We consider the periodic quintic nonlinear Schrödinger and prove small-mass global well-posedness in \(H^s(\mathbb{T})\) for \(s>0\). The proof relies on a new derivative-loss-free
\(L^6_{t,x}\) Strichartz estimate which is established using the high-low method, an asymmetric superlevel set estimate and a new refined broad-narrow argument. Although our \(L^6_{t,x}\)
Strichartz estimate is not sharp, being valid on slightly shorter time scales than the optimal logarithmic scale, combining it with the \(I\)-method enables the extension of local solutions to arbitrary times.
We consider the quintic nonlinear Schrödinger equation (NLS) on the unit circle \(\mathbb{T}=\mathbb{R}/\left(2\pi \mathbb{Z}\right)\), \[\label{eq:NLS}
\begin{cases} i \partial_tu +\Delta u=\mu \left\lvert u\right\rvert^4u, \\ u(x,0)=u_0(x) \in H^{s}\left(\mathbb{T}\right), \end{cases} \tag{1}\] where \(\mu = 1\) corresponds to the defocusing case and \(\mu = -1\) to the focusing case. For smooth solutions \(u\), the mass \(M(u(t))\) and energy \(E(u(t))\) are conserved along the
flow of 1 , where \[\begin{align} \tag{2} M\left(u(t)\right) &:= \left\lVert u(t)\right\rVert_{L_x^2(\mathbb{T})}, \\ \tag{3} E(u(t)) &:= \frac{1}{2}\left\lVert\partial_x
u(t)\right\rVert_{L_x^2(\mathbb{T})}^2 + \frac{\mu}{6} \left\lVert u(t)\right\rVert^6_{L_x^6(\mathbb{T})}. \end{align}\] Moreover, 1 enjoys a scaling symmetry which is critical with respect to the mass. Specifically, for any \(\lambda>0\), we map a solution of 1 to another solution, \(u \mapsto u^\lambda\) via the transformation \[u^\lambda(x,t):= \frac{1}{\lambda^\frac{1}{2}} u\left(\frac{x}{\lambda}, \frac{t}{\lambda^{2}}\right),\] and stress that \(u^\lambda\) is defined on \(\mathbb{T}_\lambda \times \mathbb{R}\) where \(\mathbb{T}_\lambda := \mathbb{R}/(2\pi\lambda\mathbb{Z})\). We say that 1 is mass-critical as the rescaling leaves the mass invariant.
To formulate our main results, we recall the standard notion of well-posedness. The initial value problem 1 is locally well-posed if, for any \(u_0 \in H^s(\mathbb{T})\), there exists a
time \(T>0\), an open ball \(B\) in \(H^s(\mathbb{T})\) containing \(u_0\), and a closed subspace, \(X\), of \(C^0([0,T] \rightarrow H^s(\mathbb{T}))\), such that for each \(u_0 \in B\) there exists a unique \(u \in X\)
satisfying \[u(t)=S(t)u_0+i \mu \int_0^t S(t-t') \left\lvert u(t')\right\rvert^4u(t') dt',\] where \(S(t):= e^{it \Delta}\) is the Schrödinger group. Moreover, we require
the map \(u_0 \mapsto u\) to be uniformly continuous as a map from \(B\) (endowed with the \(H^s(\mathbb{T})\) topology) to X (endowed with the \(C^0([0,T] \rightarrow H^s(\mathbb{T}))\) topology). If we can take \(T>0\) to be arbitrarily large, we say that 1 is globally well-posed.
The main objective of this paper is to establish global well-posedness of the Cauchy problem 1 for \(s>0\). Our approach is based on establishing a derivative-loss-free \(L^6_{t,x}\) Strichartz estimate and combining this estimate with the \(I\)-method. We begin by stating the Strichartz estimate.
Theorem 1. There exists a constant \(C>1\) such that for any \(N \geq 1\) and any \(\phi \in L^2(\mathbb{T})\) with \(\mathop{\mathrm{supp}}\hat{\phi} \subset [-N, N]\), the following estimate holds \[\left\lVert S(t) \phi\right\rVert_{L^6_{t,x}\left( \left[0, \left(\log N \right)^{-C}\right] \times
\mathbb{T}\right)} \leq C\left\lVert\phi\right\rVert_2.\]
Theorem 1 is proved via a lossless small-cap decoupling estimate. A key ingredient in the argument is an estimate on the size of the intersection
of superlevel sets of functions whose Fourier supports are contained in caps \(\Sigma_1\) and \(\Sigma_2\). In the regime where the length of \(\Sigma_1\) is
much smaller than the distance between \(\Sigma_1\) and \(\Sigma_2\), we establish an asymmetric superlevel set estimate which yields an additional gain reflecting this scale separation (see
Lemma 12 for details). This gain is used to eliminate logarithmic losses in the decoupling argument. As a further consequence of this analysis, we recover a refined trilinear Strichartz
estimate due to McConnell[1], up to an arbitrarily small polynomial loss in the frequency scale. We refer the reader
to Appendix 6 for a proof using our method.
The derivative-loss-free estimate in Theorem 1 provides the key input for the nonlinear analysis. Combining this estimate with the \(I\)-method, we prove the following small-mass global well-posedness result for 1 .
Theorem 2. There exists a constant \(\delta>0\) such that for any \(s>0\) and any initial data \(u_0 \in H^s(\mathbb{T})\) satisfying \(\left\lVert u_0\right\rVert_2 \leq \delta\), the Cauchy problem (1 ) is globally well-posed.
In his seminal work [2], Bourgain established local well-posedness of 1 for \(s >
0\). This result is sharp (up to endpoint) in the sense that the data-to-solution map fails to be uniformly continuous for \(s<0\)[3]. A key component of Bourgain’s [2] proof was the following Strichartz estimate:
there exists a constant \(c>0\) such that for all \(\phi \in L^2(\mathbb{T})\) satisfying \(\mathop{\mathrm{supp}}\widehat{\phi} \subset
\left[-N,N\right]\), the following estimate holds \[\left\lVert S(t) \phi \right\rVert_{L^6_{t,x}\left(\mathbb{T}\times \mathbb{T}\right)} \leq C_N
\left\lVert\phi\right\rVert_2, \text{ where } C_N:= c \exp\left(c \frac{\log N}{\log \log N}\right).
\label{eq:32bourgain32Strichartz}\tag{4}\] This Strichartz estimate has since played a central role in the analysis of the nonlinear Schrödinger equation on the torus and has served as a starting point for a number of refinements and
applications. We briefly review these developments, focusing first on improvements to 4 and the methods underlying their proofs, and then on applications to global well-posedness.
We begin with a discussion of previous improvements to 4 . While the estimate 4 was sufficient to establish local well-posedness for \(s>0\), it is not expected to be sharp in terms of the growth of \(C_N\). Indeed, by considering \(\phi = \sum_{|k| \leq N} e^{ikx}\), it was conjectured in
[2], [4] that the derivative loss could be reduced to \(C_N \sim (\log N)^{1/6}\). Despite significant effort, this conjecture remains open. Partial progress has been achieved through refinements of the decoupling techniques underlying the \(\ell^2\)
decoupling theorem of Bourgain and Demeter [5]. For instance, Guth–Maldague–Wang [6] applied the high-low method introduced by Guth–Solomon–Wang [7] to obtain bounds of the form \(C_N \sim (\log N)^c\) for some absolute constant \(c \gg
1\). This was subsequently improved by Guo–Li–Yung [8], who established an asymmetric bilinear decoupling inequality to show
that \(C_N \lesssim_\epsilon (\log N)^{2+\epsilon}\) for every \(\epsilon>0\).
An alternative approach to obtaining estimates of the form of 4 is to establish derivative-loss-free Strichartz estimates on shorter, frequency-dependent time intervals. More precisely, one seeks the largest
time \(T>0\) such that there exists a constant \(c>0\) with the property that, for all \(\phi \in L^2(\mathbb{T})\) satisfying \(\mathop{\mathrm{supp}}\hat{\phi} \subset [-N,N]\), the estimate \[\|S(t)\phi\|_{L^6_{t,x}([0,T]\times\mathbb{T})} \leq c \|\phi\|_2
\label{eq:derivative95free95L6}\tag{5}\] holds. If one could establish 5 with \(T=(\log N)^{-1}\), then by decomposing \([0,2\pi]\)
into intervals of length \((\log N)^{-1}\) one would immediately obtain 4 with \(C_N\sim (\log N)^{1/6}\). In this direction, Burq–Gérard–Tzvetkov
[9] proved 5 with \(T = N^{-1}\). Their result in fact
extends to arbitrary compact Riemannian manifolds in higher dimensions, for the same time scale. In the periodic setting, Herr and Kwak [10] obtained the \(L^4_{t,x}\) analogue of 5 on the two-dimensional square torus \[\left\lVert S(t) \phi \right\rVert_{L^4_{t,x}\left( \left[0, \frac{1}{\log N}\right] \times \mathbb{T}^2\right)} \leq c \left\lVert\phi\right\rVert_2,
\label{eq:32Herr95Kwaq32Strichartz}\tag{6}\] by using the Szemerédi–Trotter theorem to count rectangles with vertices in a finite set in the plane. This in turn yields a sharp Strichartz estimate for the higher-dimensional \(L^4_{t,x}\) analogue of 4 and also plays an important role in their proof of small-mass global well-posedness. Returning to the one-dimensional periodic setting, the best known result
for the maximal time for which 5 holds is \(T = N^{-131/208}\), due to McConnell [1], who used number theoretic methods to count the number of lattice points in thin annuli.
In this paper, we prove that 5 holds with \(T = (\log N)^{-10000}\). While we make no attempt to obtain a sharp exponent, this time scale already suffices for our purposes of
establishing small-mass global well-posedness. We also note that our result does not improve the best known bound [8] for the
constant \(C_N\) in 4 . Our approach is based on small-cap decoupling, in contrast with the number-theoretic methods of McConnell [1] and the incidence-geometric approach of Herr and Kwak [10]. Small-cap decoupling may be viewed as a refinement of the classical \(\ell^2\) decoupling theory adapted to the study of Strichartz estimates on
time intervals shorter than a single period. The subject was initiated by Demeter–Guth–Wang [11] and further developed in the two-dimensional setting by
Fu–Guth–Maldague [12] and Guth–Maldague [13] using the
high–low method.
We now turn to the global well-posedness problem for 1 . On the real line, Dodson [14] proved global
well-posedness of 1 in \(H^s(\mathbb{R})\) for all \(s \ge 0\), by establishing that solutions scatter in \(L^2(\mathbb{R})\). In
the periodic setting, as scattering is not expected to hold due to the lack of dispersion [15], a different approach is
required. In this context, derivative-loss-free Strichartz estimates have played a central role in recent advances toward establishing global well-posedness for mass-critical nonlinear Schrödinger equations.
In a breakthrough result, Herr and Kwak [10], [16] established global well-posedness for the mass-critical NLS on \(H^s(\mathbb{T}^2)\) for \(s>0\).
Their approach proceeds in two stages: first [10] they proved small-mass global well-posedness using the
derivative-free Strichartz estimate 6 and subsequently [16] they removed the small assumption and proved that their result is sharp in the sense that the data-to-solution map fails to be uniformly continuous for initial data in \(L^2(\mathbb{T}^2)\). The goal of the present paper is to establish the one-dimensional analogue of the small-mass global well-posedness result proved in [10].
We now briefly recall the argument in [10]. Under a suitable smallness assumption on the mass, the
derivative-free Strichartz estimate 6 yields local well-posedness in the complete metric space \[X_N:=\left\{ u\in C^0\left( J_N \rightarrow H^s(\mathbb{T}^2) \right) \cap Y^s_{J_N}:
\left\lVert u\right\rVert_{Z_N} \lesssim 1 \right\},\] where \(N \gg 1\) is sufficiently large constant, \(J_N:=\left[0,\frac{1}{\log N} \right]\) is the existence time interval, the
space \(Y^s_{J_N}\) is the time-restricted \(Y^s\) space (see 4.1 for details) and \[\left\lVert u\right\rVert_{Z_N}^2:=
\left\lVert u\right\rVert_{Y^0_{J_N}}^2+ N^{-2s} \left\lVert u\right\rVert_{Y^s_{J_N}}^2.\] As the length of the existence time interval scales with \(\frac{1}{\log N}\), local solutions may be continued for
arbitrary time intervals, thereby establishing global well-posedness. In fact, Herr and Kwak [10] proved that for
every \(k \in \mathbb{N}\), local solutions can be extended from \([0,T_k]\) to \([0,T_{k+1}]\) where \[T_k := \sum_{j=0}^{k-1}
\frac{1}{2 \log\!\bigl(K^j N_0\bigr)},\] with fixed constants \(K \gg 1\) and \(N_0 \gg_s 1\). This procedure can be iterated for arbitrarily large time intervals since \(\lim_{k \rightarrow \infty} T_k = \infty\). Crucially, this conclusion relies on the fact that the length of each extension step scales like \(\frac{1}{\log N}\). If instead the length of
existence interval scaled with \(\frac{1}{(\log N)^{c}}\) for any \(c>1\), the above summation would converge and the iteration scheme would fail. Therefore, we stress that this argument
would not work if 6 were valid for shorter time intervals of length \(\frac{1}{\left(\log N\right)^c}\) for any \(c>1\).
An alternative approach to extending local solutions to global ones is based on controlling the growth of the \(H^s\) norm of smooth solutions to 1 via the \(I\)-method. Originally introduced in [17], [18], the \(I\)-method has become a canonical tool in obtaining global well-posedness for infinite energy initial data. This method relies on constructing families of modified Hamiltonians which are almost conserved and has been
successfully applied to a range of dispersive equations, including the nonlinear Schrödinger equations [19]–[22], the derivative NLS [18], and the KdV equation [23], both in periodic and Euclidean settings.
In this direction, the \(I\)-method has been combined with refined bilinear and trilinear estimates together with 5 to establish global well-posedness for 1 for low-regularity initial data. In fact, Bourgain [24] developed an approach combining the \(I\)-method with normal form reductions to prove global well-posedness below the energy space. Subsequent developments of this framework led to progressively lower regularity thresholds. Specifically, De Silva et
al.[19], [25] established a refined bilinear Strichartz estimate which yielded global well-posedness for \(s > \tfrac{4}{9}\), while Li et al.[21] further lowered the regularity threshold to \(s > \tfrac{2}{5}\) via a resonant decomposition of the
modified energy.
More recently, derivative-free Strichartz estimates have been incorporated into the \(I\)-method framework to obtain further improvements in the regularity threshold for global well-posedness under an additional
small-mass assumption. For example, Schippa [20] combined the derivative-free Strichartz estimate of Burq–Gérard–Tzvetkov [26], valid up to time \(T=N^{-1}\), with the refined bilinear Strichartz of De
Silva et al.[19] to prove global well-posedness for \(s >
\tfrac{1}{3}\). McConnell [1] further improved this threshold to \(s >
\tfrac{131}{624}\) by establishing 5 with \(T= N^{-\frac{131}{208}}\) and by proving the following refined asymmetric Strichartz estimate
\[\left\lVert S(t)\phi_1 (S(t)\phi_2)^2\right\rVert_{L^2_{t,x}([0,T]\times\mathbb{T})}^2 \lesssim \left(T^{1/2}+\frac{N_2}{N_1}\right) \left\lVert\phi_1\right\rVert_2^2
\left\lVert\phi_2\right\rVert_2^4,
\label{eq:32strichartz95asym}\tag{7}\] for all \(\phi_1, \phi_2 \in L^2(\mathbb{T})\) satisfying \(\mathop{\mathrm{supp}}\widehat{\phi}_j \subset [N_j, 2N_j]\) for \(j=1,2\) with \(N_1 \gg N_2\). This estimate should be viewed as a refinement of 5 , reflecting an additional gain arising from the frequency separation
between the interacting functions. In this paper we are able to recover 7 up to a loss of \(N_2^\epsilon\), where \(\epsilon>0\) is arbitrarily
small, as a consequence of the decoupling argument used in the proof of Theorem 1. We include a proof in Appendix 6 for completeness. While 7 does not enter into our proof of small-mass global well-posedness, it is natural to ask whether estimates of this type could help remove the small-mass
assumption in the defocusing case. We leave this as an open problem for future work.
To summarize, in this paper we follow a similar approach to [1], [20] to obtain small-mass global well-posedness of 1 in \(H^s(\mathbb{T})\) for \(s>0\). Our
main contributions are twofold: (i) we prove 5 for longer times \(T = \frac{1}{(\log N)^c}\) for some \(c \gg 1\) and (ii) we do not rely on
resonant decompositions of the modified energy or on refined bilinear/trilinear Strichartz estimates — our proof depends solely on bounding the first modified energy.
Theorem 1 follows from a lossless small-cap decoupling estimate for functions whose Fourier support lies in an \(R^{-1}\) neighborhood of the parabola. Roughly speaking, one decomposes the Fourier support into caps \(\gamma\) of length \(1/N\) and seeks to establish an
\(L^6\) decoupling estimate without any logarithmic loss. Accordingly, let \[f=\sum_\gamma f_\gamma\] be such a decomposition where each \(f_\gamma\) has
essentially constant amplitude on \(B_R\). We refer the reader to 2 for the precise geometric setup and notation. We prove the following lossless small-cap decoupling result
\[\label{eq:32main95L695dec95intro} \|f\|_{L^6(B_R)}^6
\lesssim
N^2R
\left(\sum_\gamma a_\gamma^2\right)^3,\tag{8}\] where \(\sqrt{R}(\log N)^{10000}\leq N\leq R\) and \(a_\gamma\) denotes the amplitude of \(f_\gamma\) on \(B_R\) (see Theorem 3 for the precise formulation).
The proof of 8 begins with a standard pigeonholing argument which reduces matters to the case where \(a_\gamma \sim 1\) or \(a_\gamma=0\) for
each \(\gamma\). The main step is to estimate the size of the superlevel sets \[U_a(f):=\{x\in B_R : \frac{a}{2}\leq \left\lvert f(x)\right\rvert\leq a\}.\] More precisely, we prove that
there exist a constant \(C>1\) such that for all \(R/N^2 \lesssim (\log N)^{-2C}\), one has \[\label{eq:32main32decoupling32estimate32on32Ua}
|U_a|a^6
\lesssim
\max\left(
\log\left(\frac{\lambda}{a}\right)^{O(1)}
\frac{a}{\lambda},
(\log N)^{-C}
\right)
N^2R\lambda^3,\tag{9}\] where \(\lambda\) denotes number of caps \(\gamma\) such that \(\left\lvert f_\gamma\right\rvert\sim 1\). The estimate
in 8 then follows by summing over dyadic values of \(a\).
To establish 9 , we mainly follow the proof of [13]. As a corollary to their theorem, we see
that up to a \(\log(N)^{O(1)}\) loss, the only possible sharp contribution to \(\|f\|^6_{L^6}\) comes from \(|U_\lambda|\lambda^6\), i.e., the highest
possible peaks. In [13], the result was first proved for the broad case and a broad–narrow argument was then used to obtain the general case. To improve
their argument and remove the \(\log N\) loss, we need to overcome two obstacles: (i) replace the \(\log N\) loss in the broad estimate by a \(\log
\lambda/a\) loss and (ii) remove any potential \(\log N\) losses coming from the broad–narrow argument.
The broad estimate applies when the caps \(\Sigma_1\) and \(\Sigma_2\) are comparable in size and separated by the same scale. Following the approach of Guth and Maldague [13], we first establish a broad estimate using the high–low method and then combine it with a bilinear restriction estimate. By the high–low method, we mean
an argument based on distinguishing whether the functions are dominated by high or low frequencies. In practice, this involves a dyadic decomposition in the frequency domain and treating the resulting pieces differently: the low-frequency part is
controlled in \(L^\infty\), while the high-frequency contributions are handled using almost orthogonality. To overcome the first obstacle and replace the \(\log N\) loss arising at each
scale by the smaller factor \(\log \frac{\lambda}{a}\), we carefully restrict the number of high–low scales that contribute to the superlevel set estimate.
To overcome the second obstacle, we develop a refined broad–narrow argument. The broad–narrow decomposition has become a canonical tool in harmonic analysis and appears, for instance, in the proof of the \(\ell^2\)
decoupling theorem [5] and in [13]. However, a direct implementation of the standard broad–narrow argument from Guth and Maldague [13] would still
incur a \(\log N\) loss, due to the presence of \(\log N\) distinct broad and narrow scales. Our refinement avoids this loss by exploiting the fact that contributions coming from
sufficiently separated broad–narrow scales interact only weakly. More precisely, we prove an asymmetric superlevel estimate that deals with intersections of superlevel sets associated with functions \(f_1\) and \(f_2\) whose respective Fourier supports are contained in caps \(\Sigma_1\) and \(\Sigma_2\) such that the length of the shorter cap is much shorter than the
distance between them. Roughly speaking, for caps \(\Sigma_1\) and \(\Sigma_2\) that are at least \(l\) separated and for \(a,b\) in the appropriate ranges (see Lemma 12 for a precise statement), one has \[\label{eq:32asym95superlevel} \left\lvert U_{a}(f_{1}) \cap U_{b}(f_{2})\right\rvert \lessapprox \max\left(\frac{l(\Sigma_2)}{l},
\frac{\sqrt{R}}{N}\right)\frac{N^2R\lambda(\Sigma_1)\lambda(\Sigma_2)^2}{a^2b^4},\tag{10}\]
where \(l(\Sigma_j)\) denotes the length of the cap \(\Sigma_j\), \(\lambda(\Sigma_j)\) is the number of caps \(\gamma \subset
\Sigma_j\) such that \(\left\lvert f_\gamma\right\rvert \sim 1\) and \(\lessapprox\) should be understood as bound up to logarithmic losses. The additional gain \(\max\left(\frac{l(\Sigma_2)}{l}, \frac{\sqrt{R}}{N}\right)\) is precisely what allows us to control interactions between distant broad–narrow scales and thereby eliminate the logarithmic losses. The asymmetric estimate is
established using a high–low analysis similar to that employed in the proof of the broad estimate. In addition to its role in the proof of Theorem 1, 10 may have further applications beyond the present work. For instance, it is a key input in recovering the asymmetric Strichartz estimate in Appendix 6.
