January 01, 1970
Motivated by the works of Gromov and LeBrun in Riemannian geometry, we study the analogous phenomena in complex geometry. We first show that both \(\int_M |S_C^-(g)|^ndV_g\) and \({\rm vol}_g(M)\) (normalized by \(S_C(g)\ge -1\)) are bounded below by \(\frac{(n\pi)^n}{n!}\mathrm{CanVol}(M)\) for any Hermitian metric \(g\) on a compact complex \(n-\)manifold \(M\). Here \(S_C\) denotes the Chern scalar curvature, \(S_C^-=\max\{-S_C,0\}\) and \({\rm CanVol}(M)\) is the canonical volume of \(M\), i.e., the volume of the canonical line bundle \(K_M\). Moreover, if \({\rm vol}_g(M)=\frac{(n\pi)^n}{n!}\mathrm{CanVol}(M)\) holds for some Kähler metric with \(S_C\ge -1\), then it has to be the Kähler-Einstein metric of negative scalar curvature. The completely new phenomenon is that if \(M\) is a compact Kähler manifold such that \(K_M\) is nef, then \({\rm MinVol}_C(M)=\mathcal{I}_C(M)=\mathcal{I}_C^-(M)=\frac{(n\pi)^n}{n!}\mathrm{CanVol}(M)\), where \({\rm MinVol}_C(M)\) is the infimum of \({\rm vol}_g(M)\) with \(S_C(g)\ge -1\) and \(\mathcal{I}_C^-(M)=\inf_g \int_M |S_C^-(g)|^ndV_g\), \(\mathcal{I}_C(M)=\inf_g \int_M |S_C(g)|^ndV_g\). It remains unknown whether the nef condition is superfluous. The answer is positive when \(M\) is obtained by blowing up a finite number of points from a projective manifold with big and nef canonical line bundle. The arguments are based on the asymptotic behaviour of the Bergman kernel of \(mK_M\) as \(m\rightarrow \infty\), the theory of Kähler-Ricci flow and singular Kähler-Einstein metric, as well as a very delicate gluing technique, using the Burns-Simanca metric.
Let us start with a unified way of posing reasonable questions in Riemannian geometry. Given a compact \(n-\)manifold \(M\), define \(\mathcal{RM}(M)\) to be the set of Riemannian metrics \(g\) on \(M\). Consider a nonnegative functional \(\mathcal{F}:\mathcal{RM}(M)\rightarrow \mathbb{R}\) and look for its infimum \(\inf_{\mathcal{RM}(M)} \mathcal{F}\). According to Berger (see [1], p. 530), there are several types of basic questions:
Is \(\inf_{\mathcal{RM}(M)} \mathcal{F}\) zero or positive? Classify the manifolds \(M\) for which \(\inf_{\mathcal{RM}(M)} \mathcal{F}\) is positive and those for which it is zero.
If positive, then is it attained by some Riemannian metric \(g\) on \(M\)? When these best metrics exist, try to classify them.
Find the possible values \(\inf_{\mathcal{RM}(M)} \mathcal{F}\) when \(M\) runs through all compact manifolds of a given dimension. Or at least, we can ask if the set of these values is discrete, or if zero is an isolated point of this set.
Of course, these questions are almost impossible to answer for a general functional \(\mathcal{F}\), so one has to restrict to certain special, but crucial cases, e.g., minimal curvature integrals \[\inf_{g\in \mathcal{RM}(M)} \int_M |K(g)|^{n/2}dV_g,\;\; \inf_{g\in {\mathcal{RM}(M)}} \int_M |Ric(g)|^{n/2}dV_g,\;\; \inf_{g\in {\mathcal{RM}(M)}} \int_M |S(g)|^{n/2}dV_g,\] where \(K(g)\), \(Ric(g)\) and \(S(g)\) stand for sectional curvature, Ricci curvature and scalar curvature respectively. We consider the \(L^{n/2}\) integral instead of general \(L^p\) integrals since it is the only scale-invariant case. Another important example is Gromov’s minimal volume (cf. [2]) \[{\rm MinVol}(M):=\inf_{|K(g)|\le 1} {\rm vol}_g(M)=\inf_{g\in {\mathcal{RM}(M)}} {\rm vol}_g(M) \|K(g)\|_{L^\infty}^{n/2}.\] The Gauss-Bonnet theorem implies \({\rm MinVol}(M)\ge C_n |\chi(M)|\), where \(\chi(M)\) denotes the Euler characteristic of \(M\). Gromov proved the following highly-nontrivial inequality \[{\rm MinVol}(M)\ge \frac{\|M\|}{(n-1)^nn!},\] where \(\|M\|\) is the simplicial volume of \(M\), namely, \(\|M\|:=\inf_c \sum |a_i|\), \(c=\sum a_i\sigma_i\) runs through all representations of the fundamental class \([M]\in H_n(M,\mathbb{R})\). Thus the minimal volume is positive whenever the simplicial volume is. Positivity of the minimal volume provides an obstruction for the collapsing phenomenon in Gromov’s convergence theory. Gromov raised the famous Gap Conjecture: \[\exists\, \varepsilon_n>0\;\text{such that}\;{\rm MinVol}(M)\le \varepsilon_n\Rightarrow {\rm MinVol}(M)=0\] (see [3], [4] for partial answers). A beautiful rigidity theorem due to Besson, Courtois and Gallot [5] states that if \(g\) is a Riemannian metric on a hyperbolic \(n-\)manifold \((M,g_0)\) such that \(Ric(g)\ge -(n-1)g\), then \({\rm vol}_g(M)\ge {\rm vol}_{g_0}(M)\) with equality if and only if \(g\) is isometric to \(g_0\). Note \(|K(g)|\le 1\) implies \(Ric(g)\ge -(n-1)g\). Thus the best metric for \({\rm MinVol}(M)\) is the hyperbolic metric \(g_0\) in this case.
Among \(K(g)\), \(Ric(g)\) and \(S(g)\), the last is the weakest. In his lecture notes on scalar curvature (cf. [6], p. 38–39), Gromov conjectured there exists \(C_n>0\) such that \[\label{eq:Gromov95conj95int} \int_M |S^-(g)|^{n/2}dV_g \ge C_n \|M\|,\;\;\;S^-(g):=\max\{-S(g),0\}.\tag{1}\] Note that 1 implies \({\rm vol}_g(M)\ge C_n \|M\|\) when \(S(g)\ge -1\). This conjecture looks extremely hard since basic tools, such as Bishop-Gromov’s comparison theorem and Cheng-Yau’s gradient estimates, require a lower bound on the Ricci curvature. However, LeBrun [7] was able to show \[\label{eq:LeBrun0} \int_M |S(g)|^{2} dV_g \ge 32 \pi^2 K_M^2\tag{2}\] for minimal complex surfaces of general type, i.e., the canonical line bundle \(K_M\) is big and nef. Here, \(K_M^2 := \int_M c_1(K_M)^2\). Moreover, this inequality is sharp. LeBrun’s method is based on Seiberg-Witten theory, which is not available when the real dimension is greater than \(4\). Actually, every simply-connected compact complex \(n-\)manifolds \(M\) with ample \(K_M\) and \(n\ge 3\) satisfies \[\inf_{g\in \mathcal{RM}(M)} \int_M |S(g)|^{n} dV_g=0,\] in view of Theorem 1 in [8].
The goal of this paper is to consider analogous questions for compact Hermitian manifolds. Our hope is to find certain connections linking differential-geometric and algebraic-geometric points of view. To that end, let us consider a general compact complex \(n-\)manifold \(M\), equipped with a smooth Hermitian metric \(g\) whose Kähler form is given by \(\omega\). Let \(Ric(g)\) and \(Ric(\omega)\) denote the Riemannian Ricci curvature (for the underlying Riemannian metric) and Chern Ricci curvature form respectively. Let \(S_C(g)\) denote the Chern scalar curvature of \(g\). The canonical volume of \(M\) is given by \[\label{eq:CanVolDef} \mathrm{CanVol}(M):= \limsup_{m\rightarrow+\infty}\frac{P_m(M)}{m^n/n!},\tag{3}\] where \(P_m(M):=\dim\Gamma(M,mK_M)\) is the \(m-\)th plurigenus of \(M\). It is known from [9] that \[\mathrm{CanVol}(M)=K_M^n:=\int_Mc_1(K_M)^n,\] when \(M\) is a Kähler manifold and \(K_M\) is nef. Recall that \(M\) is of general type (i.e., \(K_M\) is big) iff \(\mathrm{CanVol}(M)>0\). Our first result is given as follows.
Theorem 1. If \((M,g)\) is a compact Hermitian \(n-\)manifold, then \[\label{eq:LeBrun951} \int_M |S_C^-(g)|^{n} dV_g \geq\frac{(n\pi)^n}{n!}\mathrm{CanVol}(M),\qquad{(1)}\] where \(S_C^-(g)=\max\{-S_C(g),0\}\). Moreover, if \(S_C(g)\ge -1\), then \[\label{eq:volume95lower951} {\rm vol}_g(M)\ge \frac{(n\pi)^n}{n!}\mathrm{CanVol}(M).\qquad{(2)}\] On the other hand, if equality in ?? holds for some Hermitian metric \(g\), then it has to be a Hermitian-Einstein metric, that is, \[Ric(\omega)=\frac{S_C(g)}{n}\omega,\] where \(\omega\) is the Kähler form of \(g\). Furthermore, if \(n\geq2\) and \(g\) is a Kähler metric, then it has to be a Kähler-Einstein metric of constant negative scalar curvature.
Remark 1. For any Einstein metric on a Riemannian manifold of dimension greater than \(2\), the (Riemannian) scalar curvature is constant (see Berger [1]). The same is not true in general for Hermitian manifolds (although true in the Kähler case).
Corollary 2. Let \(M\) be a compact Kähler \(n-\)manifold such that \(K_M\) is big but not ample. Then for any Kähler metric \(g\) with \(S_C(g)\ge -1\), \[\label{eq:volume95lower952} {\rm vol}_g(M) > \frac{(n\pi)^n}{n!}\mathrm{CanVol}(M).\qquad{(3)}\]
Proof. Suppose on the contrary that ?? does not hold. Then equality in ?? holds for suitable Kähler metric \(g\), so that \(g\) is Kähler-Einstein of negative scalar curvature. Then \(K_M\) is ample in view of Kodaira’s theorem, which is a contradiction. ◻
Let \(\mathcal{HM}(M)\) denote the set of Hermitian metrics on a compact complex \(n-\)manifold \(M\). It is reasonable to define \[\mathcal{I}_C(M):=\inf_{g\in \mathcal{HM}(M)} \int_M |S_C(g)|^{n} dV_g,\;\;\mathcal{I}_C^-(M):=\inf_{g\in \mathcal{HM}(M)} \int_M |S_C^-(g)|^{n} dV_g,\] \[\mathrm{MinVol}_C(M):=\inf_{S_C(g)\ge -1} \mathrm{vol}_g(M).\] We have known that under the hypothesis in Corollary 2, \(\mathrm{MinVol}_C(M)\) is not attained by a Kähler metric. It remains unknown whether or not it is achieved by some Hermitian metric.
As a direct consequence of Theorem 1, we have
Corollary 3. \[\label{eq:LeBrun95volume} \min\left\{\mathcal{I}_C(M),\mathrm{MinVol}_C(M)\right\}\ge \mathcal{I}_C^-(M) \geq\frac{(n\pi)^n}{n!}\mathrm{CanVol}(M).\qquad{(4)}\]
Remark 2. A deep result proved independently by Hacon-McKernan [10] and Takayama [11] states that \(\mathrm{CanVol}(M)\ge C_n>0\) when \(M\) is a projective manifold of general type. Thus \(\mathrm{MinVol}_C(M),\) \(\mathcal{I}_C(M)\) and \(\mathcal{I}_C^-(M)\) are all bounded below by some \(C_n>0\).
It is natural to formulate a Gromov-type Gap Conjecture as follows: \[\label{eq:gap95conj} \exists\, \varepsilon_n>0\;\text{such that}\;{\rm MinVol}_C(M)\le \varepsilon_n\Rightarrow {\rm MinVol}_C(M)=0.\tag{4}\] In case \(M\) is a projective \(n-\)manifold, it suffices to verify \[{\rm CanVol}(M) =0 \Rightarrow {\rm MinVol}_C(M)=0.\] If there exists some Hermitian metric \(g\) with \(S_C(g)\ge 0\), for instance, \(M\) is a Fano manifold, then \(\mathrm{MinVol}_C(M)=0\), since \(S_C(tg)=t^{-1}S_C(g)\) and \(dV_{tg}=t^ndV_g\). A typical example is the Hopf manifold \(M_\alpha:=(\mathbb{C}^n\setminus \{0\})/\langle \gamma_\alpha\rangle\), \(\gamma_\alpha=\alpha z\), \(0<|\alpha|<1\). Note that the Hermitian metric \(g=|z|^{-2} \sum dz_j\otimes d\bar{z}_j\) on \(\mathbb{C}^n\setminus \{0\}\) is \(\langle \gamma_\alpha\rangle-\)invariant, so it induces a Hermitian metric on \(M_\alpha\). A direct calculation shows the Ricci form \(Ric(\omega) = 2n i\partial\bar{\partial}\log |z|\ge 0\), where \(\omega\) is the Kähler form of \(g\), so \(S_C(g)\ge 0\) and \(\mathrm{MinVol}_C(M_\alpha)=0\).
The following result is entirely new, in contrast to the Riemannian case.
Theorem 4. If \(M\) is a compact Kähler \(n-\)manifold such that \(K_M\) is nef, then \[\label{eq:LeBrun95equality} \mathrm{MinVol}_C(M)=\mathcal{I}_C(M)=\mathcal{I}_C^-(M)=\frac{(n\pi)^n}{n!}\mathrm{CanVol}(M).\qquad{(5)}\]
Corollary 5. The gap conjecture 4 is true for compact Kähler manifolds with \(K_M\) nef.
Corollary 6. Let \(M'\) be a compact complex \(n-\)manifold which admits a generically finite holomorphic map \(F\) to a compact Kähler \(n-\)manifold \(M\) such that \(K_M\) is nef. Then \[\begin{align} \mathcal{I}_C(M')&\ge& {\rm deg}(F)\, \mathcal{I}_C(M), \label{eq:deg951}\\ \mathcal{I}^-_C(M')&\ge& {\rm deg}(F)\, \mathcal{I}^-_C(M), \label{eq:deg952}\\ \mathrm{MinVol}_C(M')&\ge& {\rm deg}(F)\, \mathrm{MinVol}_C(M). \label{eq:deg953} \end{align}\] {#eq: sublabel=eq:eq:deg951,eq:eq:deg952,eq:eq:deg953} Moreover, if \(F\) is a covering map, then equalities hold.
