Hubbard–Heisenberg Thermodynamic Comparison at Half Filling in a Fixed Staggered Field


Abstract

We study the repulsive Hubbard model at half filling in the strong-coupling regime, with a staggered magnetic field of strength \(h\). The analysis is carried out in the canonical half-filled ensemble, with temperature measured on the Heisenberg scale \(J_0(U)=4t^2/U\). Uniformly for \(|h|\le h_0\) and \(\beta J_0(U)\ge \ell_0\), we prove finite-volume Hubbard–Heisenberg pressure estimates with errors uniform in the system size. These estimates pass to thermodynamic limits whenever the limiting pressures exist.

The proof uses a strong-coupling unitary transformation which separates the singly occupied spin sector from sectors containing empty or doubly occupied sites. On the singly occupied sector, the effective Hamiltonian is compared with the Heisenberg reference Hamiltonian; the remaining sectors are controlled through a decomposition of the transformed partition function according to the set of empty or doubly occupied sites. For fixed positive staggered-field windows \(I\Subset(0,h_0]\), the magnetisation comparison is then derived from the pressure comparison by convexity of finite-volume pressures.

We also prove charge-sector suppression estimates, uniformly for \(|h|\le h_0\): in the large positive-\(U\) Heisenberg-scale regime, the density of empty or doubly occupied sites and the double-occupancy density are small, and the squared staggered charge divided by \(|\Lambda|^2\) is small. Thus the results give a quantitative Gibbs-state formulation of the strong-coupling picture in which the half-filled repulsive Hubbard model is described, at the Heisenberg scale, by effective antiferromagnetic spin degrees of freedom, while charge fluctuations are suppressed.

1 Introduction and main results↩︎

1.1 Background and purpose↩︎

The Hubbard model is one of the simplest lattice models for interacting electrons, yet it has remained a central object in mathematical physics and condensed matter theory for many decades. It was introduced as a model for electron correlations in narrow bands [1], and has since been used as a basic framework for studying Mott physics, magnetism, and the competition between spin and charge degrees of freedom; see also the exact one-dimensional solution of Lieb and Wu [2]. Its magnetic properties have motivated several rigorous approaches. Important examples include Nagaoka-type ferromagnetism, Lieb’s spin-reflection-positivity approach to the half-filled bipartite model, and flat-band or nearly-flat-band mechanisms for itinerant ferromagnetism [3][6]. Rigorous analyses of Hubbard-type systems have also been developed from other viewpoints, for example by constructive renormalization group methods in the half-filled honeycomb Hubbard model [7].

Despite these developments, rigorous results for physically natural regimes remain rather limited. The difficulty is not caused by a complicated definition of the model. Rather, it comes from the delicate interplay between electron itinerancy, spin degrees of freedom, and the local Coulomb repulsion: the same hopping term which favours delocalisation also competes with the strong on-site repulsion and generates effective magnetic interactions.

In this paper we study the repulsive Hubbard model at half filling in the strong-coupling regime. The expected physical picture is simple: when \(U\gg |t|\), charge fluctuations are energetically suppressed and the remaining low-energy thermodynamics in the singly occupied sector is governed by an antiferromagnetic spin model. More precisely, virtual hopping processes of second order in \(t/U\) produce the superexchange scale \[J_0(U):=\frac{4t^2}{U}.\] Thus the natural reference model is the spin-\(\frac{1}{2}\) Heisenberg model with exchange constant \(J_0(U)\). The point of the present work is to give a quantitative mathematical formulation of this perturbative picture at the level of finite-volume canonical Gibbs states. We do not only identify the second-order effective interaction; we control the higher-order effective remainder and the charge-defect contribution with error bounds uniform in the volume and in fixed positive-field windows. In this way, the formal Hubbard-to-Heisenberg reduction is upgraded to a volume-uniform comparison of canonical thermodynamic quantities.

From the viewpoint of phase diagrams, the charge-sector estimates are also part of the significance of the result. In attractive or charge-favouring regimes, empty and doubly occupied sites may be energetically favoured, and staggered charge order can become stable; rigorous Pirogov–Sinai analyses of Borgs, Kotecký and collaborators establish such charge-ordered phases in related extended Hubbard settings [8], [9]. The present work describes the opposite large positive-\(U\) regime at half filling: charge defects are suppressed, macroscopic staggered charge order is excluded, and the remaining thermodynamics is governed by the effective spin degrees of freedom at the Heisenberg scale.

The temperature scale used here is part of the physical regime. The charge excitation scale is of order \(U\), whereas the spin interaction inside the singly occupied sector appears only at the superexchange scale \(J_0(U)=4t^2/U\). Therefore, to see the nontrivial spin thermodynamics described by the Heisenberg reference model, temperature should be measured in units of \(J_0(U)\). This is expressed by the condition \[\beta J_0(U)\ge \ell_0.\] One may try to formulate comparisons outside this scale as well, but that would require additional control of thermal regimes not addressed in the present work.

A distinctive feature of our setting is that the analysis is carried out directly in the canonical half-filled ensemble, \[\mathcal{H}_\Lambda^{\rm hf} = \ker(N_\Lambda-|\Lambda|).\] This differs from many rigorous low-temperature phase-diagram analyses of Hubbard-type or lattice-gas models, which are naturally formulated in a grand-canonical setting with the chemical potential as one of the parameters. Strong-coupling constructions of effective Hamiltonians for quantum lattice systems, including Hubbard-type tight-binding models, are a central ingredient in the quantum Pirogov–Sinai program of Datta, Fernández and Fröhlich [10], [11]. Related Pirogov–Sinai analyses, such as those of Borgs–Jedrzejewski–Kotecký and Borgs–Kotecký–Ueltschi, establish low-temperature phase diagrams and charge-ordered phases for extended Hubbard or lattice-gas type models in regimes where charge degrees of freedom are energetically favoured [8], [9], [12], [13]. In these works, effective interactions are derived and then used to analyse phase diagrams under assumptions adapted to grand-canonical or charge-order settings.

The emphasis of the present paper is different. Rather than working at the level of maximal generality, we restrict attention to the concrete repulsive Hubbard model at half filling. This allows us to keep track of the canonical constraint, the singly occupied spin sector, and the charge-defect sectors in a more explicit way. In particular, the effective Hamiltonian is used here as part of a quantitative Hubbard–Heisenberg transfer of pressure, magnetisation density, and charge-sector estimates, rather than as an input to a grand-canonical phase-diagram analysis. Possible extensions of the method to more general settings are discussed in Subsection 1.5.

In the canonical half-filled sector, the global constraint \(N_\Lambda=|\Lambda|\) prevents a naive tensor-product factorisation of local traces. Thus, when charge defects are separated from the singly occupied spin sector, one has to keep track of the half filling constraint carefully. In the proof below this appears through a restricted trace factorisation with a common outside single-occupancy projection.

The role of the staggered field differs among the results. The pressure comparison and the charge-sector estimates are uniform for \(|h|\le h_0.\) The magnetisation comparison is stated on fixed positive windows \(I\Subset(0,h_0],\) where the field is bounded away from zero. This positivity is used in the convexity argument which turns pressure comparison into magnetisation comparison. No quasi-average limit \(h\downarrow0\) is taken in this paper.

The precise model, the reference Heisenberg system, and the main results are stated in the following subsections.

1.2 Hubbard Hamiltonian at half filling↩︎

1.2.0.1 Fermions and the half-filled sector.

Fix \(d\ge1\) and let \(\Lambda_L:=\bigl(\mathbb{Z}/L\mathbb{Z}\bigr)^d\) with \(L\in2\mathbb{N}.\) Set \(\mathfrak h_{\Lambda_L}:=\ell^2(\Lambda_L)\otimes\mathbb{C}^2\) and \[\mathcal{H}_{\Lambda_L} := \bigoplus_{n=0}^{2|\Lambda_L|} \bigwedge\nolimits^{n}\mathfrak h_{\Lambda_L} .\] For \(x\in\Lambda_L\) and \(\sigma\in\{\uparrow,\downarrow\}\), let \(c_{x\sigma},c_{x\sigma}^\ast\) be the fermionic annihilation and creation operators on \(\mathcal{H}_L\), satisfying the CAR: \[\{c_{x\sigma},c_{y\tau}^\ast\} = \delta_{xy}\delta_{\sigma\tau}, \qquad \{c_{x\sigma},c_{y\tau}\}=0, \qquad \{c_{x\sigma}^\ast,c_{y\tau}^\ast\}=0.\] Define \[n_{x\sigma}:=c_{x\sigma}^\ast c_{x\sigma}, \qquad n_x:=n_{x\uparrow}+n_{x\downarrow}, \qquad N_{\Lambda_L}:=\sum_{x\in\Lambda_L} n_x .\] We work in the half-filled sector \[\mathcal{H}_{\Lambda_L}^{\rm hf} := \ker\bigl(N_{\Lambda_L}-|\Lambda_L|\bigr) = \bigwedge\nolimits^{|\Lambda_L|}\mathfrak h_{\Lambda_L} .\]

1.2.0.2 Hamiltonian.

The Hubbard Hamiltonian at half filling is given by \[H^{\rm Hub}_{\Lambda_L} := UD_{\Lambda_L}+T_{\Lambda_L},\] where \(U>0\) is the on-site Coulomb repulsion, \[D_{\Lambda_L} := \sum_{x\in\Lambda_L} n_{x\uparrow}n_{x\downarrow},\] and \(T_{\Lambda_L}\) is the nearest-neighbour hopping term. Let \(\mathscr B_{\Lambda_L}\) denote the set of unordered nearest-neighbour bonds in the torus \(\Lambda_L\), each bond being counted once. Then \[T_{\Lambda_L} := -t \sum_{\{x,y\}\in\mathscr B_{\Lambda_L}} \sum_{\sigma=\uparrow,\downarrow} \bigl( c_{x\sigma}^\ast c_{y\sigma} + c_{y\sigma}^\ast c_{x\sigma} \bigr), \qquad t\in\mathbb{R}\setminus \{0\}.\] Define the staggering \[\eta_x:=(-1)^{x_1+\cdots+x_d},\] which is well-defined on the torus \((\mathbb{Z}/L\mathbb{Z})^d\) since \(L\) is even, and set \[S_x^{(3)} := \frac{1}{2}\bigl(n_{x\uparrow}-n_{x\downarrow}\bigr), \qquad M_{\Lambda_L} := \sum_{x\in\Lambda_L}\eta_x S_x^{(3)} .\] For \(h\in\mathbb{R}\), we consider the staggered-field Hamiltonian on \(\mathcal{H}_{\Lambda_L}^{\rm hf}\), \[H^{\rm Hub}_{\Lambda_L}(h) := H^{\rm Hub}_{\Lambda_L}-hM_{\Lambda_L}.\]

1.3 Reference Heisenberg model, pressures, and quasi-averages↩︎

Throughout this subsection, for notational simplicity, we write \(\Lambda=\Lambda_L.\)

1.3.0.1 The reference Heisenberg model.

Let \[\mathcal{H}^{\rm spin}_\Lambda := \bigotimes_{x\in\Lambda}\mathbb{C}^2\] with the tensor factors ordered in any fixed way. Let \(\sigma^{(1)},\sigma^{(2)},\sigma^{(3)}\) be the Pauli matrices: \[\sigma^{(1)} = \begin{pmatrix} 0&1\\ 1&0 \end{pmatrix}, \qquad \sigma^{(2)} = \begin{pmatrix} 0&-\mathrm{i}\,\,\\ \mathrm{i}\,\,&0 \end{pmatrix}, \qquad \sigma^{(3)} = \begin{pmatrix} 1&0\\ 0&-1 \end{pmatrix}.\] For each \(x\in\Lambda\) and \(a\in\{1,2,3\}\), define the local spin operator \(S_x^{(a)}\) on \(\mathcal{H}_\Lambda^{\rm spin}\), acting as \(\frac{1}{2}\sigma^{(a)}\) on the tensor factor at \(x\) and as the identity on all other tensor factors. Set \[\boldsymbol{S}_x := \bigl(S_x^{(1)},S_x^{(2)},S_x^{(3)}\bigr).\] This notation is chosen to match the corresponding fermionic spin operators introduced above. When both the fermionic Hilbert space and the reference spin Hilbert space appear in the same formula, the ambient space or the identifying map will be stated explicitly. Let \[M_\Lambda^{\rm spin} := \sum_{x\in\Lambda}\eta_x S_x^{(3)}.\] For \(J>0\), define \[H^{\rm Heis}_\Lambda(J) := J\sum_{\{x,y\}\in\mathscr B_\Lambda} \left( \boldsymbol{S}_x\cdot\boldsymbol{S}_y-\frac{1}{4} \right), \qquad \boldsymbol{S}_x\cdot\boldsymbol{S}_y := \sum_{a=1}^3 S_x^{(a)}S_y^{(a)}.\] With staggered field \(h\in\mathbb{R}\), set \[H^{\rm Heis}_\Lambda(J,h) := H^{\rm Heis}_\Lambda(J)-hM_\Lambda^{\rm spin}.\]

The Heisenberg reference model is used here as the effective spin model at the superexchange scale. Rigorous analyses of quantum spin systems and Heisenberg-type models have been developed from several viewpoints, including phase-transition and correlation methods for quantum spin systems and low-temperature spin-wave/free-energy asymptotics; see, for example, [9], [14].

1.3.0.2 Hubbard pressure and Gibbs state.

For \(\beta>0\), \(U>0\), and \(h\in\mathbb{R}\), define the finite-volume Hubbard partition function by \[\require{physics} Z_{\Lambda,\beta,U}^{\rm Hub}(h) := \Tr_{\mathcal{H}_\Lambda^{\rm hf}} e^{-\beta H_\Lambda^{\rm Hub}(h)}.\] The corresponding pressure is \[p_{\Lambda,\beta,U}^{\rm Hub}(h) := \frac{1}{\beta|\Lambda|} \log Z_{\Lambda,\beta,U}^{\rm Hub}(h).\] For \(O\in\mathcal{B}(\mathcal{H}_\Lambda^{\rm hf})\), the Hubbard Gibbs state is \[\require{physics} \omega_{\Lambda,\beta,U,h}^{\rm Hub}(O) := \frac{ \Tr_{\mathcal{H}_\Lambda^{\rm hf}} \left( Oe^{-\beta H_\Lambda^{\rm Hub}(h)} \right) }{ Z_{\Lambda,\beta,U}^{\rm Hub}(h) }.\] The finite-volume staggered magnetisation density is \[m_{\Lambda,\beta,U}^{\rm Hub}(h) := \frac{1}{|\Lambda|} \omega_{\Lambda,\beta,U,h}^{\rm Hub}(M_\Lambda).\] Since the volume is finite, \(h\mapsto p_{\Lambda,\beta,U}^{\rm Hub}(h)\) is differentiable, and \[\partial_h p_{\Lambda,\beta,U}^{\rm Hub}(h) = m_{\Lambda,\beta,U}^{\rm Hub}(h).\]

1.3.0.3 Heisenberg pressure and Gibbs state.

For \(J>0\), \(\beta>0\), and \(h\in\mathbb{R}\), define \[\require{physics} Z_{\Lambda,\beta}^{\rm Heis}(J,h) := \Tr_{\mathcal{H}_\Lambda^{\rm spin}} e^{-\beta H_\Lambda^{\rm Heis}(J,h)}.\] The corresponding pressure is \[p_{\Lambda,\beta}^{\rm Heis}(J,h) := \frac{1}{\beta|\Lambda|} \log Z_{\Lambda,\beta}^{\rm Heis}(J,h).\] For \(O\in\mathcal{B}(\mathcal{H}_\Lambda^{\rm spin})\), the Heisenberg Gibbs state is \[\require{physics} \omega_{\Lambda,\beta,J,h}^{\rm Heis}(O) := \frac{ \Tr_{\mathcal{H}_\Lambda^{\rm spin}} \left( Oe^{-\beta H_\Lambda^{\rm Heis}(J,h)} \right) }{ Z_{\Lambda,\beta}^{\rm Heis}(J,h) }.\] The finite-volume staggered magnetisation density is \[m_{\Lambda,\beta}^{\rm Heis}(J,h) := \frac{1}{|\Lambda|} \omega_{\Lambda,\beta,J,h}^{\rm Heis}(M_\Lambda^{\rm spin}).\] Again, \[\partial_h p_{\Lambda,\beta}^{\rm Heis}(J,h) = m_{\Lambda,\beta}^{\rm Heis}(J,h).\]

1.3.0.4 The effective Heisenberg reference model.

For the Hubbard model with coupling \(U\), set \[J_0(U):=\frac{4t^2}{U}.\] The Heisenberg model used as the reference model in the main comparison theorems is the nearest-neighbour antiferromagnetic Heisenberg model with coupling \(J_0(U)\) and the same staggered field \(h\): \(H_\Lambda^{\rm Heis}(J_0(U),h).\) The corresponding pressure is denoted by \[p_{\Lambda,\beta,U}^{\rm Heis}(h) := p_{\Lambda,\beta}^{\rm Heis}(J_0(U),h).\] We also write \[\omega_{\Lambda,\beta,U,h}^{\rm Heis} := \omega_{\Lambda,\beta,J_0(U),h}^{\rm Heis}\] and \[m_{\Lambda,\beta,U}^{\rm Heis}(h) := m_{\Lambda,\beta}^{\rm Heis}(J_0(U),h) = \partial_h p_{\Lambda,\beta,U}^{\rm Heis}(h).\]

1.4 Main theorems↩︎

1.4.1 Pressure and magnetisation comparison↩︎

1.4.1.1 Heisenberg-scale regime.

The comparison is made in the Heisenberg-scale temperature regime \(\beta J_0(U)\ge \ell_0.\) This means that the inverse temperature is measured on the spin-exchange scale \(J_0(U)=4t^2/U\), rather than on the original hopping scale. Thus, as \(U\to\infty\), the temperature is low enough to resolve the effective spin interaction.

Below, the pressure comparison and the charge-sector estimates are stated uniformly for \(|h|\le h_0,\) whereas the magnetisation comparison is stated on fixed field windows \(I\Subset(0,h_0].\) The condition \(\inf I>0\) is used only in the convexity step which converts pressure comparison into magnetisation comparison. No quasi-average limit \(h\downarrow0\) is taken.

Theorem 1 (Hubbard–Heisenberg pressure comparison on the bounded field window). Fix \(\ell_0>0\). There exist \(U_0=U_0(\ell_0,d,h_0,t)\) and an error function \(\varepsilon_{\rm FE}(U,\beta;h_0)\ge0\) such that, for all \(U\ge U_0\), all \(\beta>0\) satisfying \(\beta J_0(U)\ge\ell_0,\) all even tori \(\Lambda_L\), and all \(|h|\le h_0\), \[\left| p_{\Lambda_L,\beta,U}^{\rm Hub}(h) - p_{\Lambda_L,\beta,U}^{\rm Heis}(h) \right| \le \varepsilon_{\rm FE}(U,\beta;h_0).\] Moreover, \[\lim_{U\to\infty} \sup_{\beta J_0(U)\ge\ell_0} \varepsilon_{\rm FE}(U,\beta;h_0) = 0.\] The estimate is uniform in \(L\) and \(|h|\le h_0\).

The proof of Theorem 1 is given in Subsection 7.1.

Theorem 2 (Fixed positive-field magnetisation comparison). Fix \(\ell_0>0\) and \(I\Subset(0,h_0]\). There exist \(U_0=U_0(I,\ell_0,d,t)\) and an error function \(\varepsilon_{\rm mag}(U,\beta;I)\ge0\) such that, for all \(U\ge U_0\), all \(\beta>0\) satisfying \(\beta J_0(U)\ge\ell_0,\) all even tori \(\Lambda_L\), and all \(h\in I\), \[\left| m_{\Lambda_L,\beta,U}^{\rm Hub}(h) - m_{\Lambda_L,\beta,U}^{\rm Heis}(h) \right| \le \varepsilon_{\rm mag}(U,\beta;I).\] Moreover, \[\lim_{U\to\infty} \sup_{\beta J_0(U)\ge\ell_0} \varepsilon_{\rm mag}(U,\beta;I) = 0.\] The estimate is uniform in \(L\) and \(h\in I\).

The proof of Theorem 2 is given in Subsection 7.3.

To state the corresponding infinite-volume consequences in a concise form, we shall use the following standing assumption on the existence of fixed-field pressure limits.

Assumption 3 (Thermodynamic limits of the bounded-field pressures). For every \(U>0\) and every \(\beta>0\), the canonical half-filled Hubbard pressures have the thermodynamic limit \[p_{\beta,U}^{\rm Hub}(h) := \lim_{L\to\infty} p_{\Lambda_L,\beta,U}^{\rm Hub}(h), \qquad |h|\le h_0,\] and the Heisenberg reference pressures have the thermodynamic limit \[p_{\beta,U}^{\rm Heis}(h) := \lim_{L\to\infty} p_{\Lambda_L,\beta,U}^{\rm Heis}(h), \qquad |h|\le h_0.\]

Remark 4 (On the thermodynamic-limit assumption). Assumption 3 is a standard thermodynamic-limit input and is not a new mechanism in the present paper. For the Heisenberg model, the existence of the pressure follows from the usual thermodynamic-limit argument for finite-range quantum spin systems, based on locality and boundary surface estimates.

For the Hubbard model, the point is slightly more notational because we work in the canonical half-filled sector. This sector does not factorise under a spatial decomposition. Rather, for a decomposition \(\Lambda=\Lambda_1\cup\Lambda_2\), one has \[\mathcal{H}_{\Lambda}^{N_\Lambda=|\Lambda|} = \bigoplus_{N_1+N_2=|\Lambda|} \mathcal{H}_{\Lambda_1}^{N_1} \otimes \mathcal{H}_{\Lambda_2}^{N_2}.\] Thus the canonical proof is most cleanly obtained from the standard thermodynamic-limit theory for finite-range lattice fermions at fixed density, equivalently by first proving the grand-canonical pressure and then using the Legendre–Fenchel ensemble equivalence to recover the canonical half-filled pressure.

We keep this as an assumption because the present paper is concerned with the Hubbard–Heisenberg comparison at fixed positive field, not with reproving the general thermodynamic-limit theory for finite-range fermion systems.

Assume Assumption 3. For \(\sharp\in\{{\rm Hub},{\rm Heis}\}\), define \[\mathcal{D}_{\beta,U}^{\sharp} := \left\{ h\in(-h_0,h_0): p_{\beta,U}^{\sharp} \text{ is differentiable at }h \right\}.\] Since \(p_{\beta,U}^{\sharp}\) is convex, the set \((-h_0,h_0)\setminus \mathcal{D}_{\beta,U}^{\sharp}\) is at most countable. For \(h\in\mathcal{D}_{\beta,U}^{\sharp}\), set \[m_{\beta,U}^{\sharp}(h) := \partial_h p_{\beta,U}^{\sharp}(h).\] By Lemma 54, this agrees with the thermodynamic limit of the finite-volume magnetisations: \[m_{\beta,U}^{\sharp}(h) = \lim_{L\to\infty} m_{\Lambda_L,\beta,U}^{\sharp}(h), \qquad h\in\mathcal{D}_{\beta,U}^{\sharp}.\]

Corollary 5 (Infinite-volume pressure and fixed-field magnetisation comparison). Assume Assumption 3. Under the assumptions of Theorem 1, one has, for all \(|h|\le h_0\), \[\left| p_{\beta,U}^{\rm Hub}(h) - p_{\beta,U}^{\rm Heis}(h) \right| \le \varepsilon_{\rm FE}(U,\beta;h_0).\]

Let \(I\Subset(0,h_0]\). Under the assumptions of Theorem 2, one has, for every \(h\in \operatorname{int} I \cap \mathcal{D}_{\beta,U}^{\rm Hub} \cap \mathcal{D}_{\beta,U}^{\rm Heis},\) the magnetisation comparison \[\left| m_{\beta,U}^{\rm Hub}(h) - m_{\beta,U}^{\rm Heis}(h) \right| \le \varepsilon_{\rm mag}(U,\beta;I).\] Thus, at every common differentiability point in the positive field window, the infinite-volume staggered magnetisation density of the Hubbard model is approximated by that of the Heisenberg reference model on the Heisenberg scale.

Remark 6 (Differentiability in positive field). The differentiability restriction in Corollary 5 is a convexity-theoretic precaution. The limiting pressures are convex functions of \(h\), and hence are differentiable except possibly at countably many points. In the fixed positive-field regime one expects differentiability, and often analyticity, but proving such a one-phase regularity statement is not part of the present paper. We therefore state the infinite-volume magnetisation comparison only at common differentiability points.

1.4.1.2 Positive fixed-field Hubbard magnetisation.

The fixed positive-field magnetisation comparison has a concrete consequence for the Hubbard magnetisation itself. We combine the elementary lower bound for the Heisenberg reference magnetisation with Theorem 2.

Corollary 7 (Positive fixed-field Hubbard magnetisation). Fix \(\ell_0>0\) and \(I\Subset(0,h_0]\), and set \(h_I:=\inf I>0.\) Let \(\varepsilon_{\rm mag}(U,\beta;I)\) be the error function in Theorem 2. Let \(C_d<\infty\) be the constant in Lemma 52, and define \[m_{\rm Hub}^{\rm lb}(U,\beta;I) := \frac{1}{2}\tanh\left(\frac{\beta h_I}{4}\right) - \frac{4C_d}{h_I}J_0(U) - \varepsilon_{\rm mag}(U,\beta;I).\] Then, after increasing the strong-coupling threshold if necessary, for all \(U\) above this threshold, all \(\beta>0\) satisfying \(\beta J_0(U)\ge \ell_0,\) all even tori \(\Lambda_L\), and all \(h\in I\), one has \[m_{\Lambda_L,\beta,U}^{\rm Hub}(h) \ge m_{\rm Hub}^{\rm lb}(U,\beta;I).\] Moreover, \[\lim_{U\to\infty} \inf_{\beta J_0(U)\ge\ell_0} m_{\rm Hub}^{\rm lb}(U,\beta;I) = \frac{1}{2}.\] Consequently, after increasing the threshold once more if necessary, \[m_{\Lambda_L,\beta,U}^{\rm Hub}(h) \ge \frac{1}{4}\] uniformly in \(L\), \(h\in I\), and \(\beta>0\) satisfying \(\beta J_0(U)\ge\ell_0\).

The proof of Corollary 7 is given in Appendix 7.5.

Remark 8 (Significance of the fixed-field transfer). Corollary 7 should be read as a quantitative fixed-field transfer statement. The positivity of the Hubbard staggered magnetisation in a positive external field is physically natural, but it is not an immediate consequence of the formal strong-coupling picture: one still has to control hopping effects and charge defects in the canonical half-filled ensemble. Theorem 2 provides this control by transferring the elementary positive-field lower bound for the Heisenberg reference model to the Hubbard model.

This is a fixed-positive-field result. No \(h\downarrow0\) comparison is proved here. The statement establishes the fixed-field part of the effective Heisenberg description, with estimates that are uniform and quantitative in the Heisenberg-scale regime.

1.4.2 Charge-sector consequences↩︎

1.4.2.1 Standing assumptions and Gibbs state.

Throughout this subsubsection, fix \(\ell_0>0\). Recall the finite-volume half-filled Hubbard Gibbs state \(\omega_{\Lambda_L,\beta,U,h}^{\rm Hub}\) introduced above. All expectations below are taken with respect to this state, uniformly for \(|h|\le h_0\).

1.4.2.2 Charge observables.

Set \[q_x:=(n_x-1)^2.\] Thus \(q_x\) detects deviations from single occupancy at \(x\). We also define the staggered charge observable \[C_{\Lambda_L}^{\rm ch} := \sum_{x\in\Lambda_L}\eta_x(n_x-1).\]

Theorem 9 (Charge-sector suppression and absence of macroscopic CDW). There exist \(U_0=U_0(\ell_0,d,h_0,t)\) and an error function \(\varepsilon_{\rm ch}(U,\beta;h_0)\ge0\) such that, for all \(U\ge U_0\), all \(\beta>0\) satisfying \(\beta J_0(U)\ge\ell_0,\) all even tori \(\Lambda_L\), and all \(|h|\le h_0\), one has \[\frac{1}{|\Lambda_L|} \sum_{x\in\Lambda_L} \omega_{\Lambda_L,\beta,U,h}^{\rm Hub}(q_x) \le \varepsilon_{\rm ch}(U,\beta;h_0).\] Consequently, \[\frac{1}{|\Lambda_L|} \sum_{x\in\Lambda_L} \omega_{\Lambda_L,\beta,U,h}^{\rm Hub} (n_{x\uparrow}n_{x\downarrow}) \le \frac{1}{2}\varepsilon_{\rm ch}(U,\beta;h_0).\] Moreover, \[\left| \frac{1}{|\Lambda_L|} \omega_{\Lambda_L,\beta,U,h}^{\rm Hub}(C_{\Lambda_L}^{\rm ch}) \right| \le \varepsilon_{\rm ch}(U,\beta;h_0),\] and \[\frac{1}{|\Lambda_L|^2} \omega_{\Lambda_L,\beta,U,h}^{\rm Hub} \left( (C_{\Lambda_L}^{\rm ch})^2 \right) \le \varepsilon_{\rm ch}(U,\beta;h_0).\] Finally, \[\lim_{U\to\infty} \sup_{\beta J_0(U)\ge\ell_0} \varepsilon_{\rm ch}(U,\beta;h_0) = 0.\]

The proof of Theorem 9 is given in Subsection 7.6.

Remark 10 (Meaning of the charge estimates). The theorem should be read as a charge-sector statement in the large positive-\(U\), Heisenberg-scale regime. The estimate on \[\frac{1}{|\Lambda_L|} \sum_{x\in\Lambda_L} \omega_{\Lambda_L,\beta,U,h}^{\rm Hub}(q_x), \qquad q_x=(n_x-1)^2,\] says that the density of charge defects is small. Since \(q_x\) vanishes on singly occupied states and equals one on empty or doubly occupied states, the Hubbard Gibbs state is concentrated, up to a small density error, near the singly occupied spin sector.

On the half-filled sector, \[\sum_{x\in\Lambda_L}q_x = 2\sum_{x\in\Lambda_L}n_{x\uparrow}n_{x\downarrow}.\] Thus the same estimate gives suppression of the double-occupancy density. The estimates involving \(C_{\Lambda_L}^{\rm ch} = \sum_{x\in\Lambda_L}\eta_x(n_x-1)\) show that macroscopic staggered charge order is excluded in the thermodynamic normalization used here.

In short, the theorem confirms the expected large-repulsion picture: charge defects are dilute, and the dominant low-energy degrees of freedom are spin degrees of freedom on an approximately singly occupied background. The theorem does not assert exponential decay of local charge correlations.

1.5 Possible extensions and robustness of the comparison↩︎

The main statements above are formulated on the even torus \(\Lambda_L=(\mathbb{Z}/L\mathbb{Z})^d\) with nearest-neighbour hopping and a uniform staggered field. This choice keeps the notation simple and avoids boundary terms. The mechanism, however, is more flexible.

  • Other boundary conditions and van Hove sequences. The finite-volume comparison is local in nature. Thus one expects the same thermodynamic pressure and magnetisation comparison along standard van Hove sequences of finite boxes, with periodic or open boundary conditions, provided the boundary contribution is negligible after division by the volume. The torus assumption is used here mainly to avoid carrying these boundary errors.

  • More general bipartite graphs. The argument should extend to families of finite bipartite graphs with uniformly bounded degree and a compatible staggering \(\eta_x\), as long as the hopping connects the two sublattices and the relevant local estimates are uniform in the volume. In that setting the effective spin Hamiltonian is the antiferromagnetic Heisenberg model on the same graph.

  • Non-uniform finite-range hopping. For hopping amplitudes \(t_{xy}\) of finite range, the second-order effective spin model should have edge-dependent antiferromagnetic couplings of order \(J_{xy}\simeq \frac{4|t_{xy}|^2}{U}.\) Thus the comparison with \(J_0(U)=4t^2/U\) is replaced by a comparison with a non-uniform effective Heisenberg model. The present paper treats the translation-invariant nearest-neighbour case in order to keep the main theorem transparent.

  • Fixed positive fields beyond the uniform case. The fixed-field nature of the argument is essential, but the precise choice of a constant staggered field is not expected to be essential. A site-dependent staggered field bounded away from zero should lead to a similar field-dominated comparison, with constants depending on the lower bound of the field window.

  • Zero-temperature finite-volume limits. At fixed finite volume, one may simply take \(\beta\to\infty\). Since the Hilbert space is finite-dimensional, the Gibbs state converges to the normalized projection onto the ground-state space. Hence all estimates in the main theorem which are uniform in \(\beta\) pass directly to the finite-volume zero-temperature mixed ground-state expectation. No finite-volume ground-state uniqueness is needed for this passage.

    It is plausible that, in the present positive staggered-field setting, the finite-volume ground state is in fact unique. This, however, is a separate Perron–Frobenius or reflection-positivity type input and is not used in the present comparison argument; see, for example, [4], [15], [16]. If such a uniqueness statement is established in the present setting, the mixed ground-state expectation above may be replaced by the unique ground-state expectation.

These extensions are not needed for the main results of this paper. They indicate that the comparison mechanism is not tied to the translation-invariant torus geometry, but rather to three structural features: strong repulsion at half filling, a bipartite staggered-field structure, and locality of the hopping.

1.6 Strategy and outline↩︎

The goal of the paper is to compare the canonical half-filled Hubbard model with the Heisenberg reference model on the Heisenberg scale \(\beta J_0(U)\ge \ell_0\) with \(J_0(U)=\frac{4t^2}{U}.\) The pressure comparison and the charge-sector estimates are uniform for \(|h|\le h_0.\) The magnetisation comparison is stated on fixed positive windows \(I\Subset(0,h_0],\) because the passage from pressure comparison to magnetisation comparison uses a fixed-window convexity argument. No quasi-average limit \(h\downarrow0\), reflection positivity, infrared bound, or long-range-order input is used.

1.6.0.1 Road map.

The proof has three main parts.

  • First, we use the LS/SW diagonalisation scheme to conjugate the Hubbard Hamiltonian to a \(D_{\Lambda_L}\)-diagonal effective Hamiltonian, \[U_{{\rm SW},\Lambda_L}(h) H_{\Lambda_L}^{\rm Hub}(h) U_{{\rm SW},\Lambda_L}(h)^\ast = UD_{\Lambda_L}+A_{\Lambda_L}(h), \qquad [A_{\Lambda_L}(h),D_{\Lambda_L}]=0.\] The sector \(D_{\Lambda_L}=0\) is the singly occupied spin sector and is denoted by \(P\). Since the transformed Hamiltonian preserves the \(D_{\Lambda_L}\)-sectors, the \(P\)-block can be analysed separately.

  • Second, we compare the effective \(P\)-block Hamiltonian with the Heisenberg reference model. The second-order term gives a Heisenberg Hamiltonian with intermediate parameters \(J(h)\) and \(h_{\rm eff}(h)\). The parameter renormalisation and the higher-order \(P\)-block remainder are controlled uniformly for \(|h|\le h_0\). This gives the pressure comparison between the effective \(P\)-block Hamiltonian and the Heisenberg reference model.

  • Third, we compare the full Hubbard pressure with the \(P\)-block pressure by a soft defect estimate. Combining this estimate with the \(P\)-block comparison gives the Hubbard–Heisenberg pressure comparison for \(|h|\le h_0\). The charge-sector estimates are obtained from the same defect decomposition, together with the LS/SW dressing estimate for the normalized defect density.

The magnetisation comparison is then derived from the pressure comparison by convexity.

This proves the finite-volume pressure comparison stated in Theorem 1, the fixed-positive-field magnetisation comparison stated in Theorem 2, and the charge-sector estimates stated in Theorem 9.

1.6.0.2 Positive fixed-field magnetisation.

Since \(h\) is bounded away from zero and \(J_0(U)\to0\), the Heisenberg reference model is close to the pure staggered-field spin system at the level of pressure. This gives an explicit lower bound \[m_{\Lambda_L,\beta,U}^{\rm Heis}(h) \ge m_{\rm Heis}^{\rm lb}(U,\beta;I), \qquad h\in I,\] with \(m_{\rm Heis}^{\rm lb}(U,\beta;I)\to\frac{1}{2}\) uniformly under \(\beta J_0(U)\ge\ell_0\) as \(U\to\infty\). The Hubbard–Heisenberg magnetisation comparison then gives the corresponding positive fixed-field magnetisation bound for the Hubbard model.

1.6.0.3 Charge-sector consequences.

The same defect decomposition controls the density of charge defects \(q_x=(n_x-1)^2.\) After conjugating back to the original Hubbard Gibbs state by the LS/SW dressing estimate for the normalized defect density, we obtain \[\frac{1}{|\Lambda_L|} \sum_{x\in\Lambda_L} \omega_{\Lambda_L,\beta,U,h}^{\rm Hub}(q_x) \le \varepsilon_{\rm ch}(U,\beta;h_0).\] This implies suppression of double occupancy and excludes macroscopic staggered charge order in the normalization used here.

1.6.0.4 Organisation of the paper.

Section 2 develops the LS/SW diagonalisation and derives the \(D_{\Lambda_L}\)-diagonal effective Hamiltonian \(H_{*,\Lambda_L}(h)=UD_{\Lambda_L}+A_{\Lambda_L}(h).\) Section 3 introduces the two auxiliary deformation schemes used to identify the relevant second-order spin term and to compare it with the physical endpoint correction. The resulting second-order \(P\)-block Hamiltonian is identified with a Heisenberg-type spin Hamiltonian in Section 4.

Section 5 compares the effective \(P\)-block spin Hamiltonian with the Heisenberg reference model. This step controls both the mismatch between the renormalized parameters and the reference parameters, and the higher-order \(P\)-block remainder. Section 6 then compares the full Hubbard pressure with the \(P\)-block pressure by the soft defect estimate, and records the corresponding diagonal charge-defect bound.

The main finite-volume estimates are assembled in Section 7. First, the \(P\)-block comparison and the soft defect pressure estimate give the Hubbard–Heisenberg reference pressure comparison. Next, the magnetisation comparison is obtained from the pressure comparison on the enlarged window \(I^\sharp\) by the fixed-window convexity argument. The same section also proves the positive fixed-field magnetisation consequence, the charge-sector theorem, and the thermodynamic-limit corollaries.

The appendices contain the deferred technical estimates. Appendix 8 collects the BCH, graded-word, and quantitative LS/SW estimates, including the LS/SW dressing estimate for the normalized defect density. Appendix 9 contains the spin representation and the two-site computation underlying the Heisenberg identification. Appendix 10 proves the \(P\)-block remainder and parameter-mismatch estimates. Appendix 11 records the finite-volume pressure Lipschitz, derivative, and convexity tools used in the final assembly and in the thermodynamic-limit arguments.

Acknowledgements↩︎

This work was supported by JSPS KAKENHI Grant Number 23H01086.

Declarations↩︎

  • Conflict of interest: The authors have no conflicts of interest to declare that are relevant to the content of this article.

  • Data availability: Data sharing is not applicable to this article as no datasets were generated or analysed during the current study.