We now turn to the proof of Theorem 2. The proof of Theorem 2 is based on the \(I\)-method and broadly follows the approach developed in [1], [19], [20]. As we are assuming that the mass is small, it suffices to consider the defocusing case (\(\mu=1\)) by the
Gagliardo-Nirenberg [27] inequality. Next, by exploiting the rescaling symmetry of the equation, we analyze solutions \(u^\lambda\) on the space-time domain \(\mathbb{T}_\lambda \times \mathbb{R}\). We introduce a Fourier multiplier \(I\) which acts as the identity on low
frequencies \(\left\lvert k\right\rvert \lesssim N\) and damps high frequencies \(\left\lvert k\right\rvert\gg N\) at the rate \(\left(\left\lvert k\right\rvert/N
\right)^{s-1}\), where \(N\) is a large parameter to be determined. We define the \(I\)-system by applying the \(I\)-operator to 1 and the modified energy \(E^1(u) := E(Iu)\) is then naturally interpreted as the energy of the \(I\)-system. Under a small mass assumption, we establish a local
existence result for the \(I\)-system for time intervals of length \(\lambda^2 \log(\lambda N)^{-c}\) where \(c>0\) is a fixed constant. The main
challenge is to extend this local result to arbitrary times. This is achieved by proving that \(E^1(u(t))\) is "almost conserved", in the sense that the time-averaged derivative of \(E^1\)
exhibits mild growth. This slow growth of the modified energy allows us to iterate the local existence argument and propagate the \(H^s\)-bound for \(u^\lambda\) over arbitrarily long times.
Undoing the rescaling then yields polynomial-in-time bounds for the original solution \(u\), which establishes global well-posedness.
Our paper is organized as follows: in 2 we introduce the geometric setup for decoupling, in 3 we prove Theorem 1 using the high-low method and a refined broad-narrow argument, in 4 we transfer our Strichartz estimates to \(Y^s\) spaces and in 5 we give the proof of Theorem 2 using the \(I\)-method. In Appendix 6 we give an alternative proof of the asymmetric Strichartz estimate first established in [1].
We use \(A \lesssim B\) to indicate an estimate of the form \(A \leq CB\) for some constant \(C>0\). When we want to stress that the constant depends
on a parameter, say \(p\), we write \(A \lesssim_p B\). If both \(A \lesssim B\) and \(B \lesssim A\) hold, we write \(A \sim B\). Furthermore, \(A \ll B\) signifies that \(A \leq cB\) for some small constant \(0<c<1\) and we use \(a\pm\) to denote \(a \pm \epsilon\) where \(0<\epsilon \ll 1\). When we say that a property \(Q(A,B)\) holds whenever \(A \ll B\), we mean that that there exist a small enough absolute constant \(0<c<1\) such that \(Q(A,B)\) holds whenever \(A \leq
cB\). For any measurable \(A \subset \mathbb{R}^d\), we denote its characteristic function by \(\chi_A\) and its Lebesgue measure by \(\left\lvert
A\right\rvert\). Finally, \(\mathbb{N}\) denotes the set of natural numbers and we write \(\mathbb{N}_0:=\mathbb{N} \cup \{0\}\) for the set of non-negative integers.
2 Geometric Setup and Preliminary Lemmas for Decoupling↩︎
Let’s first go through some definitions and standard results in decoupling. Let \[\mathcal{P}:= \{(x,x^2) : x \in [0,1]\}\] denote the truncated parabola, and let \(\Gamma:=N_{1/R}(\mathcal{P})\) be its \(1/R\)-neighborhood. We write \(B_r(x)\) for the ball of radius \(r\) centered at \(x \in \mathbb{R}^2\), and \(B_r\) for the ball of radius \(r\) centered at the origin. We now record some basic notations.
Definition 1. A cap\(\tau\) of length \(l(\tau)\) centered at \(c(\tau)\) is defined as \[\tau :=
N_{1/R}(\mathcal{P}) \cap B_{l(\tau)}(c(\tau)).\] The direction\(d(\tau)\) of \(\tau\) is the direction of the normal to \(\mathcal{P}\) at
\(c(\tau)\).
Definition 2. We say that a set \(S\) has rectangular shape if there exist rectangles. \[R_1 \subseteq S \subseteq R_2\] such that \(|R_2|
\leq 100\,|R_1|\) where \(|R|\) denotes the area of the rectangle \(R\).
Given a rectangular shape \(S\), we say that a function \(W\)decays rapidly off \(S\) if \[W(x) \lesssim
\left(\frac{1}{1+\operatorname{dist}(x,S)}\right)^{100}.\]
The dual set\(S^*\) of \(S\) is defined by \[S^* := \{x \in \mathbb{R}^2 : |x \cdot y| \leq 1 \;\; \text{for all } y \in S \}.\]
We use \(W_S\) to denote an (\(L^1\)-normalized) weight function on \(S\), i.e.a nonnegative function such that
\(W_S \sim \tfrac{1}{|S|}\) on \(S\),
\(\int W_S \sim 1\),
\(W_S\) decays rapidly off \(S\),
\(\widecheck{W_S}\) and \(\widehat{W_S}\) are supported in \(S^*\).
By \(\|f\|_{\sout{L}^p(W_S)}\), we mean \(\left(\int |f|^p W_S\right)^{1/p}\).
By the argument in section 2.1 in [13], given any set \(S\) with rectangular shape, there exists a weight function
\(W_S\) on \(S\).
Lemma 1. (Locally Constant)Let \(S\) be a rectangular shape and suppose that \(\boldsymbol{supp }\hat{g} \subset S^*\), then \(g\) is locally
constant on \(S\). In other words, for any translation \(S'\) of \(S\), \[\|g\|_{L^\infty (S')} \leq \|g\|_{\sout{L}^1
(W_{S'})}\] for some weight function \(W_{S'}\) on \(S'\).
Proof. There exists a function \(\eta_{S^*}\) such that \(\eta_{S^*} \sim 1\) on \(S^*\) and is supported on \(cS^*\) and \(\check{\eta_{S^*}}\sim \frac{1}{|S|}\) on \(S\) and decays rapidly off \(S\). Thus, \(g(x)=g*\check{\eta_{S^*}}\). Therefore, for any \(x \in S'\), we have \[\begin{align} |g(x)| &=& |g *\check{\eta}_{S^*}(x)|\\ &\leq& \int
|g(x-y)||\check{\eta}_{S^*}(y)| dy\\ &\leq& \int |g|W_{S'}
\end{align}\] We put \(W_{S'}(y):\sim \max_{x \in S'}|\check{\eta}_{S^*}(x-y)|\) to be the weight function. Note that, \(W_{S'} \sim \frac{1}{|S|}\) on \(S+S'\sim S'\) and decays rapidly off \(S+S'\). ◻
Definition 3. Given a function \(f\) with \(\boldsymbol{supp }\hat{f} \subseteq N_{1/R}(\mathcal{P}^1)\), we define \(f_\tau\), the Fourier
restriction of \(f\) to \(\tau\), to be \[f_\tau: = f* \check{\chi}_\tau.\]
Definition 4. Let \(N\gg 1\) and \(R\gg 1\) such that \(N \leq R< N^2\). We say that a function \(f\) with
\(\boldsymbol{supp }\hat{f} \subset \mathbb{N}_{1/R}(\mathcal{P})\) satisfies \(\text{Cond}\) if \(f=\sum_{\gamma} f_\gamma\) such that each \(f_\gamma\) has fourier support on a cap \(\gamma\) of length \(1/N\) and for each \(\gamma\) there exists a real number \(a_\gamma\) such that \(\frac{a_\gamma}{100} \leq|f_\gamma| \leq a_\gamma\) on \(B_R\) and \(f_\gamma\) decays rapidly off \(B_R\). We say that \(f\) satisfies \(\text{Cond}_0\) if for all \(\gamma\) we have either \(a_\gamma=1\) or \(a_{\gamma}=0\).
We shall first prove our main result for the special case in which \(f\) satisfies \(\text{Cond}_0\), and then extend it to the general case. Let \(f\)
satisfies \(\text{Cond}_0\). Define \(l_k=3^{-k}\). Then, \(l_{k-1}/l_k=3\) and \[R^{-1/2}=l_M <l_{M-1} <\cdots < l_1
<l_0=1.\] Let \(c\) be the smallest number such that \(l_c> N/R\). For \(1 \leq k \leq M-1\), We cut \(\mathcal{P}\) into caps \(\tau_k\) of length \(l_k\) and for \(c \leq k \leq M-1\), we cut \(\mathcal{P}\) into caps \(\omega_k\) of length \(l_k^{-1}R^{-1}\). Also, we cut \(\mathcal{P}\) into caps \(\theta\) of length \(R^{-1/2}\) and into caps \(\gamma\) of length \(1/N\). Given any cap \(\tau\), we define \[\begin{align} \lambda(\tau)&:=\#\{\gamma: \gamma \subset \tau, |f_\gamma|\sim 1\}, \\ \lambda(l_k)&:=\max_{\tau_k}\#\{\gamma \subset \tau_k: |f_\gamma|\sim 1 \text{ on }
B_R\}, \\
\lambda(l_k^{-1}R^{-1})&:=\max_{\omega_k}\#\{\gamma \subset \omega_k: |f_\gamma|\sim 1 \text{ on } B_R\}
\end{align}\]
Also, given a cap \(\theta\), we define \[\lambda(\theta)=\#\{\gamma \subset \theta: |f_\gamma|\sim 1 \text{ on }B_R\}.\]
For any \(k\) and any \(\tau_k \in \mathcal{P}\), we tile \(B_R\) by \(l_kR \times R\) tubes, \(U_{\tau_k}\), whose long axis is in the direction \(d(\tau_k)\). We call this set of tubes \(\mathbb{U}_{\tau_k}\). For \(U_{\tau_k}
\in \mathbb{U}_{\tau_k}\), let \(W_{U_k}\) be a weight function on \(U_{\tau_k}\).
Let \(\{\eta_k\}_{0 \leq k \leq M} \cup \{\eta_{l_k}\}_{0 \leq k \leq M}\) be a smooth partition of unity on \(B_1\) such that
\[\boldsymbol{supp }\eta_{l_k} \subseteq \left\{x: \frac{l_{k}}{2} \leq |x| \leq 2l_{k-1}\right\} \text{ for } 1 \leq k \leq M\]
\[\boldsymbol{supp }\eta_k \subseteq \left\{x: \frac{R^{-1}l_{k-1}^{-1}}{2} \leq |x| \leq 2R^{-1}l_{k}^{-1}\right\} \text{ for } 1 \leq k \leq M\] and \(\boldsymbol{supp }\eta_0 \subseteq
\left\{x: |x| \leq 2R^{-1}\right\}.\)
\(\check{\eta}_k(x)\sim R^{-2}l_k^{-2}\) on \(B_{Rl_{k}}\) and decays rapidly off \(B_{Rl_{k-1}}\) and \(\check{\eta}_{l_k}(x)\sim_K l_k^{2}\) on \(B_{l_{k-1}^{-1}}\) and decays rapidly off \(B_{l_{k}^{-1}}\)
\(\int |\check{\eta}_k| \sim 1\) and \(\int |\check{\eta}_{l_k}| \sim 1\)
In this paper, we shall look at the blurred version of \(f\) at many different scales. For \(1\leq k \leq M\), define \(g_k=\sum_{\tau_k} |f_{\tau_k}|^2\)
and define \(g=\sum_{\theta}|f_\theta|^2\) and \(g_{\tau}=\sum_{\theta \subset \tau}|f_\theta|^2\). Then, \(g_k\) is basically \(|f|^2\) blurred at scale \(l_k^{-1}\), \(g\) is \(f\) blurred at scale \(R^{1/2}\) and \(g_\tau\) is \(|f_\tau|^2\) blurred at scale \(R^{1/2}\). Moreover, we can view \(g\) as the sum of the characteristic functions
of a bunch of \(R \times R^{1/2}\) tubes.
Then, intuitively \(|U_{\tau_k}|\|f_{\tau_k}\|_{\sout{L}^2(W_{U_k})}^2\sim |U_{\tau_k}|\|g_{\tau_k}\|_{\sout{L}^1(W_{U_k})}\) counts the number of \(R\times R^{1/2}\) tubes contained in
\(U_{\tau_k}\). Now, let’s prove some properties of \(\|f\|^2_{\sout{L}^2(W_{U_{\tau_k})}}\).
Lemma 2. (Local Orthogonality)\[\|g_{\tau_k}\|_{\sout{L}^1(W_{U_{\tau_k})}}\sim \|f_{\tau_k}\|_{\sout{L}^2(W_{U_k})}^2 \lesssim \begin{cases}
\lambda(l_k)\lambda(l_k^{-1}R^{-1}) \text{ if } k \geq c\\ \lambda(l_k)\text{ if } k < c
\end{cases}\]
Proof. By Plancherel’s theorem, we have \[\begin{align} \int |f_\theta|^2 W_{U_\tau} &=& \int \hat{f_\theta}(\xi) \hat{\bar{f_\theta}}*\hat{W}_{U_{\tau_k}}(\xi) \, d\xi\\ &=&\sum_{\omega \subset
\theta} \sum_{\omega' \subset \theta} \int \hat{f_\omega}(\xi) \hat{\bar{f_{\omega'}}}*\hat{W}_{U_{\tau_k}}(\xi) \, d\xi\\
\end{align}\] Note that the summand from \((\omega, \omega')\) is non-zero only if \(\omega \cap (-\omega' +U_{\tau_k}) \not=\emptyset\). Thus, we need \(|c(\omega)-c(\omega')| \leq R^{-1}l_k^{-1}\). In this case, we say \(\omega \sim \omega'\). As \(l(\omega )\geq R^{-1}l_k^{-1}\) for each \(\omega\) there is \(\sim 1\) many \(\omega'\) such that \(\omega \sim \omega'\). Thus, \[\begin{align} \int |f_\theta|^2 W_{U_\tau} &=&\sum_{\omega \subset \theta} \sum_{\omega' \sim \omega} \int \hat{f_\omega}(\xi) \hat{\bar{f_{\omega'}}}*\hat{W}_{U_{\tau_k}}(\xi) \, d\xi\\ &=&\sum_{\omega
\subset \theta} \sum_{\omega' \sim \omega} \int f_\omega\bar{f_{\omega'}}W_{U_{\tau_k}} \text{ by Plancherel }\\ &\lesssim &\sum_{\omega \subset \theta} \int |f_\omega|^2W_{U_{\tau_k}} \text{ by Cauchy-Schwartz}\\
\end{align}\]
Next, we prove a slightly generalized version of the bilinear restriction.
Lemma 3. (Bilinear Restriction)Let \(T\) be a \(L_1\) by \(L_2\) rectangle. Suppose that \(d(\tau_1)\) is
perpendicular to the side of length \(L_1\) and \(d(\tau_1)\) is perpendicular to the side of length \(L_2\). Let \(\omega_1\) be caps of length \(\geq L_1^{-1}\) and \(\omega_2\) be caps of length \(\geq L_2^{-1}\) Then, \[\int_{T}|f_{\tau_1}|^2|f_{\tau_2}|^2 \lesssim \int \left(\sum_{\omega_1 \subset \tau_1} |f_{\omega_1}|^2\right) \left(\sum_{\omega_2 \subset \tau_2} |f_{\omega_2}|^2\right)W_T.\]
Proof. The proof is essentially a slight variation of the bilinear restriction proof. Let \(\eta_T\) be a smooth cut-off function on \(T\) that has Fourier support in \(T^*\). Then, \[\begin{align} && \int_{T} |f_{\tau_1}|^2 |f_{\tau_2}|^2 \\ & \lesssim & \int |f_{\tau_1}|^2 |f_{\tau_2}|^2 \eta_T\\ & = & \int |\hat{f}_{\tau_1}|^2
|\hat{f}_{\tau_2}|^2 \eta_T \text{ by Plancherel }\\ & \leq & \sum_{\omega_1} \sum_{\omega_1'} \sum_{\omega_2} \sum_{\omega_2'} \int \hat{f}_{\omega_1}*\hat{\bar{f}}_{\omega_1'}(\xi) \hat{f}_{\omega_2}\ast
\hat{\bar{f}}_{\omega_2'}\ast \hat{\eta}_T(\xi)
\end{align}\] Note that \(\hat{f}_{\omega_1}*\hat{\bar{f}}_{\omega_1'}\) has support in \(\omega_1-\omega_1'\) and \(\hat{f}_{\omega_2}*\hat{\bar{f}}_{\omega_2'}*\hat{\eta}_T\) has support in \(\omega_2-\omega_2'+T\). Thus, in order for \[\int
\hat{f}_{\omega_1}*\hat{\bar{f}}_{\omega_1'}(\xi) \hat{f}_{\omega_2}\ast \hat{\bar{f}}_{\omega_2'}\ast \hat{\eta}_T(\xi)\not=0,\] we need \[(\omega_1-\omega_1') \cap
(\omega_2-\omega_2'+T)\not=\emptyset.\]
Let \((\xi_1,\xi_1^2),(\xi_1',\xi_1'^2), (\xi_2,\xi_2^2), (\xi_2',\xi_2'^2)\) be the center of \(\omega_1, \omega_1', \omega_2, \omega_2'\). Note that \(\omega_1-\omega_1'\) is a \(R^{-1/2}L_2 \times R^{-1}\) tube centering at \((\xi_1-\xi_1', \xi_1^2-\xi_1'^2)\) and \(\omega_2-\omega_2'+S\) is a \(R^{-1/2}L_2 \times R^{-1/2}\) tube centering at \((\xi_2-\xi_2', \xi_2^2-\xi_2'^2)\) Then, we need \[|(\xi_1-\xi_1')-(\xi_2-\xi_2')| \leq R^{-1/2}L_2\]\[|(\xi_1^2-\xi_1'^2)-(\xi_2^2-\xi_2'^2)| \leq R^{-1/2}L_1.\]
Thus, \[\begin{align} R^{-1/2}L_1 &\geq& |(\xi_1^2-\xi_1'^2)-(\xi_2^2-\xi_2'^2)| \\ &=&|(\xi_1+\xi_1'-\xi_2-\xi_2')(\xi_2-\xi_2')+(\xi_1+\xi_1')((\xi_1-\xi_1')-(\xi_2-\xi_2'))|
\\ &\geq&|(\xi_1+\xi_1'-\xi_2-\xi_2')(\xi_2-\xi_2')|-|(\xi_1+\xi_1')((\xi_1-\xi_1')-(\xi_2-\xi_2'))| \\ &\geq&|(\xi_1+\xi_1'-\xi_2-\xi_2')(\xi_2-\xi_2')|-C R^{-1/2}L_2 \\
\end{align}\] Also, note that \((\xi_1+\xi_1'-\xi_2-\xi_2') \gtrsim 1\) as \(\Gamma_1\) and \(\Gamma_2\) are \(\sim
1\) distance apart. Thus, we have \(|\xi_2-\xi_2'| \lesssim R^{-1/2}L_1\). In this case, we say that \(\omega_2' \in G(\omega_2)\). If we fix \(\omega_1,\omega_2, \omega_2'\), as \(|(\xi_1-\xi_1')-(\xi_2-\xi_2')| \leq R^{-1/2}L_2\), there is \(\lesssim 1\) choice for \(\omega_1'\). In this case, we call \(\omega_1' \in G(\omega_1,\omega_2, \omega_2')\). Thus, \[\begin{align} & \int_{T} |f_1|^2 |f_2|^2 \\ & \leq
\sum_{\omega_2} \sum_{\omega_2' \in G(\omega_2)}\sum_{\omega_1} \sum_{\omega_1' \in G(\omega_1,\omega_2, \omega_2')} \int \hat{f}_{\omega_1}*\hat{\bar{f}}_{\omega_1'}(\xi) \hat{f}_{\omega_2}\ast \hat{\bar{f}}_{\omega_2'}\ast
\hat{\eta}_T(\xi)\\ & = \sum_{\omega_2} \sum_{\omega_2' \in G(\omega_2)}\sum_{\omega_1} \sum_{\omega_1' \in G(\omega_1,\omega_2, \omega_2')} \int f_{\omega_1} \bar{f}_{\omega_1'} f_{\omega_2} \bar{f}_{\omega_2'} \eta_T \text{ by
Plancherel}\\ & = \sum_{\omega_2} \sum_{\omega_2' \in G(\omega_2)}\sum_{\omega_1} \sum_{\omega_1' \in G(\omega_1,\omega_2, \omega_2')} \int (|f_{\omega_1}|^2+ |{f}_{\omega_1'}|^2) f_{\omega_2} \bar{f}_{\omega_2'} \eta_T\\ & =
\sum_{\omega_2} \sum_{\omega_2' \in G(\omega_2)} \int_S (\sum_{\omega_1} |f_{\omega_1}|^2) f_{\omega_2} \bar{f}_{\omega_2'} \eta_T \text{ as }|G(\omega_1,\omega_2, \omega_2')| \lesssim 1 \\ & = \int (\sum_{\omega_1} |f_{\omega_1}|^2)
(\sum_{\omega_2} |f_{\omega_2}|^2)\eta_T \text{ as }|G(\omega_2)| \lesssim 1 \qedhere
\end{align}\] ◻
Next, we recall some high-low lemmas from [13] that will be useful in our proof.