Conjecture 1. ?? holds for any compact complex \(n-\)manifold (at least when \(K_M\) is big).
To support this conjecture, we shall show
Theorem 7. Let \(M\) be a compact Kähler \(n-\)manifold with \(n\ge 2\) and \(\widehat{M}\) be obtained from \(M\) by blowing-up a finite number of points. If \(K_M\) is big and nef, then ?? holds for \(\widehat{M}\).
Remark 3. The proof of Theorem 7 also yields \(\mathrm{MinVol}_C(\widehat M)=\mathcal{I}_C^-(\widehat{M})=0\) when \(K_M\) is nef but not big (see § 7 for details).
Our analysis relies heavily on asymptotic behaviour of the Bergman kernel of \(mK_M\) as \(m\rightarrow \infty\), as well as the theory of Kähler-Ricci flow and existence of the singular Kähler-Einstein metric (when \(K_M\) is big). More precisely, ?? follows directly from the arithmetic-geometric mean inequality and the well-known asymptotic upper bound of the Bergman kernel of \(mK_M\) (which follows easily from the mean-value inequality of plurisubharmonic functions (cf. [12]; see also [13])). If \(M\) is a projective manifold of general type, then there exists a singular Kähler-Einstein metric \(g_{KE}\), which is smooth on some Zariski open subset \(U\subset M\) (cf. [14], see also [15]). With the help of asymptotic lower bound of the Bergman kernel of \(mK_M\) with respect to \(g_{KE}\), ?? for the big case can be reduced to find a sequence \(\{g_j\}\) of smooth Hermitian metrics on \(M\) such that
\(g_j\rightarrow g_{KE}\) in \(C^\infty_{\mathrm{loc}}-\)topology on \(U\);
both \(dV_{g_j}\) and \(|S_C(g_j)|\) are uniformly bounded on \(M\);
\(S_C(g_j)\ge -n\).
In case \(K_M\) is big and nef, the Kähler-Ricci flow fits well with this purpose. It remains open whether the above sequence exists for any compact Kähler manifold of general type. The proof of Theorem 7 is based on a rather delicate gluing technique using the Burns-Simanca metric (compare [16] and [17]).
An even more interesting problem is to find the relations between the canonical volume and the simplicial volume. For instance, it is unknown whether there exists a constant \(C_n>0\) such that \[\label{eq:CV-SV} \mathrm{CanVol}(M)\geq C_n\|M\|\tag{5}\] for any compact complex \(n-\)manifold \(M\). Note that 5 would imply a conjecture of Zhang [18] that \(\|M\|=0\) provided \({\rm CanVol}(M)=0\). Gromov [2] showed that if the Ricci curvature of a Riemannian metric \(g\) is bounded below by \(-1\), then \[{\rm vol}_g (M)\ge \frac{\|M\|}{(n-1)^nn!}.\] This combined with the argument in § 6 would imply 5 for projective manifolds of general type, provided that there exists a sequence \(\{g_j\}\) of Kähler metrics on \(M\) such that
\(g_j\rightarrow g_{KE}\) in \(C^\infty_{\mathrm{loc}}-\)topology on \(U\);
\(dV_{g_j}\) is uniformly bounded on \(M\);
\(Ric(\omega_j)\ge -\omega_j\), where \(\omega_j\) is the Kähler form of \(g_j\).
Using a result of LeBrun [19], we will show in § 8 that for certain complex surfaces of general type \(g_{KE}\) cannot be approximated by Kähler metrics such that both the volume form and the Ricci form are uniformly bounded. We will return to this topic in a future paper.
Finally, recall that the Kodaira dimension of a compact complex \(n-\)manifold is defined to be \[\kappa (M):=\limsup_{m\rightarrow+\infty}\frac{\log P_m(M)}{\log{m}}.\] It is well known that there exists a constant \(C>1\) such that \[C^{-1} m^{\kappa(M)} \le P_m(M) \le C m^{\kappa(M)}\] (see [20]). Two interesting questions immediately arise. The first is to look for a geometric bound similar as scalar curvature integral or minimal volume for the quantity \[\limsup_{m\rightarrow+\infty}\frac{P_m(M)}{{m}^{\kappa(M)}}.\] The other is to find the relationship between \(\kappa(M)\) and the Ricci rank \(\mathcal{R}_g\) of a Hermitian metric \(g\), i.e., the maximum of the number of negative eigenvalues of \(Ric(\omega)\). Liu [21] proved \(\kappa(M)=\mathcal{R}_g\) when \(g\) is a Kähler metric with nonpositive bisectional curvature (see also Wu-Zheng [22] for real-analytic case). In general, we have the following
Proposition 8. If \((M,g)\) is a compact Hermitian \(n-\)manifold, then \[\kappa(M)\leq \frac{\mathcal{R}_g+2n}{3} = \mathcal{R}_g+\frac{2}{3}(n-\mathcal{R}_g).\]
Proposition 8 turns out to be a fairly simple consequence of a very precise asymptotic upper bound for the Bergman kernel, which is given as follows. Consider a compact Hermitian \(n-\)manifold \((M,g)\) and a holomorphic line bundle \(L\) over \(M\). Given a (possibly singular) Hermitian metric \(h=e^{-\phi}\) of \(L\), define the Bergman space of \(mL=L^{\otimes m}\) to be \[A^2_{g,h}(M,mL):=\left\{s\in \Gamma(M,mL): \int_M |s|^2_{h^{\otimes m}} dV_g<\infty\right\},\] where \(\Gamma(M,mL)\) denotes the space of holomorphic sections of \(mL\) over \(M\). The corresponding Bergman kernel function is given by \[B_{g,h,mL} (x)=\sum |s_j(x)|^2_{h^{\otimes m}}\] for an/any orthonormal basis \(\{s_j\}\) of \(A^2_{g,h}(M,mL)\). In case \(L=K_M\) and \(h=(dV_g)^{-1}\), we simply write \(B_m\) instead of \(B_{g,(dV_g)^{-1},mK_M}\).
Theorem 9. Let \((M,g)\) be a compact Hermitian \(n-\)manifold. Let \(\lambda_1,\cdots,\lambda_n\) be eigenvalues of the Ricci form \(Ric(\omega)\) associated to \(\omega\). Fix \(A_m>0\) with \[\lim_{m\rightarrow+\infty}A_m=+\infty \;\; \text{and}\;\; \lim_{m\rightarrow+\infty}A_m/m^{1/3}=0.\] Then there exists a constant \(C>0\) such that \[\label{eq:Bergman95upper951951} B_{m}(x) \leq \left(1+\frac{C A_m^{3/2}}{m^{1/2}}\,\right)\,\frac{m^n}{\pi^nA_m^{n-p-q}}\left(\prod_{\lambda_j\neq0}|\lambda_j|\right)\left(\prod_{\lambda_j>0}e^{-\lambda_jA_m}\right)\qquad{(6)}\] holds uniformly on \(M\) as \(m\rightarrow \infty\). Here \(p\) (resp. \(q\)) is the number of positive (resp. negative) eigenvalues at \(x\).
A large literature exists on the asymptotic behaviour of the Bergman kernel of \(mL\) as \(m\rightarrow \infty\) in case \(L\) is ample, among them the most famous is the so-called Tian-Yau-Catlin-Zelditch asymptotic expansion (see e.g., [23], [24], [25], [26]), which has deep applications in Kähler geometry. Although the proof of Theorem 9 is only a refinement of known methods, the theorem itself might be of independent interest. For instance, it gives a new proof of the following classical vanishing result.
Theorem 10 (cf. [27], Corollary 3.1.16). Let \((M,g)\) be a compact Hermitian manifold. If the Ricci form admits at least one positive eigenvalue everywhere on \(M\), then \(P_m(M)=0\).
Recently, Theorem 10 has been extended substantially by Yang in [28].
Let \(M\) be a complex \(n-\)manifold. Let \(g\) be a Hermitian metric given locally by \(\sum^n_{j,k=1}g_{j\bar{k}}dz_j\otimes {d\bar{z}_k}.\) Then locally \(\omega=i\sum^n_{j,k=1}g_{j\bar{k}}dz_j\wedge d\bar{z}_k\) is the Kähler form of \(g\). The Chern Ricci curvature form of \(\omega\) is defined by \[Ric(\omega)=-i\partial\bar{\partial}\log\det(g_{j\bar{k}}).\] The trace of \(Ric(\omega)=: i \sum R_{j\bar{k}}dz_j\wedge d\bar{z}_k\) is called the Chern scalar curvature \(S_C(g)\) of \(g\), namely, \[S_C(g)=\mathrm{tr}_g(Ric(\omega))=\sum g^{j\bar{k}}R_{j\bar{k}},\] where \((g^{j\bar{k}})=(g_{j\bar{k}})^{-1}\). It is well-known that the Riemannian scalar curvature equals twice the Chern scalar curvature if \(g\) is a Kähler metric. In general, the relationship between them is much more complicated (compare [29]).
Let \(M\) be a complex \(n-\)manifold and \(L\) a holomorphic line bundle over \(M\). A singular Hermitian metric of \(L\) may be written as \[h=h_0 e^{-\varphi}\] where \(h_0\) is a smooth Hermitian metric of \(L\) and \(\varphi\in L^1_{\mathrm{loc}}(M)\). \(L\) is said to be pseudoeffective if there exists a singular Hermitian metric \(h\) of \(L\) such that \[\Theta_h = \Theta_{h_0} + i\partial\bar{\partial} \varphi\] is a closed positive current.
The multiplier ideal sheaf \(\mathcal{I}(h)\subset \mathcal{O}_M(L)\) of \((M,L)\) is defined by \[\Gamma(U,\mathcal{I}(h)):=\left\{f\in \Gamma(U,\mathcal{O}_U(L)): |f|^2_{h_0} e^{-\varphi}\in L^1_{\rm loc}(U)\right\}.\] Following Tsuji [30], \(h\) is called an analytic Zariski decomposition if
\(\Theta_h\) is a closed positive current,
for every \(m\ge 0\), the natural inclusion \[H^0\left(M,mL\otimes \mathcal{I}(h^{\otimes m})\right ) \rightarrow H^0(M,mL)\] is an isomorphism.
Here we collect some basic facts about the Kähler-Ricci flow by following the lecture notes of Song and Weinkove (cf. [31], p. 19, 20, 48). Let \((M,g_0)\) be a compact Kähler \(n-\)manifold. A Kähler-Ricci flow means the following equation \[\label{eq:KR1} \frac{\partial \omega_t}{\partial t}=-Ric(\omega_t),\;\;\;\omega_t|_{t=0}=\omega_0,\tag{6}\] and the normalized Kähler-Ricci flow is given by \[\label{eq:KR2} \frac{\partial \omega_t}{\partial t}=-Ric(\omega_t)-\omega_t,\;\;\;\omega_t|_{t=0}=\omega_0,\tag{7}\] where \(\omega_t\) is the Kähler form of \(g_t\). We shall focus on 7 . Then the following properties hold:
There exists a unique solution \(g_t\) of 7 on some maximal time interval \([0,T)\) with some \(0<T\le \infty\). If \(K_M\) is nef, then one can take \(T=\infty\).
Set \(C_0:=-\inf_M S_C(g_0)-n\). Then \[\label{eq:ScalarLower} S_C(g_t) \ge -n - C_0 e^{-t},\;\;\; t\in [0,T).\tag{8}\]
Let \(C_0\) be as above. Then \[\label{eq:volumeCompare} dV_{g_t} \le e^{C_0(1-e^{-t})} dV_{g_0},\;\;\; t\in [0,T).\tag{9}\] In particular, \(dV_{g_t}\) is uniformly bounded from above for \(t\in [0,T)\).
A deeper observation is the following theorem of Zhang [32] (for a generalization to the semi-ample case, see Song-Tian [33]).
Theorem 11. If \(M\) is a projective manifold such that \(K_M\) is big and nef, then \(S_C(g_t)\) is uniformly bounded for all \(t\in [0,\infty)\).
The Kähler-Ricci flow was first used by Cao [34] to give an alternative proof of Yau’s theorem on the existence of Kähler-Einstein metric on compact Kähler manifolds with trivial or negative first Chern class (cf. Yau [35]; see also Aubin [36] for the negative case). Tsuji [37] (see also Tian-Zhang [38]) proved the following
Theorem 12. If \(K_M\) is big and nef, then the solution \(g_t\) of 7 converges in \(C^\infty_{\rm loc}-\)topology on some Zariski open set \(U\subset M\) to a Kähler-Einstein metric \(g_{KE}\) on \(U\). Moreover, the Kähler form of \(g_{KE}\) extends to a closed positive current on \(M\).
One calls \(g_{KE}\) a singular Kähler-Einstein metric on \(M\). Tsuji’s work was extended by Eyssidieux-Guedj-Zeriahi [39], Boucksom et al. [15] and Song-Tian [14] to general projective manifolds of general type.
Theorem 13 (cf. [14], Theorem B1, C1). Let \(M\) be a projective manifold of general type. Then there exists a measure \(dV_{KE}\) such that
\((K_M,(dV_{KE})^{-1})\) is an analytic Zariski decomposition,
\(\omega_{KE}:=i\partial\bar{\partial}\log dV_{KE}\) is a closed positive current on \(M\); moreover, \(\omega_{KE}\) is smooth on a Zariski open set \(U\subset M\) and satisfies \[{\rm Ric}(\omega_{KE})=-\omega_{KE} \;\;\;\text{on\;\;}U.\]
Denote by \(\mathrm{Bl}_0\mathbb{C}^n\) the blow-up of \(\mathbb{C}^n\) at the origin, i.e., \[\mathrm{Bl}_0\mathbb{C}^n:=\left\{(z,[\zeta])\in\mathbb{C}^n\times\mathbb{P}^{n-1},\;z_j\zeta_k=z_k\zeta_j,\;1\leq j,k\leq n\right\}.\] Here \([\zeta]=[\zeta_1:\cdots:\zeta_n]\) is the homogeneous coordinate on \(\mathbb{P}^{n-1}\). It is known that \(\mathrm{Bl}_0\mathbb{C}^n\) is the total space of the tautological line bundle over \(\mathbb{P}^{n-1}\) with a natural projection \(\pi:\mathrm{Bl}_0\mathbb{C}^n\rightarrow\mathbb{P}^{n-1}\). In particular, \(\mathrm{Bl}_0\mathbb{C}^n\) is a complex manifold. There is another natural holomorphic map \[\varpi:\mathrm{Bl}_0\mathbb{C}^n\rightarrow\mathbb{C}^n,\;\;\;(z,[\zeta])\mapsto z,\] which maps \(\mathrm{Bl}_0\mathbb{C}^n\setminus\varpi^{-1}(0)\) biholomorphically to \(\mathbb{C}^n\setminus\{0\}\). Recall that \(\varpi^{-1}(0)\) is called the exceptional locus, which is a submanifold of \(\mathrm{Bl}_0\mathbb{C}^n\) (biholomorphic to \(\mathbb{P}^{n-1}\)).