2 \(D_\Lambda\)-diagonalisation by LS/SW and the physical output↩︎

Throughout this section, \(\Lambda=\Lambda_L\) denotes a fixed even torus, and all operators are understood on the half-filled Hilbert space \(\mathcal{H}_\Lambda^{\rm hf}\), unless explicitly stated otherwise.

The diagonalisation used below is a finite-volume strong-coupling Lie–Schwinger/Schrieffer–Wolff scheme. Such transformations go back to the work of Schrieffer and Wolff, and related \(t/U\)-expansions for the Hubbard model have been developed in several forms; see, for example, [17][20]. Closely related Lie–Schwinger block-diagonalisation methods have also been used in recent work on gapped quantum chains, including systems with unbounded interactions [21].

In the present paper the grading is given by the double-occupancy operator \(D_\Lambda\). The purpose of the construction is to conjugate the Hubbard Hamiltonian to a \(D_\Lambda\)-diagonal form \[UD_\Lambda+A_\Lambda(h), \qquad [A_\Lambda(h),D_\Lambda]=0,\] with estimates uniform in the volume and in the field range \(|h|\le h_0.\) The restriction to fixed positive field windows enters only later, when the pressure comparison is converted into a magnetisation comparison by convexity.

2.1 \(D\)-grading, interactions, and norms↩︎

2.1.0.1 Defect projections.

Set \[n_x:=n_{x\uparrow}+n_{x\downarrow}, \qquad q_x:=(n_x-1)^2 .\] Then \(q_x\) is the projection onto the subspace with \(n_x\in\{0,2\}\), and the family \(\{q_x\}_{x\in\Lambda}\) is commuting. On the half-filled subspace \(\mathcal{H}_\Lambda^{\rm hf}\) one has \[\label{eq:spec-qsum-2D} \sum_{x\in\Lambda}q_x=2D_\Lambda .\tag{1}\] Since we work at half filling, \(N_\Lambda=|\Lambda|\), the sector \(D_\Lambda=0\) consists precisely of the singly occupied configurations. Equivalently, \((n_{x\uparrow}+n_{x\downarrow})\psi=\psi \, (x\in\Lambda)\) for every vector \(\psi\) in this sector. We set \[\label{eq:def-PQ} P:=\mathbb{1}_{\{D_\Lambda=0\}}\restriction_{\mathcal{H}_\Lambda^{\rm hf}}, \qquad Q:=\mathbb{1}-P .\tag{2}\]

2.1.0.2 The CAR algebra, local subalgebras, and even observables.

Let \(\frak A\) denote the quasi-local CAR algebra on the infinite lattice \(\mathbb{Z}^d\).1 For a finite set of sites \(X\), either in \(\mathbb{Z}^d\) or in a finite torus \(\Lambda\), we write \(\frak A_X\) for the CAR algebra generated by \(\{c_{x\sigma},c_{x\sigma}^\ast: x\in X,\;\sigma\in\{\uparrow,\downarrow\}\}.\) Thus, when \(X\subset\Lambda\), the symbol \(\frak A_X\) denotes the corresponding finite-volume local algebra on the torus, and \(\frak A_\Lambda\) denotes the full finite-volume CAR algebra acting on \(\mathcal{H}_\Lambda\). We work almost exclusively in finite volume; the quasi-local algebra \(\frak A\) is used only as a convenient language for locality.

Let \(\Theta\) be the fermion-parity automorphism, defined on generators by \[\Theta(c_{x\sigma})=-c_{x\sigma}, \qquad \Theta(c_{x\sigma}^\ast)=-c_{x\sigma}^\ast .\] We write \[\frak A_X^{\rm even} := \{A\in\frak A_X:\Theta(A)=A\}\] for the even local subalgebra. We shall use the elementary fact that if \(X\cap Y=\varnothing\), \(A\in\frak A_X^{\rm even}\), and \(B\in\frak A_Y\), then \([A,B]=0.\) Thus even local observables with disjoint supports commute in the usual sense.

2.1.0.3 Adjoint notation and BCH.

For \(S\in\frak A_\Lambda\), define the inner derivation \[\mathrm{ad}_S:\frak A_\Lambda\to\frak A_\Lambda, \qquad \mathrm{ad}_S(A):=[S,A].\] We also write \[\mathrm{ad}_S^{\,0}(A):=A, \qquad \mathrm{ad}_S^{\,n}(A):=\mathrm{ad}_S\bigl(\mathrm{ad}_S^{\,n-1}(A)\bigr) \quad(n\ge1).\] We repeatedly use the Baker–Campbell–Hausdorff expansion \[e^{S}Ae^{-S} = \sum_{n\ge0}\frac{1}{n!}\mathrm{ad}_S^{\,n}(A),\] whenever the series is norm convergent.

2.1.0.4 Interactions and the identification convention.

Throughout the paper, an interaction on \(\Lambda\) means a family of even local terms \[\Phi=\{\Phi_X\}_{X\subset\Lambda}, \qquad \Phi_X\in\frak A_X^{\rm even}.\] Self-adjointness or anti-self-adjointness will be specified separately when needed. We say that \(\Phi\) is finite-range if there exists \(R<\infty\) such that \(\Phi_X=0\) whenever \(\operatorname{diam}(X)>R\), where the diameter is taken with respect to the graph distance on \(\Lambda\).2 The associated finite-volume operator is \[\Phi_\Lambda:=\sum_{X\subset\Lambda}\Phi_X .\] Throughout the paper we freely identify \(\Phi\) with \(\Phi_\Lambda\) when no confusion can arise. Termwise operations for interactions are collected in Appendix 8.

2.1.0.5 Interaction norm and interaction commutator.

For a finite-range interaction \(\Phi=\{\Phi_X\}_{X\subset\Lambda}\) and \(\kappa\ge0\), define \[\label{eq:spec-kappa-norm} \|\Phi\|_\kappa := \sup_{x\in\Lambda} \sum_{X\ni x} e^{\kappa |X|}\|\Phi_X\|, \qquad \|\Phi\|_0:=\|\Phi\|_{\kappa=0}.\tag{3}\] Here \(|X|\) denotes the cardinality of \(X\), and \(\|\cdot\|\) denotes the operator norm in the finite-volume representation. The notation \(\sum_{X\ni x}\) means the sum over all nonempty subsets \(X\subset\Lambda\) containing the site \(x\).

For two interactions \(A=\{A_X\}_{X\subset\Lambda}\) and \(B=\{B_Y\}_{Y\subset\Lambda}\), define the interaction \(\mathrm{ad}_A(B)=\{(\mathrm{ad}_A(B))_Z\}_{Z\subset\Lambda}\) by \[\label{eq:spec-ad-interaction-def} (\mathrm{ad}_A(B))_Z := \sum_{\substack{X,Y\subset\Lambda:\\ X\cup Y=Z}} [A_X,B_Y].\tag{4}\]

2.1.0.6 Support size of an interaction.

For an interaction \(A=\{A_X\}_{X\subset\Lambda}\), set \[\mathrm{supp}A:=\{X\subset\Lambda:\;A_X\neq0\}, \qquad s(A):=\sup\{|X|:\;X\in\mathrm{supp}A\}.\] Thus \(s(A)<\infty\) whenever \(A\) is finite-range with uniformly bounded support size.

Lemma 11 (Commutator bound in \(\|\cdot\|_\kappa\)). Let \(A,B\) be finite-range interactions. Then \[\|\mathrm{ad}_A(B)\|_\kappa \le 2\bigl(s(A)+s(B)\bigr)\, \|A\|_\kappa\,\|B\|_\kappa .\]

Proof. See Appendix 8, §8.1. ◻

Lemma 12 (BCH summability bound). Let \(A,B\) be finite-range interactions. Assume \(2s(A)\|A\|_\kappa\le \rho<1 .\) Then there exists a constant \(C_{\rm BCH}=C_{\rm BCH}(s(A),s(B),\rho)\) such that \[\sum_{n\ge1}\frac{1}{n!} \|\mathrm{ad}_A^{\,n}(B)\|_\kappa \le C_{\rm BCH}\,\|A\|_\kappa\,\|B\|_\kappa.\] Consequently, \[\left\| e^A B e^{-A}-B \right\|_\kappa \le C_{\rm BCH}\,\|A\|_\kappa\,\|B\|_\kappa.\]

Proof. See Appendix 8, §8.1. ◻

2.1.0.7 \(D\)-grading.

For \(m\in\mathbb{N}_0\), let \[P_m := \mathbb{1}_{\{D_\Lambda=m\}}\restriction_{\mathcal{H}_\Lambda^{\rm hf}}\] be the corresponding spectral projection. We set \(P_m:=0\) if \(m\notin\operatorname{spec}(D_\Lambda)\). Then \[\sum_{m\ge0}P_m=\mathbb{1}, \qquad D_\Lambda P_m=mP_m .\] For any \(B\in\frak A_\Lambda\), define its \(D\)-graded parts by \[\label{eq:def-D-graded} B^{(k)} := \sum_{m\ge0}P_{m+k}BP_m, \qquad k\in\mathbb{Z},\tag{5}\] with the convention \(P_{m+k}=0\) if \(m+k<0\). Since the volume is finite, the sum over \(k\) is finite and \[B=\sum_{k\in\mathbb{Z}}B^{(k)}.\] Moreover, \[\label{eq:adUD-on-graded} \mathrm{ad}_{UD_{\Lambda}}(B^{(k)})=kU B^{(k)}.\tag{6}\] We write \[B^{\rm diag}:=B^{(0)}, \qquad B^{\rm off}:=\sum_{k\neq0}B^{(k)}.\] We say that \(B\) is \(D\)-diagonal if \(B=B^{\rm diag}\), equivalently \(\mathrm{ad}_{D_\Lambda}(B)=0\).

Lemma 13 (Contractivity of the \(D\)-grading). For any bounded operator \(A\) and any \(k\in\mathbb{Z}\), \[\label{eq:D-graded-op-norm} \|A^{(k)}\| = \sup_{m\ge0}\|P_{m+k}AP_m\| \le \|A\|.\qquad{(1)}\] Moreover, \[\|A^{\rm diag}\|\le\|A\|, \qquad \|A^{\rm off}\|\le2\|A\|.\]

Consequently, if \(C=\{C_X\}_{X\subset\Lambda}\) is an interaction and \(C^{(k)}:=\{(C_X)^{(k)}\}_{X\subset\Lambda},\) then \[\|C^{(k)}\|_\kappa\le \|C\|_\kappa, \qquad \|C^{\rm diag}\|_\kappa\le \|C\|_\kappa, \qquad \|C^{\rm off}\|_\kappa\le2\|C\|_\kappa.\] If, in addition, \(s(C)<\infty,\) then \[\sum_{k\neq0}\|C^{(k)}\|_\kappa \le 2s(C)\|C\|_\kappa .\]

Proof. See Appendix 8, §8.1. ◻

2.1.0.8 Homological inverses \(\mathcal{I}\) and \(\mathcal{I}_h\).

We use the \(D\)-grading notation introduced above. For \(B\in\frak A_\Lambda\), recall \(B^{\rm diag}:=B^{(0)},\) and \(B^{\rm off}:=\sum_{k\neq0}B^{(k)}.\)

The case \(h=0\). On the \(D\)-off-diagonal subspace, the map \(\mathrm{ad}_{UD_\Lambda}\) is inverted explicitly by \[\label{eq:def-I} \mathcal{I}(B^{\rm off}) := \sum_{k\neq0}\frac{1}{kU}B^{(k)} .\tag{7}\] Indeed, \[\label{eq:adUD-I} \mathrm{ad}_{UD_\Lambda} \bigl( \mathcal{I}(B^{\rm off}) \bigr) = B^{\rm off}.\tag{8}\] Moreover, if \(B\) is self-adjoint, then \(\mathcal{I}(B^{\rm off})^\ast = -\mathcal{I}(B^{\rm off}).\)

The case \(|h|\le h_0\). For nonzero field we use a local, \(h\)-dependent homological inverse. More precisely, let \(A\in\frak A_X\) be a local operator of \(D\)-grade \(k\neq0\). Under the standing large-\(U\) condition \(|k|U>h_0|X|,\) we define \(\mathcal{I}_h(A)\) as the local inverse of \(\mathrm{ad}_{UD_\Lambda-hM_\Lambda}\) on the \(k\)-graded piece, so that \[\label{eq:adUDh-Ih-local} \mathrm{ad}_{UD_\Lambda-hM_\Lambda} \bigl( \mathcal{I}_h(A) \bigr) = A.\tag{9}\] The concrete definition is given in Appendix 8.2 by a Neumann series on each graded local piece. It has the following properties: \(\mathcal{I}_h(A)\) is supported in the same set \(X\), has the same \(D\)-grade \(k\), and satisfies the corresponding local \(\|\cdot\|\)- and \(\|\cdot\|_\kappa\)-bounds. Moreover, if \(A\) is self-adjoint after summing over opposite grades, then the resulting \(\mathcal{I}_h\)-image is anti-self-adjoint.

At \(h=0\), this local inverse agrees with \(\mathcal{I}\). Thus one may write \(\mathcal{I}_0=\mathcal{I}.\)

Interaction-level convention. If \(B=\{B_X\}_{X\subset\Lambda}\) is a finite-range interaction, then all operations above are understood termwise in \(X\). Namely, we define \[B^{(k)} := \{(B_X)^{(k)}\}_{X\subset\Lambda}, \qquad B^{\rm off} := \{(B_X)^{\rm off}\}_{X\subset\Lambda},\] and set \[\mathcal{I}(B^{\rm off}) := \left\{ \mathcal{I}\bigl((B_X)^{\rm off}\bigr) \right\}_{X\subset\Lambda}, \qquad \mathcal{I}_h(B^{\rm off}) := \left\{ \mathcal{I}_h\bigl((B_X)^{\rm off}\bigr) \right\}_{X\subset\Lambda}.\] For \(U\) sufficiently large compared with \(h_0\) and the finite range of \(B\), this termwise definition is well-defined. In particular, \(\mathcal{I}(B^{\rm off})\) and \(\mathcal{I}_h(B^{\rm off})\) are again finite-range interactions with the same range as \(B\); see Appendix 8.2, especially Lemma 36.

Remark 14 (Relation to spectral-flow constructions). The field-dependent homological inverse \(\mathcal{I}_h\) plays the role of a local inverse to the commutator with \(UD_\Lambda-hM_\Lambda\) on \(D_\Lambda\)-off-diagonal terms. This is conceptually related to quasi-adiabatic and spectral-flow constructions of quasi-local inverses of Liouvillians on suitable off-diagonal subspaces; see, for example, Teufel’s work on NEASS and linear response [24].

In the present paper, however, we do not use the general spectral-flow machinery. The inverse \(\mathcal{I}_h\) is constructed directly from the strong-coupling \(D_\Lambda\)-grading of the half-filled Hubbard model and is estimated in finite-volume interaction norms. For related operator-theoretic ideas in a different setting, see also [25].

2.2 Quantitative convergence of the Lie–Schwinger iteration↩︎

2.2.0.1 Convention on constants in the large-\(U\) regime.

Throughout the LS/SW analysis, constants may depend on \(d,\kappa\), on the fixed range of the hopping interaction, and on the fixed field window size \(h_0\). We fix once and for all a threshold \(U_\ast=U_\ast(d,\kappa,h_0)\) and work under the standing assumption \(U\ge U_\ast\). This threshold is chosen large enough so that the bounds for the field-dependent homological inverse \(\mathcal{I}_h\) are uniform for all \(|h|\le h_0\). After this choice, constants depending on \(h_0/U\) are absorbed into constants depending only on the fixed parameters, and we write them as \(C(d,\kappa)\), \(q(d,\kappa)\), \(\varepsilon_\ast(d,\kappa)\), and so on.

Lemma 15 (One Lie–Schwinger step: quantitative form). Fix \(h_0>0\) and assume \(|h|\le h_0\). Let \[H=UD_\Lambda-hM_\Lambda+B\] on \(\mathcal{H}_\Lambda^{\rm hf}\), where \(B\) is a self-adjoint finite-range interaction. Write \[B=B^{\rm diag}+B^{\rm off}\] with respect to the \(D_\Lambda\)-grading, and set \(S:=\mathcal{I}_h(B^{\rm off}).\) Then \[\mathrm{ad}_S(UD_\Lambda-hM_\Lambda)=-B^{\rm off}.\] Moreover, \(S^\ast=-S\), and hence \(e^S\) is unitary.

Assume that, for some fixed \(\rho_0\in(0,1)\), \[\label{eq:spec-LS-smallness} 2s(B)\|S\|_\kappa\le \rho_0 .\qquad{(2)}\] Let \[H^+:=e^SHe^{-S}, \qquad B^+:=H^+-(UD_\Lambda-hM_\Lambda).\] Then \[H^+ = UD_\Lambda-hM_\Lambda+(B^+)^{\rm diag}+(B^+)^{\rm off},\] and one has the bounds \[\begin{align} \|(B^+)^{\rm off}\|_\kappa &\le C_1(d,\kappa,\rho_0)\, \|S\|_\kappa \bigl( \|B^{\rm diag}\|_\kappa+\|B^{\rm off}\|_\kappa \bigr), \label{eq:spec-off-step-bound} \\ \|(B^+)^{\rm diag}-B^{\rm diag}\|_\kappa &\le C_2(d,\kappa,\rho_0) \left[ \|S\|_\kappa\|B^{\rm off}\|_\kappa + \|S\|_\kappa^2 \bigl( \|B^{\rm diag}\|_\kappa+\|B^{\rm off}\|_\kappa \bigr) \right]. \label{eq:spec-diag-step-bound} \end{align}\] {#eq: sublabel=eq:eq:spec-off-step-bound,eq:eq:spec-diag-step-bound} Furthermore, if \(U>h_0s(B),\) then \[\label{eq:spec-S-bound} \|S\|_\kappa \le \frac{2s(B)}{U-h_0s(B)} \|B^{\rm off}\|_\kappa.\qquad{(3)}\] In particular, if \[\label{eq:CI-absorb-condition} \frac{h_0}{U}s(B)\le \frac{1}{2},\qquad{(4)}\] then \[\label{eq:spec-S-bound-simplified} \|S\|_\kappa \le \frac{4s(B)}{U}\|B^{\rm off}\|_\kappa.\qquad{(5)}\]

Proof. See Appendix 8.3, §8.3.1. ◻

2.2.0.2 Iteration: abstract LS/SW scheme.

Fix \(U>0\) and \(|h|\le h_0\). Let \(B_0=B_{0,\Lambda}(h)\) be a self-adjoint finite-range interaction on \(\Lambda\), and set \[H^{(0)} := UD_\Lambda-hM_\Lambda+B_0 .\]

By our standing convention, each interaction is identified with its finite-volume sum whenever no confusion can arise. The norm \(\|\cdot\|_\kappa\), the \(D_\Lambda\)-grading, and the diagonal/off- diagonal decompositions are all taken at the interaction level.

For \(n\ge0\), suppose that \[H^{(n)} = UD_\Lambda-hM_\Lambda+B_n\] has been constructed, with \(B_n\) viewed as an interaction. Define \(S_n := \mathcal{I}_h\bigl((B_n)^{\rm off}\bigr),\) and set \[H^{(n+1)} := e^{S_n}H^{(n)}e^{-S_n}, \qquad B_{n+1} := H^{(n+1)}-(UD_\Lambda-hM_\Lambda).\] By the defining property of \(\mathcal{I}_h\), \[\mathrm{ad}_{S_n}(UD_\Lambda-hM_{\Lambda})=-\mathrm{ad}_{UD_{\Lambda}-hM_{\Lambda}}(S_n) = -(B_n)^{\rm off}.\] Thus the first-order \(D_\Lambda\)-off-diagonal part of \(B_n\) is cancelled at the \(n\)-th step.

If \(B_0\) is self-adjoint, then each \(B_n\) is self-adjoint. Moreover, \(S_n^\ast=-S_n,\) so every step is implemented by a unitary conjugation.

Proposition 16 (Contraction and convergence). Fix \(h_0>0\) and \(\kappa>0\). Assume \(U\ge U_\ast\), where \(U_\ast=U_\ast(d,\kappa,h_0)\) is chosen so that the large-\(U\) convention in Subsection 2.2 applies. Then there exist \[\varepsilon_\ast=\varepsilon_\ast(d,\kappa)>0, \qquad q=q(d,\kappa)\in(0,1), \qquad C_\ast=C_\ast(d,\kappa)<\infty,\] such that the following holds.

Let \(|h|\le h_0\), and let \(B_0=B_{0,\Lambda}(h)\) be a self-adjoint finite-range interaction. Set \[H^{(0)} := UD_\Lambda-hM_\Lambda+B_0 .\] Assume \[\|(B_0)^{\rm off}\|_\kappa\le \varepsilon_\ast U, \qquad \|(B_0)^{\rm diag}\|_\kappa\le \varepsilon_\ast U.\] Then the LS/SW iteration defined above is well-defined for all \(n\ge0\), and \[\begin{align} \|(B_{n+1})^{\rm off}\|_\kappa &\le q\,\|(B_n)^{\rm off}\|_\kappa, \label{eq:spec-linear-contract} \\ \|(B_{n+1})^{\rm diag}-(B_n)^{\rm diag}\|_\kappa &\le C_\ast\, \frac{\|(B_n)^{\rm off}\|_\kappa^2}{U}. \label{eq:spec-diag-increment} \end{align}\] {#eq: sublabel=eq:eq:spec-linear-contract,eq:eq:spec-diag-increment} Moreover, \[\sum_{n\ge0}\|S_n\|_\kappa<\infty.\] Consequently, the product unitary \[U_{\rm SW} := \lim_{N\to\infty} e^{S_{N-1}}\cdots e^{S_1}e^{S_0}\] exists in finite volume, in operator norm, and \[U_{\rm SW}H^{(0)}U_{\rm SW}^{\ast} = UD_\Lambda-hM_\Lambda+B_\infty(h),\] where \(B_\infty(h)\) is \(D_\Lambda\)-diagonal. Furthermore, \[\label{eq:spec-B-infty-bound} \|B_\infty(h)-(B_0)^{\rm diag}\|_\kappa \le C_\ast\, \frac{\|(B_0)^{\rm off}\|_\kappa^2}{U}.\qquad{(6)}\] More quantitatively, after enlarging \(C_\ast\) if necessary, \[\label{eq:spec-generator-sum-bound} \sum_{n\ge0}\|S_n\|_\kappa \le C_\ast\, \frac{\|(B_0)^{\rm off}\|_\kappa}{U}.\qquad{(7)}\] All constants are independent of \(L\), \(h\), \(U\), and \(B_0\), subject to the assumptions above.

Proof. See Appendix 8.3, §8.3.2. ◻

Corollary 17 (Small-\(|t|/U\) regime for the LS/SW iteration). Fix \(h_0>0\) and \(\kappa>0\). Assume \(U\ge U_\ast\), where \(U_\ast=U_\ast(d,\kappa,h_0)\) is the standing large-\(U\) threshold in Proposition 16. Let \[\varepsilon_\ast=\varepsilon_\ast(d,\kappa)>0, \qquad q=q(d,\kappa)\in(0,1), \qquad C_\ast=C_\ast(d,\kappa)<\infty\] be as in Proposition 16.

Let \(C_T(d,\kappa)\ge1\) be a constant such that, uniformly in \(\Lambda\), \[\|T_\Lambda\|_\kappa\le C_T(d,\kappa)|t|, \qquad \|(T_\Lambda)^{\rm off}\|_\kappa\le C_T(d,\kappa)|t|, \qquad \|T_\Lambda^{(0)}\|_\kappa\le C_T(d,\kappa)|t|.\] Here \(C_T(d,\kappa)\) is enlarged, if necessary, to absorb the fixed finite-range constants coming from the \(D_\Lambda\)-grading.

Define \[\varepsilon_{\rm SW}(d,\kappa) := \min\left\{ 1,\, \frac{\varepsilon_\ast(d,\kappa)}{2C_T(d,\kappa)} \right\}.\] Assume \(|h|\le h_0\) and \(|t|/U\le \varepsilon_{\rm SW}(d,\kappa).\) Set \[B_{0,\Lambda}:=T_\Lambda, \qquad H_\Lambda^{(0)}(h) := H_\Lambda^{\rm Hub}(h) = UD_\Lambda-hM_\Lambda+B_{0,\Lambda}.\] Then, uniformly in \(\Lambda\), \[\|(B_{0,\Lambda})^{\rm off}\|_\kappa = \|(T_\Lambda)^{\rm off}\|_\kappa \le \varepsilon_\ast U, \qquad \|(B_{0,\Lambda})^{\rm diag}\|_\kappa = \|T_\Lambda^{(0)}\|_\kappa \le \varepsilon_\ast U.\] Hence the hypotheses of Proposition 16 hold for the Hubbard initial datum \[H_\Lambda^{(0)}(h) = H_\Lambda^{\rm Hub}(h) = UD_\Lambda-hM_\Lambda+T_\Lambda .\] Consequently, the LS/SW iteration is well-defined for all \(n\ge0\), and ?? –?? hold for the sequence \((B_n,S_n)\) generated from this initial datum.

In particular, the product unitary \(U_{\rm SW}=U_{\rm SW}(h)\) exists and \[U_{\rm SW}(h)H_\Lambda^{\rm Hub}(h)U_{\rm SW}(h)^\ast = UD_\Lambda-hM_\Lambda+B_\infty(h), \qquad [B_\infty(h),D_\Lambda]=0.\] Writing \[\Delta_\Lambda(h) := B_\infty(h)-T_\Lambda^{(0)},\] we obtain \[U_{\rm SW}(h)H_\Lambda^{\rm Hub}(h)U_{\rm SW}(h)^\ast = UD_\Lambda-hM_\Lambda+T_\Lambda^{(0)}+\Delta_\Lambda(h), \qquad [\Delta_\Lambda(h),D_\Lambda]=0.\] Moreover, \[\|\Delta_\Lambda(h)\|_\kappa \le \widetilde{C}(d,\kappa)\frac{t^2}{U}, \qquad \widetilde{C}(d,\kappa):=C_\ast(d,\kappa)C_T(d,\kappa)^2.\] Finally, after enlarging \(C_\ast(d,\kappa)\) if necessary, the generators satisfy \[\sum_{n\ge0}\|S_n(h)\|_\kappa \le C_\ast(d,\kappa)\frac{|t|}{U}.\]

Proof. See Appendix 8.3, §8.3.3. ◻

Remark 18. In the main comparison theorem, \(t\in\mathbb{R}\setminus\{0\}\) is fixed and \(U\to\infty\). Equivalently, \(J_0(U):=\frac{4t^2}{U}\downarrow0.\) In particular, \(\frac{|t|}{U} = \frac{J_0(U)}{4|t|} \xrightarrow[U\to\infty]{} 0.\) Thus the perturbative smallness condition \(|t|/U\le\varepsilon_{\rm SW}\) needed to initialise the LS/SW scheme imposes no additional restriction beyond taking \(U\) sufficiently large for fixed \(t\). This condition, as well as the large-\(U\) uniformity required for the bounds on \(\mathcal{I}_h\), is absorbed into the final threshold in the main theorem. All thresholds are independent of the volume \(\Lambda\).

2.2.0.3 Notation for the LS/SW output.

With \(\Delta_\Lambda(h)\) as in Corollary 17, set \[\label{eq:def-A-Lambda} A_\Lambda(h) := -hM_\Lambda+T_\Lambda^{(0)}+\Delta_\Lambda(h), \qquad [A_\Lambda(h),D_\Lambda]=0.\tag{10}\] We also define the \(P\)-block Hamiltonian by \[H_{P,\Lambda}(h):=P A_\Lambda(h)P.\] The following sections analyse \(A_\Lambda(h)\), its \(P\)-block, and their comparison with the effective Heisenberg reference model.

3 Two deformations and the second-order connection↩︎

3.1 The \(\xi\)-scheme and the second-order effective term↩︎

The second-order effective spin Hamiltonian is defined using the full hopping-scale deformation \[H_\Lambda(h;\xi) := UD_\Lambda-hM_\Lambda+\xi T_\Lambda, \qquad \xi\in[0,1].\] Assume \(|h|\le h_0\), \(|\xi|\le1\), and that the hypotheses of Corollary 17 hold for the \(\xi\)-deformed Hamiltonian. Equivalently, it suffices to impose the smallness condition at \(\xi=1\). The LS/SW iteration yields a product unitary \(U_{\rm SW}(\xi)\) and a \(D_\Lambda\)-diagonal correction \(\Delta_\Lambda(h;\xi)\) such that \[U_{\rm SW}(\xi)H_\Lambda(h;\xi)U_{\rm SW}(\xi)^\ast = UD_\Lambda-hM_\Lambda+\xi T_\Lambda^{(0)} +\Delta_\Lambda(h;\xi), \qquad [\Delta_\Lambda(h;\xi),D_\Lambda]=0.\] Since \(H_\Lambda(h;0)=UD_\Lambda-hM_\Lambda\) is already \(D_\Lambda\)-diagonal, one has \(\Delta_\Lambda(h;0)=0.\) The first-order coefficient also vanishes, and we write \[\label{eq:xi-expansion-Binf} \Delta_\Lambda(h;\xi) = \sum_{n\ge2}\xi^n(\Delta_\Lambda)^{[n]}_{\xi}(h).\tag{11}\] We define the second-order effective term by \[\label{eq:def-H2} H^{(2)}_\Lambda(h) := (\Delta_\Lambda)^{[2]}_{\xi}(h) = \frac{1}{2} \frac{d^2}{d\xi^2} \Delta_\Lambda(h;\xi)\Big|_{\xi=0}.\tag{12}\] This is the term which will be identified with the antiferromagnetic Heisenberg interaction in Section 4.

For later use, we also record the endpoint remainder \[\label{eq:def-K-xi} K_\Lambda^{\xi}(h) := \Delta_\Lambda(h;\xi)\big|_{\xi=1} - H^{(2)}_\Lambda(h).\tag{13}\] Thus, at the physical endpoint, \[\Delta_\Lambda(h) = H^{(2)}_\Lambda(h)+K_\Lambda^{\xi}(h).\]

3.2 The auxiliary \(\lambda\)-deformation↩︎

We shall also use the auxiliary deformation \[H_\Lambda(h;\lambda) := UD_\Lambda-hM_\Lambda+T_\Lambda^{(0)} +\lambda (T_\Lambda)^{\rm off}, \qquad \lambda\in[0,1].\] This deformation has the same physical endpoint as the \(\xi\)-scheme, but a different reference point at zero. Indeed, \[H_\Lambda(h;\lambda)\big|_{\lambda=1} = H_\Lambda(h;\xi)\big|_{\xi=1} = UD_\Lambda-hM_\Lambda+T_\Lambda,\] whereas \[H_\Lambda(h;\lambda)\big|_{\lambda=0} = UD_\Lambda-hM_\Lambda+T_\Lambda^{(0)}, \qquad H_\Lambda(h;\xi)\big|_{\xi=0} = UD_\Lambda-hM_\Lambda.\]

Under the same smallness assumptions, the LS/SW iteration applied to \(H_\Lambda(h;\lambda)\) yields a unitary \(U_{\rm SW}(\lambda)\) and a \(D_\Lambda\)-diagonal correction \(\Delta_\Lambda(h;\lambda)\) such that \[U_{\rm SW}(\lambda)H_\Lambda(h;\lambda)U_{\rm SW}(\lambda)^\ast = UD_\Lambda-hM_\Lambda+T_\Lambda^{(0)} +\Delta_\Lambda(h;\lambda), \qquad [\Delta_\Lambda(h;\lambda),D_\Lambda]=0.\] Since the \(\lambda=0\) Hamiltonian is already \(D_\Lambda\)-diagonal, \(\Delta_\Lambda(h;0)=0.\) The first-order coefficient vanishes, and we write \[\label{eq:lambda-expansion-Binf} \Delta_\Lambda(h;\lambda) = \sum_{n\ge2}\lambda^n(\Delta_\Lambda)^{[n]}_{\lambda}(h).\tag{14}\]

The \(\lambda\)-deformation plays a specific technical role in this paper. It is not used to define the second-order effective term; that role belongs to the \(\xi\)-scheme. Instead, the \(\lambda\)-scheme is used to compare the full physical endpoint correction \[\Delta_\Lambda(h) = \Delta_\Lambda(h;\lambda)\big|_{\lambda=1}\] with the second-order coefficient \(H_\Lambda^{(2)}(h)\) defined through the \(\xi\)-scheme. This comparison is one of the main technical inputs for the control of the \(P\)-block remainder, and the required estimates are carried out in Appendix 10.

Remark 19 (The two coefficient expansions are different). The \(\lambda\)- and \(\xi\)-deformations have the same physical endpoint, \[\Delta_\Lambda(h;\lambda)\big|_{\lambda=1} = \Delta_\Lambda(h;\xi)\big|_{\xi=1} = \Delta_\Lambda(h),\] but their Taylor coefficients at the origin are different in general. In particular, \(H_\Lambda^{(2)}(h) = (\Delta_\Lambda)^{[2]}_{\xi}(h)\) is defined through the \(\xi\)-scheme and should not be identified with \((\Delta_\Lambda)^{[2]}_{\lambda}(h)\).

3.3 The second-order coefficient in the \(\xi\)-scheme↩︎

Lemma 20 (Second-order diagonal correction in the \(\xi\)-scheme). Let \(\Delta_\Lambda(h;\xi)\) be the \(D_\Lambda\)-diagonal LS/SW correction in the \(\xi\)-scheme, defined by 11 . Then \[(\Delta_\Lambda)^{[2]}_{\xi}(h) = \frac{1}{2} \left( \mathrm{ad}_{\mathcal{I}_h\left((T_\Lambda)^{\rm off}\right)}\left( (T_\Lambda)^{\rm off}\right) \right)^{\rm diag}.\]

Proof. See Appendix 8.6, §8.6.1. ◻

Lemma 21 (Second-order comparison of the auxiliary and \(\xi\)-deformations). Assume \(|h|\le h_0\) and \(U\ge U_\ast\). Let \(\Delta_\Lambda(h;\lambda)\) be the \(D_\Lambda\)-diagonal LS/SW correction for the auxiliary \(\lambda\)-deformation 14 , and let \(\Delta_\Lambda(h;\xi)\) be the \(D_\Lambda\)-diagonal LS/SW correction for the \(\xi\)-deformation 11 . Then \[(\Delta_\Lambda)^{[2]}_{\lambda}(h) = (\Delta_\Lambda)^{[2]}_{\xi}(h) + \mathcal{R}^{(2)}_\Lambda(h) + \mathcal{E}^{(2)}_\Lambda(h),\] where \[\mathcal{R}^{(2)}_\Lambda(h) := \frac{1}{2} \left( \mathrm{ad}^2_{\mathcal{I}_h\bigl((T_\Lambda)^{\rm off}\bigr)} (T_{\Lambda}^{(0)})\right)^{\rm diag},\] and \[\mathcal{E}^{(2)}_\Lambda(h) := (\Delta_\Lambda)^{[2]}_{\lambda}(h) - (\Delta_\Lambda)^{[2]}_{\xi}(h) - \mathcal{R}^{(2)}_\Lambda(h).\] Thus \(\mathcal{R}^{(2)}_\Lambda(h)\) is the explicit third-order commutator correction caused by the diagonal hopping \(T_\Lambda^{(0)}\), while \(\mathcal{E}^{(2)}_\Lambda(h)\) is the remaining higher-order residual in this second-order comparison.

Both \(\mathcal{R}^{(2)}_\Lambda(h)\) and \(\mathcal{E}^{(2)}_\Lambda(h)\) are \(D_\Lambda\)-diagonal. Moreover, after increasing \(U_\ast\) if necessary, there exist constants \(C_{R,0}(d)\ge1\) and \(C_{E,0}(d)\ge1\) such that, uniformly in \(\Lambda\) and \(|h|\le h_0\), \[\|\mathcal{R}^{(2)}_\Lambda(h)\|_0 \le C_{R,0}(d)\frac{|t|^3}{U^2}, \qquad \|\mathcal{E}^{(2)}_\Lambda(h)\|_0 \le C_{E,0}(d)\frac{|t|^4}{U^3}.\]

Proof. See Appendix 8.6, §8.6.2. ◻

4 The second-order \(P\)-block and its Heisenberg form↩︎

4.1 Spin representation of the \(D_\Lambda=0\) half-filled block↩︎

4.1.0.1 Canonical identification with the spin Hilbert space.

Recall the spin Hilbert space \(\mathcal{H}^{\rm spin}_\Lambda\) introduced in Subsection 1.3. In this subsection we fix the explicit unitary identification between this spin space and the singly occupied subspace of the half-filled fermionic Hilbert space.

Fix once and for all an ordering \(\Lambda=\{x_1,\dots,x_{|\Lambda|}\}.\) We view \[\mathcal{H}^{\rm spin}_\Lambda = \bigotimes_{j=1}^{|\Lambda|}\mathbb{C}^2\] with the \(j\)-th tensor factor assigned to the site \(x_j\), and with standard basis \(|\!\uparrow\, \rangle_{x_j}\) and \(|\!\downarrow\, \rangle_{x_j}.\) On the fermionic side we work on \(\mathcal{H}^{\rm hf}_\Lambda\) and recall \(P := \mathbb{1}_{\{D_\Lambda=0\}} \restriction _{\mathcal{H}^{\rm hf}_\Lambda}.\) For \(\boldsymbol{\sigma}\in\{\uparrow,\downarrow\}^{\Lambda}\), define \[|\boldsymbol{\sigma}\rangle_{\rm f} := c_{x_1\sigma_{x_1}}^\ast \cdots c_{x_{|\Lambda|}\sigma_{x_{|\Lambda|}}}^\ast |0\rangle .\] Then \(\{ |\boldsymbol{\sigma}\rangle_{\rm f} \}_{\boldsymbol{\sigma}\in\{\uparrow,\downarrow\}^{\Lambda}}\) is an orthonormal basis of \(P\mathcal{H}^{\rm hf}_\Lambda\). We define the unitary identification \[\label{eq:def-U-spin-identification} \mathcal{U}_\Lambda: P\mathcal{H}^{\rm hf}_\Lambda \longrightarrow \mathcal{H}^{\rm spin}_\Lambda\tag{15}\] by \[\mathcal{U}_\Lambda |\boldsymbol{\sigma}\rangle_{\rm f} := \bigotimes_{j=1}^{|\Lambda|} |\sigma_{x_j}\rangle_{x_j}.\]

4.1.0.2 Spin operators and bond projector.

Let \(\sigma^{(1)},\sigma^{(2)},\sigma^{(3)}\) be the Pauli matrices. On \(\mathcal{H}^{\rm hf}_\Lambda\), define the fermionic local spin operators by \[S_x^{(a)} := \frac{1}{2} \sum_{\alpha,\beta\in\{\uparrow,\downarrow\}} c_{x\alpha}^\ast (\sigma^{(a)})_{\alpha\beta} c_{x\beta}, \qquad a\in\{1,2,3\},\] and set \(\boldsymbol{S}_x := \bigl(S_x^{(1)},S_x^{(2)},S_x^{(3)}\bigr).\)

Let \(\mathcal{U}_\Lambda: P\mathcal{H}_\Lambda^{\rm hf} \longrightarrow \mathcal{H}_\Lambda^{\rm spin}\) be the canonical identification of the singly occupied fermionic sector with the spin Hilbert space. To state the identification without ambiguity, let \(S_{x,{\rm spin}}^{(a)}\) denote the usual spin-\(\frac{1}{2}\) operator on \(\mathcal{H}_\Lambda^{\rm spin}\) acting on the tensor factor at \(x\). Then, with \(\boldsymbol{S}_{x,{\rm spin}} := \bigl( S_{x,{\rm spin}}^{(1)}, S_{x,{\rm spin}}^{(2)}, S_{x,{\rm spin}}^{(3)} \bigr),\) one has \[\label{eq:spin-identification} \mathcal{U}_\Lambda (P\boldsymbol{S}_xP) \mathcal{U}_\Lambda^\ast = \boldsymbol{S}_{x,{\rm spin}}, \qquad x\in\Lambda .\tag{16}\] After this identification is fixed, we suppress the subscript \({\rm spin}\) and write simply \(S_x^{(a)}\) and \(\boldsymbol{S}_x\) for the corresponding spin-space operators whenever the ambient Hilbert space is clear.