Proof. It is enough to prove that \(|f_\tau|^2*\check{\eta}_{\leq r} \lesssim \sum_{\tau'\subset \tau} |f_{\tau'}|^2 *\check{\eta}_{\leq r}\) whenever \(r<l(\tau')<l(\tau)\). Note, we can write \[|f_{\tau}|^2*\check{\eta}_{\leq r}=\sum_{\tau_1'} \sum_{\tau_2'} (f_{\tau_1'}\overline{f_{\tau_2'}})*\check{\eta}_{\leq r}\]
Note that \((f_{\tau_1'}\overline{f_{\tau_2'}})*\check{\eta}_{\leq r}\equiv 0\) if \((\tau_1' -\tau_2') \cap B(0,r)=\emptyset\). Thus, for each \(\tau_1'\) there are only finitely many \(\tau_2'\) such that \((f_{\tau_1'}\overline{f_{\tau_2'}})*\check{\eta}_{\leq r} \neq 0\). Thus, by
Cauchy-Schwartz, \[|f_{\tau}|^2*\check{\eta}_{\leq r}\lesssim \sum_{\tau'\subset \tau} |f_{\tau'}|^2 *\check{\eta}_{\leq r}.\] The proof for the \(\check{\eta}_{\sim r}\) case is
basically the same. ◻
The following lemma essentially states that the low-frequency components have small \(L^\infty\) norms.
Lemma 5. (Low Lemma) Let \(R^{-1} \leq r \leq R^{-1/2}\). \[|g_{\tau}*\check{\eta}_{\leq r}|\lesssim \begin{cases} \lambda(\tau) \text{ if }r\leq 1/N\\ \lambda(\tau)rN \text{ if
}r>1/N \end{cases}\]
Proof. Note that \(\check{\eta}_{\leq r}(x) \sim r^2\) on a ball of radius \(1/r\). Note that \(||f_\theta|^2*\check{\eta}_{\leq r}|\) are
locally contained on \(R \times 1/r\) tubes \(U\). Thus, \[\||f_\theta|^2 * \check{\eta}_{\leq r}(x)\|_{\infty}\sim \max_{U}\||f_\theta|^2 * \check{\eta}_{\leq
r}(x)\|_{L^1(U)} \lesssim \begin{cases} \lambda_0 \text{ if }r\leq 1/N\\ \lambda_0rN \text{ if }r>1/N \end{cases}.\] Note that the number of \(\theta\)’s is \(\lambda(\tau)/\lambda_0\) so that \[|g*\check{\eta}_{\leq r}|\lesssim \begin{cases} \lambda(\tau) \text{ if }r\leq 1/N,\\ \lambda(\tau)rN \text{ if }r>1/N. \end{cases} \qedhere\] ◻
The following lemma exploits the transversality for the high-frequency part.
Lemma 6. (high-low)Let \(\tau_0\) be a cap. Let \(R^{-1}<s<R^{-1/2}\). Then, \[\int |g_{\tau_0}*\check{\eta}_{\sim s} |^2 \lesssim
\sum_{\substack{\tau\subset \tau_0\\ l(\tau)=(sR)^{-1}}}\sum_{U \in \mathbb{U}_\tau}|U|\|f_\tau\|^4_{\sout{L}^2(U)}.\]
Proof. Define \(g_{\tau}=\sum_{\theta \subset \tau} |f_\theta|^2\). Then, \(g_{\tau_0}=\sum_{\tau\subset \tau_0}g_\tau\). Note that the support of \(\hat{g_\tau}\) is contained in \(\cup_{\theta \subset \tau} \theta-\theta\) which is a \(R^{-1/2} \times R^{-1/2}l(\tau)\) rectangle in the same direction as
\(\tau\). Note that unless \(dist(\tau,\tau')\lesssim l(\tau)\), \[\hat{g}_\tau \cap \hat{g}_{\tau'} \cap \{\xi: |\xi|>s\}=\emptyset\] so \(\int |g_\tau * \check{\eta}_{\sim s}||g_{\tau'} * \check{\eta}_{\sim s}|=0\). Thus, \[\begin{align} \int_{B_R} |g*\check{\eta}_{\sim s} |^2 &=\int_{B_R} |\sum_{\tau}
g_{\tau}*\check{\eta}_{\sim s} |^2 \\ &\lesssim \sum_{\tau}\int_{B_R}| g_{\tau}*\check{\eta}_{\sim s} |^2 \\ &\lesssim \sum_{\tau}\sum_{U \subset \mathbb{U}_{\tau}}\int_{U}| g_{\tau}*\check{\eta}_{\sim s} |^2 \\ &\lesssim \sum_{\tau}\sum_{U \in
\mathbb{U}_{\tau}}|U|\|g_\tau*\check{\eta}_{\sim s}\|^2_{\sout{L}^2(U)}\\ &\lesssim \sum_{\tau}\sum_{U \in \mathbb{U}_{\tau}}|U|\|g_\tau*\check{\eta}_{\sim s}\|^2_{\sout{L}^1(W_U)} \text{ as }g_\tau*\check{\eta}_{\sim s} \text{ is locally constant on
}U\\ &\sim \sum_{\tau}\sum_{U \in \mathbb{U}_{\tau}}|U|\|f_\tau\|^4_{\sout{L}^2(W_U)} \text{ by local orthogonality} \qedhere
\end{align}\] ◻
In this section, we prove Theorem 1. By standard reductions, it suffices to establish the following lossless small-cap decoupling estimate.
Theorem 3 (Lossless small-cap decoupling). Suppose that \(\sqrt{R}(\log N)^{10000} \leq N \leq R\) and Let \(f\) be a function with \(f=\sum_\gamma
f_\gamma\) with \(\alpha_\gamma/100 \leq |f_\gamma| \leq \alpha_\gamma\) on \(B_R\) for some \(\alpha_\gamma \in \mathbb{R}\). Then, \[\|f\|_{L^6(B_R)}\lesssim \left(\sum_{\gamma} \|f_\gamma\|^2_{L^6(B_R)}\right)^{1/2}\left(\frac{N^2}{R}\right)^{1/6}.\]
The proof of Theorem 3 is divided into two parts. First, we reduce matters to the special case in which \(f\) satisfies \(\text{Cond}_0\). We then prove this special case.
In order to prove the Theorem 3, we first prove that the general result follows from a special case when \(f\) satisfies \(\text{Cond}_0\). Define the superlevel set \[U_a(f):=\{x \in B_R: a/2 \leq |f(x)| \leq a \}.\]
Lemma 7. Suppose that \(f\) satisfies \(\text{Cond}_0\), then \[|U_a(f)|a^6 \lesssim \log\left(\frac{\lambda}{a}\right)^{O(1)}\frac{a}{\lambda}
N^2R\lambda^3.\]
Now let’s prove that Theorem 3 follows from Lemma 7.
Definition 5. We say that a function \(f\) satisfies condition \(\operatorname{Cond}_0(\lambda)\) if \(f=\sum_{\gamma}f_\gamma\) such that \(\frac{1}{100}\leq |f_r(x)| \leq 1\) for \(x \in B_R\) and \(f_r\) decays rapidly off \(B_R\) or \(f_\gamma \equiv 0\) and we let \(\lambda\) be the number of non-zero \(\gamma\)’s. We say that a function \(f\) satisfies \(\operatorname{Cond}_1(\alpha,\lambda)\) if \(f/\alpha\) satisfies \(\operatorname{Cond}_0(\lambda)\).
By lemma 7 and a rescaling argument, if \(f\) satisfies \(\text{Cond}_1(\alpha,\lambda)\), then
\[\label{con1} |U_a(f)|a^6 \lesssim \log\left(\frac{\alpha\lambda}{a}\right)^{O(1)} \frac{a}{\alpha\lambda}N^2R\alpha^6\lambda^3.\tag{11}\]
Definition 6. We say that \(f\) satisfies \(\text{Cond}_2(Q,S)\) if there exists a set \(J \subset \mathbb{Z}\) with \(|J|=S\) such that \(f=\sum_J f_j\) and each \(f_j\) satisfied \(\text{Cond}_1(\alpha_j,\lambda_j)\) such that \(Q/(100)^3 \leq \alpha_j^6\lambda_j^2 \leq Q\) and \(100^{j-1} \leq \alpha_j\lambda_j \leq 100^{j}\).
Lemma 8. Let \(J \subset \mathbb{Z}\). If \(h_k=2^k \chi_{S_k}\), then \[\|\sum_{k \in J} h_k\|_r^r \lesssim \sum_k \|h_k\|_r^r\] for any \(r\geq 1\). (Note that we do not require \(S_k\) to be disjoint.)
Proof of Theorem 3. First, we group all the \(f_\gamma\) with similar \(\alpha_\gamma\)’s together. We write
\(f=\sum_{j\in J} f_j\) such that each \(f_j\) satisfy \(\operatorname{Cond}_1(100^j,\lambda_j)\) for some \(\lambda_j\).
Then we group the \(f_j\)’s with similar \(L_2\) norms. Define \[K_k:=\{j: 100^{k-1}\leq \alpha_j^2\lambda_j \leq 100^k\} \text{ and } f_k=\sum_{j \in
K_k}f_{j}.\] Note that for each \(j \in K_k\), we have \(f_j\) satisfies \(\text{Cond}_1(\alpha_j,\lambda_j)\) with \(\alpha_j=100^j\) and \(100^{k-j-1}\leq \alpha_j\lambda_j \leq 100^{k-j}\). Then, each \(f_k\) satisfy \(\operatorname{Cond}_2(100^{3k},
|K_k|)\) and \(f=\sum_k f_k\). Thus, we can apply proposition 5 to \(f\) to get the result we want. ◻
The goal of this section is to prove the Lemma 7, which follows quickly from the following Lemma.
Lemma 9. There exists a constant \(c_0\) such that \[|U_a|a^6 \lesssim (\log N)^{c_0} \max\left(\frac{a^2}{\lambda^2},\frac{R}{N^2}\right)N^2R\lambda^3 .\] We can put \(c_0\) to be \(100\), say. Moreover, suppose that \(a >\lambda (\log N)^{-100}\), Then, \[|U_a|a^6 \lesssim
\log\left(\frac{\lambda}{a}\right)^{O(1)}\frac{a}{\lambda} N^2R\lambda^3\]
First, we derive the first part of the about lemma as a quick corollary from the superlevel bound from the wave envelop paper [13]. The second part of
the lemma is our key contribution.
Let’s recall a superlevel set estimate by Guth and Maldague that we heavily rely on in this paper.
Remark 7. Note that this is not exactly what was stated in [13], they had \(\lesssim_\epsilon R^\epsilon\)
instead of \(\lesssim(\log N)^{O(1)}K^{O(1)}\) because in their write up they put \(K\) to be \(R^\epsilon\) but they proof actually gives \(\lesssim(\log N)^{O(1)}K^{O(1)}\).
The above theorem implies the following corollary.
Corollary 1. There exists a constant \(c_0\) such that if \(f\) satisfy \(\text{Cond}_0\), then \[|U_a^{\lambda_0}|a^6
\lesssim (\log N)^{c_0} \max\left(\frac{\lambda_0}{R^{-1/2}N}\frac{a^2}{\lambda^2},\frac{R}{N^2}\right)\lambda^3 N^2R.\] We can put \(c_0\) to be \(100\), say.
Proof. Note by local orthogonality, \(\|g_{\tau_k}\|_{\sout{L}^1(W_{U_{\tau_k}})} \sim \|f_{\tau_k}\|_{\sout{L}^2(U_k)}^2\). If \(l_k<N/R\), \[\begin{align} && \sum_{\tau_k} \sum_{\substack{U_k \\ \|g_{\tau_k}\|^{1/2}_{\sout{L}^1(W_{U_{\tau_k}})} \geq \frac{K^{-1}a \lambda(l_k)}{\lambda} }}|U_k|\|g_{\tau_k}\|^{2}_{\sout{L}^1(W_{U_{\tau_k}})}\\
&\lesssim&\max_{\tau_k, U_{\tau_k}} \|f_{\tau_k}\|_{\sout{L}^2(U_k)}^2\sum_{\tau_k} \sum_{\substack{U_k \\ \|g_{\tau_k}\|^{1/2}_{\sout{L}^1(W_{U_{\tau_k}})}\geq \frac{K^{-1}a \lambda(l_k)}{\lambda}
}}|U_k|\|g_{\tau_k}\|_{\sout{L}^1(W_{U_{\tau_k}})}\\ &\lesssim&\max_{\tau_k, U_{\tau_k}} \|f_{\tau_k}\|_{\sout{L}^2(U_k)}^2\sum_{\tau_k} \|f_{\tau_k}\|^2_{L^2(B_R)}\\ &\lesssim&\max_{\tau_k, U_{\tau_k}}
\|f_{\tau_k}\|_{\sout{L}^2(U_k)}^2\|f\|^2_{L^2(B_R)}\\
&\lesssim&\lambda(l_k)\lambda(l_k^{-1}R^{-1})\|f\|^2_{L^2(B_R)}\\ &\lesssim&\lambda_0(l_kR^{1/2})(l_k^{-1}R^{-1}N)\|f\|^2_{L^2(B_R)}\\
\end{align}\] as \(\lambda(l_k)\lesssim \lambda_0(l_kR^{1/2})\) and \(\lambda(l_k^{-1}R^{-1})\lesssim (l_k^{-1}R^{-1}N)\). Thus, if \(l_k<N/R\), we
have \[\sum_{\tau_k} \sum_{\substack{U_k \\ \|g_{\tau_k}\|^{1/2}_{\sout{L}^1(W_{U_{\tau_k}})}\geq \frac{K^{-1}a \lambda_2(l_k)}{\lambda_2} }}|U_k|\|g_{\tau_k}\|^{2}_{\sout{L}^1(W_{U_{\tau_k}})}\lesssim \lambda_0R^{-1/2}N\lambda
R^2.\] On the other hand, if \(l_k \geq N/R\), then \[\begin{align} && a^2\sum_{\tau_k} \sum_{\substack{U_k \\ \|g_{\tau_k}\|^{1/2}_{\sout{L}^1(W_{U_{\tau_k}})} \geq \frac{K^{-1}a
\lambda(l_k)}{\lambda} }}|U_k|\|g_{\tau_k}\|^{2}_{\sout{L}^1(W_{U_{\tau_k}})}\\ &\lesssim&K^2\lambda^2\frac{1}{\lambda(l_k)^2}\sum_{\tau_k} \sum_{U_k}|U_k|\|g_{\tau_k}\|^{3}_{\sout{L}^1(W_{U_{\tau_k}})}\\
&\lesssim&K^2\lambda^2\frac{1}{\lambda(l_k)^2}\max_{\tau_k, U_{\tau_k}} \|f_{\tau_k}\|_{\sout{L}^2(U_k)}^4\sum_{\tau_k} \sum_{\substack{U_k \\ \|S_{U_{\tau_k}}\|_{\sout{L}_2} \geq \frac{R^{-\epsilon}a \lambda(l_k)}{\lambda}
}}|U_k|\|g_{\tau_k}\|_{\sout{L}^1(W_{U_{\tau_k}})}\\ &\lesssim&K^2\lambda^3R^2.\\
\end{align}\] where in the last line we used that \[\|f_{\tau_k}\|^2_{\sout{L}^2(U_k)}\lesssim \lambda(l_k)\] if \(l_k \geq N/R\) using local orthogonality. Thus, \[\begin{align} |U_a|a^6 &\lesssim (\log N)^{O(1)} K^{O(1)} \max(a^2\lambda_0 R^{-1/2}N\lambda R^2, \lambda^3 R^2)\\ &=(\log N)^{O(1)}
K^{O(1)}\max\left(\frac{\lambda_0}{R^{-1/2}N}\frac{a^2}{\lambda^2},\frac{R}{N^2}\right)\lambda^3 N^2R. \qedhere
\end{align}\] ◻
In particular, summing up the different dyadic choices of \(\lambda_0\leq \frac{N}{\sqrt{R}}\), we have the following corollary.
Corollary 2. There exists a constant \(c_0\) such that that if \(f\) satisfy \(\text{Cond}_0\) then \[|U_a|a^6
\lesssim (\log N)^{c_0} \max\left(\frac{a^2}{\lambda^2},\frac{R}{N^2}\right)\lambda^3 N^2R.\] We can put \(c_0\) to be \(100\), say.
To deal with the second part of lemma 7, we pigeonhole on \(\lambda(\theta)\) and write \[f=\sum_{\substack{1\leq\lambda_0 \leq R^{-1/2}N\\ dyadic}} f^{\lambda_0}\] with each \(f^{\lambda_0}\) has \(\lambda_0/2\leq\lambda(\theta)\leq\lambda_0\).
Define
As \(1+ \frac{1}{2^2}+\frac{1}{3^2}+\cdots \lesssim 1\) and the scale for \(\lambda_0\) is dyadic, we have \[\sum_{1\leq \lambda_0 \leq R^{-1/2}N}
\frac{1}{(\log (R^{-1/2}N/\lambda_0))^2} \sim 1+\frac{1}{2^2}+\frac{1}{3^2}+\cdots +\frac{1}{(\log R^{-1/2}N)^2}\lesssim 1.\]
From now on in this subsection, we shall focus on the case when \(a >\lambda (\log N)^{-100}\) and \(\lambda_0>R^{-1/2}N(\log N)^{-100}\). We prove the following key lemma, which
would immediately imply the second part of Lemma 9 by summing over all the dyadic \(\lambda_0\)’s.
Lemma 10. Suppose that \(a >\lambda (\log N)^{-100}\) and \(\lambda_0>R^{-1/2}N(\log N)^{-100}\). Then, \[|U_a|a^6 \lesssim
\left((\log\left(\frac{\lambda}{a}\frac{NR^{-1/2}}{\lambda_0}\right)\right)^{O(1)}\frac{a}{\lambda}\frac{NR^{-1/2}}{\lambda_0} N^2R\lambda^3\]
Lemma 10 follows from two key lemmas: the broad estimate (see Lemma 11) and the asymmetric estimate (see Lemma 12), which both estimate the size of the intersection of the superlevel set of \(f_{\Sigma_1}\) and \(f_{\Sigma_2}\). The
broad estimate deals with the case when \(\Sigma_1\) and \(\Sigma_2\) have the same length, and the length is similar to the distance between the two caps, and the asymmetric estimate deals
with the case when the length of the shorter cap is much smaller than the distance between the two caps.
Let \(\Sigma_1\) and \(\Sigma_2\) be two caps. Within both proofs, we shall use \(\lambda_i\) to denote \(\lambda(\Sigma_i)\) and use \(l_i\) to denote \(l(\Sigma_i)\) for \(i=1,2\). Define \[U_{a,b}(f_1,f_2):=\{x\in B_R: |f_1|>a \text{ and }|f_2|>b\}\] to be the joint superlevel set of \(f_1\) and \(f_2\). Define \(V(k,\beta):=\{x: g_k \gtrsim \beta\}\) and \(V(\beta):=\{x: g \gtrsim \beta\}\) to be the superlevel set of the blurred versions of \(f\). Define \(V'(k,\beta):=\{x: g_k \sim \beta\}\) and \(V'(\beta):=\{x: g \sim \beta\}\).
The overall strategy of the proof for the broad estimate follows that of [13], with the key additional ingredient being a more careful control on the
number of scales that can contribute to the high–low estimate. To bound \(U_{a,b}(f_{\Sigma_1},f_{\Sigma_2})\), we shall first bound the high frequency part of \(g_k\), which can be viewed
as the \(|f|^2\) blurred at scale \(l_k^{-1}\). Then, we shall see that \(U_{a,b}(f_{\Sigma_1},f_{\Sigma_2})\) is contained in \(V(k,\beta)\) the superlevel set of \(g_k\) for a big enough \(\beta\). Then, we shall show that when \(\beta\) is big enough,
\(g_k\) is necessarily dominated by its high-frequency part. Finally, we related the size of \(U_{a,b}(f_1,f_2)\) with that of \(V(k,\beta)\) using bilinear
restriction and the fact that the Fourier support of \(f_1\) and \(f_2\) are transversal.
Lemma 11. (Broad Estimate)Suppose \(\Sigma_1\) and \(\Sigma_2\) are caps of length \(l\) and are \(l\) distance
apart also suppose that \(a> \lambda(\Sigma_1)(\log N)^{-4000}\), \(b> \lambda(\Sigma_2)(\log N)^{-4000}\), \(\lambda_0> NR^{-1/2}(\log N)^{-100}\)
then \[U_{a,b}(f_{\Sigma_1},f_{\Sigma_2}) \lesssim \log\left(\frac{\lambda(\Sigma_2)}{b} \frac{NR^{-1/2}}{\lambda_0}\right)\frac{N^2R(\lambda(\Sigma_1)+\lambda(\Sigma_2))}{a^2b^2}\frac{\lambda_0}{NR^{-1/2}}.\]
Proof. By a rescaling argument, it suffices to prove the case where \(l\sim 1\). Now, let’s get an estimate of the high-dominated part.
