On enumeration of \(b\)-angulations of surfaces from an integrability perspective


Abstract

In this paper, we study generating series enumerating polygonal angulations of closed oriented surfaces of fixed genus, focusing on \(b\)-angulations with \(b = 3\) or \(b = 2\nu\), \(\nu \geq 2\). Based on Toda integrability, we establish new structural results in the cases \(b = 3\) and \(b = 4\). Furthermore, via the Hodge–GUE correspondence, we derive a fine structure in the \(b = 2\nu\) case, which implies a conjectural statement of Gharakhloo–Latimer.

1 Introduction and statements of the main results↩︎

Enumerating ribbon graphs, also known as (combinatorial) maps, is a fundamental problem at the interface of mathematics and mathematical physics, attracting interest from combinatorics (cf. [1][5]), and revealing deep relations to quantum field theory [1], [6][10] and geometry [4], [11][15]. Let \(\mathcal{R}^{\rm conn}_{g}(b_1,\dots,b_k)\) be the set of connected oriented labelled1 ribbon graphs of genus \(g\) with \(k\) vertices of valencies \(b_1,\dots,b_k\), and let \(n_{g}(b_1,\dots,b_k)\mathrel{\vcenter{:}}=|\mathcal{R}^{\rm conn}_{g}(b_1,\dots,b_k)|\). Here, \(g\geq 0\) and \(b_1,\dots,b_k\geq 1\). By the Euler formula, the number \(n_g(b_1,\dots,b_k)\) vanishes unless \(2-2g-k+\frac{|b|}{2}\) is a positive integer. By looking at the dual graphs, one can also understand \(n_g(b_1,\dots,b_k)\) as the number of polygon-angulations with \(k\) polygons of sizes \(b_1,\dots,b_k\) on a genus \(g\) closed oriented surface.

Following [13], [16], define a power series of infinitely many variables \({\boldsymbol{s}}=(s_1,s_2,\dots)\) by \[\begin{align} \mathcal{F}(x,{\boldsymbol{s}};\epsilon) = & \, \frac{x^2}{2\epsilon^2}\Bigl(\log x-\frac{3}{2}\Bigr) - \frac{\log x}{12} + \zeta'(-1) + \sum_{g\geq2} \frac{\epsilon^{2g-2} B_{2g}}{4g(g-1)x^{2g-2}}\nonumber\\ &+\sum_{g\geq 0}\epsilon^{2g-2}\sum_{k\geq 1}\frac{1}{k!}\sum_{b_1,\dots,b_k\ge1}n_{g}(b_1,\dots,b_k) \, s_{b_1} \cdots s_{b_k} x^{2-2g - k + \frac{|{\boldsymbol{b}}|}{2}}\,, \label{Fgue1x39} \end{align}\tag{1}\] called the free energy, and define \(Z(x,{\boldsymbol{s}};\epsilon)\mathrel{\vcenter{:}}= e^{\mathcal{F}(x,{\boldsymbol{s}};\epsilon)}\), called the partition function. Here, \(x\) is a formal variable, \(\zeta(s)\) denotes the Riemann zeta function, and \(B_m\) denotes the \(m\)th Bernoulli number. It is known from e.g. [1], [4], [15][17] that \(Z(x,{\boldsymbol{s}};\epsilon)\) can be understood as the following integral \[\label{matrixintegral} 2^{-n}\pi^{-\frac{n(n+1)}{2}} \epsilon^{-\frac{1}{12}} G(n+1) \int_{{\mathcal{H}}(n)} \exp\Bigl(-\frac{1}{\epsilon}{\rm tr}\Bigl(\frac{1}{2} M^2-\sum_{b\geq 1}s_b M^b \Bigr)\Bigr) dM\,,\tag{2}\] where \(x=n\epsilon\), \(G\) denotes Barnes’s \(G\)-function, and \[dM = \prod_{1\leq i\leq n} d M_{ii} \prod_{1\leq i<j\leq n} d{\rm Re} M_{ij}\, d{\rm Im}M_{ij}\,.\]

Define \(\mathcal{F}_g(x,{\boldsymbol{s}})\mathrel{\vcenter{:}}=[\epsilon^{2g-2}]\mathcal{F}(x,{\boldsymbol{s}};\epsilon)\), \(g\geq 0\), the genus \(g\) free energy. Structures for \(\mathcal{F}_g(x,{\boldsymbol{s}})\) have been studied in [13][16], [18][20]. By definition, \(\mathcal{F}_g(x,{\boldsymbol{s}})\) encodes the enumeration of arbitrary tilings on a genus \(g\) surface (throughout this paper, all surfaces are assumed to be closed and oriented). The special case of enumeration of \(b\)-angulations, with a fixed value of \(b\), has attracted a lot of interest [16], [21][24] and will be the main focus of this paper. This corresponds to restricting \(\mathcal{F}(x,{\boldsymbol{s}};\epsilon)\) to \({\boldsymbol{s}}=(0,\dots,0,s_b=s,0,\dots)\), and by rescaling we can assume \(s=1\), so we will consider \[\begin{align} \label{Fgexplicit} \mathcal{F}_g^{\{b\}}(x)\mathrel{\vcenter{:}}=&\,\mathcal{F}_g(x,{\boldsymbol{s}}={\boldsymbol{1}}_b) = \delta_{g,0}\frac{x^2}{2}\Bigl(\log x-\frac{3}{2}\Bigr) +\delta_{g,1}\Bigl(-\frac{\log x}{12} + \zeta'(-1)\Bigr)\nonumber\\ &\,+\, \delta_{g\geq 2}\frac{B_{2g}}{4g(g-1)x^{2g-2}} +\sum_{k\geq 1}\frac{n_{g}(b^k)}{k!}x^{2-2g+(\frac{b}{2}-1)k}\,, \end{align}\tag{3}\] where \({\boldsymbol{1}}_b\) denotes the infinite vector with the \(b\)th component equal to 1 and all other components equal to 0.

According to e.g. [15][17], [25], \(Z(x,{\boldsymbol{s}};\epsilon)\) is a tau-function of the Toda lattice hierarchy. The latter will be one of the main tools for this paper. Following [13], [15], [16], [26], define \[u=\frac{\partial^2 \mathcal{F}^{\{b\}}_0(x)}{\partial x^2}\,,\quad w=e^{u}\,.\]

The case \(b=3\). Following [16], [27], introduce a power series \(v=v(x)=6 x+324 x^2+31104 x^3+\cdots\) as the unique solution to the following cubic equation \[\label{triveqn} 6 \, x = (1-9v+18v^2) \, v\,.\tag{4}\] According to [16] we have the identity \[\label{triweqn} w = \frac{x}{1-6v}\,.\tag{5}\] (We will give a new proof of 5 in Section 3.) It follows from 45 that \(w=x+36x^2+3240x^3+\cdots\) is the unique solution to the cubic equation \[\label{triweqn2} x^2=w^2-72w^3\,.\tag{6}\] Equation 6 was also obtained in [27]. Building on, for example,[16], [17], [25] (see also [27]) and using a method from [28], we will prove in Section 3 the following theorem.

Theorem 1. For \(g=0\), we have \(\frac{\partial^2 \mathcal{F}^{\{3\}}_0(x)}{\partial x^2}=\log w\). For \(g=1\), \[\label{triF1form1333} \mathcal{F}^{\{3\}}_1(x) = -\frac{1}{12}\log w-\frac{1}{24} \log (1-108 w)+ \zeta'(-1).\tag{7}\] For \(g\geq2\), \(\mathcal{F}^{\{3\}}_g(x)\) has the expression: \[\label{triFform1} \mathcal{F}^{\{3\}}_g(x)=\frac{1-2g}{(2g)!}\,B_{2g}\,\partial_x^{2g-2}(\log w) +\sum_{\ell=3g-3}^{5g-5}\frac{a_{g,\ell}}{(1-108w)^{\ell}}\,,\tag{8}\] where \(a_{g,3g-3},\dots,a_{g,5g-5}\) are rational numbers.

For \(g\ge2\), the coefficient \(a_{g,5g-5}\) has the expression \[\label{tritopcoef} a_{g,5g-5}=\frac{162^g}{3888}\frac{C_g}{(5g-3)(5g-5)},\tag{9}\] which can be straightforwardly deduced using 8 and the well-known result (see e.g. [27]) \[\label{tricorrasymp} n_g(3^{2j})\sim \frac{16}{\sqrt{3}} \, \frac{\bigl(108\sqrt{3}\bigr)^j}{\bigl(256\sqrt{3}\bigr)^{g}} \frac{(2j)!\,(2j)^{\frac{5g-7}{2}}}{\Gamma({\frac{5g-1}{2}})}\,C_g \quad (j\to \infty) \,.\tag{10}\] Here \(C_g\), with \(C_0=-1, \ldots\), are constants determined (cf. e.g. [3], [27][32]) by requiring that the formal series \(U=\sum_{g\geq 0}C_g X^{\frac{1-5g}{2}}\) satisfies the Painlevé I equation \[\label{painleveI} \frac{d ^2 U}{d X^2}+\frac{1}{16}U^2-\frac{1}{16}X=0\,.\tag{11}\]

Table 1 consists of \(n_g(3^{4g-4+2d})\) for \(g=0,\dots,4\) and \(d=1,\dots,5\). For the reader’s convenience, we also provide \[\begin{align} \mathcal{F}^{\{3\}}_2&=\frac{\partial_x^2 (\log w)}{240}-\frac{351}{8 (1-108 w)^3}+\frac{27}{8 (1-108w)^4}+\frac{189}{10 (1-108 w)^5}\,, \tag{12}\\ \mathcal{F}^{\{3\}}_3&=-\frac{\partial_x^4 (\log w)}{6048}+\frac{589761}{4 (1-108 w)^6}-\frac{8203437}{28 (1-108 w)^7} -\frac{448335}{2 (1-108 w)^8}+\frac{324405}{(1-108 w)^9}\nonumber\\ & \quad\quad +\frac{178605}{(1-108 w)^{10}}\,.\tag{13} \end{align}\]

Table 1: The numbers \(n_{g}(3^{4g-4+2d})\) for \(g=0,\dots,4\) and \(d=1,\dots,5\).
\({\tiny d}\) \(g=0\) \(g=1\) \(g=2\) \(g=3\) \(g=4\)
\(1\) \(0\) \(3\) \(3061800\) 357485480352000 561734730904309522 560000
\(2\) \(0\) \(4536\) \(89414357760\) 475379823378087 93600 208281465835272806 019563520000
\(3\) \(12\) \(19362240\) 2834113460935 680 514591710352541 8098278400 547188956214674466 69373094461440000
\(4\) \(5184\) \(164367221760\) 1107578328829 37856000 565109847632479 817270034432000 131217479838294406 811733692434863882 24000
\(5\) \(9797760\) 233201956829 1840 5405486118155 731877068800 672926687318093 573568845764362 24000 313985184119369209 780057086172883719 8151680000

The case \(b=4\). According to [1], [20], [23], \(w=x+12x^2+288x^3+\cdots\) is the unique solution to \[\label{quadwgenus0eqn} x =w - 12 \, w^2\,.\tag{14}\] Explicitly, \(w=\frac{1-\sqrt{1-48x}}{24}\).