For a nearest-neighbour bond \(\langle x,y\rangle\), let \(P_{xy}\) be the swap operator on \(\mathcal{H}^{\rm spin}_\Lambda\), defined on the two tensor factors at \(x\) and \(y\) by \[P_{xy} \bigl( |\sigma\rangle_x\otimes|\tau\rangle_y \bigr) := |\tau\rangle_x\otimes|\sigma\rangle_y\] and extended as the identity on all other tensor factors. Define \[\label{eq:def-Bxy-spin} B_{xy} := \frac{1}{2}(\mathbb{1}-P_{xy}).\tag{17}\] The standard two-spin identities give \[\label{eq:bond-density-identities} P_{xy} = 2\boldsymbol{S}_x\cdot\boldsymbol{S}_y+\frac{1}{2}, \qquad B_{xy} = \frac{1}{4}-\boldsymbol{S}_x\cdot\boldsymbol{S}_y,\tag{18}\] where \[\boldsymbol{S}_x\cdot\boldsymbol{S}_y := \sum_{a=1}^3 S_x^{(a)}S_y^{(a)}.\] In particular, on \(\mathbb{C}^2\otimes\mathbb{C}^2\), \(B_{xy}\) is the orthogonal projection onto the singlet subspace.

4.1.0.3 Heisenberg Hamiltonian and the bond projector.

Recall the Heisenberg reference Hamiltonian with staggered field from Subsection 1.3. With \(\mathscr B_\Lambda\) denoting the set of unordered nearest-neighbour bonds in \(\Lambda\), it is given by \[H_\Lambda^{\rm Heis}(J,h) = J\sum_{\{x,y\}\in\mathscr B_\Lambda} \left( \boldsymbol{S}_x\cdot\boldsymbol{S}_y-\frac{1}{4} \right) - hM_\Lambda^{\rm spin}.\] The point used below is that the interaction term can be written in terms of the singlet bond projector \(B_{xy}\). Indeed, by 18 , \[\begin{align} H_\Lambda^{\rm Heis}(J,h) = -J\sum_{\{x,y\}\in\mathscr B_\Lambda}B_{xy} - hM_\Lambda^{\rm spin}. \label{eq:def-Heis-J} \end{align}\tag{19}\]

Proposition 22 (Heisenberg form of the second-order \(P\)-block Hamiltonian). Work on \(\mathcal{H}^{\rm hf}_\Lambda\) and let \(P:=\mathbb{1}_{\{D_\Lambda=0\}}\restriction_{\mathcal{H}_\Lambda^{\rm hf}}.\) Let \(\mathcal{U}_\Lambda: P\mathcal{H}^{\rm hf}_\Lambda \longrightarrow \mathcal{H}^{\rm spin}_\Lambda\) be the unitary identification in 15 . Let \[H^{(2)}_\Lambda(h):=(\Delta_\Lambda)^{[2]}_\xi(h)\] be the second-order diagonal coefficient in the \(\xi\)-scheme. Then, for every \(|h|\le h_0\), one has on \(\mathcal{H}^{\rm spin}_\Lambda\) \[\label{eq:H2-to-Heis-prop} \mathcal{U}_\Lambda P\bigl(-hM_\Lambda+H^{(2)}_\Lambda(h)\bigr)P \mathcal{U}_\Lambda^\ast = H^{\rm Heis}_\Lambda\bigl(J(h),h_{\rm eff}(h)\bigr),\qquad{(8)}\] where \[\label{eq:def-J-heff} J(h) := \frac{4t^2U}{U^2-h^2}, \qquad h_{\rm eff}(h) := h-\frac{4dht^2}{U^2-h^2}.\qquad{(9)}\]

Proof. See Appendix 9, § 9.3. ◻

Remark 23 (Intermediate effective parameters). The parameters \(J(h)\) and \(h_{\rm eff}(h)\) arise from the exact second-order computation in the defect-free \(P\)-block. They should be viewed as renormalized parameters of the intermediate effective spin Hamiltonian appearing in the proof. The main comparison theorem, however, is stated with the Heisenberg reference model \(H_\Lambda^{\rm Heis}(J_0(U),h)\) with \(J_0(U):=\frac{4t^2}{U}.\) For \(|h|\le h_0\) and \(U>h_0\), one has the elementary bounds \[|J(h)-J_0(U)| \le C(h_0)|t|^2\frac{1}{U^3}, \qquad |h_{\rm eff}(h)-h| \le C(d,h_0)|t|^2\frac{1}{U^2}.\] Thus the passage from the intermediate effective spin Hamiltonian \(H_\Lambda^{\rm Heis}(J(h),h_{\rm eff}(h))\) to the Heisenberg reference model \(H_\Lambda^{\rm Heis}(J_0(U),h)\) amounts to a small renormalized-parameter mismatch on fixed field windows. This mismatch is controlled later in the \(P\)-block-to-reference pressure comparison. The final magnetisation estimate is then obtained from the assembled pressure comparison by the fixed-window convexity argument.

5 Comparison of the \(P\)-block with the Heisenberg reference model↩︎

The purpose of this section is to compare the effective Hamiltonian on the \(P\)-block with the Heisenberg reference Hamiltonian used in the pressure comparison theorem. All estimates in this section are uniform for \(|h|\le h_0.\) No positivity of the field is used here; the restriction to fixed positive field windows enters later, when pressure comparison is converted into magnetisation comparison by convexity.

Recall from 10 that the LS/SW output is \[A_\Lambda(h) = -hM_\Lambda+T_\Lambda^{(0)}+\Delta_\Lambda(h), \qquad [A_\Lambda(h),D_\Lambda]=0.\] The effective \(P\)-block Hamiltonian is \[H_{P,\Lambda}(h) := PA_\Lambda(h)P.\] Since \(PT_\Lambda^{(0)}P=0,\) we have \[\label{eq:P-block-Hamiltonian-basic} H_{P,\Lambda}(h) = P\bigl(-hM_\Lambda+\Delta_\Lambda(h)\bigr)P.\tag{20}\]

The second-order term used for the Heisenberg identification was computed through the \(\xi\)-deformation. In this section we compare the full LS/SW endpoint correction \(\Delta_\Lambda(h)\) with this second-order term, and absorb the remaining contributions into the \(P\)-block remainder. This gives a pressure comparison between the effective \(P\)-block Hamiltonian and the Heisenberg reference model.

5.1 Intermediate effective spin Hamiltonian and \(P\)-block remainder↩︎

Let \(H_\Lambda^{(2)}(h) = (\Delta_\Lambda)^{[2]}_{\xi}(h)\) be the second-order coefficient defined through the \(\xi\)-scheme. We decompose the effective \(P\)-block Hamiltonian as \[\label{eq:P-block-intermediate-decomposition} H_{P,\Lambda}(h) = P\bigl(-hM_\Lambda+H_\Lambda^{(2)}(h)\bigr)P + R_{P,\Lambda}(h),\tag{21}\] where \[\label{eq:def-P-block-remainder} R_{P,\Lambda}(h) := P\bigl(\Delta_\Lambda(h)-H_\Lambda^{(2)}(h)\bigr)P .\tag{22}\] Thus \(R_{P,\Lambda}(h)\) measures the part of the LS/SW endpoint correction which is not captured by the \(\xi\)-second-order term.

The use of \(H_\Lambda^{(2)}(h)\) here is justified by the comparison between the \(\xi\)-scheme and the auxiliary deformation. In particular, Lemma 21 identifies the explicit second-order mismatch and shows that the remaining residual is of higher order. These contributions are absorbed into the \(P\)-block remainder estimated below.

Under the spin identification \(\mathcal{U}_\Lambda: P\mathcal{H}_\Lambda^{\rm hf} \longrightarrow \mathcal{H}_\Lambda^{\rm spin},\) define the spin representative of the \(P\)-block remainder by \[\label{eq:def-spin-P-block-remainder} \mathcal{R}_{P,\Lambda}(h) := \mathcal{U}_\Lambda R_{P,\Lambda}(h)\mathcal{U}_\Lambda^\ast .\tag{23}\] By Proposition 22, \(\mathcal{U}_\Lambda P\bigl(-hM_\Lambda+H_\Lambda^{(2)}(h)\bigr)P \mathcal{U}_\Lambda^\ast = H_\Lambda^{\rm Heis}(J(h),h_{\rm eff}(h)).\) Consequently, \[\label{eq:P-block-spin-representation-with-remainder} \mathcal{U}_\Lambda H_{P,\Lambda}(h)\mathcal{U}_\Lambda^\ast = H_\Lambda^{\rm Heis}(J(h),h_{\rm eff}(h)) + \mathcal{R}_{P,\Lambda}(h).\tag{24}\]

The rest of this section compares the right-hand side of 24 with the Heisenberg reference model \(H_\Lambda^{\rm Heis}(J_0(U),h)\) with \(J_0(U)=\frac{4t^2}{U}.\) There are two contributions to control:

  1. the explicit difference between the intermediate effective parameters and the reference parameters, \(H_\Lambda^{\rm Heis}(J(h),h_{\rm eff}(h)) - H_\Lambda^{\rm Heis}(J_0(U),h);\)

  2. the \(P\)-block remainder \(\mathcal{R}_{P,\Lambda}(h)\).

Both are estimated uniformly for \(|h|\le h_0\). These estimates give the \(P\)-block-to-Heisenberg-reference pressure comparison used in the final assembly.

5.2 From the intermediate effective parameters to the reference model↩︎

The main theorem is stated with the Heisenberg reference Hamiltonian \(H_\Lambda^{\rm Heis}(J_0(U),h),\) Thus we compare the intermediate effective spin Hamiltonian \(H_\Lambda^{\rm Heis}(J(h),h_{\rm eff}(h))\) with the reference model \(H_\Lambda^{\rm Heis}(J_0(U),h)\).

Proposition 24 (Parameter mismatch with the Heisenberg reference model). Assume \(U>2h_0\). Define \[G_{\Lambda,U}(h) := H_\Lambda^{\rm Heis}(J(h),h_{\rm eff}(h)) - H_\Lambda^{\rm Heis}(J_0(U),h).\] Equivalently, \[\label{eq:parameter-mismatch-operator} G_{\Lambda,U}(h) = \bigl(J(h)-J_0(U)\bigr) \sum_{\{x,y\}\in\mathscr B_\Lambda} \left( \boldsymbol{S}_x\cdot\boldsymbol{S}_y-\frac{1}{4} \right) - \bigl(h_{\rm eff}(h)-h\bigr)M_\Lambda^{\rm spin}.\qquad{(10)}\] Viewed as an interaction on the spin system, \(G_{\Lambda,U}(h)\) satisfies \[\label{eq:reference-parameter-mismatch-bound} \sup_{|h|\le h_0} \|G_{\Lambda,U}(h)\|_0 \le C(d,h_0,t)\frac{1}{U^2},\qquad{(11)}\] and \[\label{eq:reference-parameter-mismatch-derivative-bound} \sup_{|h|\le h_0} \|\partial_hG_{\Lambda,U}(h)\|_0 \le C(d,h_0,t)\frac{1}{U^2}.\qquad{(12)}\] In particular, both estimates hold uniformly for \(|h| \le h_0\).

Proof. See Appendix 10, §10.1. ◻

5.3 Bound on the \(P\)-block remainder↩︎

The next estimate controls the \(P\)-block remainder uniformly on the bounded field window \(|h|\le h_0\). Its \(C^0\)-part is used for the \(P\)-block pressure comparison with the Heisenberg reference model; the \(h\)-derivative bound records the corresponding regularity of the effective \(P\)-block Hamiltonian.

Proposition 25 (Uniform bound on the \(P\)-block remainder). Under the hypotheses of Corollary 17, there exists an error function \(\varepsilon_P(U;h_0)\ge0\) such that, uniformly in the even torus \(\Lambda=\Lambda_L\), \[\label{eq:P-block-remainder-C0-C1-bound} \sup_{|h|\le h_0} \|\mathcal{R}_{P,\Lambda}(h)\|_0 + \sup_{|h|\le h_0} \|\partial_h\mathcal{R}_{P,\Lambda}(h)\|_0 \le \varepsilon_P(U;h_0).\qquad{(13)}\] Moreover, \[\lim_{U\to\infty}\varepsilon_P(U;h_0)=0.\]

Proof. See Appendix 10, §10.2. ◻

Combining 24 with Proposition 24, we can write the spin representative of the effective \(P\)-block Hamiltonian as \[\label{eq:P-block-Heis-reference-plus-perturbation} \mathcal{U}_\Lambda H_{P,\Lambda}(h)\mathcal{U}_\Lambda^\ast = H_\Lambda^{\rm Heis}(J_0(U),h) + W_{P,\Lambda}(h),\tag{25}\] where \[\label{eq:def-P-block-total-perturbation} W_{P,\Lambda}(h) := G_{\Lambda,U}(h)+\mathcal{R}_{P,\Lambda}(h).\tag{26}\] Hence, by Proposition 24 and Proposition 25, \[\label{eq:P-block-total-perturbation-C1-bound} \sup_{|h|\le h_0} \|W_{P,\Lambda}(h)\|_0 + \sup_{|h|\le h_0} \|\partial_hW_{P,\Lambda}(h)\|_0 \le \varepsilon_P(U;h_0)+C(d,h_0,t)U^{-2}.\tag{27}\] In particular, the right-hand side tends to zero as \(U\to\infty\).

5.4 \(P\)-block pressure comparison with the Heisenberg reference model↩︎

Define the \(P\)-block pressure by \[\require{physics} p_{\Lambda,\beta,U}^{P}(h) := \frac{1}{\beta|\Lambda|} \log \Tr_{P\mathcal{H}_\Lambda^{\rm hf}} e^{-\beta H_{P,\Lambda}(h)}.\] Under the spin identification \(\mathcal{U}_\Lambda\), the pressure is unchanged. Therefore, by 25 , the \(P\)-block pressure is the pressure of the Heisenberg reference Hamiltonian perturbed by \(W_{P,\Lambda}(h)\).

Proposition 26 (\(P\)-block pressure comparison with the Heisenberg reference model). Under the hypotheses of Corollary 17, there exists an error function \(\varepsilon_{P}^{\rm FE}(U;h_0)\ge0\) such that, for all \(U\) sufficiently large, all \(\beta>0\), all even tori \(\Lambda=\Lambda_L\), and all \(|h|\le h_0\), \[\left| p_{\Lambda,\beta,U}^{P}(h) - p_{\Lambda,\beta,U}^{\rm Heis}(h) \right| \le \varepsilon_P^{\rm FE}(U;h_0).\] Moreover, \[\lim_{U\to\infty} \varepsilon_P^{\rm FE}(U;h_0) = 0.\]

Proof. By 25 , \(H_{P,\Lambda}(h)\) is unitarily equivalent to \(H_\Lambda^{\rm Heis}(J_0(U),h)+W_{P,\Lambda}(h).\) Hence Lemma 48 gives \[\left| p_{\Lambda,\beta,U}^{P}(h) - p_{\Lambda,\beta,U}^{\rm Heis}(h) \right| \le \|W_{P,\Lambda}(h)\|_0.\] By 27 , in particular, \[\sup_{|h|\le h_0} \|W_{P,\Lambda}(h)\|_0 \le \varepsilon_P(U;h_0)+C(d,h_0,t)U^{-2}.\] Thus we may set \(\varepsilon_P^{\rm FE}(U;h_0) := \varepsilon_P(U;h_0)+C(d,h_0,t)U^{-2}.\) The right-hand side tends to zero as \(U\to\infty\), uniformly in \(\Lambda\), \(\beta\), and \(|h|\le h_0\). This proves the proposition. ◻

Remark 27 (Role of the \(P\)-block comparison). Proposition 26 is the spin-sector pressure comparison. After the LS/SW reduction and restriction to the \(P\)-block, the effective Hamiltonian is a small fixed-field perturbation of the Heisenberg reference Hamiltonian in the sense of pressure. In the final assembly, this pressure estimate is combined with the soft defect estimate to compare the full Hubbard pressure with the Heisenberg reference pressure. The magnetisation comparison in the main theorem is then obtained from the fixed-window pressure comparison by convexity.

6 Defects and comparison with the \(P\)-block↩︎

This section compares the full half-filled Hubbard model with the defect-free \(P\)-block system. The basic mechanism is the defect decomposition of the transformed Hamiltonian \[H_{*,\Lambda}(h) = UD_\Lambda+A_\Lambda(h), \qquad [A_\Lambda(h),D_\Lambda]=0,\] obtained from the LS/SW construction.

The goal is twofold. First, we prove a soft comparison between the full Hubbard pressure and the \(P\)-block pressure. Second, we derive charge-sector estimates, including suppression of double occupancy and absence of macroscopic staggered charge order.

6.1 Transformed partition function and the \(P\)-block pressure↩︎

Assume the hypotheses of Corollary 17. Recall that \[U_{\rm SW}(h)H_\Lambda^{\rm Hub}(h)U_{\rm SW}(h)^\ast = UD_\Lambda+A_\Lambda(h),\] where \(A_\Lambda(h) = -hM_\Lambda+T_\Lambda^{(0)}+\Delta_\Lambda(h).\) By unitary invariance of the trace, \[\require{physics} Z_{\Lambda,\beta,U}^{\rm Hub}(h) = \Tr_{\mathcal{H}_\Lambda^{\rm hf}} e^{-\beta(UD_\Lambda+A_\Lambda(h))}.\] The defect-free \(P\)-block partition function is \[\require{physics} Z_{\Lambda,\beta,U}^{P}(h) := \Tr_{P\mathcal{H}_\Lambda^{\rm hf}} e^{-\beta H_{P,\Lambda}(h)}, \qquad H_{P,\Lambda}(h):=P A_\Lambda(h)P.\] Equivalently, since \(P\) commutes with \(A_\Lambda(h)\), \[\require{physics} Z_{\Lambda,\beta,U}^{P}(h) = \Tr_{\mathcal{H}_\Lambda^{\rm hf}} \left( P e^{-\beta A_\Lambda(h)} \right).\] We define \[p_{\Lambda,\beta,U}^{P}(h) := \frac{1}{\beta|\Lambda|} \log Z_{\Lambda,\beta,U}^{P}(h).\]

6.2 Defect projectors and defect counting↩︎

6.2.0.1 Local defect projectors.

Define \[p_x^{(1)} := n_x-2n_{x\uparrow}n_{x\downarrow}, \qquad q_x:=\mathbb{1}-p_x^{(1)}.\] Equivalently, \[q_x=(n_x-1)^2 = \mathbb{1}-n_x+2n_{x\uparrow}n_{x\downarrow}.\] Thus \(p_x^{(1)}\) projects onto the singly occupied states at \(x\), while \(q_x\) projects onto the empty or doubly occupied states at \(x\).

For \(\mathcal{D}\subset\Lambda\), set \[Q_{\mathcal{D}} := \prod_{x\in\mathcal{D}}q_x \prod_{x\notin\mathcal{D}}p_x^{(1)}.\] Then \(\{Q_{\mathcal{D}}\}_{\mathcal{D}\subset\Lambda}\) are mutually orthogonal projections and \[\sum_{\mathcal{D}\subset\Lambda}Q_{\mathcal{D}} = \mathbb{1} \qquad \text{on }\mathcal{H}_\Lambda^{\rm hf}.\] In particular, \(Q_\varnothing=P.\)

Lemma 28 (Defect counting at half filling). On \(\mathcal{H}_\Lambda^{\rm hf}\), \[\sum_{x\in\Lambda}q_x=2D_\Lambda.\] Consequently, for any \(\mathcal{D}\subset\Lambda\), \[Q_{\mathcal{D}}UD_\Lambda Q_{\mathcal{D}} = \frac{U}{2}|\mathcal{D}|Q_{\mathcal{D}},\] and \(Q_{\mathcal{D}}\mathcal{H}_\Lambda^{\rm hf}=\{0\}\) if \(|\mathcal{D}|\) is odd.

Proof. On the full Fock space, \(q_x = \mathbb{1}-n_x+2n_{x\uparrow}n_{x\downarrow}.\) Hence \[\sum_{x\in\Lambda}q_x = |\Lambda|-\sum_{x\in\Lambda}n_x + 2\sum_{x\in\Lambda}n_{x\uparrow}n_{x\downarrow}.\] On \(\mathcal{H}_\Lambda^{\rm hf}\), one has \(\sum_{x\in\Lambda}n_x=|\Lambda|.\) Therefore \(\sum_{x\in\Lambda}q_x = 2\sum_{x\in\Lambda}n_{x\uparrow}n_{x\downarrow} = 2D_\Lambda.\)

On \(\operatorname{ran}(Q_{\mathcal{D}})\), we have \(q_x=1\) for \(x\in\mathcal{D}\) and \(q_x=0\) for \(x\notin\mathcal{D}\). Thus \(\sum_{x\in\Lambda}q_x=|\mathcal{D}|\) on \(\operatorname{ran}(Q_{\mathcal{D}})\). Combining this with \(\sum_x q_x=2D_\Lambda\) gives \(D_\Lambda=\frac{1}{2}|\mathcal{D}|\) on \(\operatorname{ran}(Q_{\mathcal{D}})\). This proves the stated identity for \(UD_\Lambda\). Since \(D_\Lambda\) has integer spectrum, \(\operatorname{ran}(Q_{\mathcal{D}})\) is zero whenever \(|\mathcal{D}|\) is odd. ◻

6.2.0.2 Defect decomposition of the transformed partition function.

By Lemma 28, \[e^{-\beta UD_\Lambda} = \sum_{\mathcal{D}\subset\Lambda} e^{-\frac{\beta U}{2}|\mathcal{D}|} Q_{\mathcal{D}} \qquad \text{on }\mathcal{H}_\Lambda^{\rm hf}.\] Since \([A_\Lambda(h),D_\Lambda]=0\), we have \(e^{-\beta(UD_\Lambda+A_\Lambda(h))} = e^{-\beta UD_\Lambda}e^{-\beta A_\Lambda(h)}.\) Consequently, \[\require{physics} \label{eq:defect-decomposition-partition} Z_{\Lambda,\beta,U}^{\rm Hub}(h) = \sum_{\mathcal{D}\subset\Lambda} e^{-\frac{\beta U}{2}|\mathcal{D}|} \Tr_{\mathcal{H}_\Lambda^{\rm hf}} \left( Q_{\mathcal{D}}e^{-\beta A_\Lambda(h)} \right).\tag{28}\] The term \(\mathcal{D}=\varnothing\) is exactly the \(P\)-block partition function: \[\require{physics} \Tr_{\mathcal{H}_\Lambda^{\rm hf}} \left( Q_\varnothing e^{-\beta A_\Lambda(h)} \right) = Z_{\Lambda,\beta,U}^{P}(h).\]

6.3 Soft pressure comparison with the \(P\)-block↩︎

The defect decomposition gives a coarse but useful exponential estimate on the difference between the full Hubbard pressure and the \(P\)-block pressure.

Proposition 29 (Soft pressure comparison with the \(P\)-block). Assume the hypotheses of Corollary 17, and let \(A_\Lambda(h)\) be defined by 10 . Then, for all \(|h|\le h_0\), \[\label{eq:defect-pressure-soft} 0 \le p_{\Lambda,\beta,U}^{\rm Hub}(h) - p_{\Lambda,\beta,U}^{P}(h) \le \frac{2}{\beta} \exp\left[ -\beta \left( \frac{U}{2}-4\|A_\Lambda(h)\|_0 \right) \right].\qquad{(14)}\]

Proof. Set \(Z(h):=Z_{\Lambda,\beta,U}^{\rm Hub}(h)\) and \(Z_0(h):=Z_{\Lambda,\beta,U}^{P}(h).\) By 28 , \[\require{physics} \label{eq:defect-Z-sum-pressure} Z(h) = \sum_{\mathcal{D}\subset\Lambda} e^{-\frac{\beta U}{2}|\mathcal{D}|} \Tr_{\mathcal{H}_\Lambda^{\rm hf}} \left( Q_{\mathcal{D}}e^{-\beta A_\Lambda(h)} \right).\tag{29}\] The \(\mathcal{D}=\varnothing\) term is \(\require{physics} \Tr_{\mathcal{H}_\Lambda^{\rm hf}} \left( Q_\varnothing e^{-\beta A_\Lambda(h)} \right) = Z_0(h),\) because \(Q_\varnothing=P\). Hence \(Z(h)\ge Z_0(h)\), and therefore \[p_{\Lambda,\beta,U}^{\rm Hub}(h) - p_{\Lambda,\beta,U}^{P}(h) = \frac{1}{\beta|\Lambda|} \log\frac{Z(h)}{Z_0(h)} \ge0.\]

For \(\mathcal{D}\subset\Lambda\), define \[\require{physics} r_{\mathcal{D}}(h) := \frac{ \Tr\left(Q_{\mathcal{D}}e^{-\beta A_\Lambda(h)}\right) }{ \Tr\left(Q_\varnothing e^{-\beta A_\Lambda(h)}\right) } = \frac{ \Tr\left(Q_{\mathcal{D}}e^{-\beta A_\Lambda(h)}\right) }{ Z_0(h) }.\] We estimate \(r_{\mathcal{D}}(h)\) for \(\mathcal{D}\neq\varnothing\).

Write \(\mathcal{D}^c:=\Lambda\setminus\mathcal{D}\). Decompose \(A_\Lambda(h) = A_{\mathcal{D}}(h) + A_{\mathcal{D}^c}(h) + A_{\partial}(h),\) where \[A_{\mathcal{D}}(h) := \sum_{X\subset\mathcal{D}}(A_\Lambda(h))_X, \qquad A_{\mathcal{D}^c}(h) := \sum_{X\subset\mathcal{D}^c}(A_\Lambda(h))_X,\] and \(A_\partial(h)\) is the sum of those interaction terms \((A_\Lambda(h))_X\) which meet both \(\mathcal{D}\) and \(\mathcal{D}^c\). By the definition of the \(\|\cdot\|_0\)-norm, \[\|A_{\partial}(h)\| \le |\mathcal{D}|\|A_\Lambda(h)\|_0, \qquad \|A_{\mathcal{D}}(h)\| \le |\mathcal{D}|\|A_\Lambda(h)\|_0.\] Using the elementary operator inequalities \(X-\|Y\|\le X+Y\le X+\|Y\|\) for self-adjoint \(X,Y\), we obtain \[\require{physics} r_{\mathcal{D}}(h) \le e^{2\beta\|A_\partial(h)\|} \frac{ \Tr\left( Q_{\mathcal{D}} e^{-\beta(A_{\mathcal{D}}(h)+A_{\mathcal{D}^c}(h))} \right) }{ \Tr\left( Q_{\varnothing} e^{-\beta(A_{\mathcal{D}}(h)+A_{\mathcal{D}^c}(h))} \right) }.\]

We split the projectors into the inside part on \(\mathcal{D}\) and the common outside single-occupancy projector on \(\mathcal{D}^c\). Namely, set \[Q_{\mathcal{D}}^{\rm in} := \prod_{x\in\mathcal{D}}q_x, \qquad Q_{0,\mathcal{D}}^{\rm in} := \prod_{x\in\mathcal{D}}p_x^{(1)}, \qquad Q_{\mathcal{D}}^{\rm out} := \prod_{x\in\mathcal{D}^c}p_x^{(1)}.\] Then \(Q_{\mathcal{D}} = Q_{\mathcal{D}}^{\rm in}Q_{\mathcal{D}}^{\rm out},\) and \(Q_{\varnothing} = Q_{0,\mathcal{D}}^{\rm in}Q_{\mathcal{D}}^{\rm out}.\) Since \(A_{\mathcal{D}^c}(h)\) is an even operator supported in \(\mathcal{D}^c\), it commutes with the inside operators. Moreover, the \(D_\Lambda\)-diagonality and particle-number conservation of \(A_\Lambda(h)\) imply, for the outside-supported part, \[[A_{\mathcal{D}^c}(h),D_{\mathcal{D}^c}]=0, \qquad [A_{\mathcal{D}^c}(h),N_{\mathcal{D}^c}]=0.\] Hence \(A_{\mathcal{D}^c}(h)\) preserves \(\operatorname{Ran}Q_{\mathcal{D}}^{\rm out} = \ker(D_{\mathcal{D}^c})\cap \ker( N_{\mathcal{D}^c}-|\mathcal{D}^c|).\) The restricted trace factorisation lemma, Lemma 50, applied with \(X=\mathcal{D}\) and \(Y=\mathcal{D}^c\), gives \[\require{physics} \frac{ \Tr_{\mathcal{H}_\Lambda^{\rm hf}}\left( Q_{\mathcal{D}} e^{-\beta(A_{\mathcal{D}}(h)+A_{\mathcal{D}^c}(h))} \right) }{ \Tr_{\mathcal{H}_\Lambda^{\rm hf}}\left( Q_{\varnothing} e^{-\beta(A_{\mathcal{D}}(h)+A_{\mathcal{D}^c}(h))} \right) } = \frac{ \Tr_{\mathcal{H}_{\mathcal{D}}^{\rm hf}} \left( Q_{\mathcal{D}}^{\rm in} e^{-\beta A_{\mathcal{D}}(h)} \right) }{ \Tr_{\mathcal{H}_{\mathcal{D}}^{\rm hf}} \left( Q_{0,\mathcal{D}}^{\rm in} e^{-\beta A_{\mathcal{D}}(h)} \right) }.\] Moreover, since \(e^{-\beta A_{\mathcal{D}}(h)} \le e^{\beta\|A_{\mathcal{D}}(h)\|}\mathbb{1},\) and \(e^{-\beta A_{\mathcal{D}}(h)} \ge e^{-\beta\|A_{\mathcal{D}}(h)\|}\mathbb{1},\) we have \[\require{physics} \frac{ \Tr_{\mathcal{H}_{\mathcal{D}}^{\rm hf}} \left( Q^{\rm in}_{\mathcal{D}} e^{-\beta A_{\mathcal{D}}(h)} \right) }{ \Tr_{\mathcal{H}_{\mathcal{D}}^{\rm hf}} \left( Q^{\rm in}_{\varnothing} e^{-\beta A_{\mathcal{D}}(h)} \right) } \le e^{2\beta\|A_{\mathcal{D}}(h)\|} \frac{ \Tr_{\mathcal{H}_{\mathcal{D}}^{\rm hf}} \left( Q^{\rm in}_{\mathcal{D}} \right) }{ \Tr_{\mathcal{H}_{\mathcal{D}}^{\rm hf}} ( Q_{0,\mathcal{D}}^{\rm in} ) }.\] The last ratio is bounded by \(2^{|\mathcal{D}|}\). Therefore \[r_{\mathcal{D}}(h) \le \exp\left[ \left( \log 2+4\beta\|A_\Lambda(h)\|_0 \right) |\mathcal{D}| \right].\]

Using 29 , we obtain \(\frac{Z(h)}{Z_0(h)} = 1+ \sum_{\mathcal{D}\neq\varnothing} e^{-\frac{\beta U}{2}|\mathcal{D}|} r_{\mathcal{D}}(h).\) The preceding bound gives \[\frac{Z(h)}{Z_0(h)} \le 1+ \sum_{\mathcal{D}\neq\varnothing} \left( 2 e^{-\beta(\frac{U}{2}-4\|A_\Lambda(h)\|_0)} \right)^{|\mathcal{D}|}.\] Since there are at most \(\binom{|\Lambda|}{k}\) subsets of size \(k\), we get \[\frac{Z(h)}{Z_0(h)} \le \left( 1+ 2 e^{-\beta(\frac{U}{2}-4\|A_\Lambda(h)\|_0)} \right)^{|\Lambda|}.\] Taking \((\beta|\Lambda|)^{-1}\log\) and using \(\log(1+x)\le x\) gives \[p_{\Lambda,\beta,U}^{\rm Hub}(h) - p_{\Lambda,\beta,U}^{P}(h) \le \frac{2}{\beta} \exp\left[ -\beta \left( \frac{U}{2}-4\|A_\Lambda(h)\|_0 \right) \right].\] This proves ?? . ◻

Corollary 30 (Defect pressure error on the bounded field window). Under the assumptions of Proposition 29, set \[A_{h_0}(U) := \sup_{\Lambda_L} \sup_{|h|\le h_0} \|A_{\Lambda_L}(h)\|_0, \qquad \Gamma_U(h_0) := \frac{U}{2}-4A_{h_0}(U).\] Then, for all \(|h|\le h_0\), \[0 \le p_{\Lambda_L,\beta,U}^{\rm Hub}(h) - p_{\Lambda_L,\beta,U}^{P}(h) \le \varepsilon_{\rm def}^{\rm FE}(U,\beta;h_0),\] where \[\varepsilon_{\rm def}^{\rm FE}(U,\beta;h_0) := \frac{2}{\beta}e^{-\beta\Gamma_U(h_0)}.\] Moreover, for \(U\) sufficiently large, \(\Gamma_U(h_0)>0,\) and, for every \(\ell_0>0\), \[\lim_{U\to\infty} \sup_{\beta J_0(U)\ge \ell_0} \varepsilon_{\rm def}^{\rm FE}(U,\beta;h_0) = 0.\]

Proof. The pressure estimate is an immediate consequence of Proposition 29, after taking the supremum of \(\|A_{\Lambda_L}(h)\|_0\) over \(\Lambda_L\) and \(|h|\le h_0\).

It remains to check that \(\Gamma_U(h_0)>0\) for large \(U\). By \(A_\Lambda(h) = -hM_\Lambda+T_\Lambda^{(0)}+\Delta_\Lambda(h)\) and Corollary 17, we have, uniformly in \(\Lambda_L\) and \(|h|\le h_0\), \(\|A_{\Lambda_L}(h)\|_0 \le C(d,h_0,t).\) Indeed, the field and hopping terms have uniformly bounded \(\|\cdot\|_0\)-norms, and \[\|\Delta_{\Lambda_L}(h)\|_0 \le \|\Delta_{\Lambda_L}(h)\|_\kappa \le \widetilde{C}(d,\kappa)\frac{|t|^2}{U}.\] Hence \(A_{h_0}(U)\le C(d,h_0,t)\) for all sufficiently large \(U\). Therefore \(\Gamma_U(h_0) = \frac{U}{2}-4A_{h_0}(U) \rightarrow\infty \;(U\to\infty),\) and in particular \(\Gamma_U(h_0)>0\) for \(U\) sufficiently large.

Finally, if \(\beta J_0(U)\ge\ell_0\), then \(\beta \ge \frac{\ell_0}{J_0(U)} = \frac{\ell_0 U}{4t^2}.\) Since \(\Gamma_U(h_0)\ge U/4\) for \(U\) sufficiently large, we get \(\frac{2}{\beta}e^{-\beta\Gamma_U(h_0)} \le \frac{2}{\beta}e^{-\beta U/4} \rightarrow0\) uniformly under \(\beta J_0(U)\ge\ell_0\). This proves the claimed limit. ◻

6.4 Charge-sector consequences of the soft defect bound↩︎

We record a charge-sector consequence of the soft defect bound in the LS/SW-diagonal representation. Throughout this subsection the estimates are uniform for \(|h|\le h_0.\)

Define \[H_{*,\Lambda_L}(h):=UD_{\Lambda_L}+A_{\Lambda_L}(h)\] on \(\mathcal{H}_{\Lambda_L}^{\rm hf}\), where \(A_{\Lambda_L}(h)\) is defined in 10 . We write \[\require{physics} \omega_{\Lambda_L,\beta,U,h}^{*}(O) := \frac{ \Tr_{\mathcal{H}_{\Lambda_L}^{\rm hf}} \left( Oe^{-\beta H_{*,\Lambda_L}(h)} \right) }{ \Tr_{\mathcal{H}_{\Lambda_L}^{\rm hf}} e^{-\beta H_{*,\Lambda_L}(h)} }\] for the Gibbs state of the diagonal representative.

