April 27, 2025
Figure 1:
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Averaging operators play a fundamental role in harmonic analysis and it is often desirable to obtain sharp estimates for them. The fractional Hardy operator is very interesting since it is a useful tool to study the embedding properties of function spaces. Mizuta et al. [1] showed that the optimal bound of fractional Hardy operator implies the sharp embedding properties of the function spaces. There is much literature on the function spaces. Let \(f\) be a locally integrable function on \(\mathbb{R} ^n\). Then the \(n\)-dimensional fractional Hardy operator and its duality from can be started as \[H_{\alpha}f\left( x \right) =\frac{1}{\left| x \right|^{n-\alpha}}\int_{\left| y \right|<\left| x \right|}{f\left( y \right)}dy,\quad H_{\alpha}^{*}f\left( x \right) =\int_{\left| y \right|>\left| x \right|}{\frac{1}{\left| y \right|^{n-\alpha}}f\left( y \right)}dy,\] where \(0<\alpha<n\), \(x\in \mathbb{R} ^n\backslash\left\{ 0\right\}\). If \(\alpha\) = 0, the fractional Hardy operator is the classic Hardy operator. There is much literature on the boundness of these operators [2]–[5]. Among them, Lu et al. [3] obtained the following estimates. Suppose \[0<\alpha <n,\quad1<p\leqslant \frac{n}{\alpha},\quad\frac{1}{p}-\frac{1}{q}=\frac{\alpha}{n}.\] Then \[\left\| H_{\alpha}f \right\| _{L^q\left( \mathbb{R} ^n \right)}\leqslant C\left\| f \right\| _{L^p\left( \mathbb{R} ^n \right)},\] where \[\left( \frac{p}{q} \right) ^{1/q}\left( \frac{p}{p-1} \right) ^{1/q}\left( \frac{q}{q-1} \right) ^{1-1/q}\left( 1-\frac{p}{q} \right) ^{1/p-1/q}\left( \frac{\omega _n}{n} \right) ^{1-\alpha /n}\leqslant C\leqslant \left( \frac{p}{p-1} \right) ^{p/q}\left( \frac{\omega _n}{n} \right) ^{1-\alpha /n}.\] If \(p=1\), then \[\left\| H_{\alpha} \right\| _{L^1\left( \mathbb{R} ^n \right) \rightarrow L^{n/\left( n-\alpha \right) ,\infty}\left( \mathbb{R} ^n \right)}=\left( \frac{\omega _n}{n} \right) ^{1-\frac{\alpha}{n}}.\] The optimal \(L^p\rightarrow L^q\) estimate was later obtained in [5]: \[\left\| H_{\alpha} \right\| _{L^p\left( \mathbb{R} ^n \right) \rightarrow L^q\left( \mathbb{R} ^n \right)}=\left( \frac{p\prime}{q} \right) ^{1/q}\left( \frac{n}{q\alpha}\cdot B\left( \frac{n}{q\alpha},\frac{n}{q^{\prime}\alpha} \right) \right) ^{-\alpha /n}\left( \frac{\omega _n}{n} \right) ^{1-\frac{\alpha}{n}},\] where \[p^{\prime}=\frac{p}{p-1},\quad q^{\prime}=\frac{q}{q-1},\] and \(B\left( \cdot ,\cdot \right)\) is the Beta function defined by \[B\left( z,\omega \right) =\int_0^1{t^{z-1}\left( 1-t \right) ^{\omega -1}dt},\] here \(z\) and \(\omega\) are complex numbers with positive real parts. Comparing with the complicated bounds in the power weighted spaces, the sharp weak bounds for \(H_{\alpha}\) and \(H_{\alpha}^{*}\) seem easier to understand. Gao and Zhao [5] set up \[\left\| H_{\alpha}^{*} \right\| _{L^1(\mathbb{R} ^n)\rightarrow L^{n/(n-\alpha ),\infty}(\mathbb{R} ^n)}=\left( \frac{\omega _n}{n} \right) ^{1-\frac{\alpha}{n}},\quad\parallel H_{\alpha}^{*}\parallel _{L^p(\mathbb{R} ^n)\rightarrow L^{q,\infty}(\mathbb{R} ^n)}\,=\left( \frac{\omega _n}{n} \right) ^{\frac{1}{q}+\frac{1}{p^{\prime}}}\bigl( \frac{q}{p^{\prime}} \bigr) ^{1/p^{\prime}}.\]
It is then a nature problem to obtain the operator norms of \(H_\alpha\) and its dual operator \(H_\alpha^*\) in corresponding power weighted spaces. For the latter, Gao et al. [6] set up \[\left\|H_\alpha^*\right\|_{L_{|x|^ \rho}^1\left(\mathbb{R}^n\right) \rightarrow L_{|x|^\beta}^{(n+\beta) /(n-\alpha+\rho), \infty}\left(\mathbb{R}^n\right)}=\left(\frac{\omega_n}{n+\beta}\right)^{(n-\alpha+\rho) /(n+\beta)},\] and \[\left\|H_\alpha^*\right\|_{L_{|x|}^p \rho}\left(\mathbb{R}^n\right) \rightarrow L_{|x| \beta}^{q, \infty}\left(\mathbb{R}^n\right)=\left(\frac{\omega_n}{n+\beta}\right)^{\frac{1}{q}+\frac{1}{p^{\prime}}}\left(\frac{q}{p^{\prime}}\right)^{1 / p^{\prime}}.\] Then Yu et al. [7] set up \[\parallel H_{\alpha}\parallel _{L_{|x|^{\rho}}^{p}(\mathbb{R} ^n)\rightarrow L_{|x|^{\beta}}^{q,\infty}(\mathbb{R} ^n)}\,=\bigl( \frac{\omega _n}{n+\beta} \bigr) ^{1/q}\biggl( \frac{\omega _n}{n-\frac{\rho}{p-1}} \biggr) ^{1/p^{\prime}},\] and \[\parallel H_{\alpha}\parallel _{L^1(\mathbb{R} ^n)\rightarrow L_{|x|^{\beta}}^{(n+\beta )/(n-\alpha ),\infty}(\mathbb{R} ^n)}\,=\bigl( \frac{\omega _n}{n+\beta} \bigr) ^{(n-\alpha )/(n+\beta )}.\]
With the rapid development of mathematics in various fields, \(p\)-adic analysis is becoming more and more important in mathematical analysis, it has attracted attention from mathematical physics and other fields [8]–[13]. The harmonic analysis on \(p\)-adic field has received high attention [14]–[17]. Inspired by them, we will study the sharp weak bound for the \(p\)-adic fractional Hardy operator from \(L^p\) to \(L^{q,\infty}\), which plays an important role in several branches of mathematics. Now, allow us to introduce some basic knowledge about the \(p\)-adic fields which will be used later.
For a prime number \(p\), let \(\mathbb{Q} _p\) be the field of \(p\)-adic numbers, which is defined as the completion of the field of rartional numbers \(\mathbb{Q}\) with respect to the non-Archimedean \(p\)-adic norm \(\left| \cdot \right|_p\). This norm is defined as follows: \(\left| 0 \right|_p=0\). If any non-zero rational number \(x\) is represented as \(x=p^{\gamma}\frac{m}{n}\), where \(m\) and \(n\) are integers which are not divisible by \(p\), and \(\gamma\) is an integer. then \(\left| x \right|_p=p^{-\gamma}\). It is not difficult to show that the norm satisfies the following properties \[\left| xy \right|_p=\left| x \right|_p\left| y \right|_p,\quad\left| x+y \right|_p\leqslant \max \{ \left| x \right|_p,\left| y \right|_p \}\] and \[| \left| x \right|_py |_p=\left| x \right|_{p}^{-1}\left| y \right|_p,\quad x\in \mathbb{Q} _{p}^{n}.\] It follows from the second property that when \(\left| x \right|_p\ne \left| y \right|_p\), then \(\left| x+y \right|_p=\max \{ \left| x \right|_p,\left| y \right|_p \}\). From the standard \(p\)-adic analysis [13], we see that any non-zero \(p\)-adic number \(x\in \mathbb{Q} _p\) can be unique represented in the canonical series \[\begin{align} x=p^{\gamma}\sum_{j=0}^{\infty}{a_jp^j},\quad\gamma =\gamma \left( x \right) \in \mathbb{Z}, \end{align}\] where \(a_j\) are integers, \(0\leqslant a_j\leqslant p-1,a_0\ne 0\). The series (1.1) converges in the \(p\)-adic norm because \(\left| a_jp^j \right|_p=p^{-\gamma}\). The space \(\mathbb{Q} _{p}^{n}\) consists of points \(x=\left( x_1,x_2,...,x_n \right)\), where \(x_j\in \mathbb{Q} _p\), \(j=1,...,2\). The \(p\)-aidc norm on \(\mathbb{Q} _{p}^{n}\) is \[\left| x \right|_p:=\underset{1\leqslant j\leqslant n}{\max}\left| x_j \right|_p.\] Denoted by \(B_{\gamma}=\{ x\in \mathbb{Q} _{p}^{n}:\left| x-a \right|_p\leqslant p^{\gamma} \}\), the ball with center at \(a\in \mathbb{Q} _p\) and radius \(p^{\gamma}\), and by \(S_{\gamma}\left( a \right) :=\left\{ x\in \mathbb{Q} _{p}^{n}:|x-a|_p=p^{\gamma} \right\}\) the sphere with center at \(a\in \mathbb{Q} _{p}^{n}\) and radius \(p^{\gamma}\), \(\gamma \in \mathbb{Z}\). it is clear that \(S_{\gamma}\left( a \right) =B_{\gamma}\left( a \right) \backslash B_{\gamma -1}\left( a \right)\) and
\[B_{\gamma}\left( a \right) =\bigcup_{k\leqslant \gamma}{S_k\left( a \right)},\quad \{ x\in \mathbb{Q} _{p}^{n}:\left| x-a \right|_p<p^{\gamma} \} =\bigcup_{k<\gamma}{S_k\left( a \right)}.\] We set \(B_{\gamma}\left( 0 \right) =B_{\gamma}\) and \(S_{\gamma}\left( 0 \right) =S_{\gamma}\). Since \(\mathbb{Q} _{p}^{n}\) is a locally compact commutative group under addition, it follows from the standard analysis that there exists a unique Haar measure \(d\)x on \(\mathbb{Q} _{p}^{n}\)(up to positive constant multiple) which is translation invariant.We normalize the measure \(dx\) so that \[\int_{B_0\left( 0 \right)}{dx}=\left| B_0\left( 0 \right) \right|_H=1.\] Where \(\left| E \right|_H\) denotes the Haar measure of a measurable subset \(E\) of \(\mathbb{Q} _{p}^{n}\). From this integral theory, it is easy to obtain that \(\left| B_{\gamma}\left( a \right) \right|_H=p^{\gamma n}\) and \(\left| S_{\gamma}\left( a \right) \right|_H=p^{\gamma n}\left( 1-p^{-n} \right)\) for any \(a\in \mathbb{Q} _{p}^{n}\). For a more complete introduction to \(p\)-adic field, see [18].
To get the main conclusion, it is necessary to introduce some fundamental knowledge and definitions. These operators and spaces are the \(p\)-adic \(n\)-dimensional fractional Hardy operator, \(p\)-adic \(m\)-linear \(n\)-dimensional Hardy operator, \(p\)-adic \(m\)-linear \(n\)-dimensional Hilbert operator and \(p\)-adic \(m\)-linear \(n\)-dimensional Hausdorff operator, \(p\)-adic weighted \(L^p\), \(p\)-adic weighted \(L^{q,\infty}\) and \(p\)-adic weighted-type space \(H_{\alpha}^{\infty}( \mathbb{Q} _{p}^{n} )\).
Definition 1. Let \(f\) be a nonnegative locally integrable function on \(\mathbb{Q}^{n}_{p}\), \(0<\alpha <n\). The \(p\)-adic \(n\)-dimensional fractional Hardy operator is defined by \[\begin{align} \mathcal{H} _{\alpha}f\left( x \right) =\frac{1}{|x|_{p}^{n-\alpha}}\int_{|y|_p<|x|_p}{f\left( y \right) dy,} \end{align}\] where \(x\in \mathbb{Q}^{n}_{p}\backslash\left\{ 0\right\}\).