Proposition 8. (Bounding High dominated part)For any \(0 \leq k<M\), \[\int| \sum_{\tau_k} |f_{\tau_k}|^2*\check{\eta}_{\geq R^{-1}l_k^{-1}}(x)|^2dx \lesssim
K^{O(1)}(M+1-k)\sum_{m=k}^M \sum_{\tau_m}|U_m|\|f_{\tau_m}\|^2_{\sout{L}^4(U_m)}.\]
Proof. Let \(\eta_{\sim r}\) be the frequency support on the annulus \(\{\xi: r/K \leq |\xi| \leq r\}\) and is about \(r^2\) on a ball of radius
\(\sim 1/r\) and decays rapidly off that ball. \[\begin{align} \int| \sum_{\tau_k} |f_{\tau_k}|^2*\check{\eta}_{\geq R^{-1}l_k^{-1}}(x)|^2dx &\sim& \sum_{m=k}^M \int| \sum_{\tau_m}
|f_{\tau_m}|^2*\check{\eta}_{\sim l_m^{-1}R^{-1}}(x)|^2dx\\ &+& \sum_{m=k}^M \int| \sum_{\tau_m} |f_{\tau_m}|^2*\check{\eta}_{\sim l_m}(x)|^2dx.
\end{align}\] By high-low lemma 6, we can bound \[\begin{align} &&\int| \sum_{\tau_m} |f_{\tau_m}|^2*\check{\eta}_{\sim l_m^{-1}R^{-1}}(x)|^2dx\\
&\lesssim &\int| \sum_{\theta} |f_{\theta}|^2*\check{\eta}_{\sim l_m^{-1}R^{-1}}(x)|^2dx \text{ by lemma }\ref{break}\\ &\sim& K^{O(1)}\sum_{\tau_m}\sum_{U_{\tau_m}} |U_{\tau_m}| \|f_{\tau_m}\|^4_{\sout{L}^2(U_{\tau_m})}.
\end{align}\] Also note that for \(m \geq k\), \[\begin{align} &&\int| \sum_{\tau_k} |f_{\tau_k}|^2*\check{\eta}_{\sim l_m}(x)|^2dx\\ &\sim & K^{O(1)} \int| \sum_{\tau_m}
|f_{\tau_m}|^2*\check{\eta}_{\sim l_m}(x)|^2dx\\ &\lesssim & K^{O(1)}\sum_{\tau_m} \int |f_{\tau_m}|^4dx \text{ by disjoint support in high frequency}\\ &\lesssim & K^{O(1)}\sum_{\tau_m} \int| \sum_{\theta \subset \tau_m}|f_\theta|^2|^2dx
\text{ by Cordoba }L^4 \text{ estimate \cite{cor77}}\\
\end{align}\] Let’s bound \(\int| \sum_{\theta \subset \tau_m}|f_\theta|^2|^2dx\). Note that \[\int| \sum_{\theta \subset \tau_m}|f_\theta|^2|^2dx=\int| \sum_{\theta \subset
\tau_m}|f_\theta|^2*\check{\eta}_{ \leq l_m^{-1}R^{-1}}|^2dx+\sum_{n=m}^M \int| \sum_{\theta \subset \tau_m}|f_\theta|^2*\check{\eta}_{ \sim l_n^{-1}R^{-1}}|^2dx.\] By the low lemma 5
and orthogonality, we have \[\sum_{\theta\subset \tau_m}|f_\theta|^2* \check{\eta}_{s \leq l_m^{-1}R^{-1}}(x) \sim \sum_{U_m} 1_{U_m} \|f_{\tau_m}\|_{\sout{L}^2(U_m)}^2\] so \[\int|\sum_{\theta
\subset \tau_m}|f_\theta|^2*\check{\eta}_{s \leq l_m^{-1}R^{-1}}|^2dx\lesssim K^{O(1)}\sum_{U_{\tau_m}} |U_{\tau_m}| \|f_{\tau_m}\|^4_{\sout{L}^2(U_{\tau_m})}.\] Finally, note that \[\begin{align} &&\int|
\sum_{\theta \subset \tau_m}|f_\theta|^2*\check{\eta}_{s \sim l_n^{-1}R^{-1}}|^2dx\\ &\lesssim & K^{O(1)} \int| \sum_{\tau_n \subset \tau_m}\left(\sum_{\theta \subset \tau_n}|f_\theta|^2\right)*\check{\eta}_{s \sim l_n^{-1}R^{-1}}|^2dx\\
&\lesssim & K^{O(1)} \sum_{\tau_n \subset \tau_m}\sum_{U_{\tau_n}} |U_{\tau_n}| \|f_{\tau_n}\|^4_{\sout{L}^2(U_{\tau_n})} \text{ by lemma }\ref{hl}\\
\end{align}\] Thus, we have \[\begin{align} & \int| \sum_{\tau_k} |f_{\tau_k}|^2*\check{\eta}_{\geq R^{-1}l_k^{-1}}(x)|^2dx \\ & \lesssim K^{O(1)}\sum_{m=k}^M\left(\sum_{\tau_m}\sum_{U_{\tau_m}} |U_{\tau_m}|
\|f_{\tau_m}\|^4_{\sout{L}^2(U_{\tau_m})}+\sum_{n=m}^M \sum_{\tau_n }\sum_{U_{\tau_n}} |U_{\tau_n}| \|f_{\tau_n}\|^4_{\sout{L}^2(U_{\tau_n})} \right)\\ & \lesssim K^{O(1)}(M+1-k)\sum_{m=k}^M\sum_{\tau_m}\sum_{U_{\tau_m}} |U_{\tau_m}|
\|f_{\tau_m}\|^4_{\sout{L}^2(U_{\tau_m})} \qedhere
\end{align}\] ◻
Next, we show that if \(a\) and \(b\) are big enough, then the joint superlevel set \(U_{a,b}(f_1,f_2)\) is contained in \(V(k,\beta)\) for a big enough \(\beta\) and show that when \(\beta\) is big enough, \(g\) is high-dominated.
Proposition 9. (Condition for high dominated) Suppose that \(a> \lambda_1(\log N)^{-4000}\), \(b> \lambda_2(\log N)^{-4000}\), \(\lambda_0> NR^{-1/2}(\log N)^{-100}\) and \(l_k\gg R^{-1/2}\frac{\lambda^2}{a^2}\frac{R^{-1/2}N}{\lambda_0}\), Then, we are in the high dominated case, i.e. \[|U_{a,b}(f_1,f_2)|a^2b^2 \lesssim \int_{B_R}| \sum_{\tau_k\subset \tau_1\cup \tau_2} |f_{\tau_k}|^2*\check{\eta}_{\geq R^{-1}l_k^{-1}}(x)|^2dx.\]
Proof. First, we show that \(U_a(f_1) \subset V(k,\beta,\Sigma_1)\) with \(\beta=\frac{a^2}{\# (\tau_k\subset \Sigma_1)}\). This just follows from Cauchy-Schwartz, as \(x \in U_a(f_1)\) implies that \(\sum_{\tau_k \subset \Sigma_1}|f_{\tau_k}(x)|^2 \geq \frac{a^2}{\# (\tau_k\subset \Sigma_1)}\).
Next, we show that for \(x \in V(k,\frac{a^2}{\# (\tau_k\subset \Sigma_1)},\Sigma_1)\), we have \[\sum_{\tau_k\subset \Sigma_1}|f_{\tau_k}(x)|^2\lesssim \sum_{\tau_k\subset
\Sigma_1}|f_{\tau_k}(x)|^2*\check{\eta}_{\geq R^{-1}l_k^{-1}}(x).\] This basically follows from the fact that the low-frequency part cannot have a big \(L^\infty\) norm. By lemma 4 and low lemma 5, \[\begin{align} |g_{k,\Sigma_1}*\check{\eta}_{\leq R^{-1}l_k^{-1}}(x)| \lesssim
\begin{cases}
\lambda_1 \text{ if }l_k \leq N/R \\ \lambda_1\lambda(l_k^{-1}R^{-1}) \text{ if }l_k >N/R\\ \end{cases}
\end{align}\] Note that \[\begin{align} \lambda_1 \#(\tau_k \subset \tau_1)\leq \lambda_1\frac{\lambda_1}{\lambda_0}&\leq \frac{\lambda_1^2}{R^{-1/2}N}(\log N)^{100}\\ &\leq \lambda_1^2(\log N)^{-9900}\\ &\ll
(\lambda_1 (\log N)^{-4000})^2 \\ &\ll a^2.
\end{align}\] Suppose that \(l_k<N/R\), then as \(l_k\gg R^{-1/2}\frac{\lambda_1^2}{a^2}\frac{R^{-1/2}N}{\lambda_0}\), \[\lambda_1\lambda(l_k^{-1}R^{-1})\# \tau_k \leq \frac{\lambda_1^2}{\lambda_0}(l_k^{-1}R^{-1}N)\ll \frac{\lambda_1^2}{\lambda_0}(R^{-1}N)R^{1/2}(a^2/\lambda_1^2)\frac{\lambda_0}{R^{-1/2}N}=a^2.\] Thus, in both cases \[|g_{k,\Sigma_1}*\check{\eta}_{\leq R^{-1}l_k^{-1}}(x)|\ll \frac{a^2}{\# (\tau_k\subset \Sigma_1)}.\] As \[g_{k,\Sigma_1}=g_{k,\Sigma_1}*\check{\eta}_{\leq
R^{-1}l_k^{-1}}(x)+g_{k,\Sigma_1}*\check{\eta}_{\geq R^{-1}l_k^{-1}}(x),\] so \(|g_{k,\Sigma_1}(x)\lesssim g_{k,\Sigma_1}*\check{\eta}_{\geq R^{-1}l_k^{-1}}(x)|\) if \(x \in
V(k,\frac{a^2}{\# (\tau_k\subset \Sigma_1)},\Sigma_1)\) as \(x \in U_a(f_1)\subseteq V(k,\frac{a^2}{\# (\tau_k\subset \Sigma_1)},\Sigma_1)\), the inequality holds when \(x \in
U_a(f_1)\). Similarly, \(x \in U_b(f_2)\) implies that \(|g_{k,\Sigma_2}(x)\lesssim g_{k,\Sigma_2}*\check{\eta}_{\geq R^{-1}l_k^{-1}}(x)|\) Now we first convert bounds for \(f_1\) and \(f_2\) to bounds for \(g_{k,\Sigma_1}\) and \(g_{k,\Sigma_2}\) using bilinear restriction lemma 3. \[\begin{align} |U_{a,a}(f_1,f_2)|a^4 &\leq \sum_{U_a \cap B_{l_k^{-1}}\not=\emptyset} \int_{B_{l_k^{-1}}}|f_1|^2|f_2|^2 \\ &\lesssim \sum_{U_a \cap
B_{l_k^{-1}}\not=\emptyset} \int_{B_{l_k^{-1}}}\left(\sum_{\tau_k \subset \Sigma_1} |f_{\tau_k}|^2 \right)\left(\sum_{\tau_k \subset \Sigma_2} |f_{\tau_k}|^2 \right),
\end{align}\] where the second line follows from bilinear restriction lemma 11. Next, we exploit the fact that \(g_{k,\Sigma_1}\), \(g_{k,\Sigma_2}\), \(g_{k,\Sigma_1}*\check{\eta}_{\geq R^{-1}l_k^{-1}}\) and \(g_{k,\Sigma_2}*\check{\eta}_{\geq R^{-1}l_k^{-1}}\) are basically constant on \(B_{l_k^{-1}}\). \[\begin{align} & \sum_{U_a \cap B_{l_k^{-1}}\not=\emptyset} |B_{l_k^{-1}}|\left\|\left(\sum_{\tau_k \subset \Sigma_1} |f_{\tau_k}|^2 \right)\left(\sum_{\tau_k \subset \Sigma_2}
|f_{\tau_k}|^2 \right)\right\|_{L^\infty(B_{l_k^{-1}})}\\ &\lesssim \sum_{U_a \cap B_{l_k^{-1}}\not=\emptyset} |B_{l_k^{-1}}|\left\|\left(\sum_{\tau_k \subset \Sigma_1} |f_{\tau_k}|^2 *\check{\eta}_{\geq R^{-1}l_k^{-1}}\right)\left(\sum_{\tau_k \subset
\Sigma_2} |f_{\tau_k}|^2 *\check{\eta}_{\geq R^{-1}l_k^{-1}}\right)\right\|_{L^\infty(B_{l_k^{-1}})}\\ &\lesssim \sum_{U_a \cap B_{l_k^{-1}}\not=\emptyset} |B_{l_k^{-1}}|\left\|\left(\sum_{\tau_k \subset \Sigma_1\cup \Sigma_2} |f_{\tau_k}|^2
*\check{\eta}_{\geq R^{-1}l_k^{-1}}\right)^2\right\|_{L^\infty(B_{l_k^{-1}})}\\ &\lesssim \sum_{U_a \cap B_{l_k^{-1}}\not=\emptyset} \left\|\sum_{\tau_k \subset \Sigma_1\cup \Sigma_2} |f_{\tau_k}|^2 *\check{\eta}_{\geq
R^{-1}l_k^{-1}}\right\|_{L^2(W_{B_{l_k^{-1}}})} \\ &\lesssim \int_{B_R}|\sum_{\tau_k\subset \tau_1 \cup \tau_2}|f_{\tau_k}|^2*\check{\eta}_{\geq R^{-1}l_k^{-1}}(x)|^2
\end{align}\] where the third line follows from Cauchy Schwartz, the fourth line follows by locally constant principle lemma 1 and the last line follows as
the tail of \(W_{B_{l_k^{-1}}}\) is rapidly decaying. ◻
Combining Propositions 8 and 9, we have \[|U_{a,b}(f_1,f_2)|a^2b^2 \leq
K^{O(1)}(M+1-k)\sum_{m=k}^M \sum_{\tau_m \subset \Sigma_1 \cup \Sigma_2}|U_{\tau_m}|\|f_{\tau_m}\|^4_{\sout{L}^2(U_{\tau_m})}\] with \(k\) chosen so that \(l_k=K'
R^{-1/2}\frac{\lambda^2}{a^2}\frac{R^{-1/2}N}{\lambda_0}\) for some big constant \(K'\). Note that \((M-k)\lesssim \log(\frac{\lambda^2}{a^2}\frac{R^{-1/2}N}{\lambda_0})\) so
there are \(\sim \log(\frac{\lambda^2}{a^2}\frac{R^{-1/2}N}{\lambda_0})\) terms in the above sum. Thus, \[|U_{a,b}(f_1,f_2)|a^2b^2 \lesssim
\left(\log(\frac{\lambda^2}{a^2}\frac{R^{-1/2}N}{\lambda_0})\right)^2\max_{k \leq m\leq M} \sum_{\tau_m \subset \Sigma_1 \cup \Sigma_2}\sum_{U_{\tau_m}}|U_{\tau_m}|\|f_{\tau_m}\|^4_{\sout{L}^2(U_{\tau_m})}.\] Next, we bound \[\begin{align}
\sum_{\substack{\tau_m \subset \Sigma_1 \cup \Sigma_2 \\ U_{\tau_m}}} |U_{\tau_m}|
\|f_{\tau_m}\|^4_{\sout{L}^2(U_{\tau_m})}
&\leq \max_{\tau_m,U_{\tau_m}}\|f_{\tau_m}\|^2_{\sout{L}^2(U_{\tau_m})}
\sum_{\substack{\tau_m \subset \Sigma_1 \cup \Sigma_2 \\ U_{\tau_m}}} |U_{\tau_m}|
\|f_{\tau_m}\|^2_{\sout{L}^2(U_{\tau_m})} \\
&\leq \max_{\tau_m,U_{\tau_m}}\|f_{\tau_m}\|^2_{\sout{L}^2(U_{\tau_m})} \sum_{\tau_m \subset \Sigma_1 \cup \Sigma_2}\|f_{\tau_m}\|^2_{L^2(B_R)}\\
&\leq \lambda(l_m)\lambda(l_m^{-1}R^{-1})(\lambda_1+\lambda_2)R^2\\
&\leq \lambda_0 \frac{l_m}{R^{-1/2}}(l_m^{-1}R^{-1}N)(\lambda_1+\lambda_2)R^2\\
&\leq \lambda_0 \frac{\lambda_0}{NR^{-1/2}}(\lambda_1+\lambda_2)N^2R \qedhere
\end{align}\] ◻
Next, we shall prove the following asymmetric estimate.
Lemma 12. (Asymmetric Estimate)Let \(\Sigma_1\) and \(\Sigma_2\) be caps that are \(\sim l\) distance apart. Suppose \(\lambda(\Sigma_2)/\lambda_0^{1/2} \ll b \leq \lambda(\Sigma_2)\), then \[\left\lvert U_{a,b}(f_{\Sigma_1},f_{\Sigma_2})\right\rvert \lesssim \log\left(\frac{\lambda(\Sigma_2)}{b}
\frac{NR^{-1/2}}{\lambda_0}\right)\max\left(\frac{l(\Sigma_2)}{l}, \frac{\sqrt{R}}{N}\right)\frac{N^2R\lambda(\Sigma_1)\lambda(\Sigma_2)^2}{a^2b^4}.\]
By a rescaling argument, the lemma above follows from the following lemma.
Lemma 13. Let \(\Sigma_1\) and \(\Sigma_2\) be caps that are \(\sim 1\) distance apart and suppose that \(\lambda(\Sigma_2)/\lambda_0^{1/2} \ll b \leq \lambda(\Sigma_2)\). Then \[\left\lvert U_{a,b}\right\rvert \lesssim \log\left(\frac{\lambda(\Sigma_2)}{b}
\frac{NR^{-1/2}}{\lambda_0}\right)^3\max\left(l(\Sigma_2), \frac{\sqrt{R}}{N}\right)\frac{N^2R\lambda(\Sigma_1)\lambda(\Sigma_2)^2}{a^2b^4}.\]
We begin by estimating the superlevel sets of \(g_{\Sigma_2}\) via a high–low decomposition, while carefully controlling the number of scales that can contribute. Note that \(g_{\Sigma_2}\) is essentially locally constant on rectangles \(T\) of dimensions \(R^{1/2} \times R^{1/2}L_2^{-1}\).
Next, we apply a slightly generalized bilinear restriction estimate 3 on each such rectangle \(T\). This yields a decomposition of \(f_{\Sigma_1}\) into caps \(\omega\) of length \(\max\{N^{-1}, R^{-1/2}L_2\}\), and of \(f_{\Sigma_2}\) into caps of length \(L_2\), allowing us to bound the intersection of \(U_{a,b}\) with each \(T\).
Since we assume \(L_2\) is small, the length of the cap \(\omega\) we can break \(f_{\Sigma_1}\) into is particularly small, which yields a gain of a
factor \(l(\Sigma_2)\).
Right now to simplify notation, write \(g=\sum_{\theta \subset \Sigma_2} |f_\theta|^2\) and \(V_\beta=\{x: g(x)>\beta\}\). Note that \[\fint_{B_R} g \sim
\fint_{B_R} \sum_{\gamma \subset \Sigma_2}|f_\gamma|^2 \sim \lambda_2.\] In the following lemma, we proved a bound for \(|V_\beta|\) when \(\beta\) is significantly bigger than the
average size of \(g\) on \(B_R\).
Now, we are ready to put things together. First, by Cauchy-Schwartz, \(|f_2(x)| \geq b\) implies that \(g(x) \geq \frac{b^2\lambda_0}{\lambda_2}\). Thus, \[U_{a,b} \subseteq \bigcup_{\lambda_2\lambda_0 \geq \beta \geq \frac{b^2\lambda_0}{\lambda_2}} V(\beta) \cap U_{a,b}.\] For \(b \gg \lambda_2 \lambda_0^{-1/2}\), we need \(\beta \gg \lambda_2\). Note there are just \(\log(\frac{\lambda_2^2}{b^2})\) many choices of dyadic \(\lambda_2\lambda_0 \geq \beta \geq
\frac{b^2\lambda_0}{\lambda_2}\). We shall bound each \(|V(\beta) \cap U_{a,b}|\).
\[\begin{align} && |V(\beta) \cap U_{a,b}|a^2b^2 \\&\leq& \int_{V(\beta)} |f_1|^2|f_2|^2 \\ & \lesssim & \|\sum_{\omega \subseteq \Gamma_1} |f_{1, \omega}|\|_\infty \beta |T|(\#\{T:T\cap V(\beta)\not=
\emptyset\}) \text{ by lemma }\ref{bires}\\ & \lesssim_\epsilon& \frac{1}{\beta}\|\sum_{\omega \subseteq \Gamma_1} |f_{1, \omega}|\|_\infty \log\left(\frac{\lambda_2 }{\beta}\frac{N}{\sqrt{R}}\right)^2\lambda_0 NR^{-1/2}R^2\lambda_2.
\end{align}\] Suppose that \(R^{-1/2}l_2 \geq 1/N\). We let \(l(\omega)=R^{-1/2}L_2\), so \(\|\sum_{\omega \subset \Gamma_1} |f_{1,\omega}|^2\| \leq
\lambda_1\lambda_1(R^{-1/2}l_2)\leq \lambda_1 (l_2N/\sqrt{R})\). Suppose that \(R^{-1/2}l_2 \leq 1/N\). We let \(l(\omega)=1/N\) so \(\|\sum_{\omega \subset
\Gamma_1} |f_{1,\omega}|^2\| \leq \lambda_1\). Thus, we have plugging in \(\beta \geq \frac{b^2\lambda_0}{\lambda_2}\). \[\begin{align} && |V(\beta) \cap U_{a,b}|a^2b^2 \\
&\leq& \frac{\lambda_2}{b^2\lambda_0} \lambda_1 \max(1, l_2N/\sqrt{R}) \log\left(\frac{\lambda_2^2 }{b^2}\frac{NR^{-1/2}}{\lambda_0}\right)^2\lambda_0 NR^{-1/2}R^2\lambda_2 \\
& \lesssim & \frac{1}{b^2}\max(1, l_2N/\sqrt{R}) \log\left(\frac{\lambda_2 }{b}\frac{NR^{-1/2}}{\lambda_0}\right)^2\lambda_0 NR^{-1/2}R^2 \lambda_1\lambda_2^2
\end{align}\] Summing over all the dyadic \(\beta\)’s, we proved Lemma 13.