With \(\Gamma_U(h_0)\) as in Corollary 30, assume \(\Gamma_U(h_0)>0.\) Set \[\eta_{\rm def}^{\rm dens}(U,\beta;h_0) := \frac{4}{\beta\Gamma_U(h_0)} e^{-\beta\Gamma_U(h_0)/2}.\]

Proposition 31 (Defect-density bound in the diagonal representation). Assume the hypotheses of Proposition 29 uniformly for \(|h|\le h_0\), and assume \(\Gamma_U(h_0)>0,\) where \(\Gamma_U(h_0)\) is defined in Corollary 30. Then, uniformly in \(L\in2\mathbb{N}\) and \(|h|\le h_0\), \[\label{eq:star-defect-density-bound} \frac{1}{|\Lambda_L|} \sum_{x\in\Lambda_L} \omega_{\Lambda_L,\beta,U,h}^{*}(q_x) \le \eta_{\rm def}^{\rm dens}(U,\beta;h_0).\qquad{(15)}\]

Proof. Introduce the defect-source deformation \[H_{*,\Lambda_L}^{(\alpha)}(h) := H_{*,\Lambda_L}(h) - \alpha\sum_{x\in\Lambda_L}q_x, \qquad \alpha\ge0.\] By Lemma 28, \(\sum_{x\in\Lambda_L}q_x=2D_{\Lambda_L}\) on \(\mathcal{H}_{\Lambda_L}^{\rm hf}\). Hence \[H_{*,\Lambda_L}^{(\alpha)}(h) = \left( \frac{U}{2}-\alpha \right) \sum_{x\in\Lambda_L}q_x + A_{\Lambda_L}(h).\] Let \[\require{physics} p_{\Lambda_L,\beta,U}^{*,\alpha}(h) := \frac{1}{\beta|\Lambda_L|} \log \Tr_{\mathcal{H}_{\Lambda_L}^{\rm hf}} e^{-\beta H_{*,\Lambda_L}^{(\alpha)}(h)} .\] For \(\alpha=0\), the transformed Hamiltonian is unitarily equivalent to the Hubbard Hamiltonian, so \(p_{\Lambda_L,\beta,U}^{*,0}(h) = p_{\Lambda_L,\beta,U}^{\rm Hub}(h).\)

The defect-free block is unchanged by the source. Repeating the proof of Proposition 29, with \(U/2\) replaced by \(U/2-\alpha\), gives, for \(0\le\alpha<\Gamma_U(h_0),\) the bound \[\label{eq:source-soft-defect-pressure-bound} 0 \le p_{\Lambda_L,\beta,U}^{*,\alpha}(h) - p_{\Lambda_L,\beta,U}^{P}(h) \le \frac{2}{\beta} \exp\left( -\beta\bigl(\Gamma_U(h_0)-\alpha\bigr) \right),\tag{30}\] uniformly in \(L\) and \(|h|\le h_0\). Since \(0 \le p_{\Lambda_L,\beta,U}^{*,0}(h) - p_{\Lambda_L,\beta,U}^{P}(h),\) we obtain \[p_{\Lambda_L,\beta,U}^{*,\alpha}(h) - p_{\Lambda_L,\beta,U}^{*,0}(h) \le \frac{2}{\beta} \exp\left( -\beta\bigl(\Gamma_U(h_0)-\alpha\bigr) \right).\]

The map \(\alpha\mapsto p_{\Lambda_L,\beta,U}^{*,\alpha}(h)\) is convex, and its derivative at \(\alpha=0\) is \[\left. \frac{\partial}{\partial\alpha} p_{\Lambda_L,\beta,U}^{*,\alpha}(h) \right|_{\alpha=0} = \frac{1}{|\Lambda_L|} \sum_{x\in\Lambda_L} \omega_{\Lambda_L,\beta,U,h}^{*}(q_x).\] Therefore, for \(0<\alpha<\Gamma_U(h_0)\), \[\frac{1}{|\Lambda_L|} \sum_{x\in\Lambda_L} \omega_{\Lambda_L,\beta,U,h}^{*}(q_x) \le \frac{ p_{\Lambda_L,\beta,U}^{*,\alpha}(h) - p_{\Lambda_L,\beta,U}^{*,0}(h) }{\alpha}.\] Thus \[\frac{1}{|\Lambda_L|} \sum_{x\in\Lambda_L} \omega_{\Lambda_L,\beta,U,h}^{*}(q_x) \le \frac{2}{\beta\alpha} \exp\left( -\beta\bigl(\Gamma_U(h_0)-\alpha\bigr) \right).\] Choosing \(\alpha=\frac{1}{2}\Gamma_U(h_0)\) gives \[\frac{1}{|\Lambda_L|} \sum_{x\in\Lambda_L} \omega_{\Lambda_L,\beta,U,h}^{*}(q_x) \le \frac{4}{\beta\Gamma_U(h_0)} \exp\left( -\frac{\beta\Gamma_U(h_0)}{2} \right) = \eta_{\rm def}^{\rm dens}(U,\beta;h_0).\] This proves the proposition. ◻

7 Proof of the main comparison theorems↩︎

This section assembles the estimates proved above. We first prove the Hubbard–Heisenberg pressure comparison on the bounded field window \(|h|\le h_0\). The magnetisation comparison is then obtained from this pressure comparison on a fixed positive field window by convexity.

7.1 Proof of the finite-volume pressure comparison↩︎

Proof of Theorem 1. Fix \(\ell_0>0\). By Proposition 26, there is an error function \(\varepsilon_P^{\rm FE}(U;h_0)\ge0\) such that, for all sufficiently large \(U\), all \(\beta>0\), all even tori \(\Lambda_L\), and all \(|h|\le h_0\), \[\left| p_{\Lambda_L,\beta,U}^{P}(h) - p_{\Lambda_L,\beta,U}^{\rm Heis}(h) \right| \le \varepsilon_P^{\rm FE}(U;h_0),\] and \(\lim_{U\to\infty} \varepsilon_P^{\rm FE}(U;h_0) = 0.\)

By Corollary 30, there is an error function \(\varepsilon_{\rm def}^{\rm FE}(U,\beta;h_0)\ge0\) such that, for all sufficiently large \(U\), all \(\beta>0\) satisfying \(\beta J_0(U)\ge\ell_0,\) all even tori \(\Lambda_L\), and all \(|h|\le h_0\), \[0 \le p_{\Lambda_L,\beta,U}^{\rm Hub}(h) - p_{\Lambda_L,\beta,U}^{P}(h) \le \varepsilon_{\rm def}^{\rm FE}(U,\beta;h_0),\] and \(\lim_{U\to\infty} \sup_{\beta J_0(U)\ge\ell_0} \varepsilon_{\rm def}^{\rm FE}(U,\beta;h_0) = 0.\)

Define the total pressure comparison error by \[\label{eq:def-total-FE-error} \varepsilon_{\rm FE}(U,\beta;h_0) := \varepsilon_P^{\rm FE}(U;h_0) + \varepsilon_{\rm def}^{\rm FE}(U,\beta;h_0).\tag{31}\] Then, by the triangle inequality, \[\label{eq:assembled-pressure-comparison} \sup_{|h|\le h_0} \left| p_{\Lambda_L,\beta,U}^{\rm Hub}(h) - p_{\Lambda_L,\beta,U}^{\rm Heis}(h) \right| \le \varepsilon_{\rm FE}(U,\beta;h_0),\tag{32}\] uniformly in \(\Lambda_L\). Moreover, \[\label{eq:total-FE-error-vanishes} \lim_{U\to\infty} \sup_{\beta J_0(U)\ge\ell_0} \varepsilon_{\rm FE}(U,\beta;h_0) = 0.\tag{33}\] This proves Theorem 1. ◻

7.2 From fixed-window pressure comparison to magnetisation comparison↩︎

We next record the convexity step which converts 32 into a magnetisation comparison on \(I\).

Lemma 32 (Fixed-window pressure comparison implies magnetisation comparison). For every \(h\in I\), \[\left| m_{\Lambda,\beta,U}^{\rm Hub}(h) - m_{\Lambda,\beta,U}^{\rm Heis}(h) \right| \le \varepsilon_{\rm mag}^{\rm conv}(U,\beta;I),\] where \[\label{eq:def-convexity-mag-error} \varepsilon_{\rm mag}^{\rm conv}(U,\beta;I) := \frac{1}{2} \left( 1-\tanh\left(\frac{\beta h_I}{4}\right) \right) + \frac{4}{h_I} \left( \varepsilon_{\rm FE}(U,\beta;h_0) + C_d J_0(U) \right).\qquad{(16)}\] In particular, \[\lim_{U\to\infty} \sup_{\beta J_0(U)\ge\ell_0} \varepsilon_{\rm mag}^{\rm conv}(U,\beta;I) = 0.\]

Proof. Let \[\require{physics} p_{\Lambda,\beta}^{0}(h) := \frac{1}{\beta|\Lambda|} \log \Tr_{\mathcal{H}_\Lambda^{\rm spin}} e^{\beta hM_\Lambda^{\rm spin}}.\] Since \(M_\Lambda^{\rm spin} = \sum_{x\in\Lambda}\eta_xS_x^{(3)}\) is a product-field Hamiltonian and \(\eta_x=\pm1\), one has \[p_{\Lambda,\beta}^{0}(h) = \frac{1}{\beta} \log\left(2\cosh\frac{\beta h}{2}\right),\qquad \partial_h p_{\Lambda,\beta}^{0}(h) = \frac{1}{2}\tanh\left(\frac{\beta h}{2}\right).\]

We first compare the Heisenberg pressure with the pure-field pressure. Write \[H_\Lambda^{\rm Heis}(J_0(U),h) = -hM_\Lambda^{\rm spin} + H_\Lambda^{\rm Heis},\] where \(H_\Lambda^{\rm Heis} := J_0(U) \sum_{\{ x,y\}\in\mathscr{B}_\Lambda} \left( \boldsymbol{S}_x\cdot\boldsymbol{S}_y-\frac{1}{4} \right).\) As an interaction, \(\|H_\Lambda^{\rm Heis}\|_0 \le C_dJ_0(U).\) Therefore, applying the pressure Lipschitz bound Lemma 48 to the spin Hilbert space \(\mathcal{H}_\Lambda^{\rm spin}\), with \(H=-sM_\Lambda^{\rm spin}\) and \(K=H_\Lambda^{\rm Heis},\) we get, uniformly for \(|s|\le h_0\), \[\begin{align} \left| p_{\Lambda,\beta,U}^{\rm Heis}(s) - p_{\Lambda,\beta}^{0}(s) \right| \le C_dJ_0(U). \label{inq:Heis-0} \end{align}\tag{34}\] Combining this with 32 , we obtain \[\label{eq:Hub-pure-field-pressure-window} \sup_{s\in I^\sharp} \left| p_{\Lambda,\beta,U}^{\rm Hub}(s) - p_{\Lambda,\beta}^{0}(s) \right| \le \varepsilon_{\rm FE}(U,\beta;h_0) + C_dJ_0(U).\tag{35}\] For shortness, set \(\delta_{\rm FE}(U,\beta;h_0) := \varepsilon_{\rm FE}(U,\beta;h_0) + C_dJ_0(U).\)

We shall use the following elementary fact. If \(f\) is a differentiable convex function and \(a<b\), then \[f'(b) \ge \frac{f(b)-f(a)}{b-a} \ge f'(a).\] The finite-volume pressures \[h\mapsto p_{\Lambda,\beta,U}^{\rm Hub}(h), \qquad h\mapsto p_{\Lambda,\beta,U}^{\rm Heis}(h), \qquad h\mapsto p_{\Lambda,\beta}^{0}(h)\] are convex because they are logarithmic partition functions with a linear field source. Their first derivatives are the corresponding normalized magnetisations by the pressure derivative formula Lemma 49. In particular, \(\partial_h p_{\Lambda,\beta,U}^{\rm Hub}(h) = m_{\Lambda,\beta,U}^{\rm Hub}(h)\) and \(\partial_h p_{\Lambda,\beta,U}^{\rm Heis}(h) = m_{\Lambda,\beta,U}^{\rm Heis}(h).\)

Fix \(h\in I\). Since \(h/2\in I^\sharp\), convexity of \(p_{\Lambda,\beta,U}^{\rm Hub}\) gives \[m_{\Lambda,\beta,U}^{\rm Hub}(h) = \partial_h p_{\Lambda,\beta,U}^{\rm Hub}(h) \ge \frac{ p_{\Lambda,\beta,U}^{\rm Hub}(h) - p_{\Lambda,\beta,U}^{\rm Hub}(h/2) }{h/2}.\] Using 35 at \(h\) and \(h/2\), we get \[p_{\Lambda,\beta,U}^{\rm Hub}(h) - p_{\Lambda,\beta,U}^{\rm Hub}(h/2) \ge p_{\Lambda,\beta}^{0}(h) - p_{\Lambda,\beta}^{0}(h/2) - 2\delta_{\rm FE}(U,\beta;h_0).\] Therefore \[m_{\Lambda,\beta,U}^{\rm Hub}(h) \ge \frac{ p_{\Lambda,\beta}^{0}(h) - p_{\Lambda,\beta}^{0}(h/2) }{h/2} - \frac{4}{h} \delta_{\rm FE}(U,\beta;h_0).\] Applying the same secant inequality to the convex function \(p_{\Lambda,\beta}^{0}\), we obtain \[\frac{ p_{\Lambda,\beta}^{0}(h) - p_{\Lambda,\beta}^{0}(h/2) }{h/2} \ge \partial_h p_{\Lambda,\beta}^{0}(h/2) = \frac{1}{2}\tanh\left(\frac{\beta h}{4}\right).\] Since \(h\ge h_I\), this implies \[\label{eq:Hub-mag-lower-convex} m_{\Lambda,\beta,U}^{\rm Hub}(h) \ge \frac{1}{2}\tanh\left(\frac{\beta h_I}{4}\right) - \frac{4}{h_I} \delta_{\rm FE}(U,\beta;h_0).\tag{36}\] On the other hand, \(m_{\Lambda,\beta,U}^{\rm Hub}(h) = \frac{1}{|\Lambda|} \omega_{\Lambda,\beta,U,h}^{\rm Hub}(M_\Lambda) \le \frac{1}{2},\) because \(\|M_\Lambda\|\le\frac{|\Lambda|}{2}.\)

The same argument applied to \(p_{\Lambda,\beta,U}^{\rm Heis}\), using only 34 , gives \[m_{\Lambda,\beta,U}^{\rm Heis}(h) \ge \frac{1}{2}\tanh\left(\frac{\beta h_I}{4}\right) - \frac{4C_d}{h_I}J_0(U).\] Also, \(m_{\Lambda,\beta,U}^{\rm Heis}(h) = \frac{1}{|\Lambda|} \omega_{\Lambda,\beta,U,h}^{\rm Heis}(M_\Lambda^{\rm spin}) \le \frac{1}{2}.\) Thus both magnetisations lie in the interval \(\left[ \frac{1}{2}-\varepsilon_{\rm mag}^{\rm conv}(U,\beta;I), \frac{1}{2} \right].\) Consequently, \[\left| m_{\Lambda,\beta,U}^{\rm Hub}(h) - m_{\Lambda,\beta,U}^{\rm Heis}(h) \right| \le \varepsilon_{\rm mag}^{\rm conv}(U,\beta;I).\]

It remains to prove the limiting statement. Since \(J_0(U)=\frac{4t^2}{U}\to0,\) and \(\beta J_0(U)\ge\ell_0 \Rightarrow \beta h_I \ge \frac{\ell_0 h_I}{J_0(U)} \to\infty,\) we have \(1-\tanh\left(\frac{\beta h_I}{4}\right)\to0\) uniformly under the condition \(\beta J_0(U)\ge\ell_0\). The assumed convergence of \(\varepsilon_{\rm FE}(U,\beta;I^\sharp)\) and \(J_0(U)\to0\) imply \(\lim_{U\to\infty} \sup_{\beta J_0(U)\ge\ell_0} \varepsilon_{\rm mag}^{\rm conv}(U,\beta;I) = 0.\) This completes the proof. ◻

7.3 Proof of the finite-volume fixed-field magnetisation comparison↩︎

Proof of Theorem 2. Let \[h_I:=\inf I, \qquad h_+:=\sup I, \qquad I^\sharp:=\left[\frac{h_I}{2},h_+\right].\] Since \(I\Subset(0,h_0]\), we have \(I^\sharp\subset[-h_0,h_0].\) Therefore the pressure comparison 32 applies on \(I^\sharp\): \[\sup_{s\in I^\sharp} \left| p_{\Lambda_L,\beta,U}^{\rm Hub}(s) - p_{\Lambda_L,\beta,U}^{\rm Heis}(s) \right| \le \varepsilon_{\rm FE}(U,\beta;h_0).\] Applying Lemma 32, we get, for every \(h\in I\), \[\left| m_{\Lambda_L,\beta,U}^{\rm Hub}(h) - m_{\Lambda_L,\beta,U}^{\rm Heis}(h) \right| \le \varepsilon_{\rm mag}^{\rm conv}(U,\beta;I).\] Set \(\varepsilon_{\rm mag}(U,\beta;I) := \varepsilon_{\rm mag}^{\rm conv}(U,\beta;I).\) The convergence \(\lim_{U\to\infty} \sup_{\beta J_0(U)\ge\ell_0} \varepsilon_{\rm mag}(U,\beta;I) = 0\) is part of Lemma 32, using 33 . This proves the theorem. ◻

7.4 Infinite-volume consequences↩︎

Proof of Corollary 5. Assume Assumption 3. Taking \(L\to\infty\) in Theorem 1 gives, for every \(|h|\le h_0\), \(\left| p_{\beta,U}^{\rm Hub}(h) - p_{\beta,U}^{\rm Heis}(h) \right| \le \varepsilon_{\rm FE}(U,\beta;h_0).\)

It remains to pass the fixed positive-field magnetisation comparison to the thermodynamic limit. Let \(I\Subset(0,h_0]\), and let \(h\in \operatorname{int}I \cap \mathcal{D}_{\beta,U}^{\rm Hub} \cap \mathcal{D}_{\beta,U}^{\rm Heis}.\) By Lemma 54, the thermodynamic magnetisations at such an \(h\) are the derivatives of the limiting pressures and are also the limits of the corresponding finite-volume magnetisations. Therefore, taking \(L\to\infty\) in Theorem 2 gives \(\left| m_{\beta,U}^{\rm Hub}(h) - m_{\beta,U}^{\rm Heis}(h) \right| \le \varepsilon_{\rm mag}(U,\beta;I).\) This proves the corollary. ◻

7.5 Positive fixed-field magnetisation↩︎

Proof of Corollary 7. By Lemma 52, for all \(h\in I\), \[m_{\Lambda_L,\beta,U}^{\rm Heis}(h) \ge m_{\rm Heis}^{\rm lb}(U,\beta;I),\] and \(\lim_{U\to\infty} \inf_{\beta J_0(U)\ge\ell_0} m_{\rm Heis}^{\rm lb}(U,\beta;I) = \frac{1}{2}.\) By Theorem 2, \[\left| m_{\Lambda_L,\beta,U}^{\rm Hub}(h) - m_{\Lambda_L,\beta,U}^{\rm Heis}(h) \right| \le \varepsilon_{\rm mag}(U,\beta;I).\] Therefore \[m_{\Lambda_L,\beta,U}^{\rm Hub}(h) \ge m_{\rm Heis}^{\rm lb}(U,\beta;I) - \varepsilon_{\rm mag}(U,\beta;I) = m_{\rm Hub}^{\rm lb}(U,\beta;I).\]

Taking the infimum over \(\beta J_0(U)\ge\ell_0\), we obtain \[\inf_{\beta J_0(U)\ge\ell_0} m_{\rm Hub}^{\rm lb}(U,\beta;I) \ge \inf_{\beta J_0(U)\ge\ell_0} m_{\rm Heis}^{\rm lb}(U,\beta;I) - \sup_{\beta J_0(U)\ge\ell_0} \varepsilon_{\rm mag}(U,\beta;I).\] The first term converges to \(1/2\) by Lemma 52, while the second term converges to \(0\) by Theorem 2. Hence \(\lim_{U\to\infty} \inf_{\beta J_0(U)\ge\ell_0} m_{\rm Hub}^{\rm lb}(U,\beta;I) = \frac{1}{2}.\) The final lower bound by \(1/4\) follows by increasing the strong-coupling threshold. ◻

7.6 Proof of the charge-sector theorem↩︎

We prove Theorem 9. The only additional input needed beyond the diagonal defect-density estimate is the LS/SW dressing estimate for the normalized defect density.

For \(L\in2\mathbb{N}\), set \[\bar q_{\Lambda_L} := \frac{1}{|\Lambda_L|} \sum_{x\in\Lambda_L}q_x.\] Let \(U_{{\rm SW},\Lambda_L}(h)\) be the LS/SW product unitary from Proposition 16 and Corollary 17.

Proposition 33 (Dressing of the normalized defect density). Define \[\rho_q(U;h_0) := \sup_{L\in2\mathbb{N}} \sup_{|h|\le h_0} \left\| U_{{\rm SW},\Lambda_L}(h) \bar q_{\Lambda_L} U_{{\rm SW},\Lambda_L}(h)^{\ast} - \bar q_{\Lambda_L} \right\|.\] Then, after increasing the strong-coupling threshold if necessary, \[\rho_q(U;h_0)\longrightarrow0 \qquad (U\to\infty).\]

Proof. See Appendix 8.4. ◻

The proof of Proposition 33 is a pure LS/SW conjugation estimate for a normalized extensive observable. It is based on the summability of the generators \(S_n(h)\) and is placed in the appendix.

With \(\Gamma_U(h_0)\) as in Corollary 30, recall \(\eta_{\rm def}^{\rm dens}(U,\beta;h_0) = \frac{4}{\beta\Gamma_U(h_0)} e^{-\beta\Gamma_U(h_0)/2},\) whenever \(\Gamma_U(h_0)>0\). Define \[\varepsilon_{\rm ch}(U,\beta;h_0) := \eta_{\rm def}^{\rm dens}(U,\beta;h_0) + \rho_q(U;h_0).\]

Proof of Theorem 9. Choose \(U_0=U_0(\ell_0,d,h_0,t)\) sufficiently large so that the LS/SW construction, Propositions 31 and 33, and \(\Gamma_U(h_0)>0\) all hold for \(U\ge U_0\).

Recall the Gibbs state \(\omega_{\Lambda_L,\beta,U,h}^{*}\) of the diagonal representative. Since \[H_{*,\Lambda_L}(h) = U_{{\rm SW},\Lambda_L}(h) H_{\Lambda_L}^{\rm Hub}(h) U_{{\rm SW},\Lambda_L}(h)^{\ast},\] we have, for every observable \(B\) on \(\mathcal{H}_{\Lambda_L}^{\rm hf}\), \[\omega_{\Lambda_L,\beta,U,h}^{\rm Hub}(B) = \omega_{\Lambda_L,\beta,U,h}^{*} \left( U_{{\rm SW},\Lambda_L}(h) B U_{{\rm SW},\Lambda_L}(h)^{\ast} \right).\] Applying this with \(B=\bar q_{\Lambda_L}\), we obtain \[\omega_{\Lambda_L,\beta,U,h}^{\rm Hub} \left( \bar q_{\Lambda_L} \right) \le \omega_{\Lambda_L,\beta,U,h}^{*} \left( \bar q_{\Lambda_L} \right) + \rho_q(U;h_0).\] By Proposition 31, we have \(\omega_{\Lambda_L,\beta,U,h}^{*} \left( \bar q_{\Lambda_L} \right) \le \eta_{\rm def}^{\rm dens}(U,\beta;h_0),\) for \(|h|\le h_0\). Hence \[\omega_{\Lambda_L,\beta,U,h}^{\rm Hub} \left( \bar q_{\Lambda_L} \right) \le \varepsilon_{\rm ch}(U,\beta;h_0).\] Since \[\omega_{\Lambda_L,\beta,U,h}^{\rm Hub} \left( \bar q_{\Lambda_L} \right) = \frac{1}{|\Lambda_L|} \sum_{x\in\Lambda_L} \omega_{\Lambda_L,\beta,U,h}^{\rm Hub}(q_x),\] this proves the first estimate in Theorem 9.

Next, Lemma 28 gives, on \(\mathcal{H}_{\Lambda_L}^{\rm hf}\), \(\sum_{x\in\Lambda_L}q_x = 2D_{\Lambda_L} = 2\sum_{x\in\Lambda_L}n_{x\uparrow}n_{x\downarrow}.\) Therefore \[\frac{1}{|\Lambda_L|} \sum_{x\in\Lambda_L} \omega_{\Lambda_L,\beta,U,h}^{\rm Hub} (n_{x\uparrow}n_{x\downarrow}) = \frac{1}{2} \omega_{\Lambda_L,\beta,U,h}^{\rm Hub} \left( \bar q_{\Lambda_L} \right) \le \frac{1}{2} \varepsilon_{\rm ch}(U,\beta;h_0).\]

It remains to prove the two staggered charge estimates. Recall \(C_{\Lambda_L}^{\rm ch} = \sum_{x\in\Lambda_L}\eta_x(n_x-1).\) Since the number operators \(n_x\) commute, the operators \(\{n_x-1\}_{x\in\Lambda_L}\) can be treated by joint functional calculus. On each site, \(n_x-1\) has spectrum contained in \(\{-1,0,1\}\), and hence \(|n_x-1|=(n_x-1)^2=q_x.\) Therefore, by the scalar triangle inequality in the joint spectral representation, \(|C_{\Lambda_L}^{\rm ch}| = \left| \sum_{x\in\Lambda_L}\eta_x(n_x-1) \right| \le \sum_{x\in\Lambda_L}|n_x-1| = \sum_{x\in\Lambda_L}q_x .\) Thus \[\left| \frac{1}{|\Lambda_L|} \omega_{\Lambda_L,\beta,U,h}^{\rm Hub} (C_{\Lambda_L}^{\rm ch}) \right| \le \frac{1}{|\Lambda_L|} \omega_{\Lambda_L,\beta,U,h}^{\rm Hub} \left( \sum_{x\in\Lambda_L}q_x \right) \le \varepsilon_{\rm ch}(U,\beta;h_0).\] Similarly, \((C_{\Lambda_L}^{\rm ch})^2 \le \left( \sum_{x\in\Lambda_L}q_x \right)^2 \le |\Lambda_L| \sum_{x\in\Lambda_L}q_x,\) because the \(q_x\)’s are commuting projections. Hence \[\frac{1}{|\Lambda_L|^2} \omega_{\Lambda_L,\beta,U,h}^{\rm Hub} \left( (C_{\Lambda_L}^{\rm ch})^2 \right) \le \frac{1}{|\Lambda_L|} \omega_{\Lambda_L,\beta,U,h}^{\rm Hub} \left( \sum_{x\in\Lambda_L}q_x \right) \le \varepsilon_{\rm ch}(U,\beta;h_0).\]

Finally, we check the strong-coupling limit of the error. By Corollary 30, after increasing \(U_0\) if necessary, \(\Gamma_U(h_0)\ge \frac{U}{4}, \, U\ge U_0.\) If \(t\ne0\), the condition \(\beta J_0(U)\ge\ell_0\) implies \(\beta\ge\frac{\ell_0 U}{4t^2}.\) Therefore \[\sup_{\beta J_0(U)\ge\ell_0} \eta_{\rm def}^{\rm dens}(U,\beta;h_0) \le \frac{64t^2}{\ell_0 U^2} \exp\left( -\frac{\ell_0 U^2}{32t^2} \right) \longrightarrow0.\] Together with Proposition 33, this gives \(\lim_{U\to\infty} \sup_{\beta J_0(U)\ge\ell_0} \varepsilon_{\rm ch}(U,\beta;h_0) = 0.\) This completes the proof. ◻

8 BCH/LS estimates and \(D\)-graded interactions↩︎

8.1 Proofs deferred from Section 2.1↩︎

Proof of Lemma 11. Fix \(x\in\Lambda\). Since the interactions considered here are even, local terms with disjoint supports commute. Hence only pairs \((X,Y)\) with \(X\cap Y\neq\varnothing\) contribute to \((\mathrm{ad}_A(B))_Z\).

Using \(\|[S,T]\|\le 2\|S\|\,\|T\|\) and \(e^{\kappa|X\cup Y|} \le e^{\kappa|X|}e^{\kappa|Y|},\) we obtain \[\begin{align} \sum_{Z\ni x} e^{\kappa|Z|} \|(\mathrm{ad}_A(B))_Z\| &\le \sum_{\substack{X,Y\subset\Lambda:\\ x\in X\cup Y,\;X\cap Y\neq\varnothing}} e^{\kappa|X\cup Y|} \|[A_X,B_Y]\| \\ &\le 2 \sum_{\substack{X,Y\subset\Lambda:\\ x\in X\cup Y,\;X\cap Y\neq\varnothing}} e^{\kappa|X|}\|A_X\|\, e^{\kappa|Y|}\|B_Y\|. \end{align}\] Splitting the condition \(x\in X\cup Y\) into the two cases \(x\in X\) and \(x\in Y\), we get \[\begin{align} \sum_{Z\ni x} e^{\kappa|Z|} \|(\mathrm{ad}_A(B))_Z\| &\le 2\sum_{X\ni x}e^{\kappa|X|}\|A_X\| \sum_{\substack{Y\subset\Lambda:\\Y\cap X\neq\varnothing}} e^{\kappa|Y|}\|B_Y\| \\ &\quad+ 2\sum_{Y\ni x}e^{\kappa|Y|}\|B_Y\| \sum_{\substack{X\subset\Lambda:\\X\cap Y\neq\varnothing}} e^{\kappa|X|}\|A_X\|. \end{align}\] For a fixed \(X\) with \(A_X\neq0\), one has \(|X|\le s(A)\), and hence \[\sum_{\substack{Y\subset\Lambda:\\Y\cap X\neq\varnothing}} e^{\kappa|Y|}\|B_Y\| \le \sum_{y\in X} \sum_{Y\ni y}e^{\kappa|Y|}\|B_Y\| \le s(A)\|B\|_\kappa .\] Similarly, for a fixed \(Y\) with \(B_Y\neq0\), \(\sum_{\substack{X\subset\Lambda:\\X\cap Y\neq\varnothing}} e^{\kappa|X|}\|A_X\| \le s(B)\|A\|_\kappa .\) Therefore \[\sum_{Z\ni x} e^{\kappa|Z|} \|(\mathrm{ad}_A(B))_Z\| \le 2(s(A)+s(B))\|A\|_\kappa\|B\|_\kappa .\] Taking the supremum over \(x\in\Lambda\) proves \(\|\mathrm{ad}_A(B)\|_\kappa \le 2(s(A)+s(B))\|A\|_\kappa\|B\|_\kappa,\) which is the stated bound. ◻

Proof of Lemma 12. If \(A=0\), the assertion is trivial. Hence we assume \(A\neq0\), so \(s_A\ge1\). Set \(B_n:=\mathrm{ad}_A^{\,n}(B), \, n\ge0.\) Then \(B_0=B\). Since every commutator with \(A\) replaces a support \(Y\) by a union \(X\cup Y\) with \(|X|\le s_A\), the interaction \(B_n\) has support size bounded by \(s(B_n) \le s(B)+n s(A) .\) Applying Lemma 11 to \(A\) and \(B_n\), we get \[\|B_{n+1}\|_\kappa = \|\mathrm{ad}_A(B_n)\|_\kappa \le 2\bigl(s(A)+s(B_n)\bigr) \|A\|_\kappa\|B_n\|_\kappa .\] Using \(s(B_n)\le s(B)+n s(A)\), this gives \(\|B_{n+1}\|_\kappa \le 2\bigl(s(B)+(n+1)s(A)\bigr) \|A\|_\kappa\|B_n\|_\kappa .\) Iterating from \(B_0=B\), we obtain, for \(n\ge1\), \[\|\mathrm{ad}_A^{\,n}(B)\|_\kappa \le (2\|A\|_\kappa)^n \prod_{j=1}^{n} (s(B)+j s(A))\, \|B\|_\kappa .\] Therefore \[\frac{1}{n!} \|\mathrm{ad}_A^{\,n}(B)\|_\kappa \le (2s(A)\|A\|_\kappa)^n \prod_{j=1}^{n} \left(1+\frac{s(B)}{j s(A)}\right) \|B\|_\kappa .\] Let \(a:=\frac{s(B)}{s(A)}.\) Since \[\prod_{j=1}^{n} \left(1+\frac{a}{j}\right) \le \exp\left( a\sum_{j=1}^{n}\frac{1}{j} \right) \le e^a(n+1)^a,\] we have \(\frac{1}{n!} \|\mathrm{ad}_A^{\,n}(B)\|_\kappa \le e^a (2s(A)\|A\|_\kappa)^n (n+1)^a \|B\|_\kappa .\) By assumption, \(r:=2s(A)\|A\|_\kappa\le \rho<1.\) Hence \[\sum_{n\ge1}\frac{1}{n!} \|\mathrm{ad}_A^{\,n}(B)\|_\kappa \le e^a \sum_{n\ge1} r^n (n+1)^a \|B\|_\kappa .\] Factoring out \(r\) and using \(r\le \rho\), we get \(\sum_{n\ge1} r^n (n+1)^a \le r \sum_{n\ge1}\rho^{n-1}(n+1)^a .\) Since \(\rho<1\), the series \(\sum_{n\ge1}\rho^{n-1}(n+1)^a\) is finite. Therefore \[\sum_{n\ge1}\frac{1}{n!} \|\mathrm{ad}_A^{\,n}(B)\|_\kappa \le C_{\rm BCH}\, \|A\|_\kappa\,\|B\|_\kappa,\] where one may take \(C_{\rm BCH} := 2s(A) e^{s(B)/s(A)} \sum_{n\ge1}\rho^{n-1}(n+1)^{s(B)/s(A)}.\) This constant depends only on \(s(A),s(B),\rho\).

Finally, the BCH expansion gives \(e^A B e^{-A}-B = \sum_{n\ge1}\frac{1}{n!}\mathrm{ad}_A^{\,n}(B),\) with convergence in \(\|\cdot\|_\kappa\) by the estimate just proved. Taking the \(\|\cdot\|_\kappa\)-norm yields \(\left\| e^A B e^{-A}-B \right\|_\kappa \le C_{\rm BCH}\, \|A\|_\kappa\,\|B\|_\kappa .\) ◻

Proof of Lemma 13. Write \(\mathcal{H}_m:=\operatorname{ran}(P_m),\) so that \(\mathcal{H}_\Lambda^{\rm hf} = \bigoplus_{m\ge0}\mathcal{H}_m\) orthogonally.

For \[\psi=\sum_{m\ge0}\psi_m, \qquad \psi_m:=P_m\psi\in\mathcal{H}_m,\] we have \[A^{(k)}\psi = \sum_{m\ge0}P_{m+k}A\psi_m, \qquad P_{m+k}A\psi_m\in\mathcal{H}_{m+k}.\] Since the spaces \(\mathcal{H}_{m+k}\) are mutually orthogonal for different \(m\), it follows that \[\|A^{(k)}\psi\|^2 = \sum_{m\ge0}\|P_{m+k}A\psi_m\|^2 \le \left( \sup_{m\ge0}\|P_{m+k}AP_m\|^2 \right) \sum_{m\ge0}\|\psi_m\|^2 .\] Hence \(\|A^{(k)}\psi\|^2 \le \left( \sup_{m\ge0}\|P_{m+k}AP_m\|^2 \right) \|\psi\|^2.\) Taking the supremum over \(\|\psi\|=1\) gives \(\|A^{(k)}\| \le \sup_{m\ge0}\|P_{m+k}AP_m\|.\) The reverse inequality follows from \(P_{m+k}AP_m = P_{m+k}A^{(k)}P_m .\) Thus \(\|A^{(k)}\| = \sup_{m\ge0}\|P_{m+k}AP_m\| \le \|A\|.\)

For \(k=0\), this gives the contractivity of the diagonal part: \(\|A^{\rm diag}\|=\|A^{(0)}\|\le\|A\|.\) Since \(A^{\rm off}=A-A^{\rm diag},\) we also have \(\|A^{\rm off}\|\le2\|A\|.\)

Applying these estimates termwise to an interaction \(C=\{C_X\}_{X\subset\Lambda}\), we obtain \[\|C^{(k)}\|_\kappa\le\|C\|_\kappa, \qquad \|C^{\rm diag}\|_\kappa\le\|C\|_\kappa, \qquad \|C^{\rm off}\|_\kappa\le2\|C\|_\kappa.\]

It remains to show the grade-summation estimate. If \(C_X\in\frak A_X\), then \(C_X\) commutes with \(q_y\) for \(y\notin X\). Since \(\sum_{y\in\Lambda}q_y=2D_\Lambda\) on \(\mathcal{H}_\Lambda^{\rm hf}\), the operator \(C_X\) can change the \(D_\Lambda\)-eigenvalue only through the sites in \(X\). Hence \((C_X)^{(k)}=0\) whenever \(|k|>|X|\). Therefore, if \(s(C)<\infty,\) then, for every \(X\) with \(C_X\neq0\), only the values \(0<|k|\le s(C)\) can contribute to \((C_X)^{(k)}\). Using \(\|(C_X)^{(k)}\|\le\|C_X\|,\) we get \(\sum_{k\neq0}\|(C_X)^{(k)}\| \le 2s(C)\|C_X\|.\) Multiplying by \(e^{\kappa|X|}\), summing over \(X\ni x\), and taking the supremum over \(x\in\Lambda\), we obtain \(\sum_{k\neq0}\|C^{(k)}\|_\kappa \le 2s(C)\|C\|_\kappa.\) This completes the proof. ◻

8.2 Well-definedness and bounds for \(\mathcal{I}_h\)↩︎

Throughout this subsection we fix \(h\) with \(|h|\le h_0.\)

Lemma 34 (Local commutator bound with the staggered field). For every local operator \(A_X\in\frak A_X\), one has \[\label{eq:adM-local-bound} \|\mathrm{ad}_{M_\Lambda}(A_X)\| \le |X|\|A_X\|.\qquad{(17)}\] Consequently, for all \(n\ge0\), \[\label{eq:adM-power-local-bound} \|\mathrm{ad}_{M_\Lambda}^{\,n}(A_X)\| \le |X|^{n}\|A_X\|.\qquad{(18)}\]

Proof. Recall that \(M_\Lambda = \sum_{x\in\Lambda}\eta_x S_x^{(3)}, \; \eta_x\in\{\pm1\}, \; \|S_x^{(3)}\|=\frac{1}{2}.\) Since \(S_x^{(3)}\) is supported at \(x\), only sites in \(X\) contribute to the commutator with \(A_X\). Hence \(\mathrm{ad}_{M_\Lambda}(A_X) = \sum_{x\in X}\eta_x [S_x^{(3)},A_X].\) Using \(\|\mathrm{ad}_{S_x^{(3)}}(A_X)\| \le 2\|S_x^{(3)}\|\|A_X\| = \|A_X\|,\) we obtain \(\|\mathrm{ad}_{M_\Lambda}(A_X)\| \le \sum_{x\in X}\|A_X\| = |X|\|A_X\|.\) This proves ?? . Iterating the same estimate gives \(\|\mathrm{ad}_{M_\Lambda}^{\,n}(A_X)\| \le |X|^{n}\|A_X\|,\) which is ?? . ◻

Lemma 35 (Definition of \(\mathcal{I}_h\) on graded local pieces). Assume \(|h|\le h_0\). Let \(k\neq0\), and let \(A\in\frak A_X\) be a local operator supported in a finite set \(X\subset\Lambda\) and of \(D_\Lambda\)-grade \(k\), namely \[A=A^{(k)}, \qquad \mathrm{ad}_{D_\Lambda}(A)=kA.\] Assume moreover that \[\label{eq:Ih-smallness-condition} |k|U>h_0|X|.\qquad{(19)}\] Define \[\label{eq:def-Ih-Neumann} \mathcal{I}_h(A) := \frac{1}{kU} \sum_{n\ge0} \left(\frac{h}{kU}\right)^n \mathrm{ad}_{M_\Lambda}^{\,n}(A).\qquad{(20)}\] Then the series converges absolutely in operator norm and the following hold.