Definition 2. Let \(1\leqslant p<\infty\). The \(p\)-adic Lebesgue space \(L^p\left( \mathbb{Q} ^{n}_{p}\right)\) is defined by \[L^p\left( \mathbb{Q} ^{n}_{p}\right) =\{ f\in L_{loc}^{p}:\left\| f \right\| _{L^p\left( \mathbb{Q} ^{n}_{p} \right)}<\infty \},\] where \[\begin{align} \left\| f \right\| _{L^p\left( \mathbb{Q} ^{n}_{p} \right)}=\left( \int_{\mathbb{Q} ^{n}_{p}}{\left| f\left( x \right) \right|^p dx} \right) ^{1/p}. \end{align}\]
Definition 3. Let \(\omega : \mathbb{Q} ^{n}_{p}\rightarrow \left( 0,\infty \right)\) be a positive measurable function, \(1\leqslant p<\infty\). The \(p\)-adic weighted Lebesgue space \(L^p\left( \mathbb{Q} ^{n}_{p},\omega \right)\) is defined by \[L^p\left( \mathbb{Q} _{p}^{n},\omega \right) =\{f\in L_{loc}^{p}:\left\| f \right\| _{L^p\left( \mathbb{Q} _{p}^{n},\omega \right)}<\infty \},\] where \[\begin{align} \left\| f \right\| _{L^p\left( \mathbb{Q} _{p}^{n},\omega \right)}=\left( \int_{\mathbb{Q} _{p}^{n}}{\left| f\left( x \right) \right|^p\omega \left( x \right) dx} \right) ^{1/p}. \end{align}\]
Definition 4. Let \(\omega : \mathbb{Q} ^{n}_{p}\rightarrow \left( 0,\infty \right)\) be a positive measurable function, \(1\leqslant p<\infty\). The weighted \(p\)-adic weak type Lebesgue space \(L^p\left( \mathbb{Q} ^{n}_{p},\omega \right)\) is defined by \[L^{q,\infty}\left( \mathbb{Q} ^{n}_{p},\omega \right) =\left\{ f\in L_{loc}^{p}:\left\| f \right\| _{L^{q,\infty}\left( \mathbb{Q} ^{n}_{p},\omega \right)}<\infty \right\} ,\] where \[\begin{align} \left\| f \right\| _{L^{q,\infty}\left( \mathbb{Q} ^{n}_{p},\omega \right)}=\underset{\lambda >0}{\mathrm{sup}}\,\lambda \left( \int_{\mathbb{Q} ^{n}_{p}}{\chi _{\left\{ x:f\left( x \right) >\lambda \right\}}\left( x \right) \omega \left( x \right) dx} \right) ^{1/q}. \end{align}\]
Definition 5. Let \(m\) be a positive integer and \(f_1,\dots,f_m\) be nonnegative locally integrable functions on \(\mathbb{Q}_p^n\). The \(p\)-adic \(m\)-linear \(n\)-dimensional Hardy operator is defined by \[\begin{align} T_{1}^{p}\left( f_1,...,f_m \right) \left( x \right) =\frac{1}{\left| x \right|_{p}^{mn}}\int_{\left| \left( y_1,...,y_m \right) \right|_p\leqslant \left| x \right|_p}{f_1\left( y_1 \right) \cdots f_m\left( y_m \right) dy_1\cdots dy_m}, \end{align}\] where \(x\in \mathbb{Q}_p^n\backslash\left\{ 0\right\}\).
Definition 6. Let \(m\) be a positive integer and \(f_1,\dots,f_m\) be nonnegative locally integrable functions on \(\mathbb{Q}_p^n\). The \(p\)-adic \(m\)-linear \(n\)-dimensional Hilbert operator is defined by \[\begin{align} T_{2}^{p}\left( f_1,...,f_m \right) \left( x \right) =\int_{\mathbb{Q} _{p}^{n}}{\cdots}\int_{\mathbb{Q} _{p}^{n}}{\frac{f_1\left( y_1 \right) \cdots f_m\left( y_m \right)}{( \left| x \right|_{p}^{n}+\left| y_1 \right|_{p}^{n}+\cdots +\left| y_m \right|_{p}^{n} ) ^m}}dy_1\cdots dy_m, \end{align}\] where \(x\in \mathbb{Q}_p^n\backslash\left\{ 0\right\}\).
Definition 7. Let \(m\) be a positive integer, \(f_1,\dots,f_m\) be nonnegative locally integrable functions on \(\mathbb{Q}_p^n\), and \(\Phi\) be a nonnegative function on \(\mathbb{Q}_p^n\). The \(p\)-adic \(m\)-linear \(n\)-dimensional Hausdorff operator is defined by \[\begin{align} T_{\Phi}^{p}\left( f_1,...,f_m \right) \left( x \right) =\int_{\mathbb{Q} _{p}^{n}}{\cdots}\int_{\mathbb{Q} _{p}^{n}}{\frac{\Phi ( x/\left| y_1 \right|_p,...,x/\left| y_m \right|_p )}{\left| y_1 \right|_{p}^{n}\cdots \left| y_m \right|_{p}^{n}}}f_1\left( y_1 \right) \cdots f_m\left( y_m \right) dy_1\cdots dy_m, \end{align}\] where \(x\in \mathbb{Q}_p^n\backslash\left\{ 0\right\}\).
We present the definition of the weighted \(p\)-adic space \(H_{\alpha}^{\infty}( \mathbb{Q} _{p}^{n} )\) on \(\mathbb{Q} _{p}^{n}\), where \(\left| x \right|_{p}^{\alpha}\): \(\mathbb{Q} _{p}^{n}\rightarrow \left( 0,\infty \right)\) are positive measurable functions.
Definition 8. The \(p\)-adic weighted-type space \(H_{\alpha}^{\infty}( \mathbb{Q} _{p}^{n} )\) with \(\alpha>0\) consist of all measurable functions \(f\) satisfying \[\begin{align} \left\| f \right\| _{H_{\alpha}^{\infty}( \mathbb{Q} _{p}^{n} )}:=\mathrm{ess} \underset{x\in \mathbb{Q} _{p}^{n}}{\mathrm{sup}}\left| x \right|_{p}^{\alpha}\left| f\left( x \right) \right|<\infty. \end{align}\]
The function \(\left\| \cdot \right\| _{H_{\alpha}^{\infty}( \mathbb{Q} _{p}^{n})}\) is a norm on the space. Weighted-type spaces on various domains frequently appear in the literature and are quite suitable for invertigations, see [19].
Computation of the operator norm of integral operators is a challenging work in harmonic analysis. Batbold and Sawano [20] obtained that the norm of \(T_1^p\) on \(p\)-adic Lebesgue spaces and \(p\)-adic Morrey spaces, that is \[\left\| T_1^p \right\| _{L^{q_1}\left( \mathbb{Q} _p,\left| x \right|_{p}^{\alpha _1q_1/q} \right) \times \cdots \times L^{q_m}\left( \mathbb{Q} _p,\left| x \right|_{p}^{\alpha _mq_m/q} \right) \rightarrow L^q\left( \mathbb{Q} _p,\left| x \right|_{p}^{\alpha} \right)}=\frac{\left( 1-p^{-1} \right) ^m}{\prod\nolimits_{j=1}^m{( 1-p^{\left( 1/q_j \right) +\left( a_j/q \right) -1} )}}\] and \[\left\| T_1^p \right\| _{L^{q_1,\lambda _1}\left( \mathbb{Q} _p,\left| x \right|_{p}^{\beta _1q_1/q} \right) \times \cdots \times L^{q_m,\lambda _m}\left( \mathbb{Q} _p,\left| x \right|_{p}^{\beta _mq_m/q} \right) \rightarrow L^{q,\lambda}\left( \mathbb{Q} _p,\left| x \right|_{p}^{\beta} \right)}=\frac{\left( 1-p^{-1} \right) ^m}{\prod\nolimits_{i=1}^m{( 1-p^{\delta _i} )}}.\] Duong and Hong [21] obtained the norm of Multilinear Hausdorff operator on \(p\)-adic function space. In 2017, Batbold and Sawano [22] studied the one-dimensional \(m\)-linear Hilbert-type operators that includes Hardy-Littlewood-Pólya operator on weighted Morrey spaces, and they obtained the sharp bounds. Later, He et al [23] extended the results in [22] and obtain the sharp bound for the generalized Hardy-Littlewood-Pólya operator on power weighted central and noncentral homogenous Morrey space. In 2011, Wu and Fu [24] got the best estimate of the \(m\)-linear \(p\)-adic Hardy operator on Lebesgue spaces with power weights weights.
Inspired by the above, we first study the sharp estimate for the \(p\)-adic \(n\)-dimensional fractional Hardy operator from \(L^p\) to \(L^{q,\infty}\). Secondly, we study a more general operator which includes the \(p\)-adic Hardy and Hilbert operator as a special case and consider their operator norm on \(p\)-adic weighted function space. Finally, we also find the sharp bound for the \(p\)-adic Hausdorff operator on \(p\)-adic weighted function space, which generalizes the previous results.
In this section, we will study the \(p\)-adic weighted \(L^p\) estimate for the \(p\)-adic fractional Hardy operator. For the \(p\)-adic \(n\)-dimensional fractional Hardy operator, our results have a restricted condition: \(\beta =0\) when \(p_1=1\) and \(\beta>0\) when \(p_1>1\). Removing this restrictive condition requires a more complicated argument, and it will be presented in a paper.
Theorem 1. Let \(1<p_1<\infty\), \(1\leqslant q<\infty\), \(\beta <n\left( p_1-1 \right)\), \(n+\gamma >0\), \(0\leqslant\alpha <\frac{\beta}{p_1-1}\), and \(\frac{1}{p_1}+\frac{1}{p_{1}^{\prime}}=1\).
If \[\frac{\gamma +n}{q}+\alpha =\frac{\beta +n}{p_1},\]
then \[\begin{align} \left\| \mathcal{H} _{\alpha} \right\| _{L^{p_1}(\mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\beta})\rightarrow \,\,L^{q,\infty}(\mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\gamma})}=\left( \frac{\left( 1-p^{-n} \right) p^{-n-\gamma}}{1-p^{-n-\gamma}} \right) ^{\frac{1}{q}}\left( \frac{\left( 1-p^{-n} \right) p^{\frac{\beta}{p_1-1}-n}}{1-p^{\frac{\beta}{p_1-1}-n}} \right) ^{\frac{1}{p_{1}^{\prime}}}. \end{align}\]
Theorem 2. Let \(n+\gamma >0\), and \(0<\alpha <n\). Then \[\begin{align} \left\| \mathcal{H} _{\alpha} \right\| _{L^1\left( \mathbb{Q} _{p}^{n} \right) \rightarrow L^{\left( n+\gamma \right) /\left( n-\alpha \right) ,\infty}\left( \mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\gamma} \right)}=\left( \frac{\left( 1-p^{-n} \right)}{\left( 1-p^{-n-\gamma} \right) p^{n+\gamma}} \right) ^{\frac{n-\alpha}{n+\gamma}}. \end{align}\]
Proof of Theorem 1:. Noticing \(n-\frac{\beta}{p_1-1}>n-\frac{n\left( p_1-1 \right)}{p_1-1}=0\), by \(\mathrm{H}\ddot{\mathrm{o}}\mathrm{lder}\)’s inequality, we have \[\begin{align} |\mathcal{H} _{\alpha}f\left( x \right) | &=\left| \frac{1}{|x|_{p}^{n-\alpha}}\int_{|y|_p<|x|_p}{f\left( y \right) dy} \right|=\left|\frac{1}{|x|_{p}^{n-\alpha}}\int_{|y|_p<|x|_p}{|y|_{p}^{-\frac{\beta}{p_1}}f\left( y \right) |y|_{p}^{\frac{\beta}{p_1}}dy} \right| \\ &\leqslant \frac{1}{|x|_{p}^{n-\alpha}}\left( \int_{|y|_p<|x|_p}{|y|_{p}^{-\frac{\beta p_{1}^{\prime}}{p_1}}dy} \right) ^{\frac{1}{p_{1}^{\prime}}}\left( \int_{|y|_p<|x|_p}{\left| f\left( y \right) \right|^{p_1}\left| y \right|_{p}^{\beta}dy} \right) ^{\frac{1}{p_1}} \\ &\leqslant \frac{1}{|x|_{p}^{n-\alpha}}\left( \sum_{i=-\infty}^{\log _p|x|_p-1}{\int_{S_i}{\left| y \right|_{p}^{-\frac{\beta p_{1}^{\prime}}{p_1}}dy}} \right) ^{\frac{1}{p_{1}^{\prime}}}\left( \int_{\mathbb{Q} _{p}^{n}}{\left| f\left( y \right) \right|^{p_1}\left| y \right|_{p}^{\beta}dy} \right) ^{\frac{1}{p_1}} \\ &=|x|_{p}^{\alpha -n}\times \left( \sum_{i=-\infty}^{\log _p|x|_p-1}{p^{-\frac{i\beta p_{1}^{\prime}}{p_1}}\int_{S_i}{dy}} \right) ^{\frac{1}{p_{1}^{\prime}}}\left\| f \right\| _{L^{p_1}(\mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\beta})} \\ &=|x|_{p}^{\alpha -n}\left( \left( 1-p^{-n} \right) \sum_{i=-\infty}^{\log _p|x|_p-1}{p^{i(n-\frac{\beta}{p_1-1})}} \right) ^{\frac{1}{p_{1}^{\prime}}}\left\| f \right\| _{L^{p_1}(\mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\beta})} \\ &=\left( \frac{\left( 1-p^{-n} \right) p^{\frac{\beta}{p_1-1}-n}}{1-p^{\frac{\beta}{p_1-1}-n}} \right) ^{\frac{1}{p_{1}^{\prime}}}\left\| f \right\| _{L^{p_1}(\mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\beta})}\left| x \right|_{p}^{-\frac{n}{p_1}-\frac{\beta}{p_1}+\alpha}=C_{p_1,n,\beta ,f}\left| x \right|_{p}^{-\frac{n}{p_1}-\frac{\beta}{p_1}+\alpha}, \end{align}\] where \[C_{p_1,n,\beta ,f}=\left( \frac{\left( 1-p^{-n} \right) p^{\frac{\beta}{p_1-1}-n}}{1-p^{\frac{\beta}{p_1-1}-n}} \right) ^{\frac{1}{p_{1}^{\prime}}}\left\| f \right\| _{L^{p_1}(\mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\beta})}.\]
Noticing \(|\mathcal{H} _{\alpha}f\left( x \right) |\leqslant C_{p_1,n,\beta ,f}\left| x \right|_{p}^{-\frac{n}{p_1}-\frac{\beta}{p_1}+\alpha}\), we have \(\left\{ x:|\mathcal{H} _{\alpha}f\left( x \right) |>\lambda \right\} \subset \{ x:C_{p_1,n,\beta ,f}\left| x \right|_{p}^{-\frac{n}{p_1}-\frac{\beta}{p_1}+\alpha}>\lambda \}\).