Now, we develop a refined broad and narrow argument by combining the broad estimate with the asymmetric estimate to prove lemma 10.
Definition 7. We say \(x \in Br_{m}(a')\) if there exist \(\tau_m,\tau_m'\) such that \(l_m \leq dist( \tau_m, \tau_m')\leq
2l_{m-1}\) and \(x \in U_{a'/10,a'/10}(f_{\tau_m}, f_{\tau_m'})\). We say \(x \in Nar_m(a')\) if there exists \(\tilde{\tau}_m\) of
length \(2l_m\) such that \(|f_{\tau_m}(x)|>a'/10\).
Now, let’s gather some properties of \(Br_m\) and \(Nar_m\).
Proposition 12. If \(a_1+\cdots+a_k <a/2\) and \(l_k<a/(10N)\), then \[U_a \subset \bigcup_{j=1}^k Br_m(a_m).\]
Proof. First, we note that \(U_a \subset Br_1(a')\cup Nar_1(a-a')\) for \(0<a'<a\). Then, note that for \(m \geq 1\), \(Nar_m(a') \subset Br_{m+1}(a'')\cup Nar_{m+1}(a'-a'')\) for \(0<a''<a'\). Thus, inductively, we have \[U_a \subset
Br_1(a_1)\cup \cdots \cup Br_m(a_m) \cup Nar_m(a-\sum_{j=1}^m a_j).\] In particular, suppose \(a_1+\cdots+ a_k <a/2\), then \[U_a \subset Br_1(a_1)\cup \cdots \cup Br_k(a_k) \cup
Nar_k(1-\sum_{j=1}^k a_k).\] Note that \(Nar_k(a-\sum_{j=1}^k a_k)\) is empty as \(a-\sum_{j=1}^k a_k>a/2\) and \(\lambda(l_k)<a/10\). ◻
Proof. Define \(A=\{m: Br_m(a')\not=\emptyset \}\). Then, for each \(m \in A\), there exist \(\tau_m\) and \(\tau_{m'}\) that are \(\gtrsim l_m\) distance apart and \(\lambda(\tau_m)\geq a'\) and \(\lambda(\tau_m')\geq
a'\) so \(\lambda(\tau_m \cup \tau_{m'}) \geq 2a'\). Suppose \(n>m\), \(m,n \in A\), then either \((\tau_n
\cup \tau_n') \cap \tau_m=\emptyset\) or \((\tau_n \cup \tau_n') \cap \tau_m'=\emptyset\), \(\lambda(\tau_m \cup \tau_{m'} \cup \tau_n \cup \tau_n') \geq
3a'\). In general, \(\lambda(\cup_{j=1}^{|A|}(\tau_{m_j} \cup\tau_{m_j}'))\geq |A|a'\). Thus, \(|A|\leq \lambda/a'\). ◻
From now on, we put \[h=100\log((\lambda/a)\log(NR^{-1/2}/\lambda_0)).\]
Proposition 14. If \(|m-n|>h\), then \[\left\lvert Br_m(a(a/\lambda)^3) \cap Br_n(a(a/\lambda)^3)\right\rvert\lesssim
\frac{N^2R\lambda}{a^4}\left(\frac{a}{\lambda}\right)^{20}.\]
Proof. Suppose \(x \in Br_m(a(a/\lambda)^3) \cap Br_n(a(a/\lambda)^3)\), suppose \(m>n+h\) then there exist \(\tau_m\) and \(\tau_n\) such that \(dist(\tau_m,\tau_n) \gtrsim l_n\) and \(x \in U_{a',a'}(f_{\tau_m},f_{\tau_n})\) with \(a'=a(a/\lambda)^3\). Note that \[a'\gg \lambda (\log N)^{-400}\gg \lambda(\tau_m)/\lambda_0^{1/2}\] as we assumed that \[a>\lambda (\log N)^{-100},
N>R^\frac{1}{2}(\log N)^{100000} \text{ and } \lambda_0>R^{-1/2}N(\log N)^{-100}.\] Thus, we can apply lemma 12 to get \[\begin{align} \left\lvert
U_{a',a'}(f_{\tau_m},f_{\tau_n})\right\rvert &\lesssim\log\left(\frac{\lambda(\tau_2)}{a'} \frac{NR^{-1/2}}{\lambda_0}\right)\max\left(\frac{l_m}{l_n}, \frac{\sqrt{R}}{N}\right)\frac{N^2R\lambda(\tau_m)\lambda(\tau_n)^2}{a'^6} \\
&\lesssim \log\left(\frac{\lambda}{a'} \frac{NR^{-1/2}}{\lambda_0}\right)\max\left(3^{-h}, (\log N)^{-10000}\right)\frac{N^2R\lambda^3}{a'^6}\\ &\lesssim\;\log\left(\frac{\lambda}{a'} \frac{N R^{-1/2}}{\lambda_0}\right)
\max\left(\left(\frac{a}{\lambda}\right)^{100}, (\log N)^{-10000}\right) \\
&\quad \times \log\left(\frac{N R^{-1/2}}{\lambda_0}\right)^{-100}
\frac{N^2 R \lambda^3}{a'^6} \\
&\lesssim \frac{N^2 R \lambda}{a^4}\left(\frac{a}{\lambda}\right)^{50}.
\end{align}\] Note that in the last step we used that \((a/\lambda)^{100} \geq (\log N)^{-10000}\) as we assume that \(a>\lambda (\log N)^{-100}\).
Note in order for \(\tau_m\) to contribute, \(\lambda(\tau_m) \geq a'\) and the same to \(\tau_n\). Thus, there are less than \(\lambda/a'\) many \(\tau_m\) and \(\lambda/a'\) many \(\tau_n\) that might contribute. Then, we sum things up \[\begin{align} \left\lvert Br_m(a(a/\lambda)^3) \cap Br_n(a(a/\lambda)^3)\right\rvert &\lesssim \sum_{\substack{\tau_m,\tau_n\\ \lambda(\tau_m)\geq a',\lambda(\tau_n)\geq a'\\ dist(\tau_m,\tau_n)\gtrsim
l_n}}U_{a',a'}(f_{\tau_m},f_{\tau_n})\\ &\lesssim \sum_{\substack{\tau_m,\tau_n\\ \lambda(\tau_m)\geq a',\lambda(\tau_n)\geq a'\\ dist(\tau_m,\tau_n)\gtrsim l_n}}\frac{N^2R\lambda}{a^4}\left(\frac{a}{\lambda}\right)^{50}\\ &\lesssim
(\lambda/a')^2\frac{N^2R\lambda}{a^4}\left(\frac{a}{\lambda}\right)^{50}\\ &\lesssim \frac{N^2R\lambda}{a^4}\left(\frac{a}{\lambda}\right)^{20} \qedhere
\end{align}\] ◻
Proposition 15. If we define \(B_1=\cup_m Br_m(a/(100h))\) and \[B_2=\bigcup_{|m-n|>h}\left(Br_m(a(a/\lambda)^3) \cap Br_n(a(a/\lambda)^3)\right)\] Then, \(U_a \subset B_1 \cup B_2\).
Proof. Suppose \(x \not\in B_2\), then there exists \(A \in \{1,\cdots, k\}\) such that \(|A|<h\) and for \(m
\not\in A\), \(x\not \in Br_m(a(a/\lambda)^3)\). Put \(a_m=a(a/\lambda)^3\) for \(m\not\in A\) and \(a_m=a/(100h)\)
for \(m\in A\). Note \(\sum_{m=1}^k a_m<a/2\), so \(x \in \cup_{m\in A}Br_m(a/(10h))\). Thus, \(x\in B_1\). ◻
Proof. We write \(\tau_m \sim \tau_m'\) if \(l_m<dist(\tau_m', \tau_m)<2l_{m-1}\). Note that \[\frac{a}{100h} \gtrsim \lambda (\log
N)^{-100} \log((\lambda/a)\log(NR^{-1/2}/\lambda_0))^{-1}\gtrsim \lambda (\log N)^{-4000}.\] Thus, we can apply lemma 11 to get \[\begin{align} \left\lvert
Br_m(a/100h)\right\rvert&\lesssim \sum_{\tau_m\sim\tau_m'}\log\left(\frac{\lambda(\tau_2)}{b} \frac{NR^{-1/2}}{\lambda_0}\right)\frac{N^2R(\lambda(\tau_m)+\lambda(\tau_m'))}{(a/(100h))^4}\frac{\lambda_0}{NR^{-1/2}}\\
&\lesssim\sum_{\tau_m\sim\tau_m'}\log\left(\frac{\lambda(\tau_2)}{b} \frac{NR^{-1/2}}{\lambda_0}\right)\frac{N^2R(\lambda(\tau_m)+\lambda(\tau_m'))}{a^4}h^4\frac{\lambda_0}{NR^{-1/2}}\\
&\lesssim\log\left(\frac{\lambda(\tau_2)}{b} \frac{NR^{-1/2}}{\lambda_0}\right)\frac{N^2R\lambda}{a^4}h^4\frac{\lambda_0}{NR^{-1/2}}\\
&\lesssim\log\left(\frac{\lambda(\tau_2)}{b} \frac{NR^{-1/2}}{\lambda_0}\right)^{O(1)}\frac{N^2R\lambda}{a^4}\frac{\lambda_0}{NR^{-1/2}}
\end{align}\] as we put \(h=100\log((\lambda/a)\log(NR^{-1/2}/\lambda_0))\). Summing things up and by proposition 13, \[\begin{align} \left\lvert B_1\right\rvert&\lesssim \sum_{m=1}^k Br_m(a/100h)\\ &\lesssim \frac{\lambda}{a/(100h)}\log\left(\frac{\lambda(\tau_2)}{b}
\frac{NR^{-1/2}}{\lambda_0}\right)^{O(1)}\frac{N^2R\lambda}{a^4}\frac{\lambda_0}{NR^{-1/2}}\\ &\lesssim\log\left(\frac{\lambda}{a}\frac{NR^{-1/2}}{\lambda_0}\right)^{O(1)} \frac{N^2R\lambda^2}{a^5}\frac{\lambda_0}{NR^{-1/2}} \qedhere
\end{align}\] ◻
Adding the previous two propositions up, we proved that \[|U_a^{\lambda_0}|\lesssim \log\left(\frac{\lambda}{a}\frac{NR^{-1/2}}{\lambda_0}\right)^{O(1)} \frac{N^2R\lambda^2}{a^5}\frac{\lambda_0}{NR^{-1/2}}.\]
We begin by introducing the rescaled torus \(\mathbb{T}_\lambda:= \mathbb{R}/\left(2\pi \lambda \mathbb{Z}\right)\) with \(\lambda\geq 1\) and the associated function spaces that will be
used in the sequel. For \(f: \mathbb{T}_\lambda \rightarrow \mathbb{C}\) measurable, we define Lebesgue norms by \[\left\lVert f\right\rVert_{L^p(\mathbb{T}_\lambda)}^p = \int_{0}^{2\pi\lambda}
\left\lvert f(x)\right\rvert^p \,\, dx,\] for \(1 \leq p < \infty\) and the usual modification for \(p=\infty\). We also define \(\left(dk\right)_\lambda\) to be the normalized counting measure on \(\mathbb{Z}_\lambda := \frac{1}{\lambda}\mathbb{Z}\)\[\int_{\mathbb{Z}_\lambda} a(k)
\left(dk\right)_\lambda := \frac{1}{2\pi\lambda} \sum _{k \in \mathbb{Z}_\lambda} a(k).\] The Fourier coefficients of \(f \in L^1(\mathbb{T}_\lambda)\) are given by \[\hat{f}(k) =
\int_{0}^{2\pi\lambda} e^{-i k x} f(x) \, \, dx,\] for \(k \in \mathbb{Z}_\lambda\) and the Fourier inversion formula is given by \[f(x)= \int_{\mathbb{Z}_\lambda} e^{i k x}
\hat{f}(k)\left(dk\right)_\lambda.\] Using this convention, the following identities hold \[\begin{align} \tag{12} & \int_{0}^{2\pi\lambda} f(x) \overline{g(x)} \,\, dx = \int_{\mathbb{Z}_\lambda}
\hat{f}(k) \overline{\hat{g}(k)} \,\, (dk)_\lambda,\\ \tag{13}
&\left\lVert f\right\rVert_{L^2(\mathbb{T}_\lambda)}=\left\lVert\hat{f}\right\rVert_{L^2((dk)_\lambda)}, \\
\tag{14} &\widehat{fg}(k) = \int_{\mathbb{Z}_\lambda} \hat{f}(k_1) \hat{g}(k-k_1) \,\, (dk_1)_\lambda.
\end{align}\] The Sobolev space, \(H^s=H^s(\mathbb{T}_\lambda)\), is defined as the completion of smooth functions under the norm \[\left\lVert f\right\rVert_{H^s}=\left\lVert\langle k \rangle^s
\hat{f}(k)\right\rVert_{L^2((dk)_\lambda)},\] where \(\langle k \rangle := (1+\left\lvert k\right\rvert^2)^\frac{1}{2}\). We will frequently make use of Littlewood-Paley theory which allows us to quantitatively
separate the rough, high-frequency behavior of a function from the smooth, low-frequency one. In particular, for \(A \subset \mathbb{Z}_\lambda\) let \(P_A\) denote the Fourier multiplier
\(\widehat{P_A f}:= \chi_A \hat{f}.\) By a slight abuse of notation, for \(N \in 2^{k_0\mathbb{N}_0}\) with \(k_0 \geq 1\) we define \[P_N:= \begin{cases} P_{\left[-2^{k_0}N,-N\right) \cup \left(N,2^{k_0}N\right]} &\text{ for } N > 1\\ P_{\left[-1,1\right]} &\text{ for } N \leq 1. \end{cases}\] In most of our estimates, we adopt the standard dyadic
decomposition with \(k_0 = 1\). The sole exception occurs in Lemma 23, where we take \(k_0 = 1/s\) for \(0 < s \leq 1\). We also stress that if \(f = f(x,t)\) depends on time, the operator \(P_A\) acts only on
the spatial variable: \((P_A f)(x,t) = P_A(f(\cdot,t))(x)\).
We define \(S_\lambda(t)\) to be the solution operator to the linear Schrödinger equation \[i \partial_t u + \Delta u =0, \text{ } u(x,0)=u_0(x), \text{ } x \in \mathbb{T}_\lambda,\]
that is, \[S_\lambda(t) u_0(x) = \int_{\mathbb{Z}_\lambda} e^{ i(k x+\left\lvert k\right\rvert^{2}t)} \hat{u}_0(k) (dk)_\lambda.\] When \(\lambda=1\), we drop the subscript and write \(S(t):=S_1(t)\).
As we will be working with long-time Strichartz estimates on the rescaled torus \(\mathbb{T}_\lambda\), it is convenient to prove local well-posedness results in adapted function spaces instead of using \(X^{s,b}\) spaces. To this end, we introduce the \(V^p\), \(U^p\) and \(Y^s\) spaces which were first used in the critical
regularity well-posedness theory of dispersive equations on periodic domains [28]–[30]. More recently, the same spaces have been used to prove global well-posedness for the mass critical NLS on \(\mathbb{T}\)[1], [20] and \(\mathbb{T}^2\)[10] in the sub-critical setting.
Throughout the remainder of this section, let \(p \geq 1\), let \(\mathcal{H}\) be a separable Hilbert space over \(\mathbb{C}\) and define \(\mathcal{Z}\) to be set of finite partitions \(-\infty <t_0 <t_1 < \cdots<t_K\leq \infty\) of the real line. If \(t_K=\infty\), we use the convention
that \(v(t_K):=0\) for all functions \(v: \mathbb{R}\rightarrow \mathcal{H}\).
Definition 8. \(V^p=V^p(\mathbb{R}\rightarrow \mathcal{H})\) is defined to be the space of all right continuous functions \(f : \mathbb{R}\rightarrow \mathcal{H}\) which satisfy
\(\lim_{t \rightarrow - \infty} f(t)=0\) and \[\left\lVert f\right\rVert_{V^p}^p:= \sup_{\{t_k\}_{k=0}^K \in \mathcal{Z}} \sum_{k=1}^K \left\lVert f(t_k)-f(t_{k-1})\right\rVert_{\mathcal{H}}^p
< \infty.\] Moreover, for \(\mathcal{H}=L^2(\mathbb{T}_\lambda)\), we define \(V^p_S:=S_\lambda(\cdot) V^p\) and endow it with norm \(\left\lVert
f\right\rVert_{V^p_S}:=\left\lVert S_\lambda(-\cdot)f\right\rVert_{V^p}.\)
Definition 9. For \(\{t_k\}_{k=0}^K \in \mathcal{Z}\) and \(\{f_k\}_{k=0}^{K-1} \subset \mathcal{H}\) satisfying \(\sum_{k=0}^{K-1} \left\lVert
f_k\right\rVert_{\mathcal{H}}^p =1\) and \(f_0=0\), we define \(f: \mathbb{R}\rightarrow \mathcal{H}\) to be a \(U^p\)-atom if \[f(t)=\sum_{k=1}^K \chi_{[t_k,t_{k-1})}(t)f_{k-1}.\] The atomic space \(U^p=U^p(\mathbb{R}\rightarrow \mathcal{H})\) comprises functions \(f: \mathbb{R}\rightarrow
\mathcal{H}\) of the form \[f(t)=\sum_{j=1}^\infty \lambda_j f_j(t) \text{ for } U^p\text{-atoms } f_j, \{\lambda_j\} \in \ell^1,\] and is endowed with norm \[\left\lVert
f\right\rVert_{U^p} := \inf\left\{ \sum_{j=1}^\infty \left\lvert\lambda_j\right\rvert : f=\sum_{j=1}^\infty \lambda_j f_j, \,\, \lambda_j \in \mathbb{C}, \,\, f_j \text{ } U^p\text{-atom}\right\}.\] Moreover, for \(\mathcal{H}=L^2(\mathbb{T}_\lambda)\), we define \(U^p_S:=S_\lambda(\cdot) U^p\) and endow it with norm \(\left\lVert f\right\rVert_{U^p_S}:=\left\lVert
S_\lambda(-\cdot)f\right\rVert_{U^p}\).
The spaces \(U^p\) and \(V^p\) are related by the following continuous embeddings which follow from [28].
Lemma 14. For \(1 \leq p < q <\infty\), we have the following continuous embeddings \[U^p \hookrightarrow V^p \hookrightarrow U^q.\]
We conclude by the defining the \(Y^s\) spaces and stating some well-known properties. For details, see [28].
Definition 10. For \(s \in \mathbb{R}\), define \(Y^s=Y^s(\mathbb{R}\times \mathbb{T}_\lambda \rightarrow \mathbb{C})\) as the space of functions \(f:
\mathbb{R}\times \mathbb{T}_{\lambda} \rightarrow \mathbb{C}\) such that \(e^{-it\left\lvert k\right\rvert^{2\alpha}}\widehat{f(t)}(k)\) lies in \(V^2(\mathbb{R}\rightarrow
\mathbb{C})\) for all \(k \in \mathbb{Z}_\lambda\) and \[\left\lVert f\right\rVert_{Y^s}^2:= \int_{\mathbb{Z}_\lambda} \langle k \rangle^{2s} \left\lVert e^{-it\left\lvert
k\right\rvert^{2}}\widehat{f(t)}(k)\right\rVert_{V^2}^2 (dk)_\lambda<\infty.\] For a time interval \(J_T \subset \mathbb{R}\) of length \(T>0\), we define \(Y_{J_T}^s\) to be the restriction of \(Y^s\) to \(J_T \times \mathbb{T}_\lambda\) and endow it with the norm \[\left\lVert
f\right\rVert_{Y^s_{J_T}} := \inf \left\{\left\lVert g\right\rVert_{Y^s} : f= g \text{ on } J_{T} \times \mathbb{T}_\lambda \right\}.\] When \(J_T=[0,T)\), we drop the double subscript and write \(Y^s_T\) instead.
Lemma 15. For any \(s \in \mathbb{R}\), the \(Y^s\) spaces satisfy the following properties:
The embeddings \(Y^s \hookrightarrow L^\infty(\mathbb{R}\rightarrow H^s)\) and \(Y^0 \hookrightarrow V^2_S\) are continuous;
For any \(A, B\) disjoint subsets of \(\mathbb{Z}_\lambda\), \[\left\lVert P_{A\cup B} \phi \right\rVert_{Y^s}^2=\left\lVert P_{A}
\phi\right\rVert_{Y^s}^2+\left\lVert P_{B} \phi\right\rVert_{Y^s}^2;\]
For any \(T>0\) and any \(\phi \in H^s\), \[\left\lVert\chi_{[0,T)}S_\lambda(t)\phi\right\rVert_{Y^s} \sim
\left\lVert\phi\right\rVert_{H^s};\]
For any \(T>0\) and any \(f \in L^1 \left([0,T) \rightarrow H^s\right)\), \[\left\lVert\chi_{[0,T)} \int_0^t S_\lambda(t-t') f(t')
\,\,dt'\right\rVert_{Y^s} \lesssim \sup_{\left\lVert g\right\rVert_{Y^{-s}} \leq 1} \left\lvert\int_0^T \int_{\mathbb{T}_\lambda} f\overline{g} dx dt\right\rvert.\]
We stress that the constants in the above estimates are independent of \(\lambda\), \(s\) and \(T\).
We next turn to transferring the Strichartz estimate proved in 3 to \(Y^s\) spaces. Throughout this section, all frequency scales \(M\) appearing in the
projections \(P_M\) are assumed to satisfy \(M \geq 1\), unless stated otherwise. We also assume throughout that \(\lambda \geq 1\).