  1. **Inverse property on the \(k\)-graded sector. \[\label{eq:Ih-inverse-property} \mathrm{ad}_{UD_\Lambda-hM_\Lambda} \bigl( \mathcal{I}_h(A) \bigr) = A.\qquad{(21)}\]

  2. **\(D_\Lambda\)-grading preservation.* The operator \(\mathcal{I}_h(A)\) has the same \(D_\Lambda\)-grade as \(A\): \[\mathrm{ad}_{D_\Lambda}(\mathcal{I}_h(A)) = k\mathcal{I}_h(A).\] In particular, since \(k\neq0\), \[(\mathcal{I}_h(A))^{\rm diag}=0, \qquad (\mathcal{I}_h(A))^{\rm off}=\mathcal{I}_h(A).\]*

  3. **Support preservation. \[A\in\frak A_X \quad\Longrightarrow\quad \mathcal{I}_h(A)\in\frak A_X .\]

  4. **Local norm bound.* For all \(|h|\le h_0\), \[\label{eq:Ih-local-bound} \|\mathcal{I}_h(A)\| \le \frac{1}{|k|U-|h|\,|X|}\|A\| \le \frac{1}{|k|U-h_0|X|}\|A\|.\tag{37}\] *

  5. **Adjoint compatibility. \[\mathcal{I}_h(A^\ast) = -(\mathcal{I}_h(A))^\ast .\]

Proof. Since \(M_\Lambda\) commutes with \(D_\Lambda\), the operator \(\mathrm{ad}_{M_\Lambda}^{\,n}(A)\) has \(D_\Lambda\)-grade \(k\) for every \(n\ge0\). Hence, for every operator \(X\) of \(D_\Lambda\)-grade \(k\), \(\mathrm{ad}_{UD_\Lambda-hM_\Lambda}(X) = kU X-h\mathrm{ad}_{M_\Lambda}(X).\) For the partial sums \[S_N := \frac{1}{kU} \sum_{n=0}^{N} \left(\frac{h}{kU}\right)^n \mathrm{ad}_{M_\Lambda}^{\,n}(A),\] we therefore obtain the telescoping identity \[\begin{align} \mathrm{ad}_{UD_\Lambda-hM_\Lambda}(S_N) &= \sum_{n=0}^{N} \left(\frac{h}{kU}\right)^n \mathrm{ad}_{M_\Lambda}^{\,n}(A) - \sum_{n=0}^{N} \left(\frac{h}{kU}\right)^{n+1} \mathrm{ad}_{M_\Lambda}^{\,n+1}(A) \\ &= A - \left(\frac{h}{kU}\right)^{N+1} \mathrm{ad}_{M_\Lambda}^{\,N+1}(A). \end{align}\] By Lemma 34, \[\left\| \left(\frac{h}{kU}\right)^{N+1} \mathrm{ad}_{M_\Lambda}^{\,N+1}(A) \right\| \le \left( \frac{|h|\,|X|}{|k|U} \right)^{N+1} \|A\|.\] The right-hand side tends to zero by ?? . The same estimate also gives absolute convergence of the series defining \(\mathcal{I}_h(A)\). Letting \(N\to\infty\) in the telescoping identity proves ?? .

The grading preservation follows because every term \(\mathrm{ad}_{M_\Lambda}^{\,n}(A)\) has \(D_\Lambda\)-grade \(k\). Since \(k\neq0\), the diagonal part vanishes. This proves (ii).

For support preservation, only the terms in \(M_\Lambda\) supported in \(X\) contribute to commutators with \(A\). Thus repeated commutators with \(M_\Lambda\) do not enlarge the support, proving (iii).

The local norm bound follows by summing the geometric series: \[\|\mathcal{I}_h(A)\| \le \frac{1}{|k|U} \sum_{n\ge0} \left( \frac{|h|\,|X|}{|k|U} \right)^n \|A\| = \frac{1}{|k|U-|h|\,|X|}\|A\|.\] Since \(|h|\le h_0\), this implies 37 .

Finally, \(A^\ast\) has \(D_\Lambda\)-grade \(-k\), and \(\left(\mathrm{ad}_{M_\Lambda}(C)\right)^\ast=-\mathrm{ad}_{M_\Lambda}(C^\ast).\) Hence \(\bigl(\mathrm{ad}_{M_\Lambda}^{\,n}(A)\bigr)^\ast = (-1)^n\mathrm{ad}_{M_\Lambda}^{\,n}(A^\ast).\) Using the definition of \(\mathcal{I}_h\), we compute \[\begin{align} (\mathcal{I}_h(A))^\ast &= \frac{1}{kU} \sum_{n\ge0} \left(\frac{h}{kU}\right)^n (-1)^n \mathrm{ad}_{M_\Lambda}^{\,n}(A^\ast) \\ &= - \frac{1}{(-k)U} \sum_{n\ge0} \left(\frac{h}{(-k)U}\right)^n \mathrm{ad}_{M_\Lambda}^{\,n}(A^\ast) \\ &= -\mathcal{I}_h(A^\ast). \end{align}\] This proves (v). ◻

Lemma 36 (Interaction-level definition, support preservation, and \(\|\cdot\|_\kappa\) bound). Let \(B=\{B_X\}_{X\subset\Lambda}\) be a finite-range interaction. Assume \[\label{eq:Ih-smallness-condition-interaction} U>h_0 s(B).\qquad{(22)}\] Then the following hold.

  1. **Local definition on the off-diagonal sector.* Let \(A\in\frak A_X\) be \(D_\Lambda\)-off-diagonal. Write \[A=\sum_{k\neq0}A^{(k)}.\] Then \[\mathcal{I}_h(A) := \sum_{k\neq0}\mathcal{I}_h(A^{(k)})\] is well-defined, belongs to \(\frak A_X\), and satisfies \[\mathrm{ad}_{UD_\Lambda-hM_\Lambda} \bigl( \mathcal{I}_h(A) \bigr) = A, \qquad (\mathcal{I}_h(A))^{\rm diag}=0.\] In particular, for a nearest-neighbour bond \(e=\langle x,y\rangle\), \[\operatorname{supp}(T_e^{\rm off})\subset\{x,y\} \quad\Longrightarrow\quad \operatorname{supp}\bigl(\mathcal{I}_h(T_e^{\rm off})\bigr) \subset\{x,y\}.\]*

  2. **Interaction-level definition.* Define \(\mathcal{I}_h(B^{\rm off})\) termwise by \[\bigl(\mathcal{I}_h(B^{\rm off})\bigr)_X := \sum_{k\neq0} \mathcal{I}_h\bigl((B_X)^{(k)}\bigr), \qquad X\subset\Lambda .\] Then \(\mathcal{I}_h(B^{\rm off})\) is a finite-range interaction with the same range as \(B\).*

  3. **\(\kappa\)-norm bound.* One has \[\label{eq:Ih-kappa-bound} \|\mathcal{I}_h(B^{\rm off})\|_\kappa \le C_{\mathcal{I}_h}(U,h_0,s(B))\|B\|_\kappa, \qquad C_{\mathcal{I}_h}(U,h_0,s) := \frac{2s}{U-h_0s}.\tag{38}\] *

  4. **Grading preservation.* The map \(\mathcal{I}_h\) preserves the \(D_\Lambda\)-grading termwise. In particular, \[\bigl(\mathcal{I}_h(B^{\rm off})\bigr)^{\rm diag}=0, \qquad \bigl(\mathcal{I}_h(B^{\rm off})\bigr)^{\rm off} = \mathcal{I}_h(B^{\rm off}).\]*

  5. **Right-inverse identity.* As finite-volume operators on \(\mathcal{H}_\Lambda^{\rm hf}\), \[\mathrm{ad}_{UD_\Lambda-hM_\Lambda} \left( \sum_{X\subset\Lambda} \bigl(\mathcal{I}_h(B^{\rm off})\bigr)_X \right) = \sum_{X\subset\Lambda}(B_X)^{\rm off}.\]*

  6. **Adjoint compatibility.* If \(B_\Lambda=\sum_X B_X\) is self-adjoint, then the associated finite-volume operator \[\bigl(\mathcal{I}_h(B^{\rm off})\bigr)_\Lambda := \sum_{X\subset\Lambda} \bigl(\mathcal{I}_h(B^{\rm off})\bigr)_X\] is anti-self-adjoint: \[\bigl(\mathcal{I}_h(B^{\rm off})\bigr)_\Lambda^\ast = - \bigl(\mathcal{I}_h(B^{\rm off})\bigr)_\Lambda .\]*

Proof. For (a), let \(A\in\frak A_X\) be \(D_\Lambda\)-off-diagonal and write \(A=\sum_{k\neq0}A^{(k)}.\) Since \(A\) is supported in \(X\), each nonzero graded piece \(A^{(k)}\) is supported in \(X\), and \(|k|\le |X|\). If \(A^{(k)}\neq0\), then \(|k|U\ge U>h_0 s(B)\ge h_0|X|,\) whenever this construction is applied to local pieces with \(|X|\le s(B)\). Thus Lemma 35 applies to each graded piece. Summing the identities \(\mathrm{ad}_{UD_\Lambda-hM_\Lambda} \bigl( \mathcal{I}_h(A^{(k)}) \bigr) = A^{(k)}\) over \(k\neq0\) gives \(\mathrm{ad}_{UD_\Lambda-hM_\Lambda} \bigl( \mathcal{I}_h(A) \bigr) = A.\) The support preservation and off-diagonality also follow by summing the corresponding conclusions of Lemma 35. The bond statement is the special case \(X=\{x,y\}\).

For (b), apply (a) to each local term \(B_X\). Since \(|X|\le s(B)\) whenever \(B_X\neq0\), the smallness condition ?? ensures that all graded pieces are covered by Lemma 35. Support preservation gives \(\operatorname{supp} \bigl( \mathcal{I}_h((B_X)^{(k)}) \bigr) \subset X,\) and hence \(\mathcal{I}_h(B^{\rm off})\) has the same range as \(B\).

For (c), fix \(X\subset\Lambda\) and \(k\neq0\). By Lemma 35, \[\left\| \mathcal{I}_h\bigl((B_X)^{(k)}\bigr) \right\| \le \frac{1}{|k|U-h_0|X|} \left\|(B_X)^{(k)}\right\| \le \frac{1}{U-h_0s(B)} \|B_X\|.\] Moreover, \((B_X)^{(k)}=0\) for \(|k|>|X|\), so there are at most \(2|X|\le2s(B)\) nonzero values of \(k\neq0\). Therefore \[\left\| \bigl(\mathcal{I}_h(B^{\rm off})\bigr)_X \right\| \le \frac{2s(B)}{U-h_0s(B)} \|B_X\|.\] Multiplying by \(e^{\kappa|X|}\), summing over \(X\ni x\), and taking the supremum over \(x\in\Lambda\) yields 38 .

Part (d) follows termwise from the grading preservation in Lemma 35. Part (e) follows by summing the termwise identities \(\mathrm{ad}_{UD_\Lambda-hM_\Lambda} \bigl( \mathcal{I}_h((B_X)^{(k)}) \bigr) = (B_X)^{(k)}\) over \(X\subset\Lambda\) and \(k\neq0\).

Finally, assume \(B_\Lambda\) is self-adjoint. Then \((B_\Lambda^{(k)})^\ast=B_\Lambda^{(-k)}.\) Using the adjoint compatibility from Lemma 35, we get, at the operator level, \[\left( \mathcal{I}_h(B_\Lambda^{\rm off}) \right)^\ast = \sum_{k\neq0} \bigl( \mathcal{I}_h(B_\Lambda^{(k)}) \bigr)^\ast = -\sum_{k\neq0} \mathcal{I}_h\bigl((B_\Lambda^{(k)})^\ast\bigr) = -\sum_{k\neq0} \mathcal{I}_h(B_\Lambda^{(-k)}) = -\mathcal{I}_h(B_\Lambda^{\rm off}).\] This is precisely (f). ◻

Lemma 37 (\(h\)-derivative bound for \(\mathcal{I}_h\) on graded local pieces). Let \(k\neq0\), and let \(A\in\frak A_X\) be local of \(D_\Lambda\)-grade \(k\). Assume \(|k|U>h_0|X|.\) Then the map \(h\mapsto \mathcal{I}_h(A)\) is analytic in a neighbourhood of the interval \([-h_0,h_0]\), and for \(|h|\le h_0\), \[\partial_h\mathcal{I}_h(A) = \mathcal{I}_h\bigl(\mathrm{ad}_{M_\Lambda}(\mathcal{I}_h(A))\bigr).\] Moreover, \[\|\partial_h\mathcal{I}_h(A)\| \le \frac{|X|}{(|k|U-|h|\,|X|)^2}\|A\| \le \frac{|X|}{(|k|U-h_0|X|)^2}\|A\|.\]

Proof. Analyticity follows directly from the Neumann series definition \[\mathcal{I}_h(A) = \frac{1}{kU} \sum_{n\ge0} \left(\frac{h}{kU}\right)^n \mathrm{ad}_{M_\Lambda}^{\,n}(A),\] because the series converges absolutely and uniformly for \(h\) in a neighbourhood of \([-h_0,h_0]\).

Next differentiate the identity \(\mathrm{ad}_{UD_\Lambda-hM_\Lambda} \bigl( \mathcal{I}_h(A) \bigr) = A.\) Since \(\partial_h \mathrm{ad}_{UD_\Lambda-hM_\Lambda} = -\mathrm{ad}_{M_\Lambda},\) we obtain \(\mathrm{ad}_{UD_\Lambda-hM_\Lambda} \bigl( \partial_h\mathcal{I}_h(A) \bigr) = \mathrm{ad}_{M_\Lambda} \bigl( \mathcal{I}_h(A) \bigr).\) The operator \(\mathrm{ad}_{M_\Lambda}(\mathcal{I}_h(A))\) is supported in \(X\) and has the same \(D_\Lambda\)-grade \(k\). Applying the local inverse \(\mathcal{I}_h\) gives \(\partial_h\mathcal{I}_h(A) = \mathcal{I}_h\bigl(\mathrm{ad}_{M_\Lambda}(\mathcal{I}_h(A))\bigr).\)

For the norm bound, Lemma 34 gives \(\|\mathrm{ad}_{M_\Lambda}(\mathcal{I}_h(A))\| \le |X|\|\mathcal{I}_h(A)\|.\) Using Lemma 35 twice, we get \[\|\partial_h\mathcal{I}_h(A)\| \le \frac{1}{|k|U-|h|\,|X|} \|\mathrm{ad}_{M_\Lambda}(\mathcal{I}_h(A))\|\] and hence \[\|\partial_h\mathcal{I}_h(A)\| \le \frac{|X|}{|k|U-|h|\,|X|} \|\mathcal{I}_h(A)\| \le \frac{|X|}{(|k|U-|h|\,|X|)^2}\|A\|.\] The final bound follows from \(|h|\le h_0\). ◻

8.3 Quantitative LS/SW iteration: deferred proofs↩︎

8.3.1 Proof of Lemma 15↩︎

Write \[H=H_0+V, \qquad H_0:=UD_\Lambda-hM_\Lambda, \qquad V:=B^{\rm diag}+B^{\rm off}.\] By the BCH expansion, \[H^+ := e^SHe^{-S} = H+\mathrm{ad}_S(H)+\sum_{n\ge2}\frac{1}{n!}\mathrm{ad}_S^{\,n}(H).\] Since \(S=\mathcal{I}_h(B^{\rm off}),\) the defining property of \(\mathcal{I}_h\) gives \(\mathrm{ad}_S(H_0) = -B^{\rm off}.\) Therefore the first-order \(D\)-off-diagonal term cancels: \(B^{\rm off}+\mathrm{ad}_S(H_0)=0.\) Thus \[H^+ = H_0 + B^{\rm diag} + \mathrm{ad}_S(B^{\rm diag}+B^{\rm off}) + R,\] where the remainder may first be written as \[R := \sum_{n\ge2}\frac{1}{n!}\mathrm{ad}_S^{\,n}(H_0+V).\]

For the estimates below, we rewrite this remainder so that \(H_0\) no longer appears. Since \(\mathrm{ad}_S(H_0)=-B^{\rm off},\) we have, for \(n\ge2\), \(\mathrm{ad}_S^{\,n}(H_0) = -\mathrm{ad}_S^{\,n-1}(B^{\rm off}).\) Hence \[R = - \sum_{m\ge1}\frac{1}{(m+1)!}\mathrm{ad}_S^{\,m}(B^{\rm off}) + \sum_{n\ge2}\frac{1}{n!} \mathrm{ad}_S^{\,n}(B^{\rm diag}+B^{\rm off}).\] In particular, \(R\) is expressed entirely in terms of \(S\), \(B^{\rm diag}\), and \(B^{\rm off}\).

Set \(B^+ := B^{\rm diag} + \mathrm{ad}_S(B^{\rm diag}+B^{\rm off}) + R.\) Then \(H^+=UD_\Lambda-hM_\Lambda+B^+.\)

BCH remainder bounds. We split \(R=R_0+R_V,\) where \[R_0 := -\sum_{m\ge1}\frac{1}{(m+1)!}\mathrm{ad}_S^{\,m}(B^{\rm off}), \qquad R_V := \sum_{n\ge2}\frac{1}{n!}\mathrm{ad}_S^{\,n}(V).\]

By Lemma 36, the map \(\mathcal{I}_h\) preserves supports. Hence \(s(S)\le s(B).\) Together with the smallness condition \(2s(B)\|S\|_\kappa\le \rho_0<1,\) this implies the hypothesis of Lemma 12 for repeated commutators with \(S\). Applying that lemma to the preceding series gives \(\|R_0\|_\kappa \le C(d,\kappa,\rho_0) \|S\|_\kappa\|B^{\rm off}\|_\kappa .\)

For \(R_V\), write \[R_V = \sum_{n\ge2}\frac{1}{n!}\mathrm{ad}_S^{\,n}(V) = \sum_{m\ge1}\frac{1}{(m+1)!} \mathrm{ad}_S^{\,m}\bigl(\mathrm{ad}_S(V)\bigr).\] By Lemma 11, \(\|\mathrm{ad}_S(V)\|_\kappa \le C(d,\kappa) \|S\|_\kappa\|V\|_\kappa .\) Applying Lemma 12 once more gives \(\|R_V\|_\kappa \le C(d,\kappa,\rho_0) \|S\|_\kappa \|\mathrm{ad}_S(V)\|_\kappa .\) Consequently, \(\|R_V\|_\kappa \le C(d,\kappa,\rho_0) \|S\|_\kappa^2 \|V\|_\kappa .\) Since \(V=B^{\rm diag}+B^{\rm off},\) we have \(\|V\|_\kappa \le \|B^{\rm diag}\|_\kappa+\|B^{\rm off}\|_\kappa.\) Combining the estimates for \(R_0\) and \(R_V\), and increasing the constant if necessary, we obtain \[\begin{align} \|R\|_\kappa \le C(d,\kappa,\rho_0) \left[ \|S\|_\kappa\|B^{\rm off}\|_\kappa + \|S\|_\kappa^2 \bigl( \|B^{\rm diag}\|_\kappa+\|B^{\rm off}\|_\kappa \bigr) \right]. \label{Inq:R95kappa} \end{align}\tag{39}\]

Extracting \(D\)-diagonal and off-diagonal parts. Since \(S\) is \(D\)-off-diagonal and \(B^{\rm diag}\) is \(D\)-diagonal, one has \(\bigl(\mathrm{ad}_S(B^{\rm diag})\bigr)^{\rm diag}=0.\) Thus \[(B^+)^{\rm off} = \mathrm{ad}_S(B^{\rm diag}) + \bigl(\mathrm{ad}_S(B^{\rm off})\bigr)^{\rm off} + R^{\rm off},\] and \[(B^+)^{\rm diag}-B^{\rm diag} = \bigl(\mathrm{ad}_S(B^{\rm off})\bigr)^{\rm diag} + R^{\rm diag}.\]

By Lemma 13, taking the \(D\)-diagonal part is contractive in \(\|\cdot\|_\kappa\), and the \(D\)-off-diagonal extraction satisfies \(\|\Phi^{\rm off}\|_\kappa \le 2\|\Phi\|_\kappa\) for every interaction \(\Phi\). Hence \[\|(B^+)^{\rm off}\|_\kappa \le \|\mathrm{ad}_S(B^{\rm diag})\|_\kappa + 2\|\mathrm{ad}_S(B^{\rm off})\|_\kappa + 2\|R\|_\kappa,\] and \[\|(B^+)^{\rm diag}-B^{\rm diag}\|_\kappa \le \|\mathrm{ad}_S(B^{\rm off})\|_\kappa + \|R\|_\kappa.\]

By Lemma 11, \[\|\mathrm{ad}_S(B^{\rm diag})\|_\kappa \le C(d,\kappa)\|S\|_\kappa\|B^{\rm diag}\|_\kappa, \qquad \|\mathrm{ad}_S(B^{\rm off})\|_\kappa \le C(d,\kappa)\|S\|_\kappa\|B^{\rm off}\|_\kappa.\] Combining these estimates and 39 , we obtain \[\|(B^+)^{\rm diag}-B^{\rm diag}\|_\kappa \le C_2(d,\kappa,\rho_0) \left[ \|S\|_\kappa\|B^{\rm off}\|_\kappa + \|S\|_\kappa^2 \bigl( \|B^{\rm diag}\|_\kappa+\|B^{\rm off}\|_\kappa \bigr) \right],\] which proves ?? .

For the off-diagonal part, the same estimates give \[\|(B^+)^{\rm off}\|_\kappa \le C(d,\kappa,\rho_0) \left[ \|S\|_\kappa\|B^{\rm diag}\|_\kappa + \|S\|_\kappa\|B^{\rm off}\|_\kappa + \|S\|_\kappa^2 \bigl( \|B^{\rm diag}\|_\kappa+\|B^{\rm off}\|_\kappa \bigr) \right].\] If \(S=0\), the desired estimate is immediate. Otherwise the smallness assumption \(2s(B)\|S\|_\kappa\le \rho_0<1\) implies \(\|S\|_\kappa\le1\), since \(s(B)\ge1\). Therefore the quadratic term is bounded by the corresponding linear term. Enlarging the constant gives \[\|(B^+)^{\rm off}\|_\kappa \le C_1(d,\kappa,\rho_0) \|S\|_\kappa \bigl( \|B^{\rm diag}\|_\kappa+\|B^{\rm off}\|_\kappa \bigr),\] which proves ?? .

Bound on the generator. Since \(S=\mathcal{I}_h(B^{\rm off}),\) Lemma 36 gives, whenever \(U>h_0s(B)\), \[\|S\|_\kappa \le \frac{2s(B)}{U-h_0s(B)} \|B^{\rm off}\|_\kappa.\] This is ?? . If in addition \(\frac{h_0}{U}s(B)\le\frac{1}{2},\) then \(U-h_0s(B)\ge \frac{U}{2},\) and hence \(\|S\|_\kappa \le \frac{4s(B)}{U}\|B^{\rm off}\|_\kappa,\) which is ?? . 0◻

8.3.2 Proof of Proposition 16↩︎

Assume \(U\ge U_\ast\). By the large-\(U\) convention and Lemma 15, there is a constant \(C_{\mathcal{I}}=C_{\mathcal{I}}(d,\kappa)\) such that, for every step of the iteration, \[\label{eq:proof-LS-Sn-bound} \|S_n\|_\kappa \le \frac{C_{\mathcal{I}}}{U} \|(B_n)^{\rm off}\|_\kappa .\tag{40}\] The constants \(C_1,C_2\) below are those in Lemma 15, with a fixed choice of \(\rho_0\in(0,1)\).

8.3.2.1 Step 1: choice of \(\varepsilon_\ast\) and bootstrap region.

We use the bootstrap conditions \[\label{eq:spec-bootstrap} \|(B_n)^{\rm off}\|_\kappa\le \varepsilon_\ast U, \qquad \|(B_n)^{\rm diag}\|_\kappa\le 2\varepsilon_\ast U .\tag{41}\] Choose \(\varepsilon_\ast>0\) sufficiently small so that \[\begin{align} &2s_\ast C_{\mathcal{I}}\varepsilon_\ast\le \rho_0, \tag{42} \\ &q:= 3C_1(d,\kappa,\rho_0)C_{\mathcal{I}}\varepsilon_\ast \le \frac{1}{2}. \tag{43} \end{align}\] Here \(s_\ast\) denotes the fixed local-size constant entering the one-step BCH estimate. Finally, enlarge \(C_\ast=C_\ast(d,\kappa)\), if necessary, and shrink \(\varepsilon_\ast\) further so that \[\label{eq:spec-eps-choice-3} C_\ast\frac{\varepsilon_\ast}{1-q^2}\le 1.\tag{44}\] This last condition will keep the diagonal part inside the bootstrap region.

8.3.2.2 Step 2: bootstrap invariance.

Assume that 41 holds at step \(n\). Then 40 gives \(2s_\ast\|S_n\|_\kappa \le 2s_\ast C_{\mathcal{I}}\varepsilon_\ast \le \rho_0,\) so Lemma 15 applies at step \(n\).

For the off-diagonal part, Lemma 15 and 40 give \[\begin{align} \|(B_{n+1})^{\rm off}\|_\kappa &\le C_1(d,\kappa,\rho_0) \|S_n\|_\kappa \bigl( \|(B_n)^{\rm diag}\|_\kappa + \|(B_n)^{\rm off}\|_\kappa \bigr) \\ &\le C_1(d,\kappa,\rho_0) \frac{C_{\mathcal{I}}}{U} \|(B_n)^{\rm off}\|_\kappa \bigl( 2\varepsilon_\ast U+\varepsilon_\ast U \bigr) \\ &= 3C_1(d,\kappa,\rho_0)C_{\mathcal{I}} \varepsilon_\ast \|(B_n)^{\rm off}\|_\kappa . \end{align}\] By the definition of \(q\) in 43 , this yields \(\|(B_{n+1})^{\rm off}\|_\kappa \le q\|(B_n)^{\rm off}\|_\kappa.\) This proves ?? and keeps \(\|(B_{n+1})^{\rm off}\|_\kappa\le \varepsilon_\ast U .\)

For the diagonal increment, Lemma 15 gives \[\begin{align} \|(B_{n+1})^{\rm diag}-(B_n)^{\rm diag}\|_\kappa \le C_2(d,\kappa,\rho_0) \Bigl[ \|S_n\|_\kappa\|(B_n)^{\rm off}\|_\kappa + \|S_n\|_\kappa^2 \bigl( \|(B_n)^{\rm diag}\|_\kappa + \|(B_n)^{\rm off}\|_\kappa \bigr) \Bigr]. \end{align}\] Using 40 and the bootstrap bounds, we obtain \[\begin{align} \|(B_{n+1})^{\rm diag}-(B_n)^{\rm diag}\|_\kappa &\le C_2(d,\kappa,\rho_0) \left[ C_{\mathcal{I}} + 3C_{\mathcal{I}}^2\varepsilon_\ast \right] \frac{\|(B_n)^{\rm off}\|_\kappa^2}{U}. \end{align}\] After enlarging \(C_\ast(d,\kappa)\), this gives \(\|(B_{n+1})^{\rm diag}-(B_n)^{\rm diag}\|_\kappa \le C_\ast \frac{\|(B_n)^{\rm off}\|_\kappa^2}{U}.\) This is ?? .

Summing the diagonal increments and using the contraction of the off-diagonal part gives \[\begin{align} \|(B_n)^{\rm diag}\|_\kappa &\le \|(B_0)^{\rm diag}\|_\kappa + C_\ast\frac{1}{U} \sum_{j=0}^{n-1} \|(B_j)^{\rm off}\|_\kappa^2 \\ &\le \varepsilon_\ast U + C_\ast \frac{\|(B_0)^{\rm off}\|_\kappa^2}{U} \sum_{j=0}^{\infty}q^{2j} \\ &\le \varepsilon_\ast U + C_\ast \frac{\varepsilon_\ast^2U}{1-q^2}. \end{align}\] By 44 , the last term is at most \(\varepsilon_\ast U\). Hence \(\|(B_n)^{\rm diag}\|_\kappa\le 2\varepsilon_\ast U.\) Thus the bootstrap region 41 is invariant, and the same \(\varepsilon_\ast\) works for all \(n\).

8.3.2.3 Step 3: convergence and the \(B_\infty\)-bound.

From ?? and 40 , we get \[\sum_{n\ge0}\|S_n\|_\kappa \le \frac{C_{\mathcal{I}}}{U} \sum_{n\ge0}\|(B_n)^{\rm off}\|_\kappa \le \frac{C_{\mathcal{I}}}{U} \frac{1}{1-q} \|(B_0)^{\rm off}\|_\kappa .\] After enlarging \(C_\ast\), this gives \[\label{eq:proof-generator-summability} \sum_{n\ge0}\|S_n\|_\kappa \le C_\ast \frac{\|(B_0)^{\rm off}\|_\kappa}{U}.\tag{45}\]

In finite volume, this summability implies the existence of the product unitary. Indeed, by the elementary bound from interaction norm to finite-volume operator norm, \(\|S_{n,\Lambda}\| \le |\Lambda|\|S_n\|_\kappa,\) and hence, for each fixed finite \(\Lambda\), \(\sum_{n\ge0}\|S_{n,\Lambda}\|<\infty.\) For notational simplicity we write \(S_n\) for the corresponding finite-volume operator in the following estimate.

Set \(U_N:=e^{S_{N-1}}\cdots e^{S_0}.\) Since each \(S_n\) is anti-self-adjoint, \(e^{S_n}\) is unitary. Moreover, \(U_{N+1}=e^{S_N}U_N,\) and therefore \(\|U_{N+1}-U_N\| = \|(e^{S_N}-\mathbb{1})U_N\| = \|e^{S_N}-\mathbb{1}\|.\) Using \(\|e^{S_N}-\mathbb{1}\| \le e^{\|S_N\|}\|S_N\|,\) we obtain, for \(M>N\), \[\|U_M-U_N\| \le \sum_{k=N}^{M-1}\|U_{k+1}-U_k\| \le \exp\left( \sum_{j\ge0}\|S_j\| \right) \sum_{k=N}^{M-1}\|S_k\|.\] Since \(\sum_{n\ge0}\|S_n\|<\infty\) in finite volume, the right-hand side tends to \(0\) as \(N\to\infty\). Thus \((U_N)_N\) is Cauchy in operator norm, and we may define \[U_{\rm SW} := \lim_{N\to\infty}U_N = \lim_{N\to\infty}e^{S_{N-1}}\cdots e^{S_0}.\] Since \(U_N\) is unitary for every \(N\), the norm limit \(U_{\rm SW}\) is also unitary.

Next, ?? and ?? imply \[\sum_{n\ge0} \|(B_{n+1})^{\rm diag}-(B_n)^{\rm diag}\|_\kappa \le C_\ast \frac{1}{U} \sum_{n\ge0} \|(B_n)^{\rm off}\|_\kappa^2 <\infty.\] Hence \((B_n)^{\rm diag}\) converges in \(\|\cdot\|_\kappa\) to a \(D_\Lambda\)-diagonal limit, which we denote by \(B_\infty(h)\). Also, by ?? , \(\|(B_n)^{\rm off}\|_\kappa \le q^n\|(B_0)^{\rm off}\|_\kappa \longrightarrow0.\) Therefore \(B_n = (B_n)^{\rm diag}+(B_n)^{\rm off} \longrightarrow B_\infty(h)\) in \(\|\cdot\|_\kappa\). For each fixed finite volume, this also implies operator-norm convergence of the corresponding finite-volume sums.

By construction, \(H^{(N)} = U_NH^{(0)}U_N^\ast = UD_\Lambda-hM_\Lambda+B_N .\) Passing to the limit in finite-volume operator norm gives \(U_{\rm SW}H^{(0)}U_{\rm SW}^{\ast} = UD_\Lambda-hM_\Lambda+B_\infty(h).\) Since each \((B_n)^{\rm diag}\) is \(D_\Lambda\)-diagonal and the diagonal subspace is closed under the \(\|\cdot\|_\kappa\)-limit, \(B_\infty(h)\) is \(D_\Lambda\)-diagonal.

Finally, summing ?? over \(n\ge0\) and using \(\|(B_n)^{\rm off}\|_\kappa \le q^n\|(B_0)^{\rm off}\|_\kappa,\) we obtain \[\|B_\infty(h)-(B_0)^{\rm diag}\|_\kappa \le C_\ast \frac{1}{U} \sum_{n\ge0} \|(B_n)^{\rm off}\|_\kappa^2 \le C_\ast \frac{\|(B_0)^{\rm off}\|_\kappa^2}{U} \sum_{n\ge0}q^{2n}.\] After enlarging \(C_\ast\), this gives \(\|B_\infty(h)-(B_0)^{\rm diag}\|_\kappa \le C_\ast \frac{\|(B_0)^{\rm off}\|_\kappa^2}{U}.\) This is ?? . 0◻

8.3.3 Proof of Corollary 17↩︎

By the choice of \(C_T(d,\kappa)\), one has \(\|(T_\Lambda)^{\rm off}\|_\kappa\le C_T(d,\kappa)|t|,\) and \(\|T_\Lambda^{(0)}\|_\kappa\le C_T(d,\kappa)|t|.\) Since \(\frac{|t|}{U}\le \varepsilon_{\rm SW}(d,\kappa) \le \frac{\varepsilon_\ast(d,\kappa)}{2C_T(d,\kappa)},\) we have \[\|(B_{0,\Lambda})^{\rm off}\|_\kappa = \|(T_\Lambda)^{\rm off}\|_\kappa \le \varepsilon_\ast U, \qquad \|(B_{0,\Lambda})^{\rm diag}\|_\kappa = \|T_\Lambda^{(0)}\|_\kappa \le \varepsilon_\ast U.\] Thus the hypotheses of Proposition 16 hold for the initial datum \[B_{0,\Lambda}=T_\Lambda, \qquad H_\Lambda^{(0)}(h) = H_\Lambda^{\rm Hub}(h) = UD_\Lambda-hM_\Lambda+T_\Lambda .\] Hence the LS/SW iteration is well-defined for all \(n\ge0\), and the bounds ?? –?? hold for the sequence generated from \(B_{0,\Lambda}=T_\Lambda\).

In particular, Proposition 16 gives a product unitary \(U_{\rm SW}(h)\) and a \(D_\Lambda\)-diagonal interaction \(B_\infty(h)\) such that \(U_{\rm SW}(h)H_\Lambda^{\rm Hub}(h)U_{\rm SW}(h)^\ast = UD_\Lambda-hM_\Lambda+B_\infty(h).\) Define \(\Delta_\Lambda(h):=B_\infty(h)-T_\Lambda^{(0)}.\) Since both \(B_\infty(h)\) and \(T_\Lambda^{(0)}\) are \(D_\Lambda\)-diagonal, one has \([\Delta_\Lambda(h),D_\Lambda]=0.\) Therefore \[U_{\rm SW}(h)H_\Lambda^{\rm Hub}(h)U_{\rm SW}(h)^\ast = UD_\Lambda-hM_\Lambda+T_\Lambda^{(0)}+\Delta_\Lambda(h).\]

Moreover, by ?? , \[\|\Delta_\Lambda(h)\|_\kappa = \|B_\infty(h)-T_\Lambda^{(0)}\|_\kappa \le C_\ast(d,\kappa) \frac{\|(T_\Lambda)^{\rm off}\|_\kappa^2}{U}.\] Using \(\|(T_\Lambda)^{\rm off}\|_\kappa\le C_T(d,\kappa)|t|,\) we obtain \(\|\Delta_\Lambda(h)\|_\kappa \le C_\ast(d,\kappa)C_T(d,\kappa)^2 \frac{t^2}{U}.\) This gives the stated estimate with \(\widetilde{C}(d,\kappa) := C_\ast(d,\kappa)C_T(d,\kappa)^2.\)

Finally, ?? gives \[\sum_{n\ge0}\|S_n(h)\|_\kappa \le C_\ast(d,\kappa) \frac{\|(T_\Lambda)^{\rm off}\|_\kappa}{U} \le C_\ast(d,\kappa)C_T(d,\kappa) \frac{|t|}{U}.\] After enlarging \(C_\ast(d,\kappa)\) once more, this becomes \(\sum_{n\ge0}\|S_n(h)\|_\kappa \le C_\ast(d,\kappa) \frac{|t|}{U}.\) This completes the proof. 0◻

8.4 Dressing of the normalized defect density↩︎

We prove Proposition 33. The only point is that the observable is normalized by the volume. This normalization turns the commutator with a short-range interaction into a volume-uniform quantity.

For a finite torus \(\Lambda_L\), set \[\bar q_{\Lambda_L} := \frac{1}{|\Lambda_L|} \sum_{x\in\Lambda_L}q_x .\]

Lemma 38 (Averaged onsite commutator bound). Let \(K=\{K_X\}_{X\subset\Lambda_L}\) be an even interaction on \(\Lambda_L\), and write \[K_{\Lambda_L}:=\sum_{X\subset\Lambda_L}K_X .\] Then \[\left\| [K_{\Lambda_L},\bar q_{\Lambda_L}] \right\| \le 2\|K\|_0 \le 2\|K\|_\kappa .\]

Proof. Since \(q_x\) is even and supported at \(x\), an even local term \(K_X\) commutes with \(q_x\) whenever \(x\notin X\). Hence \[[K_{\Lambda_L},\bar q_{\Lambda_L}] = \frac{1}{|\Lambda_L|} \sum_{x\in\Lambda_L} \sum_{X\ni x} [K_X,q_x].\] Using \(\|q_x\|\le1\), we obtain \[\left\| [K_{\Lambda_L},\bar q_{\Lambda_L}] \right\| \le \frac{2}{|\Lambda_L|} \sum_{x\in\Lambda_L} \sum_{X\ni x} \|K_X\|.\] By the definition of the interaction norm, \(\sum_{X\ni x}\|K_X\|\le \|K\|_0\) for every \(x\). Therefore \(\left\| [K_{\Lambda_L},\bar q_{\Lambda_L}] \right\| \le 2\|K\|_0.\) The inequality \(\|K\|_0\le\|K\|_\kappa\) is immediate. ◻

Proof of Proposition 33. Choose the LS/SW norm parameter \(\kappa>0\) used in the construction. Recall \[\rho_q(U;h_0) := \sup_{L\in2\mathbb{N}} \sup_{|h|\le h_0} \left\| U_{{\rm SW},\Lambda_L}(h) \bar q_{\Lambda_L} U_{{\rm SW},\Lambda_L}(h)^\ast - \bar q_{\Lambda_L} \right\|.\] By Proposition 16 and Corollary 17, after increasing the strong-coupling threshold if necessary, the LS/SW unitary is the norm limit of finite products of unitary conjugations generated by even anti-self-adjoint interactions \(S_n(h)\), and \[\label{eq:appendix-SW-generator-sum-for-charge} \sup_{L\in2\mathbb{N}} \sup_{|h|\le h_0} \sum_{n\ge0}\|S_n(h)\|_\kappa \le C_{\rm SW}(h_0,d,\kappa)\frac{|t|}{U}.\tag{46}\] Here \(C_{\rm SW}(h_0,d,\kappa)<\infty\) is independent of \(L\), \(h\), and \(U\).