The Burns-Simanca metric \(g_{BS}\) is a Kähler metric on \(\mathrm{Bl}_0\mathbb{C}^n\) with zero scalar curvature (cf. [40], [41]). On the complement of the exceptional divisor, its Kähler form can be written as \[\omega_{BS}=i\partial\bar{\partial}\left(\frac{|z|^2}{2}+\psi(z)\right),\] where \[\label{eq:BS95zero} \psi(z)=a\log|z|^2+\eta(|z|^2)\tag{10}\] for some smooth function \(\eta\) on \([0,+\infty)\) and \(a>0\). When \(n=2\), one can take \(a=1\) and \(\eta\equiv0\); when \(n\geq3\), \(\eta\) cannot be written explicitly, but we have the asymptotic expansion \[\label{eq:BS95infty} \psi(z)=-|z|^{4-2n}+O(|z|^{2-2n}),\;\;\;|z|\to \infty\tag{11}\] (see [17]).
The formula 10 enables us to extend \(\omega_{BS}\) through the exceptional locus. Indeed, if \((z,[\zeta])\in\mathrm{Bl}_0\mathbb{C}^n\), then \[\log|z|^2=\log\left(\sum^n_{j=1}\frac{|\zeta_j|^2|z_k|^2}{|\zeta_k|^2}\right)=\log|\zeta|^2+\log|z_k|^2-\log|\zeta_k|^2,\] where \(z_k,\zeta_k\neq0\), so that \[i\partial\bar{\partial}\log|z|^2=i\partial\bar{\partial}\log|\zeta|^2.\] As a consequence, we have \[\label{eq:BS95FS} \omega_{BS}=a\cdot \pi^*\omega_{FS}+\varpi^*\left(i\partial\bar{\partial}\left(\frac{|z|^2}{2}+\eta(|z|^2)\right)\right)\tag{12}\] outside the exceptional locus, where \(\omega_{FS}\) is the Fubini-Study metric on \(\mathbb{P}^{n-1}\).
We present the following refinement of Demailly-Nadel’s vanishing theorem which might be useful for other purposes.
Theorem 14. Let \(M\) be a projective \(n-\)manifold equipped with a Kähler metric \(g\) and \(L\) a holomorphic line bundle over \(M\) equipped with a singular Hermitian metric \(h=e^{-\varphi}\) satisfying
\(\Theta_h\) is a closed positive current on \(M\),
\(h\) is smooth on some open set \(U\subset M\) and there exists a continuous positive \((1,1)\)-form on \(\gamma\) on \(U\) such that \[i\partial\bar{\partial}\varphi\geq\gamma\;\;\;\text{on\;\;} U.\]
Then for any \(\bar{\partial}\)-closed \(v\in L^2_{(0,1)}(M,K_M+ L)\) with \(\mathrm{supp}\,v\subset U\) and \[\int_M|v|^2_{(dV_g)^{-1},\gamma}e^{-\varphi}dV_g:=\int_U |v|^2_{(dV_g)^{-1},\gamma}e^{-\varphi}dV_g<+\infty,\] there exists \(u\in L^2(M,K_M+ L)\) such that \(\bar{\partial}u=v\) and \[\int_M|u|^2_{(dV_g)^{-1}}e^{-\varphi}dV_g\leq\int_M |v|^2_{(dV_g)^{-1},\gamma}e^{-\varphi}dV_g.\] Here if we write \(v=\sum v_j dz_1\wedge\cdots \wedge dz_n \wedge d\bar{z}_j \otimes \xi\) and \(\gamma=\sum \gamma_{jk} dz_j\wedge d\bar{z}_k\) in local coordinates, then \[|v|^2_{(dV_g)^{-1},\gamma} = \sum \gamma^{jk} v_j\bar{v}_k,\;\;\;(\gamma^{jk})=(\gamma_{jk})^{-1}.\]
Proof. Take an ample divisor \(E\) of \(M\), so that \(M':=M\setminus E\) is a Stein manifold. Fix a smooth Hermitian metric \(h_0=e^{-\varphi_0}\) of \(L\) and set \(\psi=\varphi-\varphi_0\). Then
\(i\partial\bar{\partial}\psi+i\partial\bar{\partial}\varphi_0\geq0\) on \(M\) in the sense of currents,
\(i\partial\bar{\partial}\psi+i\partial\bar{\partial}\varphi_0\geq\gamma\) on \(U\).
Since \(M'\) is Stein, there exists a nontrivial holomorphic section \(f\) of \(L\) over \(M'\), in view of Cartan’s Theorem A. It follows that \[\phi:=\psi-\log|f|^2_{h_0}\] is a smooth plurisubharmonic (psh) exhaustion function on \(M'':=M'\setminus\{f=0\}\), which satisfies \[i\partial\bar{\partial}\phi\geq\gamma\;\;\;\text{on\;\;} M''\cap U.\] In particular, \(M''\) is a Stein manifold since \(M'\) is, which can be realized as a closed complex submanifold of \(\mathbb{C}^{2n+1}\). Thus there exists a neighbourhood \(W\) of \(M''\) in \(\mathbb{C}^{2n+1}\) and a holomorphic retraction \(\Psi:W\rightarrow M''\), so that \(\phi\circ\Psi\) is psh on \(W\). Let \(\{M_j\}\) be an increasing sequence of relatively compact Stein domains in \(M''\) such that \(\bigcup^\infty_{j=1}M_j=M''\). By standard regularization of \(\phi\circ \Psi\), we may find a smooth strictly psh function \(\phi_j\) on \(M_j\) such that \(\phi_j\downarrow\phi\) and \[i\partial\bar{\partial}\phi_j\geq\gamma\;\;\;\text{on }M_j\cap U_0.\]
With \(\varphi_j:=\varphi_0+\phi_j+\log|f|^2_{h_0}\), \(h_j:=e^{-\varphi_j}\) becomes a smooth Hermitian metric of \(L\) over \(M_j\) satisfying
\(i\partial\bar{\partial}\varphi_j\geq i\partial\bar{\partial}\phi_j>0\) on \(M_j\),
\(i\partial\bar{\partial}\varphi_j\geq\gamma\) on \(M_j\cap{U}\),
\(\varphi_j\downarrow\varphi\) as \(j\uparrow+\infty\).
By standard \(L^2\) estimates for \(\bar{\partial}\) on complete Kähler manifolds (see e.g., [9]), we can find a solution \(u_j\) of \(\bar{\partial}u=v\) on \(M_j\) such that \[\int_{M_j}|u_j|^2_{(dV_g)^{-1}}e^{-\varphi_j}dV_g \leq \int_{M_j}|v|^2_{(dV_g)^{-1},i\partial\bar{\partial}\phi_j}e^{-\varphi_j}dV_g \leq \int_M|v|^2_{(dV_g)^{-1},\gamma}e^{-\varphi}dV_g.\] Thanks to the Banach-Alaoglu theorem, there exists a weak limit \(u\) of \(\{u_j\}\) such that \(\bar{\partial}u=v\) holds in the sense of distributions on \(M''\), together with estimate \[\int_{M''}|u|^2_{(dV_g)^{-1}}e^{-\varphi}dV_g \leq \int_M|v|^2_{(dV_g)^{-1},\gamma}e^{-\varphi}dV_g.\] The conclusion follows immediately from the well-known \(L^2\) extension property of the \(\bar{\partial}\)-equation across analytic sets (cf. [9]). ◻
Proof of Theorem 9. For the sake of simplicity, we write \[|s|_m^2:= |s|^2_{(dV_g)^{-\otimes m}}=\frac{|f|^2}{(\det(g_{j\bar{k}}))^m}, \;\;\;s=f\, (dz_1\wedge\cdots\wedge dz_n)^{\otimes m}\in \Gamma(M,mK_M).\] Recall that the Bergman kernel function \(B_m\) enjoys the following extremal property \[\label{eq:extremal} B_m(x)=\sup\left\{|s(x)|^2_m:s\in{\Gamma(M,mK_M)},\;\int_M|s|^2_mdV_g\leq1\right\}.\tag{13}\] A trivial but very useful formula is \[\label{eq:plurigenera} P_m(M)=\int_M B_m dV_g.\tag{14}\]
Let \(\lambda_1,\cdots,\lambda_n\) be the eigenvalues of \(Ric(\omega)=i\sum R_{j\bar{k}}dz_j\wedge d\bar{z}_k\) with respect to \(g\), that is, the eigenvalues of the matrix \((g_{j\bar{k}})^{-1}(R_{j\bar{k}})\), with \(\lambda_1\leq\lambda_2\leq\cdots\leq\lambda_n\). Note that \(\lambda_j=\lambda_j(x)\) is merely a continuous function on \(M\). If we write \(\varphi=\log\det(g_{j\bar{k}})\), then \[\label{eq:det} (i\partial\bar{\partial}\varphi)^n=(-1)^nn!\lambda_1\cdots\lambda_ndV_g\tag{15}\] and \[\label{eq:tr} \mathrm{Tr}_g(i\partial\bar{\partial}\varphi)=-S_C=-(\lambda_1+\cdots+\lambda_n).\tag{16}\]
Fix \(x\in{M}\) and take a local coordinate \((z_1,\cdots,z_n)\) around \(x\) with \(z(x)=0\). Near \(x\), the Kähler form \(\omega\) of the Hermitian metric \(g\) may be expressed as \[\omega=\frac{i}{2}\sum^n_{j=1}dz_j\wedge{d\bar{z}_j}+ O(|z|),\] so that \[dV_g:=\frac{\omega^n}{n!}=\left(1+O(|z|)\right)\left(\frac{i}{2}\right)^n dz_1\wedge{d\bar{z}_1}\wedge\cdots\wedge{dz_n\wedge{d\bar{z}_n}}=:\left(1+O(|z|)\right)dV_0.\] Moreover, we have \[\varphi(z)=\varphi(0)-\sum^n_{j=1}\lambda_{j}|z_j|^2 + 2\mathrm{Re}\,P(z)+O(|z|^3),\] where \(P\) is a complex polynomial of degree \(2\) with \(P(0)=0\).
Take \(0<r\ll1\). For every \(s\in\Gamma(M,mK_M)\) with \(\int_M|s|^2_m e^{-m\varphi}dV_g\leq1\), we can identify \(s\) with a holomorphic function near \(x\), so that \[\begin{align} 1 &\geq& \int_{|z_j|<r,\atop 1\leq{j}\leq{n}}|s|^2e^{-m\varphi}dV_g\\ &=& \int_{|z_j|<r,\atop1\leq{j}\leq{n}}\left|s(z)e^{-mP(z)}\right|^2e^{-m\varphi(0)+m\sum^n_{j=1}\lambda_j|z_j|^2+O(m|z|^3)}\left(1+O(|z|)\right)dV_0\\ &\ge & e^{-m\varphi(x)}\left(1-Cr\right)\left(1-Cmr^3\right)\int_{|z_j|<r,\atop1\leq{j}\leq{n}}\left|s(z)e^{-mP(z)}\right|^2e^{m\sum^n_{j=1}\lambda_j|z_j|^2}dV_0\\ &\geq& |s(x)|^2e^{-m\varphi(x)}\left(1-Cr\right)\left(1-Cmr^3\right)\prod^n_{j=1}\int_{|z_j|<r}e^{m\lambda_j |z_j|^2}dV_{z_j}, \end{align}\] in view of the mean value inequality, where \(dV_{z_j}\) is the Euclidean volume element in the \(z_j-\)plane. Here and in what follows, \(C\) denotes a generic positive constant and \(r=o(m^{-1/3})\) as \(m\rightarrow+\infty\). It follows from 13 that \[\label{eq:Bergman95upper951a} B_{m}(x)\leq \left(1+Cr+Cmr^3\right)\prod^n_{j=1}\left(\int_{|z_j|<r}e^{m\lambda_j|z_j|^2}dV_{z_j}\right)^{-1}.\tag{17}\] A straightforward calculation shows \[\begin{align} \int_{|z_j|<r}e^{m\lambda_j|z_j|^2}dV_{z_j} &=& \begin{cases} \frac{\pi}{m\lambda_j}(e^{m\lambda_j r^2}-1),\;\;\;&\lambda_j\neq0,\\ \pi{r}^2,\;\;\;&\lambda_j=0. \end{cases} \end{align}\]
Now suppose that \(Ric(\omega)|_x=-i\partial\bar{\partial}\varphi|_x\) admits \(p=p(x)\) positive eigenvalues and \(q=q(x)\) negative eigenvalues, i.e., \[\label{eq:eigenvalues} \lambda_1\leq\cdots\leq\lambda_q<0,\;\;\;\lambda_{q+1}=\cdots=\lambda_{n-p}=0,\;\;\;\lambda_n\geq\cdots\geq\lambda_{n-p+1}>0.\tag{18}\] Note that \(p(x)\) and \(q(x)\) are lower semicontinuous functions on \(M\).
Take \(A_m>0\) with \(\lim_{m\rightarrow+\infty}A_m=+\infty\) and \(\lim_{m\rightarrow+\infty}A_m/m^{1/3}=0\). Let us choose \(r=(A_m/m)^{1/2}\).
If \(1\leq j\leq q\), then \[\int_{|z_j|<r}e^{m\lambda_j|z_j|^2}dV_{z_j} =\frac{\pi}{|\lambda_j|}\frac{1-e^{-|\lambda_j|A_m}}{m}\sim \frac{\pi}{|\lambda_j|m},\;\; \text{as\;} m\rightarrow+\infty.\]
If \(q+1\leq j\leq n-p\), then \[\int_{|z_j|<r}e^{m\lambda_j|z_j|^2}dV_{z_j} =\pi\cdot\frac{A_m}{m}.\]
If \(n-p+1\leq j\leq n\), then \[\int_{|z_j|<r}e^{m\lambda_j|z_j|^2}dV_{z_j} =\frac{\pi}{\lambda_j}\frac{e^{\lambda_jA_m}-1}{m} \sim\frac{\pi}{\lambda_jm}e^{\lambda_jA_m},\;\; \text{as\;} m\rightarrow+\infty.\]
These together with 17 yield ?? . ◻
Remark 4. Theorem 9 implies \[\label{eq:Bergman95upper951} \limsup_{m\rightarrow+\infty}\frac{B_m(x)}{m^n}\leq (-1)^n\frac{\lambda_1\cdots\lambda_n}{\pi^n},\;\;\;x\in{M_0}\qquad{(7)}\] \[\label{eq:Bergman95upper952} \limsup_{m\rightarrow+\infty}\frac{B_m(x)}{m^n}=0,\;\;\;x\notin{M_0},\qquad{(8)}\] where \(M_0:=\{x\in M:Ric(\omega)|_x<0\}=\{x\in M:q(x)=n\}\). Both ?? and ?? are well-known (see e.g., [12], [13]).