Theorem 2. For \(g=0\), we have \(\frac{\partial^2 \mathcal{F}^{\{4\}}_0(x)}{\partial x^2}=\log w\). For \(g=1\), \[\mathcal{F}^{\{4\}}_1(x) = -\frac{1}{12}\log w-\frac{1}{12} \log (1-24w)+ \zeta'(-1).\] For \(g\geq 2\), \(\mathcal{F}^{\{4\}}_g(x)\) has the expression: \[\label{quadFform} \mathcal{F}^{\{4\}}_g(x)=\frac{1-2g}{(2g)!}\,B_{2g}\,\partial_x^{2g-2}(\log w) +\sum_{\ell=4g-4}^{5g-5}\frac{\tilde{a}_{g,\ell}}{(1-24w)^{\ell}}\,,\tag{15}\] where \(\tilde{a}_{g,4g-4},\dots,\tilde{a}_{g,5g-5}\) are rational numbers.

The proof, which is based on [16], [17], [25] and uses a method from [28], is given in Section 4.

It is easy to deduce using 15 and a result of [22] that the number \(\tilde{a}_{g,5g-5}\) equals to \(\frac{48^g}{576}\frac{C_g}{(5g-3)(5g-5)}\) (this statement can also be proved using just the Toda lattice theory), where \(C_g\) are the universal constants introduced in 10 .

The case \(b=2\nu\). In this case, the following theorem (using our notations) was originally conjectured in [23] and confirmed recently in the third arXiv version of [23].

([23]) For \(\nu\geq 2\), define \(q=q(x)\) as the power-series-in-\(x\) solution to the equation \[\label{qeqn} 1-q+\frac{(2\nu)!}{\nu!(\nu-1)!} \; x^{\nu-1} q^{\nu}=0\,.\qquad{(1)}\] Then for \(g\geq 2\), \[\label{evenFform4} x^{2g-2}\mathcal{F}_g^{\{2\nu\}}(x) =\sum_{\ell=2g-2}^{5g-5}\frac{r_{g,\ell}(\nu)}{(\nu-(\nu-1)q)^{\ell}}\,,\qquad{(2)}\] where for each \(\nu\geq 2\), \(r_{g,2g-2}(\nu),\dots,r_{g,5g-5}(\nu)\) are rational numbers.

We mention here that for the case when \(b=4\) one can use \(g\) parameters to express the genus \(g\) free energy with \(g\ge2\) (see 15 ) instead of \(3g-2\) parameters (see ?? ). For the case when \(b=6\) we have similar observations in which \(2g-1\) parameters are sufficient, whose proof will be given elsewhere.

We will also give several proofs of Theorem A, which were completed before noticing the updated version of [23].

In Section 4, a proof of Theorem A will be achieved based on Theorem 2. By using a formula of [22], we will give a second proof, which also corresponds to the proof in [23].

In [14], [20] a relationship between \(n_g(2\nu_1,\dots,2\nu_k)\) and certain cubic Hodge integrals on the Deligne–Mumford moduli spaces, called the Hodge–GUE correspondence, was established. As an application of the Hodge–GUE correspondence, we will give a third proof of Theorem A.

Motivated by a study of Gharakhloo–Latimer [24], we give in the following theorem a fine structure for \(\mathcal{F}_g^{\{2\nu\}}(x)\) as another application of the Hodge–GUE correspondence.

Theorem 3. For \(g\geq 2\), the coefficients \(r_{g,\ell}(\nu)\) in ?? are polynomials in \(\nu\) of degree \(3g-3\).

The proof is in Section 5.

Following [24], define \(S_{g,k}(\nu)\) by \[\label{evenexplicit} n_{g}((2\nu)^k) =:\biggl(\frac{(2\nu)!}{(\nu+1)!\nu!}\biggr)^k S_{g,k}(\nu)\,.\tag{16}\] By ?? , ?? we have \[\begin{align} \label{Sgjdef} S_{g,k}(\nu)=k!(\nu(\nu+1))^k \sum_{m=0}^{k} \binom{\nu k-1}{k-m}\frac{(\nu-1)^m}{m!} \sum_{\ell=2g-2}^{5g-5}r_{g,\ell}(\nu)(\ell-1)_m\,. \end{align}\tag{17}\] Theorem 3 then implies a conjectural statement given by Gharakhloo–Latimer in [24]: for \(g\geq 0\) and \(k\geq 1\), \(S_{g,k}(\nu)\) is a polynomial in \(\nu\) of degree \(3g-3+3k\). A further conjectural statement on distributions of zeros of \(S_{g,k}(\nu)\) was also proposed in [24]. We recall that, when \(g=0\), the expressions of \(n_0((2\nu)^k)\), \(\nu\geq 2\), were given in [33] (the \(\nu=2\) case also given in [34]); when \(g=1\), the expressions of \(n_1((2\nu)^k)\) were obtained in [34] for \(\nu=2\) and in [35] for \(\nu\ge2\); when \(g=2\), the expressions of \(n_2((2\nu)^k)\), \(\nu\geq 2\), \(k=1,2,3\), were given in [24]; the expressions of \(n_{g}(4^k)\), \(g=2,\dots,7\), \(k\geq 1\), were given in [35], and the expressions of \(n_{g}(6^k)\), \(g=2,\dots,5\), \(k\geq 1\), were given in [24]. We also note that, the above-proved polynomiality of \(S_{g,k}(\nu)\) can alternatively be deduced from the celebrated quasi-polynomiality of [36], [37] (cf. also [38], [39]), which is deeply related to topological recursion.

In Section 2 we review earlier works on the free energy \(\mathcal{F}(x,{\boldsymbol{s}};\epsilon)\). In Section 3 we prove Theorem 1. In Section 4 we prove Theorem 2. In Section 5 we prove Theorem 3.

We thank Paul Norbury for pointing out the reference [19]. The work of E.G-F. is supported by the Ramón y Cajal Fellowship RYC2023-045188-I, funded by MCIN/AEI/10.13039/501100011033 and by the FSE+. She also acknowledges support by the project PID2024-155686NB-I00 of the Spanish Ministry of Science and Innovation, the ANR CarteEtPlus ANR-23-CE48-0018, a Tremplin grant from Sorbonne Université, a PEPS grant from the CNRS and the ERC Synergy Grant ReNewQuantum. The work of D.Y. and J.X. is supported by NSFC 12371254 and CAS YSBR-032.

2 Review of the GUE free energy \(\mathcal{F}(x,{\boldsymbol{s}};\epsilon)\)↩︎

In this section we review several properties of the GUE free energy \(\mathcal{F}(x,{\boldsymbol{s}};\epsilon)\).

It is known (cf. e.g. [4], [25], [40][42]) that the partition function \(Z=Z(x,{\boldsymbol{s}};\epsilon)\) satisfies the following Virasoro constraints: \[\label{virasoro} L_{k}(Z(x,{\boldsymbol{s}};\epsilon))=0\,,\quad k\geq -1\,,\tag{18}\] where \(L_k\) are linear operators given by \[\begin{align} &L_{-1}=\sum_{j\geq 2}j s_j \frac{\partial}{\partial s_{j-1}}-\frac{\partial}{\partial s_1}+\frac{x s_1}{\epsilon^2}\,,\tag{19}\\ &L_0=\sum_{j\geq 1}j s_j \frac{\partial}{\partial s_j}-\frac{\partial}{\partial s_2}+\frac{x^2}{\epsilon^2}\,,\tag{20}\\ &L_k=\epsilon^2\sum_{j=1}^{k-1}\frac{\partial^2 }{\partial s_j \partial s_{k-j}}+2x\frac{\partial}{\partial s_k}+\sum_{j\geq 1}j s_j\frac{\partial}{\partial s_{j+k}}-\frac{\partial}{\partial s_{k+2}}\,,\quad k\geq 1\,, \end{align}\] which satisfy the Virasoro commutation relations: \[[L_k,L_\ell]=(k-\ell)L_{k+\ell}\,,\quad k,\ell\geq -1\,.\] The \(k=-1\) equation in 18 is also known as the string equation. It also follows from 2 that \(Z\) satisfies the following dilaton equation: \[\sum_{j\geq1} s_j \, \frac{\partial Z}{\partial s_j} + \epsilon\, \frac{\partial Z}{\partial\epsilon} + x \, \frac{\partial Z}{\partial x} + \frac{1}{12} \, Z = \frac{1}{2} \, \frac{\partial Z}{\partial s_2}\,. \label{dilaton}\tag{21}\]

Denote by \(\Lambda=e^{\epsilon\partial_x}\) the shift operator. It is known (cf. [16], [17], [25], [41]) that \((V^{\rm GUE}=V^{\rm GUE}(x,{\boldsymbol{s}};\epsilon),W^{\rm GUE}=W^{\rm GUE}(x,{\boldsymbol{s}};\epsilon))\) defined by \[\begin{align} \label{defVWintro} V^{\rm GUE}(x,{\boldsymbol{s}};\epsilon) &= \epsilon(\Lambda-1) \frac{\partial\mathcal{F}(x,{\boldsymbol{s}};\epsilon)}{\partial s_1}\,,\\ W^{\rm GUE}(x,{\boldsymbol{s}};\epsilon) &=\epsilon^2\frac{\partial^2 \mathcal{F}(x,{\boldsymbol{s}};\epsilon)}{\partial s_1 \partial s_1} \end{align}\tag{22}\] is a solution to the Toda lattice hierarchy [43], [44]: \[\epsilon\frac{\partial L}{\partial s_j}=[A_j, L]\,,\quad j\geq 1\,,\] where \[L=\Lambda+V+W \Lambda^{-1}\,,\quad A_j\mathrel{\vcenter{:}}=(L^j)_{+}\,.\] Here and below, for a difference operator \(P=\sum_{k\in\mathbb{Z}} P_k \Lambda^k\), \(P_{+}\mathrel{\vcenter{:}}=\sum_{k\geq 0} P_k \Lambda^k\) and \({\rm res} \, P\mathrel{\vcenter{:}}= P_0\). Denote \[V^{\{b\}}(x,\epsilon)\mathrel{\vcenter{:}}= V^{\rm GUE}(x,{\boldsymbol{1}}_b;\epsilon)\,, \quad W^{\{b\}}(x,\epsilon)\mathrel{\vcenter{:}}= W^{\rm GUE}(x,{\boldsymbol{1}}_b;\epsilon)\,.\] By definition, we know that \(W^{\{b\}}(x,\epsilon)\) has the following genus expansion: \[\label{topoWbexpand} W^{\{b\}}(x,\epsilon) = \sum_{g\geq0} \epsilon^{2g} W^{\{b\}}_{g}(x)\,.\tag{23}\]