Let \(V_{n,\Lambda_L}(h):=e^{S_n(h)}.\) For each \(n\), the integral form of the Duhamel formula gives \[V_{n,\Lambda_L}(h)\bar q_{\Lambda_L} V_{n,\Lambda_L}(h)^\ast - \bar q_{\Lambda_L} = \int_0^1 e^{sS_n(h)} \mathrm{ad}_{S_n(h)}(\bar q_{\Lambda_L}) e^{-sS_n(h)} \,ds .\] Thus, by unitarity and Lemma 38, \(\left\| V_{n,\Lambda_L}(h)\bar q_{\Lambda_L} V_{n,\Lambda_L}(h)^\ast - \bar q_{\Lambda_L} \right\| \le 2\|S_n(h)\|_\kappa .\)

Let \(U_{{\rm SW},\Lambda_L}^{(N)}(h) := e^{S_{N-1}(h)}\cdots e^{S_1(h)}e^{S_0(h)}\) be the finite LS/SW product after \(N\) steps. A telescoping expansion of the product of unitary conjugations yields \[\left\| U_{{\rm SW},\Lambda_L}^{(N)}(h) \bar q_{\Lambda_L} U_{{\rm SW},\Lambda_L}^{(N)}(h)^\ast - \bar q_{\Lambda_L} \right\| \le \sum_{n=0}^{N-1} \left\| V_{n,\Lambda_L}(h)\bar q_{\Lambda_L} V_{n,\Lambda_L}(h)^\ast - \bar q_{\Lambda_L} \right\|.\] Consequently, \(\left\| U_{{\rm SW},\Lambda_L}^{(N)}(h) \bar q_{\Lambda_L} U_{{\rm SW},\Lambda_L}^{(N)}(h)^\ast - \bar q_{\Lambda_L} \right\| \le 2\sum_{n=0}^{N-1}\|S_n(h)\|_\kappa .\) Passing to the norm limit \(N\to\infty\), we obtain \[\left\| U_{{\rm SW},\Lambda_L}(h) \bar q_{\Lambda_L} U_{{\rm SW},\Lambda_L}(h)^\ast - \bar q_{\Lambda_L} \right\| \le 2\sum_{n\ge0}\|S_n(h)\|_\kappa .\] Taking the supremum over \(L\in2\mathbb{N}\) and \(|h|\le h_0\), and using 46 , gives \(\rho_q(U;h_0) \le 2C_{\rm SW}(h_0,d,\kappa)\frac{|t|}{U}.\) Since \(t\) is fixed in the strong-coupling limit, the right-hand side tends to zero as \(U\to\infty\). Hence \(\rho_q(U;h_0)\rightarrow0.\) ◻

8.5 \(h\)-derivative estimates for LS/SW increments↩︎

The estimates in this subsection are used to control the \(h\)-dependence of the \(\lambda\)-expansion remainders in Appendix 10. They are not used to prove a direct \(C^1\) comparison between the full Hubbard pressure and the \(P\)-block pressure.

Lemma 39 (Differentiated one-step diagonal increment). Let \[H(h)=H_{\rm d}(h)+D(h)+F(h), \qquad H_{\rm d}(h):=UD_\Lambda-hM_\Lambda,\] where \(D(h)\) is \(D_\Lambda\)-diagonal and \(F(h)\) is \(D_\Lambda\)-off-diagonal. Assume that \(D(h)\) and \(F(h)\) are \(C^1\) in \(h\) in the interaction norm. Let \(S(h):=\mathcal{I}_h(F(h)),\) and let \[H^+(h):=e^{S(h)}H(h)e^{-S(h)} = H_{\rm d}(h)+D^+(h)+F^+(h)\] be one LS/SW step, with \(D^+(h)\) the \(D_\Lambda\)-diagonal part. Set \[\delta(h):=D^+(h)-D(h).\] Assume the one-step smallness hypotheses of Lemma 15, and assume the local \(h\)-derivative bounds for \(\mathcal{I}_h\) from Lemmas 35 and 37. Then there exists a constant \(C=C(d,\kappa,h_0/U)<\infty\) independent of \(\Lambda\) such that \[\|\partial_h\delta(h)\|_\kappa \le C \left( \frac{\|F(h)\|_\kappa}{U} \|\partial_hF(h)\|_\kappa + \frac{\|F(h)\|_\kappa^2}{U^2} \bigl(1+\|\partial_hD(h)\|_\kappa\bigr) \right).\]

Proof. For readability write \[a:=\|F(h)\|_\kappa, \qquad \dot{a}:=\|\partial_hF(h)\|_\kappa, \qquad d:=\|D(h)\|_\kappa, \qquad \dot{d}:=\|\partial_hD(h)\|_\kappa.\] The one-step hypotheses include the usual bootstrap bound \(d\le C U,\) with \(C\) independent of \(\Lambda\). This constant will be absorbed below.

We first record the bounds on the generator. Since \(S(h)=\mathcal{I}_h(F(h)),\) Lemma 36 gives \(\|S(h)\|_\kappa \le C\frac{a}{U}.\) Differentiating \(S(h)=\mathcal{I}_h(F(h))\) gives \(\partial_hS(h) = \mathcal{I}_h(\partial_hF(h)) + (\partial_h\mathcal{I}_h)(F(h)).\) By Lemmas 36 and 37, \(\|\partial_hS(h)\|_\kappa \le C \left( \frac{\dot{a}}{U} + \frac{a}{U^2} \right).\)

Next we write the diagonal increment explicitly. Since \(\mathrm{ad}_{S(h)}(H_{\rm d}(h))=-F(h),\) the BCH expansion gives \[e^{S}H_{\rm d}e^{-S} + e^{S}Fe^{-S} - H_{\rm d} = \sum_{m\ge1} \frac{m}{(m+1)!}\, \mathrm{ad}_S^{\,m}(F),\] where \(S=S(h)\) and \(F=F(h)\). Also, \[e^{S}D e^{-S}-D = \sum_{m\ge1} \frac{1}{m!}\mathrm{ad}_S^{\,m}(D).\] The first term \(\mathrm{ad}_{S}(D)\) is \(D_\Lambda\)-off-diagonal, because \(S\) is off-diagonal and \(D\) is diagonal. Hence it does not contribute to the diagonal increment. Therefore \[\label{eq:one-step-diag-increment-BCH} \delta(h) = \left( \sum_{m\ge1} \frac{m}{(m+1)!}\mathrm{ad}_S^{\,m}(F) + \sum_{m\ge2} \frac{1}{m!}\mathrm{ad}_S^{\,m}(D) \right)^{\rm diag}.\tag{47}\] The series are absolutely convergent in \(\|\cdot\|_\kappa\) by Lemma 12 and the one-step smallness assumption.

We now differentiate 47 . Termwise differentiation is justified by the same BCH summability bound, applied uniformly in the one-step smallness regime. For any \(X=X(h)\), \[\partial_h\mathrm{ad}_S^{\,m}(X) = \sum_{j=0}^{m-1} \mathrm{ad}_S^{\,j} \mathrm{ad}_{\partial_hS} \mathrm{ad}_S^{\,m-1-j}(X) + \mathrm{ad}_S^{\,m}(\partial_hX).\] Applying this identity to the first series in 47 , we estimate the two types of terms separately. For the terms in which the derivative hits one of the \(S\)’s, Lemma 11 gives, for each \(m\ge1\), \[\left\| \sum_{j=0}^{m-1} \mathrm{ad}_S^{\,j} \mathrm{ad}_{\partial_hS} \mathrm{ad}_S^{\,m-1-j}(F) \right\|_\kappa \le C m \bigl(C\|S\|_\kappa\bigr)^{m-1} \|\partial_hS\|_\kappa\,\|F\|_\kappa .\] The case \(m=1\) is important here: it gives the term \(\mathrm{ad}_{\partial_hS}(F)\), and hence no factor \(\|S\|_\kappa\) is present in the leading contribution. Using the one-step smallness assumption, we may assume \(C_{\rm com}(d,\kappa)\|S\|_\kappa\le \rho<1 .\) Hence \[\sum_{m\ge1} \frac{m}{(m+1)!} m \bigl(C_{\rm com}(d,\kappa)\|S\|_\kappa\bigr)^{m-1} \le \sum_{m\ge1} \frac{m^2}{(m+1)!}\rho^{m-1} =:C_\rho<\infty .\] Therefore \[\sum_{m\ge1} \frac{m}{(m+1)!} \left\| \sum_{j=0}^{m-1} \mathrm{ad}_S^{\,j} \mathrm{ad}_{\partial_hS} \mathrm{ad}_S^{\,m-1-j}(F) \right\|_\kappa \le C_\rho\, \|\partial_hS\|_\kappa\,a .\]

For the terms in which the derivative hits \(F\), every term contains at least one factor \(S\), since the first series starts with \(m=1\). Thus \(\left\| \mathrm{ad}_S^{\,m}(\partial_hF) \right\|_\kappa \le C \bigl(C\|S\|_\kappa\bigr)^m \|\partial_hF\|_\kappa ,\) and the same summability gives \(\sum_{m\ge1} \frac{m}{(m+1)!} \left\| \mathrm{ad}_S^{\,m}(\partial_hF) \right\|_\kappa \le C\|S\|_\kappa\,\dot{a} .\) Consequently, \[\left\| \partial_h \left( \sum_{m\ge1} \frac{m}{(m+1)!}\mathrm{ad}_S^{\,m}(F) \right) \right\|_\kappa \le C \left( \|\partial_hS\|_\kappa\,a + \|S\|_\kappa\,\dot{a} \right).\]

We next estimate the second series. Since this series starts at \(m=2\), a term in which the derivative hits one occurrence of \(S\) still contains at least one further occurrence of \(S\). Hence, for \(m\ge2\), \[\left\| \sum_{j=0}^{m-1} \mathrm{ad}_S^{\,j} \mathrm{ad}_{\partial_hS} \mathrm{ad}_S^{\,m-1-j}(D) \right\|_\kappa \le C m \bigl(C_{\rm com}(d,\kappa)\|S\|_\kappa\bigr)^{m-1} \|\partial_hS\|_\kappa\,\|D\|_\kappa .\] Using again the one-step smallness assumption \(C_{\rm com}(d,\kappa)\|S\|_\kappa\le \rho<1,\) we have \[\sum_{m\ge2} \frac{m}{m!} \bigl(C_{\rm com}(d,\kappa)\|S\|_\kappa\bigr)^{m-1} \le C_\rho\,\|S\|_\kappa ,\] after increasing \(C_\rho\) if necessary. Therefore \[\sum_{m\ge2} \frac{1}{m!} \left\| \sum_{j=0}^{m-1} \mathrm{ad}_S^{\,j} \mathrm{ad}_{\partial_hS} \mathrm{ad}_S^{\,m-1-j}(D) \right\|_\kappa \le C\,\|S\|_\kappa\,\|\partial_hS\|_\kappa\,d .\]

If the derivative hits the factor \(D\), then every term contains at least two factors \(S\). Thus, by the same smallness assumption, \(\sum_{m\ge2} \frac{1}{m!} \left\| \mathrm{ad}_S^{\,m}(\partial_hD) \right\|_\kappa \le C\,\|S\|_\kappa^2\,\dot{d} .\) Combining the two estimates gives \[\left\| \partial_h \left( \sum_{m\ge2} \frac{1}{m!}\mathrm{ad}_S^{\,m}(D) \right) \right\|_\kappa \le C \left( \|S\|_\kappa\,\|\partial_hS\|_\kappa\,d + \|S\|_\kappa^2\,\dot{d} \right).\]

The \(D_\Lambda\)-diagonal projection is contractive in the interaction norm, so the same estimates apply after taking the diagonal part. Combining the two series, we get \[\|\partial_h\delta(h)\|_\kappa \le C \left( \|\partial_hS\|_\kappa\,a + \|S\|_\kappa\,\dot{a} + \|S\|_\kappa\,\|\partial_hS\|_\kappa\,d + \|S\|_\kappa^2\,\dot{d} \right).\]

Finally, we substitute \[\|S\|_\kappa\le C\frac{a}{U}, \qquad \|\partial_hS\|_\kappa \le C\left(\frac{\dot{a}}{U}+\frac{a}{U^2}\right), \qquad d\le CU.\] The first two terms give \(\|\partial_hS\|_\kappa\,a+\|S\|_\kappa\,\dot{a} \le C\left( \frac{a\dot{a}}{U} + \frac{a^2}{U^2} \right).\) The third term gives \(\|S\|_\kappa\,\|\partial_hS\|_\kappa\,d \le C \frac{a}{U} \left( \frac{\dot{a}}{U}+\frac{a}{U^2} \right)U \le C\left( \frac{a\dot{a}}{U} + \frac{a^2}{U^2} \right),\) and the last term gives \(\|S\|_\kappa^2\,\dot{d} \le C\frac{a^2}{U^2}\dot{d}.\) Hence \(\|\partial_h\delta(h)\|_\kappa \le C \left( \frac{a\dot{a}}{U} + \frac{a^2}{U^2} + \frac{a^2}{U^2}\dot{d} \right).\) The proof is complete. ◻

8.6 Second-order computations for the \(\xi\)- and \(\lambda\)-schemes↩︎

8.6.1 Proof of Lemma 20↩︎

Set \[H_{\rm d}:=UD_\Lambda-hM_\Lambda, \qquad T^{(0)}:=T_\Lambda^{(0)}, \qquad V:=(T_\Lambda)^{\rm off}.\] Thus \[H_\Lambda(h;\xi)=H_{\rm d}+\xi T^{(0)}+\xi V, \qquad [H_{\rm d},D_\Lambda]=0.\]

Step 1. Expansion at \(\xi=0\). We use the \(\xi\)-expansion introduced in Subsection 3.1. In particular, \[B_\infty(h;\xi) = \xi T^{(0)}+\Delta_\Lambda(h;\xi), \qquad \Delta_\Lambda(h;\xi) = \sum_{m\ge2}\xi^m(\Delta_\Lambda)^{[m]}_{\xi}(h),\] and \[H_\Lambda^{(2)}(h) = (\Delta_\Lambda)^{[2]}_{\xi}(h).\] Thus it remains only to compute the \(\xi^2\)-coefficient of the diagonal correction. This coefficient is determined by the first LS/SW step, since the off-diagonal part left after that step is already of order \(\xi^2\), and later diagonal increments are at least quadratic in that remaining off-diagonal part.

Step 2. The first LS/SW step and the \(\xi^2\)-diagonal term. Let \[S^{[1]}:=\mathcal{I}_h(V), \qquad S_0(\xi):=\mathcal{I}_h\bigl((\xi T_\Lambda)^{\rm off}\bigr) = \xi S^{[1]}.\] By the defining property of \(\mathcal{I}_h\), \(\mathrm{ad}_{H_{\rm d}}(S^{[1]})=V,\) and \(\mathrm{ad}_{S^{[1]}}(H_{\rm d})=-V.\) Set \[H_0(\xi):=H_\Lambda(h;\xi), \qquad H_1(\xi):=e^{S_0(\xi)}H_0(\xi)e^{-S_0(\xi)}.\] By the BCH expansion, with the remainder controlled in \(\|\cdot\|_\kappa\) by Lemma 12 and Lemma 11, we have \[H_1(\xi) = H_0(\xi) + \mathrm{ad}_{S_0(\xi)}(H_0(\xi)) + \frac{1}{2} \mathrm{ad}_{S_0(\xi)}^2(H_0(\xi)) + O(|\xi|^3)\] in \(\|\cdot\|_\kappa\). Substituting \(H_0(\xi)=H_{\rm d}+\xi T^{(0)}+\xi V\) and \(S_0(\xi)=\xi S^{[1]},\) we obtain \[H_1(\xi) = H_{\rm d} + \xi T^{(0)} + \xi V + \xi \mathrm{ad}_{S^{[1]}}(H_{\rm d}) + \xi^2\mathrm{ad}_{S^{[1]}}(T^{(0)}) + \xi^2\mathrm{ad}_{S^{[1]}}(V) + \frac{1}{2}\xi^2\mathrm{ad}_{S^{[1]}}^2(H_{\rm d}) + O(|\xi|^3).\] The \(\xi\)-linear off-diagonal terms cancel, because \(\xi V+\xi\mathrm{ad}_{S^{[1]}}(H_{\rm d})=0.\) Moreover, \(\mathrm{ad}_{S^{[1]}}^2(H_{\rm d}) = -\mathrm{ad}_{S^{[1]}}(V).\) Hence \[H_1(\xi) = H_{\rm d} + \xi T^{(0)} + \xi^2\mathrm{ad}_{S^{[1]}}(T^{(0)}) + \frac{1}{2}\xi^2\mathrm{ad}_{S^{[1]}}(V) + O(|\xi|^3)\] in \(\|\cdot\|_\kappa\).

Since \(T^{(0)}\) is \(D_\Lambda\)-diagonal and \(S^{[1]}\) is \(D_\Lambda\)-off-diagonal, the \(D\)-grading rule gives \(\bigl(\mathrm{ad}_{S^{[1]}}(T^{(0)})\bigr)^{\rm diag}=0.\) Therefore \[\label{eq:first-step-xi2-diag} H_1(\xi)^{\rm diag} = H_{\rm d} + \xi T^{(0)} + \frac{1}{2}\xi^2 \bigl(\mathrm{ad}_{\mathcal{I}_h(V)}(V)\bigr)^{\rm diag} + O(|\xi|^3).\tag{48}\] Also, \[\label{eq:first-step-off-Oxi2} H_1(\xi)^{\rm off}=O(\xi^2) \qquad \text{in }\|\cdot\|_\kappa,\tag{49}\] because the \(\xi\)-linear off-diagonal term is cancelled in the first step.

Step 3. Later LS/SW steps do not change the \(\xi^2\)-diagonal coefficient. Let \(H_n(\xi)\) be the Hamiltonian after \(n\) LS/SW steps, and write \(H_n(\xi)=H_{\rm d}+B_n(\xi).\) By 49 , \(B_1(\xi)^{\rm off}=O(|\xi|^2)\) in \(\|\cdot\|_\kappa\). Applying the contraction estimate ?? from Proposition 16 from step \(1\) onward, we get \(\|B_n(\xi)^{\rm off}\|_\kappa \le C q^{n-1}|\xi|^2, \, n\ge1,\) for \(|\xi|\) sufficiently small. Here \(C\) is uniform in \(n\), \(\Lambda\), and \(|h|\le h_0\).

By the diagonal increment estimate ?? , \(\|B_{n+1}(\xi)^{\rm diag}-B_n(\xi)^{\rm diag}\|_\kappa \le C_\ast \frac{\|B_n(\xi)^{\rm off}\|_\kappa^2}{U}.\) Therefore \[\sum_{n\ge1} \|B_{n+1}(\xi)^{\rm diag}-B_n(\xi)^{\rm diag}\|_\kappa \le C|\xi|^4 \sum_{n\ge1}q^{2(n-1)} = O(|\xi|^4)\] in \(\|\cdot\|_\kappa\). Hence the total contribution of all LS/SW steps after the first one to the diagonal part is \(O(|\xi|^4)\). In particular, these later steps do not change the \(\xi^2\)-coefficient of the limiting diagonal correction.

Step 4. Identification of the second-order coefficient. By 48 , \[B_1(\xi)^{\rm diag} = \xi T^{(0)} + \frac{1}{2}\xi^2 \bigl(\mathrm{ad}_{\mathcal{I}_h(V)}(V)\bigr)^{\rm diag} + O(|\xi|^3)\] in \(\|\cdot \|_{\kappa}\). By Step 3, the diagonal increments from all later steps are \(O(|\xi|^4)\). Hence \[B_\infty(h;\xi) = \xi T^{(0)} + \frac{1}{2}\xi^2 \bigl(\mathrm{ad}_{\mathcal{I}_h(V)}(V)\bigr)^{\rm diag} + O(|\xi|^3).\] Since, by definition, \(B_\infty(h;\xi) = \xi T^{(0)}+\Delta_\Lambda(h;\xi),\) we obtain \[\Delta_\Lambda(h;\xi) = \frac{1}{2}\xi^2 \bigl(\mathrm{ad}_{\mathcal{I}_h(V)}(V)\bigr)^{\rm diag} + O(|\xi|^3).\] Therefore \((\Delta_\Lambda)^{[2]}_{\xi}(h) = \frac{1}{2} \bigl(\mathrm{ad}_{\mathcal{I}_h(V)}(V)\bigr)^{\rm diag}.\) Since \(V=(T_\Lambda)^{\rm off}\), this proves the asserted formula. 0◻

8.6.2 Proof of Lemma 21↩︎

Write \(T_\Lambda=T_\Lambda^{(0)}+V\) with \(V:=(T_\Lambda)^{\rm off},\) and set \(H_0(h):=UD_\Lambda-hM_\Lambda.\)

Second-order coefficient at the first LS/SW step. By Lemma 20, we have \((\Delta_\Lambda)^{[2]}_{\xi}(h) = \frac{1}{2} \bigl(\mathrm{ad}_{\mathcal{I}_h(V)}(V)\bigr)^{\rm diag}.\) For the \(\lambda\)-scheme, \(H_\Lambda(h;\lambda) = H_0(h)+T_\Lambda^{(0)}+\lambda V.\) The first generator is \(S_0(\lambda)=\lambda\mathcal{I}_h(V),\) and the defining property of \(\mathcal{I}_h\) gives \(\mathrm{ad}_{\mathcal{I}_h(V)}(H_0(h))=-V.\)

By the BCH expansion, with the remainder controlled in \(\|\cdot\|_0\) by Lemma 12 and Lemma 11, we have \[e^{S_0(\lambda)} H_\Lambda(h;\lambda) e^{-S_0(\lambda)} = H_\Lambda(h;\lambda) + \mathrm{ad}_{S_0(\lambda)}(H_\Lambda(h;\lambda)) + \frac{1}{2} \mathrm{ad}_{S_0(\lambda)}^2(H_\Lambda(h;\lambda)) + O(|\lambda|^3)\] in \(\|\cdot\|_0\). Substituting \(S_0(\lambda)=\lambda\mathcal{I}_h(V)\) and using \(\mathrm{ad}_{\mathcal{I}_h(V)}(H_0(h))=-V,\) we obtain \[\begin{align} e^{S_0(\lambda)} H_\Lambda(h;\lambda) e^{-S_0(\lambda)} &= H_0(h)+T_\Lambda^{(0)} +\lambda\,\mathrm{ad}_{\mathcal{I}_h(V)}(T_\Lambda^{(0)}) \\ &\quad +\lambda^2 \left[ \mathrm{ad}_{\mathcal{I}_h(V)}(V) + \frac{1}{2} \mathrm{ad}_{\mathcal{I}_h(V)}^2(H_0(h)) + \frac{1}{2} \mathrm{ad}_{\mathcal{I}_h(V)}^2(T_\Lambda^{(0)}) \right] + O(|\lambda|^3). \end{align}\] Since \(\mathrm{ad}_{\mathcal{I}_h(V)}^2(H_0(h)) = -\mathrm{ad}_{\mathcal{I}_h(V)}(V),\) the \(\lambda^2\)-coefficient becomes \(\frac{1}{2}\mathrm{ad}_{\mathcal{I}_h(V)}(V) + \frac{1}{2}\mathrm{ad}_{\mathcal{I}_h(V)}^2(T_\Lambda^{(0)}).\) Taking the \(D_\Lambda\)-diagonal part gives \(\frac{1}{2} \bigl(\mathrm{ad}_{\mathcal{I}_h(V)}(V)\bigr)^{\rm diag} + \frac{1}{2} \bigl(\mathrm{ad}_{\mathcal{I}_h(V)}^2(T_\Lambda^{(0)})\bigr)^{\rm diag}.\) The first term is exactly \((\Delta_\Lambda)^{[2]}_{\xi}(h),\) and the second term is \(\mathcal{R}^{(2)}_\Lambda(h).\)

Thus, after the first LS/SW step, the \(\lambda^2\)-diagonal coefficient is \((\Delta_\Lambda)^{[2]}_{\xi}(h) + \mathcal{R}^{(2)}_\Lambda(h).\) However, unlike the \(\xi\)-scheme, the first transformed Hamiltonian still has a \(\lambda\)-linear off-diagonal term, \(\lambda\, \mathrm{ad}_{\mathcal{I}_h(V)}(T_\Lambda^{(0)}).\) The remaining contribution to the \(\lambda^2\)-diagonal coefficient comes from the subsequent LS/SW steps. We denote this total later contribution by \(\mathcal{E}^{(2)}_\Lambda(h)\). Equivalently, \[\mathcal{E}^{(2)}_\Lambda(h) = (\Delta_\Lambda)^{[2]}_{\lambda}(h) - (\Delta_\Lambda)^{[2]}_{\xi}(h) - \mathcal{R}^{(2)}_\Lambda(h).\] This gives the asserted decomposition.

Definition and estimate of \(\mathcal{E}^{(2)}_\Lambda(h)\). Let \(B_n(h;\lambda)\) be the interaction produced by the LS/SW iteration applied to \(H_\Lambda(h;\lambda) = H_0(h)+T_\Lambda^{(0)}+\lambda V .\) Thus the initial interaction is \[B_0(h;\lambda) := T_\Lambda^{(0)}+\lambda V, \qquad B_0(h;\lambda)^{\rm diag}=T_\Lambda^{(0)}, \qquad B_0(h;\lambda)^{\rm off}=\lambda V.\] After \(n\) steps we write \[H_n(h;\lambda) = H_0(h) + B_n(h;\lambda) = H_0(h) + (B_n(h;\lambda))^{\rm diag} + (B_n(h;\lambda))^{\rm off}.\] Set \[\delta_n(h;\lambda) := (B_{n+1}(h;\lambda))^{\rm diag} - (B_n(h;\lambda))^{\rm diag}.\] Since the limiting interaction \(B_\infty(h;\lambda)\) is \(D_\Lambda\)-diagonal and, by definition, \(B_\infty(h;\lambda) = T_\Lambda^{(0)}+\Delta_\Lambda(h;\lambda),\) we have \[\Delta_\Lambda(h;\lambda) = B_\infty(h;\lambda)-T_\Lambda^{(0)} = \sum_{n\ge0}\delta_n(h;\lambda),\] with convergence in the interaction norm, for \(|\lambda|\) sufficiently small.

By the analytic dependence of the LS/SW iteration on \(\lambda\), each \(\delta_n(h;\lambda)\) is analytic near \(\lambda=0\). Moreover, \(\delta_n(h;\lambda)\) has no linear term, because the diagonal increment is quadratic in the off-diagonal input and \(B_0(h;\lambda)^{\rm off}=\lambda V.\) We therefore write \[\delta_n(h;\lambda) = \sum_{m\ge2}\lambda^m\delta_n^{[m]}(h).\] By the computation of the first step above, the \(\lambda^2\)-coefficient of \(\delta_0(h;\lambda)\) is \((\Delta_\Lambda)^{[2]}_{\xi}(h) + \mathcal{R}^{(2)}_\Lambda(h).\) Hence the remaining contribution to the \(\lambda^2\)-coefficient is \[\mathcal{E}^{(2)}_\Lambda(h) := \sum_{n\ge1}\delta_n^{[2]}(h).\] Each \(\delta_n^{[2]}(h)\) is \(D_\Lambda\)-diagonal, and therefore so is \(\mathcal{E}^{(2)}_\Lambda(h)\). We now estimate this series. We use the one-step estimates with \(\kappa=0\). Choose \(r_0\in(0,1]\) so small that the LS/SW contraction estimates apply uniformly for \(|\lambda|\le r_0\). By ?? , \[\|\delta_n(h;\lambda)\|_0 \le C_\ast(d) \frac{\|(B_n(h;\lambda))^{\rm off}\|_0^2}{U}.\] For \(n\ge1\), the contraction estimate ?? gives \[\|(B_n(h;\lambda))^{\rm off}\|_0 \le q^{n-1} \|(B_1(h;\lambda))^{\rm off}\|_0 .\]

It remains to bound the first off-diagonal remainder. Put \(S:=\mathcal{I}_h(V).\) Since \(S_0(\lambda)=\lambda S\) and \(\mathrm{ad}_S(H_0(h))=-V,\) the first LS/SW step cancels the leading off-diagonal term \(\lambda V\). More precisely, after expanding by BCH and extracting the terms of order at most \(\lambda^2\), we get \[(B_1(h;\lambda))^{\rm off} = \lambda \bigl( \mathrm{ad}_S(T_\Lambda^{(0)}) \bigr) + R_1(h;\lambda),\] where \[R_1(h;\lambda) = \left[ \lambda^2 \left( \frac{1}{2}\mathrm{ad}_S(V) + \frac{1}{2}\mathrm{ad}_S^2(T_\Lambda^{(0)}) \right) + R_{\ge3}(h;\lambda) \right]^{\rm off}.\] Here \(R_{\ge3}(h;\lambda)\) denotes the part of the BCH expansion of order at least \(\lambda^3\). To see this, the \(H_0(h)\)-tail is first rewritten using \(\mathrm{ad}_S(H_0(h))=-V.\) Thus, for the \(H_0(h)\)-part, we have \(\mathrm{ad}_S^r(H_0(h)) = -\mathrm{ad}_S^{r-1}(V)\, (r\ge1),\) so no norm of \(H_0(h)\) appears in the tail estimates.

By Lemma 36 and the hopping bounds, \[\|S\|_0 = \|\mathcal{I}_h(V)\|_0 \le C(d)\frac{|t|}{U}, \qquad \|V\|_0+\|T_\Lambda^{(0)}\|_0 \le C(d)|t|.\] Using the interaction commutator bound Lemma 11, we get \[\|\mathrm{ad}_S(T_\Lambda^{(0)})\|_0 \le C(d)\frac{|t|^2}{U}, \qquad \|\mathrm{ad}_S(V)\|_0 \le C(d)\frac{|t|^2}{U}, \qquad \|\mathrm{ad}_S^2(T_\Lambda^{(0)})\|_0 \le C(d)\frac{|t|^3}{U^2}.\] After increasing the strong-coupling threshold if necessary, \(\|\mathrm{ad}_S^2(T_\Lambda^{(0)})\|_0 \le C(d)\frac{|t|^2}{U}.\)

It remains to estimate \(R_{\ge3}(h;\lambda)\). Since the terms up to order \(\lambda^2\) have already been extracted, the BCH tail is a shifted tail beginning at order \(\lambda^3\). Applying Lemma 12 in this shifted form, together with Lemma 11, gives \[\|R_{\ge3}(h;\lambda)\|_0 \le C(d)|\lambda|^3 \left( \|S\|_0^2\|V\|_0 + \|S\|_0^3\|T_\Lambda^{(0)}\|_0 \right).\] Using the bounds above and \(|\lambda|\le r_0\le1\), this implies \(\|R_{\ge3}(h;\lambda)\|_0 \le C(d)|\lambda|^2\frac{|t|^2}{U}.\) Therefore \[\|R_1(h;\lambda)\|_0 \le C(d)|\lambda|^2\frac{|t|^2}{U}\] uniformly for \(|h|\le h_0\) and \(|\lambda|\le r_0\).

Combining the leading off-diagonal term with this remainder, we obtain \[\|(B_1(h;\lambda))^{\rm off}\|_0 \le C(d)|\lambda|\frac{|t|^2}{U}.\] Consequently, for \(n\ge1\), \[\|\delta_n(h;\lambda)\|_0 \le C(d)q^{2(n-1)} |\lambda|^2 \frac{|t|^4}{U^3}.\]

We now use the analytic dependence on the auxiliary parameter. Although \(\lambda\) is real in the original deformation, we temporarily regard \(\lambda\) as a complex parameter in order to extract Taylor coefficients. The operations entering the LS/SW construction in this argument, namely the \(D\)-grading, the homological map \(\mathcal{I}_h\), commutators, and the BCH series, are complex-linear or multilinear operations on the complex Banach space of interactions. Moreover, the convergence estimates used above are norm estimates depending only on \(|\lambda|\).

Therefore, after decreasing \(r_0>0\) if necessary, the interactions \(\delta_n(h;\lambda)\) extend to Banach-valued holomorphic functions of \(\lambda\) on \(|\lambda|<r_0\), with the same bounds uniformly on \(|\lambda|\le r_0\). In this coefficient estimate we do not use self-adjointness of \(H_\Lambda(h;\lambda)\) or unitarity of the conjugations.

By Cauchy’s estimate for Banach-valued holomorphic functions, applied on the circle \(|\lambda|=r_0\), we obtain \[\|\delta_n^{[2]}(h)\|_0 \le r_0^{-2} \sup_{|\lambda|=r_0} \|\delta_n(h;\lambda)\|_0 \le C(d)q^{2(n-1)} \frac{|t|^4}{U^3}.\] Summing over \(n\ge1\), we get \[\|\mathcal{E}^{(2)}_\Lambda(h)\|_0 \le C(d) \frac{|t|^4}{U^3} \sum_{n\ge1}q^{2(n-1)} \le C_{E,0}(d)\frac{|t|^4}{U^3}.\] This proves the desired estimate for \(\mathcal{E}^{(2)}_\Lambda(h)\), uniformly in \(\Lambda\) and \(|h|\le h_0\).

Soft \(0\)-norm bound for \(\mathcal{R}^{(2)}_\Lambda(h)\). By Lemma 13, the \(D_\Lambda\)-diagonal extraction is contractive in \(\|\cdot\|_0\). Hence \[\|\mathcal{R}^{(2)}_\Lambda(h)\|_0 \le \frac{1}{2} \left\| \mathrm{ad}_{\mathcal{I}_h(V)} \left( \mathrm{ad}_{\mathcal{I}_h(V)}(T_\Lambda^{(0)}) \right) \right\|_0 .\] Applying the interaction commutator bound Lemma 11 twice, with \(\kappa=0\), gives \[\|\mathcal{R}^{(2)}_\Lambda(h)\|_0 \le C(d) \|\mathcal{I}_h(V)\|_0^2 \|T_\Lambda^{(0)}\|_0 .\] By Lemma 36, together with the large-\(U\) convention and the hopping bounds, we have uniformly in \(\Lambda\) and \(|h|\le h_0\), \(\|\mathcal{I}_h(V)\|_0 \le C(d)\frac{|t|}{U}\) and \(\|T_\Lambda^{(0)}\|_0 \le C(d)|t|.\) Therefore \(\|\mathcal{R}^{(2)}_\Lambda(h)\|_0 \le C_{R,0}(d)\frac{|t|^3}{U^2},\) after increasing \(U_\ast\) if necessary. This bound is uniform in \(\Lambda\) and \(|h|\le h_0\).

Combining the decomposition above with the estimates for \(\mathcal{R}^{(2)}_\Lambda(h)\) and \(\mathcal{E}^{(2)}_\Lambda(h)\) completes the proof. 0◻

9 Spin representation and two-site computation↩︎

9.1 Cross-bond terms vanish on the \(P\)-block↩︎

9.1.0.1 Bond hopping terms.

For a nearest-neighbour bond \(e=\langle x,y\rangle\in\mathscr B_\Lambda\), we set \[T_e := -t \sum_{\sigma\in\{\uparrow,\downarrow\}} \left( c_{x\sigma}^{*}c_{y\sigma} + c_{y\sigma}^{*}c_{x\sigma} \right).\] Thus \(T_\Lambda=\sum_{e\in\mathscr B_\Lambda}T_e.\) We use the \(D_\Lambda\)-grading convention from Subsection 2.1, and write \((T_e)^{\rm off} := \sum_{k\neq0}(T_e)^{(k)}.\)

Lemma 40 (Cross-bond terms vanish after diagonal projection and \(P\)-compression). Let \(P:=\mathbb{1}_{\{D_\Lambda=0\}}\restriction_{\mathcal{H}_\Lambda^{\rm hf}},\) and let \(e,e'\in\mathscr B_\Lambda\) be distinct nearest-neighbour bonds. Then, for every \(|h|\le h_0\), \[\label{eq:cross-bond-vanish} P \left( \mathrm{ad}_{ \mathcal{I}_h((T_{e})^{\rm off})} \left( (T_{e'})^{\rm off} \right) \right)^{\rm diag} P = 0.\qquad{(23)}\]

Proof. Since \(P=P_0\) is the \(D_\Lambda\)-spectral projection at eigenvalue \(0\), one has \(PX^{\rm diag}P=PXP\) for every operator \(X\). Hence it is enough to prove \[\label{eq:cross-bond-vanish-reduced} P \left( \mathrm{ad}_{ \mathcal{I}_h((T_{e})^{\rm off})} \left( (T_{e'})^{\rm off} \right) \right) P = 0.\tag{50}\]

Write \(e=\{x,y\}\) and \(e'=\{u,v\}.\) By Lemma 36, the operator \(\mathcal{I}_h((T_e)^{\rm off})\) is supported on the bond \(e\), and it is \(D_\Lambda\)-off-diagonal. In particular, \(P\mathcal{I}_h((T_e)^{\rm off})P=0.\)

We first prove \[\label{eq:cross-term-1} P (T_{e'})^{\rm off}\mathcal{I}_h((T_e)^{\rm off})P=0.\tag{51}\] Let \(\psi\in\operatorname{ran}(P)\). Since \(\psi\) is in the singly occupied sector, an off-diagonal hop on the bond \(e\) creates a hole–doublon pair on the two endpoints of \(e\). The map \(\mathcal{I}_h\) only changes the coefficients of the corresponding \(D_\Lambda\)-graded components and preserves the support. Hence every occupation-number basis component of \(\mathcal{I}_h((T_e)^{\rm off})\psi\) has charge defects at the two endpoints of \(e\).

Because \(e\neq e'\), there exists an endpoint \(w\in e\) which is not an endpoint of \(e'\). The operator \((T_{e'})^{\rm off}\) acts only on the endpoints of \(e'\), and therefore it cannot change the occupation at \(w\). Thus the charge defect at \(w\) remains after applying \((T_{e'})^{\rm off}\). Consequently \(( T_{e'})^{\rm off}\mathcal{I}_h((T_e)^{\rm off})\psi \perp \operatorname{ran}(P),\) which proves 51 .

The same argument with the two bonds interchanged gives \[\label{eq:cross-term-2} P\mathcal{I}_h((T_e)^{\rm off})(T_{e'})^{\rm off}P=0.\tag{52}\] Indeed, starting from \(\operatorname{ran}(P)\), the operator \((T_{e'})^{\rm off}\) creates a hole–doublon pair on \(e'\), and since \(e\neq e'\), at least one endpoint of \(e'\) is not touched by \(\mathcal{I}_h((T_e)^{\rm off})\).

Subtracting 52 from 51 gives 50 , and hence ?? . ◻

9.2 Two-site computation↩︎

Lemma 41 (Two-site computation on a bond). Assume \(|h|\le h_0\) and \(U>h_0\). Fix a nearest-neighbour bond \(e=\{x,y\}\in\mathscr B_\Lambda\), and label its endpoints so that \(\eta_x=+1\) and \(\eta_y=-1.\) On \(P\mathcal{H}^{\rm hf}_\Lambda\), with \(P=\mathbb{1}_{\{D_\Lambda=0\}}\restriction_{\mathcal{H}_\Lambda^{\rm hf}},\) define \[X_{xy}(h) := P\frac{1}{2} \left( \mathrm{ad}_{ \mathcal{I}_h((T_{e})^{\rm off}) }( (T_e)^{\rm off} ) \right)^{\rm diag} P.\] Then \(X_{xy}(h)\) is supported on \(\{x,y\}\). Under the spin identification \(\mathcal{U}_\Lambda:P\mathcal{H}^{\rm hf}_\Lambda\to\mathcal{H}^{\rm spin}_\Lambda,\) one has \[\label{eq:two-site-computation-formula} \mathcal{U}_\Lambda X_{xy}(h)\mathcal{U}_\Lambda^\ast = -J_{xy}(h)B_{xy} + b_{xy}(h)M_e^{\rm spin},\qquad{(24)}\] where \(M_e^{\rm spin}:=\eta_xS_x^{(3)}+\eta_yS_y^{(3)} = S_x^{(3)}-S_y^{(3)}\) on \(\mathcal{H}_\Lambda^{\rm spin}\), and \[\label{eq:two-site-coeffs} J_{xy}(h):=\frac{4t^2U}{U^2-h^2}, \qquad b_{xy}(h):=\frac{2ht^2}{U^2-h^2}.\qquad{(25)}\] In particular, \[J_{xy}(0)=\frac{4t^2}{U}, \qquad b_{xy}(0)=0.\]

Proof. By Lemma 36, the operator \(\mathcal{I}_h((T_e)^{\rm off})\) is supported in \(\{x,y\}\). Hence \(X_{xy}(h)\) is also supported in \(\{x,y\}\).