Since \[n+\gamma >0 \,\,\,\text{and} \,\,\,\frac{\gamma +n}{q}+\alpha =\frac{\beta +n}{p_1},\] we have \[\begin{align} \left\| \mathcal{H} _{\alpha}f \right\| _{L^{q,\infty}(\mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\gamma})} &=\underset{\lambda >0}{\mathrm{sup}}\,\,\lambda \left( \int_{\mathbb{Q} _{p}^{n}}{\chi _{\left\{ x:|\mathcal{H} _{\alpha}f\left( x \right) |>\lambda \right\}}\left( x \right) \left| x \right|_{p}^{\gamma}dx} \right) ^{\frac{1}{q}} \\ &\leqslant \underset{\lambda >0}{\mathrm{sup}}\,\,\lambda \left( \int_{\mathbb{Q} _{p}^{n}}{\chi _{\{x:C_{p,n,\beta ,f}\left| x \right|_{p}^{-\frac{Q}{p_1}-\frac{\beta}{p_1}+\alpha}>\lambda \}}\left( x \right) \left| x \right|^{\gamma}_pdx} \right) ^{\frac{1}{q}} \\ &=\underset{\lambda >0}{\mathrm{sup}}\,\,\lambda \left( \int_{|x|_p<(\frac{C_{p_1,n,\beta ,f}}{\lambda})^{\frac{q}{n+\gamma}}}{\left| x \right|_{p}^{\gamma}dx} \right) ^{\frac{1}{q}}=\underset{\lambda >0}{\mathrm{sup}}\,\,\lambda \left( \prod_{i=-\infty}^{\log _p(\frac{C_{p_1,n,\beta ,f}}{\lambda})^{\frac{q}{n+\gamma}}-1}{p^{i\gamma}\int_{S_i}{dx}} \right) ^{\frac{1}{q}} \\ &=\underset{\lambda >0}{\mathrm{sup}}\,\,\lambda \left( \frac{\left( 1-p^{-n} \right) \left( C_{p_1,n,\beta ,f}/\lambda \right) ^q}{\left( 1-p^{-n-\gamma} \right) p^{n+\gamma}} \right) ^{\frac{1}{q}}=\,\,C_{p_1,n,\beta ,f}\times \left( \frac{\left( 1-p^{-n} \right)}{\left( 1-p^{-n-\gamma} \right) p^{n+\gamma}} \right) ^{\frac{1}{q}} \\ &=\left( \frac{\left( 1-p^{-n} \right)}{\left( 1-p^{-n-\gamma} \right) p^{n+\gamma}} \right) ^{\frac{1}{q}}\left( \frac{\left( 1-p^{-n} \right) p^{\frac{\beta}{p_1-1}-n}}{1-p^{\frac{\beta}{p_1-1}-n}} \right) ^{\frac{1}{p_{1}^{\prime}}}\left\| f \right\| _{L^{p_1}(\mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\beta})}. \end{align}\] Thus \[\left\| \mathcal{H} _{\alpha} \right\| _{L^{p_1}\left( \mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\beta} \right) \rightarrow L^{q,\infty}\left( \mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\gamma} \right)}\leqslant \left( \frac{\left( 1-p^{-n} \right)}{\left( 1-p^{-n-\gamma} \right) p^{n+\gamma}} \right) ^{\frac{1}{q}}\left( \frac{\left( 1-p^{-n} \right) p^{\frac{\beta}{p_1-1}-n}}{1-p^{\frac{\beta}{p_1-1}-n}} \right) ^{\frac{1}{p_{1}^{\prime}}}.\] On the other hand, let \[f_0\left( x \right) =|x|_{p}^{-\frac{\beta}{p_1-1}}\chi _{\{x:\left| x \right|_p<1\}}\left( x \right) .\] Noticing \(n+\beta ( 1-\frac{p_1}{p_1-1} ) =n-\frac{\beta}{p_1-1}>0\), we have \[\begin{align} \left\| f_0 \right\| _{L^{p_1}(\mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\beta})} &=\left( \int_{\mathbb{Q} _{p}^{n}}{|\left| x \right|_{p}^{-\frac{\beta}{p_1-1}}\chi _{\{x:\left| x \right|_p<1\}}\left. \left( x \right) \right|^{p_1}\left| x \right|_{p}^{\beta}dx} \right) ^{\frac{1}{p_1}}=\left( \int_{|x|_p<1}{\left| x \right|_{p}^{-\frac{\beta p_1}{p_1-1}}\left| x \right|_{p}^{\beta}dx} \right) ^{\frac{1}{p_1}}\\ &=\left( \left( 1-p^{-n} \right) \sum_{i=-\infty}^{-1}{p^{i( n+\beta -\frac{\beta p_1}{p_1-1} )}} \right) ^{\frac{1}{p_1}}=\left( \frac{\left( 1-p^{-n} \right) p^{\frac{\beta}{p_1-1}-n}}{1-p^{\frac{\beta}{p_1-1}-n}} \right) ^{\frac{1}{p_1}}<\infty . \end{align}\] So we have proved that \(f_0\in L^{p_1}(\mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\beta})\). Then we calculate \(\mathcal{H} _{\alpha}\left( f_0 \right) \left( x \right)\). \[\begin{align} \mathcal{H} _{\alpha}\left( f_0 \right) \left( x \right) &=\frac{1}{|x|_{p}^{n-\alpha}}\int_{|y|_p<|x|_p}{|y|_{p}^{-\frac{\beta}{p_1-1}}\chi _{\{y:\left| y \right|_p<1\}}\left( y \right) dy}\\ &=\frac{1}{|x|_{p}^{n-\alpha}}\left\{ \begin{array}{l} \int_{|y|_p<|x|_p}{|y|_{p}^{-\frac{\beta}{p_1-1}}dy,\,\left| x \right|_p\leqslant1}\\ \int_{|y|_h<1}{|y|_{p}^{-\frac{\beta}{p_1-1}}dy,\,\,\,\,\,\,\left| x \right|_p>1}\\ \end{array} \right. =\left\{ \begin{array}{l} \sum_{i=-\infty}^{\log _p|x|_p-1}{\int_{S_i}{|y|_{p}^{-\frac{\beta}{p_1-1}}dy,\,\left| x \right|_p\leqslant1}}\\ \sum_{i=-\infty}^{-1}{\int_{S_i}{|y|_{p}^{-\frac{\beta}{p_1-1}}dy,\,\,\,\,\,\,\,\,\,\,\left| x \right|_p>1}}\\ \end{array} \right. \\ &=\left( 1-p^{-n} \right) \begin{cases} \sum_{i=-\infty}^{\log _p|x|_p-1}{p^{i( n-\frac{\beta}{p_1-1})},\,\left| x \right|_p\leqslant1}\\ \sum_{i=-\infty}^{-1}{p^{i( n-\frac{\beta}{p_1-1} )},\,\,\,\,\,\,\,\,\,\,\left| x \right|_p>1}\\ \end{cases}=\frac{\left( 1-p^{-n} \right) p^{\frac{\beta}{p_1-1}-n}}{1-p^{\frac{\beta}{p_1-1}-n}}\begin{cases} |x|_{p}^{\alpha -\frac{\beta}{p_1-1}},\,\left| x \right|_p\leqslant1\\ |x|_{p}^{\alpha -n},\,\,\,\,\,\,\,\,\,\left| x \right|_p>1\\ \end{cases}. \end{align}\] For convenience, we set \(C_{p_1,n,\beta}=\frac{\left( 1-p^{-n} \right) p^{\frac{\beta}{p_1-1}-n}}{1-p^{\frac{\beta}{p_1-1}-n}}\), we have \[\left\{ x:|\mathcal{H} _{\alpha}\left( f_0 \right) \left( x \right) |>\lambda \right\} =\{\left| x \right|_p\leqslant 1:C_{p_1,n,\beta}\left| x \right|_{p}^{\alpha -\frac{\beta}{p_1-1}}>\lambda \}\cup \{\left| x \right|_p>1:C_{p_1,n,\beta}\left| x \right|_{p}^{\alpha -n}>\lambda \}.\]
When \(0<\lambda <C_{p_1,n,\beta}\), noticing \(\alpha <\frac{\beta}{p_1-1}\,\,\) and \(\beta <n\left( p_1-1 \right)\), we have \(\alpha <n\) and \[\begin{align} \left\{ x:|\mathcal{H} _{\alpha}\left( f_0 \right) \left( x \right) |>\lambda \right\} &=\left\{\left| x \right|_p\leqslant 1:\left| x \right|_{p}^{\frac{\beta}{p_1-1}-\alpha}<\frac{C_{p_1,n,\beta}}{\lambda}\right\}\cup \left\{ \left| x \right|_p>1:\left| x \right|_p<\left( \frac{C_{p_1,n,\beta}}{\lambda} \right) ^{\frac{1}{n-\alpha}} \right\} \\ &=\{\left| x \right|_p\leqslant 1\}\cup \left\{ \left| x \right|_p>1:\left| x \right|_p<\left( \frac{C_{p_1,n,\beta}}{\lambda} \right) ^{\frac{1}{n-\alpha}} \right\} \\ &=\left\{ x:\left| x \right|_p<\left( \frac{C_{p_1,n,\beta}}{\lambda} \right) ^{\frac{1}{n-\alpha}} \right\} . \end{align}\]
When \(\lambda \geqslant C_{p_1,n,\beta}\), noticing \(\alpha <\frac{\beta}{p_1-1}\) and \(\beta <n\left( p_1-1 \right)\), we have \(\alpha <n\) and \[\begin{align} \left\{ x:|\mathcal{H} _{\alpha}\left( f_0 \right) \left( x \right) |>\lambda \right\} &=\left\{\left| x \right|_p\leqslant 1:\left| x \right|_{p}^{\frac{\beta}{p_1-1}-\alpha}<\frac{C_{p_1,n,\beta}}{\lambda}\right\}\cup \varnothing \\ &=\left\{ x:\left| x \right|_p<\left( \frac{C_{p_1,n,\beta}}{\lambda} \right) ^{\frac{1}{\frac{\beta}{p_1-1}-\alpha}} \right\} . \end{align}\] Based on the above analysis, we have \[\begin{align} &\left\| \mathcal{H} _{\alpha}\left( f_0 \right) \right\| _{L^{q,\infty}(\mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\gamma})} \\ &=\max \left\{ \underset{0<\lambda <C_{p_1,n,\beta}}{\mathrm{sup}}\lambda \left( \int_{\mathbb{Q} _{p}^{n}}{\chi _{\left\{ x:|\mathcal{H} _{\alpha}\left( f_0 \right) \left( x \right) |>\lambda \right\}}\left( x \right) |x|_{p}^{\gamma}dx\,\,} \right) ^{\frac{1}{q}},\underset{C_{p_1,n,\beta}\leqslant \lambda}{\mathrm{sup}}\lambda \left( \int_{\mathbb{Q} _{p}^{n}}{\chi _{\left\{ x:|\mathcal{H} _{\alpha}\left( f_0 \right) \left( x \right) |>\lambda \right\}}\left( x \right) |x|_{p}^{\gamma}dx\,\,} \right) ^{\frac{1}{q}} \right\} \\ &=:\max \left\{ M_1,M_2 \right\} . \end{align}\] Now we first calculate \(M_1\). Since \[\left\| f_0 \right\| _{L^{p_1}(\mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\beta})}=\left( \frac{\left( 1-p^{-n} \right) p^{\frac{\beta}{p_1-1}-n}}{1-p^{\frac{\beta}{p_1-1}-n}} \right) ^{\frac{1}{p_1}},\quad \gamma >-n\] and \[1-\frac{n+\gamma}{\left( n-\alpha \right) q}=1-\frac{1}{n-\alpha}( \frac{\beta +n}{p_1}-\alpha ) =\frac{n\left( p_1-1 \right) -\beta}{p_1\left( n-\alpha \right)}>0,\] we have \[\begin{align} M_1&=\underset{0<\lambda <C_{p_1,n,\beta}}{\mathrm{sup}}\lambda \left( \int_{\mathbb{Q} _{p}^{n}}{\chi _{\left\{ x:|\mathcal{H} _{\alpha}\left( f_0 \right) \left( x \right) |>\lambda \right\}}\left( x \right) |x|_{p}^{\gamma}dx\,\,} \right) ^{\frac{1}{q}}=\underset{0<\lambda <C_{p_1,n,\beta}}{\mathrm{sup}}\lambda \left( \int_{\left| x \right|_p<(\frac{C_{p_1,n,\beta}}{\lambda})^{\frac{1}{n-\alpha}}}{|x|_{p}^{\gamma}dx\,\,} \right) ^{\frac{1}{q}} \\ &=\underset{0<\lambda <C_{p_1,n,\beta}}{\mathrm{sup}}\lambda \left( \left( 1-p^{-n} \right) \sum_{i=-\infty}^{\frac{1}{n-\alpha}\log _p\frac{C_{p_1,n,\beta}}{\lambda}-1}{p^{i\left( n+\gamma \right)}} \right) ^{\frac{1}{q}} \\ &=\underset{0<\lambda <C_{p_1,n,\beta}}{\mathrm{sup}}\lambda \left( \frac{1-p^{-n}}{1-p^{-n-\gamma}}\times p^{( \frac{1}{n-\alpha}\log _p\frac{C_{p_1,n,\beta}}{\lambda}-1 ) \left( n+\gamma \right)} \right) ^{\frac{1}{q}} \\ &=\underset{0<\lambda <C_{p_1,n,\beta}}{\mathrm{sup}}\left( \frac{\left( 1-p^{-n} \right) p^{-n-\gamma}}{1-p^{-n-\gamma}} \right) ^{\frac{1}{q}}\left( C_{p_1,n,\beta} \right) ^{\frac{n+\gamma}{\left( n-\alpha \right) q}}\lambda ^{1-\frac{n+\gamma}{\left( n-\alpha \right) q}} \\ &=\left( \frac{\left( 1-p^{-n} \right) p^{-n-\gamma}}{1-p^{-n-\gamma}} \right) ^{\frac{1}{q}}C_{p_1,Q,\beta}=\left( \frac{\left( 1-p^{-n} \right) p^{-n-\gamma}}{1-p^{-n-\gamma}} \right) ^{\frac{1}{q}}\left( \frac{\left( 1-p^{-n} \right) p^{\frac{\beta}{p_1-1}-n}}{1-p^{\frac{\beta}{p_1-1}-n}} \right) ^{\frac{1}{p_1}+\frac{1}{p_1^{\prime}}} \\ &=\left( \frac{\left( 1-p^{-n} \right) p^{-n-\gamma}}{1-p^{-n-\gamma}} \right) ^{\frac{1}{q}}\left( \frac{\left( 1-p^{-n} \right) p^{\frac{\beta}{p_1-1}-n}}{1-p^{\frac{\beta}{p_1-1}-n}} \right) ^{\frac{1}{p_1^{\prime}}}\left\| f_0 \right\| _{L^p(\mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\beta})}. \end{align}\] Then we calculate \(M_2\), noticing \(\left\| f_0 \right\| _{L^p(\mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\beta})}=\left( \frac{\left( 1-p^{-n} \right) p^{\frac{\beta}{p_1-1}-n}}{1-p^{\frac{\beta}{p_1-1}-n}} \right) ^{\frac{1}{p_1}}\), \(\gamma >-n\) and \[1-\frac{n+\gamma}{( \frac{\beta}{p_1-1}-\alpha) q}=1-\frac{1}{\frac{\beta}{p_1-1}-\alpha}( \frac{\beta +n}{p_1}-\alpha ) =\frac{\beta -n\left( p_1-1 \right)}{p_1(\frac{\beta}{p_1-1}-\alpha )(p_1-1)}<0,\] we have \[\begin{align} M_2&=\underset{C_{p_1,n,\beta}\geqslant \lambda}{\mathrm{sup}}\lambda \left( \int_{\mathbb{Q} _{p}^{n}}{\chi _{\left\{ x:|\mathcal{H} _{\alpha}\left( f_0 \right) \left( x \right) |>\lambda \right\}}\left( x \right) |x|_{p}^{\gamma}dx\,\,} \right) ^{\frac{1}{q}}=\underset{C_{p_1,n,\beta}\geqslant \lambda}{\mathrm{sup}}\lambda \left( \int_{\left| x \right|_p<(\frac{C_{p_1,n,\beta}}{\lambda})^{\frac{1}{\frac{\beta}{p_1-1}-\alpha}}}{|x|_{p}^{\gamma}dx\,\,} \right) ^{\frac{1}{q}} \\ &=\underset{C_{p_1,n,\beta}\geqslant \lambda}{\mathrm{sup}}\lambda \left( \left( 1-p^{-n} \right) \sum_{i=-\infty}^{\frac{1}{(\frac{\beta}{p_1-1}-\alpha )}\log _p\frac{C_{p_1,n,\beta}}{\lambda}-1}{p^{i\left( n+\gamma \right)}} \right) ^{\frac{1}{q}} \\ &=\underset{C_{p_1,n,\beta}\geqslant \lambda}{\mathrm{sup}}\lambda \left( \frac{1-p^{-n}}{1-p^{-n-\gamma}}\times p^{(\frac{1}{(\frac{\beta}{p_1-1}-\alpha )}\log _p\frac{C_{p_1,n,\beta}}{\lambda}-1)\left( n+\gamma \right)} \right) ^{\frac{1}{q}} \\ &=\underset{C_{p_1,n,\beta}\geqslant \lambda}{\mathrm{sup}}\lambda \left( \frac{\left( 1-p^{-n} \right) p^{-n-\gamma}}{1-p^{-n-\gamma}} \right) ^{\frac{1}{q}}\left( C_{p_1,n,\beta} \right) ^{\frac{n+\gamma}{(\frac{\beta}{p_1-1}-\alpha )q}}\lambda ^{1-\frac{n+\gamma}{(\frac{\beta}{p_1-1}-\alpha )q}} \\ &=\left( \frac{\left( 1-p^{-n} \right) p^{-n-\gamma}}{1-p^{-n-\gamma}} \right) ^{\frac{1}{q}}C_{p_1,n,\beta}=\left( \frac{\left( 1-p^{-n} \right) p^{-n-\gamma}}{1-p^{-n-\gamma}} \right) ^{\frac{1}{q}}\left( \frac{\left( 1-p^{-n} \right) p^{\frac{\beta}{p_1-1}-n}}{1-p^{\frac{\beta}{p_1-1}-n}} \right) ^{\frac{1}{p_1}+\frac{1}{p_1^{\prime}}} \\ &=\left( \frac{\left( 1-p^{-n} \right) p^{-n-\gamma}}{1-p^{-n-\gamma}} \right) ^{\frac{1}{q}}\left( \frac{\left( 1-p^{-n} \right) p^{\frac{\beta}{p_1-1}-n}}{1-p^{\frac{\beta}{p_1-1}-n}} \right) ^{\frac{1}{p_1^{\prime}}}\left\| f_0 \right\| _{L^p(\mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\beta})}. \end{align}\] Its easy to see that \(M_1=M_2\), and then \[\left\| \mathcal{H} _{\alpha} \right\| _{L^{p_1}(\mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\beta})\rightarrow \,\,L^{q,\infty}(\mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\gamma})}=\left( \frac{\left( 1-p^{-n} \right) p^{-n-\gamma}}{1-p^{-n-\gamma}} \right) ^{\frac{1}{q}}\left( \frac{\left( 1-p^{-n} \right) p^{\frac{\beta}{p_1-1}-n}}{1-p^{\frac{\beta}{p_1-1}-n}} \right) ^{\frac{1}{p_{1}^{\prime}}}.\] This finishes the proof of Theorem 1. ◻
Proof of Theorem 2:. It is easy to see that \[\left| \mathcal{H} _{\alpha}f\left( x \right) \right|=\left| \frac{1}{|x|_{p}^{n-a}}\int_{|y|_p<|x|_p}{f\left( y \right) dy} \right|\leqslant \left| \frac{1}{|x|_{p}^{n-a}}\int_{\mathbb{Q} _{p}^{n}}{f\left( y \right) dy} \right|=|x|_{p}^{\alpha -n}\left\| f \right\| _{L^1\left( \mathbb{Q} _{p}^{n} \right)}.\] Notice \(\left| \mathcal{H} _{\alpha}f\left( x \right) \right|\leqslant |x|_{p}^{\alpha -n}\left\| f \right\| _{L^1( \mathbb{Q} _{p}^{n})}\), and we have \(\left\{ x:\left| \mathcal{H} _{\alpha}f\left( x \right) \right|>\lambda \right\} \subset \{x:|x|_{p}^{\alpha -n}\left\| f \right\| _{L^1( \mathbb{Q} _{p}^{n} )}>\lambda \}\). Since \(n-\alpha >0\) and \(n+\gamma >0\), we have \[\begin{align} &\left\| \mathcal{H} _{\alpha}f \right\| _{L^{\left( n+\gamma \right) /\left( n-\alpha \right) ,\infty}\left( \mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\gamma} \right)}=\underset{\lambda >0}{\mathrm{sup}}\,\,\lambda \left( \int_{\mathbb{Q} _{p}^{n}}{\chi _{\left\{ x:|\mathcal{H} _{\alpha}f\left( x \right) |>\lambda \right\}}\left( x \right) |x|_{p}^{\gamma}dx\,\,} \right) ^{\frac{n-\alpha}{n+\gamma}} \\ &\leqslant \underset{\lambda >0}{\mathrm{sup}}\,\,\lambda \left( \int_{\mathbb{Q} _{p}^{n}}{\chi _{\{x:|x|_{p}^{\alpha -n}\left\| f \right\| _{L^1( \mathbb{Q} _{p}^{n} )}>\lambda \}}\left( x \right) |x|_{p}^{\gamma}dx\,\,} \right) ^{\frac{n-\alpha}{n+\gamma}}=\underset{\lambda >0}{\mathrm{sup}}\,\,\lambda \left( \int_{\left| x \right|_p<(\left\| f \right\| _{L^1( \mathbb{Q} _{p}^{n} )}/\lambda )^{\frac{1}{n-\alpha}}}{|x|_{p}^{\gamma}dx\,\,} \right) ^{\frac{n-\alpha}{n+\gamma}} \\ &=\underset{\lambda >0}{\mathrm{sup}}\,\,\lambda \left( \sum_{i=-\infty}^{\frac{1}{n-\alpha}\log _p\frac{\left\| f \right\| _{L^1( \mathbb{Q} _{p}^{n} )}}{\lambda}-1}{\int_{S_i}{|x|_{p}^{\gamma}dx}} \right) ^{\frac{n-\alpha}{n+\gamma}}=\underset{\lambda >0}{\mathrm{sup}}\,\,\lambda \left( \left( 1-p^{-n} \right) \sum_{i=-\infty}^{\frac{1}{n-\alpha}\log _p\frac{\left\| f \right\| _{L^1( \mathbb{Q} _{p}^{n} )}}{\lambda}-1}{p^{i\left( n+\gamma \right)}} \right) ^{\frac{n-\alpha}{n+\gamma}} \\ &=\underset{\lambda >0}{\mathrm{sup}}\,\,\lambda \left( \left( 1-p^{-n} \right) \frac{p^{(\frac{1}{n-\alpha}\log _p\frac{\left\| f \right\| _{L^1(\mathbb{Q} _{p}^{n})}}{\lambda}-1)\left( n+\gamma \right)}}{1-p^{-n-\gamma}} \right) ^{\frac{n-\alpha}{n+\gamma}}=\left( \frac{1-p^{-n}}{\left( 1-p^{-n-\gamma} \right) p^{n+\gamma}} \right) ^{\frac{n-\alpha}{n+\gamma}}\left\| f \right\| _{L^1(\mathbb{Q} _{p}^{n})}. \end{align}\] Thus \[\left\| \mathcal{H} _{\alpha}f\left( x \right) \right\| _{L^{( n+\gamma) /\left( n-\alpha \right) ,\infty}( \mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\gamma} )}\leqslant \left( \frac{1-p^{-n}}{\left( 1-p^{-n-\gamma} \right) p^{n+\gamma}} \right) ^{\frac{n-\alpha}{n+\gamma}}\left\| f \right\| _{L^1( \mathbb{Q} _{p}^{n})}.