Dividing the \(k=-1\) equation in 18 by \(Z(x,{\boldsymbol{s}};\epsilon)\), we have \[\label{string2} \sum_{j\geq 2}j s_j \;\frac{\partial\mathcal{F}(x,{\boldsymbol{s}};\epsilon)}{\partial s_{j-1}}+\frac{x s_1}{\epsilon^2} =\frac{\partial\mathcal{F}(x,{\boldsymbol{s}};\epsilon)}{\partial s_1}\,.\tag{24}\] Applying \(\epsilon(\Lambda-1)\) on both sides of 24 yields \[\label{string21} \epsilon\sum_{j\geq2}j s_j (\Lambda-1)\frac{\partial\mathcal{F}(x,{\boldsymbol{s}};\epsilon)}{\partial s_{j-1}}+s_1=\epsilon(\Lambda-1)\frac{\partial\mathcal{F}(x,{\boldsymbol{s}};\epsilon)}{\partial s_1}\,.\tag{25}\] Following [16], define \(h_j\mathrel{\vcenter{:}}=\frac{1}{j+2}{\rm res}L^{j+2}\in\mathbb{Q}[V,W,\Lambda^{\pm 1}V,\Lambda^{\pm 1}W,\dots]\). In particular, \(h_{-1}=V\). From [16] we know \[\epsilon(\Lambda-1)\frac{\partial\mathcal{F}(x,{\boldsymbol{s}};\epsilon)}{\partial s_j}=j h_{j-2}\bigl|\bigr._{\Lambda^i V=\Lambda^i V^{\rm GUE},\,\Lambda^i W=\Lambda^i W^{\rm GUE},\, i\in\mathbb{Z}} \, ,\] then 25 becomes \[\label{Ptype1} \sum_{j\geq 2}j(j-1) s_j \; h_{j-3}\bigl|\bigr._{\Lambda^i V=\Lambda^i V^{\rm GUE},\,\Lambda^i W=\Lambda^i W^{\rm GUE},\, i\in\mathbb{Z}} +s_1 =V^{\rm GUE}\,.\tag{26}\] Applying \(\epsilon^2\frac{\partial}{\partial{s_1}}\) on both sides of 24 , we get \[\label{string22} \epsilon^2\sum_{j\geq2}j s_j \frac{\partial^2 \mathcal{F}(x,{\boldsymbol{s}};\epsilon)}{\partial s_1\partial s_{j-1}}+x=\epsilon^2\frac{\partial^2 \mathcal{F}(x,{\boldsymbol{s}};\epsilon)}{\partial s_1^2}\,.\tag{27}\] Then according to [16] and [45], we obtain \[\label{Ptype2} \sum_{j\geq2}j s_{j}(\Lambda+1)^{-1}(j h_{j-2}-(j-1)V h_{j-3}) |_{\Lambda^i V=\Lambda^i V^{\rm GUE},\,\Lambda^i W=\Lambda^i W^{\rm GUE},\, i\in\mathbb{Z}}+x =W^{\rm GUE}\,.\tag{28}\] We note that special cases of 26 and 28 were given in e.g. [7], [27], [34], [46].

Define \({\boldsymbol{v}}^{\rm GUE}(x,{\boldsymbol{s}})=(v^{\rm GUE}(x,{\boldsymbol{s}}),u^{\rm GUE}(x,{\boldsymbol{s}}))\mathrel{\vcenter{:}}=(V^{\rm GUE}(x,{\boldsymbol{s}};0), \log W^{\rm GUE}(x,{\boldsymbol{s}};0))\). Based on the Dubrovin–Zhang theory, the following formulas were obtained in [13] (cf. also [3], [15], [18], [47]):

\[\begin{align} \mathcal{F}_0(x,{\boldsymbol{s}}) = & \frac{1}{2}\sum_{p,q\geq0} (p+1)! (q+1)! \bigl(s_{p+1}-\frac{1}{2}\delta_{p,1}\bigr) \bigl(s_{q+1}-\frac{1}{2}\delta_{q,1}\bigr) \Omega^{{\mathbb{P}^1},[0]}_{2,p;2,q}(v^{\rm GUE}(x,{\boldsymbol{s}}),u^{\rm GUE}(x,{\boldsymbol{s}})) \nonumber\\ & + x\sum_{p\geq0} (p+1)! \bigl(s_{p+1}-\frac{1}{2}\delta_{p,1}\bigr) \theta^{\mathbb{P}^1}_{2,p}(v^{\rm GUE}(x,{\boldsymbol{s}}),u^{\rm GUE}(x,{\boldsymbol{s}})) + \frac{1}{2} x^2 u^{\rm GUE}(x,{\boldsymbol{s}})\,, \tag{29}\\ \mathcal{F}_g(x,{\boldsymbol{s}}) = &F_g^{\mathbb{P}^1}\biggl(v^{\rm GUE}(x,{\boldsymbol{s}})\,, u^{\rm GUE}(x,{\boldsymbol{s}}), \dots,\frac{\partial^{3g-2} v^{\rm GUE}(x,{\boldsymbol{s}})}{\partial x^{3g-2}},\frac{\partial^{3g-2} u^{\rm GUE}(x,{\boldsymbol{s}})}{\partial x^{3g-2}}\biggr) \nonumber\\ & + \bigl(\zeta'(-1)-\frac{1}{24} \log(-1)\bigr)\delta_{g,1}\,,\quad g\geq1\,.\tag{30} \end{align}\] Here, \(\Omega^{{\mathbb{P}^1},[0]}_{2,p;2,q}(v,u)\) and \(\theta^{{\mathbb{P}^1}}_{2,p}(v,u)\) are certain genus \(0\) two-point correlation functions of the \(\mathbb{P}^1\)-Frobenius manifold, and \(F_g^{\mathbb{P}^1}(v,u,v_1,u_1,\dots,v_{3g-2},u_{3g-2})\) denotes the genus \(g\) free energy in jet variables. For \(g=1\), \[\label{jetF1} F_1^{\mathbb{P}^1}(v,u,v_1,u_1)=\frac{1}{24}\log(v_1^2-e^{u}u_1^2)-\frac{1}{24}u\,.\tag{31}\] For \(g\geq 2\), \(F_g^{\mathbb{P}^1}(v,u,v_1,u_1,\dots,v_{3g-2},u_{3g-2})\) depends polynomially on \(v_2,u_2,\dots,v_{3g-2},u_{3g-2}\) and rationally on \(v_1,u_1\) with coefficients being smooth functions of \(v\) and \(u\). Moreover, \[\deg F^{\mathbb{P}^1}_{g}(v,u,v_1,u_1,\dots,v_{3g-2},u_{3g-2})=2g-2\,,\] where \(\deg v_k=\deg u_k\mathrel{\vcenter{:}}= k\). The reader is referred to e.g. [12], [15], [26] for details on the \(\mathbb{P}^1\)-Frobenius manifold, \(\theta^{{\mathbb{P}^1}}_{2,p}(v,u)\), \(\Omega^{{\mathbb{P}^1},[0]}_{2,p;2,q}(v,u)\), and \(F_g^{\mathbb{P}^1}(v,u,v_1,u_1,\dots,v_{3g-2},u_{3g-2})\).

Following for example [10], consider the even GUE free energy \(\mathcal{F}^{\rm even}\), which is the GUE free energy restricted to even couplings, i.e., \[\mathcal{F}^{\rm even} = \mathcal{F}^{\rm even}(x,s_2,s_4,\dots;\epsilon)\mathrel{\vcenter{:}}=\mathcal{F}(x,{\boldsymbol{s}};\epsilon)|_{s_1=s_3=\cdots=0}\] and plays an important role in two-dimensional quantum gravity [10]. Denote by \(\mathcal{F}^{{\rm even}}_g\mathrel{\vcenter{:}}=[\epsilon^{2g-2}]\mathcal{F}^{\rm even}\) the genus \(g\) part of \(\mathcal{F}^{\rm even}\), and denote \[v_{\rm even}=v^{\rm GUE}(x,{\boldsymbol{s}})|_{s_1=s_3=\dots=0}\,,\; u_{\rm even}=u^{\rm GUE}(x,{\boldsymbol{s}})|_{s_1=s_3=\dots=0}\,.\] It was proved in [20] that \(v_{\rm even}\equiv 0\) and \(w_{\rm even}\mathrel{\vcenter{:}}= e^{u_{\rm even}}\) satisifies \[\label{evengenus0eqn} x=w_{\rm even}-\sum_{\nu\geq 1}\frac{(2\nu)!}{\nu!(\nu-1)!}s_{2\nu} w_{\rm even}^{\nu}\,.\tag{32}\]

The Hodge–GUE correspondence, which gives an explicit relationship between a certain cubic Hodge free energy and \(\mathcal{F}^{\rm even}\), was established in [14], [20]. Let \(\overline{\mathcal{M}}_{g,n}\) denote the Deligne–Mumford moduli space of stable genus-\(g\) curves with \(n\) marked points. Denote by \(\psi_i\) the first Chern class of the \(i\)th tautological line bundle over \(\overline{\mathcal{M}}_{g,n}\), and by \(\lambda_i\) the \(i\)th Chern class of the rank-\(g\) Hodge bundle on \(\overline{\mathcal{M}}_{g,n}\).

We define the Chern polynomial \(\Lambda_g(z)\mathrel{\vcenter{:}}=\sum_{i=0}^g \lambda_i z^i\), and set \[\mathcal{H}({\boldsymbol{t}};\epsilon)\mathrel{\vcenter{:}}=\sum_{g\geq 0}\epsilon^{2g-2}\sum_{n\geq 0}\frac{1}{n!}\sum_{i_1,\cdots,i_n\geq 0} \prod_{m=1}^{n}t_{i_m}\int_{\overline{\mathcal{M}}_{g,n}}\Lambda_g(-1)\Lambda_g(-1)\Lambda_g(\tfrac12) \psi_1^{i_1}\cdots\psi_{n}^{i_n}\,.\] The Hodge–GUE correspondence says that \[\mathcal{F}^{\rm even}(x,s_2,s_4,\dots)= \epsilon^{-2}A(x,s_2,s_4,\dots)+\zeta'(-1) +(\Lambda^{\frac{1}{2}}+\Lambda^{-\frac{1}{2}})\mathcal{H}({\boldsymbol{t}}(x,s_2,s_4,\dots);\epsilon)\,,\] where \(A=A(x,s_2,s_4,\dots)\) is defined by \[A=\frac{1}{2}\sum_{k_1,k_2\geq 1}\frac{k_1 k_2}{k_1+k_2} \binom{2k_1}{k_1}\binom{2k_2}{k_2}s_{2k_1}s_{2k_2} -\sum_{k\geq 1}\frac{k}{1+k}\binom{2k}{k}s_{2k}+x\sum_{k\geq1}\binom{2k}{k}s_{2k}+\frac{1}{4}-x\,,\] and \[t_i(x,s_2,s_4,\dots)\mathrel{\vcenter{:}}=\sum_{k\geq 1} k^{i+1}\binom{2k}{k}s_{2k}-1+\delta_{i,1}+x \delta_{i,0}\,,\quad i\geq 0\,.\] This correspondence yields the only known ELSV-type formula for strictly monotone Hurwitz numbers [48], to the best of our knowledge. Explicit expressions for \(\mathcal{F}^{{\rm even}}_g\) for \(g=1,\dots,5\) in terms of \(u_{\rm even}\) and its \(x\)-derivatives were given in [20] and its arXiv preprint version. For example, [20] shows that \[\label{Feven1general} \mathcal{F}^{{\rm even}}_1= \frac{1}{12} \log \frac{\partial u_{\rm even}}{\partial x} +\zeta'(-1).\tag{33}\]

3 On triangulations↩︎

In this section we prove Theorem 1.