Write \(H_0(h):=UD_\Lambda-hM_\Lambda.\) On operators supported in \(\{x,y\}\), the commutator with \(H_0(h)\) reduces to the commutator with the two-site operator \[H_{0,e}(h):=UD_e-hM_e, \qquad D_e:=n_{x\uparrow}n_{x\downarrow} +n_{y\uparrow}n_{y\downarrow},\qquad M_e:=S_x^{(3)}-S_y^{(3)}.\] Indeed, the part of \(H_0(h)\) supported outside \(e\) commutes with \((T_e)^{\rm off}\) and with the local inverse generated from it. Thus the calculation may be performed on the two-site \(N=2\) subspace.

Two-site basis and fermionic sign convention. We use \[|\sigma\tau\rangle := c_{x\sigma}^\ast c_{y\tau}^\ast|0\rangle, \qquad \sigma,\tau\in\{\uparrow,\downarrow\},\] and \[|d_x\rangle := c_{x\uparrow}^\ast c_{x\downarrow}^\ast|0\rangle, \qquad |d_y\rangle := c_{y\uparrow}^\ast c_{y\downarrow}^\ast|0\rangle.\] Then \(\operatorname{ran}(P)\) is spanned by \(|\!\uparrow\uparrow \rangle,\, |\!\downarrow\uparrow\rangle,\, |\!\uparrow\downarrow\rangle,\, |\!\downarrow\downarrow\rangle,\) and the orthogonal complement of \(\operatorname{ran}(P)\) in the two-site \(N=2\) sector is \(\operatorname{span}\{|d_x\rangle,|d_y\rangle\}.\) The signs below are with respect to this convention.

On \(\operatorname{ran}(P)\), one has \(D_e=0\), hence \(H_{0,e}(h)=-hM_e\). On \(\operatorname{span}\{|d_x\rangle,|d_y\rangle\}\), one has \(D_e=1\) and \(M_e=0\), hence \(H_{0,e}(h)=U\).

Moreover, \((T_e)^{\rm off}\) maps \(\operatorname{ran}(P)\) into \(\operatorname{span}\{|d_x\rangle,|d_y\rangle\}\) and annihilates \(|\!\uparrow\uparrow\rangle\) and \(|\!\downarrow\downarrow\rangle\). A direct CAR computation gives \[\label{eq:two-site-hop-action} (T_e)^{\rm off}|\!\uparrow\downarrow\rangle = -t(|d_x\rangle+|d_y\rangle), \qquad (T_e)^{\rm off}|\!\downarrow\uparrow\rangle = t(|d_x\rangle+|d_y\rangle),\tag{53}\] and \((T_e)^{\rm off}|\!\uparrow\uparrow\rangle = (T_e)^{\rm off}|\!\downarrow\downarrow\rangle = 0.\) The reverse actions are \[\label{eq:two-site-hop-action-reverse} (T_e)^{\rm off}|d_x\rangle = t\bigl(|\!\downarrow\uparrow\rangle-|\!\uparrow\downarrow\rangle\bigr), \qquad (T_e)^{\rm off}|d_y\rangle = t\bigl(|\!\downarrow\uparrow\rangle-|\!\uparrow\downarrow\rangle\bigr).\tag{54}\]

Since \(H_{0,e}(h)\) is diagonal in the above basis, the defining relation \(\mathrm{ad}_{H_{0,e}(h)}(\mathcal{I}_h(A))=A\) gives, for eigenvectors \(|\phi\rangle,|\psi\rangle\) with eigenvalues \(E_\phi,E_\psi\), \[\label{eq:energy-difference-division} \langle\psi|\mathcal{I}_h(A)|\phi\rangle = \frac{\langle\psi|A|\phi\rangle}{E_\psi-E_\phi}, \qquad E_\psi\neq E_\phi.\tag{55}\] Applying this to \(A=(T_e)^{\rm off}\), we use \(M_e|\!\uparrow\downarrow\rangle=|\!\uparrow\downarrow\rangle\) and \(M_e|\!\downarrow\uparrow\rangle=-|\!\downarrow\uparrow\rangle.\) Thus \[H_{0,e}(h)|\!\uparrow\downarrow\rangle = -h|\!\uparrow\downarrow\rangle, \qquad H_{0,e}(h)|\!\downarrow\uparrow\rangle = h|\!\downarrow\uparrow\rangle,\] whereas \[H_{0,e}(h)|d_x\rangle=U|d_x\rangle, \qquad H_{0,e}(h)|d_y\rangle=U|d_y\rangle.\] Hence the relevant energy differences are \(U+h\) and \(U-h\), and 5355 give \[\label{eq:two-site-Ih-action} \mathcal{I}_h((T_e)^{\rm off})|\!\uparrow\downarrow\rangle = -\frac{t}{U+h}(|d_x\rangle+|d_y\rangle), \qquad \mathcal{I}_h((T_e)^{\rm off})|\!\downarrow\uparrow\rangle = \frac{t}{U-h}(|d_x\rangle+|d_y\rangle).\tag{56}\] Similarly, using 54 , \[\label{eq:two-site-Ih-action-reverse} \mathcal{I}_h((T_e)^{\rm off})|d_x\rangle = \frac{t}{U+h}|\!\uparrow\downarrow\rangle - \frac{t}{U-h}|\!\downarrow\uparrow\rangle,\tag{57}\] and the same formula holds with \(|d_x\rangle\) replaced by \(|d_y\rangle\). Also, \(\mathcal{I}_h((T_e)^{\rm off})|\!\uparrow\uparrow\rangle = \mathcal{I}_h((T_e)^{\rm off})|\!\downarrow\downarrow\rangle = 0,\) because \((T_e)^{\rm off}\) has no off-diagonal matrix elements from these two states.

Using 5356 and \(PX^{\rm diag}P=PXP\), we compute the restriction of \[X_{xy}(h) = P\frac{1}{2}\mathrm{ad}_{\mathcal{I}_h((T_e)^{\rm off})}((T_e)^{\rm off})P\] to \(\operatorname{ran}(P)\). In the ordered basis \((|\!\uparrow\uparrow\rangle, |\!\downarrow\uparrow\rangle, |\!\uparrow\downarrow\rangle, |\!\downarrow\downarrow\rangle),\) this yields \[\mathcal{U}_\Lambda X_{xy}(h)\mathcal{U}_\Lambda^\ast = \begin{pmatrix} 0 & 0 & 0 & 0\\ 0 & -\frac{2t^2}{U-h} & \frac{2Ut^2}{(U-h)(U+h)} & 0\\ 0 & \frac{2Ut^2}{(U-h)(U+h)} & -\frac{2t^2}{U+h} & 0\\ 0 & 0 & 0 & 0 \end{pmatrix}.\] On the other hand, in the same basis, \[B_{xy} = \begin{pmatrix} 0 & 0 & 0 & 0\\ 0 & \frac{1}{2} & -\frac{1}{2} & 0\\ 0 & -\frac{1}{2} & \frac{1}{2} & 0\\ 0 & 0 & 0 & 0 \end{pmatrix}, \qquad M_e^{\rm spin} = \begin{pmatrix} 0 & 0 & 0 & 0\\ 0 & -1 & 0 & 0\\ 0 & 0 & 1 & 0\\ 0 & 0 & 0 & 0 \end{pmatrix}.\] Comparing the off-diagonal entries gives \(J_{xy}(h) = \frac{4t^2U}{U^2-h^2}.\) Comparing, for instance, the \((2,2)\)-entries gives \(-\frac{J_{xy}(h)}{2}-b_{xy}(h) = -\frac{2t^2}{U-h},\) and hence \(b_{xy}(h) = \frac{2ht^2}{U^2-h^2}.\) Finally, since both \(B_{xy}\) and \(M_e^{\rm spin}\) have vanishing \((1,1)\)- and \((4,4)\)-entries, no multiple of the identity appears. This proves ?? . ◻

9.3 Proof of Proposition 22↩︎

Proof of Proposition 22. Recall from Lemma 20 that \[H_\Lambda^{(2)}(h) = \frac{1}{2}\left( \mathrm{ad}_{ \mathcal{I}_h\bigl((T_\Lambda)^{\rm off}\bigr) } \left( (T_\Lambda)^{\rm off} \right) \right)^{\rm diag} \qquad (|h|\le h_0).\] Note \((T_\Lambda)^{\rm off} = \sum_{e\in\mathscr B_\Lambda}(T_e)^{\rm off}.\) By the support preservation and linearity of \(\mathcal{I}_h\), \[\mathcal{I}_h\bigl((T_\Lambda)^{\rm off}\bigr) = \sum_{e\in\mathscr B_\Lambda} \mathcal{I}_h((T_e)^{\rm off}).\] Expanding the commutator gives \[\mathrm{ad}_{ \mathcal{I}_h\left((T_\Lambda)^{\rm off}\right) } \left( (T_\Lambda)^{\rm off} \right) = \sum_{e\in\mathscr B_\Lambda}\mathrm{ad}_{ \mathcal{I}_h\left((T_e)^{\rm off}\right) } \left( (T_e)^{\rm off} \right) + \sum_{\substack{e,e'\in\mathscr B_\Lambda\\ e\neq e'}} \mathrm{ad}_{ \mathcal{I}_h\left((T_e)^{\rm off}\right) } \left( (T_{e\rq{}})^{\rm off} \right).\] Hence, by Lemma 40, \[\label{eq:P-H2-sum-bonds} P H_\Lambda^{(2)}(h)P = \sum_{e\in\mathscr B_\Lambda} P \frac{1}{2} \left( \mathrm{ad}_{ \mathcal{I}_h((T_e)^{\rm off})}( (T_e)^{\rm off}) \right)^{\rm diag} P .\tag{58}\]

For each bond \(e=\{x,y\}\in\mathscr B_\Lambda\), label its endpoints so that \(\eta_x=+1\) and \(\eta_y=-1.\) By Lemma 41, \[\mathcal{U}_\Lambda P \frac{1}{2} \left( \mathrm{ad}_{ \mathcal{I}_h((T_e)^{\rm off})}( (T_e)^{\rm off}) \right)^{\rm diag} P \mathcal{U}_\Lambda^\ast = -J(h)B_{xy} + b(h)\bigl(\eta_x S_x^{(3)}+\eta_y S_y^{(3)}\bigr),\] where \(J(h)=\frac{4t^2U}{U^2-h^2}\) and \(b(h)=\frac{2ht^2}{U^2-h^2}.\) Summing over bonds in 58 , with this endpoint labelling on each bond, we obtain \[\mathcal{U}_\Lambda P H_\Lambda^{(2)}(h)P \mathcal{U}_\Lambda^\ast = -J(h) \sum_{\{x,y\}\in\mathscr B_\Lambda}B_{xy} + b(h) \sum_{\{x,y\}\in\mathscr B_\Lambda} \bigl(\eta_x S_x^{(3)}+\eta_y S_y^{(3)}\bigr).\] Since each site \(x\) appears as an endpoint of exactly \(2d\) bonds, \(\sum_{\{x,y\}\in\mathscr B_\Lambda} \bigl(\eta_x S_x^{(3)}+\eta_y S_y^{(3)}\bigr) = 2d M_\Lambda^{\rm spin}.\) Therefore, using 19 , we have \(\mathcal{U}_\Lambda P H_\Lambda^{(2)}(h)P \mathcal{U}_\Lambda^\ast = H_\Lambda^{\rm Heis}(J(h)) + 2d b(h) M_\Lambda^{\rm spin}.\)

Finally, using \(\mathcal{U}_\Lambda P M_\Lambda P\mathcal{U}_\Lambda^\ast = M_\Lambda^{\rm spin},\) we get \[\mathcal{U}_\Lambda P\bigl(-hM_\Lambda+H_\Lambda^{(2)}(h)\bigr)P \mathcal{U}_\Lambda^\ast = H_\Lambda^{\rm Heis}(J(h)) - \bigl(h-2d b(h)\bigr)M_\Lambda^{\rm spin}.\] Thus \(\mathcal{U}_\Lambda P\bigl(-hM_\Lambda+H_\Lambda^{(2)}(h)\bigr)P \mathcal{U}_\Lambda^\ast = H_\Lambda^{\rm Heis}\bigl(J(h),h_{\rm eff}(h)\bigr),\) where \(h_{\rm eff}(h) := h-2d b(h) = h-\frac{4dht^2}{U^2-h^2}.\) This proves ?? . ◻

10 \(P\)-block remainder estimates↩︎

This appendix contains the estimates used in Section 5. The goal is to control, on fixed positive-field windows, the difference between the effective \(P\)-block Hamiltonian and the Heisenberg reference Hamiltonian.

10.1 Parameter mismatch with the Heisenberg reference model↩︎

Proof of Proposition 24. Recall that \(J(h)=\frac{4t^2U}{U^2-h^2}\) and \(J_0(U)=\frac{4t^2}{U}.\) Hence \(J(h)-J_0(U) = \frac{4t^2h^2}{U(U^2-h^2)}.\) If \(U>2h_0\) and \(|h|\le h_0\), then \(U^2-h^2\ge \frac{3}{4} U^2.\) Therefore \[\label{eq:J-J0-bound} |J(h)-J_0(U)| \le C(h_0,t)\frac{1}{U^3}.\tag{59}\] Similarly, \(h_{\rm eff}(h)-h = -\frac{4dht^2}{U^2-h^2},\) and hence \[\label{eq:heff-h-bound} |h_{\rm eff}(h)-h| \le C(d,h_0,t)\frac{1}{U^2}.\tag{60}\]

By definition, \(G_{\Lambda,U}(h) = \bigl(J(h)-J_0(U)\bigr) \sum_{\{x,y\}\in\mathscr B_\Lambda} \left( \boldsymbol{S}_x\cdot\boldsymbol{S}_y-\frac{1}{4} \right) - \bigl(h_{\rm eff}(h)-h\bigr)M_\Lambda^{\rm spin}.\) We regard this as an interaction on the spin system. Since \(\left\| \boldsymbol{S}_x\cdot\boldsymbol{S}_y-\frac{1}{4} \right\| \le 1\) and each site belongs to \(2d\) nearest-neighbour bonds, the bond part satisfies \(\left\| \bigl(J(h)-J_0(U)\bigr) \sum_{\{x,y\}\in\mathscr B_\Lambda} \left( \boldsymbol{S}_x\cdot\boldsymbol{S}_y-\frac{1}{4} \right) \right\|_0 \le 2d\,|J(h)-J_0(U)|.\) Moreover, \(\|S_x^{(3)}\|=\frac{1}{2},\) and therefore the field part satisfies \(\left\| \bigl(h_{\rm eff}(h)-h\bigr)M_\Lambda^{\rm spin} \right\|_0 \le \frac{1}{2} |h_{\rm eff}(h)-h|.\) Combining this with 59 and 60 , we obtain \[\sup_{|h|\le h_0} \|G_{\Lambda,U}(h)\|_0 \le C(d,h_0,t)\frac{1}{U^2}.\]

It remains to prove the \(h\)-derivative estimate. Differentiating \(J(h)\), we get \(J'(h) = \frac{8t^2Uh}{(U^2-h^2)^2}.\) Thus, for \(U>2h_0\), \[\label{eq:J-prime-bound} \sup_{|h|\le h_0}|J'(h)| \le C(h_0,t)\frac{1}{U^3}.\tag{61}\] Next, \(\partial_h(h_{\rm eff}(h)-h) = -4dt^2 \frac{U^2+h^2}{(U^2-h^2)^2}.\) Hence \[\label{eq:heff-minus-h-prime-bound} \sup_{|h|\le h_0} |\partial_h(h_{\rm eff}(h)-h)| \le C(d,h_0,t)\frac{1}{U^2}.\tag{62}\] Applying the same interaction-norm estimates to \(\partial_hG_{\Lambda,U}(h)\), and using 61 and 62 , gives \[\sup_{|h|\le h_0} \|\partial_hG_{\Lambda,U}(h)\|_0 \le C(d,h_0,t)\frac{1}{U^2}.\] This proves the proposition. ◻

10.2 Uniform \(C^1\) bound on the \(P\)-block remainder↩︎

We prove Proposition 25. Recall that \[R_{P,\Lambda}(h) = P\bigl(\Delta_\Lambda(h)-H_\Lambda^{(2)}(h)\bigr)P, \qquad \mathcal{R}_{P,\Lambda}(h) = \mathcal{U}_\Lambda R_{P,\Lambda}(h) \mathcal{U}_\Lambda^\ast .\] Since \(\mathcal{U}_\Lambda\) is unitary, it suffices to estimate \(R_{P,\Lambda}(h)\).

Lemma 42 (Decomposition of the \(P\)-block remainder). Recall the second-order comparison terms \(\mathcal{R}_\Lambda^{(2)}(h)\) and \(\mathcal{E}_\Lambda^{(2)}(h)\) from Lemma 21. Define \[\mathcal{K}_\Lambda^{(\ge3)}(h) := \Delta_\Lambda(h;\lambda)\big|_{\lambda=1} - (\Delta_\Lambda)^{[2]}_\lambda(h).\] Then \[R_{P,\Lambda}(h) = P\mathcal{R}_\Lambda^{(2)}(h)P + P\mathcal{E}_\Lambda^{(2)}(h)P + P\mathcal{K}_\Lambda^{(\ge3)}(h)P.\]

Proof. At the physical endpoint the two deformations give the same LS/SW correction: \(\Delta_\Lambda(h) = \Delta_\Lambda(h;\lambda)\big|_{\lambda=1} = \Delta_\Lambda(h;\xi)\big|_{\xi=1}.\) By definition, \(H_\Lambda^{(2)}(h) = (\Delta_\Lambda)^{[2]}_\xi(h),\) and hence \[R_{P,\Lambda}(h) = P \left( \Delta_\Lambda(h) - (\Delta_\Lambda)^{[2]}_\xi(h) \right) P.\] Using the definition of \(\mathcal{K}_\Lambda^{(\ge3)}(h)\), we write \(\Delta_\Lambda(h) = \Delta_\Lambda(h;\lambda)\big|_{\lambda=1} = (\Delta_\Lambda)^{[2]}_\lambda(h) + \mathcal{K}_\Lambda^{(\ge3)}(h).\) Here the notation \((\ge3)\) refers to the Taylor expansion in the auxiliary parameter \(\lambda\): after subtracting the second-order coefficient, the remaining terms start at order three.

By Lemma 21, \((\Delta_\Lambda)^{[2]}_\lambda(h) = (\Delta_\Lambda)^{[2]}_\xi(h) + \mathcal{R}_\Lambda^{(2)}(h) + \mathcal{E}_\Lambda^{(2)}(h).\) Substituting this identity into the previous display gives \[\Delta_\Lambda(h) - (\Delta_\Lambda)^{[2]}_\xi(h) = \mathcal{R}_\Lambda^{(2)}(h) + \mathcal{E}_\Lambda^{(2)}(h) + \mathcal{K}_\Lambda^{(\ge3)}(h).\] Compressing by \(P\) on both sides proves the claimed decomposition. ◻

10.2.0.1 Later-step notation in the \(\lambda\)-scheme.

For the auxiliary \(\lambda\)-deformation, write the LS/SW iterates as \[H^{(n)}(h;\lambda) = H_{\rm d}(h)+B_n(h;\lambda), \qquad H_{\rm d}(h):=UD_\Lambda-hM_\Lambda .\] We decompose \[B_n(h;\lambda) = D_n(h;\lambda)+F_n(h;\lambda), \qquad D_n(h;\lambda):=B_n(h;\lambda)^{\rm diag}, \qquad F_n(h;\lambda):=B_n(h;\lambda)^{\rm off}.\] Thus \(D_n(h;\lambda)\) is \(D_\Lambda\)-diagonal and \(F_n(h;\lambda)\) is \(D_\Lambda\)-off-diagonal. The \(n\)-th diagonal increment is \[\delta_n(h;\lambda) := D_{n+1}(h;\lambda)-D_n(h;\lambda) = B_{n+1}(h;\lambda)^{\rm diag} - B_n(h;\lambda)^{\rm diag}.\]

Lemma 43 (Later-step bounds in the \(\lambda\)-scheme). Assume the hypotheses of Corollary 17 and the local \(h\)-derivative bounds for \(\mathcal{I}_h\) from Lemmas 36 and 37. After increasing the strong-coupling threshold if necessary, there exist \(q\in(0,1)\) and \(C<\infty\), independent of \(n,\Lambda,h,\lambda\), such that, for all \(n\ge1\), \(|h|\le h_0\), and \(|\lambda|\le1\), \[\begin{align} \|D_n(h;\lambda)\|_\kappa &\le C, \label{eq:lambda-Dn-bound}\\ \|F_n(h;\lambda)\|_\kappa &\le Cq^{n-1}|\lambda|\frac{|t|^2}{U}, \label{eq:lambda-Fn-bound}\\ \|\partial_hD_n(h;\lambda)\|_\kappa &\le C, \label{eq:lambda-dDn-bound}\\ \|\partial_hF_n(h;\lambda)\|_\kappa &\le Cq^{n-1}|\lambda|\frac{|t|^2}{U^2}. \label{eq:lambda-dFn-bound} \end{align}\] {#eq: sublabel=eq:eq:lambda-Dn-bound,eq:eq:lambda-Fn-bound,eq:eq:lambda-dDn-bound,eq:eq:lambda-dFn-bound}

Proof. We first estimate the first LS/SW step. Set \(V:=(T_\Lambda)^{\rm off}\) and \(S:=\mathcal{I}_h(V).\) In the auxiliary \(\lambda\)-scheme, \(B_0(h;\lambda)=T_\Lambda^{(0)}+\lambda V\) and \(S_0(h;\lambda)=\lambda S.\) Moreover, \(\mathrm{ad}_S(H_{\rm d}(h))=-V\) with \(H_{\rm d}(h):=UD_\Lambda-hM_\Lambda.\) We expand the first conjugation: \[\begin{align} e^{\lambda S} \bigl( H_{\rm d}(h)+T_\Lambda^{(0)}+\lambda V \bigr) e^{-\lambda S} &= H_{\rm d}(h)+T_\Lambda^{(0)}+\lambda V + \sum_{r\ge1}\frac{\lambda^r}{r!} \mathrm{ad}_S^{\,r}(H_{\rm d}(h)) \\ &\quad+ \sum_{r\ge1}\frac{\lambda^r}{r!} \mathrm{ad}_S^{\,r}(T_\Lambda^{(0)}) + \sum_{r\ge1}\frac{\lambda^{r+1}}{r!} \mathrm{ad}_S^{\,r}(V). \end{align}\] Since \(\mathrm{ad}_S^{\,r}(H_{\rm d}(h)) = -\mathrm{ad}_S^{\,r-1}(V)\, (r\ge1),\) the term \(\lambda V\) is cancelled by the \(r=1\) contribution from \(H_{\rm d}(h)\). Thus the remaining part after the first step is \[\begin{align} B_1(h;\lambda) &= T_\Lambda^{(0)} + \sum_{r\ge1}\frac{\lambda^r}{r!} \mathrm{ad}_S^{\,r}(T_\Lambda^{(0)}) + \sum_{m\ge1} \frac{m}{(m+1)!}\lambda^{m+1} \mathrm{ad}_S^{\,m}(V). \end{align}\] Here the first off-diagonal contribution is \(\lambda\,\mathrm{ad}_S(T_\Lambda^{(0)}),\) because \(T_\Lambda^{(0)}\) is \(D_\Lambda\)-diagonal and \(S\) is \(D_\Lambda\)-off-diagonal. The remaining terms are BCH tails containing at least two powers of \(\lambda\), or at least two occurrences of \(S\). More precisely, using Lemmas 11 and 12, together with Lemma 36, we have \(\|S\|_\kappa\le C\frac{|t|}{U}\) and \(\|V\|_\kappa+\|T_\Lambda^{(0)}\|_\kappa\le C|t|.\) Therefore, for \(|\lambda|\le1\), \[\|F_1(h;\lambda)\|_\kappa = \|B_1(h;\lambda)^{\rm off}\|_\kappa \le C|\lambda|\,\|S\|_\kappa\|T_\Lambda^{(0)}\|_\kappa + C|\lambda|\,\|S\|_\kappa\|V\|_\kappa \le C|\lambda|\frac{|t|^2}{U}.\] In the second term we used \(|\lambda|^{m+1}\le |\lambda|\) for \(|\lambda|\le1\), and absorbed the remaining summable BCH series into the constant.

The \(h\)-derivative of \(F_1\) is estimated in the same way as in the proof of Lemma 39. The operators \(V\) and \(T_\Lambda^{(0)}\) are independent of \(h\), and the \(H_{\rm d}\)-tail has already been rewritten in terms of \(V\). Thus the derivative only hits \(S=\mathcal{I}_h(V)\). By Lemma 37, \(\|\partial_hS\|_\kappa \le C\frac{|t|}{U^2}.\) Differentiating the displayed BCH expression for \(B_1(h;\lambda)\), and using the same BCH summability bounds as in Lemma 39, gives \[\|\partial_hF_1(h;\lambda)\|_\kappa \le C|\lambda|\,\|\partial_hS\|_\kappa \left( \|T_\Lambda^{(0)}\|_\kappa+\|V\|_\kappa \right) \le C|\lambda|\frac{|t|^2}{U^2}.\] The diagonal part \(D_1(h;\lambda)=B_1(h;\lambda)^{\rm diag}\) is bounded uniformly because \(T_\Lambda^{(0)}\) is bounded in \(\|\cdot\|_\kappa\), and the diagonal increment of the first step is bounded by the one-step diagonal estimate. The differentiated bound follows from Lemma 39. Hence \(\|D_1(h;\lambda)\|_\kappa\le C,\) and \(\|\partial_hD_1(h;\lambda)\|_\kappa\le C.\)

We now propagate the estimates. The off-diagonal contraction estimate ?? , applied from step \(1\) onward, gives \[\|F_n(h;\lambda)\|_\kappa \le q^{n-1}\|F_1(h;\lambda)\|_\kappa \le Cq^{n-1}|\lambda|\frac{|t|^2}{U}, \qquad n\ge1.\] This proves ?? .

For the derivative of the off-diagonal part, we use the same rewritten one-step expansion as in the first step. Namely, at the \(n\)-th step we have \[H^{(n)}(h;\lambda) = H_{\rm d}(h)+D_n(h;\lambda)+F_n(h;\lambda), \qquad S_n(h;\lambda)=\mathcal{I}_h(F_n(h;\lambda)),\] and hence \(\mathrm{ad}_{S_n(h;\lambda)}(H_{\rm d}(h)) = -F_n(h;\lambda).\) Expanding the conjugation and rewriting the \(H_{\rm d}\)-tail as in the first step gives \[B_{n+1}(h;\lambda) = D_n(h;\lambda) + \sum_{r\ge1}\frac{1}{r!} \mathrm{ad}_{S_n}^{\,r}\bigl(D_n(h;\lambda)\bigr) + \sum_{m\ge1} \frac{m}{(m+1)!} \mathrm{ad}_{S_n}^{\,m}\bigl(F_n(h;\lambda)\bigr),\] where, for readability, \(S_n=S_n(h;\lambda)\). Therefore \[F_{n+1}(h;\lambda) = \left[ \sum_{r\ge1}\frac{1}{r!} \mathrm{ad}_{S_n}^{\,r}\bigl(D_n(h;\lambda)\bigr) + \sum_{m\ge1} \frac{m}{(m+1)!} \mathrm{ad}_{S_n}^{\,m}\bigl(F_n(h;\lambda)\bigr) \right]^{\rm off}.\]

We differentiate this expression. Since \(\partial_hS_n = \mathcal{I}_h(\partial_hF_n) + (\partial_h\mathcal{I}_h)(F_n),\) Lemmas 36 and 37 give \(\|\partial_hS_n\|_\kappa \le C\left( \frac{\|\partial_hF_n\|_\kappa}{U} + \frac{\|F_n\|_\kappa}{U^2} \right).\) The differentiated terms containing \(\mathcal{I}_h(\partial_hF_n)\) give the differentiated contraction term, and, after increasing the strong-coupling threshold if necessary, are bounded by \(q\|\partial_hF_n(h;\lambda)\|_\kappa .\) All remaining differentiated terms contain at least one factor \(S_n\) or \(F_n\), together with either \((\partial_h\mathcal{I}_h)(F_n)\) or \(\partial_hD_n\). Using Lemma 11, Lemma 12, and the already obtained bound \(\|F_n(h;\lambda)\|_\kappa \le Cq^{n-1}|\lambda|\frac{|t|^2}{U},\) these terms are bounded by \(Cq^{n-1}|\lambda|\frac{|t|^2}{U^2} \bigl(1+\|\partial_hD_n(h;\lambda)\|_\kappa\bigr).\) Consequently, \[\|\partial_hF_{n+1}(h;\lambda)\|_\kappa \le q\|\partial_hF_n(h;\lambda)\|_\kappa + Cq^{n-1}|\lambda|\frac{|t|^2}{U^2} \bigl(1+\|\partial_hD_n(h;\lambda)\|_\kappa\bigr).\]

We next close the estimate for \(\partial_hD_n\) simultaneously. Since \(D_{n+1}(h;\lambda)=D_n(h;\lambda)+\delta_n(h;\lambda),\) Lemma 39 gives \[\begin{align} \|\partial_h\delta_n(h;\lambda)\|_\kappa \le C\left( \frac{\|F_n(h;\lambda)\|_\kappa}{U} \|\partial_hF_n(h;\lambda)\|_\kappa + \frac{\|F_n(h;\lambda)\|_\kappa^2}{U^2} \bigl(1+\|\partial_hD_n(h;\lambda)\|_\kappa\bigr) \right). \end{align}\] Put \(x_n:=\|\partial_hD_n(h;\lambda)\|_\kappa\) and \(y_n:=\|\partial_hF_n(h;\lambda)\|_\kappa.\) Using the bound for \(F_n\), the two preceding estimates imply \[\begin{align} y_{n+1} &\le qy_n + Cq^{n-1}|\lambda|\frac{|t|^2}{U^2}(1+x_n), \tag{63}\\ x_{n+1} &\le x_n + Cq^{n-1}|\lambda|\frac{|t|^2}{U^2}y_n + Cq^{2(n-1)}|\lambda|^2\frac{|t|^4}{U^4}(1+x_n). \tag{64} \end{align}\] We claim that \(x_n\) is uniformly bounded and \(y_n\le Cnq^{n-1}|\lambda|\frac{|t|^2}{U^2}.\) Indeed, assume first that \(x_j\le K\) for \(1\le j\le n\). Then 63 , together with the first-step bound on \(y_1\), gives \(y_j\le C_K j q^{j-1}|\lambda|\frac{|t|^2}{U^2}\) for \(1\le j\le n+1\).

Substituting this into 64 , we obtain \[x_{n+1} \le x_1 + C_K \sum_{j=1}^{n} j q^{2(j-1)} |\lambda|^2\frac{|t|^4}{U^4} + C \sum_{j=1}^{n} q^{2(j-1)} |\lambda|^2\frac{|t|^4}{U^4} (1+x_j).\] The sums are bounded uniformly in \(n\), and their prefactor is \(O(|t|^4/U^4)\). After increasing the strong-coupling threshold, this contribution is smaller than, say, \(1\). Choosing \(K\) larger than \(x_1+1\), the bootstrap closes and gives \(\sup_{n\ge1}x_n\le C.\) Returning to 63 , we then get \(y_n \le C n q^{n-1}|\lambda|\frac{|t|^2}{U^2}.\) Finally, choose \(q_1\in(q,1)\). Since \(n q^{n-1}\le C(q,q_1)q_1^{n-1},\) we may enlarge the constant and rename \(q_1\) as \(q\). Thus \[\|\partial_hF_n(h;\lambda)\|_\kappa \le Cq^{n-1}|\lambda|\frac{|t|^2}{U^2},\qquad \|\partial_hD_n(h;\lambda)\|_\kappa\le C.\] This proves ?? and ?? .

It remains only to record the non-differentiated diagonal bound. From \(D_{n+1}=D_n+\delta_n\) and the diagonal increment estimate \(\|\delta_n(h;\lambda)\|_\kappa \le C\frac{\|F_n(h;\lambda)\|_\kappa^2}{U},\) we get \(\|\delta_n(h;\lambda)\|_\kappa \le Cq^{2(n-1)}|\lambda|^2\frac{|t|^4}{U^3}.\) This is summable in \(n\), and \(D_1\) is already uniformly bounded. Therefore \(\|D_n(h;\lambda)\|_\kappa\le C\) for \(n\ge1\). The proof is complete. ◻

Lemma 44 (Geometric bounds for diagonal increments). In the setting and notation of Lemma 43, one has, uniformly in \(n\ge1\), \(\Lambda\), \(|h| \le h_0\), and \(|\lambda|\le1\), \[\label{eq:geom-delta-bound} \|\delta_n(h;\lambda)\|_\kappa \le Cq^{2(n-1)}|\lambda|^2\frac{|t|^4}{U^3},\qquad{(26)}\] and \[\label{eq:geom-d-delta-bound} \|\partial_h\delta_n(h;\lambda)\|_\kappa \le Cq^{2(n-1)}|\lambda|^2\frac{|t|^4}{U^4}.\qquad{(27)}\] In particular, for \(U\ge1\), \[\label{eq:geom-d-delta-bound-weaker} \|\partial_h\delta_n(h;\lambda)\|_\kappa \le Cq^{2(n-1)}|\lambda|^2\frac{|t|^4}{U^3}.\qquad{(28)}\]

Proof. By the diagonal increment estimate ?? , applied to the \(n\)-th LS/SW step, \(\|\delta_n(h;\lambda)\|_\kappa \le C\frac{\|F_n(h;\lambda)\|_\kappa^2}{U}.\) Using Lemma 43, \(\|F_n(h;\lambda)\|_\kappa \le Cq^{n-1}|\lambda|\frac{|t|^2}{U},\) we obtain \[\|\delta_n(h;\lambda)\|_\kappa \le C\frac{1}{U} \left( q^{n-1}|\lambda|\frac{|t|^2}{U} \right)^2 = Cq^{2(n-1)}|\lambda|^2\frac{|t|^4}{U^3}.\] This proves ?? .

For the \(h\)-derivative, apply Lemma 39 to the \(n\)-th LS/SW step, with \(D=D_n(h;\lambda)\) and \(F=F_n(h;\lambda).\) It gives \[\|\partial_h\delta_n(h;\lambda)\|_\kappa \le C \left( \frac{\|F_n(h;\lambda)\|_\kappa}{U} \|\partial_hF_n(h;\lambda)\|_\kappa + \frac{\|F_n(h;\lambda)\|_\kappa^2}{U^2} \bigl(1+\|\partial_hD_n(h;\lambda)\|_\kappa\bigr) \right).\] By Lemma 43, \[\|\partial_hF_n(h;\lambda)\|_\kappa \le Cq^{n-1}|\lambda|\frac{|t|^2}{U^2}, \qquad \|\partial_hD_n(h;\lambda)\|_\kappa\le C.\] Therefore the first term is bounded by \(C \frac{1}{U} \left( q^{n-1}|\lambda|\frac{|t|^2}{U} \right) \left( q^{n-1}|\lambda|\frac{|t|^2}{U^2} \right) = Cq^{2(n-1)}|\lambda|^2\frac{|t|^4}{U^4}.\) The second term is bounded by \(C \frac{1}{U^2} \left( q^{n-1}|\lambda|\frac{|t|^2}{U} \right)^2 = Cq^{2(n-1)}|\lambda|^2\frac{|t|^4}{U^4}.\) Combining the two estimates proves ?? . The weaker bound ?? follows immediately for \(U\ge1\). ◻

The next estimate is the only use of the auxiliary \(\lambda\)-expansion beyond the second-order bridge.

Lemma 45 (Higher-order endpoint remainder bound). Under the hypotheses of Corollary 17, there exists a constant \(C_{\ge3}=C_{\ge3}(d,h_0,t)\) such that, uniformly in \(\Lambda\), \[\sup_{|h|\le h_0} \|P\mathcal{K}_\Lambda^{(\ge3)}(h)P\|_0 + \sup_{|h|\le h_0} \|\partial_h(P\mathcal{K}_\Lambda^{(\ge3)}(h)P)\|_0 \le C_{\ge3}\frac{|t|^3}{U^2}.\]

Proof. Set \(V:=(T_\Lambda)^{\rm off}.\) For the auxiliary \(\lambda\)-deformation, write the diagonal increments as \(\delta_n(h;\lambda) := B_{n+1}(h;\lambda)^{\rm diag} - B_n(h;\lambda)^{\rm diag}.\) Then \(\Delta_\Lambda(h;\lambda) = \sum_{n\ge0}\delta_n(h;\lambda)\) with convergence in \(\|\cdot\|_\kappa\). Near \(\lambda=0\), each \(\delta_n(h;\lambda)\) is analytic and has the expansion \[\delta_n(h;\lambda) = \sum_{m\ge2}\lambda^m\delta_n^{[m]}(h).\]

We split the higher-order endpoint remainder into the first LS/SW step and the later steps: \[\mathcal{K}_\Lambda^{(\ge3)}(h) = \rho_0^{(\ge3)}(h) + \rho_{\ge1}^{(\ge3)}(h),\] where \[\rho_0^{(\ge3)}(h) := \delta_0(h;1)-\delta_0^{[2]}(h), \qquad \rho_{\ge1}^{(\ge3)}(h) := \sum_{n\ge1} \left( \delta_n(h;1)-\delta_n^{[2]}(h) \right).\]

Step 1: the first LS/SW step. For the \(\lambda\)-deformation, \[H_\Lambda(h;\lambda) = H_{\rm d}+T_\Lambda^{(0)}+\lambda V, \qquad H_{\rm d}:=UD_\Lambda-hM_\Lambda.\] Set \(S:=\mathcal{I}_h(V).\) Then \(S_0(h;\lambda)=\lambda S\) and \(\mathrm{ad}_S(H_{\rm d})=-V.\) Expanding the first conjugation gives \[\begin{align} e^{\lambda S} H_\Lambda(h;\lambda) e^{-\lambda S} &= H_{\rm d}+T_\Lambda^{(0)} +\lambda V \\ &\quad+ \sum_{r\ge1}\frac{\lambda^r}{r!}\mathrm{ad}_S^{\,r}(H_{\rm d}) + \sum_{r\ge1}\frac{\lambda^r}{r!}\mathrm{ad}_S^{\,r}(T_\Lambda^{(0)}) + \sum_{r\ge1}\frac{\lambda^{r+1}}{r!}\mathrm{ad}_S^{\,r}(V). \end{align}\] Using \(\mathrm{ad}_S^{\,r}(H_{\rm d}) = -\mathrm{ad}_S^{\,r-1}(V), \;(r\ge1),\) the term \(\lambda V\) is cancelled by the \(r=1\) contribution from \(H_{\rm d}\). Therefore \[e^{\lambda S} H_\Lambda(h;\lambda) e^{-\lambda S} = H_{\rm d}+T_\Lambda^{(0)} + \sum_{r\ge1}\frac{\lambda^r}{r!} \mathrm{ad}_S^{\,r}(T_\Lambda^{(0)}) + \sum_{m\ge1} \frac{m}{(m+1)!}\lambda^{m+1}\mathrm{ad}_S^{\,m}(V).\] Taking the \(D_\Lambda\)-diagonal part and subtracting \(T_\Lambda^{(0)}\), we get \[\delta_0(h;\lambda) = \left[ \sum_{r\ge1}\frac{\lambda^r}{r!} \mathrm{ad}_S^{\,r}(T_\Lambda^{(0)}) + \sum_{m\ge1} \frac{m}{(m+1)!}\lambda^{m+1}\mathrm{ad}_S^{\,m}(V) \right]^{\rm diag}.\] Since \(T_\Lambda^{(0)}\) is \(D_\Lambda\)-diagonal and \(S\) is \(D_\Lambda\)-off-diagonal, \(\left(\mathrm{ad}_S(T_\Lambda^{(0)})\right)^{\rm diag}=0.\) Thus \[\delta_0^{[2]}(h) = \frac{1}{2}\left(\mathrm{ad}_S(V)\right)^{\rm diag} + \frac{1}{2}\left(\mathrm{ad}_S^2(T_\Lambda^{(0)})\right)^{\rm diag},\] and \(\rho_0^{(\ge3)}(h)\) is the diagonal part of \(\sum_{r\ge3}\frac{1}{r!}\mathrm{ad}_S^{\,r}(T_\Lambda^{(0)}) + \sum_{m\ge2} \frac{m}{(m+1)!}\mathrm{ad}_S^{\,m}(V).\) In this expression the \(H_{\rm d}\)-tail has been rewritten in terms of \(V\)-commutators, so no norm of \(H_{\rm d}\) enters the estimate.