\] On the other hand, let \(f_0\left( x \right) =\chi _{\{ x:\left| x \right|_p< 1 \}}\left( x \right)\), we have \[\left\| f_0 \right\| _{L^1(\mathbb{Q} _{p}^{n})}=\int_{\mathbb{Q} _{p}^{n}}{\chi _{\{x:\left| x \right|_p<1\}}\left( x \right) dx=\int_{\left| x \right|_p<1}{dx}}=\sum_{i=-\infty}^{-1}{\int_{S_i}{dx}}=\left( 1-p^{-n} \right) \sum_{i=-\infty}^{-1}{p^{in}}=p^{-n}<\infty ,\] thus \(f_0\in L^1( \mathbb{Q} _{p}^{n})\) and \[\begin{align} \mathcal{H} _{\alpha}\left( f_0 \right) \left( x \right) &=\frac{1}{|x|_{p}^{n-a}}\int_{|y|_p<|x|_p}{\chi _{\left\{ y:|y|_p<1 \right\}}\left( y \right) dy} \\ &=\frac{1}{|x|_{p}^{n-a}}\left\{ \begin{array}{l} \int_{|y|_p<|x|_p}{dy,\,|x|_p}\leqslant 1\\ \int_{|y|_p<1}{dy,\,\,\,\,\,\,|x|_p}>1\\ \end{array} \right. =p^{-n}\left\{ \begin{array}{l} |x|_{p}^{\alpha},\,\,\,\,\,\,\,\,|x|_p\leqslant 1\\ |x|_{p}^{\alpha -n},\,\,|x|_p>1\\ \end{array} \right. . \end{align}\] Denote \[\left\{ x:|\mathcal{H} _{\alpha}\left( f_0 \right) \left( x \right) |>\lambda \right\} =\left\{ |x|_p\leqslant 1:|x|_{p}^{\alpha}p^{-n}>\lambda \right\} \cup \{|x|_p>1:|x|_{p}^{\alpha -n}p^{-n}>\lambda \}.\]
When \(\lambda \geqslant p^{-n}\), noticing \(0<\alpha <n\), we have \[\left\{ x:|\mathcal{H} _{\alpha}\left( f_0 \right) \left( x \right) |>\lambda \right\} =\left\{ |x|_p\leqslant 1:|x|_p>\left( \frac{\lambda}{p^{-n}} \right) ^{\frac{1}{\alpha}} \right\} \cup \left\{ |x|_p>1:|x|_p<\left( \frac{p^{-n}}{\lambda} \right) ^{\frac{1}{n-\alpha}} \right\} =\varnothing.\]
When \(0<\lambda <p^{-n}\), noticing \(0<\alpha <n\), we have \[\left\{ x:|\mathcal{H} _{\alpha}\left( f_0 \right) \left( x \right) |>\lambda \right\} =\left\{ x:\left( \frac{\lambda}{p^{-n}} \right) ^{\frac{1}{\alpha}}<\left| x \right|_p<\left( \frac{p^{-n}}{\lambda} \right) ^{\frac{1}{n-\alpha}} \right\} .\] We have \[\begin{align} &\left\| \mathcal{H} _{\alpha}\left( f_0 \right) \left( x \right) \right\| _{L^{\left( n+\gamma \right) /\left( n-\alpha \right) ,\infty}\left( \mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\gamma} \right)} \\ &=\max \left\{ \underset{0<\lambda <p^{-n}}{\mathrm{sup}}\lambda \left( \int_{\mathbb{Q} _{p}^{n}}{\chi _{\left\{ x:|\mathcal{H} _{\alpha}f_0\left( x \right) |>\lambda \right\}}\left( x \right) |x|_{p}^{\gamma}dx\,\,} \right) ^{\frac{n-\alpha}{n+\gamma}},\underset{\lambda \geqslant p^{-n}}{\mathrm{sup}}\lambda \left( \int_{\mathbb{Q} _{p}^{n}}{\chi _{\left\{ x:|\mathcal{H} _{\alpha}f_0\left( x \right) |>\lambda \right\}}\left( x \right) |x|_{p}^{\gamma}dx\,\,} \right) ^{\frac{n-\alpha}{n+\gamma}} \right\} \\ &=:\max \left\{ M_3,M_4 \right\} . \end{align}\] When \(\lambda \geqslant p^{-n}\), then \(\left\{ x:|\mathcal{H} _{\alpha}f_0\left( x \right) |>\lambda \right\} =\varnothing\), and we have \(M_4=0\), then we only need to calculate \(M_3\). In addition, noticing \[n+\gamma >0,\quad 0<\alpha <n,\quad \left\| f_0 \right\| _{L^1( \mathbb{Q} _{p}^{n} )}=p^{-n},\] we have \[\begin{align} M_3&=\underset{0<\lambda <p^{-n}}{\mathrm{sup}}\lambda \left( \int_{\mathbb{Q} _{p}^{n}}{\chi _{\left\{ x:|\mathcal{H} _{\alpha}f_0\left( x \right) |>\lambda \right\}}\left( x \right) |x|_{p}^{\gamma}dx\,\,} \right) ^{\frac{n-\alpha}{n+\gamma}} =\underset{0<\lambda <p^{-n}}{\mathrm{sup}}\lambda \left( \int_{(\lambda p^n)^{\frac{1}{\alpha}}<\left| x \right|_p<(\frac{1}{p^n\lambda})^{\frac{1}{n-\alpha}}}{|x|_{p}^{\gamma}dx\,\,} \right) ^{\frac{n-\alpha}{n+\gamma}} \\ &=\underset{0<\lambda <p^{-n}}{\mathrm{sup}}\lambda \left( \sum_{i=\log _p( \lambda p^n ) ^{\frac{1}{\alpha}}+1}^{\log _p( \frac{1}{\lambda p^n}) ^{\frac{1}{n-\alpha}}-1}{\int_{S_i}{|x|_{p}^{\gamma}dx}} \right) ^{\frac{n-\alpha}{n+\gamma}}=\underset{0<\lambda <p^{-n}}{\mathrm{sup}}\lambda \left( \left( 1-p^{-n} \right) \sum_{i=\log _p(\lambda p^n)^{\frac{1}{\alpha}}+1}^{\log _p(\frac{1}{\lambda p^n})^{\frac{1}{n-\alpha}}-1}{p^{i\left( n+\gamma \right)}} \right) ^{\frac{n-\alpha}{n+\gamma}} \\ &=\underset{0<\lambda <p^{-n}}{\mathrm{sup}}\lambda \left( \left( 1-p^{-n} \right) \frac{p^{(\log _p(\frac{1}{\lambda p^n})^{\frac{1}{n-\alpha}}-1)\left( n+\gamma \right)}(1-\left( p^{-n-\gamma} \right) ^{\log _p(\frac{1}{\lambda p^n})^{\frac{1}{n-\alpha}}-1-(\log _p(\lambda p^n)^{\frac{1}{\alpha}}+1)+1})}{1-p^{-n-\gamma}} \right) ^{\frac{n-\alpha}{n+\gamma}} \\ &=\underset{0<\lambda <p^{-n}}{\mathrm{sup}}\lambda \left( \left( 1-p^{-n} \right) \times \frac{( \frac{1}{\lambda p^n} ) ^{\frac{n+\gamma}{n-\alpha}}( 1-\left( p^{-n-\gamma} \right) ^{\log _p\left( \lambda p^n \right) ^{\frac{1}{\alpha -n}-\frac{1}{\alpha}}-1} )}{\left( 1-p^{-n-\gamma} \right) p^{n+\gamma}} \right) ^{\frac{n-\alpha}{n+\gamma}} \\ &=\underset{0<\lambda <p^{-n}}{\mathrm{sup}}\left( 1-\frac{\left( \lambda p^n \right) ^{\frac{n}{\alpha}}}{p^{-n-\gamma}} \right) \left( \frac{\left( 1-p^{-n} \right)}{\left( 1-p^{-n-\gamma} \right) p^{n+\gamma}} \right) ^{\frac{n-\alpha}{n+\gamma}}p^{-n}=\left( \frac{\left( 1-p^{-n} \right)}{\left( 1-p^{-n-\gamma} \right) p^{n+\gamma}} \right) ^{\frac{n-\alpha}{n+\gamma}}\left\| f_0 \right\| _{L^1\left( \mathbb{Q} _{p}^{n} \right)}. \end{align}\] Thus \[\left\| \mathcal{H} _{\alpha} \right\| _{L^1\left( \mathbb{Q} _{p}^{n} \right) \rightarrow L^{\left( n+\gamma \right) /\left( n-\alpha \right) ,\infty}\left( \mathbb{Q} _{p}^{n},\left| x \right|_{p}^{\gamma} \right)}=\left( \frac{\left( 1-p^{-n} \right)}{\left( 1-p^{-n-\gamma} \right) p^{n+\gamma}} \right) ^{\frac{n-\alpha}{n+\gamma}}.\] This finishes the proof of Theorem 2. Notice that theorem 2 no longer holds when \(\alpha=0\). ◻
In this section, we will study the \(p\)-adic \(m\)-linear \(n\)-dimensional integral operator with a kernel. Let \(K:\mathbb{Q} _{p}^{n}\times \cdots \times \mathbb{Q} _{p}^{n}\rightarrow \left( 0,\infty \right)\) be a measurable kernel, it satisfies that \[\begin{align} \label{2461} C^p=\int_{\mathbb{Q} _{p}^{n}}{\cdots \int_{\mathbb{Q} _{p}^{n}}{K\left( y_1,...,y_m \right) \prod_{i=1}^m{\left| y_i \right|_{p}^{-\alpha _i}}}}dy_1\cdots dy_m<\infty, \end{align}\tag{1}\] where \(\alpha_j\) is pre-defined indicator and some fixed indices, \(j=1,2,...,m\). The \(p\)-adic \(m\)-linear \(n\)-dimensional integral operator with a kernel is defined by \[\begin{align} T^p\left( f_1,...,f_m \right) \left( x \right) =\int_{\mathbb{Q} _{p}^{n}}{\cdots}\int_{\mathbb{Q} _{p}^{n}}{K\left( y_1,...,y_m \right) f_1( \left| x \right|_{p}^{-1}y_1 ) \cdots}f_m( \left| x \right|_{p}^{-1}y_m ) dy_1\cdots dy_m, \end{align}\] where \(x\in \mathbb{Q}_p ^n\backslash \left\{ 0 \right\}\) and \(f_j\) is a measurable function on \(\mathbb{Q} _{p}^{n}\) with \(j=1,2,...,m\). Note that \(T^p\) is in fact an integral operator having a homogeneous kernel \(K\) of degree \(-mn\).
We will give the sharp bounds for the \(p\)-adic \(m\)-linear \(n\)-dimensional integral operator with a kernel on \(p\)-adic weighted space \(H_{\alpha}^{\infty}( \mathbb{Q} _{p}^{n} )\). Finally, by taking a particular kernel \(K\) in operator \(C^p\) defined by (1 ), we can obtain the sharp bounds for the \(p\)-adic Hardy and Hilbert operators. Our results in this section are as follows.
Theorem 3. Let \(m\in \mathbb{N}\), \(\alpha \in \mathbb{R}\) and \(\alpha=\alpha_1+\cdots+\alpha_m\) with \(\alpha _j\in \mathbb{R}\) \((j=1,2,...,m)\). \(f_j\) be a measurable function in \(H_{\alpha _j}^{\infty}( \mathbb{Q} _{p}^{n} )\). Then \[\begin{align} \left\| T^p\left( f_1,...,f_m \right) \left( x \right) \right\| _{\prod\nolimits_{j=1}^m{H_{\alpha _j}^{\infty}(\mathbb{Q} _{p}^{n})}\rightarrow H_{\alpha}^{\infty}(\mathbb{Q} _{p}^{n})}=C^p, \end{align}\] where \(C^p\) is the constant defined by (1 ).