Proof of Theorem 10. Choose \(A_m=m^\alpha\) for \(\alpha\in(0,1/3)\) in Theorem 9. If \(p(x)>0\), i.e., \(Ric(\omega)|_x\) admits a positive eigenvalue \(\lambda_1\), then \[\label{eq:vanishing95Bergman} B_m(x)\leq e^{-cm^\alpha}\tag{19}\] for some \(c>0\) independent of \(x\). If \(Ric(\omega)|_x\) admits a positive eigenvalue everywhere on \(M\), then 19 holds for every \(x\in M\). It follows from 14 that \(\kappa(M)=-\infty\), i.e., \(P_m(M)=0\), \(\forall\,m\). ◻
Proof of Proposition 8. By the proof of Theorem 10, it suffices to assume \(p(x)=0\), i.e., \(Ric(\omega)|_x\leq0\). With \(A_m=m^\alpha\) for \(\alpha\in(0,1/3)\), Theorem 9 yields \[\label{eq:RicciRank95Bergman} B_m(x)\leq \left(1+Cm^{\frac{3\alpha-1}{2}}\right)\frac{1}{\pi^n}\left(\prod_{\lambda_j\neq0}|\lambda_j|\right)m^{\alpha q+(1-\alpha)n}\tag{20}\] for some positive constant \(C\) independent of \(x\). Note that \(q\leq \mathcal{R}_g\). By 14 , 19 and 20 , we have \[\kappa(M)\leq \alpha \mathcal{R}_g+(1-\alpha)n=\mathcal{R}_g+(1-\alpha)(n-\mathcal{R}_g),\;\;\;\forall\,0<\alpha<1/3.\] The conclusion follows by letting \(\alpha\rightarrow1/3\). ◻
With the help of Theorem 14, Tian’s method of peak functions (cf. [25]) applies to the following
Theorem 15. Let \(M\) be a projective \(n-\)manifold equipped with a Kähler metric \(g_0\). Let \(g\) be a smooth Hermitian metric defined on an open set \(U\subset M\) with Kähler form \(\omega\), such that
\(Ric(\omega)<0\) on \(U\),
the curvature of the metric \((dV_g)^{-1}\) on \(K_M|_{U}\) extends to a closed positive current on \(M\).
Let \(\lambda_1,\cdots,\lambda_n\) be the eigenvalues of \(Ric(\omega)\) with respect to \(g\) on \(U\). Set \[\widetilde{B}_m(x) = B_{g_0,(dV_g)^{-1},mK_M}(x).\] Then \[\label{eq:AsympLower} \liminf_{m\rightarrow+\infty}\frac{\widetilde{B}_m(x)}{m^n}\geq (-1)^n\frac{\lambda_1\cdots\lambda_n}{\pi^n}\cdot \frac{dV_g}{dV_{g_0}}(x), \;\;\;\forall\;x\in U.\qquad{(9)}\]
Proof. For any fixed \(x\in{M}\), we can take a local coordinate \((z_1,\cdots,z_n)\) around \(x\) such that \(z(x)=0\), and the Kähler form \(\omega_0\) of \(g_0\) may be written as \[\omega_0=\sum dz_j\wedge{d\bar{z}_j}+ O(|z|).\] Moreover, if one writes \((dV_g)^{-1}=e^{-\varphi}\) near \(x\), then \[\varphi(z)=\varphi(0)-\sum \lambda_{j}|z_j|^2 + 2\mathrm{Re}\,P(z)+O(|z|^3),\] where \(P\) is a complex polynomial of degree \(2\) with \(P(0)=0\). Without loss of generality, we may assume that the coordinate neighbourhood is the unit ball \(\mathbb{B}^n\) and it is contained in \(U\); moreover, \(Ric(\omega)\leq -2\varepsilon \omega\) on \(\mathbb{B}^n\) for some \(\varepsilon>0\), so that \(\lambda_j\leq -2\varepsilon\) for \(j=1,2,\cdots,n\).
As before, take \(A_m>0\) with \(A_m\rightarrow+\infty\) and \(A_m/m^{1/3}\rightarrow0\) as \(m\rightarrow+\infty\). Let \(\chi:[0,+\infty)\rightarrow[0,1]\) be a smooth cut-off function such that \(\chi|_{[0,1]}=1\) and \(\chi|_{[2,+\infty)}=0\). Set \[\begin{align} \chi_m(z) & := & \chi\left(\left(m/A_m\right)^{1/2}z\right)e^{mP(z)} (dz_1\wedge\cdots\wedge dz_n)^{\otimes (m+1)}\\ v_m & := & e^{mP}\bar{\partial}\chi_m\otimes (dz_1\wedge\cdots\wedge dz_n)^{\otimes (m+1)}. \end{align}\] Note that \[\begin{align} \label{eq:chi95m95L2} \int_M|\chi_m|^2_{(dV_{g_0})^{-1}\otimes (dV_g)^{\otimes (-m)}} dV_{g_0} &\le & \int_{|z|\leq 2(A_m/m)^{1/2}} e^{-m\varphi(0)+m\sum^n_{j=1}\lambda_j|z_j|^2-O(m|z|^3)}(1+O(|z|))dV_0(z)\notag\\ &\le& e^{-m\varphi(x)}\left(1-C\frac{A_m^{3/2}}{m^{1/2}}\right)\int_{|z|\leq 2(A_m/m)^{1/2}} e^{m\sum^n_{j=1}\lambda_j|z_j|^2}dV_0(z)\notag\\ &=& \frac{e^{-m\varphi(x)}}{m^n}\left(1-C\frac{A_m^{3/2}}{m^{1/2}}\right)\int_{|\zeta|\leq 2 A_m^{1/2}} e^{\sum^n_{j=1}\lambda_j|\zeta_j|^2}dV_0(\zeta)\notag\\ &\sim& \frac{e^{-m\varphi(x)}}{m^n}\int_{\zeta\in\mathbb{C}^n} e^{\sum^n_{j=1}\lambda_j|\zeta_j|^2}dV_0(\zeta)\notag\\ &=& \frac{\pi^n}{m^n}\left(\prod^n_{j=1}|\lambda_j|\right)^{-1}e^{-m\varphi(x)},\;\;\;m\rightarrow+\infty. \end{align}\tag{21}\] Moreover, \[\begin{align} \label{eq:v95m95L2} && \int_M|v_m|^2_{(dV_{g_0})^{-1}\otimes (dV_g)^{\otimes (-m)}} dV_{g_0}\nonumber\\ &\leq& \frac{m}{A_m}\sup|\chi'|^2\int_{(A_m/m)^{1/2}\leq |z|\leq 2(A_m/m)^{1/2}}e^{-m\varphi(0)+m\sum^n_{j=1}\lambda_j|z_j|^2-O(m|z|^3)}(1+O(|z|))dV_0(z)\notag\\ &\leq& \frac{m e^{-m\varphi(x)}}{A_m}\sup|\chi'|^2 \left(1+C\frac{A_m^{3/2}}{m^{1/2}}\right) \int_{(A_m/m)^{1/2}\leq |z|\leq 2(A_m/m)^{1/2}}e^{-m\varepsilon|z|^2}dV_0(z)\notag\\ &=& \frac{e^{-m\varphi(x)}}{m^{n-1}A_m}\sup|\chi'|^2\left(1+C\frac{A_m^{3/2}}{m^{1/2}}\right)\int_{A_m^{1/2}\leq |\zeta|\leq 2A_m^{1/2}}e^{-\varepsilon|\zeta|^2}dV_0(\zeta)\notag\\ &\leq& C_0\frac{A_m^{n-1}e^{-\varepsilon A_m}}{m^{n-1}}e^{-m\varphi(x)},\;\;\;\forall\,m\gg1, \end{align}\tag{22}\] where \(C_0\) is a numerical constant.
Let us take \(A_m\) such that \(e^{-\varepsilon A_m}= o(m^{-N})\) for all \(N>0\) (e.g., \(A_m=(\log m)^2\)). By Theorem 14 and 22 , there exists a solution \(u_m\) of \(\bar{\partial}u_m=v_m\) on \(M\), such that \[\begin{align} \label{eq:u95m95L2} \int_M|u_m|^2_{(dV_{g_0})^{-1}\otimes (dV_g)^{\otimes (-m)}} dV_{g_0} &\leq& \int_M|v_m|^2_{(dV_{g_0})^{-1}\otimes (dV_g)^{\otimes (-m)},-mRic(\omega)} dV_{g_0}\notag\\ &\leq& \frac{1}{2\varepsilon m}\int_M|v_m|^2_{(dV_{g_0})^{-1}\otimes (dV_g)^{\otimes (-m)}} dV_{g_0}\notag\\ &\leq& \frac{C_0}{\varepsilon}\frac{A_m^{n-1}e^{-\varepsilon A_m}}{m^n}e^{-m\varphi(x)}\notag\\ &\leq& \frac{C_0}{\varepsilon}\frac{1}{m^{n+1}}e^{-m\varphi(x)},\;\;\;\forall\,m\gg1. \end{align}\tag{23}\]
Let \(u_m^\ast\) be a local representation of \(u_m\) at \(x\). It follows that \[\begin{align} & & \int_{|z|<(A_m/m)^{1/2}}|u_m|^2_{(dV_{g_0})^{-1}\otimes (dV_g)^{\otimes (-m)}} dV_{g_0}\\ &=& \int_{|z|<(A_m/m)^{1/2}}\left|u_m^\ast (z)e^{-mP(z)}\right|^2e^{-m\varphi(0)+m\sum^n_{j=1}\lambda_j|z_j|^2+O(m|z|^3)}\left(1+O(|z|)\right)dV_0(z)\\ &\geq& e^{-m\varphi(x)}\left(1-C\frac{A_m^{3/2}}{m^{1/2}}\right)\int_{|z|<(A_m/m)^{1/2}}\left|u_m^\ast(z)e^{-mP(z)}\right|^2e^{m\sum^n_{j=1}\lambda_j|z_j|^2}dV_0(z)\\ &\geq& |u_m^\ast (x)|^2e^{-m\varphi(x)}\left(1-C\frac{A_m^{3/2}}{m^{1/2}}\right)\int_{|z|<(A_m/m)^{1/2}}e^{m\sum^n_{j=1}\lambda_j |z_j|^2}dV_0(z)\\ &=& |u_m^\ast (x)|^2e^{-m\varphi(x)}\frac{1}{m^n}\left(1-C\frac{A_m^{3/2}}{m^{1/2}}\right)\int_{|\zeta|<A_m^{1/2}}e^{\sum^n_{j=1}\lambda_j |\zeta_j|^2}dV_0(\zeta) \end{align}\] in view of the mean value inequality. This combined with 23 yields \[\begin{align} \label{eq:u95m95x} |u_m^\ast(x)|^2e^{-m\varphi(x)} &\leq& \frac{C_0}{\varepsilon} \frac{1}{m} \left(1-C\frac{A_m^{3/2}}{m^{1/2}}\right)^{-1}\left(\int_{|\zeta|<A_m^{1/2}}e^{\sum^n_{j=1}\lambda_j |\zeta_j|^2}dV_0(\zeta)\right)^{-1}e^{-m\varphi(x)}\notag\\ &\sim& \frac{C_0}{\varepsilon} \frac{1}{m}\left(\int_{\zeta\in\mathbb{C}^n}e^{\sum^n_{j=1}\lambda_j |\zeta_j|^2}dV_0(\zeta)\right)^{-1}e^{-m\varphi(x)}\notag\\ &\leq& \frac{C}{m}e^{-m\varphi(x)}. \end{align}\tag{24}\] Recall that \(C\) denotes a generic constant depending on the geometry of \((M,g)\), but is independent of \(m\).
Set \(s_m:=\chi_m-u_m\). Clearly, \(s_m\in \Gamma(M,(m+1)K_M)\). It follows from 21 , 23 and 24 that \[\begin{align} |s_m^\ast (x)|^2e^{-m\varphi(x)} &\geq& \left(|\chi_m^\ast (x)|e^{-m\varphi(x)/2}-|u_m^\ast (x)|e^{-m\varphi(x)/2}\right)^2\\ &\geq& \left(1-\frac{C^{1/2}}{m^{1/2}}\right)^2e^{-m\varphi(x)}\\ &\sim& e^{-m\varphi(x)},\;\;\;m\rightarrow+\infty, \end{align}\] and \[\begin{align} && \int_M|s_m|^2_{(dV_{g_0})^{-1}\otimes (dV_g)^{\otimes (-m)}} dV_{g_0}\\ &\leq& \left(\left(\int_M|\chi_m|^2_{(dV_{g_0})^{-1}\otimes (dV_g)^{\otimes (-m)}} dV_{g_0}\right)^{1/2}+\left(\int_M|u_m|^2_{(dV_{g_0})^{-1}\otimes (dV_g)^{\otimes (-m)}} dV_{g_0}\right)^{1/2}\right)^2\\ &\sim& \frac{\pi^n}{m^n}\left(\prod^n_{j=1}|\lambda_j|\right)^{-1}e^{-m\varphi(x)},\;\;\;m\rightarrow+\infty. \end{align}\] These together with the extremal property 13 yield ?? . ◻
Recall that \(M_0\) is the open subset of \(M\) where \(\lambda_j<0\) for all \(1\leq{j}\leq{n}\). By 14 , ?? , ?? and Fatou’s lemma, we have
\[\begin{align} \label{eq:LeBrun95M950} \mathrm{CanVol}(M) & = & \limsup_{m\rightarrow+\infty}\frac{P_m(M)}{m^n/n!}\leq \int_M\limsup_{m\rightarrow+\infty}\frac{B_m}{m^n/n!}dV_g\nonumber\\ &\leq& \frac{(-1)^nn!}{\pi^n}\int_{M_0}\lambda_1\cdots\lambda_n{dV_g}\nonumber\\ &\leq& \frac{n!}{\pi^n}\int_{M_0}\left(\frac{-\lambda_1-\cdots-\lambda_n}{n}\right)^n{dV_g}\nonumber\\ &\leq& \frac{n!}{(n\pi)^n}\int_M|S^-_{C}|^ndV_g, \end{align}\tag{25}\] i.e., ?? holds, which implies ?? since \[{\rm vol}_g (M)\ge \int_M|S^-_{C}(g)|^ndV_g\] if \(S_C(g)\ge -1\).