By Lemmas 11, 12, and 36, \(\|S\|_\kappa\le C\frac{|t|}{U}\) and \(\|V\|_\kappa+\|T_\Lambda^{(0)}\|_\kappa\le C|t|.\) Hence \[\|P\rho_0^{(\ge3)}(h)P\|_0 \le C(d,h_0,t) \left( \|S\|_\kappa^2\|V\|_\kappa + \|S\|_\kappa^3\|T_\Lambda^{(0)}\|_\kappa \right) \le C(d,h_0,t)\frac{|t|^3}{U^2}.\]

For the \(h\)-derivative, we differentiate the same rewritten expression. Since \(V\) and \(T_\Lambda^{(0)}\) are independent of \(h\), the derivative only hits the factors \(S=\mathcal{I}_h(V)\). By Lemma 37, \(\|\partial_hS\|_\kappa = \|\partial_h\mathcal{I}_h(V)\|_\kappa \le C(d,\kappa,h_0)\frac{|t|}{U^2}.\) Differentiating the two BCH tails and using Lemmas 11 and 12, we obtain \[\begin{align} \|\partial_h(P\rho_0^{(\ge3)}(h)P)\|_0 &\le C(d,h_0,t) \left( \|\partial_hS\|_\kappa\|S\|_\kappa\|V\|_\kappa + \|\partial_hS\|_\kappa\|S\|_\kappa^2 \|T_\Lambda^{(0)}\|_\kappa \right) \le C(d,h_0,t)\frac{|t|^3}{U^2}. \end{align}\]

Step 2: later LS/SW steps. We now estimate the contribution from the steps \(n\ge1\). By Lemma 44, applied in the auxiliary \(\lambda\)-scheme, we have \[\begin{align} \|\delta_n(h;\lambda)\|_\kappa &\le Cq^{2(n-1)}|\lambda|^2\frac{|t|^4}{U^3}, \tag{65}\\ \|\partial_h\delta_n(h;\lambda)\|_\kappa &\le Cq^{2(n-1)}|\lambda|^2\frac{|t|^4}{U^4} \le Cq^{2(n-1)}|\lambda|^2\frac{|t|^4}{U^3}. \tag{66} \end{align}\]

We extract the \(\lambda^2\)-coefficient by Cauchy’s estimate. As in the proof of Lemma 21, the LS/SW maps are holomorphic in \(\lambda\), and the estimates above depend only on \(|\lambda|\). Applying Cauchy’s estimate on a fixed circle \(|\lambda|=r_0\le1\), and absorbing the factor \(r_0^{-2}\) into the constant, gives \[\label{eq:Kge3-delta2-coeff-bound} \|\delta_n^{[2]}(h)\|_\kappa + \|\partial_h\delta_n^{[2]}(h)\|_\kappa \le Cq^{2(n-1)}\frac{|t|^4}{U^3}.\tag{67}\]

Since \(\rho_{\ge1}^{(\ge3)}(h) = \sum_{n\ge1} \left( \delta_n(h;1)-\delta_n^{[2]}(h) \right),\) the estimates 65 , 66 , and 67 imply \[\|P\rho_{\ge1}^{(\ge3)}(h)P\|_0 + \|\partial_h(P\rho_{\ge1}^{(\ge3)}(h)P)\|_0 \le C(d,h_0,t)\frac{|t|^4}{U^3}.\] Here we used that \(P\) is independent of \(h\). Since \(\frac{|t|}{U}\le\varepsilon_{\rm SW},\) the right-hand side is bounded by \(C(d,h_0,t)\frac{|t|^3}{U^2}.\)

Combining this with the estimates for \(\rho_0^{(\ge3)}\), we obtain \[\sup_{|h|\le h_0} \|P\mathcal{K}_\Lambda^{(\ge3)}(h)P\|_0 + \sup_{|h|\le h_0} \|\partial_h(P\mathcal{K}_\Lambda^{(\ge3)}(h)P)\|_0 \le C_{\ge3}\frac{|t|^3}{U^2}.\] This proves the lemma. ◻

Lemma 46 (\(C^1\) bound on the explicit second-order comparison term). Under the hypotheses of Corollary 17, there is a constant \(C_R(d,h_0,t)<\infty\) such that, uniformly in \(\Lambda\), \[\sup_{|h|\le h_0} \|\mathcal{R}_\Lambda^{(2)}(h)\|_0 + \sup_{|h|\le h_0} \|\partial_h\mathcal{R}_\Lambda^{(2)}(h)\|_0 \le C_R(d,h_0,t)\frac{|t|^3}{U^2}.\] Consequently, \[\sup_{|h|\le h_0} \|P\mathcal{R}_\Lambda^{(2)}(h)P\|_0 + \sup_{|h|\le h_0} \|\partial_h(P\mathcal{R}_\Lambda^{(2)}(h)P)\|_0 \le C_R(d,h_0,t)\frac{|t|^3}{U^2}.\]

Proof. Set \(V:=(T_\Lambda)^{\rm off}.\) We first estimate the uncompressed interaction \(\mathcal{R}_\Lambda^{(2)}(h)\). The corresponding compressed estimate follows by applying \(P\) on both sides, since \(P\) is an orthogonal projection and is independent of \(h\).

We use the following upstream inputs, all with the \(0\)-norm. By Lemma 36, \(\|\mathcal{I}_h(V)\|_0 \le C(d)\frac{|t|}{U}.\) By Lemma 37, \(\|\partial_h\mathcal{I}_h(V)\|_0 \le C(d,h_0)\frac{|t|}{U^2}.\) The hopping bounds give \(\|T_\Lambda^{(0)}\|_0\le C(d)|t|\) and \(\|V\|_0\le C(d)|t|.\) Finally, Lemma 21 gives the \(C^0\)-bound: \(\|\mathcal{R}_\Lambda^{(2)}(h)\|_0 \le C_{R,0}(d)\frac{|t|^3}{U^2}.\)

It remains to estimate the \(h\)-derivative. Recall that \[\mathcal{R}_\Lambda^{(2)}(h) = \frac{1}{2} \left( \mathrm{ad}_{\mathcal{I}_h(V)} \left( \mathrm{ad}_{\mathcal{I}_h(V)}(T_\Lambda^{(0)}) \right) \right)^{\rm diag}.\] The \(D_\Lambda\)-diagonal extraction is contractive in the \(0\)-norm by Lemma 13. Differentiating gives \[\begin{align} \partial_h\mathcal{R}_\Lambda^{(2)}(h) &= \frac{1}{2} \left( \mathrm{ad}_{\partial_h\mathcal{I}_h(V)} \left( \mathrm{ad}_{\mathcal{I}_h(V)}(T_\Lambda^{(0)}) \right) \right)^{\rm diag} + \frac{1}{2} \left( \mathrm{ad}_{\mathcal{I}_h(V)} \left( \mathrm{ad}_{\partial_h\mathcal{I}_h(V)}(T_\Lambda^{(0)}) \right) \right)^{\rm diag}. \end{align}\] Using the interaction commutator bound Lemma 11, we obtain \[\begin{align} \|\partial_h\mathcal{R}_\Lambda^{(2)}(h)\|_0 &\le C(d) \|\partial_h\mathcal{I}_h(V)\|_0 \|\mathcal{I}_h(V)\|_0 \|T_\Lambda^{(0)}\|_0 \le C(d,h_0,t) \frac{|t|}{U^2} \frac{|t|}{U} |t| = C(d,h_0,t)\frac{|t|^3}{U^3}. \end{align}\] After increasing the large-\(U\) threshold if necessary, this is bounded by \(C(d,h_0,t)\frac{|t|^3}{U^2}.\) Together with the \(C^0\)-bound from Lemma 21, this proves \[\sup_{|h|\le h_0} \|\mathcal{R}_\Lambda^{(2)}(h)\|_0 + \sup_{|h|\le h_0} \|\partial_h\mathcal{R}_\Lambda^{(2)}(h)\|_0 \le C_R(d,h_0,t)\frac{|t|^3}{U^2}.\]

Since \(P\) is independent of \(h\), \(\partial_h(P\mathcal{R}_\Lambda^{(2)}(h)P) = P(\partial_h\mathcal{R}_\Lambda^{(2)}(h))P.\) The compressed estimate follows from the same bound after applying \(P\) on both sides. This completes the proof. ◻

Lemma 47 (\(C^1\) bound on the residual second-order comparison term). Under the hypotheses of Corollary 17, there is a constant \(C_E(d,h_0,t)<\infty\) such that, uniformly in \(\Lambda\), \[\sup_{|h|\le h_0} \|\mathcal{E}_\Lambda^{(2)}(h)\|_0 + \sup_{|h|\le h_0} \|\partial_h\mathcal{E}_\Lambda^{(2)}(h)\|_0 \le C_E(d,h_0,t)\frac{|t|^4}{U^3}.\] Consequently, \[\sup_{|h|\le h_0} \|P\mathcal{E}_\Lambda^{(2)}(h)P\|_0 + \sup_{|h|\le h_0} \|\partial_h(P\mathcal{E}_\Lambda^{(2)}(h)P)\|_0 \le C_E(d,h_0,t)\frac{|t|^4}{U^3}.\]

Proof. We prove the uncompressed estimates for \(\mathcal{E}_\Lambda^{(2)}(h)\). The compressed estimates follow at the end by applying \(P\) on both sides.

Recall the notation for the auxiliary \(\lambda\)-scheme. The diagonal increments are \(\delta_n(h;\lambda) := D_{n+1}(h;\lambda)-D_n(h;\lambda) \, (n\ge0).\) Near \(\lambda=0\), we write \(\delta_n(h;\lambda) = \sum_{m\ge2}\lambda^m\delta_n^{[m]}(h).\) By definition, \(\mathcal{E}_\Lambda^{(2)}(h) = \sum_{n\ge1}\delta_n^{[2]}(h).\) It is enough to prove \[\label{eq:E2-claim-delta-coeff} \|\delta_n^{[2]}(h)\|_0 + \|\partial_h\delta_n^{[2]}(h)\|_0 \le C(d,h_0,t)q^{2(n-1)} \frac{|t|^4}{U^3}, \qquad n\ge1,\tag{68}\] uniformly in \(\Lambda\) and \(|h|\le h_0\).

By Lemma 44, for \(|\lambda|\le1\), \[\|\delta_n(h;\lambda)\|_\kappa \le Cq^{2(n-1)} |\lambda|^2\frac{|t|^4}{U^3}, \qquad \|\partial_h\delta_n(h;\lambda)\|_\kappa \le Cq^{2(n-1)} |\lambda|^2\frac{|t|^4}{U^3}.\] We now extract the \(\lambda^2\)-coefficient. As in the proof of Lemma 21, we regard \(\lambda\) as a complex parameter in a fixed small disc. The LS/SW maps are holomorphic in \(\lambda\), and the estimates above depend only on \(|\lambda|\). Cauchy’s estimate on a fixed circle \(|\lambda|=r_0\le1\) gives \[\|\delta_n^{[2]}(h)\|_\kappa + \|\partial_h\delta_n^{[2]}(h)\|_\kappa \le Cq^{2(n-1)}\frac{|t|^4}{U^3},\] where the factor \(r_0^{-2}\) is absorbed into the constant. Since \(\|\cdot\|_0\le\|\cdot\|_\kappa\), this proves 68 .

Summing 68 over \(n\ge1\), we obtain \[\|\mathcal{E}_\Lambda^{(2)}(h)\|_0 + \|\partial_h\mathcal{E}_\Lambda^{(2)}(h)\|_0 \le C(d,h_0,t)\frac{|t|^4}{U^3}.\] Since \(P\) is independent of \(h\), \(\partial_h(P\mathcal{E}_\Lambda^{(2)}(h)P) = P(\partial_h\mathcal{E}_\Lambda^{(2)}(h))P.\) The compressed estimate follows by applying \(P\) on both sides. This completes the proof. ◻

Proof of Proposition 25. By Lemma 42, \[R_{P,\Lambda}(h) = P\mathcal{R}_\Lambda^{(2)}(h)P + P\mathcal{E}_\Lambda^{(2)}(h)P + P\mathcal{K}_\Lambda^{(\ge3)}(h)P.\] Since \(P\) is independent of \(h\), differentiating this identity gives \[\partial_hR_{P,\Lambda}(h) = \partial_h\bigl(P\mathcal{R}_\Lambda^{(2)}(h)P\bigr) + \partial_h\bigl(P\mathcal{E}_\Lambda^{(2)}(h)P\bigr) + \partial_h\bigl(P\mathcal{K}_\Lambda^{(\ge3)}(h)P\bigr).\] Hence Lemmas 45, 46, and 47 imply \[\sup_{|h| \le h_0} \|R_{P,\Lambda}(h)\|_0 + \sup_{|h| \le h_0} \|\partial_hR_{P,\Lambda}(h)\|_0 \le C(d,h_0,t) \left( \frac{|t|^3}{U^2} + \frac{|t|^4}{U^3} \right).\] Since the spin identification \(\mathcal{U}_\Lambda\) is unitary and independent of \(h\) and \(\mathcal{R}_{P,\Lambda}(h) = \mathcal{U}_\Lambda R_{P,\Lambda}(h)\mathcal{U}_\Lambda^\ast,\) we have \(\partial_h\mathcal{R}_{P,\Lambda}(h) = \mathcal{U}_\Lambda (\partial_hR_{P,\Lambda}(h)) \mathcal{U}_\Lambda^\ast .\) Thus the same estimate holds for \(\mathcal{R}_{P,\Lambda}(h)\). Therefore Proposition 25 follows with \(\varepsilon_P(U;h_0) := C(d,h_0,t) \left( \frac{|t|^3}{U^2} + \frac{|t|^4}{U^3} \right).\) Clearly \(\varepsilon_P(U;h_0)\to0\) as \(U\to\infty\). ◻

11 Finite-volume pressure and convexity tools↩︎

This appendix collects the finite-volume trace estimates used in Section 6. The purpose is twofold. First, we record the elementary pressure Lipschitz and Duhamel derivative bounds used to compare finite-volume pressures and their \(h\)-derivatives. Second, we prove the soft \(C^1\) defect estimate which compares the full Hubbard pressure with the \(P\)-block pressure in the fixed positive-field window.

11.1 Pressure Lipschitz and derivative formula↩︎

Let \(\mathcal{K}\) be a finite-dimensional Hilbert space. For a self-adjoint operator \(H\) on \(\mathcal{K}\), define \[\require{physics} p_\beta(H) := \frac{1}{\beta|\Lambda|} \log\Tr_{\mathcal{K}}e^{-\beta H}.\] Here \(|\Lambda|\) is the volume parameter used for normalization.

Lemma 48 (Pressure Lipschitz bound). Let \(H\) and \(K\) be self-adjoint operators on \(\mathcal{K}\). Then \[|p_\beta(H+K)-p_\beta(H)| \le \frac{\|K\|}{|\Lambda|}.\] In particular, if \(K=K_\Lambda\) is the finite-volume sum of an interaction \(\mathsf K=\{K_X\}_{\varnothing\neq X\subset\Lambda}\), then \[|p_\beta(H+K_\Lambda)-p_\beta(H)| \le \|\mathsf K\|_0.\]

Proof. Set \(\require{physics} \Phi(A):=\log\Tr_{\mathcal{K}}e^A\) for self-adjoint \(A\) on \(\mathcal{K}\). By the Gibbs variational principle, \[\require{physics} \Phi(A) = \sup_{\rho} \left\{ \Tr_{\mathcal{K}}(\rho A) - \Tr_{\mathcal{K}}(\rho\log\rho) \right\},\] where the supremum is over density matrices on \(\mathcal{K}\). Hence \[\require{physics} \Phi(A)-\Phi(B) \le \sup_{\rho} \Tr_{\mathcal{K}}\bigl(\rho(A-B)\bigr) \le \|A-B\|.\] Exchanging \(A\) and \(B\), we obtain \(|\Phi(A)-\Phi(B)|\le \|A-B\|.\)

Apply this with \(A=-\beta(H+K)\) and \(B=-\beta H.\) Then \[\require{physics} \left| \log\Tr_{\mathcal{K}}e^{-\beta(H+K)} - \log\Tr_{\mathcal{K}}e^{-\beta H} \right| \le \beta\|K\|.\] Dividing by \(\beta|\Lambda|\) gives \(|p_\beta(H+K)-p_\beta(H)| \le \frac{\|K\|}{|\Lambda|}.\)

If \(K_\Lambda=\sum_{\varnothing\neq X\subset\Lambda}K_X,\) then \[\|K_\Lambda\| \le \sum_{\varnothing\neq X\subset\Lambda}\|K_X\| = \sum_{y\in\Lambda} \sum_{X\ni y} \frac{\|K_X\|}{|X|} \le \sum_{y\in\Lambda} \sum_{X\ni y}\|K_X\| \le |\Lambda|\|\mathsf K\|_0.\] Combining this with the operator-norm bound proves the interaction-norm version. ◻

Lemma 49 (Pressure derivative formula). Let \(H(h)\) be a \(C^1\) family of self-adjoint operators on \(\mathcal{K}\), and define \[\require{physics} p_\beta(h) := \frac{1}{\beta|\Lambda|} \log\Tr_{\mathcal{K}}e^{-\beta H(h)}.\] Then \[\partial_h p_\beta(h) = -\frac{1}{|\Lambda|} \omega_{\beta,h}(\partial_hH(h)),\] where \[\require{physics} \omega_{\beta,h}(O) := \frac{\Tr_{\mathcal{K}}(Oe^{-\beta H(h)})}{\Tr_{\mathcal{K}}e^{-\beta H(h)}}.\]

Proof. By the Duhamel formula and cyclicity of the trace, \[\require{physics} \partial_h \Tr_{\mathcal{K}}e^{-\beta H(h)} = -\beta \Tr_{\mathcal{K}} \left( (\partial_hH(h))e^{-\beta H(h)} \right).\] Dividing by \(\require{physics} \beta|\Lambda|\Tr_{\mathcal{K}}e^{-\beta H(h)}\) gives the stated formula. ◻

11.2 Even CAR operators and restricted trace factorisation↩︎

We record the restricted trace factorisation used in the soft defect pressure bound. Since we work in a fermionic canonical half-filled sector, we do not use an unrestricted tensor-product factorisation of half-filled traces. Instead, we insert a common outside single-occupancy projector; this freezes the outside part and reduces the half-filling constraint to the inside region.

We also use that all operators involved are even CAR operators, so that operators with disjoint supports commute.

Lemma 50 (Restricted trace factorisation with a common outside single-occupancy projector). Let \(X,Y\subset\Lambda\) be disjoint and set \(Z:=X\cup Y.\) Define \[P_X^{\rm hf}:=\mathbb{1}_{\{N_X=|X|\}}, \qquad P_Y^{(1)}:=\prod_{y\in Y}p_y^{(1)}, \qquad P_Z^{\rm hf}:=\mathbb{1}_{\{N_Z=|Z|\}}.\] Let \(Q_X,A_X\in\mathfrak A_X^{\rm even}\) and \(B_Y\in\mathfrak A_Y^{\rm even}.\) Then \[\require{physics} \label{eq:trace-factorisation-with-Qout} \Tr_{\mathcal{H}_Z^{\rm hf}} \bigl( Q_X\,P_Y^{(1)}\,A_X\,B_Y \bigr) = \Tr_{\mathcal{H}_X} \bigl( P_X^{\rm hf}Q_XA_XP_X^{\rm hf} \bigr)\, \Tr_{\mathcal{H}_Y} \bigl( P_Y^{(1)}B_YP_Y^{(1)} \bigr).\qquad{(29)}\] If, in addition, \(B_Y\) preserves \(P_Y^{(1)}\mathcal{H}_Y\) (for instance, if \([B_Y,P_Y^{(1)}]=0\)), then \[\require{physics} \label{eq:trace-factorisation-with-Qout-invariant} \Tr_{\mathcal{H}_Z^{\rm hf}} \bigl( Q_X\,P_Y^{(1)}\,A_X\,B_Y \bigr) = \Tr_{\mathcal{H}_X} \bigl( P_X^{\rm hf}Q_XA_XP_X^{\rm hf} \bigr)\, \Tr_{P_Y^{(1)}\mathcal{H}_Y} \bigl( B_Y\restriction_{P_Y^{(1)}\mathcal{H}_Y} \bigr).\qquad{(30)}\]

Proof. Since \(X\cap Y=\varnothing\), the local Fock space over \(Z\) is canonically identified with \[\mathcal{H}_Z\cong \mathcal{H}_X\otimes\mathcal{H}_Y.\] Under this identification, \(N_Z=N_X\otimes\mathbb{1}+\mathbb{1}\otimes N_Y,\) and \(P_Y^{(1)}=\mathbb{1}\otimes P_Y^{(1)}.\)

We first rewrite the left-hand side as a trace on the full space: \[\require{physics} \Tr_{\mathcal{H}_Z^{\rm hf}} \bigl( Q_X\,P_Y^{(1)}\,A_X\,B_Y \bigr) = \Tr_{\mathcal{H}_Z} \bigl( P_Z^{\rm hf}\, Q_X\,P_Y^{(1)}\,A_X\,B_Y\, P_Z^{\rm hf} \bigr).\] Because \(Q_X,A_X\in\mathfrak A_X^{\rm even}\) and \(P_Y^{(1)},B_Y\in\mathfrak A_Y^{\rm even}\), the \(X\)-local factors commute with the \(Y\)-local factors. Moreover, \(P_Y^{(1)}\) commutes with \(P_Z^{\rm hf}\), since both are functions of the local number operators. Hence \[\require{physics} \begin{align} \Tr_{\mathcal{H}_Z^{\rm hf}} \bigl( Q_X\,P_Y^{(1)}\,A_X\,B_Y \bigr) &= \Tr_{\mathcal{H}_Z} \bigl( P_Z^{\rm hf}P_Y^{(1)}\,Q_XA_X\,B_Y\,P_Z^{\rm hf} \bigr) \notag\\ &= \Tr_{\mathcal{H}_Z} \bigl( P_Z^{\rm hf}P_Y^{(1)}\,Q_XA_X\,B_Y\,P_Y^{(1)}P_Z^{\rm hf} \bigr). \label{eq:trace-factorisation-with-Qout-compressed} \end{align}\tag{69}\] The second equality uses \(P_Y^{(1)2}=P_Y^{(1)}\) together with cyclicity of the trace.

Now observe that on the subspace \(P_Y^{(1)}\mathcal{H}_Y\), one has \(N_Y=|Y|\). Since \(|Z|=|X|+|Y|,\) the condition \(N_Z=|Z|\) on \(P_Z^{\rm hf}\mathcal{H}_Z\) forces \(N_X=|X|\) once we restrict to \(P_Y^{(1)}\mathcal{H}_Y\). Therefore \[\label{eq:PZhf-PY1-factor} P_Z^{\rm hf}P_Y^{(1)} = P_X^{\rm hf}\otimes P_Y^{(1)} = P_Y^{(1)}P_Z^{\rm hf}.\tag{70}\] Substituting 70 into 69 , and using again that the \(X\)-local factors commute with the \(Y\)-local ones, we obtain \[\require{physics} \begin{align} \Tr_{\mathcal{H}_Z^{\rm hf}} \bigl( Q_X\,P_Y^{(1)}\,A_X\,B_Y \bigr) &= \Tr_{\mathcal{H}_X\otimes\mathcal{H}_Y} \bigl( (P_X^{\rm hf}Q_XA_XP_X^{\rm hf}) \otimes (P_Y^{(1)}B_YP_Y^{(1)}) \bigr) \notag\\ &= \Tr_{\mathcal{H}_X} \bigl( P_X^{\rm hf}Q_XA_XP_X^{\rm hf} \bigr)\, \Tr_{\mathcal{H}_Y} \bigl( P_Y^{(1)}B_YP_Y^{(1)} \bigr). \end{align}\] This proves ?? .

If \(B_Y\) preserves \(P_Y^{(1)}\mathcal{H}_Y\), then \(P_Y^{(1)}B_YP_Y^{(1)}\restriction_{P_Y^{(1)}\mathcal{H}_Y} = B_Y\restriction_{P_Y^{(1)}\mathcal{H}_Y},\) and therefore \[\require{physics} \Tr_{\mathcal{H}_Y} \bigl( P_Y^{(1)}B_YP_Y^{(1)} \bigr) = \Tr_{P_Y^{(1)}\mathcal{H}_Y} \bigl( B_Y\restriction_{P_Y^{(1)}\mathcal{H}_Y} \bigr).\] This gives ?? . ◻

11.3 Finite-volume pressure derivatives↩︎

Recall the finite-volume Hubbard and Heisenberg pressures \(p_{\Lambda_L,\beta,U}^{\rm Hub}(h)\) and \(p_{\Lambda_L,\beta,U}^{\rm Heis}(h)\) introduced in Subsection 1.3. Since both are finite-volume log-partition functions with \(h\) coupled linearly to the staggered magnetisation, they are convex functions of \(h\).

Lemma 51 (Finite-volume derivative equals magnetisation). Fix a finite even torus \(\Lambda_L\), \(\beta>0\), and \(U>0\). Then \(h\mapsto p_{\Lambda_L,\beta,U}^{\rm Hub}(h)\) is real-analytic and convex on \(\mathbb{R}\), and \[\partial_h p_{\Lambda_L,\beta,U}^{\rm Hub}(h) = m_{\Lambda_L,\beta,U}^{\rm Hub}(h) = \frac{1}{|\Lambda_L|} \omega_{\Lambda_L,\beta,U,h}^{\rm Hub}(M_{\Lambda_L}).\] Similarly, \[\partial_h p_{\Lambda_L,\beta,U}^{\rm Heis}(h) = m_{\Lambda_L,\beta,U}^{\rm Heis}(h) = \frac{1}{|\Lambda_L|} \omega_{\Lambda_L,\beta,U,h}^{\rm Heis} (M_{\Lambda_L}^{\rm spin}).\] Moreover, \[\left| \partial_h p_{\Lambda_L,\beta,U}^{\rm Hub}(h) \right| \le \frac{1}{2}, \qquad \left| \partial_h p_{\Lambda_L,\beta,U}^{\rm Heis}(h) \right| \le \frac{1}{2}.\] Consequently, for \(\sharp\in\{{\rm Hub},{\rm Heis}\}\), \[\left| p_{\Lambda_L,\beta,U}^{\sharp}(h) - p_{\Lambda_L,\beta,U}^{\sharp}(\tilde{h}) \right| \le \frac{1}{2} |h-\tilde{h}|.\]

Proof. We use the following standard fact without further comment: in finite volume, a pressure obtained from a Hamiltonian of the form \(H(h)=H(0)-hM\) is real-analytic and convex as a function of \(h\). Thus both \(h\mapsto p_{\Lambda_L,\beta,U}^{\rm Hub}(h),\) and \(h\mapsto p_{\Lambda_L,\beta,U}^{\rm Heis}(h)\) are real-analytic and convex on \(\mathbb{R}\).

For the derivative identities, apply Lemma 49. Since \(\partial_h H_{\Lambda_L}^{\rm Hub}(h) = -M_{\Lambda_L},\) we obtain \[\partial_h p_{\Lambda_L,\beta,U}^{\rm Hub}(h) = \frac{1}{|\Lambda_L|} \omega_{\Lambda_L,\beta,U,h}^{\rm Hub}(M_{\Lambda_L}) = m_{\Lambda_L,\beta,U}^{\rm Hub}(h).\] Similarly, since \(\partial_h H_{\Lambda_L}^{\rm Heis}(J_0(U),h) = -M_{\Lambda_L}^{\rm spin},\) we have \[\partial_h p_{\Lambda_L,\beta,U}^{\rm Heis}(h) = \frac{1}{|\Lambda_L|} \omega_{\Lambda_L,\beta,U,h}^{\rm Heis} (M_{\Lambda_L}^{\rm spin}) = m_{\Lambda_L,\beta,U}^{\rm Heis}(h).\]

Finally, since \(\|M_{\Lambda_L}\|\le\frac{|\Lambda_L|}{2}\) and \(\|M_{\Lambda_L}^{\rm spin}\|\le\frac{|\Lambda_L|}{2},\) one obtains \[\left| \partial_h p_{\Lambda_L,\beta,U}^{\rm Hub}(h) \right| \le \frac{1}{2}, \qquad \left| \partial_h p_{\Lambda_L,\beta,U}^{\rm Heis}(h) \right| \le \frac{1}{2}.\] Integrating these bounds gives, for \(\sharp\in\{{\rm Hub},{\rm Heis}\}\), \(\left| p_{\Lambda_L,\beta,U}^{\sharp}(h) - p_{\Lambda_L,\beta,U}^{\sharp}(\tilde{h}) \right| \le \frac{1}{2} |h-\tilde{h}|.\) This completes the proof. ◻

11.4 Positive fixed-field magnetisation↩︎

Lemma 52 (Heisenberg reference magnetisation lower bound). Let \(h_I:=\inf I>0.\) There exists a constant \(C_d<\infty\), depending only on the dimension and on the normalization of the nearest-neighbour interaction norm, such that \[m_{\Lambda_L,\beta,U}^{\rm Heis}(h) \ge m_{\rm Heis}^{\rm lb}(U,\beta;I), \qquad h\in I,\] where \[m_{\rm Heis}^{\rm lb}(U,\beta;I) := \frac{1}{2}\tanh\left(\frac{\beta h_I}{4}\right) - \frac{4C_d}{h_I}J_0(U).\] Moreover, for every \(\ell_0>0\), \[\lim_{U\to\infty} \inf_{\beta J_0(U)\ge\ell_0} m_{\rm Heis}^{\rm lb}(U,\beta;I) = \frac{1}{2}.\]

Proof. Set \(h_+:=\sup I\) and \(I^\sharp:=\left[\frac{h_I}{2},h_+\right].\) Let \(p_{\Lambda_L,\beta}^{0}\) be the pure staggered-field spin pressure. Then \[p_{\Lambda_L,\beta}^{0}(h) = \frac{1}{\beta}\log\left(2\cosh\frac{\beta h}{2}\right), \qquad \partial_h p_{\Lambda_L,\beta}^{0}(h) = \frac{1}{2}\tanh\left(\frac{\beta h}{2}\right).\] Moreover, \[H_{\Lambda_L}^{\rm Heis}(J_0(U),h) = -hM_{\Lambda_L}^{\rm spin} + H_{\Lambda_L}^{\rm Heis}, \qquad \|H_{\Lambda_L}^{\rm Heis}\|_0 \le C_dJ_0(U).\] Thus Lemma 48 gives \(\sup_{s\in I^\sharp} \left| p_{\Lambda_L,\beta,U}^{\rm Heis}(s) - p_{\Lambda_L,\beta}^{0}(s) \right| \le C_dJ_0(U).\) Applying the fixed-window convexity estimate used in Lemma 32, with \(C_dJ_0(U)\) in place of the pressure-comparison error, yields \[m_{\Lambda_L,\beta,U}^{\rm Heis}(h) \ge \frac{1}{2}\tanh\left(\frac{\beta h_I}{4}\right) - \frac{4C_d}{h_I}J_0(U), \qquad h\in I.\] This is the asserted lower bound.

Finally, \(J_0(U)=4t^2/U\to0\), and \(\beta J_0(U)\ge\ell_0 \, \Longrightarrow\, \beta h_I \ge \frac{\ell_0 h_I}{J_0(U)} \to\infty.\) Hence \(\tanh\left(\frac{\beta h_I}{4}\right)\to1\) uniformly in the Heisenberg-scale regime, and the claimed limit follows. ◻

Remark 53 (Non-optimality of the elementary lower bound). The lower bound in Lemma 52 is not intended to be optimal. It is an elementary finite-volume bound obtained only from the pressure Lipschitz comparison with the pure staggered-field spin system and the fixed-window convexity argument.

In the infinite-volume Heisenberg model, one expects stronger bounds in the regime where antiferromagnetic long-range order is known. In particular, a suitable Dyson–Lieb–Simon/infrared-bound input should give a positive staggered magnetisation uniformly as \(h\downarrow0+\) in the dimensions and temperature regimes where such long-range order holds. We do not use this stronger input here; the elementary bound above is sufficient for the fixed positive-field comparison considered in this paper.

11.5 Thermodynamic derivatives and quasi-averages↩︎

The following statement explains how thermodynamic derivatives of pressures relate to limits of finite-volume magnetisations.

Lemma 54 (Thermodynamic derivatives and magnetisation limits). Fix \(\beta>0\), \(U>0\), and \(h_0>0\). Let \(\sharp\in\{{\rm Hub},{\rm Heis}\}\). Assume that the thermodynamic limit \[p_{\beta,U}^{\sharp}(h) := \lim_{L\to\infty} p_{\Lambda_L,\beta,U}^{\sharp}(h)\] exists as a finite real number for every \(h\in[0,h_0]\). Then \(p_{\beta,U}^{\sharp}\) is convex on \([0,h_0]\).

Moreover, for every \(h\in(0,h_0)\), the one-sided derivatives \[\partial_h^-p_{\beta,U}^{\sharp}(h) := \lim_{\varepsilon\downarrow0} \frac{ p_{\beta,U}^{\sharp}(h) - p_{\beta,U}^{\sharp}(h-\varepsilon) }{\varepsilon}, \qquad \partial_h^+p_{\beta,U}^{\sharp}(h) := \lim_{\varepsilon\downarrow0} \frac{ p_{\beta,U}^{\sharp}(h+\varepsilon) - p_{\beta,U}^{\sharp}(h) }{\varepsilon}\] exist and satisfy \[\partial_h^-p_{\beta,U}^{\sharp}(h) \le \liminf_{L\to\infty} m_{\Lambda_L,\beta,U}^{\sharp}(h) \le \limsup_{L\to\infty} m_{\Lambda_L,\beta,U}^{\sharp}(h) \le \partial_h^+p_{\beta,U}^{\sharp}(h).\] Consequently, if \(p_{\beta,U}^{\sharp}\) is differentiable at \(h\in(0,h_0)\), then the thermodynamic limit of the finite-volume magnetisations exists and is given by \[\lim_{L\to\infty} m_{\Lambda_L,\beta,U}^{\sharp}(h) = \partial_h p_{\beta,U}^{\sharp}(h).\] In particular, this conclusion holds for all \(h\in(0,h_0)\) outside the at most countable set of non-differentiability points of \(p_{\beta,U}^{\sharp}\).

Proof. For each finite volume, the pressure \(p_{\Lambda_L,\beta,U}^{\sharp}(h)\) is a convex differentiable function of \(h\), and its derivative is the corresponding finite-volume magnetisation: \(\partial_h p_{\Lambda_L,\beta,U}^{\sharp}(h) = m_{\Lambda_L,\beta,U}^{\sharp}(h).\) Since \(p_{\beta,U}^{\sharp}\) is the pointwise finite limit of convex functions, it is convex on \([0,h_0]\).

Fix \(h\in(0,h_0)\). Let \(\varepsilon>0\) be such that \(h-\varepsilon,h+\varepsilon\in[0,h_0]\). By convexity of \(p_{\Lambda_L,\beta,U}^{\sharp}\), we have \[\frac{ p_{\Lambda_L,\beta,U}^{\sharp}(h) - p_{\Lambda_L,\beta,U}^{\sharp}(h-\varepsilon) }{\varepsilon} \le \partial_h p_{\Lambda_L,\beta,U}^{\sharp}(h) \le \frac{ p_{\Lambda_L,\beta,U}^{\sharp}(h+\varepsilon) - p_{\Lambda_L,\beta,U}^{\sharp}(h) }{\varepsilon}.\] Using \(\partial_h p_{\Lambda_L,\beta,U}^{\sharp}(h) = m_{\Lambda_L,\beta,U}^{\sharp}(h),\) and taking \(\liminf\) and \(\limsup\) as \(L\to\infty\), we obtain \[\frac{ p_{\beta,U}^{\sharp}(h) - p_{\beta,U}^{\sharp}(h-\varepsilon) }{\varepsilon} \le \liminf_{L\to\infty} m_{\Lambda_L,\beta,U}^{\sharp}(h) \le \limsup_{L\to\infty} m_{\Lambda_L,\beta,U}^{\sharp}(h) \le \frac{ p_{\beta,U}^{\sharp}(h+\varepsilon) - p_{\beta,U}^{\sharp}(h) }{\varepsilon}.\] Letting \(\varepsilon\downarrow0\) gives \[\partial_h^-p_{\beta,U}^{\sharp}(h) \le \liminf_{L\to\infty} m_{\Lambda_L,\beta,U}^{\sharp}(h) \le \limsup_{L\to\infty} m_{\Lambda_L,\beta,U}^{\sharp}(h) \le \partial_h^+p_{\beta,U}^{\sharp}(h).\]

If \(p_{\beta,U}^{\sharp}\) is differentiable at \(h\), then the left and right derivatives coincide. Hence the \(\liminf\) and \(\limsup\) above coincide, and the thermodynamic limit of the finite-volume magnetisations exists and equals \(\partial_h p_{\beta,U}^{\sharp}(h)\).

Finally, a convex function on an interval is differentiable outside an at most countable set. This proves the last assertion. ◻

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  1. For the general \(C^\ast\)-algebraic formulation of CAR algebras and quasi-local algebras, we refer to Bratteli and Robinson [22], [23].↩︎

  2. Equivalently, \(\Phi_X=0\) unless \(X\) is contained in some ball of radius \(R\), up to a harmless change of \(R\).↩︎