Corollary 1. Assume that the real paramenters \(\alpha\), \(\alpha_j\) with \(j=1,2,...,m\) as same as in Theorem 1, \(f_j\) be a measurable function in \(H_{\alpha _j}^{\infty}( \mathbb{Q} _{p}^{n} )\). Assume also that \(\alpha_j<n\), then \[\begin{align} \left\| T_{1}^{p}\left( f_1,...,f_m \right) \left( x \right) \right\| _{\prod\nolimits_{j=1}^m{H_{\alpha _j}^{\infty}( \mathbb{Q} _{p}^{n} )}\rightarrow H_{\alpha}^{\infty}( \mathbb{Q} _{p}^{n} )}=\frac{\left( 1-p^{-n} \right) ^m}{\prod\nolimits_{j=1}^m{\left( 1-p^{\alpha _j-n} \right)}}. \end{align}\]
Corollary 2. Assume that the real paramenters \(\alpha\), \(\alpha_j\) with \(j=1,2,...,m\) as same as in Theorem 1, \(f_j\) be a measurable function in \(H_{\alpha _j}^{\infty}( \mathbb{Q} _{p}^{n})\). Assume also that \(\alpha_j<n\) and \(\alpha>0\), then \[\begin{align} &\left\| T_{2}^{p}\left( f_1,...,f_m \right) \left( x \right) \right\| _{\prod\nolimits_{j=1}^m{H_{\alpha _j}^{\infty}( \mathbb{Q} _{p}^{n} )}\rightarrow H_{\alpha}^{\infty}( \mathbb{Q} _{p}^{n} )} \\ &=(1-p^{-n})^m\sum_{k_1=-\infty}^{+\infty}{\sum_{k_2=-\infty}^{+\infty}{\cdots}\sum_{k_m=-\infty}^{+\infty}{\frac{1}{(1+p^{k_1n}+\cdots +p^{k_mn})^m}}}\prod_{j=1}^m{p^{k_j(-\alpha _j+n)}} \\ &\leqslant \frac{\left( 1-p^{-n} \right) ^m\left( 1-p^{-mn} \right)}{\left( 1-p^{-\alpha} \right) \prod\nolimits_{j=1}^m{\left( 1-p^{\alpha _j-n} \right)}}<\infty. \end{align}\]
Proof of Theroem 3:. Since the proof of the case when \(m=1\) is similar to and even simpler than of the case when \(m>1\), for simplicity, we will only give the proof of case when \(m>1\). Using the definition of weighted-type space \(H_{\alpha}^{\infty}( \mathbb{Q} _{p}^{n} )\), we can infer that \[\begin{align} &\left\| T^p\left( f_1,...,f_m \right) \left( x \right) \right\| _{H_{\alpha}^{\infty}( \mathbb{Q} _{p}^{n} )} \\ &=\mathrm{ess} \underset{x\in \mathbb{Q} _{p}^{n}}{\mathrm{sup}}\left| x \right|_{p}^{\alpha}\left| \int_{\mathbb{Q} _{p}^{mn}}{K\left( y_1,...,y_m \right) f_1( \left| x \right|_{p}^{-1}y_1 ) \cdots f_m( \left| x \right|_{p}^{-1}y_m ) dy_1\cdots dy_m} \right| \\ &=\mathrm{ess} \underset{x\in \mathbb{Q} _{p}^{n}}{\mathrm{sup}}\left| \int_{\mathbb{Q} _{p}^{mn}}{K\left( y_1,...,y_m \right) \left| x \right|_{p}^{\alpha _1}f_1( \left| x \right|_{p}^{-1}y_1 ) \cdots \left| x \right|_{p}^{\alpha _m}f_m( \left| x \right|_{p}^{-1}y_m ) dy_1\cdots dy_m} \right| \\ &=\mathrm{ess} \underset{x\in \mathbb{Q} _{p}^{n}}{\mathrm{sup}}\left| \int_{\mathbb{Q} _{p}^{mn}}{K\left( y_1,...,y_m \right) \prod_{j=1}^m{\frac{1}{\left| y_j \right|_{p}^{\alpha _j}}| \left| x \right|_{p}^{-1}y_j |_{p}^{\alpha _j}f_j( \left| x \right|_{p}^{-1}y_j )}dy_1\cdots dy_m} \right| \\ &\leqslant \left| \int_{\mathbb{Q} _{p}^{mn}}{K\left( y_1,...,y_m \right) \left( \prod_{j=1}^m{\left| y_j \right|_{p}^{-\alpha _j}} \right) \left( \prod_{j=1}^m{\mathrm{ess} \underset{x_j,y_j\in \mathbb{Q} _{p}^{n}}{\mathrm{sup}}| | x_j |_{p}^{-1}y_j |_{p}^{\alpha _j}| f_j( \left| x_j \right|_{p}^{-1}y_j ) |} \right) dy_1\cdots dy_m} \right| \\ &=\left| \int_{\mathbb{Q} _{p}^{mn}}{K\left( y_1,...,y_m \right) \left( \prod_{j=1}^m{\left| y_j \right|_{p}^{-\alpha _j}} \right) \left( \prod_{j=1}^m{\mathrm{ess} \underset{t_j\in \mathbb{Q} _{p}^{n}}{\mathrm{sup}}\left| t_j \right|_{p}^{\alpha _j}\left| f_j\left( t_j \right) \right|} \right) dy_1\cdots dy_m} \right| \\ &=\left| \int_{\mathbb{Q} _{p}^{mn}}{K\left( y_1,...,y_m \right) \prod_{j=1}^m{\left| y_j \right|_{p}^{-\alpha _j}}dy_1\cdots dy_m} \right|\times \prod_{j=1}^m{\left\| f_j \right\| _{H_{\alpha _j}^{\infty}\left( \mathbb{Q} _{p}^{n} \right)}}=C^p\prod_{j=1}^m{\left\| f_j \right\| _{H_{\alpha _j}^{\infty}\left( \mathbb{Q} _{p}^{n} \right)}}, \end{align}\] for ever \(f_j \in \prod\nolimits_{j=1}^m{H_{\alpha _j}^{\infty}( \mathbb{Q} _{p}^{n} )}\), from which by taking the supremum in \(H_{\alpha _j}^{\infty}( \mathbb{Q} _{p}^{n} )\), we can infer that \[\begin{align} \left\| T^p \right\| _{\prod\nolimits_{j=1}^m{H_{\alpha _j}^{\infty}( \mathbb{Q} _{p}^{n} )}\rightarrow H_{\alpha}^{\infty}\left( \mathbb{Q} _{p}^{n} \right)}\leqslant C^p \end{align}\] and consequently the boundedness of the operator.
On the other hand, by taking \[f_j\left( x \right) =\begin{cases} 1/\left| x \right|_{p}^{\alpha _j}, x\ne 0.\\ 0, x=0.\\ \end{cases},\] then it is clear that for \(j=1,2,...,m\), we have \[\begin{align} \left\| f_j\left( x \right) \right\| _{H_{\alpha _j}^{\infty}\left( \mathbb{Q} _{p}^{n} \right)}=\mathrm{ess} \underset{x\in \mathbb{Q} _{p}^{n}}{\mathrm{sup}}\left| x \right|_{p}^{\alpha _j}\times \frac{1}{\left| x \right|_{p}^{\alpha _j}}=1<\infty. \end{align}\] After performing some straightforward calculations, it follows that \[\begin{align} &\left\| T^p\left( f_1,...,f_m \right) \left( x \right) \right\| _{H_{\alpha}^{\infty}( \mathbb{Q} _{p}^{n} )} \\ &=\mathrm{ess} \underset{x\in \mathbb{Q} _{p}^{n}}{\mathrm{sup}}\left| x \right|_{p}^{\alpha}\left| \int_{\mathbb{Q} _{p}^{mn}}{K\left( y_1,...,y_m \right) | \left| x \right|_{p}^{-1}y_1 |_{p}^{-\alpha _1}\cdots | \left| x \right|_{p}^{-1}y_m |_{p}^{-\alpha _m}dy_1\cdots dy_m} \right| \\ &=\mathrm{ess} \underset{x\in \mathbb{Q} _{p}^{n}}{\mathrm{sup}}\left| \int_{\mathbb{Q} _{p}^{mn}}{K\left( y_1,...,y_m \right) \left| x \right|_{p}^{\alpha}\left| x \right|_{p}^{-\alpha _1}\left| y_1 \right|_{p}^{-\alpha _1}\cdots \left| x \right|_{p}^{-\alpha _m}\left| y_m \right|_{p}^{-\alpha _m}dy_1\cdots dy_m} \right| \\ &=\left| \int_{\mathbb{Q} _{p}^{mn}}{K\left( y_1,...,y_m \right) \left| y_1 \right|_{p}^{-\alpha _1}\cdots \left| y_m \right|_{p}^{-\alpha _m}dy_1\cdots dy_m} \right| \\ &=\left| \int_{\mathbb{Q} _{p}^{mn}}{K\left( y_1,...,y_m \right) \prod_{j=1}^m{\left| y_j \right|_{p}^{-\alpha _j}}dy_1\cdots dy_m} \right|\times \prod_{j=1}^m{\mathrm{ess} \underset{x\in \mathbb{Q} _{p}^{n}}{\mathrm{sup}}\left| x \right|_{p}^{\alpha _1}\times \left| \frac{1}{\left| x \right|_{p}^{\alpha _1}} \right|} \\ &=C^p\prod_{j=1}^m{\left\| f_j \right\| _{H_{\alpha _j}^{\infty}( \mathbb{Q} _{p}^{n} )}}. \end{align}\] For \(x\ne 0\), where we used the condition \(\alpha =\alpha _1+\cdots +\alpha _m\). This finishes the proof of Theorem 3. ◻
Proof of Corollary 1:. Next, we refer to the methods in [24] to solve it. If we take the kernel \[K\left( y_1,...,y_m \right) =\chi _{\{ \left| \left( y_1,...,y_m \right) \right|_p\leqslant 1 \}}\left( y_1,...,y_m \right)\] in Theorems 3, by a change of variables, it is easy to verify that \(T^p=T_{1}^{p}\), and then \(T_{1}^{p}\) can be denoted by \[T_{1}^{p}=\int_{\left| \left( y_1,...,y_m \right) \right|_p\leqslant 1}{f_1( \left| x \right|_{p}^{-1}y_1 ) \cdots f_m( \left| x \right|_{p}^{-1}y_m ) dy_1\cdots dy_m},\] respectively, then all things reduce to calculating \[C_{1}^{p}=\int_{\left| \left( y_1,...,y_m \right) \right|_p\leqslant 1}{\prod_{j=1}^m{\left| y_j \right|_{p}^{-\alpha_j}}dy_1\cdots dy_m}.\] To calculate this integral, we divide the integral into \(m\) parts. Let \[\begin{align} &D_1=\{ \left( y_1,...,y_m \right) \in \mathbb{Q} _{p}^{n}\cdots \mathbb{Q} _{p}^{n}:\left| y_1 \right|_p\leqslant 1,\left| y_k \right|_p\leqslant \left| y_1 \right|_p,1<k\leqslant m \}, \\ &D_i=\{ \left( y_1,...,y_m \right) \in \mathbb{Q} _{p}^{n}\cdots \mathbb{Q} _{p}^{n}:\left| y_i \right|_p\leqslant 1,\left| y_j \right|_p<\left| y_i \right|_p,\left| y_k \right|_p\leqslant \left| y_i \right|_p,1\leqslant j<i<k\leqslant m \}, \\ &D_m=\{ \left( y_1,...,y_m \right) \in \mathbb{Q} _{p}^{n}\cdots \mathbb{Q} _{p}^{n}:\left| y_m \right|_p\leqslant 1,\left| y_j \right|_p<\left| y_m \right|_p,1\leqslant j<m \}. \end{align}\] It is clear that \[\bigcup_{j=1}^m{D_j=\{ \left( y_1,...,y_m \right) \in \mathbb{Q} _{p}^{n}\cdots \mathbb{Q} _{p}^{n}:\left| \left( y_1,...,y_m \right) \right|_p\leqslant 1 \}}\] and \(D_i\cap D_j=\varnothing \left( i\ne j \right)\). Let \[I_j:=\int_{D_j}{\prod_{k=1}^m{\left| y_k \right|_{p}^{-\alpha_k}}dy_1\cdots dy_m}.\] Then \[C_{1}^{p}=\sum_{j=1}^m{I_j:}=\sum_{j=1}^m{\int_{D_j}{\prod_{k=1}^m{\left| y_k \right|_{p}^{-\alpha_k}}dy_1\cdots dy_m}}.