\text{for all } t\in\mathbb{R},\] where \(\gamma=1\) if \(A_1A_2\neq 0\) and \(A_1 \neq A_2\), and \(\gamma= {1}/{2}\) otherwise.

Proof. In this case, write \[v_t(\mathbf{x})=\sum_{i=1}^{2} B_i(t) \cos\left(\mathbf{k}_i \cdot \mathbf{x} + \beta_i(t)\right),\quad B_i(t)\geq0,\;\beta_i(t)\in\mathbb{R}.\] Then \[\notag \begin{align} \mathrm{dist}_2\bigl(v_t,\mathbf{O}_{\bar\omega}\bigr)^2 =&\min_{\mathbf{p}\in\mathbb{T}_\Lambda}\|v_t(\mathbf{x})-\bar\omega(\mathbf{x}-\mathbf{p})\|_{L^2(\mathbb{T}_\Lambda)}^2 \\ =&C\min_{\theta_1, \,\theta_2 \in \mathbb{R}} \left( \left|B_1e^{i\beta_1}-A_1 e^{i(\theta_1+\alpha_1)}\right|^2+ \left|B_2e^{i\beta_2}-A_2 e^{i(\theta_2+\alpha_2)}\right|^2\right)\\ =&C\left(\left|B_1- A_1\right|^2+\left|B_2- A_2\right|^2\right), \end{align}\] which yields \[\notag \begin{align} \mathrm{dist}_2\bigl(v_t,\mathbf{O}_{\bar\omega}\bigr) \leq C\left(\left|B_1- A_1\right|+\left|B_2- A_2\right|\right). \end{align}\] By a straightforward computation, we have that \[\label{C24} \begin{align} &\mathsf C_2(\bar \omega)= \frac{|\mathbb{T}_\Lambda|}{2}(A_1^2 + A_2^2);\\ &\mathsf C_4(\bar \omega)= \frac{3|\mathbb{T}_\Lambda|}{8}\left( A_1^4 + 4A_1^2A_2^2 + A_2^4 \right). \end{align}\tag{57}\] From 57 , we see that \(\mathbf{a}=(A_1^2,A_2^2)\) satisfies the following system: \[\label{4df123b} \begin{cases} f_1(\mathbf{a})= \frac{2}{|\mathbb{T}_\Lambda|} \mathsf C_2(\bar \omega), \\ f_1^2(\mathbf{a})+2f_2(\mathbf{a}) =\frac{8}{3|\mathbb{T}_\Lambda|}\mathsf C_4(\bar \omega). \end{cases}\tag{58}\] Similarly, \(\mathbf{b}=(B_1^2,B_2^2)\) satisfies \[\label{4df123t} \begin{cases} f_1(\mathbf{b}) = \frac{2}{|\mathbb{T}_\Lambda|} \mathsf C_2(v_t), \\ f_1^2(\mathbf{b})+2f_2(\mathbf{b})=\frac{8}{3|\mathbb{T}_\Lambda|}\mathsf C_4(v_t). \end{cases}\tag{59}\] As in the proof of Theorem 9, we may assume that \({\rm dist}_2(\omega_0,\mathbf{O})= \|\omega_0-\bar\omega\|_{L^2(\mathbb{T}_\Lambda)}<\varepsilon\). Then, in view of 58 and 59 , we can apply Lemma 4 to get \[\label{4d-f-control} \left|f_i(\mathbf{a})-f_i(\mathbf{b})\right|< C\varepsilon,\quad i=1,2,\tag{60}\] where \(f_1,f_2\) are the elementary symmetric polynomials in two variables. As in the previous case, a continuity argument shows that, for \(\varepsilon\) sufficiently small, \(b_k(t)\) remains in a sufficiently small neighborhood of \(a_k\) for all \(t\in\mathbb{R}\). Hence the assumptions of Corollary 1 are satisfied. In view of Corollary 1 and 60 , we distinguish three cases:

  • \(A_1\neq A_2\) and \(A_1 A_2\neq 0\). In this case, \[\left|B_i^2-A_i^2\right|<\frac{C \varepsilon}{\left|A_1^2-A_2^2\right|} \quad\Longrightarrow\quad \left|B_i-A_i\right|<\frac{C \varepsilon}{|A_1^2-A_2^2|\,A_i},\] where \(i=1,2.\) Therefore, \[\mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr) < \sum_{i=1}^2\frac{C\varepsilon}{A_i\,|A_1^2-A_2^2|};\]

  • Exactly one of \(A_1, A_2\) vanishes. In this case, without loss of generality, we may assume that \(A_2=0\). We obtain \[|B_1^2-A_1^2|<\frac{C\varepsilon}{A_1^2}\quad\Longrightarrow\quad |B_1-A_1|<\frac{C\varepsilon}{A_1^3}, \qquad |B_2|^2< \frac{C\varepsilon}{A_1^2}\quad\Longrightarrow\quad|B_2|< \frac{C\varepsilon^{1/2}}{A_1}.\] Hence \[\mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr) < \frac{C\varepsilon}{A_1^3}+\frac{C\varepsilon^{1/2}}{A_1}\leq \frac{C\varepsilon^{1/2}}{A_1};\]

  • \(A_1= A_2\neq 0\). In this case, \[|B_i^2-A_i^2|<C\varepsilon^{1/2}\quad\Longrightarrow\quad |B_i-A_i|<\frac{C\varepsilon^{1/2} }{A_i},\] where \(i=1,2.\) Therefore, \[\mathrm{dist}_2\bigl(v_t,\mathbf{O}\bigr) < \frac{C\varepsilon^{1/2} }{A_1}.\]

The proof is complete. ◻

G. Wang was supported by National Natural Science Foundation of China (Grant No. 12471101) and Fundamental Research Funds for the Central Universities (Grant No. DUT23RC(3)077).

Data sharing not applicable to this article as no datasets were generated or analysed during the current study.

The authors declare that they have no conflict of interest to this work.

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