In view of the scaling symmetry of the problem, it is natural to work on the rescaled torus \(\mathbb{T}_\lambda\). To relate this setting to the standard torus \(\mathbb{T}\), we begin
by recalling a rescaling lemma from [22], which allows us to transfer estimates between the two
settings.
Lemma 16. Let \(T>0\), \(n\in \mathbb{N}\) and \(N_1, \dots N_n >0\). Then the following two statements are equivalent:
There exists a constant \(C_1(T, N_1, \dots , N_n)>0\) such that for all \(f_j \in L^2(\mathbb{T})\) satisfying \(\mathop{\mathrm{supp}}\hat{f}_j \subset
\left\{k \in \mathbb{Z}: \frac{N_j}{2} \leq \left\lvert k\right\rvert < N_j \right\}\) for \(1\leq j \leq n\), we have the following estimate \[\int_{[0,T] \times \mathbb{T}}
\prod_{j=1}^n \left\lvert S(t)f_j\right\rvert^2 \leq C_1(T, N_1, \dots , N_n) \prod_{j=1}^n \left\lVert f_j\right\rVert_{2}^2.\]
There exists a constant \(C_\lambda(T, N_1, \dots , N_n)>0\) such that for all \(\phi_j \in L^2(\mathbb{T}_\lambda)\) satisfying \(\mathop{\mathrm{supp}}\hat{\phi}_j \subset \left\{k \in \mathbb{Z}_\lambda: \frac{N_j}{2} \leq \left\lvert k\right\rvert < N_j \right\}\) for \(1\leq j \leq n\), we have the following
estimate \[\int_{[0,T] \times \mathbb{T}_\lambda} \prod_{j=1}^n \left\lvert S_\lambda(t)\phi_j\right\rvert^2 \leq C_\lambda(T, N_1, \dots , N_n)\prod_{j=1}^n \left\lVert\phi_j\right\rVert_{2}^2.\]
Moreover, the constants are related by \[C_\lambda(T, N_1, \dots , N_n)=\lambda^{3-n}C_1(\lambda^{-2}T, \lambda N_1, \dots , \lambda N_n).\]
The following lemma follows immediately from Theorem 1.
Lemma 17. There exist a constant \(C>1\) such that for any \(\phi \in L^2(\mathbb{T})\) and any \(N \geq 1\), the following estimate holds
\[\left\lVert S(t)P_M\phi\right\rVert_{L_{t,x}^6([0,\left(\log N\right)^{-C}] \times \mathbb{T})} \leq C \left(1+\frac{\log M}{\log N}\right)^\frac{C}{6} \left\lVert\phi\right\rVert_2.\]
Combining Lemma 17 with Lemma 16 yields the following Strichartz estimates on the rescaled torus.
Lemma 18. There exists a constant \(C>1\) such that for any \(\phi \in L^2(\mathbb{T}_\lambda)\) and any \(N \geq 1\), the following estimate
holds \[\left\lVert S_\lambda(t)P_M\phi\right\rVert_{L_{t,x}^6([0,\lambda^2\left(\log \lambda N\right)^{-C}] \times \mathbb{T}_\lambda)} \leq C \left(1+\frac{\log M}{\log N}\right)^\frac{C}{6}
\left\lVert\phi\right\rVert_2.\]
We conclude this section by transferring the linear Strichartz estimate to \(Y^s\) spaces and by stating a trilinear estimate on \(Y^s\) spaces.
Lemma 19. There exist a constant \(C>1\), such that for any \(u \in Y^0(\mathbb{R}\times \mathbb{T}_\lambda \rightarrow \mathbb{C})\) and any \(N
\geq 1\), the following estimate holds \[\begin{align}
\left\lVert P_Mu\right\rVert_{L_{t,x}^6([0,\lambda^2\left(\log \lambda N\right)^{-C}]\times \mathbb{T}_\lambda)}\leq C \left(1+\frac{\log M}{\log N}\right)^\frac{C}{6} \left\lVert u\right\rVert_{Y^0}.
\end{align}\]
Proof. Define \(T:=\lambda^2\left(\log \lambda N\right)^{-C}\) and let \(u\) be a \(U^6_S\) atom \[u(t)=\sum_{k=1}^K
\chi_{[t_{k-1},t_k)}(t) S_\lambda(t)u_{k-1},\] where \(\{u_k\}_{k=0}^{K-1} \subset L^2(\mathbb{T}_\lambda)\) such that \(\sum_{k=0}^{K-1} \left\lVert u_k\right\rVert_{2}^6 =1\). Then
by Lemma 18 followed by Hölder’s inequality, we have \[\begin{align}
\left\lVert\chi_{[0,T]}P_Mu\right\rVert_{L^6_{t,x}}^6 &\leq \sum_{k=1}^K \left\lVert\chi_{[0,T]}S_\lambda(t) P_Mu_{k-1}\right\rVert_{L^6_{t,x}}^6, \\ &\lesssim \left(1+\frac{\log M}{\log N}\right)^{C} \sum_{k=1}^K \left\lVert
u_{k-1}\right\rVert_{2}^6, \\ &\lesssim \left(1+\frac{\log M}{\log N}\right)^{C}.
\end{align}\] From the above estimate, it immediately follows that for any \(u \in U^6_S\)\[\left\lVert\chi_{[0,T]}P_Mu\right\rVert_{L^6_{x,t}}\lesssim \left(1+\frac{\log M}{\log
N}\right)^\frac{C}{6} \left\lVert u\right\rVert_{U_S^6}.\] Therefore, for any \(u \in Y^0\), we can use Lemma 14 followed by Lemma 15 to conclude that \[\left\lVert\chi_{[0,T]}P_Mu\right\rVert_{L^6_{x,t}} \lesssim \left(1+\frac{\log M}{\log N}\right)^\frac{C}{6} \left\lVert u\right\rVert_{V^2_S} \lesssim \left(1+\frac{\log M}{\log N}\right)^\frac{C}{6} \left\lVert
u\right\rVert_{Y^0}. \qedhere\] ◻
Lemma 20. There exists a constant \(C>1\) such that for any functions \(u_1, u_2 \in Y^0(\mathbb{R}\times \mathbb{T}_\lambda \rightarrow \mathbb{C})\) and any \(N \geq 1\), the following estimate holds \[\left\lVert P_{N_1}u_1 \left(P_{N_2}u_2\right)^2\right\rVert_{L_{t,x}^2([0, \lambda^2\left(\log \lambda N\right)^{-C}] \times \mathbb{T}_\lambda)} \leq
C\left(1+ \frac{\log N_2}{\log N} \right)^\frac{C}{2} \left\lVert u_1\right\rVert_{Y^0}\left\lVert u_2\right\rVert_{Y^0}^2.\]
Proof. If \(N_1 \lesssim N_2\), the statement follows immediately from Hölder inequality and Lemma 19. On the other hand, if \(N_1 \gg N_2\), we decompose \(u_1= \sum_{\substack{\left\lvert J\right\rvert \sim N_2}} P_{J}u_1\) where the
summation is taken over intervals \(J \subset \{ k \in \mathbb{Z}_\lambda: \frac{N_1}{2}\leq \left\lvert k\right\rvert < N_1\}\) of length \(\left\lvert J\right\rvert=N_2\). Define \(T:= \lambda^2\left(\log \lambda N\right)^{-C}\) and note that \[\begin{align} \left\lVert P_{N_1}u_1 \left(P_{N_2}u_2\right)^2\right\rVert_{L_{t,x}^2([0,T] \times \mathbb{T}_\lambda)} &\lesssim
\left(\sum_J \left\lVert P_J u_1 \left(P_{N_2}u_2\right)^2\right\rVert_{L_{t,x}^2([0,T]\times \mathbb{T}_\lambda)}^2\right)^\frac{1}{2}, \\ &\lesssim \left(1+\frac{\log N_2}{\log N}\right)^\frac{C}{2} \left(\sum_J \left\lVert P_J
u_1\right\rVert_{Y^0}^2 \left\lVert u_2\right\rVert_{Y^0}^4\right)^\frac{1}{2}, \\ &\lesssim \left(1+\frac{\log N_2}{\log N}\right)^\frac{C}{2} \left\lVert u_1\right\rVert_{Y^0}\left\lVert u_2\right\rVert_{Y^0}^2,
\end{align}\] where the first line follows from almost orthogonality, the second line follows from Lemma 19 and last line is due
to Lemma 15. ◻
The aim of this section is to prove Theorem 2 using the \(I\)-method. Henceforth, let \(0 < s < 1\), and unless otherwise stated, all spatial norms are taken on \(\mathbb{T}_\lambda\), i.e.\(H^s = H^s(\mathbb{T}_\lambda)\), etc. Under the
small-mass assumption, it suffices to restrict attention to the defocusing case, i.e. we assume \(\mu = 1\) throughout this section.
To prove Theorem 2, we follow a strategy similar to that in [1], [19], [20]. Rather than working directly with the original 1 on \(\mathbb{T}\), we consider the \(I\)-system 17 (see 5.2) on \(\mathbb{T}_\lambda\), in order to exploit the scaling symmetry of the equation. We show that solutions
to 17 can be extended to arbitrarily large times, which yields a growth bound for solutions to 1 on the rescaled torus \(\mathbb{T}_\lambda\). By inverting the
rescaling, we obtain polynomial-in-time bounds for the \(H^s(\mathbb{T})\) norm of solutions to 1 , thereby establishing global well-posedness.
Following [19], our proof is divided into two steps: (i) establishing well-posedness for the
\(I\)-system, and (ii) deriving a growth bound for the modified energy \(E^1\).
We begin by constructing the \(I\)-operator and the first modified energy. Define \(m_1\) to be the restriction to \(\mathbb{Z}_\lambda\) of the following
smooth and monotone multiplier which satisfies \[m_1(x):=\begin{cases} 1 &\text{ if } \left\lvert x\right\rvert \leq 1, \\ \left\lvert x\right\rvert^{-1} &\text{ if } \left\lvert x\right\rvert > 2, \end{cases}\]
and for which, for every \(k\in\mathbb{N}_0\), there exists a constant \(C_k>0\) such that \[\sup_{x\in\mathbb{R}} \Bigg| \frac{x^k}{m_1(x)} \frac{d^k
m_1}{dx^k}(x) \Bigg| \le C_k.\] The conditions on derivatives of \(m_1\) are included to guarantee that the multiplier is sufficiently smooth for subsequent analysis (see Lemma 25). For \(N>0\) set \(m_N(x):=m_1(\frac{x}{N})\) and for \(\beta\geq 0\), let
\(I_N^\beta\) denote the Fourier multiplier \(\widehat{I_N^\beta f}=m^\beta_N\hat{f}\). Additionally, note that \(I_N^\beta\) is a smoothing operator of
degree \(\beta\), satisfying \[\left\lVert u\right\rVert_{H^{s_0}(\mathbb{T}_\lambda)} \lesssim \left\lVert I_N^\beta u\right\rVert_{H^{s_0+\beta}(\mathbb{T}_\lambda)}\lesssim_\beta N^{\beta}
\left\lVert u\right\rVert_{H^{s_0}(\mathbb{T}_\lambda)},\] for all \(s_0 \in \mathbb{R}\). We stress that the implicit constant in the first inequality is independent of \(\beta\)
provided \(N \geq 2\).
We also recall an interpolation lemma [31] which is useful for proving local well-posedness estimates.
Lemma 21. Let \(\beta>0\) and \(n\geq 1\). Suppose that \(Z, X_1, \dots X_n\) are translation-invariant Banach spaces and \(F\) is a translation invariant \(n\)-linear operator such that the following estimate holds \[\label{hypothesis:32N611}
\left\lVert I_1^\beta F(u_1,\dots,u_n)\right\rVert_Z \lesssim \prod_{j=1}^n \left\lVert I_1^\beta u_j \right\rVert_{X_j},\tag{15}\] for all \(0 \leq \beta \leq \beta_0\) and \(u_1,
\dots u_n\). Then one has the estimate, \[\label{conlcusion:32all32N} \left\lVert I_N^\beta F(u_1,\dots,u_n)\right\rVert_Z \lesssim \prod_{j=1}^n \left\lVert I_N^\beta u_j
\right\rVert_{X_j},\tag{16}\] for all \(0 \leq \beta \leq \beta_0\), \(u_1, \dots u_n\) and \(N \geq 1\), with explicit constant independent of
\(N\).
Remark 18. We will use Lemma 21 with \(\beta=1-s\) where \(0<s<1\) and with the translation-invariant Banach spaces \(Z=X_1= \dots=X_n=H^1(\mathbb{T}_\lambda)\) or \(Z=X_1= \dots=X_n=Y^1(\mathbb{R}\times
\mathbb{T}_\lambda \rightarrow \mathbb{C})\). For details, see Lemma 23. Under these assumptions, note that \(\left\lVert I_1^{1-s} f\right\rVert_{H^1} \sim \left\lVert f\right\rVert_{H^1}\) where the implicit constants are independent of \(s\). Moreover, if the implicit constant in the hypothesis 15 is independent of \(s\), then the constant in the conclusion 16 will also not depend on \(s\).
For the remainder of this paper, we define \(m:=m_N^{1-s}\) and \(I=I_N^{1-s}\) for some \(N \gg 1\) to be specified later. The first modified energy
associated with the \(I\)-operator is defined by \[E^1\left(u(t)\right):= E\left(Iu(t)\right)= \frac{1}{2}\int_{\mathbb{T}_\lambda} \left\lvert\partial_xIu(x,t)\right\rvert^2 \,\, dx + \frac{1}{6}
\int_{\mathbb{T}_\lambda} \left\lvert Iu(x,t)\right\rvert^{6}\,\, dx.\]
The first step in the proof of Theorem 2 is establishing a bound for \(\left\lVert Iu\right\rVert_{Y^1_T}\)
for some long enough \(T>0\). To do this we apply the \(I\)-operator to 1 and use a fixed point argument on the following initial value problem,
\[\label{eq:I95system} \begin{cases} i \partial_t Iu+\Delta Iu=I\left(\left\lvert u \right \rvert^4 u\right), \\ Iu(x,0)=Iu_0(x) \in H^{1}. \end{cases} \tag{17}\] In
particular, we prove the following result.
Lemma 22. There exist constants \(\delta>0\) and \(c>1\) such that the following holds: for any data \(u_0\) satisfying \(\left\lVert I u_0\right\rVert_{H^1} \leq \delta\) and any \(s>0\), there exists a constant \(N_0 = N_0(s,c,\delta) > 0\) such that for all \(N > N_0\), the solution \(u\) to 1 satisfies \[\left\lVert Iu\right\rVert_{Y^1_T} \leq 2\delta,\] where \(T := \lambda^{2}\log(\lambda N)^{-c}.\)
By standard iterative methods and the properties of \(Y^s\) spaces, Lemma 22 follows immediately from the following
multilinear estimate.
Lemma 23. There exits constants \(c>1\) and \(C>1\) with the following property: for every \(0<s \leq 1\) there exists a constant \(N_0=N_0(s,c,C)>1\) such that for any \(N>N_0\), the following estimate holds \[\left\lVert\chi_{[0,T)}\int_0^t S_\lambda(t-t')I(u_1u_2u_3u_4u_5)
dt'\right\rVert_{Y^1} \leq C \prod_{j=1}^5 \left\lVert Iu_j\right\rVert_{Y^1},\] where \(T:=\lambda^{2}\log(\lambda N)^{-c}\). Moreover, in the above estimate, each \(u_j\) may be
replaced by its complex conjugate \(\overline{u}_j\).
Proof. First note that by Lemma 21, it suffices to show that \[\left\lVert\chi_{[0,T)}\int_0^t S_\lambda(t-t')u_1u_2u_3u_4u_5 dt'\right\rVert_{Y^s} \lesssim \prod_{j=1}^5 \left\lVert u_j\right\rVert_{Y^s}.\] By Lemma 15, we have that \[\left\lVert\chi_{[0,T)}\int_0^t S_\lambda(t-t')u_1u_2u_3u_4u_5 dt'\right\rVert_{Y^s} \lesssim \sup_{\left\lVert v\right\rVert_{Y^{-s}}\leq 1}
\left\lvert\int_0^T\int_{\mathbb{T}_\lambda}u_1u_2u_3u_4u_5\overline{v} dx dt\right\rvert.\] We perform a Paley-Littlewood decomposition, \(u_j=\sum_{L_j} P_{L_j}u_j\) for \(j=1,\dots,
5\) and \(v=\sum_{M} P_M v\) where \(L_1, \dots L_5, M \in 2^{k_s\mathbb{N}_0}\) and \(k_s:=\frac{1}{s}\). We therefore need to bound \[\sum_{L,M} \mathcal{I}(L,M) := \sum_{L,M} \int_0^T\int_{\mathbb{T}_\lambda}\left\lvert P_{L_1}u_1P_{L_2}u_2P_{L_3}u_3P_{L_4}u_4P_{L_5}u_5P_M v\right\rvert dx dt,\] where \(L=(L_1,L_2,L_3,L_4,L_5)\) and the summation is restricted to \(M \lesssim L_1+\dots+L_5\) due to orthogonality. Without loss in generality we can assume that \(L_1 \geq
\cdots \geq L_5\) and so \(M \lesssim L_1\). Also note that each \(u_j\) can be replaced by its complex conjugate \(\overline{u}_j\) in the definition
of \(\mathcal{I}(L,M)\).
We split the summation into two regions: (a) \(L_1 \lesssim N\) and (b) \(L_1 \gg N\). First consider case (a) \(L_1 \lesssim N\). Then, \[\begin{align} \sum_{\substack{L,M\\ L_1 \lesssim N}} \mathcal{I}(L,M) &\leq \sum_{L,M} \prod_{j=1}^5 \left\lVert\chi_{[0,T)}P_{L_j}u_j\right\rVert_{L^6_{t,x}} \left\lVert\chi_{[0,T)}P_{M}v\right\rVert_{L^6_{t,x}}, \\
&\lesssim \sum_{L,M}\prod_{j=1}^5 \left\lVert P_{L_j}u_j\right\rVert_{Y^0} \left\lVert P_{M}v\right\rVert_{Y^0}, \\ &\lesssim \prod_{j=2}^5 \left\lVert u_j\right\rVert_{Y^s} \sum_{M\lesssim L_1} \left(\frac{M}{L_1}\right)^s \left\lVert
P_{L_1}u_1\right\rVert_{Y^s} \left\lVert P_{M}v\right\rVert_{Y^{-s}}, \\
&\lesssim \prod_{j=1}^5 \left\lVert u_j\right\rVert_{Y^{s}} \left\lVert v\right\rVert_{Y^{-s}},
\end{align}\] where the first line follows from Hölder’s inequality, the second line follows from Lemma 19 and the last two lines
follow from summing geometric progressions and the fact that \(s>0\). The selection of \(k_s=\frac{1}{s}\) ensures that the implicit constants in the above estimates do not depend on
\(s\).
Next consider case (b): \(L_1 \gg N\). We further split of case (b) into two regions: (i) \(M \lesssim L_2\) and (ii) \(M \gg L_2\). In sub-case (i),
\(M \lesssim L_2\) and so \(L_1 \sim L_2\). Therefore, an analogous argument to case (a) yields \[\begin{align} \sum_{\substack{L,M \\ L_1 \sim L_2}}
\mathcal{I}(L,M) &\leq \sum_{\substack{L,M \\ L_1 \sim L_2}}\prod_{j=1}^5 \left\lVert\chi_{[0,T)}P_{L_j}u_j\right\rVert_{L^6_{t,x}} \left\lVert\chi_{[0,T)}P_{M}v\right\rVert_{L^6_{t,x}}, \\ &\lesssim \sum_{\substack{L,M \\ L_1 \sim L_2}}
\left(\frac{\log L_2}{\log N}\right)^{c} \prod_{j=1}^5 \left\lVert P_{L_j}u_j\right\rVert_{Y^0} \left\lVert P_{M}v\right\rVert_{Y^0}, \\ & \lesssim \frac{N^{-s}}{s} \prod_{j=2}^5 \left\lVert u_j\right\rVert_{Y^s} \sum_{M \lesssim L_1}
\left(\frac{M}{L_1}\right)^s \left\lVert P_{L_1}u_1\right\rVert_{Y^s} \left\lVert P_{M}v\right\rVert_{Y^{-s}}, \\ &\lesssim \frac{N^{-s}}{s} \prod_{j=1}^5 \left\lVert u_j\right\rVert_{Y^s} \left\lVert v\right\rVert_{Y^{-s}},
\end{align}\] where the first line follows from Hölder’s inequality, the second line follows from Lemma 19 and the fact that
\(L_2 \sim L_1 \gg N\). The last two estimates follow from summing geometric progressions and the fact that \(s>0\).
On the other hand, for region (ii): \(M \gg L_2\) so we have \(L_1 \sim M\). Therefore, using the trilinear bound from Lemma 20 and noting that \(L_1 \gg L_2 \geq L_3\), we obtain \[\begin{align}
\left\lVert\chi_{[0,T)} \prod_{j=1}^3 P_{L_j}u_j\right\rVert_{L^2_{t,x}}^2 &\leq \left\lVert\chi_{[0,T)}P_{L_1} u_1\left(P_{L_2}u_2\right)^2\right\rVert_{L^2_{t,x}} \left\lVert\chi_{[0,T)}P_{L_1}u_1\left(P_{L_3}u_3\right)^2\right\rVert_{L^2_{t,x}}, \\
& \lesssim \left(1+\frac{\log L_2}{\log N}\right)^{c} \left\lVert P_{L_1}u_1\right\rVert_{Y^0}^2 \left\lVert P_{L_2}u_2\right\rVert_{Y^0}^2\left\lVert P_{L_3}u_3\right\rVert_{Y^0}^2.