Suppose there exists a Hermitian metric \(g\) such that \(S_C(g)\ge -1\) and \[{\rm vol}_g(M) = \frac{(n\pi)^n}{n!} {\rm CanVol}(M).\] In particular, \({\rm CanVol}(M)>0\), i.e., \(M\) is of general type. On the other hand, 25 implies \[{\rm vol}_g(M_0) \ge \frac{(n\pi)^n}{n!} {\rm CanVol}(M).\] Thus \[{\rm vol}_g(M\setminus M_0)=0\] and equalities in 25 hold. It follows that \(\lambda_1=\cdots=\lambda_n=:\lambda\) on \(M_0\), hence on \(M\) by continuity. Note that \[\lambda=\frac{1}{n}\mathrm{tr}_g(\lambda\omega)=\frac{1}{n}\mathrm{tr}_g(Ric(\omega))=\frac{S_C(g)}{n}.\] In case \(g\) is Kähler, the Chern connection coincides with the Levi-Civita connection, and hence \(g\) is also a Riemannian Einstein metric. Since the real dimension of \(M\) is greater than \(2\), we conclude that \(\lambda\) is a constant (cf. Berger [1]). Moreover, \(\lambda<0\) for \(M\) is of general type.
First of all, we have \[\label{eq:MinVol95S} \mathrm{MinVol}_C(M)\geq\mathcal{I}_C^-(M).\tag{26}\] Indeed, given any Hermitian metric \(g\) on \(M\), the scalar curvature \(S_C(g)\) is bounded from below on \(M\). Since \(S_C(tg)=t^{-1}S_C(g)\) and \(dV_{tg}=t^ndV_g\), we see that the integral \(\int_M|S_C^-(g)|^ndV_g\) is invariant under scaling. Then we may assume that \(S_C(g)\geq-1\), so that \[\int_M|S_C^-(g)|^ndV_g\leq\int_M1dV_g\leq\mathrm{vol}_g(M),\] from which 26 immediately follows.
By ?? and 26 , it suffices to verify the follow inequalities: \[\label{eq:MinVol95CanVol} \mathrm{MinVol}_C(M) \leq \frac{(n\pi)^n}{n!}\mathrm{CanVol}(M)\tag{27}\] \[\label{eq:big95nef952} \mathcal{I}_C(M)\leq\frac{(n\pi)^n}{n!}\mathrm{CanVol}(M).\tag{28}\]
Note that a compact Kähler manifold with a big line bundle is always algebraic, in view of a celebrated result of Siu [42]. Thus by Theorem 12, we know that there exists an analytic subset \(E\subset M\) such that the solution \(g_t\) of the normalized Kähler-Ricci flow 7 converges in \(C^\infty_{\rm loc}(M\setminus E)\) to the singular Kähler-Einstein metric \(g_{KE}\). Moreover, the Kähler form \(\omega_{KE}\) of \(g_{KE}\) extends to a closed positive current on \(M\). Consider the Bergman space of \(mK_M\) associated to \(dV_{KE}\), i.e., \[A^2_{g_0,(dV_{KE})^{-1}}(M,mK_M)\] and the corresponding Bergman kernel \[B_{g_0,(dV_{KE})^{-1},mK_M}(x).\] Since \[Ric(\omega_{KE})=-\omega_{KE},\qquad \text{on}\;M\setminus E,\] it follows from ?? that \[\label{eq:limit95Bergman95M95E} \liminf_{m\rightarrow+\infty}\frac{B_{g_0,(dV_{KE})^{-1},mK_M}(x)}{m^n}\ge \frac{1}{\pi^n}\cdot \frac{dV_{KE}}{dV_{g_0}}(x),\;\;\;\forall\;x\in M\setminus E.\tag{29}\] Then we have \[\begin{align} \label{eq:lower95CanVol951} && \liminf_{m\rightarrow+\infty}\frac{\dim A^2_{g_0,(dV_{KE})^{-1}}(M,mK_M)}{m^n/n!}\nonumber\\ &=& n!\liminf_{m\rightarrow+\infty}\int_{M}\frac{B_{g_0,(dV_{KE})^{-1},mK_M}(x)}{m^n}dV_{g_0}(x)\notag\\ &\geq& \frac{n!}{\pi^n}\mathrm{vol}_{KE}(M\setminus E)\;\;\;(\text{Fatou's lemma and\;}\eqref{eq:limit95Bergman95M95E}). \end{align}\tag{30}\] Thus \[\begin{align} \label{eq:lower95CanVol952} \mathrm{CanVol}(M) = \limsup_{m\rightarrow+\infty}\frac{P_m(M)}{m^n/n!} & \geq & \limsup_{m\rightarrow+\infty}\frac{\dim A^2_{g_0,(dV_{KE})^{-1}}(M,mK_M)}{m^n/n!}\nonumber\\ & \geq & \frac{n!}{\pi^n}\mathrm{vol}_{KE}(M\setminus E). \end{align}\tag{31}\]
On the other side, it follows from 9 that there exists for each \(\delta>0\), a neighbourhood \(E_\delta\) of \(E\) such that \(\mathrm{vol}_{g_t}(E_\delta)<\delta\) for \(t\in[0,\infty)\). Since \(g_t\rightarrow g_{KE}\) in \(C^\infty(M\setminus E_\delta)\), we have \(\mathrm{vol}_{g_t} (M\setminus E_\delta)\leq\mathrm{vol}_{KE}(M\setminus E_\delta)+\delta\) when \(t\gg1\), so that \[\label{eq:lower95CanVol953} \mathrm{vol}_{g_t} (M) \leq \mathrm{vol}_{g_t}(M\setminus E_\delta)+\delta \leq \mathrm{vol}_{KE}(M\setminus E_\delta)+2\delta \leq \frac{\pi^n}{n!}\mathrm{CanVol}(M)+2\delta,\tag{32}\] in view of 31 .
By 8 , the Kähler metric \((n+C_0 e^{-t})g_t\) on \(M\) satisfies \(S_C\geq-1\). Thus \[\label{eq:MinVolUpper} \mathrm{MinVol}_C(M) \leq (n+C_0e^{-t})^n\mathrm{vol}_{g_t}(M).\tag{33}\] This combined with 32 yields \[\mathrm{MinVol}_C(M) \leq (n+C_0 e^{-t})^n\left(\frac{\pi^n}{n!}\mathrm{CanVol}(M)+2\delta\right),\] when \(t\gg1\) and \(0<\delta\ll1\). Letting \(t\rightarrow\infty\) and \(\delta\rightarrow0\), we get 27 .
For 28 , we infer from Theorem 11 that there exists a constant \(C>0\) such that \[\label{eq:scalar95bdd95upper} |S_C(g_t)|\leq C,\;\;\;\forall\;t\in[0,\infty),\tag{34}\] so that \[\label{eq:I95M95small} \int_{E_\delta}|S_C(g_t)|^ndV_{g_t} \leq C^n\mathrm{vol}_{g_t} (E_\delta)<C^n\delta.\tag{35}\] Moreover, \(S_C(g_t)\) converges uniformly on \(M\setminus E_\delta\) to \(S_C(g_{KE})=-n\), so that \[\label{eq:I95M95big} \lim_{t\rightarrow\infty}\int_{M\setminus E_\delta}|S_C(g_t)|^ndV_{g_t} = n^n\mathrm{vol}_{KE}(M\setminus E_\delta)\leq \frac{(n\pi)^n}{n!}\mathrm{CanVol}(M),\tag{36}\] in view of 31 . By 35 and 36 , we have \[\label{eq:I95C95limit} \mathcal{I}_C (M)\leq\limsup_{t\rightarrow\infty}\int_M|S_C(g_t)|^ndV_{g_t} \leq \frac{(n\pi)^n}{n!}\mathrm{CanVol}(M)+C^n\delta,\tag{37}\] from which 28 immediately follows.
Recall that the numerical dimension of the nef line bundle \(K_M\) is defined by \[\label{eq:nd} \mathrm{nd}(M)=\mathrm{nd}(K_M)=\max\left\{k:\;1\leq k\leq n, c_1(K_M)^k\neq0\;\text{in}\;H^{k,k}(M,\mathbb{R})\right\}.\tag{38}\] Take a smooth \((1,1)\) form \(\gamma\) with \(c_1(K_M)=[\gamma]\) and a smooth volume form \(\Omega\) on \(M\) such that \(\gamma=i\partial\bar{\partial}\log\Omega\) and \(\int_M\Omega=1\). Let \(g_t\) be the solution to the normalized Kähler-Ricci flow 7 and \(\omega_t\) the associated Kähler form. Set \[\widehat{\omega}_t:=(1-e^{-t})\gamma+e^{-t}\omega_0.\] It follows from 7 that \[\frac{d}{dt}[\omega_t]=[-\mathrm{Ric}(\omega_t)-\omega_t]=c_1(K_M)-[\omega_t],\] i.e., \[\frac{d}{dt}(e^t[\omega_t])=c_1(K_M)e^t.\] Solving this ODE in \(H^{1,1}(M,\mathbb{R})\), we obtain \[[\omega_t]=(1-e^{-t})[c_1(K_M)]+e^{-t}[\omega_0]=[\widehat{\omega}_t].\] In particular, \[\label{eq:volume95int95cohomology} \mathrm{vol}_{g_t}(M)=\int_M\widehat{\omega}_t^n.\tag{39}\] By 8 , we have \[\label{eq:vol95nef95not95big} \mathrm{MinVol}_C(M)\leq \left(n+C_0e^{-t}\right)^n\mathrm{vol}_{g_t}(M)=\left(n+C_0e^{-t}\right)^n\int_M\widehat{\omega}_t^n.\tag{40}\] Thus it remains to verify \(\int_M\widehat{\omega}_t^n\rightarrow0\) as \(t\rightarrow+\infty\). This follows immediately from [43]. For the sake of completeness, we shall include the very simple proof as follows.
Since \([\gamma]^k=c_1(K_M)^k=0\) in \(H^{k,k}(M,\mathbb{R})\) for \(k>\mathrm{nd}(M)\), so \[\begin{align} \int_M\widehat{\omega}_t^n &=& \int_M\left(\gamma + e^{-t}(\omega_0-\gamma)\right)^n\\ &=& \sum^n_{l=0}\binom{n}{l}e^{-(n-l)t}\int_M\gamma^l\wedge(\omega_0-\gamma)^{n-l}\\ &=& e^{-(n-\mathrm{nd}(M))t}\binom{n}{\mathrm{nd}(M)}\int_M\gamma^{\mathrm{nd}(M)}\wedge\left(\omega_0-\gamma\right)^{n-\mathrm{nd}(M)}+o(e^{-(n-\mathrm{nd}(M))t}),\;\;\;t\rightarrow+\infty. \end{align}\] In particular, we get \[\label{eq:volume95numerical95dim951} C^{-1}e^{-(n-\mathrm{nd}(M))t}\mathrm{vol}_{g_0}(M) \leq \mathrm{vol}_{g_t}(M) \leq Ce^{-(n-\mathrm{nd}(M))t}\mathrm{vol}_{g_0}(M).\tag{41}\] for some constant \(C\) independent of \(t\). As \(\mathrm{Kod}(M)<n\) implies \(\mathrm{nd}(M)<n\) (cf. [9]), it follows that \(\mathrm{vol}_{g_t}(M)\rightarrow0\) as \(t\rightarrow+\infty\).
Finally, we will show \(\mathcal{I}_C(M)=0\). Consider the average Chern scalar curvature of \(g_t\) \[\label{eq:average95sc} \overline{S}_t :=\frac{1}{\mathrm{vol}_{g_t}(M)}\int_M S_C(g_t)\,dV_{g_t}.\tag{42}\] We claim that the function \(t\mapsto\overline{S}_t\) is bounded on \([0,\infty)\). Since \(g_t\) is a Kähler metric, we have the standard identity \[S_C(g_t)\,\omega_t^n = n\,Ric(\omega_t)\wedge \omega_t^{n-1},\] so that \[\int_M S_C(g_t)\,dV_{g_t} =n\int_M Ric(\omega_t)\wedge \omega_t^{n-1}.\] Recall that \([Ric(\omega_t)]=-c_1(K_M)=-[\gamma]\), so \[\label{eq:scalar95integral} \int_M S_C(g_t)\,dV_{g_t} = -n\int_M\gamma\wedge\omega_t^{n-1} = -n\int_M\gamma\wedge\widehat{\omega}_t^{n-1}.\tag{43}\] A similar argument as above yields \[\begin{align} \int_M\gamma\wedge\widehat{\omega}_t^{n-1} &=& \int_M\gamma\wedge\left(\gamma + e^{-t}(\omega_0-\gamma)\right)^{n-1}\\ &=& \sum^{n-1}_{l=0}\binom{n-1}{l}e^{-(n-1-l)t}\int_M\gamma^{l+1}\wedge(\omega_0-\gamma)^{n-1-l}. \end{align}\] Note that \([\gamma]^{l+1}=c_1(K_M)^{l+1}=0\) in \(H^{l+1,l+1}(M,\mathrm{R})\) when \(l\geq\mathrm{nd}(M)\). We get \[\left|\int_M\gamma\wedge\widehat{\omega}_t^{n-1}\right|=O(e^{-(n-\mathrm{nd}(M))t}).\] This combined with 42 , 41 and 43 gives \[\label{eq:average95sc95bdd} |\overline{S}_t|\leq C, \qquad \forall\,t\geq 0.\tag{44}\] Here \(C\) is independent of \(t\).