Taking \({\boldsymbol{s}}={\boldsymbol{1}}_3\) in 26 and 28 , we have \[\begin{align} 3 \, \bigl(V^{\{3\}}(x,\epsilon)^2 + W^{\{3\}}(x,\epsilon) + W^{\{3\}}(x+\epsilon,\epsilon)\bigr) & = V^{\{3\}}(x,\epsilon) \,, \tag{34}\\ x + 3 \, W^{\{3\}}(x,\epsilon) \, \bigl(V^{\{3\}}(x,\epsilon)+V^{\{3\}}(x-\epsilon,\epsilon)\bigr) & = W^{\{3\}}(x,\epsilon) \tag{35} \end{align}\] (cf. also e.g. [27], [34]). Introduce \[\widetilde{V}^{\{3\}}(x,\epsilon) \mathrel{\vcenter{:}}= V^{\{3\}}\bigl(x-\frac{\epsilon}{2},\epsilon\bigr)\,,\] then equations 3435 become \[\begin{align} 3 \, \Bigl(\widetilde{V}^{\{3\}}(x,\epsilon)^2 + W^{\{3\}}\bigl(x-\frac{\epsilon}{2},\epsilon\bigr) \, +\, W^{\{3\}}\bigl(x+\frac{\epsilon}{2},\epsilon\bigr)\Bigr) & = \widetilde{V}^{\{3\}}(x,\epsilon) \,, \tag{36}\\ x + 3 W^{\{3\}}(x,\epsilon) \Bigl(\widetilde{V}^{\{3\}}\bigl(x-\frac{\epsilon}{2},\epsilon\bigr)+\widetilde{V}^{\{3\}}\bigl(x+\frac{\epsilon}{2},\epsilon\bigr)\Bigr) & = W^{\{3\}}(x,\epsilon) \,. \tag{37} \end{align}\]

From the definition of \(V^{\rm GUE}(x,{\boldsymbol{s}};\epsilon)\), we know that \(\widetilde{V}^{\{3\}}(x,\epsilon)\) has the following genus expansion: \[\begin{align} \widetilde{V}^{\{3\}}(x,\epsilon) = \sum_{g\geq0} \epsilon^{2g} \widetilde{V}^{\{3\}}_g(x). \label{topoVt} \end{align}\tag{38}\] Substituting 23 and 38 in equations 3637 , we obtain \[\begin{align} & 3 \, \sum_{g_1,g_2\geq0} \epsilon^{2(g_1+g_2)} \, \widetilde{V}^{\{3\}}_{g_1} \, \widetilde{V}^{\{3\}}_{g_2} + 6\, \sum_{g,k} \frac{\epsilon^{2g+2k}}{2^{2k} (2k)!} \frac{\partial^{2k} W^{\{3\}}_{g}}{\partial x^{2k}} = \sum_{g\geq0} \epsilon^{2g} \, \widetilde{V}^{\{3\}}_{g}(x) \,, \tag{39}\\ & x + 6 \, \sum_{g_1,g_2,k\geq0} \frac{\epsilon^{2g_1+2g_2+2k}}{2^{2k} (2k)!} W^{\{3\}}_{g_1}(x) \, \frac{\partial^{2k} \widetilde{V}^{\{3\}}_{g_2}}{\partial x^{2k}} = \sum_{g\geq0} \epsilon^{2g} \, W^{\{3\}}_{g}(x) \,. \tag{40} \end{align}\] Comparing coefficients of \(\epsilon^{2g}\) (\(g \geq 0\)) on both sides of 3940 , we find \[\begin{align} 3 \, \widetilde{V}^{\{3\}}_{0}(x)^2 + 6 \, W^{\{3\}}_{0}(x) & = \widetilde{V}^{\{3\}}_{0}(x) \,, \tag{41}\\ x + 6 \, W^{\{3\}}_{0}(x) \, \widetilde{V}^{\{3\}}_{0}(x) & = W^{\{3\}}_{0}(x) \,, \tag{42} \end{align}\] and for \(g\geq1\), \[\begin{align} & \bigl(1 - 6 \widetilde{V}^{\{3\}}_{0} \bigr) \, \widetilde{V}^{\{3\}}_{g} \,-\, 6 \, W^{\{3\}}_{g} = 3 \, \sum_{g_1=1}^{g-1} \widetilde{V}^{\{3\}}_{g_1} \, \widetilde{V}^{\{3\}}_{g-g_1} + 6 \, \sum_{k=1}^g \frac{1}{2^{2k}(2k)!} \frac{\partial^{2k} W^{\{3\}}_{g-k}}{\partial x^{2k}} \,, \tag{43}\\ & - \, 6 \, W^{\{3\}}_{0} \, \widetilde{V}^{\{3\}}_{g} + (1- 6 \, \widetilde{V}^{\{3\}}_{0}) \, W^{\{3\}}_{g} = 6 \, \sum_{g_1,g_2\leq g-1 \atop g_1+g_2+k=g} \frac{1}{2^{2k} (2k)!} W^{\{3\}}_{g_1} \, \frac{\partial^{2k} \widetilde{V}^{\{3\}}_{g_2}}{\partial x^{2k}} \,. \tag{44} \end{align}\]

Solving 4142 we find that \(v=v(x)\mathrel{\vcenter{:}}=\widetilde{V}^{\{3\}}_{0}(x)\) and \(w=w(x)\mathrel{\vcenter{:}}= W^{\{3\}}_{0}(x)\) satisfy 4 and 5 , which imply 6 as well as \[\label{vwithw} v=\frac{1-\sqrt{1-72w}}{6}\,.\tag{45}\] From 6 we get \[\label{tridw} \partial_x = \frac{\sqrt{1-72\,w}}{1-108\,w} \, \partial_w\,.\tag{46}\]

Lemma 1. For \(k\geq 1\), \[\label{dxeven} \partial_x^{2k}=\sum_{i=1}^{2k}\frac{T_{k,i}(w)}{(1-108w)^{4k-i}}\partial_w^i\tag{47}\] for some polynomials \(T_{k,1}(w),\dots,T_{k,2k}(w)\). Moreover, \(\deg\,T_{k,i}(w)\leq k\) for \(i=1,\dots,2k\).

Proof. For \(k=1\), from 46 we obtain \[\label{tridw2} \partial_x^2 =\frac{72 (1-54 w)}{(1-108 w)^3}\partial_w+\frac{1-72 w}{(1-108 w)^2}\partial_w^2\,,\tag{48}\] thus 47 holds. Suppose that 47 is true for \(k=m\) with \(\deg\,T_{m,i}(w)\leq m\). Then for \(k=m+1\) we have \[\begin{align} \partial_x^{2m+2}&=\partial_x^2\circ\partial_x^{2m}= \biggl(\frac{72 (1-54 w)}{(1-108 w)^3}\partial_w+\frac{(1-72 w)}{(1-108 w)^2}\partial_w^2 \biggr) \circ \sum_{i=1}^{2m}\frac{T_{m,i}(w)}{(1-108w)^{4m-i}}\partial_w^i\nonumber\\ &=\sum_{i=1}^{2m+2}\frac{T_{m+1,i}(w)}{(1-108w)^{4m+4-i}}\partial_w^i\,. \end{align}\] Here \[\begin{align} \label{Tm431} T_{m+1,i}=&(1-72w)(1-108w)^2 \partial_w^2 T_{m,i}+2(1-72w)(1-108w)\partial_w T_{m,i-1}+(1-72w)T_{m,i-2}\nonumber\\ &+\bigl(72+216(4k-i)-(3888-15552(4k-i))w\bigr)(1-108w)\partial_w T_{m,i}\nonumber\\ &+\bigl(72+216(4k+1-i)-(3888-15552(4k+1-i))w\bigr)T_{m,i-1}\nonumber\\ &+108(4k-i)\bigl(72+108(4k+1-i)-(3888-7776(4k+1-i))w\bigr)T_{m,i}\,, \end{align}\tag{49}\] with \(T_{m,-1}\), \(T_{m,0}\), \(T_{m,2m+1}\) and \(T_{m,2m+2}\) defined as 0. Obviously, \(\deg\,T_{m+1,i}\leq m+1\) for \(i=1,\dots,2m+2\). By mathematical induction the lemma is proved. ◻

Proposition 1. For \(g\geq 1\), \(\widetilde{V}^{\{3\}}_{g}(x)\), \(W^{\{3\}}_{g}(x)\) are given by \[\label{ansatzOftriSol} W^{\{3\}}_{g}(x)=\frac{w Q_g(w)}{(1-108 w)^{5g-1}}\Big|_{w=w(x)}\, ,\quad \widetilde{V}^{\{3\}}_{g}(x)=\frac{\sqrt{1-72w}\, R_g(w)}{(1-108 w)^{5g-1}}\Big|_{w=w(x)} \,,\qquad{(3)}\] where \(Q_g(w), R_g(w)\) are polynomials of \(w\). Moreover, \(\deg\,Q_g(w)\leq 2g-1\), \(\deg\,R_g(w)\leq 2g-1\).

Proof. For \(g=1\), solving the \(g=1\) equations of 4344 gives \[\widetilde{V}^{\{3\}}_{1}(x) = \frac{54 \sqrt{1-72 w}}{(1-108 w)^4}\Bigl|_{w=w(x)}\Bigr.\,,\quad W^{\{3\}}_{1}(x) = \frac{162 \,(5-324 w)\, w}{(1-108 w)^4}\Bigl|_{w=w(x)}\Bigr. \,.\] Suppose ?? is true with \(\deg\,Q_g(w),\deg\,R_g(w)\leq 2g-1\) for \(g\leq m\). Then for \(g=m+1\), by solving the \(g=m+1\) equations of 4344 and using 45 , Lemma 1, we obtain \[\begin{align} (\widetilde{V}^{\{3\}}_{m+1}(x),W^{\{3\}}_{m+1}(x)) =\Bigl(\frac{\sqrt{1-72w}\,R_{m+1}(w)}{(1-108w)^{5m+4}}, \frac{w\,Q_{m+1}(w)}{(1-108w)^{5m+4}}\Bigr)\Bigl|_{w=w(x)}\Bigr.\,, \end{align}\] where \(Q_{m+1}(w)\), \(R_{m+1}(w)\) are polynomials of \(w\) with \(\deg\,Q_{m+1}(w),\deg\,R_{m+1}(w)\leq 2m+1\). This completes the proof of the proposition by mathematical induction. ◻

From Proposition 1 we know that \(\widetilde{V}^{\{3\}}(x,\epsilon)\), \(W^{\{3\}}(x,\epsilon)\) can be written as \[\label{trigenusinpart1} W^{\{3\}}(x,\epsilon)=w+\sum_{g\geq 1}\epsilon^{2g}\sum_{\ell=3g-1}^{5g-1}\frac{A_{g,\ell}}{(1-108w)^{\ell}}\,, \quad \widetilde{V}^{\{3\}}(x,\epsilon)=v+\sum_{g\geq 1}\epsilon^{2g}\sum_{\ell=-\infty}^{5g-1}\frac{\widetilde{B}_{g,\ell}}{(1-108w)^{\ell}}\,,\tag{50}\] for some real numbers \(A_{g,5g-1},\ldots,A_{g,3g-1},\widetilde{B}_{g,5g-1},\ldots\). Substituting 50 in 3637 , one can obtain that \(U=2^{\frac{9}{5}}3^{\frac{11}{5}}\sum_{g\geq 0}A_{g,5g-1}(2^{\frac{2}{5}}3^{\frac{8}{5}}X)^{\frac{1-5g}{2}}\) satisfies the Painlevé I equation 11 . Therefore, \[\label{univ95const} A_{g,5g-1}=\frac{162^g}{108}C_g\,,\tag{51}\] with \(C_g\) the constants introduced in 10 .