\] Now let us calculate \(I_j\), \(j=1,2,...,m\). Since \(\alpha_j<n\), then \(\alpha<mn\), so we have \[\begin{align} I_1&=\int_{D_1}{\prod_{k=1}^m{\left| y_k \right|_{p}^{-\alpha _k}dy_1}\cdots dy_m}\\ &=\int_{\left| y_1 \right|_p\leqslant 1}{\left( \int_{\left| y_2 \right|_p\leqslant \left| y_1 \right|_p}{\cdots \int_{\left| y_m \right|_p\leqslant \left| y_1 \right|_p}{\prod_{k=1}^m{\left| y_k \right|_{p}^{-\alpha _k}}dy_m}}\cdots dy_2 \right) dy_1}\\ &=\int_{\left| y_1 \right|_p\leqslant 1}{\left| y_1 \right|_{p}^{-\alpha _1}\left( \prod_{k=2}^m{\int_{\left| y_k \right|_p\leqslant \left| y_1 \right|_p}{\left| y_k \right|_{p}^{-\alpha _k}dy_k}} \right) dy_1}=\int_{\left| y_1 \right|_p\leqslant 1}{\left| y_1 \right|_{p}^{-\alpha _1}\prod_{k=2}^m{\left( \sum_{i=-\infty}^{\log _p\left| y_1 \right|_p}{\int_{S_i}{\left| y_k \right|_{p}^{-\alpha _k}dy_k}} \right) dy_1}}\\ &=\int_{\left| y_1 \right|_p\leqslant 1}{\left| y_1 \right|_{p}^{-\alpha _1}\prod_{k=2}^m{\left( \sum_{i=-\infty}^{\log _p\left| y_1 \right|_p}{p^{-i\alpha _k}}\times \int_{S_i}{dy_k} \right) dy_1}}=\int_{\left| y_1 \right|_p\leqslant 1}{\left| y_1 \right|_{p}^{-\alpha _1}\prod_{k=2}^m{\left( \left( 1-p^{-n} \right) \sum_{i=-\infty}^{\log _p\left| y_1 \right|_p}{p^{i\left( n-\alpha _k \right)}} \right) dy_1}}\\ &=\left( 1-p^{-n} \right) ^{m-1}\int_{\left| y_1 \right|_p\leqslant 1}{\left| y_1 \right|_{p}^{-\alpha _1}\prod_{k=2}^m{\left( \frac{p^{\left( n-\alpha _k \right) \log _p\left| y_1 \right|_p}}{1-p^{\alpha _k-n}} \right) dy_1}}=\frac{\left( 1-p^{-n} \right) ^{m-1}}{\prod\nolimits_{k=2}^m{\left( 1-p^{\alpha _k-n} \right)}}\int_{\left| y_1 \right|_p\leqslant 1}{\left| y_1 \right|_{p}^{-\alpha +(m-1)n}dy_1}\\ &=\frac{\left( 1-p^{-n} \right) ^{m-1}}{\prod\nolimits_{k=2}^m{\left( 1-p^{\alpha _k-n} \right)}}\sum_{i=-\infty}^0{\left( p^{-i\alpha +\left( m-1 \right) n}\int_{S_i}{dy_1} \right)}=\frac{\left( 1-p^{-n} \right) ^m}{\left( 1-p^{\alpha -mn} \right) \prod\nolimits_{k=2}^m{\left( 1-p^{\alpha _k-n} \right)}}.\\ \end{align}\]
Similar, for \(i=2,...,m-1\), we have \[\begin{align} I_i&=\int_{D_i}{\prod_{k=1}^m{\left| y_k \right|_{p}^{-\alpha _k}}dy_1}\cdots dy_m\\ &=\int_{\left| y_i \right|_p\leqslant 1}{\left| y_i \right|_{p}^{-\alpha _i}\left( \prod_{j=1}^{i-1}{\int_{\left| y_j \right|_p<\left| y_i \right|_p}{\left| y_j \right|_{p}^{-\alpha _j}dy_j}} \right) \left( \prod_{k=i+1}^m{\int_{\left| y_k \right|_p\leqslant \left| y_i \right|_p}{\left| y_k \right|_{p}^{-\alpha _k}dy_k}} \right) dy_i}\\ &=\int_{\left| y_i \right|_p\leqslant 1}{\left| y_i \right|_{p}^{-\alpha _i}\left( \prod_{j=1}^{i-1}{\sum_{u=-\infty}^{\log _p\left| y_i \right|_p-1}{\int_{S_u}{\left| y_j \right|_{p}^{-\alpha _j}}dy_j}} \right) \left( \prod_{k=i+1}^m{\sum_{v=-\infty}^{\log _p\left| y_i \right|_p}{\int_{S_v}{\left| y_k \right|_{p}^{-\alpha _k}}dy_k}} \right) dy_i}\\ &=\left( 1-p^{-n} \right) ^{m-1}\int_{\left| y_i \right|_p\leqslant 1}{\left| y_i \right|_{p}^{-\alpha _i}\left( \prod_{j=1}^{i-1}{\sum_{u=-\infty}^{\log _p\left| y_i \right|_p-1}{p^{u\left( -\alpha _j+n \right)}}} \right) \left( \prod_{k=i+1}^m{\sum_{v=-\infty}^{\log _p\left| y_i \right|_p}{p^{v(-\alpha _k+n)}}} \right) dy_i}\\ &=\left( 1-p^{-n} \right) ^{m-1}\int_{\left| y_i \right|_p\leqslant 1}{\left| y_i \right|_{p}^{-\alpha _i}\left( \prod_{j=1}^{i-1}{\frac{p^{(\alpha _j-n)}p^{\log _p\left| y_i \right|_p(-\alpha _j+n)}}{1-p^{\alpha _j-n}}} \right) \left( \prod_{k=i+1}^m{\frac{p^{\log _p\left| y_i \right|_p(-\alpha _k+n)}}{1-p^{\alpha _k-n}}} \right) dy_i}\\ &=\frac{\left( 1-p^{-n} \right) ^{m-1}\prod_{j=1}^{i-1}{p^{\alpha _j-n}}}{\prod_{1\leqslant k\leqslant m,k\ne i}{(1-p^{\alpha _k-n})}}\int_{\left| y_i \right|\leqslant 1}{\left| y_i \right|_{p}^{-\alpha +\left( m-1 \right) n}dy_i}\\ &=\frac{\left( 1-p^{-n} \right) ^m\prod_{j=1}^{i-1}{p^{\alpha _j-n}}}{(1-p^{\alpha -mn})\prod_{1\leqslant k\leqslant m,k\ne i}{(1-p^{\alpha _k-n})}}.\\ \end{align}\]
The case of \(i=m\) similar to the previous step, we show that \[\begin{align} I_m=\int_{\left| y_m \right|_p\leqslant 1}{\left| y_m \right|^{-\alpha _m}\left( \prod_{j=1}^{m-1}{\int_{\left| y_j \right|<\left| y_m \right|_p}{\left| y_j \right|^{-\alpha _j}dy_i}} \right) dy_m}=\frac{\left( 1-p^{-n} \right) ^m\prod_{j=1}^{m-1}{p^{\alpha _j-n}}}{\left( 1-p^{\alpha -mn} \right) \prod_{k=1}^{m-1}{(1-p^{\alpha _k-n})}}. \end{align}\] Now, we will calculate their sum, we set \[A_m=\frac{\left( 1-p^{-n} \right) ^m}{\left( 1-p^{\alpha -mn} \right) \prod\nolimits_{k=1}^m{\left( 1-p^{\alpha _k-n} \right)}}\,\,\,\text{and} \,\,\, d_k=\sum_{i=1}^k{\alpha _i}.\] Notice that \(d_m=\alpha\), then \[\begin{align} C_{1}^{p} &=I_1+\sum_{i=2}^{m-1}{I_i+I_m} \\ &=\frac{\left( 1-p^{-n} \right) ^m}{\left( 1-p^{\alpha -mn} \right) \prod\nolimits_{k=2}^m{\left( 1-p^{\alpha _k-n} \right)}}+\sum_{i=2}^{m-1}{\frac{\left( 1-p^{-n} \right) ^m\prod_{j=1}^{i-1}{p^{\alpha _j-n}}}{(1-p^{\alpha -mn})\prod_{1\leqslant k\leqslant m,k\ne i}{(1-p^{\alpha _k-n})}}} \\ &\quad+\frac{\left( 1-p^{-n} \right) ^m\prod_{j=1}^{m-1}{p^{\alpha _j-n}}}{\left( 1-p^{\alpha -mn} \right) \prod_{k=1}^{m-1}{(1-p^{\alpha _k-n})}}\\ &=A_m\left( (1-p^{d_1-n})+p^{\alpha _1-n}(1-p^{\alpha _2-n})+\prod_{j=1}^2{p^{\alpha _j-n}}(1-p^{\alpha _3-n})+\cdots +\prod_{j=1}^{m-1}{p^{\alpha _j-n}}(1-p^{\alpha _m-n}) \right) \\ &=A_m\left( (1-p^{d_1-n})+(p^{d_1-n}-p^{d_2-2n})+(p^{d_2-n}-p^{d_3-3n})+\cdots +(p^{d_{m-1}-(m-1)n}-p^{d_m-mn}) \right) \\ &=A_m( 1-p^{d_m-mn} ) =\frac{( 1-p^{-n} ) ^m}{\prod_{j=1}^m{(1-p^{\alpha _j-n})}}. \end{align}\] This finishes the proof of Corollary 1. ◻
Proof of Corollary 2:. Next, we refer to the methods in [25] to solve it. If we take the kernel \[K\left( y_1,...,y_m \right) =\frac{1}{( 1+\left| y_1 \right|_{p}^{n}+\cdots +\left| y_m \right|_{p}^{n} ) ^m}\] in Theorem 3, by a change of variables, we have \(T^p=T_{2}^{p}\), and then \(T_{2}^{p}\) can be denoted by \[T_{2}^{p}=\int_{\mathbb{Q}_p ^{nm}}{\frac{1}{( 1+\left| y_1 \right|_{p}^{n}+\cdots +\left| y_m \right|_{p}^{n} ) ^m}f_1( \left| x \right|_{p}^{-1}y_1 ) \cdots f_m( \left| x \right|_{p}^{-1}y_m ) dy_1\cdots dy_m},\] respectively, then all things reduce to calculating \[C_{2}^{p}=\int_{\mathbb{Q} _{p}^{nm}}{\frac{1}{(1+\left| y_1 \right|_{p}^{n}+\cdots +\left| y_m \right|_{p}^{n})^m}\prod_{j=1}^m{\left| y_j \right|_{p}^{-\alpha _j}dy_1}\cdots dy_m}.\] After a series of simple operations, we have \[\begin{align} C_{2}^{p} &=\int_{\mathbb{Q} _{p}^{n}}{\cdots \int_{\mathbb{Q} _{p}^{n}}{\sum_{k_m=-\infty}^{+\infty}{\int_{S_{k_m}}{\frac{1}{( 1+\left| y_1 \right|_{p}^{n}+\cdots +\left| y_m \right|_{p}^{n}) ^m}}}}}\prod_{j=1}^m{\left| y_j \right|_{p}^{-\alpha _j}}dy_m\cdots dy_1 \\ &=\sum_{k_1=-\infty}^{+\infty}{\sum_{k_2=-\infty}^{+\infty}{\cdots}\sum_{k_m=-\infty}^{+\infty}{\int_{S_{k_1}}{\cdots \int_{S_{k_m}}{\frac{1}{( 1+\left| y_1 \right|_{p}^{n}+\cdots +\left| y_m \right|_{p}^{n}) ^m}\prod_{j=1}^m{\left| y_j \right|_{p}^{-\alpha _j}}}}}}dy_m\cdots dy_1 \\ &=\sum_{k_1=-\infty}^{+\infty}{\sum_{k_2=-\infty}^{+\infty}{\cdots}\sum_{k_m=-\infty}^{+\infty}{\frac{1}{(1+p^{k_1n}+\cdots +p^{k_mn})^m}}}\prod_{j=1}^m{p^{-k_j\alpha _j}}\int_{S_{k_1}}{\cdots \int_{S_{k_m}}{dy_m\cdots dy_1}} \\ &=\sum_{k_1=-\infty}^{+\infty}{\sum_{k_2=-\infty}^{+\infty}{\cdots}\sum_{k_m=-\infty}^{+\infty}{\frac{1}{(1+p^{k_1n}+\cdots +p^{k_mn})^m}}}\prod_{j=1}^m{p^{-k_j\alpha _j}}\prod_{j=1}^m({p^{k_jn}( 1-p^{-n} ))} \\ &=\left( 1-p^{-n} \right) ^m\sum_{k_1=-\infty}^{+\infty}{\sum_{k_2=-\infty}^{+\infty}{\cdots}\sum_{k_m=-\infty}^{+\infty}{\frac{1}{(1+p^{k_1n}+\cdots +p^{k_mn})^m}}}\prod_{j=1}^m{p^{k_j(-\alpha _j+n)}}. \end{align}\] What we want to prove is that the sum of this series is bounded. Because it is a challenging problem to calculate the sum of this series, so we can indirectly prove that this series sum is bounded by an inequality. Clearly, \[[ \max ( 1,\left| y_1 \right|_{p}^{n},\cdots ,\left| y_m \right|_{p}^{n}) ] ^m=\underset{1\leqslant j\leqslant m}{\max}\{ 1,\left| y_j \right|_{p}^{mn} \} \leqslant ( 1+\left| y_1 \right|_{p}^{n}+\cdots +\left| y_m \right|_{p}^{n}) ^m.\] Then we have \[C_{2}^{p}\leqslant D^p=:\int_{\mathbb{Q} _{p}^{nm}}{\frac{1}{[\max\mathrm{(}1,\left| y_1 \right|_{p}^{n},...,\left| y_m \right|_{p}^{n})]^m}\prod_{j=1}^m{\left| y_j \right|_{p}^{-\alpha _j}}dy_1\cdots dy_m}.\] Thus if we prove that \(D^p\) is bounded, it means that \(C_2^p\) is bounded. Next, we refer to the methods in [25] to calculate \(D^p\).