\end{align}\] An identical argument and the fact that \(M \gg L_4 \geq L_5\) yields, \[\left\lVert\chi_{[0,T)} P_M v \prod_{j=4}^5 P_{L_j}u_j\right\rVert_{L^2_{t,x}} \lesssim
\left(1+\frac{\log L_4}{\log N}\right)^\frac{c}{2} \left\lVert P_{L_M}v\right\rVert_{Y^0} \left\lVert P_{L_4}u_4\right\rVert_{Y^0}\left\lVert P_{L_5}u_5\right\rVert_{Y^0}.\] We can thus conclude, \[\begin{align}
\sum_{ L_1 \sim M \gg L_2} \mathcal{I}(L,M) &\leq \sum_{ L_1 \sim M \gg L_2} \left\lVert\chi_{[0,T)} \prod_{j=1}^3 P_{L_j}u_j\right\rVert_{L^2_{t,x}} \left\lVert\chi_{[0,T)} P_M v \prod_{j=4}^5 P_{L_j}u_j\right\rVert_{L^2_{t,x}}, \\
&\lesssim \sum_{ L_1 \sim M \gg L_2 } \left(1+\frac{\log L_2}{\log N}\right)^{c} \prod_{j=1}^5 \left\lVert P_{L_j}u_j\right\rVert_{Y^0}, \\
&\lesssim \left(1+\frac{N^{-s}}{s}\right) \prod_{j=1}^5 \left\lVert u_j\right\rVert_{Y^s} \left\lVert v\right\rVert_{Y^{-s}}. \qedhere
\end{align}\] ◻
Next, we proceed with bounding the growth of the modified energy. Note that if \(u\) is a smooth solution to 1 , then \[\begin{align} \partial_t E^1(u(t)) &= \Re
\int_{\mathbb{T}_\lambda} \overline{\partial_t Iu } \left( \left\lvert Iu\right\rvert^4 Iu - \Delta Iu \right),\\ &= \Re \int_{\mathbb{T}_\lambda} \overline{\partial_t Iu} \left( \left\lvert Iu\right\rvert^4 Iu - I(\left\lvert u\right\rvert^4 u)
\right), \\ &= \Im \int_{\mathbb{T}_\lambda} \left(\overline{\Delta I u}- \overline{I(\left\lvert u\right\rvert^4u)} \right) \left( \left\lvert Iu\right\rvert^4 Iu - I(\left\lvert u\right\rvert^4 u) \right).
\end{align}\] Therefore, by the fundamental theorem of calculus, for any \(t_0 \in \mathbb{R}\) and any \(T>0\), we have
\[\label{eq:32fundamental95theorem95calculus95E1} E^1(u(t_0+T))-E^1(u(t_0)) = \int_{t_0}^{t_0+T} \left(\Lambda_6(u(t)) +\Lambda_{10}(u(t)
\right)\,\,dt,\tag{18}\] where we define \[\begin{align} \Lambda_6(u) &:= \Im \int_{\Gamma_6} M_6(k_1, \dots, k_6) \widehat{\overline{\Delta Iu}} (k_1) \widehat{u}(k_2) \widehat{\overline{u}}(k_3)
\widehat{u}(k_4) \widehat{\overline{u}}(k_5) \widehat{u}(k_6), \\ \Lambda_{10}(u) &:= \frac{i}{2}\int_{\Gamma_{10}} M_{10}(k_1, \dots, k_{10} ) \prod_{j=1}^5 \widehat{u} (k_{2j-1}) \widehat{\overline{u}}(k_{2j}).
\end{align}\] Here the hyperplane \(\Gamma_n=\left\{ (k_1, \dots, k_n) \in \mathbb{Z}_\lambda^n : k_1+\cdots+k_n=0 \right\}\) is endowed with measure \(\prod_{j=1}^{n-1}
(dk_j)_\lambda\) and the multipliers \(M_6: \Gamma_6 \rightarrow \mathbb{R}\) and \(M_{10}: \Gamma_{10} \rightarrow \mathbb{R}\) are given by \[\begin{align} M_6(k_1, \dots, k_6)&:=\prod_{j=2}^6 m(k_j) - m(k_1), \\ M_{10}(k_1,\dots,k_{10}) &:=m(\sum_{j=6}^{10} k_j) \prod_{j=1}^{5} m(k_j)- m(\sum_{j=1}^5 k_j)\prod_{j=6}^{10} m(k_j).
\end{align}\] Our goal is to bound the right-hand side of 18 by using the long-time linear and trilinear Strichartz estimates from Lemma 19 and Lemma 20. The remainder of this section
will focus on proving following estimate.
Lemma 24. Fix \(c>1\) as in Lemma 22 and set \(T := \lambda^2 \log(\lambda
N)^{-c}\). Then, for every \(s>0\) and every \(0<\epsilon \ll_s 1\), there exists a constant \(C=C(s,\epsilon)>1\) such that for any smooth
solution \(u:\mathbb{T}_\lambda\times \mathbb{R}\rightarrow \mathbb{C}\) to 1 and any \(t_0\in \mathbb{R}\), the following estimate holds \[E^1(u(t_0+T)) -E^1(u(t_0)) \leq C N^{-1+\epsilon}\left(\left\lVert Iu\right\rVert_{Y^1_{J_T}}^6+\left\lVert Iu\right\rVert_{Y^1_{J_T}}^{10}\right),\] where \(J_T:=[t_0,t_0+T]\).
We prove Lemma 24 by separately estimating the contributions of \(\Lambda_6\) and \(\Lambda_{10}\) in 18 . To this end, we first we first state a helpful lemma.
Lemma 25. Let \(\mathcal{M}: \Gamma_6 \rightarrow \mathbb{R}\) and suppose there exists an extension \(\widetilde{\mathcal{M}}: \mathbb{R}^6 \rightarrow \mathbb{R}\) satisfying
\[\widetilde{\mathcal{M}}(\xi_1,\dots, \xi_6)= \mathcal{M}(\xi_1, \dots, \xi_6) \text{ for all } (\xi_1, \dots, \xi_6) \in \Gamma_6,\] and for dyadic \(N_1,\dots,N_6\in 2^{\mathbb{N}_0}\)
and all \(0\le\alpha\le7\), there exists a constant \(C_1(N_1,\dots,N_6)>0\) such that \[\sup_{\substack{|\xi_k|\sim N_k\\ 1\le k\le6}} \left\lvert\partial_{\xi_j}^\alpha \widetilde{\mathcal{M}}(\xi_1, \dots, \xi_6)\right\rvert \lesssim_{\alpha} \frac{C_1(N_1,\dots, N_6)}{N_j^\alpha} \text{ for all } 1\leq j \leq 6.
\label{eq:32hypothesis951}\tag{19}\] Moreover, suppose that there exists a constant \(C_2(N_1, \dots, N_6)>0\) such that \[\sup_{x_1, \dots, x_6 \in \mathbb{R}}\int_{0}^T \int_{\mathbb{T}_\lambda} \left\lvert \prod_{j=1}^6 P_{N_j} f_j(x+x_j,t)\right\rvert dx dt \leq C_2(N_1, \dots, N_6) \prod_{j=1}^6 \left\lVert f_j\right\rVert_{Y^0}.
\label{eq:32hypothesis952}\tag{20}\] Then, \[\left\lvert\int_{0}^T \int_{\Gamma_6} \mathcal{M}(k_1,\dots, k_6)\prod_{j=1}^6 P_{N_j} \hat{f}_j(k_j,t) dk_\lambda dt\right\rvert \leq C_3(N_1, \dots, N_6) \prod_{j=1}^6
\left\lVert f_j\right\rVert_{Y^0},\] where \(C_3(N_1, \dots, N_6)\sim C_1(N_1, \dots, N_6)C_2(N_1, \dots, N_6)\).
Proof. This lemma follows from the Fourier series expansion of \(\widetilde{\mathcal{M}}\) followed by Plancherel’s theorem. For details, see Proposition 5.4 and Remark 5.5 in [20]. ◻
By combining Lemma 25 with the long-time Strichartz estimates from Lemmata 19 and 20 we obtain the following estimates.
Lemma 26. Fix \(c>1\) as in Lemma 22 and set \(T := \lambda^2 \log(\lambda
N)^{-c}\). Then, for every \(s>0\) and every \(0<\epsilon \ll_s 1\), there exists a constant \(C=C(s,\epsilon)>1\) such that for any function
\(u: \mathbb{T}_\lambda\times \mathbb{R}\rightarrow \mathbb{C}\) satisfying \(Iu \in Y^1\) and any \(t_0\in \mathbb{R}\), the following estimate holds \[\left\lvert\int_{t_0}^{t_0+T} \Lambda_6(u(t)) \,\, dt \right\rvert\leq C N^{-1+\epsilon}\left\lVert Iu\right\rVert_{Y^1}^6.\]
Proof. Without loss in generality, we may assume \(t_0=0\). We dyadically decompose \(u = \sum_{j\geq 1} u_j\) where \(u_j:=P_{N_j} u\) for
dyadic \(N_j \in 2^{\mathbb{N}_0}\). With this decomposition in hand, it suffices to prove that \[\sum_{N_1, \dots N_6} \left\lvert\int_0^T \int_{\Gamma_6} M_6 \widehat{\overline{\Delta Iu}}_1
\widehat{u}_2 \widehat{\overline{u}}_3 \widehat{u}_4 \widehat{\overline{u}}_5 \widehat{u}_6\right\rvert \lesssim N^{-1+} \left\lVert Iu\right\rVert_{Y^1}^6.\] We will use Lemma 25 to prove the above estimate. As left-hand side of 20 is invariant under complex conjugation and \(M_6\) is symmetric under permutations of
\(k_2, \dots, k_6\), we may assume without loss of generality that \(N_2 \geq \cdots \geq N_6\). Furthermore, since we are integrating on \(\Gamma_6\), \(N_1 \lesssim N_2\) also holds. We also stress that \(M_6\) vanishes unless \(N_2 \gtrsim N\). Thus we split the summation into two cases: (a) \(N_3 \ll N \lesssim N_2\) and (b) \(N_2 \geq N_3 \gtrsim N\).
For case (a), we have that \(N_1 \sim N_2 \gtrsim N \gg N_3\) and \(k_1k_2<0\). We write \(M_6(k_1, \dots, k_6) = m(k_2)-m(k_2+\dots+k_6)\) and note
that by the mean value theorem, \[\left\lvert m(k_2)-m(k_2+\dots+k_6)\right\rvert \lesssim \left\lvert k_3+\dots+k_6\right\rvert m'(N_2) \lesssim \frac{N_3}{N_2} m(N_2).\] Using a similar argument, we can bound the
partial derivatives by the same bound and conclude that \(C_1(N_1,\dots, N_6) \lesssim \frac{N_3}{N_2}m(N_2)\) where \(C_1\) is the constant defined in hypothesis 19 of Lemma 25. We next use Hölder’s inequality followed by Lemma 19, to obtain \[\begin{align}
\int_0^T \int_{\mathbb{T}_\lambda} \left\lvert\Delta I u_1 \prod_{j=2}^6 u_j\right\rvert &\leq \left\lVert\chi_{[0,T)}\Delta Iu_1\right\rVert_{L^6_{t,x}} \prod_{j=2}^6 \left\lVert\chi_{[0,T)}u_j\right\rVert_{L^6_{t,x}} \\
&\lesssim N_2^{0+}\left\lVert\Delta Iu_1\right\rVert_{Y^0} \prod_{j=2}^6 \left\lVert u_j\right\rVert_{Y^0}.
\end{align}\] Note that since Strichartz estimate are translation invariant, we conclude that \(C_2(N_1, \dots, N_6) \lesssim N_2^{0+}\) where \(C_2\) is the constant defined in
hypothesis 20 of Lemma 25. Therefore, by Lemma 25, we have shown that when \(N_3 \ll N \lesssim N_2\), we have the estimate \[\begin{align} \left\lvert\int_0^T \int_{\Gamma_6} M_6
\widehat{\overline{\Delta Iu}}_1 \widehat{u}_2 \widehat{\overline{u}}_3 \widehat{u}_4 \widehat{\overline{u}}_5 \widehat{u}_6\right\rvert &\lesssim N_2^{0+}\frac{N_3}{N_2} m(N_2) \left\lVert\Delta Iu_1\right\rVert_{Y^0} \prod_{j=2}^6 \left\lVert
u_j\right\rVert_{Y^0} \\ &\lesssim N_2^{0+}\frac{N_3}{N_2}\frac{N_1}{N_2N_3N_4N_5N_6} \prod_{j=1}^6 \left\lVert Iu_j\right\rVert_{Y^1} \\ &\lesssim N^{-1+}N_2^{0-} \prod_{j=1}^6 \left\lVert Iu_j\right\rVert_{Y^1_T},
\end{align}\] where the second line follows by noting that \(N_3 \ll N\) and so \(m(N_j)=1\) for \(j=3,4,5,6\). The last line follows since \(N_1 \sim N_2 \gtrsim N\) and \(N_4,N_5, N_6 \geq 1\). The desired bound is then obtained by summing geometric progressions.
Now consider case (b): \(N_3 \gtrsim N\) and further split the summation into two sub-cases (i) \(N_3 \sim N_2\) and (ii) \(N_3 \ll N_2 \sim N_1\). For
both sub-cases, we have the trivial bound \[\left\lvert M_6(k_1, \dots, k_6)\right\rvert \lesssim m(k_1)\] and the same upper bound holds for the partial derivatives so \(C_1(N_1,\dots, N_6)
\lesssim m(N_1)\) where \(C_1\) is the constant defined in hypothesis 19 of Lemma 25.
For sub-case (b)(i): \(N_2 \sim N_3 \gtrsim N\), we proceed in the similar way as we did in case (a) to obtain \(C_2(N_1, \dots, N_6) \lesssim N_2^{0+}\) where \(C_2\) is the constant defined in hypothesis 20 of Lemma 25. An application of Lemma
25 yields, \[\begin{align} \left\lvert\int_0^T \int_{\Gamma_6} M_6 \widehat{\overline{\Delta Iu}}_1 \widehat{u}_2
\widehat{\overline{u}}_3 \widehat{u}_4 \widehat{\overline{u}}_5 \widehat{u}_6\right\rvert &\lesssim N_2^{0+}m(N_1) \left\lVert\Delta Iu_1\right\rVert_{Y^0_T} \prod_{j=2}^6 \left\lVert u_j\right\rVert_{Y^0_T} \\ &\lesssim
N_2^{0+}\frac{m(N_1)N_1}{\prod_{j=2}^6 N_jm(N_j)} \prod_{j=1}^6 \left\lVert Iu_j\right\rVert_{Y^1_T} \\ &\lesssim N^{-1+}N_2^{0-} \prod_{j=1}^6 \left\lVert Iu_j\right\rVert_{Y^1_T},
\end{align}\] where in the last line we used the fact \(m(N_j)N_j^{1-\epsilon} \gtrsim \min(N,N_j)^{1-\epsilon}\) for every \(\epsilon \in [0,s]\). We then obtain the desired bound by
summing geometric progressions.
Next consider sub-case (b)(ii): \(N_1 \sim N_2 \gg N_3 \gtrsim N\). Here we cannot use the same bounding strategy as sub-case (b)(i) as \(N_2 \gg N_3\) and the derivative loss of \(N_2^{0+}\) cannot be removed by the \(N_3\) factor. Instead, we use Hölder’s inequality followed by the trilinear estimate from Lemma 20 to obtain \[\begin{align} \int_0^T \int_{\mathbb{T}_\lambda} \left\lvert\Delta I u_1 \prod_{j=2}^6 u_j\right\rvert &\leq
\left\lVert\chi_{[0,T)}\Delta Iu_1 u_3 u_4\right\rVert_{L^2_{t,x}} \left\lVert\chi_{[0,T)}u_2 u_5 u_6\right\rVert_{L^2_{t,x}}, \\ &\leq \prod_{j=3}^4 \left\lVert\chi_{[0,T)}\Delta Iu_1 u_j^2 \right\rVert_{L^2_{t,x}}^\frac{1}{2} \prod_{j=5}^6
\left\lVert\chi_{[0,T)}u_2 u_j^2 \right\rVert_{L^2_{t,x}}^\frac{1}{2}, \\ &\lesssim N_3^{0+} \left\lVert\Delta Iu_1\right\rVert_{Y^0_T} \prod_{j=2}^6 \left\lVert u_j\right\rVert_{Y^0}.
\end{align}\] Hence, an application of Lemma 25 yields \[\begin{align} \left\lvert\int_0^T \int_{\Gamma_6} M_6
\widehat{\overline{\Delta Iu}}_1 \widehat{u}_2 \widehat{\overline{u}}_3 \widehat{u}_4 \widehat{\overline{u}}_5 \widehat{u}_6\right\rvert &\lesssim N_3^{0+} m(N_1) \left\lVert\Delta Iu_1\right\rVert_{Y^0_T} \prod_{j=2}^6 \left\lVert
u_j\right\rVert_{Y^0_T}, \\ &\lesssim N_3^{0+}\frac{m(N_1)N_1}{\prod_{j=2}^6 N_jm(N_j)} \prod_{j=1}^6 \left\lVert Iu_j\right\rVert_{Y^1_T}, \\ &\lesssim N^{-1+}N_3^{0-} \prod_{j=1}^6 \left\lVert Iu_j\right\rVert_{Y^1_T}.
\end{align}\] We conclude by summing geometric progressions and observing that \(N_1 \sim N_2\), so the lack of decay in \(N_2\) is harmless. ◻
Lemma 27. Fix \(c>1\) as in Lemma 22 and set \(T := \lambda^2 \log(\lambda
N)^{-c}\). Then, for every \(s>0\) and every \(0<\epsilon \ll_s 1\), there exists a constant \(C=C(s,\epsilon)>1\) such that for any function
\(u: \mathbb{T}_\lambda\times \mathbb{R}\rightarrow \mathbb{C}\) satisfying \(Iu \in Y^1\) and any \(t_0\in \mathbb{R}\), the following estimate holds \[\left\lvert\int_{t_0}^{t_0+T} \Lambda_{10}(u(t)) \,\, dt \right\rvert\leq C N^{-2+\epsilon}\left\lVert Iu\right\rVert_{Y^1}^{10}.\]
Proof. Just as in the proof of Lemma 26, it suffices to consider \(t_0=0\). We dyadically decompose \(u = \sum_{j\geq 1} u_j\) where \(u_j:=P_{N_j} u\) for dyadic \(N_j \in 2^{\mathbb{N}_0}\). Let \(N_1^\star \geq \cdots \geq
N_{10}^\star\) denote the decreasing ordering of \((N_1, \dots, N_{10})\) and define \(u_j^\star:=P_{N_j^\star}u\). We will prove that, \[\sum_{N_1, \dots,
N_{10}} \left\lvert\int_0^T \int_{\Gamma_6} M_{10}\widehat{u}_1 \widehat{\overline{u}}_2 \widehat{u}_3 \widehat{\overline{u}}_4 \widehat{u}_5 \widehat{\overline{u}}_{6} \widehat{u}_7 \widehat{\overline{u}}_8
\widehat{u}_{9}\widehat{\overline{u}}_{10}\right\rvert \lesssim N^{-2+} \left\lVert Iu\right\rVert_{Y^1}^{10}.\] First note that \(M_{10}\) vanishes unless \(N_1^\star \gtrsim N\).
Therefore, since we are integrating in \(\Gamma_{10}\) we may restrict the summation to \(N_1^\star \sim N_2^\star \gtrsim N\). Next, by the triangle inequality, it suffices to show that,
\[\max_{j=1,2} \sum_{N_1, \dots, N_{10}} \left\lvert\int_0^T \int_{\Gamma_6} M_{10}^{(j)}\widehat{u}_1 \widehat{\overline{u}}_2 \widehat{u}_3 \widehat{\overline{u}}_4 \widehat{u}_5 \widehat{\overline{u}}_{6} \widehat{u}_7
\widehat{\overline{u}}_8 \widehat{u}_{9}\widehat{\overline{u}}_{10}\right\rvert \lesssim N^{-2+} \left\lVert Iu\right\rVert_{Y^1}^{10},\] where \[M_{10}^{(j)}(k_1,k_2, \dots, k_{10}):= m\left(\sum_{l \in J_j} k_l\right)
\prod_{l \in J_j^c} m(k_l),\]\(J_{1}:= \{6, \dots 10\},\)\(J_{2}:=\{1,\dots 5\}\) and \(J_j^c\) denotes the complement of \(J_j\) in \(\{1,\dots, 10\}.\) We view \(M_{10}^{(j)}\) as a multiplier acting on \(\Gamma_6\) and apply Lemma 25. By symmetry, it suffices to consider \(j=1\). To this end, we further decompose the summation \[\sum_{N_1, \dots, N_{10},K } \left\lvert\int_0^T \int_{\Gamma_6} M_{10}^{(1)}\widehat{u}_1 \widehat{\overline{u}}_2 \widehat{u}_3 \widehat{\overline{u}}_4 \widehat{u}_5 \widehat{f}_K\right\rvert:= \sum_{N_1, \dots, N_{10},K }
\mathcal{I}(N_1, \dots, N_{10}, K) ,\] where \(\hat{f}_K(k):= \sum_{\substack{ k_6+\dots+ k_{10}=k \\ \left\lvert k\right\rvert \sim K}} \widehat{\overline{u}}_6(k_{6}) \widehat{u}_7(k_{7}) \widehat{\overline{u}}_8(k_{8})
\widehat{u}_9(k_{9}) \widehat{\overline{u}}_{10}(k_{10})\). By the invariance of left-hand side in hypothesis 20 under complex conjugation together with the permutation symmetry of \(M_{10}^{(1)}\), we may further restrict the summation to \(N_1 \geq N_2 \geq \cdots \geq N_5\) and \(N_6 \geq N_7 \geq \cdots \geq N_{10}\). We split the
summation into two cases: (a) \(N_1^\star=N_1, N_2^\star=N_2\) and (b) at least one of \(N_1^\star, N_2^\star\) lies in \(\{N_6, \dots, N_{10}\}\).