We proceed to calculate \(\mathcal{F}^{\{3\}}(x,\epsilon)\). Taking \({\boldsymbol{s}}={\boldsymbol{1}}_3\) in 22 we have \[\log W^{\{3\}}(x,\epsilon) = \mathcal{F}^{\{3\}}(x+\epsilon,\epsilon) \,+\, \mathcal{F}^{\{3\}}(x-\epsilon,\epsilon) \,-\, 2 \, \mathcal{F}^{\{3\}}(x,\epsilon) \,. \label{WF}\tag{52}\] Therefore, \[\begin{align} \label{wf} \mathcal{F}^{\{3\}}(x,\epsilon) & = \frac{1}{\epsilon^2 \partial_x^2} \, \frac{\epsilon^2 \partial_x^2}{e^{\epsilon\partial_x} + e^{-\epsilon\partial_x} -2} \bigl( \log W^{\{3\}}(x,\epsilon) \bigr)\nonumber\\ &= \frac{1}{\epsilon^2 \partial_x^2} \, \sum_{k\geq 0} \frac{(1-2k) B_{2k}}{(2k)!} \, \epsilon^{2k} \partial_x^{2k} \bigl( \log W^{\{3\}}(x,\epsilon) \bigr) \,. \end{align}\tag{53}\]

It is helpful to introduce the following lemma for computing 53 :

Lemma 2. The following identity holds for \(k\geq 4\): \[\begin{align} \label{lem1gen} \frac{972(-2)^k}{(1-108w)^k}\frac{((k-2)!)^2}{(2k-4)!}= \partial_x^{2}\biggl(72w & \sqrt{3-216w} \; {\rm arctanh}\bigl(\sqrt{3-216w}\bigr)\nonumber\\ &-72w+\sum_{i=1}^{k-4}\frac{1}{(1-108w)^i}\frac{(-2)^{i+2}}{i(i+2)}\frac{(i+2)!^2}{(2i+4)!}\biggr)\,. \end{align}\tag{54}\]

Proof. Let \(a\) be a formal variable. We have \[972\sum_{k\geq 4}\frac{((k-2)!)^2}{(2k-4)!}\frac{(-2a)^k}{(1-108w)^k}= 3888\, s^2\biggl(\frac{s(s-1)}{2-s}+\frac{2\sqrt{s}\, {\rm arcsin}\bigl(\sqrt{s/2}\bigr)}{(2-s)^{\frac{3}{2}}}\biggr)\,,\] where \(s=\frac{a}{108w-1}\). Using 48 it is easy to verify that \[\begin{align} \label{lemstep1} &3888s^2\biggl(\frac{s(s-1)}{2-s}+\frac{2\sqrt{s}\, {\rm arcsin}\bigl(\sqrt{s/2}\bigr)}{(2-s)^{\frac{3}{2}}}\biggr)\nonumber\\ &=\partial_x^2\Biggl(\frac{a^4}{1-a}\biggl(72w\sqrt{3-216w}\,{\rm arctanh}\,\bigl(\sqrt{3-216w}\bigr)\nonumber\\ & \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;-72w +\frac{2}{3}\sqrt{1-\frac{s}{2}}\,\frac{s+1}{s}\,\frac{{\rm arcsin}\bigl(\sqrt{s/2}\bigr)}{\sqrt{s/2}} -\frac{2}{3s}\biggr)\Biggr)\nonumber\\ &=\partial_x^2\Biggl(\frac{a^4}{1-a}\biggl(72w\sqrt{3-216w}\,{\rm arctanh}\bigl(\sqrt{3-216w}\bigr) \nonumber\\ & \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;-72w +\sum_{i\geq 0} \frac{a^i}{(1-108w)^i}\frac{(-2)^{i+2}}{i(i+2)}\frac{(i+2)!^2}{(2i+4)!} \biggr)\Biggr)\,. \end{align}\tag{55}\] In this last equality we use the identity \[\frac{2}{3}\sqrt{1-\frac{s}{2}}\,\frac{s+1}{s}\,\frac{{\rm arcsin}\bigl(\sqrt{s/2}\bigr)}{\sqrt{s/2}}=\frac{2}{3s}+ \frac{5}{9}+\sum_{i\geq 1}\frac{(-2)^{i+2}}{i(i+2)}\frac{(i+2)!^2}{(2i+4)!} s^i\,.\] By taking the coefficient of \(a^k\), \(k\geq 4\), on both sides of 55 we obtain 54 . ◻

Using Proposition 1, we have \[\begin{align} \label{triWstep2} \log \, W^{\{3\}}(x,\epsilon) &=\log \, w \,+\, \log \, \biggl(1\,+\,\sum_{g\geq1} \, \frac{\epsilon^{2g} Q_g(w)}{(1-108w)^{5g-1}}\biggr) \,. \end{align}\tag{56}\] By substituting 56 in 53 , and using Lemma 1 and Lemma 2, we obtain for \(g\geq 2\), \[\begin{align} \mathcal{F}^{\{3\}}_g =& \frac{1-2g}{(2g)!}B_{2g}\partial_x^{2g-2}(\log w) \nonumber\\ &+\sum_{k=1}^{g-1} \frac{1-2k}{(2k)!}B_{2k}\partial_x^{2k-2} \biggl(\sum_{\ell=1}^{g-k}\frac{(-1)^{\ell-1}}{\ell (1-108w)^{5g-5k-\ell}} \sum_{m_1,\dots,m_{\ell}\geq 1\atop m_1+\cdots+m_{\ell}=g-k}\prod_{i=1}^{\ell}Q_{m_i}(w)\biggr)\nonumber\\ &+\partial_x^{-2} \biggl(\sum_{\ell=1}^{g}\frac{(-1)^{\ell-1}}{\ell (1-108w)^{5g-\ell}} \sum_{m_1,\dots,m_{\ell}\geq 1\atop m_1+\cdots+m_{\ell}=g}\prod_{i=1}^{\ell}Q_{m_i}(w)\biggr)\tag{57} \\ =&\frac{1-2g}{(2g)!}B_{2g}\partial_x^{2g-2}(\log w) +\sum_{\ell=3g-3}^{5g-5}\frac{a_{g,\ell}}{(1-108w)^{\ell}} +\alpha_g w\sqrt{1-72w}+\beta_g\nonumber\\ &+\gamma_g \cdot \biggl(72w \sqrt{3-216w}\, {\rm arctanh}(\sqrt{3-216w})\nonumber\\ &-72z+\sum_{i=1}^{3g-4}\frac{1}{(1-108w)^i}\frac{(-2)^{i+2}}{i(i+2)}\frac{(i+2)!^2}{(2i+4)!}\biggr)\,.\tag{58} \end{align}\] Here \(\alpha_g\) and \(\beta_g\) are integration constants, and \(a_{g,3g-3},\dots, a_{g,5g-5},\gamma_g\) are rational numbers.

For further simplification of 58 , introduce \[\label{Gdef} \mathcal{G}^{\{3\}}(x,\epsilon) \mathrel{\vcenter{:}}= 6 \, \Bigl(\frac{1}{4} \,-\, \frac{x^2}{\epsilon^2} + 3 \, (\epsilon\partial_\epsilon+ x \partial_x) \, (\mathcal{F}^{\{3\}}(x,\epsilon))\Bigr)\,.\tag{59}\] It has the genus expansion \(\mathcal{G}^{\{3\}}(x,\epsilon)=\sum_{g\geq 0}\epsilon^{2g-2}\mathcal{G}^{\{3\}}_g(x)\), and for \(g\geq 0\), \[\label{GandF} \mathcal{G}^{\{3\}}_g=-6x^2 \delta_{g,0}+\frac{3}{2}\delta_{g,1}+18(2g-2)\mathcal{F}^{\{3\}}_g+18x\partial_{x}(\mathcal{F}^{\{3\}}_g)\,.\tag{60}\]

By taking \({\boldsymbol{s}}={\boldsymbol{1}}_3\) in equations 19 , 20 and 21 , we find \(\mathcal{G}^{\{3\}}(x,\epsilon) = \frac{\partial Z}{\partial s_1}\), so from 22 we know \[\frac{1}{\epsilon}\, \widetilde{V}^{\{3\}}(x,\epsilon) = \mathcal{G}^{\{3\}}(x+\epsilon/2,\epsilon) - \mathcal{G}^{\{3\}}(x-\epsilon/2,\epsilon) \,. \label{VF}\tag{61}\] Therefore \[\mathcal{G}^{\{3\}}(x,\epsilon) = \frac{1}{\epsilon^2\partial_x} \frac{\epsilon\partial_x}{(\Lambda^{1/2}-\Lambda^{-1/2})} (\widetilde{V}^{\{3\}}(x,\epsilon)) = \partial_x^{-1} \sum_{g\geq0} \epsilon^{2g-2} \sum_{k+g_1=g} \frac{(-1)^k B_{2k}(\frac{1}{2})}{(2k)!}\partial_x^{2k} (\widetilde{V}^{\{3\}}_{g_1} (x))\,, \label{triGstructure}\tag{62}\] and \[\label{triGg} \mathcal{G}_g^{\{3\}}(x,\epsilon)=\partial_x^{-1}(\widetilde{V}^{\{3\}}_{g}(x))+\sum_{k=1}^g \frac{(-1)^k B_{2k}(\frac{1}{2})}{(2k)!}\partial_x^{2k-1} (\widetilde{V}^{\{3\}}_{g-k} (x))\,,\quad g\geq 0\,.\tag{63}\] Here \(B_k(p)\) denotes the \(k\)th Bernoulli polynomial.

Proposition 2. For \(g\geq2\), \(\mathcal{G}^{\{3\}}_g(x)\) is given by \[\label{triGgstructure} \mathcal{G}^{\{3\}}_g(x)= \frac{S_g(w)}{(1-108w)^{5g-3}}\Bigl|_{w=w(x)}\Bigr.+\tilde{\lambda}_g\,,\qquad{(4)}\] for a polynomial \(S_g(w)\) and some integration constant \(\tilde{\lambda}_g\). Moreover, \(\deg\, S_g(w)\leq 2g-1\).

Proof. From 6 we know that \(\partial_x^{-1}(*)=\partial_w^{-1}\bigl(\frac{1-108 w}{\sqrt{1-72 w}}\,*\bigr)\). Using this and Proposition 1, Lemma 1 in 63 , we find expression ?? and that \(\deg\, S_g(w)\leq 2g-1\). ◻

We are ready to prove Theorem 1.