To calculate this integral, divide the integral into \(m\) parts. Let \[\begin{align} &E_0=\{ \left( y_1,...,y_m \right) \in \mathbb{Q} _{p}^{n}\times \cdots \times \mathbb{Q} _{p}^{n}:\left| y_k \right|_p\leqslant 1,1\leqslant k\leqslant m\} ; \\ &E_1=\{ \left( y_1,...,y_m \right) \in \mathbb{Q} _{p}^{n}\times \cdots \times \mathbb{Q} _{p}^{n}:\left| y_1 \right|_p>1,\left| y_k \right|_p\leqslant \left| y_1 \right|_p,1<k\leqslant m \} ; \\ &E_i=\{ \left( y_1,...,y_m \right) \in \mathbb{Q} _{p}^{n}\times \cdots \times \mathbb{Q} _{p}^{n}:\left| y_i \right|_p>1,\left| y_j \right|_p<\left| y_i \right|_p,\left| y_k \right|_p\leqslant \left| y_i \right|_p,1\leqslant j<i<k\leqslant m \} ; \\ &E_m=\{ \left( y_1,...,y_m \right) \in \mathbb{Q} _{p}^{n}\times \cdots \times \mathbb{Q} _{p}^{n}:\left| y_m \right|_p>1,\left| y_j \right|_p<\left| y_m \right|_p,1\leqslant j\leqslant m \}. \end{align}\] Its clear that \[\bigcup_{j=0}^m{E_j=}\mathbb{Q} _{p}^{n}\times \cdots \times \mathbb{Q} _{p}^{n}\] and \(E_i\cap E_j=\varnothing \left( i\ne j \right)\). We let \[J_j:=\int_{E_j}{\frac{1}{[ \max ( 1,\left| y_1 \right|_{p}^{n},...,\left| y_m \right|_{p}^{n} )] ^m}\prod_{k=1}^m{\left| y_k \right|_{p}^{-\alpha_k}}}dy_1\cdots dy_m.\] Then \[D^{p}=\sum_{j=1}^m{J_j:}=\sum_{j=1}^m{\int_{E_j}{\frac{1}{[ \max ( 1,\left| y_1 \right|_{p}^{n},...,\left| y_m \right|_{p}^{n} ) ] ^m}\prod_{k=1}^m{\left| y_k \right|_{p}^{-\alpha_k}}dy_1\cdots dy_m}}.\] Now let us calculate \(I_j\), \(j=1,2,...,m\). Since \(\alpha_j<n\), so we have \[\begin{align} J_0&=\prod_{k=1}^m{\int_{\left| y_k \right|_p\leqslant 1}{\left| y_k \right|_{p}^{-\alpha _k}}dy_k=\prod_{k=1}^m{\left( \sum_{i=-\infty}^0{\int_{S_i}{\left| y_k \right|_{p}^{-\alpha _k}}dy_k} \right)}} \\ &=\prod_{k=1}^m{\left( \sum_{i=-\infty}^0{p^{-i\alpha _k}p^{in}(1}-p^{-n}) \right)}=\frac{\left( 1-p^{-n} \right) ^m}{\prod_{k=1}^m{(1-p^{\alpha _k-n})}}. \end{align}\] Similar for \(i=1\), since \(\alpha>0\) and \(\alpha_j<n\), we have \[\begin{align} J_1&=\int_{E_1}{\frac{1}{[\max\mathrm{(}1,\left| y_1 \right|_{p}^{n},...,\left| y_m \right|_{p}^{n})]^m}\prod_{k=1}^m{\left| y_k \right|_{p}^{-\alpha_k}}}dy_1\cdots dy_m \\ &=\int_{\left| y_1 \right|_p>1}{\left| y_1 \right|_{p}^{-\alpha _1-mn}}\prod_{k=2}^m{\left( \int_{\left| y_k \right|_p\leqslant \left| y_1 \right|_p}{\left| y_k \right|_{p}^{-\alpha _k}}dy_k \right) dy_1}=\frac{\left( 1-p^{-n} \right) ^{m-1}}{\prod_{k=2}^m{(1-p^{\alpha _k-n})}}\int_{\left| y_1 \right|_p>1}{\left| y_1 \right|_{p}^{-\alpha -n}}dy_1 \\ &=\frac{\left( 1-p^{-n} \right) ^{m-1}}{\prod_{k=2}^m{(1-p^{\alpha _k-n})}}\left( \int_{\left| y_1 \right|_p<\infty}{\left| y_1 \right|_{p}^{-\alpha -n}dy_1}-\int_{\left| y_1 \right|_p\leqslant 1}{\left| y_1 \right|_{p}^{-\alpha -n}dy_1} \right) \\ &=\frac{\left( 1-p^{-n} \right) ^{m-1}}{\prod_{k=2}^m{(1-p^{\alpha _k-n})}}\left( \sum_{i=-\infty}^{+\infty}{\int_{S_i}{\left| y_1 \right|_{p}^{-\alpha -n}}dy_1-\sum_{j=-\infty}^0{\int_{S_j}{\left| y_1 \right|_{p}^{-\alpha -n}}dy_1}} \right) \\ &=\frac{\left( 1-p^{-n} \right) ^{m-1}}{\prod_{k=2}^m{(1-p^{\alpha _k-n})}}\sum_{i=1}^{+\infty}{\int_{S_j}{\left| y_1 \right|_{p}^{-\alpha -n}}dy_1}=\frac{\left( 1-p^{-n} \right) ^mp^{-\alpha}}{\left( 1-p^{-\alpha} \right) \prod_{k=2}^m{(1-p^{\alpha _k-n})}}. \end{align}\] Similar for \(i=2,...,m-1\), we have \[\begin{align} J_i&=\int_{\left| y_i \right|_p>1}{\left| y_i \right|_{p}^{-\alpha _i-mn}}\left( \prod_{j=1}^{i-1}{\int_{\left| y_j \right|_p<\left| y_i \right|_p}{\left| y_j \right|_{p}^{-\alpha _j}}dy_j} \right) \left( \prod_{k=i+1}^m{\int_{\left| y_k \right|_p\leqslant \left| y_i \right|_p}{\left| y_k \right|_{p}^{-\alpha _k}}dy_k} \right)dy_i \\ &=\frac{\left( 1-p^{-n} \right) ^{m-1}\prod_{j=1}^{i-1}{p^{\alpha _j-n}}}{\prod_{1\leqslant k\leqslant m,k\ne i}{(1-p^{\alpha _k-n})}}\int_{\left| y_i \right|_p>1}{\left| y_i \right|_{p}^{-\alpha -n}}dy_i \\ &=\frac{p^{-\alpha}\left( 1-p^{-n} \right) ^m\prod_{j=1}^{i-1}{p^{\alpha _j-n}}}{(1-p^{-\alpha})\prod_{1\leqslant k\leqslant m,k\ne i}{(1-p^{\alpha _k-n})}}. \end{align}\] The case of \(i=m\) similar to the previous step, we show that \[\begin{align} J_m&=\int_{\left| y_m \right|_p}{\left| y_m \right|^{-\alpha _m-mn}\left( \prod_{j=1}^{i-1}{\int_{\left| y_j \right|_p<\left| y_i \right|_p}{\left| y_i \right|_{p}^{-\alpha _j}}dy_j} \right)}\left( \prod_{k=i+1}^m{\int_{\left| y_k \right|_p\leqslant \left| y_i \right|_p}{\left| y_k \right|_{p}^{-\alpha _k}}dy_k} \right)dy_m \\ &=\frac{p^{-\alpha}\left( 1-p^{-n} \right) ^m\prod_{j=1}^{m-1}{p^{\alpha _j-n}}}{\left( 1-p^{-\alpha} \right) \prod_{k=1}^{m-1}{(1-p^{\alpha _k-n})}}. \end{align}\] Now, we will calculate their sum, let \[B_m=\frac{p^{-\alpha}\left( 1-p^{-n} \right) ^m}{\left( 1-p^{-\alpha} \right) \prod_{k=1}^m{(1-p^{\alpha _k-n})}}\,\,\,\text{and} \,\,\, d_k=\sum_{i=1}^k{\alpha _i}.\] Notice that \(d_m=\alpha\), then \[\begin{align} D^{p}&=J_0+J_1+\sum_{i=2}^{m-1}{J_i}+J_m \\ &=\frac{\left( 1-p^{-n} \right) ^m}{\prod_{k=1}^m{(1-p^{\alpha _k-n})}}+\frac{\left( 1-p^{-n} \right) ^mp^{-\alpha}}{\left( 1-p^{-\alpha} \right) \prod_{k=2}^m{(1-p^{\alpha _k-n})}} \\ &\quad+\prod_{i=2}^{m-1}{\frac{p^{-\alpha}\left( 1-p^{-n} \right) ^m\prod_{j=1}^{i-1}{p^{\alpha _j-n}}}{(1-p^{-\alpha})\prod_{1\leqslant k\leqslant m,k\ne i}{(1-p^{\alpha _k-n})}}+\frac{p^{-\alpha}\left( 1-p^{-n} \right) ^m\prod_{j=1}^{m-1}{p^{\alpha _j-n}}}{\left( 1-p^{-\alpha} \right) \prod_{k=1}^{m-1}{(1-p^{\alpha _k-n})}}}. \\ &=B_m\left( \frac{1-p^{-\alpha}}{p^{-\alpha}}+(1-p^{d_1-n})+(p^{d_1-n}-p^{d_2-2n})+\cdots +(p^{d_{m-1}-(m-1)n}-p^{d_m-mn}) \right) \\ &=B_m\left( \frac{1-p^{-d_m}}{p^{-d_m}}+1-p^{d_m-mn} \right) =B_mp^{d_m}\left( 1-p^{-mn} \right) \\ &=\frac{\left( 1-p^{-n} \right) ^m\left( 1-p^{-mn} \right)}{\left( 1-p^{-\alpha} \right) \prod\nolimits_{k=1}^m{\left( 1-p^{\alpha _k-n} \right)}}<\infty. \end{align}\] In conclusion, we prove that \(D^p\) is bounded, it also means that \(C_2^p\) is bounded, that is \[(1-p^{-n})^m\sum_{k_1=-\infty}^{+\infty}{\sum_{k_2=-\infty}^{+\infty}{\cdots}\sum_{k_m=-\infty}^{+\infty}{\frac{1}{(1+p^{k_1n}+\cdots +p^{k_mn})^m}}}\prod_{j=1}^m{p^{k_j(-\alpha _j+n)}}<\infty.\] Our results also show that \(D^p\) is Hilbert’s upper bound. This finishes the proof of Corollary 2. ◻
In this section, we will use the previous results to give the sharp bound for the \(p\)-adic \(m\)-linear \(n\)-dimensional Hausdorff operator on \(p\)-adic weighted space.
Corollary 3. Assume that the real paramenters \(\alpha\), \(\alpha_j\) with \(j=1,2,...,m\) are the same as Theorem 3, \(f_j\) be a measurable function in \(H_{\alpha _j}^{\infty}( \mathbb{Q} _{p}^{n} )\). A non-negative function \(\Phi\) on \(\mathbb{Q} _{p}^{n}\) satisfies
\[\begin{align} C_{\Phi}^{p}=\int_{\mathbb{Q} _{p}^{n}}{\cdots}\int_{\mathbb{Q} _{p}^{n}}{\frac{\Phi \left( y_1,...,y_m \right)}{\left| y_1 \right|_{p}^{n}\cdots \left| y_m \right|_{p}^{n}}\prod_{j=1}^m{\left| y_j \right|^{-\alpha _j}}}dy_1\cdots dy_m<\infty. \end{align}\] Then \[\begin{align} \left\| T_{\Phi}^{p} \right\| _{\prod\nolimits_{j=1}^m{H_{\alpha _j}^{\infty}( \mathbb{Q} _{p}^{n} )}\rightarrow H_{\alpha}^{\infty}( \mathbb{Q} _{p}^{n} )}=C_{\Phi}^{p}. \end{align}\]
Proof of Corollary 3:. By a change of variables, the \(p\)-adic \(m\)-linear \(n\)-dimensional Hausdorff operator become \[T_{\Phi}^{p}=\int_{\mathbb{Q} _{p}^{n}}{\cdots}\int_{\mathbb{Q} _{p}^{n}}{\frac{\Phi \left( y_1,...,y_m \right)}{\left| y_1 \right|_{p}^{n}\cdots \left| y_m \right|_{p}^{n}}}f_1( x\left| y_1 \right|_{p}^{-1} ) \cdots f_m( x\left| y_m \right|_{p}^{-1} ) dy_1\cdots dy_m.\] We can obtain \[\begin{align} \left\| T_{\Phi}^{p} \right\| _{\prod\nolimits_{j=1}^m{H_{\alpha _j}^{\infty}\left( \mathbb{Q} _{p}^{n} \right)}\rightarrow H_{\alpha}^{\infty}\left( \mathbb{Q} _{p}^{n} \right)}=\int_{\mathbb{Q} _{p}^{n}}{\cdots}\int_{\mathbb{Q} _{p}^{n}}{\frac{\Phi \left( y_1,...,y_m \right)}{\left| y_1 \right|_{p}^{n}\cdots \left| y_m \right|_{p}^{n}}\prod_{j=1}^m{\left| y_j \right|^{-\alpha _j}}}dy_1\cdots dy_m=C_{\Phi}^{p}. \end{align}\] This is similar to the proof of Theorem 3, so we omit the details. This finishes the proof of Corollary 3. ◻
The authors declare that no funds, grants, or other support were received during the preparation of this manuscript.
Not applicable for this article as it is pure mathematical research with no associated data.
The authors declare that they have no conflicts of interest/competing interests regarding this work.
Tianyang He
Research Center for Mathematics and Interdisciplinary Sciences, Frontiers Science Center for Nonlinear Expectations (Ministry of Education)
Shandong University
Qingdao, 266237
P. R. China E-mail address: hty13791059207@163.com
Corresponding author, E-mail: hty13791059207@163.com. ORCID: 0009-0000-8811-3074↩︎