In both case we have the trivial bound \(m(K) \leq 1\), so it is clear that \[\left\lvert M_{10}^{(1)}(k_1, \dots, k_{10})\right\rvert \leq \prod_{j=1}^{5} m(N_j),\] and analogous bounds
hold for the partial derivatives, so that \[C_1(N_1, \dots, N_5, K) \lesssim \prod_{j=1}^{5} m(N_j),\] where \(C_1\) is the constant defined in hypothesis 19 of Lemma 25.
Next consider case (a): \(N_1^\star=N_1, N_2^\star=N_2\). By Hölder’s inequality followed by Lemma 20, we have that,
Therefore, by Lemma 25 we obtain \[\begin{align} \mathcal{I} &\lesssim N_1^{0+} \left(N_4 N_5 N_9
N_{10}\right)^{1/2} \prod_{j=1}^{5} \left\lVert Iu_j\right\rVert_{Y^0} \prod_{j=6}^{10} \left\lVert u\right\rVert_{Y^0}, \\ &\lesssim N_1^{0+} \frac{\left(N_4 N_5 N_9 N_{10}\right)^{1/2}}{\prod_{j=1}^5 N_j \prod_{j=6}^{10} m(N_j)N_j} \prod_{j=1}^{10}
\left\lVert Iu_j\right\rVert_{Y^1}, \\ &\lesssim N_1^{0+} \frac{m(N_1)m(N_2)}{m(N_1) N_1 m(N_2) N_2 m(N_9) N_9^{\frac{1}{2}} m(N_{10}) N_{10}^{\frac{1}{2}}} \prod_{j=1}^{10} \left\lVert Iu_j\right\rVert_{Y^1}, \\ &\lesssim N^{-2+} N_1^{0-}
\prod_{j=1}^{10}\left\lVert Iu_j\right\rVert_{Y^1},
\end{align}\] where the third line follows from the fact that \(m(N_j)N_j^{1-\epsilon} \gtrsim \min(N,N_j)^{1-\epsilon}\) for all \(\epsilon \in [0,s]\) and the last line follows from
the aforementioned fact and since \(N_1 \sim N_2 \geq N_9 \geq N_{10}\) implies that \(m(N_1) \sim m(N_2) \leq m(N_9) \leq m(N_{10})\). Summing geometric progressions concludes the proof for
case (a).
We now turn to case (b): at least one of \(N_1^\star, N_2^\star\) lies in \(\{N_6, \dots, N_{10}\}\). Here we use Hölder’s inequality again but the derivative loss is placed at the
frequencies \(N_2, \dots, N_5\) where it can be compensated by the \(m(N_2) \cdots m(N_5)\) gain. In fact,
\[\begin{align}
\int_0^T \int_{\mathbb{T}_\lambda} \left\lvert\prod_{j=1}^{5} u_j\, f_K\right\rvert
&\le \Bigl\| \prod_{j=1}^5 \chi_{[0,T)} u_j \Bigr\|_{L^6_{t,x}} \, \| \chi_{[0,T)} f_K \|_{L^\frac{6}{5}_{t,x}}, \\
&\le \|\chi_{[0,T)} u_1\|_{L^6_{t,x}} \prod_{j=2}^5 \|\chi_{[0,T)} u_j\|_{L^\infty_{t,x}} \prod_{j=6}^{10} \|\chi_{[0,T)} u_j\|_{L^6_{t,x}}, \\
&\lesssim \left(N_1^\star\right)^{0+} \left(N_2 N_3 N_4 N_{5}\right)^{1/2} \prod_{j=1}^{10} \|u_j\|_{Y^0}.
\end{align}\] An application of Lemma 25 and an analogous argument to the one used above conclude the proof. ◻
We are now in a position to prove Theorem 2 using Lemmata 22 and 24. Let \(u: \mathbb{T}\times \mathbb{R}\rightarrow \mathbb{C}\) denote the
solution to 1 with initial condition \(u_0 \in H^s(\mathbb{T})\). By assumption, \(u_0\) has small mass, so we rescale the initial data so that \(Iu_0^\lambda\) has small \(H^1\)-norm, where \[u_0^\lambda= \lambda^{-\frac{1}{2}}u_0\left(\frac{x}{\lambda}\right),\] and \(u^\lambda
: \mathbb{T}_\lambda \times \mathbb{R}\rightarrow \mathbb{C}\) denotes the corresponding solution to 1 with initial data \(u_0^\lambda\).
Applying Lemma 22 yields a bound for the \(H^1\) norm of \(Iu^\lambda(t)\) for all \(t \in [0,T_0]\) for some fixed \(T_0>0\). The strategy is to iterate this local result: we use Lemma 24 to bound the growth of the modified energy \(E^1(u^\lambda(t))\) on \([0,T_0]\) which in turn controls the \(\dot{H}^s\)-norm of \(Iu^\lambda(T_0)\). Combined with the conservation of mass, this provides uniform control of the \(H^s\) norm of \(Iu^\lambda(T_0)\) for sufficiently large \(N\), allowing Lemma 22 to be applied successively with
initial condition \(Iu^\lambda(T_0)\). By repeating this argument and reversing the rescaling, we extend the original solution \(u\) globally in time by letting \(N
\rightarrow \infty\). We now turn to details.
Proof of Theorem 2. Suppose that \(0<s<1\) and let \(u_0 \in
H^s(\mathbb{T})\) be such that \(\left\lVert u_0\right\rVert_2 = \delta\) where \(0<\delta < 1\). Let \(u^\lambda\) denote the solution to (1 ) with initial condition \(u^\lambda(x,0)=u^\lambda_0(x):= \lambda^{-\frac{1}{2}} u_0(\frac{x}{\lambda})\). We stress that \(u^\lambda_0 : \mathbb{T}_\lambda \rightarrow
\mathbb{C}\) whereas \(u_0: \mathbb{T}\rightarrow \mathbb{C}\) and hence all \(L^p\) norms (\(p \geq 1\)) in the remainder of the proof are defined on
the appropriate domain (\(\mathbb{T}_\lambda\) for \(u^\lambda_0\) and \(\mathbb{T}\) for \(u_0\)).
We select \(\lambda \sim_s N^{\frac{1-s}{s}} \left\lVert u_0\right\rVert_{\dot{H}^s}^{\frac{1}{s}} \left\lVert u_0\right\rVert_2^{-\frac{1}{s}}\) such that \(E^1(u_0^\lambda) \leq 2 \left\lVert
u_0\right\rVert_2^2\). In particular note that \[\left\lVert\partial_x Iu_0^\lambda\right\rVert_{2}^2=\left\lVert m(k) k \hat{u}_0^\lambda\right\rVert_{L^2((dk)_\lambda)}^2 \lesssim \frac{N^{2-2s}}{\lambda^{2s}}
\left\lVert u_0\right\rVert_{\dot{H}^s}^2 \lesssim \left\lVert u_0\right\rVert_2^2,\] and by the Gagliardo-Nirenberg inequality [27], \[\begin{align} \left\lVert Iu_0^\lambda\right\rVert_{6}^6 &\lesssim \left\lVert\partial_xIu_0^\lambda\right\rVert_{2}^{2} \left\lVert Iu_0^\lambda\right\rVert_{2}^{4} + \left\lVert Iu_0^\lambda\right\rVert_{2}^{6}, \notag \\
&\lesssim \frac{N^{2-2s}}{\lambda^{2s}} \left\lVert u_0\right\rVert_{\dot{H}^s}^{2}\left\lVert u_0\right\rVert_{2}^{4}+\left\lVert u_0\right\rVert_{2}^{6}, \notag\\ &\lesssim \left\lVert u_0\right\rVert_2^6.
\end{align}\] Therefore, since \(E^1(u_0^\lambda) \leq 2 \delta^2\), we have \[\left\lVert Iu_0^\lambda\right\rVert_{H^1}^2 \leq \left\lVert Iu_0^\lambda\right\rVert_2^2+E^1(u_0^\lambda)
\leq 3\delta^2.\] We select \(\delta \ll 1\) small enough and \(N=N(s,\delta) \gg 1\) large enough so that Lemma 22 can be applied and let \(T_0\sim \lambda^{2}\log(\lambda N)^{-c}\). Next, by Lemma 24, we have that \[\begin{align} E^1(u^\lambda(T_0)) &\leq E^1(u^\lambda(0)) + C_1 N^{-1+} \left(\left\lVert Iu^\lambda\right\rVert_{Y^1_{T_0}}^6+\left\lVert
Iu^\lambda\right\rVert_{Y^1_{T_0}}^{10}\right), \\ &\leq 2\delta^2+C_2 N^{-1+}\delta^6,
\end{align}\] where the second line follows from Lemma 22 and \(C_1, C_2 >0\) are constants depending on \(s\). By possibly increasing \(N=N(s,\delta) \gg 1\) one can ensure that \(E^1(u^\lambda(T_0)) \leq 3\delta^2\) so that Lemma 22 can be applied once more on the subsequent interval \([T_0,2T_0]\). We can repeat this process and obtain solutions satisfying \[\left\lVert Iu^\lambda(nT_0)\right\rVert_{H^1} \leq 2\delta,\] as long as \(n \ll N^{1-}\). Undoing the rescaling, the corresponding solutions to 1 satisfy \[\begin{align} \left\lVert u(t)\right\rVert_{H^s(\mathbb{T})}^2 &= \left\lVert u_0\right\rVert_2^2+ \lambda^{2s} \left\lVert u^\lambda(t\lambda^{2})\right\rVert_{\dot{H}^s(\mathbb{T}_\lambda)}^2, \\ &\lesssim \left(1
+\lambda^{2s}\right) \delta^2. \\ &\lesssim \left(1 + N^{2(1-s)}\right) \left\lVert u_0\right\rVert_{H^s(\mathbb{T})}^2.
\end{align}\] for \(t\in [0,T]\) where \(T \sim N^{1-}\log(N)^{-c}\). Therefore, we deduce that solutions can be continued for arbitrary time intervals by selecting \(N \rightarrow \infty\). ◻
6 Refined Trilinear Strichartz Estimates via Decoupling↩︎
In this appendix, we give an alternative proof of the refined trilinear Strichartz estimate first established in [1].
Theorem 19. For every \(\epsilon>0\) there exists a constant \(C_\epsilon>0\) such that for all \(N_1 \gg N_2 \geq 1\), all \(N_1^{-1} \leq T \leq 1\) and all \(\phi_1,\phi_2 \in L^2(\mathbb{T})\) with \(\mathop{\mathrm{supp}}\hat{\phi}_j \subset [N_j,2N_j]\), \(j=1,2\), the following estimate holds, \[\left\lVert S(t)\phi_1\left(S(t) \phi_2\right)^2\right\rVert_{L^2_{t,x}([0,T] \times \mathbb{T})}^2 \leq C_\epsilon N_2^\epsilon
\left(T^{1/2}+\frac{N_2}{N_1}\right)\|\phi_1\|_2^2 \|\phi_2\|_2^4.\]
The corresponding result in [1] is stronger, as it does not contain the \(N_2^\epsilon\) loss. Their proof uses number-theoretic methods, whereas ours uses decoupling tools. Thus, our method allows more flexible choices of the locations for the frequencies. We include an alternative proof here for
completeness and to highlight our method, which may be useful in higher-dimensional settings.
We shall show that Theorem 20 follows quickly from the asymmetric estimate in Lemma 13 by combining it with
an induction argument similar to the one in [32]. We also emphasize that Theorem 20 is sharp by considering Example 1 and Example 2.
By a standard rescaling and periodization argument, it suffices to establish the following decoupling estimate.
Theorem 20. Let \[\Gamma_1, \Gamma_2 \subseteq N_{1/R}(\mathcal{P})\] be two caps with \(l(\Gamma_i)=L_i \leq 1\) such that \(dist(\Gamma_1,\Gamma_2)
\sim 1\). Let \(f_1\) and \(f_2\) be two functins with \[\boldsymbol{supp }\,\widehat{f_i} \subseteq \Gamma_i,
\qquad
f_i = \sum_{\gamma \subseteq \Gamma_i} f_\gamma,\] where each \(f_\gamma\) satisfies the following:
\(\boldsymbol{supp }\,\widehat{f_\gamma} \subset \gamma\) a cap of radius \(1/N\) on \(N_{1/R}(\mathcal{P})\).
For each \(\gamma\), \[|f_\gamma| \sim a_\gamma \quad \text{on } B_R,\] for some \(a_\gamma \in \mathbb{R}\) and \(f_\gamma\) decays rapidly off \(B_R\).
Assume also that \(N \leq R \leq N^2\). Then, for any \(\epsilon>0\), there exists a constant \(C_\epsilon\) such that \[\begin{align} \fint_{B_R} & |f_1|^2 |f_2|^4 \\ &\leq C_\epsilon \,(L_2 N R)^{\epsilon} \max\!\left( L_2, \frac{\sqrt{R}}{N} \right) \frac{N^2}{R}\Bigg(\sum_{\gamma \in \Gamma_1} |a_{\gamma}|^2 \Bigg) \Bigg(\sum_{\gamma \in
\Gamma_1} |a_{\gamma}|^2 \Bigg)^{2}.
\end{align}\]
We see that lemma 20 is sharp up to a \((L_2NR)^\epsilon\) factor, if we consider the following two examples. In both examples, we shall let \(a_\xi=1\) for all \(\xi \in \Xi_1\) and \(\Xi_2\). Put \[g_1(x,t):=\sum_{j=1}^{L_1N}e(\frac{j}{N}x+\frac{j^2}{N^2}t) \text{ and
}g_2(x,t):=\sum_{j=N}^{N+L_2N}e(\frac{j}{N}x+\frac{j^2}{N^2}t).\]
Example 1. Let \(L_1=L_2^2\geq 1/N.\) Note that \(g_i(k/N)\sim L_iN\) for integers \(k\). As \(g_i\) has Fourier
support in a \(L_i \times L_i^2\) rectangle, we know that \(g_i\) is locally constant on \(L_i^{-1} \times L_i^{-2}\) tubes whose long axes are in the same
direction as \(d(\Gamma_i)\) where \(d(\Gamma_i)\) is the direction of the normal to the paraboloid at the center of \(\Gamma_i\). Thus, on \(R/N\) many \(L_2^{-1} \times L_2^{-2}\) tubes in \(B_R\), we have \(g_i \sim L_iN\). Thus, \[\begin{align} &&\fint_{B_R}|\sum_{\xi\in \Xi_1}a_{\xi}e((x,t)\cdot (\xi,\xi^2))|^2|\sum_{\xi\in \Xi_2}a_{\xi}e((x,t)\cdot (\xi,\xi^2))|^4\\ &\geq & L_2^{-3}\left(\frac{R}{N}\right)(L_1N)^2(L_2N)^4\\ &\sim&
L_2N^2/R (\sum_{\xi\in \Xi_1}|a_{\xi}|^2)(\sum_{\xi\in \Xi_1}|a_{\xi}|^2)^2.
\end{align}\]
Example 2. Let \(L_1=L_2= R^{-1/2}.\) Note that \(g_i(k/N)\sim L_iN\) for integers \(k\). We know that \(g_i\)
is locally constant on a \(R \times R^{1/2}\) tube whose long axis is in the same direction as \(d(\Gamma_i)\) where \(d(\Gamma_i)\) is the direction of the
normal to the paraboloid at the center of \(\Gamma_i\). Thus, on \((R/N)^2\) many \(R^{1/2} \times R^{1/2}\) squares, we have \(g_i
\sim L_iN\). Thus, \[\begin{align} &&\fint_{B_R}|\sum_{\xi\in \Xi_1}a_{\xi}e((x,t)\cdot (\xi,\xi^2))|^2|\sum_{\xi\in \Xi_2}a_{\xi}e((x,t)\cdot (\xi,\xi^2))|^4\\ &\geq &
(R^{1/2})^2\left(\frac{R}{N}\right)^2(L_1N)^2(L_2N)^4\\ &\sim& (N/\sqrt{R}) (\sum_{\xi\in \Xi_1}|a_{\xi}|^2)(\sum_{\xi\in \Xi_1}|a_{\xi}|^2)^2.
\end{align}\]
We shall focus on the special case when we are in the situation such that for each \(\gamma\) either \(a_\gamma \sim 1\) or \(a_\gamma=0\). In this case,
we say that \(f_1\) and \(f_2\) satisfy \(\text{Cond}(L_1,L_2)\). The general case would just follow from it from a standard pigeonholing argument, giving
rise to an extra \(\log R\) loss.
Definition 11. Define \(D(L_1,L_2,R,N)\) to be the smallest constant such that for any \((R,1/M)\) normalized \((f_1,f_2)\) satisfying \(\text{Cond}(L_1,L_2)\), we have \[\label{maineq} \int_{B_R}|f_1|^2|f_2|^4\lesssim D(L_1,L_2,R,N)\lambda_1 \lambda_2^2R^2.\tag{21}\]
To prove Theorem 20, it is enough to prove \(D(L_1,L_2,R,N)\lessapprox \max(L_2, \sqrt{R}/N) \frac{N^2}{R}\). To do so, we shall bound \(|U_{a,b}(f_1,f_2)|a^2b^4\) for the case when \(b\) is big and when \(b\) is small separately.
Suppose that \(b \geq R^\epsilon \lambda_2 \lambda_2(R^{-1/2})^{-1/2}\), then Lemma 13 implies that \[|U_{a,b}(f_1,f_2)|a^2b^4 \lessapprox \max\!\left( L_2, \frac{\sqrt{R}}{N} \right) \frac{N^2}{R}\lambda_1 \lambda_2^2.\] Suppose that \(b \leq R^\epsilon \lambda_2 \lambda_2(R^{-1/2})^{-1/2}\),
Lemma 2 immediately implies the following bound on \(|U_b(f_2)|b^6\).
Lemma 28. Suppose that \(b \leq R^\epsilon \lambda_2 \lambda_2(R^{-1/2})^{-1/2}\), then \[b^6|B_b| \lesssim_\epsilon R^{O(\epsilon)} N/\sqrt{R}\lambda_2^3R^2.\]
Next, we prove the following lemma relating \(D(L_1,L_2,R,N)\) to \(D(L_2^2,L_2,R,N)\).
Proof. As \(D(L_1,L_2,R,N)\) is monotonically increasing in \(L_1\) it is enough to prove the case when \(L_1 \geq L_2^2\). In the definition of
\(D(L_1,L_2,R,N)\), let’s replace \(e^{it\Delta}f_i\eta_{B_R}\) by \(g_i\) to simplify the notation. Thus, our goal is to prove that \[\int |g_1|^2|g_2|^4 \lesssim \sum_{\tau\subseteq \Gamma_1}\int|g_{1,\tau}|^2|g_2|^4\] where we break \(\Gamma_1\) into caps \(\tau\) of length \(L_2^2\). \[\begin{align} &&\int |g_1|^2|g_2|^4\\ &=&\int \widehat{|g_1|^2}\widehat{|g_2|^4} \text{ by Plancherel }\\ &=&\sum_{\tau \subseteq \Gamma_1}\sum_{\tau' \subseteq
\Gamma_1}\int \widehat{g_\tau}*\widehat{\overline{g_{\tau'}}}\widehat{|g_2|^4}
\end{align}\] In order for the integrand to be non-zero, we need \[\tau-\tau' \cap \boldsymbol{supp }\widehat{|g_2|^4}\not=\emptyset.\] Note that \(\boldsymbol{supp }\widehat{|g_2|^4}
\subseteq \Gamma_2+\Gamma_2-\Gamma_2-\Gamma_2\) which is contained in a \(O(L_2) \times O(L_2^2)\) rectangle whose long axis is in direction \(d(\Gamma_2)\). As \(d(\Gamma_1)\) is transversal to \(d(\Gamma_2)\), we need \(|c(\tau)-c(\tau')| \lesssim L_2^2\). In this case, we call \(\tau\sim
\tau'\). Thus, \[\begin{align} \int |g_1|^2|g_2|^4 &=\sum_{\tau \subseteq \Gamma_1}\sum_{\tau' \sim \tau}\int \widehat{g_\tau}*\widehat{\overline{g_{\tau'}}}\widehat{|g_2|^4} \\ &=\sum_{\tau \subseteq
\Gamma_1}\sum_{\tau' \sim \tau}\int g_\tau\overline{g_{\tau'}}|g_2|^4 \\ &\lesssim\int |g_\tau|^2|g_2|^4. \qedhere
\end{align}\] ◻
Combining the two lemmas above, we obtain the following inductive relation.
Lemma 30. Suppose that \(b \leq R^\epsilon \lambda_2 \lambda_2(R^{-1/2})^{-1/2}\), then \[|U_{a,b}|a^2b^4 \lesssim_\epsilon R^{o(\epsilon)} (D(L_2,L_2^2))^{1/2}(N/\sqrt{R})^{1/2}
\lambda_1\lambda_2^2R^2.\]
The authors would like to thank Professor Larry Guth for his unwavering support and helpful suggestions throughout the preparation of this paper. This work was completed under his guidance. The authors are also grateful to Professor Gigliola Staffilani
for many helpful discussions and valuable insights related to this work. In addition, [NS] would like to thank his thesis supervisor, Professor Alexandre Megretski, for his continued support, guidance, and encouragement throughout this project.
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