Proof of Theorem 1. The \(g=0\) case has been given above (cf. also 29 and [16]). For \(g=1\), the statement can be verified directly using 4344 (cf. also 3031 and [16]). For \(g\ge2\), by comparing 8 and 58 , it suffices to prove that the constants \(\alpha_g, \beta_g, \gamma_g\) appearing in 58 all vanish. From 48 we know that \(\partial_x^{2g-2}(\log w)\) is a rational function of \(w\). Putting 58 in 60 and comparing with ?? in Proposition 2, by the vanishing of \({\rm arctanh}\,(\sqrt{3-216w})\) in \(\mathcal{G}^{\{3\}}_g\) we find \(\gamma_g=0\). Since \(\partial_x (\log w)=\frac{\sqrt{1-72 w}}{(1-108 w) w}\), using 4546 we find that for \(k\geq 1\), \[\partial_x^k (v) = O(w^{\frac{1}{2}-\frac{3}{2} k})\,, \quad \partial_x^k (\log w) = O(w^{-\frac{3}{2} k})\,, \quad w \to \infty\,.\] Then from 30 (cf. [49]) we know that \(\mathcal{F}^{\{3\}}_g \to 0\) as \(w\to\infty\). Thus \(\alpha_g=\beta_g=0\). ◻

We end this section by presenting several consequences of Theorem 1. First of all, note that, using Lemmas 1, 2, 50 , 57 , 58 and Theorem 1, we can achieve a new self-contained proof of the expression 9 of \(a_{g,5g-5}\), which in turn implies 10 .

Multiplying both sides of 8 by \(dx/x^{3-2g+j}\) and taking the residue at \(x=0\), we obtain \[\begin{align} n_{g}(3^{2j})&=\sigma_{g,j}+72^{j-2g+2}(2j)!\sum_{m=0}^{j-2g+2} \binom{\frac{3j}{2}-3g+3-m}{\frac{j}{2}-g+1} \sum_{\ell=3g-3}^{5g-5}(\ell-1)_{m}\,\frac{3^m}{2^m m!}a_{g,\ell}\,, \end{align}\] where \(\sigma_{g,j}=(2j)!\mathop{\rm res}\limits_{w=0}\frac{(1-108w)dw}{w^{j-2g+3}(1-72w)^{\frac{j}{2}-g+2}}\frac{(1-2g)B_{2g}}{2g!}\partial_x^{2g-2}(\log w)\) and \((a)_m\mathrel{\vcenter{:}}= a(a+1)\cdots (a+m-1)\) is the Pochhammer symbol.

Following [21] (cf. [3]), introduce \[\label{triqchange} q=\frac{1}{1-72w}\,.\tag{64}\] Formulas 712 are then translated to \[\begin{align} \mathcal{F}^{\{3\}}_1 =-\frac{1}{12}&\log x-\frac{1}{24} \log \biggl(\frac{3-q}{2}\biggr)+\zeta'(-1)\, ,\tag{65}\\ \mathcal{F}^{\{3\}}_2 =\frac{1}{x^2}\biggl(&\frac{3}{64 \left(3-q\right)}-\frac{29}{32 \left(3-q\right)^2}+\frac{191}{48 \left(3-q\right)^3}-\frac{55}{8 \left(3-q\right)^4}+\frac{21}{5 \left(3-q\right)^5}\,\biggr)\,,\tag{66}\\ \mathcal{F}^{\{3\}}_3 =\frac{1}{x^4}\biggl(&\frac{63}{256 \left(3-q\right)^2}-\frac{22765}{1152 \left(3-q\right)^3}+\frac{7925}{24 \left(3-q\right)^4}-\frac{39311}{16 \left(3-q\right)^5}\nonumber\\ &+\frac{1443995}{144 \left(3-q\right)^6} -\frac{4055053}{168\left(3-q\right)^7}+\frac{68625}{2\left(3-q\right)^8}-\frac{26730}{\left(3-q\right)^9}+\frac{8820}{\left(3-q\right)^{10}}\biggr) \,. \tag{67} \end{align}\] Formula 66 was given in [22] (cf. [3]), and 67 was given in [3]. It was proved by Eynard [3] (using a slightly different notation) that for \(g\geq2\), \[\label{triFform4} x^{2g-2}\mathcal{F}^{\{3\}}_g(x) =\sum_{k=g-1}^{5g-5}\frac{r_{g,k}}{(3-q)^{k}}\,,\tag{68}\] where \(r_{g,g-1},\dots,r_{g,5g-5}\) are rational numbers. Noting that \[\label{pxlogform3} x^{2k} \partial_x^{2k} (\log w)=\sum_{\ell=0}^{3k-1}\frac{H_{k,\ell}}{(3-q)^{k+\ell}}\, , \quad k\ge1\,,\, H_{k,0},\dots,H_{k,3k-1}\in\mathbb{Q}\,,\tag{69}\] and using Theorem 1 and formula 6 , we can achieve a new proof of 68 . Multiplying 68 by \(dx/x^{j+1}\) and taking the residue at \(x=0\), we obtain

\[\begin{align} n_{g}(3^{2j}) =72^j (2j)! \sum_{m=0}^j\sum_{\ell=g-1}^{5g-5} \frac{(\ell-1)_m}{2^{m+\ell} m!} \binom{\frac{3j}{2}-1}{j-m} r_{g,\ell}\,.\label{triformula3} \end{align}\tag{70}\]

Another direct consequence of Theorem 1 is that for \(g\geq2\), the genus \(g\) free energy \(\mathcal{F}^{\{3\}}_g(x)\) can be written in the form \[\label{triFform2} \mathcal{F}^{\{3\}}_g(x)=\sum_{k=1}^{5g-5}\frac{b_{g,k}}{(1-108w)^{k}} +\sum_{\ell=1}^{2g-2}\frac{b'_{g,k}}{w^{k}}\,,\tag{71}\] where \(b_{g,1},\dots,b_{g,5g-5},b'_{g,1},\dots,b'_{g,2g-2}\) are rational numbers.

Finally, introduce \(p=p(x)\) by \[\label{tripchange} p=\frac{108w}{1-108w}\,.\tag{72}\]

Corollary 1. For \(g=1\), \[\label{triF1inq} \mathcal{F}^{\{3\}}_1 =-\frac{1}{12}\log x+\frac{1}{24} \log \biggl(\frac{p+3}{3}\biggr)+\zeta'(-1)\,.\qquad{(5)}\] For \(g\geq 2\), \(\mathcal{F}^{\{3\}}_g(x)\) admits an expression of the form \[\label{triFform3} x^{2g-2}\mathcal{F}^{\{3\}}_g(x)=\frac{B_{2g}}{4g(g-1)} +\sum_{m=1}^{5g-5} c_{g,m} \, p^m\,,\qquad{(6)}\] where \(c_{g,1}, \dots, c_{g,5g-5}\) are rational numbers; moreover, \(c_{g,1}=\cdots=c_{g,2g-2}=0\).

Proof. By using 46 and 72 , one can prove \[\label{trlogdxInp} x^k \partial_x^{k} (\log w) =-(k-1)!+\sum_{\ell=0}^{k-1}G_{k,\ell} p^{k+\ell} \,,\quad k\ge1\,,~ G_{k,0},\dots,G_{k,k-1}\in \mathbb{Q}\,.\tag{73}\] Then by using Theorem 1 and 6 , we obtain ?? , ?? . For \(g\ge2\), recalling \(x^{2g-2}\mathcal{F}^{\{3\}}_g-\frac{B_{2g}}{4g(g-1)}\in x^{2g-1}\mathbb{Q}[[x]]\) and noticing \(p\in x\mathbb{Q}[[x]]\), we find \(c_{g,1}=\cdots=c_{g,2g-2}=0\). ◻

Explicitly, \[\begin{align} &\mathcal{F}^{\{3\}}_2 =\frac{1}{x^2}\biggl(-\frac{1}{240}+\frac{7 p^5}{12960}+\frac{29 p^4}{10368}+\frac{35 p^3}{10368}\,\biggr)\,, \nonumber\\ &\mathcal{F}^{\{3\}}_3 =\frac{1}{x^4}\biggl(\frac{1}{1008}+\frac{245 p^{10}}{1679616}+\frac{965 p^9}{559872}+\frac{2945 p^8}{373248}+\frac{813587 p^7}{47029248}+\frac{29969 p^6}{1679616}+\frac{5005 p^5}{746496}\biggr) \,. \nonumber \end{align}\] Multiplying ?? by \(dx/x^{j+1}\) and taking the residue at \(x=0\), we obtain for \(g\ge2\) \[\begin{align} n_{g}(3^{2j})=108^j (2j)!\sum_{\ell=2g-1}^{j} c_{g,\ell}\sum_{m=0}^{j-\ell} \frac{(\frac{3j}{2}-m)_m }{m!}\frac{(\frac{j}{2}+1)_{j-\ell-m}}{(j-\ell-m)!}(-3)^{-j+\ell+m} \label{triformula2} \end{align}\tag{74}\] (\(c_{g,\ell}\) are defined as 0 if \(\ell>5g-5\)).

4 On quadrangulations and \((2\nu)\)-angulations↩︎

In this section we prove Theorem 2.

Taking \({\boldsymbol{s}}={\boldsymbol{1}}_4\) in 26 and 28 , we have \[\begin{align} &V^{\{4\}}(x,\epsilon)\equiv 0 \,,\\ & 4 \, W^{\{4\}}(x,\epsilon)(W^{\{4\}}(x,\epsilon)+W^{\{4\}}(x+\epsilon,\epsilon)+W^{\{4\}}(x-\epsilon,\epsilon)) \,-\, W^{\{4\}}(x,\epsilon) + x = 0 \label{differencequad} \end{align}\tag{75}\] (cf. also e.g. [7], [34], [46]). Substituting 23 in 75 , we find \(w=W^{\{4\}}_0(x)\) satisfies 14 , and for \(g\geq1\), \[\label{wgrec} W^{\{4\}}_{g} = \frac{4}{1-24 w} \Biggl(\sum_{g_2=1}^{g-1} W^{\{4\}}_{g_2} W^{\{4\}}_{g-g_2}+2 \sum_{0\leq g_1,g_2\leq g-1, \, j\geq0 \atop g_1+g_2+j=g} \frac{1}{(2j)!} W^{\{4\}}_{g_2} \partial_x^{2j}(W^{\{4\}}_{g_1})\Biggr)\,.\tag{76}\] From equation 14 we get \[\label{quaddw} \partial_x=\frac{1}{1-24 w}\partial_{w}\,.\tag{77}\]

Lemma 3. For \(k\geq 1\), \[\label{quaddxk} \partial_x^k = \sum_{i=1}^k \frac{\widetilde{T}_{k,i}}{(1-24w)^{2k-i}}\partial_{w}^i\,,\tag{78}\] where \(\widetilde{T}_{k,1},\dots,\widetilde{T}_{k,k}\) are rational numbers.