We will proceed the argument through suitable conformal deformation. Set \[h_t=e^{u_t/n}g_t\] for a real-valued smooth function \(u_t\) on \(M\). The volume form is given by \[\label{eq:volume95form95conformal95t} dV_{h_t}=e^{u_t}dV_{g_t},\tag{45}\] and a straightforward calculation shows \[\label{eq:sc95conformal95t} S_C(h_t)=e^{-u_t/n}\left(S_C(g_t)-\Delta_{g_t} u_t\right),\tag{46}\] where \(\Delta_{g_t}\) denotes the complex Laplacian with respect to the metric \(g_t\), i.e., \[\Delta_{g_t}\varphi=\mathrm{tr}_{g_t}(i\partial\bar{\partial}\varphi),\;\;\;\forall\,\varphi\in C^\infty(M).\] For each \(t\geq 0\), the Poisson equation \[\label{eq:Poisson} \Delta_{g_t}u_t = S_C(g_t)-\overline{S}_t\tag{47}\] admits a smooth solution \(u_t\) since the right-hand side has integral zero (see [44]). By 46 and 47 , we get \[S_C(h_t)=e^{-u_t/n}\overline{S}_t.\] This together with 45 and 44 yield \[\int_M|S_C(h_t)|^ndV_{h_t}=\int_M|\overline{S}_t|^ndV_{g_t}\leq C^n\mathrm{vol}_{g_t}(M).\] Since \(\mathrm{nd}(M)<n\), we conclude \[\int_M|S_C(h_t)|^ndV_{h_t}\rightarrow0,\;\;\;t\rightarrow+\infty,\] in view of 41 . This implies \(\mathcal{I}_C(M)=0\).
The pull-back \(F^*K_M\) of \(K_M\) is a line bundle over \(M'\), whose volume can be defined in a similar way: \[\mathrm{vol}(F^*K_M):= \limsup_{m\rightarrow+\infty}\frac{\dim\Gamma(M,F^*K_M)}{m^n/n!}.\] It follows from [45] (see also [46]) that \[\label{eq:deg95vol95pullback} \mathrm{vol}(F^*K_M)=\deg(F)\cdot\mathrm{CanVol}(M).\tag{48}\] Let \(R_F\) denote the line bundle associated to the effective divisor locally given by the zeros of the complex Jacobian determinant of \(F\). We have \[K_{M'}=F^*K_M+ R_F.\] By [47], we know that \[\label{eq:volume95increasing95effective} \mathrm{CanVol}(M')=\mathrm{vol}(F^*K_M+ R_F)\geq\mathrm{vol}(F^*K_M).\tag{49}\] Thus \[\mathrm{CanVol}(M')\geq \deg(F)\cdot\mathrm{CanVol}(M).\] This together with Corollary 3 and Theorem 4 yield ?? ?? . Moreover, if \(F\) is a covering map, then \(R_F=0\) and \(K_{M'}\) is also nef, so that \[\mathrm{CanVol}(M')=\mathrm{vol}(F^*K_M)=\deg(F)\cdot\mathrm{CanVol}(M).\] Thus equalities in ?? ?? hold, in view of Theorem 4.
Remark 5. Conversely, if equalities in ?? ?? hold, then \(F\) is not necessarily a covering map. A counterexample is given by Theorem 7.
Since the canonical volume is a bimeromorphic invariant (see, e.g., [47], [20]), it follows that \[\label{eq:canvol95bimeromorphic} \mathrm{CanVol}(\widehat M)=\mathrm{CanVol}(M).\tag{50}\] By 50 and Theorem 4, it suffices to prove that \(\mathrm{MinVol}_C\) and \(\mathcal{I}_C^-\) (resp. \(\mathcal{I}_C\)) are invariant under the blow-up at finite points when \(K_M\) is nef (resp. big and nef). For simplicity, we will only treat the case of blowing-up at one point and leave the general case to interested readers. Let \[\varpi:\widehat{M}=\mathrm{Bl}_pM\rightarrow M\] be the blow-up at \(p\in M\).
From the proof of Theorem 4, we learn that if \(K_M\) is nef, then for any \(\varepsilon>0\), there exists a Kähler metric \(g\) on \(M\) such that \(S_C(g)\geq-1\) and \[\label{eq:approximating95metric95I95minus} \int_M|S_C^-(g)|^ndV\leq \frac{(n\pi)^n}{n!}\mathrm{CanVol}(M)+\varepsilon,\tag{51}\] \[\label{eq:approximating95metric95I} \int_M|S_C(g)|^ndV\leq \frac{(n\pi)^n}{n!}\mathrm{CanVol}(M)+\varepsilon,\tag{52}\] \[\label{eq:approximating95metric95vol} \mathrm{vol}_g(M)\leq \frac{(n\pi)^n}{n!}\mathrm{CanVol}(M)+\varepsilon.\tag{53}\]
The main idea is to modify \(g\) to obtain certain metric on \(\widehat{M}\) with analogous properties. More precisely, we will divide the proof into four steps:
Glue any given metric with the Burns-Simanca metric near the exceptional divisor;
Derive quantitative estimates of the scalar curvature and the volume for the glued metric;
Deduce the equalities for \(\mathcal{I}_C\) and \(\mathcal{I}_C^-\);
Apply a conformal correction to achieve the sharp lower bound \(S_C\ge -1\), and conclude the equality for \(\mathrm{MinVol}_C\).
Step 1: Construction of the glued metric. We will glue the background metric \(g\) on \(M\) with a rescaled Burns-Simanca metric near the exceptional divisor, following LeBrun [16] and Székelyhidi [17].
Since \(g\) is Kähler, the Kähler form \(\omega\) of \(g\) can be written as \[\omega=i\partial\bar{\partial}\left(\frac{|z|^2}{2}+\varphi(z)\right)\] in a small coordinate ball \(B_\rho\) around \(p\), where \(\varphi(z)=O(|z|^4)\) as \(z\rightarrow0\). Let \(\delta>0\) be a small parameter. Consider the rescaled Burns-Simanca metric (see § 2.5) \[\omega^\delta_{BS} :=\varpi^*i\partial\bar{\partial}\left(\frac{|z|^2}{2}+\delta^2\psi\left(\frac{z}{\delta}\right)\right)\] on \(\varpi^{-1}(B_\rho)\), where \(z\in B_\rho\setminus\{0\}\). We will define a modified metric \(g_\delta\) on \(\widehat{M}\) by gluing \(g\) and \(g_{BS}^\delta\) as follows. Let \(\chi:[0,\infty)\to[0,1]\) be a smooth cut-off function with \(\chi\equiv 0\) on \([0,1]\) and \(\chi\equiv 1\) on \([2,\infty)\). Take \[r_\delta:=\delta^\alpha,\qquad 0<\alpha<{1}/{2}.\] Clearly, \(B_{2r_\delta}\subset\subset B_\rho\) for \(\delta\ll 1\). On \(B_\rho\), we define \[\label{eq:Phi95delta} \Phi_\delta(z) :=\frac{|z|^2}{2} +\chi\left(\frac{|z|}{r_\delta}\right)\varphi(z) +\left(1-\chi\left(\frac{|z|}{r_\delta}\right)\right)\delta^2\psi\left(\frac{z}{\delta}\right).\tag{54}\] Note that \(\varpi^*i\partial\bar{\partial} \Phi_\delta\) is a real \((1,1)\)-form on \(\widehat{M}\), which coincides with \(\omega^\delta_{BS}\) (resp. \(\varpi^*\omega\)) on \(\varpi^{-1}(B_{r_\delta})\) (resp. \(\varpi^{-1}(B_\rho\setminus B_{2r_\delta})\)). The glued metric \(g_\delta\) is defined through \[\label{eq:glue95Kahler} \omega_\delta:=\begin{cases} \varpi^*i\partial\bar{\partial} \Phi_\delta,\;\;\;&\text{on }\varpi^{-1}(B_\rho),\\ \varpi^*\omega,\;\;\;&\text{on }\widehat{M}\setminus\varpi^{-1}(B_\rho), \end{cases}\tag{55}\] provided that \(\omega_\delta\) is positive on the gluing annulus \[A_\delta:=\varpi^{-1}(B_{2r_\delta}\setminus B_{r_\delta}).\] To see this, let us use rescaled coordinates \(w=z/r_\delta\). Consider the holomorphic map \[\iota:\{0<|w|\leq\rho/r_\delta\}\xrightarrow{z=r_\delta w}\left\{0<|z|\leq \rho\right\}\xrightarrow{\varpi^{-1}}\widehat{M}\] and define the \((1,1)\)-tensor \[\widetilde{g}_\delta:=r_\delta^{-2}\iota^*g_\delta\] on \(\{0<|w|\leq\rho/r_\delta\}\). With respect to the coordinate \(w\), the Kähler form \(\widetilde{\omega}_\delta\) of \(\widetilde{g}_\delta\) can be written as \[\widetilde{\omega}_\delta=i\partial\bar{\partial}\,\widetilde{\Phi}_\delta,\] where \[\widetilde{\Phi}_\delta(w)=\frac{|w|^2}{2} +\chi\left(|w|\right)r_\delta^{-2}\varphi(r_\delta w) +\bigl(1-\chi\left(|w|\right)\bigr)r_\delta^{-2}\delta^2\psi\left(\frac{r_\delta w}{\delta}\right),\;\;\;0<|w|\leq\rho/r_\delta.\] Denote by \(g_{\mathrm{eucl}}\) the Euclidean metric on \(\mathbb{C}^n\) (whose Kähler form is given by \(i\partial\bar{\partial}(|w|^2/2)\)).
Lemma 16. Set \[A:=\left\{\frac{1}{2}\le |w|\le 3\right\}\subset \{0<|w|\leq\rho/r_\delta\}.\] Then \[\|\widetilde{g}_\delta-g_{\mathrm{eucl}}\|_{C^2(A)}=O(r_\delta^2),\qquad \delta\rightarrow0.\] In particular, \(\widetilde{g}_\delta\) converges to \(g_{\mathrm{eucl}}\) in the \(C^2\) topology on \(A\).
Proof. Set \[\Theta_\delta(w) :=\widetilde{\Phi}_\delta(w)-\frac{|w|^2}{2} :=\chi(|w|)\,r_\delta^{-2}\varphi(r_\delta w) +\bigl(1-\chi(|w|)\bigr)r_\delta^{-2}\delta^2\psi\left(\frac{r_\delta w}{\delta}\right).\] It suffices to show that \[\label{eq:C495converge} \|\Theta_\delta\|_{C^4(A)}:=\sup_{w\in A}\sum^4_{k=1}|D^k_w\Theta_\delta(w)|=O(\delta^{2\alpha})=O(r_\delta^2)\tag{56}\] as \(\delta\rightarrow0\). We have \[\label{eq:C495converge950} |D^k_w\Theta_\delta(w)|\lesssim \sum^k_{j=0}r_\delta^{-2+j}|D^j_z\varphi(r_\delta w)|+\sum^k_{j=0}\left(\frac{r_\delta}{\delta}\right)^{-2+j}\left|D^j_\zeta\psi\left(\frac{r_\delta w}{\delta}\right)\right|,\;\;\;0\leq k\leq 4,\tag{57}\] where \(\zeta=z/\delta=r_\delta w/\delta\) and the implicit constant is numerical. Since \(\varphi(z)=O(|z|^4)\) as \(z\rightarrow0\), we have \(|D_z^j\varphi(r_\delta w)|=O(r_\delta^{4-j})\) as \(\delta\rightarrow0\) uniformly on \(A\). Thus \[\label{eq:C495converge951} \sum^k_{j=0}r_\delta^{-2+j}|D^j_z\varphi(r_\delta w)|=O(r_\delta^2)=O(\delta^{2\alpha}).\tag{58}\] On the other hand, for \(n\ge 3\), 11 gives \[\left|D^j_\zeta\psi\left(\frac{r_\delta w}{\delta}\right)\right| = O\left(\left|\frac{r_\delta w}{\delta}\right|^{4-2n-j}\right)=O\left(\left(\frac{r_\delta}{\delta}\right)^{4-2n-j}\right)\] uniformly on \(A\), so that \[\label{eq:C495converge952} \sum^k_{j=0}\left(\frac{r_\delta}{\delta}\right)^{-2+j}\left|D^j_\zeta\psi\left(\frac{r_\delta w}{\delta}\right)\right| :=O\left(\left(\frac{r_\delta}{\delta}\right)^{2-2n}\right)=O(\delta^{(2n-2)(1-\alpha)}).\tag{59}\] For \(n=2\), we have \(\psi(\zeta)=\log|\zeta|^2\), and for \(j\geq1\), \[\left|D^j_\zeta\psi\left(\frac{r_\delta w}{\delta}\right)\right|=O\left(\left|\frac{r_\delta w}{\delta}\right|^{-j}\right)=O\left(\left(\frac{r_\delta}{\delta}\right)^{-j}\right)\] holds uniformly on \(A\). Thus \[\begin{align} \label{eq:C495converge953} \sum^k_{j=0}\left(\frac{r_\delta}{\delta}\right)^{-2+j}\left|D^j_\zeta\psi\left(\frac{r_\delta w}{\delta}\right)\right| &=& \left(\frac{r_\delta}{\delta}\right)^{-2}\left|\log\left|\frac{r_\delta w}{\delta}\right|^2\right|+\sum^k_{j=1}\left(\frac{r_\delta}{\delta}\right)^{-2+j}\left|D^j_\zeta\psi\left(\frac{r_\delta w}{\delta}\right)\right|\notag\\ &=& O\left(\delta^{2(1-\alpha)}\log\frac{1}{\delta}\right)+O\left(\delta^{2(1-\alpha)}\right)\notag\\ &=& O\left(\delta^{2(1-\alpha)}\log\frac{1}{\delta}\right). \end{align}\tag{60}\] By 57 , 58 , 59 and 60 , we have \[\|\Theta_\delta\|_{C^4(A)}= \begin{cases} O(\delta^{2\alpha})+O(\delta^{(2n-2)(1-\alpha)}),\;\;\;&n\geq3,\\ O(\delta^{2\alpha})+O(\delta^{2(1-\alpha)}\log(1/\delta)),\;\;\;&n=2. \end{cases}\] Since \(0<\alpha<1/2\), the assertion immediately follows. ◻
As a consequence, \(\omega_\delta=r_\delta^2(\iota^{-1})^*\widetilde{\omega}_\delta\) is positive on \(A_\delta\) for all sufficiently small \(\delta\). Hence \(g_\delta\) is a genuine Kähler metric on \(\widehat M\).
Step 2: Gluing estimates.
Let us first show the following
Lemma 17. \(\omega_{BS}^\delta\) is uniformly bounded on \(\varpi^{-1}(B_\rho)\) as \(\delta\rightarrow0\).
Proof. Since \[\omega_{BS}^\delta=\delta^2a\cdot \pi^*\omega_{FS}+\varpi^*\left(i\partial\bar{\partial}\left(\frac{|z|^2}{2}+\delta^2\eta(|z/\delta|^2)\right)\right)\] in view of 12 , it suffices to verify that \(\varpi^\ast i\partial\bar{\partial}(\delta^2\eta(|z/\delta|^2))\) is uniformly bounded on \(\varpi^{-1}(B_\rho)\) as \(\delta\rightarrow0\). If \(n=2\), then \(\eta\equiv0\) and there is nothing to proof. Suppose \(n\geq 3\) and fix \(C\gg1\). Since \(\eta\) is a smooth function on \([0,+\infty)\), it follows that \[i\partial\bar{\partial}(\delta^2\eta(|z/\delta|^2)) =\left.\left(i\partial_\zeta\bar{\partial}_\zeta\eta(|\zeta|^2)\right)\right|_{\zeta=z/\delta}\] is uniformly bounded for \(|z|\leq C\delta\) as \(\delta\rightarrow0\). Moreover, since \(\eta(|\zeta|^2)=\psi(\zeta)-a\log|\zeta|^2\), we may choose \(C\gg 1\) such that \[i\partial_\zeta\bar{\partial}_\zeta\psi(\zeta)=O(|\zeta|^{2-2n})\] when \(|\zeta|=|z/\delta|\geq C\), in view of 11 . Thus \[i\partial\bar{\partial}(\delta^2\eta(|z/\delta|^2))=\left.\left(i\partial_\zeta\bar{\partial}_\zeta\psi(\zeta)\right)\right|_{\zeta=z/\delta}-a\delta^2\cdot i\partial\bar{\partial}\log|z|^2=\delta^{2n-2}O(|z|^{2-2n})+\delta^2O(|z|^{-2}),\] which is uniformly bounded for \(C\delta\leq |z|\leq \rho\) as \(\delta\rightarrow0\). This completes the proof. ◻
Now we give the crucial estimates.
Lemma 18. There exists a constant \(C_0>0\), independent of \(\delta\), such that the following hold. \[\begin{align} & & S_C(g_\delta)=0\;\;\;\text{on}\;\varpi^{-1}(B_{r_\delta}),\label{eq:sc95glue951}\\ & & |S_C(g_\delta)|\leq C_0\;\;\;\text{on}\;A_\delta=\varpi^{-1}(B_{2r_\delta}\setminus B_{r_\delta}),\label{eq:sc95glue952}\\ & & S_C(g_\delta)=S_C(g)\;\;\;\text{on}\;\widehat{M}\setminus \varpi^{-1}(B_{2r_\delta}),\label{eq:sc95glue953}\\ & & \mathrm{vol}_{g_\delta}(\widehat{M})\leq \mathrm{vol}_g(M)+O(r_\delta^2),\qquad \delta\to0,\label{eq:volume95glue}\\ & & \int_{\widehat{M}}|S_C^-(g_\delta)|^n dV_{g_\delta}\leq \int_M|S_C^-(g)|^n dV_g+O(r_\delta^{2n}),\qquad \delta\to0,\label{eq:I95C95minus95glue}\\ & & \int_{\widehat{M}}|S_C(g_\delta)|^n dV_{g_\delta}\leq \int_M|S_C(g)|^n dV_g+O(r_\delta^{2n}),\qquad \delta\to0.\label{eq:I95C95glue} \end{align}\] {#eq: sublabel=eq:eq:sc95glue951,eq:eq:sc95glue952,eq:eq:sc95glue953,eq:eq:volume95glue,eq:eq:I95C95minus95glue,eq:eq:I95C95glue}
Proof. ?? and ?? are direct consequences of the definition of \(g_\delta\). For ?? , we infer from Lemma 16 that \[\sup_A|S_C(\widetilde{g}_\delta)|=\sup_A|S_C(\widetilde{g}_\delta)-S_C(g_{\mathrm{eucl}})|=O(r_\delta^2),\qquad \delta\to0,\] which implies \[\sup_{A_\delta}|S_C(g_\delta)|=\frac{1}{r_\delta^2}\sup_{1\leq|w|\leq2}|S_C(\widetilde{g}_\delta)|=\frac{1}{r_\delta^2}O(r_\delta^2)=O(1),\qquad \delta\to0.\]
Since \(g_\delta\) differs from \(g\) only inside \(\varpi^{-1}(B_{2r_\delta})\), it follows that \[\label{eq:volume95glue951} \mathrm{vol}_{g_\delta}(\widehat{M}\setminus \varpi^{-1}(B_{2r_\delta}))=\mathrm{vol}_g(M\setminus \varpi^{-1}(B_{2r_\delta}))\leq \mathrm{vol}_g(M).\tag{61}\] Recall that \(\widetilde{g}_\delta=r_\delta^{-2}\iota^*g_\delta\) and \(\widetilde{g}_\delta\rightarrow g_{\mathrm{eucl}}\) in the \(C^2\) topology on \(A\). Thus \[\mathrm{vol}_{g_\delta}(\varpi^{-1}(B_{2r_\delta}\setminus B_{r_\delta}))=r_\delta^{2n}\mathrm{vol}_{\widetilde{g}_\delta}(\{1\leq|w|<2\})\] and \[\lim_{\delta\rightarrow0}\mathrm{vol}_{\widetilde{g}_\delta}(\{1\leq|w|<2\})=\mathrm{vol}_{g_{\mathrm{eucl}}}(\{1\leq|w|<2\}),\] so that \[\label{eq:volume95glue952} \mathrm{vol}_{g_\delta}(\varpi^{-1}(B_{2r_\delta}\setminus B_{r_\delta}))=O(r_\delta^{2n}),\qquad \delta\to0.\tag{62}\] Moreover, as \(\varpi^{-1}(B_{r_\delta})\) is a tubular neighbourhood of the exceptional locus in \(\widehat{M}\), we have \[\label{eq:volume95glue953} \mathrm{vol}_{g_\delta}(\varpi^{-1}(B_{r_\delta}))=O(r_\delta^2),\qquad \delta\to0,\tag{63}\] in view of Lemma 17. Thus ?? follows immediately form 61 , 62 and 63 . Similarly, ?? –?? yield ?? and ?? . ◻
Step 3: Equalities for \(\mathcal{I}_C\) and \(\mathcal{I}_C^-\).
Suppose that \(K_M\) is nef. Recall that \(g\) satisfies 51 . By ?? , we get \[\int_{\widehat{M}}|S_C^-(g_\delta)|^n dV_{g_\delta} \leq \int_M|S_C^-(g)|^n dV_g+O(r_\delta^2) \leq \frac{(n\pi)^n}{n!}\mathrm{CanVol}(M)+\varepsilon+O(r_\delta^2),\] so that \[\mathcal{I}^-_C(\widehat{M})\leq \frac{(n\pi)^n}{n!}\mathrm{CanVol}(M)+\varepsilon+O(r_\delta^2).\] Letting \(\delta\rightarrow0\) and \(\varepsilon\rightarrow0\), we obtain \[\mathcal{I}^-_C(\widehat{M})\leq \frac{(n\pi)^n}{n!}\mathrm{CanVol}(M).\] This combined with Theorem 1 gives \[\mathcal{I}^-_C(\widehat{M})= \frac{(n\pi)^n}{n!}\mathrm{CanVol}(M).\] Using 52 and ?? instead of 51 and ?? , we obtain the equality for \(\mathcal{I}_C(M)\).
Step 4: Equality for \(\mathrm{MinVol}_C\).
This part is the most involved. Suppose \(K_M\) is nef. It is known from 53 that for any \(\varepsilon>0\) there exists a Kähler metric \(g\) with \(S_C(g)\ge -1\) and \[\mathrm{vol}_g(M)\le \frac{(n\pi)^n}{n!}\,\mathrm{CanVol}(M)+\varepsilon.\] Fix \(\tau\in(0,1)\). Replacing \(g\) by \(\lambda g\) with \(\lambda=(1-\tau)^{-1}>1\), we get \[S_C(g)\ge -1+\tau\] and \[\mathrm{vol}_g(M)\le (1-\tau)^{-n}\left(\frac{(n\pi)^n}{n!}\,\mathrm{CanVol}(M)+\varepsilon\right).\] If \(\tau\) is sufficiently small, then \[\mathrm{vol}_g(M)\le \frac{(n\pi)^n}{n!}\,\mathrm{CanVol}(M)+2\varepsilon.\] This combined with ?? implies \[\label{eq:volume95canvol95epsilon} \mathrm{vol}_{g_\delta}(\widehat{M})\leq \frac{(n\pi)^n}{n!}\,\mathrm{CanVol}(M)+3\varepsilon\tag{64}\] when \(\delta\) is sufficiently small. However, this is not enough to verify the equality for \(\mathrm{MinVol}_C\), for we merely have \[\label{eq:sc95glue} S_C(g_\delta)\geq \begin{cases} 0\;\;\;\;\;&\text{on}\;\varpi^{-1}(B_{r_\delta}),\\ -C_0\;\;\;\;\;&\text{on}\;A_\delta=\varpi^{-1}(B_{2r_\delta}\setminus B_{r_\delta}),\\ -1+\tau\;\;\;\;\;&\text{on}\;\widehat{M}\setminus \varpi^{-1}(B_{2r_\delta}), \end{cases}\tag{65}\] in view of ?? , ?? and ?? . It is unclear whether \(C_0\leq1\).
To overcome this difficulty, we will use again the technique of conformal deformation. Set \(h_\delta=e^{u_\delta/n}g_\delta\) for a real-valued smooth function \(u_\delta\) on \(\widehat M\). Recall that \[\label{eq:sc95conformal} S_C(h_\delta)=e^{-u_\delta/n}\left(S_C(g_\delta)-\Delta_{g_\delta} u_\delta\right),\tag{66}\] where \(\Delta_{g_\delta}\) denotes the complex Laplacian with respect to the metric \(g_\delta\). We are going to prove the following
Proposition 19. For \(0<\delta\ll\rho\ll1\), there exists \(u_\delta\in C^\infty(\widehat M)\) with \(u_\delta\ge 0\), such that the Hermitian metric \(h_\delta=e^{u_\delta/n}g_\delta\) satisfies \[\begin{align} & & S_C(h_\delta)\ge -1,\\ & & \mathrm{vol}_{h_\delta}(\widehat M)=\mathrm{vol}_{g_\delta}(\widehat M)+O(r_\delta^2),\qquad \delta\rightarrow0. \end{align}\]
We first show the following
Lemma 20. Let \(\varphi\) be a smooth function on \(\{0<|w|\leq \rho/r_\delta\}\). Set \(\varphi_{r_\delta}(z)=\varphi(z/r_\delta)\) for \(0<|z|\leq\rho\), which can be identified with a smooth function on \(\varpi^{-1}(B_\rho\setminus\{0\})\subset\widehat{M}\). Then \[\Delta_{g_\delta}\varphi_{r_\delta}(z)=r_\delta^{-2}\Delta_{\widetilde{g}_\delta}\varphi(w)|_{w=z/r_\delta}.\]
Proof. If one writes \[g_\delta=\sum(g_\delta)_{j\bar{k}}(z)dz_j\otimes d\bar{z}_k,\] then \[\widetilde{g}_\delta=r_\delta^{-2}\iota^*g_\delta=\sum(g_\delta)_{j\bar{k}}(r_\delta w)dw_j\otimes d\bar{w}_k.\] Let \(((g_\delta)^{j\bar{k}})\) denote the inverse matrix of \(((g_\delta)_{j\bar{k}})\). Then we have \[\begin{align} \Delta_{g_\delta}\varphi_{r_\delta}(z) &=& \sum (g_\delta)^{j\bar{k}}(z)\frac{\partial^2\varphi_{r_\delta}}{\partial z_j\bar{z}_k}(z)\\ &=& r_\delta^{-2}\sum (g_\delta)^{j\bar{k}}(z)\left.\frac{\partial^2\varphi}{\partial w_j\bar{w}_k}(w)\right|_{w=z/r_\delta}\\ &=& r_\delta^{-2}\left.\left(\sum (g_\delta)^{j\bar{k}}(r_\delta w)\frac{\partial^2\varphi}{\partial w_j\bar{w}_k}(w)\right)\right|_{w=z/r_\delta}\\ &=& r_\delta^{-2}\Delta_{\widetilde{g}_\delta}\varphi(w)|_{w=z/r_\delta}. \end{align}\] ◻
Pick a smooth radial function \(f\in C_0^\infty(\mathbb{C}^n)\) such that \[\begin{align} & & -C_0\le f\le 0 \quad \text{on } \left\{\frac{1}{2}\le |w|\le 3\right\},\\ & & f\equiv -C_0 \quad \text{on } \{1\le |w|\le 2\},\\ & & \mathrm{supp}\,f\subset \left\{\frac{1}{2}\le |w|\le 3\right\}. \end{align}\] Let \(N(w)=-c_n|w|^{2-2n}\) be the Newtonian kernel in real dimension \(2n\ge 4\), and define \[v:=N*f.\] Then \(v\) is smooth and radial on \(\mathbb{C}^n\), satisfying \(v\geq0\) and \[\Delta_{\mathrm{eucl}}v:=2\sum^n_{j=1}\frac{\partial^2v}{\partial w_j\partial \bar{w}_j}=f.\] We also need the following elementary fact.
Lemma 21. There exists a constant \(C\) depending on \(n\) and \(C_0\) such that \[\begin{align} & & |v|\leq C,\qquad \left|\frac{\partial v}{\partial w_j}\right|\leq C,\;\;\;1\leq j\leq n,\\ & & \left|\frac{\partial^2 v}{\partial w_j\partial\bar{w}_k}\right|\leq C,\;\;\;1\leq j,k\leq n. \end{align}\]
Proof. We have \[|v(w)|=|N*f|\leq \|N\|_{L^1(w+\mathrm{supp}\,f)}\|f\|_{L^\infty(\mathbb{C}^n)}\le C,\;\;\forall\,w\in \mathbb{C}^n.\] Similarly, \[\begin{align} & & \left|\frac{\partial v}{\partial w_j}(w)\right| =\left|N*\frac{\partial f}{\partial w_j}\right| \leq \|N\|_{L^1(w+\mathrm{supp}\,f)}\left\|\frac{\partial f}{\partial w_j}\right\|_{L^\infty(\mathbb{C}^n)}\le C,\\ & & \left|\frac{\partial^2 v}{\partial w_j\partial\bar{w}_k}(w)\right| =\left|N*\frac{\partial^2 f}{\partial w_j\partial\bar{w}_k}\right| \leq \|N\|_{L^1(w+\mathrm{supp}\,f)}\left\|\frac{\partial^2 f}{\partial w_j\partial\bar{w}_k}\right\|_{L^\infty(\mathbb{C}^n)}\le C. \end{align}\] ◻
Proof of Proposition 19. The function \(v\) constructed above is harmonic on \(\{|w|<1/2\}\cup\{|w|>3\}\). Since \(v\) is radial, it has to be a constant on \(\{|w|<1/2\}\). Take a cut-off function \(\kappa\in C_0^\infty(B_\rho)\) such that \(\kappa\equiv 1\) on \(B_{3r_\delta}\) and \[\label{eq:kappa95bdd} \left|\frac{\partial \kappa}{\partial z_j}\right|\lesssim 1/\rho,\qquad \left|\frac{\partial^2 \kappa}{\partial z_j\partial\bar{z}_k}\right|\lesssim 1/\rho^2,\qquad 1\leq j,k\leq n,\tag{67}\] where the implicit constants are independent of \(\rho\) and \(\delta\) (note that \(3r_\delta\ll\rho\)). Now define \(u_\delta\in C^\infty_0(\widehat{M})\) as \[u_\delta:= \begin{cases} r_\delta^2\,\kappa(z)\,v(z/r_\delta),\;\;\;&\text{on }\varpi^{-1}(B_\rho\setminus\{0\}),\\ 0,\;\;\;&\text{on }\widehat{M}\setminus\varpi^{-1}(B_\rho\setminus\{0\}). \end{cases}\] Recall that \(z\) is a local coordinate on \(B_\rho\), hence we may identify a point in \(\varpi^{-1}(B_\rho\setminus\{0\})\) with its coordinate in \(B_\rho\setminus \{0\}\). The function \(u_\delta\) can be extended smoothly across the exceptional divisor since \(v(z/r_\delta)\) and \(\kappa\) are constants on \(\varpi^{-1}(B_{r_\delta/2}\setminus\{0\})\).