Proof. For \(k=1\), formula 78 is given by 77 . Suppose that 78 is true for \(k=m\) with \(\widetilde{T}_{k,i}\) being rational numbers. Then for \(k=m+1\), we have \[\partial_x^{m+1}=\partial_x\circ\partial_x^{m}= \frac{1}{1-24 w}\partial_{w} \circ \sum_{i=1}^{m}\frac{\widetilde{T}_{m,i}}{(1-24w)^{2m-i}}\partial_{w}^i\nonumber\\ =\sum_{i=1}^{m+1}\frac{\widetilde{T}_{m+1,i}}{(1-24w)^{2m+2-i}}\partial_{w}^i\,.\] Here \[\widetilde{T}_{m,i}=24(2m-i)\widetilde{T}_{m,i}+\widetilde{T}_{m,i-1}\,,\] where \(\widetilde{T}_{m,0}\) and \(\widetilde{T}_{m,m+1}\) are defined as 0. Obviously \(\widetilde{T}_{m,i}\) are rational numbers. By mathematical induction the lemma is proved. ◻

Proposition 3. For \(g\geq 1\), \(W^{\{4\}}_{g}(x)\) is given by \[\label{quadansatzOfSol} W^{\{4\}}_{g}(x)=\frac{w\,P_g(w)}{(1-24w)^{5g-1}}\Bigl|_{w=w(x)}\Bigr.\,,\qquad{(7)}\] for some polynomial \(P_g(z)\). Moreover, \(\deg P_g(w)\leq g-1\).

Proof. For \(g=1\), formula 76 gives \[W^{\{4\}}_{1}(x)=4\frac{W^{\{4\}}_{0}(x)\,\partial_x^2 (W^{\{4\}}_{0}(x))}{1-24W^{\{4\}}_{0}(x)}=\frac{96\,w}{(1-24 w)^4}\Big|_{w=w(x)}\,,\] thus ?? holds. Suppose that ?? holds for \(g\leq m\) with \(\deg P_g(w)\leq g-1\). Then for \(g=m+1\), by using Lemma 3 in the \(g=m+1\) equation of 76 , we obtain \[W^{\{4\}}_{m+1}(x)=\frac{w\,P_{m+1}(w)}{(1-24w)^{5m+4}}\Bigl|_{w=w(x)}\Bigr.\,,\] where \(P_{m+1}(w)\) is a polynomial of \(w\) with \(\deg P_{m+1}(w)\leq g-1\). By mathematical induction the proposition is proved. ◻

Proposition 3 says that \[\label{quadW} W^{\{4\}}(x,\epsilon)=w+\sum_{g\geq 1}\epsilon^{2g}\sum_{\ell=4g-1}^{5g-1}\frac{\widetilde{A}_{g,\ell}}{(1-24w)^{\ell}}\,,\tag{79}\] for some rational numbers \(\widetilde{A}_{g,4g-2}, \dots, \widetilde{A}_{g,5g-1}\). Substituting 79 in 75 , we find that \(U=2^{\frac{11}{5}}3^{\frac{4}{5}}\sum_{g\geq 0}\widetilde{A}_{g,5g-1}(2^{\frac{8}{5}}3^{\frac{2}{5}}X)^{\frac{1-5g}{2}}\) again satisfies the Painlevé I equation 11 . Therefore, \[\widetilde{A}_{g,5g-1} =\frac{48^g}{24}C_g\,, \quad g\geq 1\,,\] where \(C_g\) is again the same universal constant as we found for triangulations 51 .

Taking \({\boldsymbol{s}}={\boldsymbol{1}}_4\) in 22 , we have \[\log W^{\{4\}}(x,\epsilon) = \mathcal{F}^{\{4\}}(x+\epsilon,\epsilon) + \mathcal{F}^{\{4\}}(x-\epsilon,\epsilon) \,-\, 2 \, \mathcal{F}^{\{4\}}(x,\epsilon) \,. \label{quadWF}\tag{80}\] Similar to 53 , we have \[\begin{align} \label{quadwf} &\mathcal{F}^{\{4\}}(x,\epsilon) = \frac{1}{\epsilon^2 \, \partial_x^2} \, \sum_{k\geq 0} \frac{(1-2k) B_{2k}}{(2k)!} \, \epsilon^{2k}\partial_x^{2k} \bigl( \log W^{\{4\}}(x,\epsilon) \bigr) \,. \end{align}\tag{81}\]

Proof of Theorem 2. The \(g=0\) case has been proved above (cf. also 29 , [16] or [20]). For \(g=1\), the statement can be verified directly using 76 (cf. also 3031 or 33 ). For \(g\ge2\), substituting 23 in 81 and using ?? , we obtain \[\begin{align} \label{quadFgansatz1} \mathcal{F}^{\{4\}}_g=& \frac{1-2g}{(2g)!}B_{2g}\partial_x^{2g-2}(\log w)\nonumber\\ &+ \sum_{k=1}^{g-1} \frac{1-2k}{(2k)!}B_{2k}\partial_x^{2k-2} \biggl(\sum_{\ell=1}^{g-k}\frac{(-1)^{\ell-1}}{\ell (1-24w)^{5g-5k-\ell}} \sum_{m_1,\dots,m_{\ell}\geq 1\atop m_1+\cdots+m_{\ell}=g-k}\prod_{i=1}^{\ell}P_{m_i}(w)\biggr)\nonumber\\ &+\partial_x^{-2} \biggl(\sum_{\ell=1}^{g}\frac{(-1)^{\ell-1}}{\ell (1-24w)^{5g-\ell}} \sum_{m_1,\dots,m_{\ell}\geq 1\atop m_1+\cdots+m_{\ell}=g}\prod_{i=1}^{\ell}P_{m_i}(w)\biggr)\nonumber\\ =&\frac{1-2g}{(2g)!}B_{2g}\partial_x^{2g-2}(\log w) +\sum_{\ell=4g-4}^{5g-5}\frac{ \tilde{a}_{g,\ell}}{(1-24w)^{\ell}} +\alpha_g w(1-12w)+\beta_g\,. \end{align}\tag{82}\] Here \(\tilde{a}_{g,4g-4},\dots, \tilde{a}_{g,5g-5}\) are rational numbers and \(\alpha_g, \beta_g\) are integration constants. Using \(\partial_x (\log w)=\frac{1}{(1-24 w) w}\) and 77 we can prove by induction on \(k\) that for \(k\geq 1\), \[\partial_x^k (\log w) = O(w^{-2k})\,, \quad w \to \infty\,.\] Then from 30 (cf. [20]) we know that \(\mathcal{F}^{\{4\}}_g \to 0\) as \(w\to\infty\). Therefore, \(\alpha_g=\beta_g=0\). ◻

Multiplying both sides of 15 by \(dx/x^{3-2g+k}\) and taking the residue at \(x=0\), we obtain \[\begin{align} n_{g}(4^k)&=\tilde{\sigma}_{g,k}+12^{k-2g+2}k! \sum_{m=0}^{k-2g+2}\binom{2k-4g+4-m}{k-2g+2-m}\Bigl(\sum_{\ell=4g-4}^{5g-5}\tilde{a}_{g,\ell}(\ell-1)_m\Bigr)\frac{2^m}{m!}\,, \end{align}\] where \(\tilde{\sigma}_{g,k}\mathrel{\vcenter{:}}= k!\mathop{\rm res}\limits_{w=0}\frac{(1-24w)dw}{w^{k-2g+3}(1-12w)^{k-2g+3}}\frac{(1-2g)B_{2g}}{(2g)!}\partial_x^{2g-2}(\log w)\).

Another direct consequence of Theorem 2 is that for \(g\geq2\), \(\mathcal{F}^{\{4\}}_g(x)\) admits the form \[\label{quadFform2} \mathcal{F}^{\{4\}}_g(x) =\sum_{k=1}^{5g-5}\frac{\tilde{b}_{g,k}}{(1-24w)^k} +\sum_{k=1}^{2g-2}\frac{\tilde{b}'_{g,k}}{w^{k}}\,,\tag{83}\] where \(\tilde{b}_{g,1},\dots,\tilde{b}_{g,5g-5},\tilde{b}'_{g,1},\dots,\tilde{b}'_{g,2g-2}\) are rational numbers satisfying \(\tilde{b}_{g,2}=\tilde{b}_{g,4}=\cdots=\tilde{b}_{g,4g-6}=0\).

Setting \[\label{quadpchange} p=\frac{24w}{1-24w}\tag{84}\] leads to the following corollary.

Corollary 2. For \(g=1\), \[\mathcal{F}^{\{4\}}_1(x) =-\frac{1}{12}\log x+\frac{1}{12} \log \biggl(\frac{p+2}{2}\biggr)+\zeta'(-1)\,.\] For \(g\geq 2\), \(\mathcal{F}^{\{4\}}_g(x)\) has the following expression: \[\label{quadFform3} x^{2g-2}\mathcal{F}^{\{4\}}_g(x) =\frac{B_{2g}}{4g(g-1)} +\sum_{m=1}^{5g-5} \tilde{c}_{g,m} \, p^m,\qquad{(8)}\] where \(\tilde{c}_{g,1}, \dots, \tilde{c}_{g,5g-5}\) are rational numbers. Moreover, \(\tilde{c}_{g,1}=\cdots=\tilde{c}_{g,2g-2}=0\).

Proof. The proof based on Theorem 2 is similar to that of Corollary 1, so is omitted. ◻

Multiplying both sides of ?? by \(dx/x^{k+1}\) and taking the residue at \(x=0\), we obtain \[\begin{align} n_{g}(4^{k})=24^k k!\sum_{\ell=2g-1}^{k} \tilde{c}_{g,\ell}\sum_{m=0}^{k-\ell} \frac{(2k-m)_m }{m!}\frac{(k+1)_{k-\ell-m}}{(k-\ell-m)!}\,(-2)^{-k+\ell+m} \end{align}\] (\(\tilde{c}_{g,\ell}\) are defined as 0 if \(\ell>5g-5\)).

Following [21], introduce \(q\) by \[\label{quadqchange} w=\frac{q-1}{12q}\,.\tag{85}\]

Corollary 3. For \(g=1\), \[\mathcal{F}^{\{4\}}_1(x) =-\frac{1}{12}\log x-\frac{1}{12}\log (2-q)+\zeta'(-1).\] For \(g\geq2\), \(\mathcal{F}^{\{4\}}_g(x)\) admits an expression of the form \[\label{quadFform4} x^{2g-2}\mathcal{F}^{\{4\}}_g(x) =\sum_{k=2g-2}^{5g-5}\frac{\tilde{r}_{g,k}}{(2-q)^{k}}\,,\qquad{(9)}\] where \(\tilde{r}_{g,2g-2},\dots,\tilde{r}_{g,5g-5}\) are rational numbers.

The proof is again omitted.

It was proved in [22] that, for any fixed \(\nu\geq 2\), the generating function \(e_g(s)\mathrel{\vcenter{:}}=\sum_{k\geq 1}\frac{n_g((2\nu)^k)}{k!}s^k\) admits the expression \[\label{Eregexpression} e_g(s)=C^{(g)}+\sum_{\ell=2g-2}^{5g-5}\frac{\tilde{r}_{g,\ell}(\nu)}{(\nu-(\nu-1)z_0)^\ell}\,, \quad g\geq 2\,.\tag{86}\] Here, \(\tilde{r}_{g,2g-2}(\nu),\dots,\tilde{r}_{g,5g-5}(\nu)\) are some rational numbers, \(C^{(g)}\) is a certain constant independent of \(\nu\), and \(z_0=z_0(s)=1+\frac{(2\nu)!}{\nu!(\nu-1)!}s+\cdots\) is the unique solution to \[\label{z0eqn} z_0=1+\frac{(2\nu)!}{\nu!(\nu-1)!}s\, z_0^{\nu}\,,\tag{87}\] Here, \(z_0(x^{\nu-1})=q(x)\). For the case when \(\nu=2\), Eynard [3] gave an expression of \(e_g(s)\), which is equivalent to 86 . Ercolani–Lega–Tippings [23] conjectured that \[\label{ELTconj} C^{(g)}=-\frac{B_{2g}}{4g(g-1)},\quad g\geq 2.\tag{88}\] By using 3 , ?? , 87 and based on 86 , we find that Ercolani–Lega–Tippings’s conjecture 88 is equivalent to Conjecture A.