In what follows, we will estimate the Laplacian of \(u_\delta\) with respect to \(g_\delta\).
On \(\widehat{M}\setminus\varpi^{-1}(B_\rho)\), we have \(u_\delta\equiv0\), so that \(\Delta_{g_\delta}u_\delta=0\).
On \(\varpi^{-1}(B_{r_\delta/2})\), both \(v(z/r_\delta)\) and \(\kappa(z)\) are constants, so that \(\Delta_{g_\delta}u_\delta=0\).
On \(\varpi^{-1}(B_{3r_\delta}\setminus B_{r_\delta/2})\), we have \(u_\delta(z)=r_\delta^2v(z/r_\delta)\). It follows from Lemma 20 that \[\Delta_{g_\delta}u_\delta(z)=\Delta_{\widetilde{g}_\delta}v(w)|_{w=z/r_\delta}.\] Lemma 16 implies \[\sup_{A}\left|\Delta_{\widetilde{g}_\delta}v-\Delta_{\mathrm{eucl}}v\right|\rightarrow0\] where \(A=\{1/2\leq|w|\leq3\}\), so that \[\Delta_{g_\delta}u_\delta(z)\rightarrow \Delta_{\mathrm{eucl}}v(w)|_{w=z/r_\delta}=f(z/r_\delta)\] uniformly for \(r_\delta/2\leq |z|\leq 3r_\delta\) as \(\delta\rightarrow0\). Thus we may take \(\delta\ll 1\) such that \[\sup_{r_\delta/2\leq |z|\leq 3r_\delta}\left|\Delta_{g_\delta}u_\delta(z)-f(z/r_\delta)\right|\leq\tau\leq 1.\] By the definition of \(f\), we obtain \[\begin{align} & & \Delta_{g_\delta}u_\delta\leq 1\;\;\;\text{on}\;\varpi^{-1}(B_{r_\delta}\setminus B_{r_\delta/2}),\\ & & \Delta_{g_\delta}u_\delta\leq -C_0+1\;\;\;\text{on}\;\varpi^{-1}(B_{2r_\delta}\setminus B_{r_\delta}),\\ & & \Delta_{g_\delta}u_\delta\leq \tau\;\;\;\text{on}\;\varpi^{-1}(B_{3r_\delta}\setminus B_{2r_\delta}). \end{align}\]
On \(\varpi^{-1}(B_\rho\setminus B_{3r_\delta})\), since \(g_\delta=g\), we have \[\begin{align} \label{eq:Laplacian95case954} \Delta_{g_\delta}u_\delta(z) &=& r_\delta^2v(z/r_\delta)\Delta_{g_\delta}\kappa(z) +\kappa(z)\Delta_{g_\delta}\left(r_\delta^2v(z/r_\delta)\right) +2r_\delta^2\mathrm{Re\,}\mathrm{tr}_{g_\delta}\left(i\partial\kappa\wedge\bar{\partial}_zv(z/r_\delta)\right)\notag\\ &=& r_\delta^2v(z/r_\delta)\Delta_g\kappa(z) +\kappa(z)\Delta_{\widetilde{g}_\delta}v(w)|_{w=z/r_\delta} +2r_\delta\mathrm{Re\,}\mathrm{tr}_{g}\left(i\partial\kappa\wedge\bar{\partial}_wv(z/r_\delta)\right). \end{align}\tag{68}\] By 67 , \[\label{eq:Laplacian95case954951} \left|r_\delta^2v(z/r_\delta)\Delta_g\kappa(z)\right|\lesssim\frac{r_\delta^2}{\rho^2},\qquad \forall\,z\in B_\rho\setminus B_{3r_\delta}.\tag{69}\] Here and in what follows, the implicit constants are independent of \(\rho\) and \(\delta\). Note that the coefficients of \(\widetilde{g}_\delta\) are given by \[(\widetilde{g}_\delta)_{j\bar{k}}(w)=g_{j\bar{k}}(r_\delta w)=\frac{1}{2}\delta_{j\bar{k}}+\frac{\partial^2\varphi}{\partial z_j\partial\bar{z}_k}(r_\delta w),\;\;\;3\leq |w|\leq \rho/r_\delta.\] Since \(\varphi(z)=O(|z|^4)\) on \(\varpi^{-1}(B_\rho)\), we have \[\sup_{3\leq |w|\leq \rho/r_\delta}\left|(\widetilde{g}_\delta)_{j\bar{k}}(w)-\frac{1}{2}\delta_{j\bar{k}}\right|=O(\rho^2),\qquad \rho\rightarrow0.\] This together with Lemma 21 yield \[\sup_{3\leq |w|\leq \rho/r_\delta}\left|\Delta_{\widetilde{g}_\delta}v-\Delta_{\mathrm{eucl}}v\right| =O(\rho^2),\;\;\;\rho\rightarrow0.\] Since \(\Delta_{\mathrm{eucl}}v(w)=f(w)=0\) when \(|w|\geq3\), it follows that \[\label{eq:Laplacian95case954952} \left|\kappa(z)\Delta_{\widetilde{g}_\delta}v(w)|_{w=z/r_\delta}\right|\lesssim\rho^2,\qquad \forall\,z\in B_\rho\setminus B_{3r_\delta}.\tag{70}\] Moreover, since \(g^{j\bar{k}}=\delta_{j\bar{k}}+O(\rho^2)\) as \(\rho\rightarrow0\), we have \[\begin{align} \label{eq:Laplacian95case954953} \left|2r_\delta\mathrm{Re\,}\mathrm{tr}_{g}\left(i\partial\kappa\wedge\bar{\partial}_wv(z/r_\delta)\right)\right| &=& 2r_\delta\left|\mathrm{Re}\,\sum g^{j\bar{k}}\frac{\partial\kappa}{\partial z_j}\frac{\partial v}{\partial\bar{w}_k}(z/r_\delta)\right|\notag\\ &\lesssim& \frac{r_\delta}{\rho},\qquad \forall\,z\in B_\rho\setminus B_{3r_\delta}. \end{align}\tag{71}\] when \(0<\delta\ll\rho\ll1\), in view of Lemma 21 and 67 . It follows from 69 , 70 , 71 and 68 that \[\Delta_{g_\delta}u_\delta(z)\lesssim \rho^2+\frac{r_\delta^2}{\rho^2}+\frac{r_\delta}{\rho},\qquad \forall\,z\in B_\rho\setminus B_{3r_\delta}.\] As a consequence, we may choose \(0<\delta\ll\rho\ll1\) such that \[\Delta_{g_\delta}u_\delta\leq\tau\;\;\;\text{on }\;\varpi^{-1}(B_\rho\setminus B_{3r_\delta}).\]
Combining (1)\(\sim\)(4) with 65 , we conclude that \[\label{eq:sc95raise} S_C(g_\delta)-\Delta_{g_\delta}u_\delta\geq-1.\tag{72}\] Since \(u_\delta\ge 0\), it follows from 72 and 66 that \[S_C(h_\delta)=e^{-u_\delta/n}\left(S_C(g_\delta)-\Delta_{g_\delta} u_\delta\right)\ge -1.\]
It remains to compare \(\mathrm{vol}_{h_\delta}\) with \(\mathrm{vol}_{g_\delta}\). Since \(u_\delta=0\) on \(\widehat{M}\setminus\varpi^{-1}(B_\rho)\), \[\label{eq:volume95conformal951} \mathrm{vol}_{h_\delta}(\widehat{M}\setminus\varpi^{-1}(B_\rho))=\mathrm{vol}_{g_\delta}(\widehat{M}\setminus\varpi^{-1}(B_\rho)).\tag{73}\] By Lemma 21, we have \(|u_\delta|\leq Cr_\delta^2\), so that \[\mathrm{vol}_{h_\delta}(\varpi^{-1}(B_\rho)) =\int_{\varpi^{-1}(B_\rho)} e^{u_\delta}\,dV_{g_\delta} \leq e^{Cr_\delta^2}\mathrm{vol}_{g_\delta}(\varpi^{-1}(B_\rho)),\] while ?? implies \[\mathrm{vol}_{g_\delta}(\varpi^{-1}(B_\rho))\leq \mathrm{vol}_{g_\delta}(\widehat{M})\leq \mathrm{vol}_g(\widehat{M})+O(r_\delta^2),\qquad \delta\rightarrow0;\] in particular, \(\mathrm{vol}_{g_\delta}(\varpi^{-1}(B_\rho))\) is bounded by a constant independent of \(\rho\) and \(\delta\) as \(\delta\rightarrow0\). Thus \[\label{eq:volume95conformal952} \mathrm{vol}_{h_\delta}(\varpi^{-1}(B_\rho))=\mathrm{vol}_{g_\delta}(\varpi^{-1}(B_\rho))+O(r_\delta^2).\tag{74}\] It follows from 73 and 74 that \[\mathrm{vol}_{h_\delta}(\widehat{M})=\mathrm{vol}_{g_\delta}(\widehat{M})+O(r_\delta^2).\] ◻
By Proposition 19 and 64 , we obtain \[\mathrm{MinVol}_C(M)\leq \mathrm{vol}_{h_\delta}(\widehat{M})\leq \frac{(n\pi)^n}{n!}\mathrm{CanVol}(M)+4\varepsilon\] when \(0<\delta\ll\rho\ll1\), while Theorem 1 gives \[\mathrm{MinVol}_C(M)\geq \frac{(n\pi)^n}{n!}\mathrm{CanVol}(M).\] The proof of Theorem 7 is complete.
It is also natural to consider \[\mathcal{I}_R(M):=\inf_{g\in\mathcal{RM}(M)}\int_M|Ric(g)|^{n/2}dV_g\] for any compact Riemannian \(n-\)manifold \(M\) (see LeBrun [19]). By [19], if \(M\) is a projective surface with \(K_M\) big and nef and \(M_k\) is the blow-up of \(M\) at \(k\) points, then \[\label{eq:Ricci95integral} \mathcal{I}_R(M_k)\geq 8\pi^2\mathrm{CanVol}(M)+k\;\left(>8\pi^2\mathrm{CanVol}(M_k)\right)\tag{75}\] holds.
Since \(K_{M_k}\) is big, there exists a singular Kähler-Einstein metric \(g_{KE}\) which is smooth on a Zariski open subset \(U\) of \(M_k\). Based on 75 , we have
Proposition 22. There does not exist a sequence \(\{g_j\}\) of smooth Kähler metrics on \(M_k\) such that the following conditions hold:
\(\{g_j\}\) converges in the \(C^\infty_{\mathrm{loc}}-\)topology to \(g_{KE}\) on \(U\).
Both \(dV_{g_j}\) and \(|Ric(g_j)|\) are uniformly bounded on \(M_k\).
Proof. Let \(\omega_{KE}\) be the Kähler form of \(g_{KE}\) on \(U\). Note that \(Ric(\omega_{KE})=-\omega_{KE}\) on \(U\). By 31 , we have \[\mathrm{vol}_{KE}(M_k\setminus E)\leq 2\pi^2\mathrm{CanVol}(M_k),\] where \(E:=M_k\setminus U\). Suppose on the contrary that there exists a sequence \(\{g_j\}\) of Kähler metrics on \(M_k\) satisfying (1) and (2). Then for any \(\delta>0\), there exists a neighbourhood \(E_\delta\) of \(E\) such that
\(\mathrm{vol}_{g_j}(E_\delta)<\delta\) for all \(j\),
\(|Ric(g_j)|\leq 2(1+\delta)\) on \(M_k\setminus E_\delta\) when \(j\gg1\), and
\(\mathrm{vol}_{g_j}(M_k\setminus E_\delta)\leq 2\pi^2\mathrm{CanVol}(M_k)+\delta\) when \(j\gg1\).
Here (b) follows from the fact that \(|Ric(\omega_{KE})|^2=|\omega_{KE}|^2=2\), \(|Ric(g_{KE})|^2=2|Ric(\omega_{KE})|^2=4\) and \(g_j\rightarrow g_{KE}\) uniformly on \(M_k\setminus E_\delta\).
Therefore, \[\int_{M_k\setminus E_\delta}|Ric(g_j)|^2dV_{g_j}\leq 4(1+\delta)^2\mathrm{vol}_{g_j}(M_k\setminus E_\delta)=4(1+\delta)^2(2\pi^2\mathrm{CanVol}(M_k)+\delta).\] Moreover, since \(|Ric(g_j)|\leq C\) for some constant \(C\) independent of \(j\), we have \[\int_{E_\delta}|Ric(g_j)|^2dV_{g_j}\leq C^2\mathrm{vol}_{g_j}(E_\delta)<C^2\delta.\] Thus \[\mathcal{I}_R(M_k)\leq \int_{M_k} |Ric(g_j)|^2dV_{g_j}< 4(1+\delta)^2(2\pi^2\mathrm{CanVol}(M_k)+\delta)+C^2\delta,\] which contradicts 75 when \(\delta\ll0\). ◻
Acknowledgements. The first author is supported by National Natural Science Foundation of China, No. 12271101; the third author is supported by National Natural Science Foundation of China, No. 12471079.