Proof of Theorem A. By comparing ?? with ?? . ◻

We note that the topological recursion (see e.g. [3]) should also lead to a proof of Theorem A.

Now we use a formula from [22] to give a second proof of Theorem A. It was already shown in [22] that the \(C^{(g)}\) for any \(\nu\) satisfy the following recursion: \[\label{ErcolaniRecursive} \frac{(2g-1)!}{(2g+2)!}-\frac{(2g-1)!}{12(2g)!} +\sum_{k=2}^{g}\frac{(1-2g)_{2g-2k+2}}{(2g-2k+2)!}C^{(k)}=0\,, \quad g\geq 2\,.\tag{89}\]

A second proof of Theorem A. Define \(\widetilde{C}^{(0)}\mathrel{\vcenter{:}}=1\), \(\widetilde{C}^{(1)}\mathrel{\vcenter{:}}=1/6\), and \(\widetilde{C}^{(g)}\mathrel{\vcenter{:}}=-4g(g-1)C^{(g)}\) for \(g\geq 2\). Then it follows from 89 that \[\label{Recursive} \sum_{k=0}^g \frac{1}{(2g-2k+2)!} \frac{2k-1}{(2k)!}\widetilde{C}^{(k)} =-\frac{1}{2} \delta_{g,0}\,, \quad g\geq 0\,.\tag{90}\] For a formal variable \(y\), mutiplying 90 by \(y^g\) and summing over \(g\), we find \[\label{generatingSeries} \biggl(\sum_{\ell\geq 0}\frac{y^{2\ell+2}}{(2\ell+2)!}\biggr) \biggl(\sum_{k\geq 0}\frac{2k-1}{(2k)!}\widetilde{C}^{(k)}y^{2k-2}\biggr)=-\frac{1}{2}\,,\tag{91}\] thus \[\label{seriesStep1} \sum_{k\geq 0}\frac{2k-1}{(2k)!}\widetilde{C}^{(k)}y^{2k-2}=-(e^{\frac{y}{2}}-e^{-\frac{y}{2}})^{-2}\,.\tag{92}\] Integrating 92 with respect to \(y\) and multiplying both sides by \(y\), we find \[\begin{align} \sum_{k\geq 0}\frac{\widetilde{C}^{(k)}}{(2k)!}y^{2k}=\frac{y}{2}\frac{e^y+1}{e^y-1} =\frac{1}{2}\Bigl(\frac{y}{e^y-1}+\frac{-y}{e^{-y}-1}\Bigl)=\sum_{k\geq 0}\frac{B_{2k}}{(2k)!}y^{2k}\,. \end{align}\] Hence \(\widetilde{C}^{(g)}=B_{2g}\). Theorem A is proved. ◻

5 More on the \(b=2\nu\) case↩︎

In this section, we prove Theorem 3 and give some more discussions on the \(b=2\nu\) case.

As a particular example of equation 32 , we know that \(w\) satisfies \[\label{2nugenus0eqn} x=w-\frac{(2\nu)!}{\nu!(\nu-1)!}w^{\nu}\,.\tag{93}\] Obviously the variable \(q\) introduced in ?? is related to \(w\) by \(q=w/x\).

Lemma 4. For \(k\geq1\), we have \[\label{xdxIny} \partial_x^k (\log w) =\frac{1}{x^k}\sum_{\ell=0}^{k-1}\frac{(-1)^{k-\ell+1}e_{k,\ell}(\nu)}{(\nu-(\nu-1)q)^{k+\ell}}\,,\tag{94}\] where \(e_{k,\ell}(\nu)\in \mathbb{Z}[\nu]\), \(\ell=0,\dots,k-1\), with \(e_{k,k-1}(\nu)=(2k-3)!!\nu^{k-1}\) and \(\deg e_{k,\ell}(\nu)\leq k-1\).

Proof. For \(k=1\), the statement can be proved easily (here we recall the convention that \((-1)!!=1\)). Suppose that the statement is true for \(k=m\). Then for \(k=m+1\), we have \[\partial_x^{m+1} (\log w) =\frac{1}{x^{m+1}}\sum_{\ell=0}^{m}\frac{(-1)^{m-\ell+2}e_{m+1,\ell}(\nu)}{(\nu-(\nu-1)q)^{m+1+\ell}}\,,\] where \[\label{evenrecursiveE} e_{m+1,\ell}(\nu)=(\ell+1)e_{m,\ell+1}(\nu)+(m+\ell)(\nu+1)e_{m,\ell}(\nu)+(m+\ell-1)\nu \,e_{m,\ell-1}(\nu)\,,\tag{95}\] with \(e_{m,-2}(\nu)=e_{m,-1}(\nu)=e_{m,m}(\nu)=e_{m,m+1}(\nu)=0\). Therefore, \(e_{m+1,\ell}(\nu)\in\mathbb{Z}[\nu]\), \(\deg e_{m,\ell}(\nu)\leq m\) and \(e_{m+1,m}=(2m-1)!!\nu^m\). The lemma is proved. ◻

Using 30 , 31 and Lemma 4, we obtain \[\mathcal{F}_1^{\{2\nu\}}(x)=-\frac{1}{12}\log x-\frac{1}{12}\log (\nu-(\nu-1)q)+\zeta'(-1)\,.\]

A third proof of Theorem A. According to the Hodge–GUE correspondence [14], [20], the function \(\mathcal{F}^{\{2\nu\}}_g(x)\) is a linear combination of \(\prod_{i=1}^{\ell(\lambda)}\partial_x^{\lambda_i}(\log w)/(\partial_x(\log w))^{\ell+2g-m-1-k}\) with rational coefficients, where \(1\leq m\leq g\), \(0\leq k\leq 3m-3\), \(\ell\geq 1\), and \(\lambda\) are partitions satisfying \(\ell(\lambda)=2g-2m+\ell\), \(|\lambda|=4g-m-3-k+\ell\). From 94 we know that \[\label{vlambda} \frac{\prod_{i=1}^{\ell(\lambda)}\partial_x^{\lambda_i}(\log w)}{(\partial_x(\log w))^{\ell+2g-m-1-k}}=\frac{(\nu-(\nu-1)q)^{2-2g}}{x^{2g-2}} \sum_{0\leq s_i\leq\lambda_i-1} \frac{\prod_{i=1}^{\ell(\lambda)}(-1)^{\lambda_i-s_i+1}e_{\lambda_i,s_i}(\nu)}{(\nu-(\nu-1)q)^{|s|}}\,.\tag{96}\] Formula ?? then follows from the fact that \(-(5g-5)\leq 2-2g-|s|\leq -(2g-2)\). ◻

Proof of Theorem 3. The fact that \(r_{g,\ell}(\nu)\in \mathbb{Q}[\nu]\) follows from 96 and that \(e_{g,\ell}(\nu)\in \mathbb{Z}[\nu]\), which we proved in Lemma 4. Since \(\deg\,e_{k,\ell}(\nu)\leq k-1\), we have \[\deg\bigl(e_{\lambda_1,s_1}(\nu)\cdots e_{\lambda_{\ell(\lambda)},s_{\ell(\lambda)}}(\nu)\bigr) =|\lambda|-\ell(\lambda)=2g+m-3-k\leq 3g-3\,,\] for \(0 \leq s_i \leq\lambda_i\), \(i=1,\dots,\ell(\lambda)\). Hence \(\deg\,r_{g,\ell}(\nu)\leq 3g-3\). ◻

Similar to [28], by using Theorem A we can prove that, for \(2m-2+j>0\), \[\label{evendxFm} \partial_x^j (\mathcal{F}^{\{2\nu\}}_m(x))=\frac{1}{x^{2m-2+j}}\sum_{\ell=2m-2+j}^{5m-5+2j}\frac{r_{m,\ell,j}(\nu)}{(\nu-(\nu-1)q)^{\ell}}\,.\tag{97}\] By 22 we have \[\label{evenWstep1} W^{\{2\nu\}}_{g}(x)=w\sum_{n= 1}^{g}\frac{2^n}{n!}\sum_{k_1+m_1,\dots,k_n+m_n\geq 1 \atop |k|+|m|=g} \prod_{i=1}^{n}\frac{\partial_x^{2k_i+2}(\mathcal{F}_{m_i}^{\{2\nu\}}(x))}{(2k_i+2)!}\,,\quad g\geq 1\,.\tag{98}\] Using 97 and 98 , we obtain \[\label{evenWg} x^{2g-1} W^{\{2\nu\}}_{g}(x)=q\sum_{\ell=2g}^{5g-1}\frac{t_{g,\ell}(\nu)}{(\nu-(\nu-1)q)^{\ell}}\,, \quad g\ge1\,.\tag{99}\] Using Theorem 3, we show that \(r_{m,\ell,j}(\nu)\) are polynomials in \(\nu\) of degree at most \(3m-3+j\). Hence, we obtain:

Corollary 4. For any \(g\ge1\), \(t_{g,\ell}(\nu)\) are polynomials of \(\nu\) with \(\deg\, t_{g,\ell}(\nu)\leq 3g-1\).

We note that part of the motivation of Corollary 4 comes from [24]. Indeed, following [24], define \[Q_{g,k}(\nu) := k![x^{1-2g+(\nu-1)k}]W^{\{2\nu\}}_{g}(x)/\Bigl(\frac{(2\nu)!}{\nu!(\nu-1)!}\Bigr)^k\,.\] (As shown in [33], \(k![x^{1-2g+(\nu-1)k}]W^{\{2\nu\}}_{g}(x)\) counts the number of two-legged \(2\nu\)-valent genus-\(g\) maps with \(k\) vertices.) It then follows from ?? and 99 that \[\label{Qgk} Q_{g,k}(\nu)=k! \sum_{m=0}^k \binom{\nu k}{k-m}\frac{(\nu-1)^m}{m!}\sum_{\ell=2g}^{5g-1} t_{g,\ell}(\nu) (\ell-1)_m\,,\tag{100}\] which, together with Corollary 4, implies validity of a conjectural statement in [24] that \(Q_{g,k}(\nu)\) are polynomials in \(\nu\) of degree \(3g-1+k\).

Finally, we note that it can be deduced using Theorem A and a result of [22] that \[\label{rgCg} r_{g,5g-5}(\nu)=\frac{\nu^{3g-3}}{12^{g}}\frac{C_g}{(5g-3)(5g-5)}\,, \quad g\ge2\,,\tag{101}\] which can also be proved using the Hodge–GUE correspondence (cf. [14] and [15]) and [31]. Here \(C_g\) are defined by 11 . By 9799 and 101 we have \[t_{g,5g-1}(\nu)=\frac{\nu^{3g-1}}{12^g}C_g\,.\]

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  1. A labelled ribbon graph refers to a ribbon graph whose half-edges are labelled.↩︎